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  • MySql left join on several regs

    - by egidiocs
    Hi there! I have this table1 idproduct(PK) | date_to_go 1 2010-01-18 2 2010-02-01 3 2010-02-21 4 2010-02-03 and this other table2 that controls date_to_go updates id | idproduct(FK) | prev_date_to_go | date_to_go | update_date 1 1 2010-01-01 2010-01-05 2009-12-01 2 1 2010-01-05 2010-01-10 2009-12-20 3 1 2010-01-10 2010-01-18 2009-12-20 4 3 2010-01-20 2010-02-03 2010-01-05 So, in this example, for table1.idproduct #1 2010-01-18 is the actual date_to_go and 2010-01-01 (table2.prev_date_to_go, first reg) is the original date_to_go . using this query select v.idproduct, v.date_to_go, p.prev_date_to_go original_date_to_go from table1 v left join produto_datas p on p.idproduto = v.idproduto group by (v.idproduto) order by v.idproduto can I assume that original_date_to_go will be the first related reg of table2? idproduct | date_to_go | original_date_to_go 1 2010-01-18 2010-01-01 2 2010-02-01 NULL 3 2010-02-21 2010-01-20 4 2010-02-03 NULL

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  • MySQL - Sort on a calculated value based on two dates

    - by Petter Magnusson
    I have the following problem that needs to be solved in a MySQL query: Fields info - textfield date1 - a date field date2 - a date field offset1 - a text field with a number in the first two positions, example "10-High" offset2 - a text field with a number in the first two positions, example "10-High" I need to sort the records by the calculated "sortvalue" based on the current date (today): If today=date2 then sortvalue=offset1*10+offset2*5+1000 else sortvalue=offset1*10+offset2*5 I have quite good understanding of basic SQL with joins etc, but this I am not even sure if its possible...if it helps I could perhaps live with a single formula giving the same sort of effect as the IFs do....ie. before date1 = low value, after date2 = high value... Rgds PM

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  • How to select DISTINCT rows without having the ORDER BY field selected

    - by JannieT
    So I have two tables students (PK sID) and mentors (PK pID). This query SELECT s.pID FROM students s JOIN mentors m ON s.pID = m.pID WHERE m.tags LIKE '%a%' ORDER BY s.sID DESC; delivers this result pID ------------- 9 9 3 9 3 9 9 9 10 9 3 10 etc... I am trying to get a list of distinct mentor ID's with this ordering so I am looking for the SQL to produce pID ------------- 9 3 10 If I simply insert a DISTINCT in the SELECT clause I get an unexpected result of 10, 9, 3 (wrong order). Any help much appreciated.

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  • Searching a table MySQL & PHP.

    - by S1syphus
    I want to be able to search through a MySQL table using values from a search string, from the url and display the results as an XML output. I think I have got the formatting and declaring the variables from the search string down. The issue I have is searching the entire table, I've looked over SO for previous answers, and they all seem to have to declare each column in the table to search through. So for example my database layout is as follows: **filesindex** -filename -creation -length -wall -playlocation First of all would the following be appropriate: $query = "SELECT * FROM filesindex WHERE filename LIKE '".$searchterm."%' UNION SELECT * FROM filesindex WHERE creation LIKE '".$searchterm."%' UNION SELECT * FROM filesindex WHERE length LIKE '".$searchterm."%' UNION SELECT * FROM filesindex WHERE wall LIKE '".$searchterm."%' UNION SELECT * FROM filesindex WHERE location LIKE '".$searchterm."%'"; Or ideally, is there an easier way that involves less hardcoding to search a table. Any ideas? Thanks

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  • SQL 2005: Select top N, group by ID with joins

