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  • Invalid XML Replace Content in PHP

    - by streetparade
    I have a invalid XML like this Warning: count() [function.count]: Node no longer exists in /var/bla/test.php <?xml version="1.0" encoding="ISO-8859-1"?> <nodes> <some>test</some> </nodes> Now i need a regex which would replace the Warning: count() [function.count]: Node no longer exists in /var/bla/test.php with "" how can i do that? The above xml is is not generated on my localmachine, its a api call which returned a invalid xml

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  • Any way to break if statement in PHP?

    - by Usman
    Is there any command in PHP to stop executing the current or parent if statement, same as break or break(1) for switch/loop. For example $arr=array('a','b'); foreach($arr as $val) { break; echo "test"; } echo "finish"; in the above code PHP will not do echo "test"; and will go to echo "finish"; I need this for if $a="test"; if("test"==$a) { break; echo "yes"; // I don't want this line or lines after to be executed, without using another if } echo "finish"; I want to break the if statement above and stop executing echo "yes"; or such codes which are no longer necessary to be executed, there may be or may not be an additional condition, is there way to do this?

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  • php time 2 hours wrong for only 50% some users

    - by user1797802
    I am having huge issues with php time. For some reason it shows a different time (by 2 hours) to some users and the correct time to other users. The code is H:i:s d-M-y T when I view the page in a browser from my PC it tells me its 11am when infact its 9am, when I check via a browser using one my RDP's I get the correct time. Both PC's are in the country (uk) both PC's have the same system time etc. Tried setting the timezone default, but no matter what I do the server still shows some users the correct time, and other users the time 2 hour forward, any ideas? the code is echo gmdate("H:i:s d-M-y T"); <?php echo gmdate("H:i:s d-M-y T"); ?>

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  • PHP - javascript validation radio button

    - by user1806136
    i have a form with 3 sets of radio buttons. i want to set a simple javascript validation alert to appear when user clicks on submit when one of the fields is null. how can i do that using javascript ? my code so far is .. <?php session_start(); $Load=$_SESSION['login_user']; include('../connect.php'); if (isset($_POST['submit'])) { $v1 = intval($_POST['v1']); $v2 = intval($_POST['v2']); $v3 = intval($_POST['v3']); $total = $v1 + $v2 + $v3 ; mysql_query("INSERT into Form1 (P1,P2,P3,TOTAL) values('$v1','$v2','$v3','$total')") or die(mysql_error()); header("Location: mark.php"); } <center><form method="post" action="mark.php" > <tr> <th > School Evaluation <font size="4" > </font></th> <tr> <th > Criteria <font size="4" > </font></th> <th> 4<font size="4" > </font></th> <th> 3<font size="4" > </font></th> <th> 2<font size="4" > </font></th> <th> 1<font size="4" > </font></th> </tr> <tr> <th> Your attendance<font size="4" > </font></th> <td> <input type="radio" name ="v1" value = "4" onclick="updateTotal();"/></td> <td> <input type="radio" name ="v1" value = "3" onclick="updateTotal();" /></td> <td> <input type="radio" name ="v1" value = "2" onclick="updateTotal();" /></td> <td> <input type="radio" name ="v1" value = "1" onclick="updateTotal();" /></td> </tr> <tr> <th > Your grades <font size="4" > </font></th> <td> <input type="radio" name ="v2" value = "4" onclick="updateTotal();" /></td> <td> <input type="radio" name ="v2" value = "3" onclick="updateTotal();" /></td> <td> <input type="radio" name ="v2" value = "2" onclick="updateTotal();" /></td> <td> <input type="radio" name ="v2" value = "1" onclick="updateTotal();" /></td> </tr> <tr> <th >Your self-control <font size="4" > </font></th> <td> <input type="radio" name ="v3" value = "4" onclick="updateTotal();" /></td> <td> <input type="radio" name ="v3" value = "3" onclick="updateTotal();" /></td> <td> <input type="radio" name ="v3" value = "2" onclick="updateTotal();" /></td> <td> <input type="radio" name ="v3" value = "1" onclick="updateTotal();" /></td> </tr> </tr> </table> i have put <br> <td><input type="submit" name="submit" value="Submit" onClick="return validation(form);"> <input type="reset" name="clear" value="clear" style="width: 70px"></td> </form> i have try alot of codes but no alert appears!

