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  • Executing ffmpeg from php running in apache

    - by foobar
    I was executing ffmpeg from php running inside apache. I used to get the error " error while loading shared libraries: libavdevice.so.52: cannot open shared object file: No such file or directory". It used to work perfectly if the php script was executed from the command prompt or ffpmeg was directly invoked from the command prompt. I followed the below steps to fix the apache error: Step 1: Check if the file “libavdevice.so.52? exists in the server using the following command. find / -name ‘libavdevice.so.*’ Step 2: You will get the directory in which the file “libavdevice.so.52? exists from the above command. Suppose the directory is “/usr/local/lib/” in this example. Step 3: You have to add the directory name in the file “/etc/ld.so.conf”. Step 4: Execute the command “ldconfig”. How did doing the above make a difference to apache?

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  • PHP Zip Archive sporadically creating multiple files

    - by user516558
    I have a PHP script (running PHP 5.2 on Apache 2.2) that creates a zip archive of files for a user to download. Everything seems to work just fine; the only issue I have is that periodically multiple files will be created before the ZIP archive is successfully finished. Example: archive-name.zip archive-name.zip.a09600 archive-name.zip.b09600 archive-name.zip.c09600 This does not happen every single time; only periodically - the file is still created but sometimes these extra 'files' are left on the server after it finishes. The code that creates the ZIP archive is as follows: $zip_archive = new ZipArchive(); $zip_archive->open($archiveFullName,ZIPARCHIVE::CREATE); if(!file_exists($archiveFullName)) { foreach ($completed_file_arr as $zip_file) { $isFiller = substr($zip_file,-8) == "_err.txt"; if(!$isFiller) { $zip_archive->addFile($zip_file,$localname); } else $zip_archive->addFromString ($zip_file, "The requested source file could not be found."); } } while(!$zip_archive->close()) sleep(1); //ensure that the ZIP file finishes closing

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  • Create table with PHP and populate from MySQL

    - by typoknig
    Hi all, I am creating a table to display on a web page and that table is populated from data in a MySQL database. I am trying to do a couple of things that are making it difficult for me. First I am trying to have call the PHP code that exists in a separate file in HTML via JavaScript. I think I have that working right but I am not 100% sure (because the table will not display). I think it is working right because some of the code for the table (which is in the PHP file) displays in FireBug. Second I am trying to make it so the rows alternate colors for easy viewing too. My PHP code so far is below. The table does not display at all in any browser. $query = "SELECT * FROM employees"; $result = mysql_query($query); $num = mysql_num_rows($result); echo '<table>'; for ($i = 0; $i < $num; $i++){ $row = mysql_fetch_array($result); $id = $row['id']; $l_name = $row['l_name']; $f_name = $row['f_name']; $ssn = $row['ssn']; $class = (($i % 2) == 0) ? "table_odd_row" : "table_even_row"; echo "<tr>"; echo "<td class=" . $class . ">$wrap_id</td>"; echo "<td class=" . $class . ">$wrap_l_name</td>"; echo "<td class=" . $class . ">$wrap_f_name</td>"; echo "<td class=" . $class . ">$wrap_ssn</td>"; echo "</tr>"; } echo '</table>'; mysql_close($link); }

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  • removing index.php of codeigniter on local

    - by Aldi Aryanto
    i'm trying to remove index.php,in my localhost, but it seems doesn't working,its on http://localhost/testing i put .htacces in 'testing' directory under the htdocs LoadModule rewrite_module modules/mod_rewrite.so at apache/conf also already uncheck here my .htaccess RewriteEngine On RewriteBase /testing/ RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ /testing/index.php/$1 [L] here my config $config['base_url'] = "http://localhost/testing"; $config['index_page'] = ''; $config['uri_protocol'] = 'AUTO'; when i access login controller, it's not found Not Found The requested URL /testing/login was not found on this server. I really don't know what to try next. Any help would be appreciated.