    - by Suzy Fresh
    I'm having real difficulty with a query involving 3 tables. I need to get the 3 newest users per department grouped by department names. The groups should be sorted by the users.dateadded so the department with the newest activity is first. The users can exist in multiple departments so Im using a lookup table that just contains the userID and deptID. My tables are as follows. Department - depID|name Users - userID|name|dateadded DepUsers - depID|userID The output I need would be Receiving John Doe - 4/23/2010 Bill Smith - 4/22/2010 Accounting Steve Jones - 4/22/2010 John Doe - 4/21/2010 Auditing Steve Jones - 4/21/2010 Bill Smith - 4/21/2010

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  • django m2m how can i get m2m table elements in a view

    - by dana
    i have a model using m2m feature: class Classroom(models.Model): user = models.ForeignKey(User, related_name = 'classroom_creator') classname = models.CharField(max_length=140, unique = True) date = models.DateTimeField(auto_now=True) open_class = models.BooleanField(default=True) members = models.ManyToManyField(User,related_name="list of invited members", through = 'Membership') and i want to take all members of one class in a view and display them using the template system. In the view, i'm trying to take all the members from a classroom like that: def inside_classroom(request,classname): try: theclass = Classroom.objects.get(classname = classname) members = Members.objects.all() etc but it doesn't work,(though the db_table is named Classroom_Members) i guess i have to use another query for getting all the members from the classroom classname. also, i want to verify if the request.user is a member using (if request.user in members) how can i het those members? Thanks in advance!

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  • MySQL calling in Username to show instead of ID!

    - by Jess
    I have a users table, books table and authors table. An author can have many books, while a user can also have many books. (This is how my DB is currently setup). As I'm pretty new to So far my setup is like bookview.php?book_id=23 from accessing authors page, then seeing all books for the author. The single book's details are all displayed on this new page...I can get the output to display the user ID associated with the book, but not the user name, and this also applies for the author's name, I can the author ID to display, but not the name, so somewhere in the query below I am not calling in the correct values: SELECT users.user_id, authors.author_id, books.book_id, books.bookname, books.bookprice, books.bookplot FROM books INNER JOIN authors on books.book_id = authors.book_id INNER JOIN users ON books.book_id = users.user_id WHERE books.book_id=" . $book_id; Could someone help me correct this so I can display the author name and user name both associated with the book! Thanks for the help :)

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  • mysql to get depth of record, count parent and ancestor records

    - by Nate
    Hey All, Say I have a post table containing the fields post_id and parent_post_id. I want to return every record in the post table with a count of the "depth" of the post. By depth, I mean, how many parent and ancestor records exist. Take this data for example... post_id parent_post_id ------- -------------- 1 null 2 1 3 1 4 2 5 4 The data represents this hierarchy... 1 |_ 2 | |_ 4 | |_ 5 |_ 3 The result of the query should be... post_id depth ------- ----- 1 0 2 1 3 1 4 2 5 3 Thanks in advance!

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  • Deleting orphans with JPA

    - by homaxto
    I have a one-to-one relation where I use CascadeType.PERSIST. This has over time build up a huge amount of child records that has not been deleted, to such an extend that it is reflected in the performance. Now I wish to add some code that cleans up the database removing all the child records that are not referenced by a parent. At the moment we are talking 400K+ records, at I need to run the code on all customer installations just to be sure they do not run into the same problem. I think the best solution would be to run a named query (because we support two databases) that deletes the necessary records, and this is where I get into problems, because how should I write it in JPQL? The result I want can be defined like the following sql statement, which unfortunaltely does not run on MySQL. DELETE FROM child c1 WHERE c1.pk NOT IN (SELECT DISTINCT p.pk FROM child c2 JOIN parent p ON p.child = c2.pk);

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  • How to get top 3 frequencies in MySQL?