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  • Optimal template for change content via XMLHTTPRequest with JQuery,PHP,SQL [closed]

    - by B.F.
    This is my method to handle XMLHTTPRequests. Avoids mysql request, foreign access, nerves user, double requests. jquery var allow=true; var is_loaded=""; $(document).ready(function(){ .... $(".xx").on("click",functio(){ if(allow){ allow=false; if(is_loaded!="that"){ $.post("job.php", {job:"that",word:"aaa",number:"123"},function(data){ $(".aaa").html(data); is_loaded="that"; }); } setTimeout(function(){allow=true},500); } .... }); job.php <?PHP ob_start('ob_gzhandler'); if(!isset($_SERVER['HTTP_X_REQUESTED_WITH']) or strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) != 'xmlhttprequest')exit("bad boy!"); if($_POST['job']=="that"){ include "includes/that.inc; } elseif($_POST['job']== .... ob_end_flush(); ?> that.inc if(!preg_match("/\w/",$_POST['word'])exit("bad boy!"); if(!is_numeric($_POST['number'])exit("bad boy!"); //exclude more. $path="temp/that_".$row['word']."txt"; if(file_exists($path) and filemtime("includes/that.inc")<$filemtime($path)){ readfile($path); } else{ include "includes/openSql.inc"; $call=sql_query("SELECT * FROM that WHERE name='".mysql_real_escape_string($_POST['word'])."'"); if(!$call)exit("ups"); $out=""; while($row=mysql_fetch_assoc($call)){ $out.=$_POST['word']." loves the color ".$row['color'].".<br/>"; } echo $out; $fn=fopen($path,"wb"); fputs($fn,$out); fclose($fn); } if something change at the database, you just have to delete involved files. Hope it was English.

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  • php var_dump returning blank array

    - by Oroku
    I'm following this tutorial on youtube: https://www.youtube.com/watch?v=VSF5p00uorc Around 4:28 - I get the following array when I load the sql.php page as in the tutorial: array(8) { [1]=> NULL [2]=> NULL [3]=> NULL [4]=> NULL [5]=> NULL [6]=> NULL [7]=> NULL [8]=> NULL } I do have 8 ids all with values in my data table. This is my code: <?php $con = mysqli_connect("localhost","root","","test2") or die('error'); $query = "select * from data"; $result = mysqli_query($con,$query); while($row = mysqli_fetch_array($result)) { $id = $row['id']; $feed = $row['feed']; $data[$id] = $feed; } var_dump($data); ?>

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  • php/ssh2 script does not display the stdout to $stream

    - by kamal
    The following php script works for simple linux commands, like ps -ef , but when i use ./dstat -t -a , it seems to hang and i dont get the prompt back on my local machine. Kep in mind that all commands are executed over ssh on a remote host: <?php $target = time() . '_' . 'txt'; if($ssh = ssh2_connect('10.1.0.174', 22)) { if(ssh2_auth_password($ssh, 'root', 'kmoon77')) { //$stream = ssh2_exec($ssh, 'whoami'); $sCommand = 'dstat -a'; //$sCommand = 'ps -ef'; $stream = ssh2_exec($ssh, $sCommand); //$stream = ssh2_exec($ssh, 'pwd'); stream_set_blocking($stream, true); $data = ''; while($buffer = fread($stream, 4096)) { $data .= $buffer; } //fclose($stream); echo $data; // user } } ?>

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  • PHP MYSQL Insert Data in Arabic Language

    - by h_a86
    I am trying to insert some Arabic Language data into MySQL using PHP and an HTML form. When I insert the data in to MYSQL table, the table field represents data as مرحبا العالم. But when I access the same data with PHP and show it in my webpage, it shows the correct data. I am using: http-equiv="Content-Type" content="text/html; charset=utf-8" meta tag in my web page to show Arabic data. My question is why my data looks like this: مرحبا العالم in MySQL table, and how should I correct it.

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  • Executing multiple update statements in PHP

    - by theband
    I have three update statements to be executed in PHP, i am getting the values of all these as return parameters. How to execute each statement independely and finally show the end user the result that it has been successfully updated. <?php public function name($parameter1,$parameter2.... $parametern) { $records=array(); $sql=""; $sql2=""; $sql3=""; $result=mysql_query($sql); //return $result; if(!$result){throw new Exception(mysql_error());} if(mysql_num_rows($result)==0){return $records;} while($row=mysql_fetch_assoc($result)){$records[]=$row;} return $records; } ?> Then how finally we can get the result in my row object.

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  • How to style email body in php

    - by Vinay
    I want to style mail body. I have tried the below methods to style mail body. But all of them didn't work 1) Used external style sheet style.css td{padding:10px;} mail.php <link rel="stylesheet" href="style.css"></link><table><td>....</td></table> 2) Defined Internal Style Sheet: mail.php <style type="text/css"> td{ padding-bottom:8px; } </style> <table><td>....</td></table> I know, Inline style works by doing <td style='padding-bottom:8px'>, But i have got many tables, doing the inline style is not a good idea, Is there any work around so that no need to define style for each element

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  • Error with connecting ftp through php ...