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  • Help with PHP and associative arrays

    - by errata
    Hello. I have to do a simple calculator in php based on user's input and choice from select field, something like this: <?php $a = $_GET['a']; $b = $_GET['b']; $array = array( "option1" => 0.1, "option2" => 0.15, "option3" => 0.3, "option4" => 3, "option5" => 3, "option6" => 16, "option7" => 16, "option8" => 16 ); echo "<form action='calc.php' method='get'>"; echo "<input type='text' name='a' value='".$a."'> of "; echo "<select name='b'>"; foreach ($array as $k => $v) { echo "<option value='".$v."'>".$k."</option>"; } echo "</select> "; echo "<input type='submit' value='='> "; $total_volume = $a * $b; echo $total_volume; echo "</form>"; ?> Well, for now everything works fine, but the idea is that after user submits form, the page reloads with sent amount in input field and selected option which user actually selected... First thing is easy: I just put value="a" in my input field, but I'm not sure how to make a selected option in <select> field??? I started with this: foreach ($array as $k => $v) { echo "<option value='".$v."'"; if ($b == $v) { echo " selected "; } echo ">".$k."</option>"; } ...but this is obviously not working as expected... Please help me with this easy one :) Thanks!

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  • PHP exec problem with s3-put

    - by schneck
    Hi there, I use the s3-bash-project to upload data to an S3-Bucket. My command looks like this: /mypath/s3_bash/s3-put -v -k '123456789' -s '/mypath/secret' -T '/mypath/upload/myuploadfile' '/my.bucket/mykeyname' I can run the command from the command line (Mac OS X), and it works well. Now I want to execute it from a PHP-Script: exec($command, $output); but in output, the "s3-put"-command only returns the command's help text. I log the command, and it works if I c&p it from the log the the command line, so there not a problem. It seems that PHP does not pass all the parameters to the command line, although I run escapeshellarg() over all the parameters. I'm using a local XAMPP-Test environment, safe_mode is off. Any ideas?

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  • The largest prime factor with php

    - by Tom
    So, I wrote php program to find the largest prime factor with php and I think it is quite optimal, because it loads quite fast. But there is a problem, it doesn't count very big numbers's prime factors. Here is a program: function is_even($s) { $sk_sum = 0; for($i = 1; $i <= $s; $i++) { if($s % $i == 0) { $sk_sum++; } } if($sk_sum == 2) { return true; } } $x = 600851475143; $i = 2; //x is number while($i <= $x) { if($x % $i == 0) { if(is_even($i)) { $sk = $i; $x = $x / $i; } } $i++; } echo $sk;

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  • Strange behaviour of mb_detect_order() in PHP

    - by termopro
    I would like to detect encoding of some text (using PHP). For that purpose i use mb_detect_encoding() function. The problem is that the function returns different results if i change the order of possible encodings with mb_detect_order() function. Consider the following example $html = <<< STR ????????????????????????????????????????????????????????????????????????????????????????????????????????? STR; mb_detect_order(array('UTF-8','EUC-JP', 'SJIS', 'eucJP-win', 'SJIS-win', 'JIS', 'ISO-2022-JP','ISO-8859-1','ISO-8859-2')); $originalEncoding = mb_detect_encoding($str); die($originalEncoding); // $originalEncoding = 'UTF-8' However if you change the order of encodings in mb_detect_order() the results will be different: mb_detect_order(array('EUC-JP','UTF-8', 'SJIS', 'eucJP-win', 'SJIS-win', 'JIS', 'ISO-2022-JP','ISO-8859-1','ISO-8859-2')); die($originalEncoding); // $originalEncoding = 'EUC-JP' So my questions are: Why is that happening ? Is there a way in PHP to correctly and unambiguously detect encoding of text ?

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  • PHP, since upgrading to 5.2.17 getting some warning ?