    - by Amenhotep
    Hello, In MySQL I have a table called "meanings" with three columns: "person" (int), "word" (byte, 16 possible values) "meaning" (byte, 26 possible values). A person assigns one or more meanings to each word: person word meaning ------------------- 1 1 4 1 2 19 1 2 7 <-- second meaning for word 2 1 3 5 ... 1 16 2 Then another person, and so on. There will be thousands of persons. I need to find for each of the 16 words the top three meanings (with their frequencies). Something like: word 1: meaning 5 (35% of people), meaning 19 (22% of people), meaning 2 (13% of people) word 2: meaning 8 (57%), meaning 1 (18%), meaning 22 (7%) ... Is it possible to solve this with a single MySQL query? (If this problem is a classic one and has been answered elsewhere, I would appreciate if you could give me a link to the solution.) Thank you very much, ve

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  • I want to search and replace multiple values in a table column in one MYsql querry.

    - by user204245
    Query to Where X update Y and where A update B in a Mysql Table column. How can I Do this in MYsql in one querry on the same column in a specific table. I want to search and replace multiple values in a table column. Conditons in table1 in column1 Where X update Y and Where a update b and Where 1 update 2 and Where 3 update 4 and Where value1 update value 2 And So on. I can individually do this but how can I do this faster is there a mysql function to help me with this. I have about 120 columns with 200 search and replace/update values for each column. Thanks.

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  • How to Display result of subquery rows as one column in MySQL?

    - by SIA
    Hi I have three tables Category, Movies and RelCatMov Category-table categoryid, categoryName 1 thriller 2 supsense 3 romantic 4 action 5 sci-fi Movies-table movieid, movieName 1 Avataar 2 Titanic 3 NinjaAssassin RelCatMov-table categoryid, MovieID 1 1 2 2 3 2 4 2 5 2 Now i Want to display a the record as MovieName Categories Titanic Suspense,Romantic,Sci-fi,action How to do this. I am writing a query select MovieName,(select categoryname from category b,relcatmov c where b.categoryid=c.categoryid and c.movieid=a.movieid) as categories from movies a; Error: Subquery returns more than one row!!! How to display the result of rows in one column? Please help!!!

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  • MongoDB - how to join parent and child products by reference

    - by Jaro
    my mongo collection stores products. There are two product types: child and parent. Parent product holds array of its child as reference. Use case: use mydb; child1 = { _id: 1, name: "Child 1", is_child: true, is_parent: false, children : [] } child2 = { _id: 2, name: "Child 2", is_child: true, is_parent: false, children : [] } parent = { _id: 3, name: "Parent product", is_child: false, is_parent: true, children : [1, 2] } db.product.insert( [child1, child2, parent] ); And I'm looking for any query returning { _id: 3, name: "Parent product", is_child: false, is_parent: true, children: [ { _id: 1, name: "Child 1", is_child: true, is_parent: false, children : [] }, { _id: 2, name: "Child 2", is_child: true, is_parent: false, children : [] } ] } I'm newbie to mongodb, but I guess an usage of map-reduce could solve the problem. Can anyone advice? Thx

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  • Javascript string syntax to write SQL

    - by sebastien leblanc
    I am writing an SQL query as a Javascript string like that: SQLdetail = 'SELECT [Avis SAP], Avis.[Ordre SAP], [Date Appel], [Heur Appel], Client_List![Code Client], [Numero Passerelle], [Designation Appel], Ordre![Metier], Ordre!Repercussion, Ordre!Objet, Ordre![Profil Panne], Ordre!Cause, Ordre![Sommaire Correctif], Ordre![Statut]' SQLdetail += ' FROM (Avis' SQLdetail += ' LEFT JOIN Client_List ON Avis.[Numero Client] = Client_List.[Numero Client])' SQLdetail += ' LEFT JOIN Ordre ON Avis.[Ordre SAP] = Ordre.[Ordre SAP] WHERE Avis.[Date Appel] BETWEEN #' & DateOne & '# AND #' & DateTwo & '#;' alert('SQLdetail:' + SQLdetail) and the last SQLdetail += somehow returns "0". Am I missing something in the syntax that just turns the whole string to a 0?

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  • How do I add a one-to-one relationship in MYSQL?

