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  • Where should test classes be stored in the project?

    - by limc
    I build all my web projects at work using RAD/Eclipse, and I'm interested to know where do you guys normally store your test's *.class files. All my web projects have 2 source folders: "src" for source and "test" for testcases. The generated *.class files for both source folders are currently placed under WebContent/WEB-INF/classes folder. I want to separate the test *.class files from the src *.class files for 2 reasons:- There's no point to store them in WebContent/WEB-INF/classes and deploy them in production. Sonar and some other static code analysis tools don't produce an accurate static code analysis because it takes account of my crappy yet correct testcase code. So, right now, I have the following output folders:- "src" source folder compiles to WebContent/WEB-INF/classes folder. "test" source folder compiles to target/test-classes folder. Now, I'm getting this warning from RAD:- Broken single-root rule: A project may not contain more than one output folder. So, it seems like Eclipse-based IDEs prefer one project = one output folder, yet it provides an option for me to set up a custom output folder for my additional source folder from the "build path" dialog, and then it barks at me. I know I can just disable this warning myself, but I want to know how you guys handle this. Thanks.

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  • SQL Compact performance on device

    - by Ben M
    My SQL Compact database is very simple, with just three tables and a single index on one of the tables (the table with 200k rows; the other two have less than a hundred each). The first time the .sdf file is used by my Compact Framework application on the target Windows Mobile device, the system hangs for well over a minute while "something" is done to the database: when deployed, the DB is 17 megabytes, and after this first usage, it balloons to 24 megs. All subsequent usage is pretty fast, so I'm assuming there's some sort of initialization / index building going on during this first usage. I'd rather not subject the user to this delay, so I'm wondering what this initialization process is and whether it can be performed before deployment. For now, I've copied the "initialized" database back to my desktop for use in the setup project, but I'd really like to have a better answer / solution. I've tried "full compact / repair" in the VS Database Properties dialog, but this made no difference. Any ideas? For the record, I should add that the database is only read from by the device application -- no modifications are made by that code.

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  • wxPython: MainLoop() seems to hang

    - by BandGap
    Hi all, my problem stems from the use of wxApp as far as I can tell. Inside a litte subroutine I call a wx.MessageDialog to ask for a yes or no. I retrieve the answer an process some stuff acordingly. My example code below actually works (though it might be ugly) except that the Dialog box stays open after hitting one of the buttons... import wx from os import path def HasFile(filename): if path.isfile(filename ): app = wx.App() dial = wx.MessageDialog(None, 'Die Datei "'+filename+'" wurde gefunden.\nSoll sie eingelesen werden?', 'Bitte antworten', wx.YES_NO | wx.YES_DEFAULT | wx.ICON_QUESTION) result = dial.ShowModal() dial.EndModal(retCode=0) dial.Destroy() app.MainLoop() return result == wx.ID_YES else: return False So while the rest of the program does whatever is expected, the box just sits there. It also seems like my calls to matplotlib later on are producing errors (a Tkinter error to be precise), maybe because of the wx stuff? Edit: I tried to end the app with a call to app.Destroy(). This doesn't change the fact that the box is still there. When I issue a app.IsActive() afterwards the whole program exits (almost like a sys.exit())! How come? Edit 2: Adding a wxApp like this isn't a good idea since the other scripts get affected as well. Subsequent plotting commands don't get displayed and I don't know how to fix this. Thus I decided to remove the DialogBox alltogether.

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  • Best "Loading" feedback for ASP.Net?

    - by IP
    So, we have an ASP.Net application - fairly standard - and in there are lots of updatepanels, and postbacks. On some pages we have <ajax:UpdatePanelAnimationExtender ID="ae" runat="server" TargetControlID="updatePanel" BehaviorID="UpdateAnimation"> <Animations> <OnUpdating> <FadeOut Duration="0.1" minimumOpacity=".3" /> </OnUpdating> <OnUpdated> <FadeIn minimumOpacity=".5" Duration="0" /> </OnUpdated> </Animations> </ajax:UpdatePanelAnimationExtender> Which basically whites out the page when a postback is going on (but this clashes with modal dialog grey backgrounds). In some cases we have a progressupdate control which just has a spinny icon in the middle of the page. But none of them seem particularly nice and all a bit clunky. They also require a lot of code in various places around the app. What methods do other people use and find effective?