    - by Holicreature
    Hi, I'm trying to connect to my server using php script to upload some files... But it doesn't connect... I dont know what is the error... I'm sure that ftp is enable, i checked it through php_info() What may be the error... <?php error_reporting(E_ALL); $ftp_server = "server.com"; //address of ftp server (leave out ftp://) $ftp_user_name = "Username"; // Username $ftp_user_pass = "Password"; // Password $conn_id = ftp_connect($ftp_server); // set up basic connection $login_result = ftp_login($conn_id,$ftp_user_name,$ftp_user_pass); if ($login_result = ftp_login($conn_id,$ftp_user_name,$ftp_user_pass)) { echo "Connected as ,$ftp_user_name,$ftp_user_pass \n"; } else { echo "Couldn't connect \n"; } ..... ..... .... .... ftp_close($conn_id); // close the FTP stream ?>

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  • PHP send batch email [closed]

    - by qalbiol
    Possible Duplicate: Sending mass email using PHP I have a PHP script that sends an individual email to all users in my DB, such as a monthly / weekly newsletter. The code I am using goes as follows: $subject = $_POST['subject']; $message = $_POST['message']; // Get all the mailing list subscribers. $query = $db->prepare("SELECT * FROM maildb"); $query->execute(); // Loop through all susbcribers, and send and individual email. foreach ($query as $row) { // Setting maximum time limit to infinite. set_time_limit(0); $newMessage = '<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> </head> <body>'; // Search for the [unsubscribe] tag and replace it with a URL for the user to unsubscribe $newMessage .= str_replace("[unsubscribe]", "<a href='".BASE_URL."unsubscribe/".$row['hash']."/".$row['email']."'>unsubscribe</a>", $message); $newMessage .= '</body></html>'; $to = $row['email']; // Establish content headers $headers = "From: [email protected]"."\n"; $headers .= "Reply-To: [email protected]"."\n"; $headers .= "X-Mailer: PHP v.". phpversion()."\n"; $headers .= "MIME-Version: 1.0"."\n"; $headers .= "Content-Type: text/html; charset=iso-8859-1"."\n"; $headers .= "Content-Transfer-Encoding: 8bit;"; mail($to, $subject, $newMessage, $headers); // Send email to each individual user } This code works perfectly with a REALLY small database... I recently populated my test db with 200k+ users, and obviously this script fails, gets out of memory, and dies... I know this is a bad way to send so many emails, thats why I'd like to ask you for much more efficient ways to do this! Thank you very much!

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  • PHP from database and query

    - by Kyle R
    I have a table: id, affiliate Each time somebody clicks a link, a new row is inserted, ID being the ID of the page, and affiliate being the ID of the affiliate. For example: Page ID: 9 Affiliate ID: 1 Page ID: 9 Affiliate ID: 2 Page ID: 9 Affiliate ID: 3 I only have 3 affiliates. I want to select this information, and group them by affiliate, for the ID. I have tried this query: SELECT COUNT(*) FROM table WHERE id = '9' GROUP BY affiliate It works fine when I do it in php my admin, how do I get the info in PHP? I have tried: $q = mysql_query("SELECT COUNT(*) FROM table WHERE id = '" . $id . "' GROUP BY affiliate"); $r = mysql_fetch_array($q); When trying to print the data onto the page, I am only getting one result. Do I need to use a foreach/while loop to get all 3? How would I go about doing this? Thank you!

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  • Copying a file with PHP Command

    - by Tom
    Hi, I'm having a problem using the copy function in PHP, what is wrong with it? I get the error; Parse error: syntax error, unexpected T_VARIABLE On the bottom line; $targetDir = 'file.txt'; $targetDir2 = 'file2.txt'; copy($targetDir, $targetDir2); Thanks The entire file is; <?PHP $targetDir = 'file.txt'; $targetDir2 = 'file2.txt'; copy($targetDir, $targetDir2); ?> copy and pasted from the doc.

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  • PHP String to Float

    - by John
    I am not familiar with PHP at all and had a quick question. I have 2 variables @pricePerUnit and @invoicedUnits. Here's the code that is setting these to values: $InvoicedUnits = ((string) $InvoiceLineItem->InvoicedUnits); $pricePerUnit = ((string) $InvoiceLineItem->PricePerUnit); If I output this, I get the correct values. Lets say 5000 invoiced units and 1.00 for price. Now, I need to show the total amount spent. When I multiply these two together it doesn't work (as expected, these are strings). But I have no clue how to parse/cast/convert variables in PHP. What should I do?

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  • Call External Javascript using php

    - by Ajith
    I am try to add a javascript using php as follows <?php Header("content-type: application/x-javascript"); $serverIP=$_SERVER['REMOTE_ADDR']; echo "document.write(\"Your IP address is: <b>" . $serverIP . "</b>\")"; ?> Here i need to print my output as follows Your IP address is: 127.0.0.1 but it is showing result like document.write("Your IP address is: <b>127.0.0.1</b>"). i am using apache server in ubuntu.What is wrong with me. help me please...

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  • PHP Losing variable data

    - by Conor B
    Hi, I'm having an issue with PHP losing data in a variable. There is quite a bit of data in the variable, because it basically contains a binary file, but I'm wondering if this is cause for it to completely lose it's information. Looking at a snippet from my code which is used to deal with email attachments: var_dump($data) if (array_key_exists('filename', $params) || array_key_exists('name', $params)) { var_dump($data) ... } The first var_dump gives the desired output of the file: "string(283155) " --Apple-Mail-5-930065543 ... etc while the second gives an output of: string(0) "" ... string(0) "" Any idea why this is happening? Does PHP just drop data in variables if they are really large? (I didn't think so, as I've never had this problem before) If so, any workaround? Thanks!

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