    - by alex
    +-------+-------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-------+-------------+------+-----+---------+-------+ | pid | varchar(99) | YES | | NULL | | +-------+-------------+------+-----+---------+-------+ 1 row in set (0.00 sec) +-------+---------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-------+---------------+------+-----+---------+-------+ | pid | varchar(2000) | YES | | NULL | | | recid | varchar(2000) | YES | | NULL | | +-------+---------------+------+-----+---------+-------+ 2 rows in set (0.00 sec) This is my table. pid is just the id of the user. "recid" is a recommended song for that user. I hope to have a list of pid's, and then recommended songs for each person. Of course, in my 2nd table, (pid, recid) would be unique key. How do I do a one-to-one query for this ?

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  • MySQL easy question CURDATE()

    - by Tristan
    I want to compare two results one is stored in the first query, and the other is exactly the same as the first, but i want only to recieve data < today "SELECT s.GSP_nom as nom, timestamp, COUNT(s.GSP_nom) as nb_votes, AVG(v.vote+v.prix+v.serviceClient+v.interface+v.interface+v.services)/6 as moy FROM votes_serveur AS v INNER JOIN serveur AS s ON v.idServ = s.idServ WHERE s.valide = 1 AND v.date < CURDATE() ROUP BY s.GSP_nom HAVING nb_votes > 9 ORDER BY moy DESC LIMIT 0,15"; is that correct ? thank you

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  • SQL conditional Pivot

    - by Coov
    Yes, this is another Pivot question... I've read through nearly all the previous questions and I can't seem to hack together a query that does what I need. Here is what my table looks like: FirmName Account Balance Pmt Revolving Installment Mortgage Amex 12345 10000 2000 1 0 0 Discover 54321 20000 4000 1 0 0 Chase 13579 100000 1500 0 0 1 Wells Fargo 2468 40000 900 0 1 0 The last three bit columns (Revolving, Installment, & Mortgage) dictate how the columns should be rolled up into a type. Each result requires three columns based on the type and its row count. The outcome should be one row with many columns. Here is what the result should look like: Revolving1_Firm Revolving1_Balance Revolving1_Pmt Revolving2_Firm Revolving2_Balance Revolving2_Pmt Realestate1_Firm Realestate1_Balance Realestate1_Pmt Vehicle1_Firm Vehicle1_Balance Vehicle1_Pmt Amex 10000 2000 Discover 20000 4000 Chase 100000 1500 Wells Fargo 40000 900 How do you pivot based on the bit fields (Revolving, Installment, & Mortgage) and retain the proper count so that that each column gets count # appended to it?

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  • Creating a loop that will edit 60 TextBox names?

    - by Darkmage
    text box set1 = 1 to 30 = in the query name = br1id to br30id textbox set 2 = 1 to 30 = in the result output i dont understand how to create a loop based on 30 diffrent textbox names? i cant copy paste these lines 30 times editing the textbox names, that wold just look wrong. try { MySqlConnection mysqlCon = new MySqlConnection( "server= 195.159.253.229;" + "Database = bruker;" + "user id=bobby;" + "password=LoLOW###;"); MySqlCommand cmd1 = new MySqlCommand( "SELECT brukernavn From bruker where ID = '" + br1id.Text + "';", mysqlCon); mysqlCon.Open(); navX[0] = cmd1.ExecuteScalar().ToString(); br1txt3.Text = navX[0]; }

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  • Unable to relate two MySQL tables (foreign keys)