    - by Jules
    I can't reproduce this on my test server no idea why this is happening, other queries / functions work.. I'm getting this warning PHP Warning: mysql_connect() [<a href='function.mysql-connect'> function.mysql-connect</a>]: Can't connect to MySQL server on '--my isps server--' (10060) in D:\domains\mydomain.com\wwwroot\p hp\_stdfuncs.php on line 191 This function and others like it are having problems (but some are ok), this is my include file... function AddPageError($PageHandle, $Requested) { global $server; global $db; global $user; global $pass; global $sDebug; $con = mysql_connect($server,$user,$pass); I have an include file which sets those variables, as I say they work on other pages and functions.. No idea why ??

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  • post selextbox values to php page in jquery

    - by JPro
    I am using jquery button click to post all the values in a selectbox to a PHP page, but this code does not seem to work. Can anyone please help? <script type="text/javascript"> $(function() { $("#btn1").click(function () { var arr= new Array; $("#target_select option").each (function () { // You can push the array on an array arr.push( $(this).val() ); //alert( $(this).val() ); not getting the alert to display too }); $.post("test.php", { name: arr } ); }); }); </script> Generate

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  • Include a repetitive chunk of html with PHP?

    - by user146780
    I basically have a div on my Web Site that always has the same stuff. However, this div is not present on all pages which is why I won't use the dynamic web template. I was wondering if it was possible for PHP to get the code from a document on the server and put in into the div? Ex: div id="section... then my text file contains (p) hello (p) basically I want PHP to put it into the div when the user sees it. If theres a smarter way of acheiving this I'd be open to it aswell. Thanks

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  • value not posting to php script

    - by user3710364
    step1 batch in dynamically loaded after selecting one of the value from dropdown step 2 is loaded by ajax call in setp 2 when i click on edit step 3 is loaded via ajax call again in step 3 when i click on edit ajax call is working fine but its nit posting the value to php script //ajax call function validateFees(strAddNo) { var collectFees = $("#collectFees").val(); if(collectFees == "") { $("#validateFeesResult").html('<div class="info">Please enter your Fees Amount.</div>'); $("#collectFees").focus(); } else { var dataString = 'collectFees' + collectFees + 'strAddNo' + strAddNo; $.ajax({ type: "POST", url: "validateFees_script.php", data: dataString, cache: false, beforeSend: function() { $("#validateFeesResult").html('Loading...'); }, success: function(response) { $("#validateFeesResult").hide().fadeIn('slow').html(response); } }); } } I'm sure it's extremely simple but I'm not understanding how to do it?

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  • Restricting IFRAME access in PHP

    - by m0j0
    I am creating a small web page using PHP that will be accessed as an IFRAME from a couple of sites. I'm wanting to restrict access to this site to work ONLY within the "approved" sites, and not other sites or accessed directly. Does anyone have any suggestions? Is this even possible? The PHP site will be Apache, and the sites iframing the content will probably be .NET. Just to clarify, any site can view the page, as long as it's iframe'd within an approved site. I want to block people from accessing it directly. I'm thinking cookies might be a solution, but I'm not sure.

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  • PHP: "Footer function"?

    - by Ricket
    I have a project. It has a good number of PHP files. Each of these files includes a standard header. They don't include a standard footer. Now I want to do something just before the end of every page. I can go through each page and add the footer code, but I was wondering if there is an easier way (and I think I've seen something like it before, though I might be mistaken). Is there a way to set a "hook" or "trigger" function that will be executed at the end of a page, from the included header PHP script? I'm thinking of something like set_error_handler but to handle a page close event. Or like C's atexit function.

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  • PHP and Javascript: Getting file contents with Javascript variable

    - by celliott1997
    Could someone help me to understand why this isn't working? var uname = "<?php echo strtolower($_GET['un']) ?>"; var source = "<?php echo file_get_contents('accounts/"+uname+"') ?>"; console.log(source); I've been trying for a while to get this working and it just doesn't seem to. Before I added in the source variable, it was working fine and displayed the un variable on the page. Thanks.

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