    - by KPL
    Hello people, Here's my USER table CREATE TABLE IF NOT EXISTS `users` ( `id` int(11) NOT NULL AUTO_INCREMENT, `username` varchar(100) NOT NULL, `expiry` varchar(6) NOT NULL, `contact_id` int(11) NOT NULL, `email` varchar(255) NOT NULL, `password` varchar(100) NOT NULL, `level` int(3) NOT NULL, `active` tinyint(4) NOT NULL DEFAULT '1', PRIMARY KEY (`id`,`email`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; And here's my contact_info table CREATE TABLE IF NOT EXISTS `contact_info` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, `email_address` varchar(255) NOT NULL, `company_name` varchar(255) NOT NULL, `license_number` varchar(255) NOT NULL, `phone` varchar(30) NOT NULL, `fax` varchar(30) NOT NULL, `mobile` varchar(30) NOT NULL, `category` varchar(100) NOT NULL, `country` varchar(20) NOT NULL, `state` varchar(20) NOT NULL, `city` varchar(100) NOT NULL, `postcode` varchar(50) NOT NULL, PRIMARY KEY (`id`,`email_address`), ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; The system uses username to login users.I want to modify it in such a way that it uses email for login. But there's no email_address in users table. I have added foreign key - email in user table(which is email_address in contact_info). How should I query database?

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  • Data Access from single table in sql server 2005 is too slow

    - by Muhammad Kashif Nadeem
    Following is the script of table. Accessing data from this table is too slow. SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO CREATE TABLE [dbo].[Emails]( [id] [int] IDENTITY(1,1) NOT NULL, [datecreated] [datetime] NULL CONSTRAINT [DF_Emails_datecreated] DEFAULT (getdate()), [UID] [nvarchar](250) COLLATE Latin1_General_CI_AS NULL, [From] [nvarchar](100) COLLATE Latin1_General_CI_AS NULL, [To] [nvarchar](100) COLLATE Latin1_General_CI_AS NULL, [Subject] [nvarchar](max) COLLATE Latin1_General_CI_AS NULL, [Body] [nvarchar](max) COLLATE Latin1_General_CI_AS NULL, [HTML] [nvarchar](max) COLLATE Latin1_General_CI_AS NULL, [AttachmentCount] [int] NULL, [Dated] [datetime] NULL ) ON [PRIMARY] Following query takes 50 seconds to fetch data. select id, datecreated, UID, [From], [To], Subject, AttachmentCount, Dated from emails If I include Body and Html in select then time is event worse. indexes are on: id unique clustered From Non unique non clustered To Non unique non clustered Tabls has currently 180000+ records. There might be 100,000 records each month so this will become more slow as time will pass. Does splitting data into two table will solve the problem? What other indexes should be there?

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  • Retrieving data from MySQL in one SQL statement

    - by james.ingham
    Hi all, If I'm getting my data from Mysql like so: $result = $dbConnector->Query("SELECT * FROM branches, businesses WHERE branches.BusinessId = businesses.Id ORDER BY businesses.Name"); $resultNum = $dbConnector->GetNumRows($result); if($resultNum > 0) { for($i=0; $i < $resultNum; $i++) { $row = $dbConnector->FetchArray($result); // $row['businesses.Name']; // $row['branches.Name']; echo $row['Name']; } } Does anyone know how to print the field Name in businesses and how to print the name from branches? My only other alternative is to rename the fields or to call Mysql with two seperate queries. Thanks in advance

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  • MySQL: filling empty fields with zeroes when using GROUP BY

    - by SaltLake
    I've got MySQL table CREATE TABLE cms_webstat ( ID int NOT NULL auto_increment PRIMARY KEY, TIMESTAMP_X timestamp DEFAULT CURRENT_TIMESTAMP, # ... some other fields ... ) which contains statistics about site visitors. For getting visits per hour I use SELECT hour(TIMESTAMP_X) as HOUR , count(*) AS HOUR_STAT FROM cms_webstat GROUP BY HOUR ORDER BY HOUR DESC which gives me | HOUR | HOUR_STAT | | 24 | 15 | | 23 | 12 | | 22 | 9 | | 20 | 3 | | 18 | 2 | | 15 | 1 | | 12 | 3 | | 9 | 1 | | 3 | 5 | | 2 | 7 | | 1 | 9 | | 0 | 12 | And I'd like to get following: | HOUR | HOUR_STAT | | 24 | 15 | | 23 | 12 | | 22 | 9 | | 21 | 0 | | 20 | 3 | | 19 | 0 | | 18 | 2 | | 17 | 0 | | 16 | 0 | | 15 | 1 | | 14 | 0 | | 13 | 0 | | 12 | 3 | | 11 | 0 | | 10 | 0 | | 9 | 1 | | 8 | 0 | | 7 | 0 | | 6 | 0 | | 5 | 0 | | 4 | 0 | | 3 | 5 | | 2 | 7 | | 1 | 9 | | 0 | 12 | How should I modify the query to get such result? Thanks.

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  • How do I locate instances of <CR><LF><LF> in a mysql longtext field

    - by Ilane
    I would like to query my table for how many rows contain one or more instances of <CR><LF><LF>. I can't figure out the correct syntax. I would try LIKE '%<CR><LF><LF>%', but I don't know how to specify these special characters. I did try where mydata REGEXP '%[.CR.][.LF.][.LF.]%', and that didn't get a syntax error but neither did it return any rows. So, I realized I need a way to insert the test data as well! Note: I am using mysql 5.0.

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  • Extreme Portability: OpenJDK 7 and GlassFish 3.1.1 on Power Mac G5!

    - by MarkH
    Occasionally you hear someone grumble about platform support for some portion or combination of the Java product "stack". As you're about to see, this really is not as much of a problem as you might think. Our friend John Yeary was able to pull off a pretty slick feat with his vintage Power Mac G5. In his words: Using a build script sent to me by Kurt Miller, build recommendations from Kelly O'Hair, and the great work of the BSD Port team... I created a new build of OpenJDK 7 for my PPC based system using the Zero VM. The results are fantastic. I can run GlassFish 3.1.1 along with all my enterprise applications. I recently had the opportunity to pick up an old G5 for little money and passed on it. What would I do with it? At the time, I didn't think it would be more than a space-consuming novelty. Turns out...I could have had some fun and a useful piece of hardware at the same time. Maybe it's time to go bargain-hunting again. For more information about repurposing classic Apple hardware and learning a few JDK-related tricks in the process, visit John's site for the full article, available here. All the best,Mark

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  • Get the highest odds from the last update

    - by Frankie Yale
    I have these tables in a PostgreSQL database: bookmakers ----------------------- | id | name | ----------------------- | 1 | Unibet | ----------------------- | 2 | 888 | ----------------------- odds --------------------------------------------------------------------- | id | odds_type | odds_index | bookmaker_id | created_at | --------------------------------------------------------------------- | 1 | 1 | 1.55 | 1 | 2012-06-02 10:30 | --------------------------------------------------------------------- | 2 | 2 | 3.22 | 2 | 2012-06-02 10:30 | --------------------------------------------------------------------- | 3 | X | 3.00 | 1 | 2012-06-02 10:30 | --------------------------------------------------------------------- | 4 | 2 | 1.25 | 1 | 2012-05-27 09:30 | --------------------------------------------------------------------- | 5 | 1 | 2.30 | 2 | 2012-05-27 09:30 | --------------------------------------------------------------------- | 6 | X | 2.00 | 2 | 2012-05-27 09:30 | --------------------------------------------------------------------- What I am trying to query is the following: Give me the 1/X/2 odds from the latest update (created_at) from ALL bookmakers and from that last update, give me the highest odds for each odds_type ('1', '2', 'X'). On my website I display them as: Best odds right now: 1 | X | 2 -------------------- 2.30 | 3.00 | 3.22 I have to first get the latest, because the odds from the update from yesterday are no longer valid. Then from that last update, I have - in this case - 2 odds from 2 different bookmakers, so I need to get the best one for type '1','2','X'. Pseudo SQL would be something like: SELECT MAX(odds_index) WHERE odds_type = '1' ORDER BY created_at DESC, odds_index DESC But that doesn't work, because I would always get the latest odds (and not the highest/best from those latest) I hope I'm making sense.

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