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  • The proper way to script periodically pulling a page from an https site

    - by DarthShader
    I want to create a command-line script for Cygwin/Bash that logs into a site, navigates to a specific page and compares it with the results of the last run. So far, I have it working with Lynx like so: ----snpipped, just setting variables---- echo "# Command logfile created by Lynx 2.8.5rel.5 (29 Oct 2005) ----snipped the recorded keystrokes------- key Right Arrow key p key Right Arrow key ^U" >> $tmp1 #p, right arrow initiate the page saving #"type" the filename inside the "where to save" dialog for i in $(seq 0 $((${#tmp2} - 1))) do echo "key ${tmp2:$i:1}" >> $tmp1 done #hit enter and quit echo "key ^J key y key q key y " >> $tmp1 lynx -accept_all_cookies -cmd_script=$tmp1 https://thewebpage.com/login diff $tmp2 $oldComp mv $tmp2 $oldComp It definitely does not feel "right": the cmd_script consists of relative user actions instead of specifying the exact link names and actions. So, if anything on the site ever changes, switches places, or a new link is added - I will have to re-create the actions. Also, I can't check for any errors so I can't abort the script if something goes wrong (login failed, etc) Another alternative I have been looking at is Mechanize with Ruby (as a note - I have 0 experience with Ruby). What would be the best way to improve or rewrite this?

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  • Android :WindowManager$BadTockenException on Spinner Click

    - by Miya
    Hi, I have a spinner in my home.class. When I click on the spinner, the process is stopped showing exception that WindowManager$BadTockenException is caught. I am calling this home.class from main.class which extends ActivityGroup. If I am simply run only the home.class, the spinner is showing all items. But the problem is only with calling home.class from main.class. The following are my code. Please tell me why this is happened. main.class public class main extends ActivityGroup { public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); Intent intent=new Intent(this,home.class); View view=getLocalActivityManager().startActivity("1", intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP)).getDecorView(); setContentView(view); } } home.class String[] country={"Please selects","US","INDIA","UK"}; Spinner s2 = (Spinner) findViewById(R.id.spinnerCountry); ArrayAdapter<CharSequence> adapterCountry=new ArrayAdapter(this,android.R.layout.simple_spinner_item,country); adapterCountry.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item); s2.setAdapter(adapterCountry); s2.setOnItemSelectedListener(new OnItemSelectedListener() { public void onItemSelected( AdapterView<?> parent, View view, int position, long id) { countryName=country[position]; } public void onNothingSelected(AdapterView<?> parent) { countryName=country[0]; } }); Stack Thread [<1 main] (Suspended (exception WindowManager$BadTokenException)) AlertDialog(Dialog).show() line: 245 AlertDialog$Builder.show() line: 802 Spinner.performClick() line: 260 View$PerformClick.run() line: 9080 ViewRoot(Handler).handleCallback(Message) line: 587 ViewRoot(Handler).dispatchMessage(Message) line: 92 Looper.loop() line: 123 ActivityThread.main(String[]) line: 3647 Method.invokeNative(Object, Object[], Class, Class[], Class, int, boolean) line: not available [native method] Method.invoke(Object, Object...) line: 507 ZygoteInit$MethodAndArgsCaller.run() line: 839 ZygoteInit.main(String[]) line: 597 NativeStart.main(String[]) line: not available [native method] Thank You....

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  • what is the correct way to force existing activities to reload using the new local

    - by pengwang
    have a settings dialog/activity where I allow the user to change the locale. Within that activity i call Resources res = ctx.getResources(); // Change locale settings on the device DisplayMetrics dm = res.getDisplayMetrics(); android.content.res.Configuration conf = res.getConfiguration(); conf.locale = new Locale(language_code.toLowerCase(), coutry_code.toUpperCase()); res.updateConfiguration(conf, dm); and call onChanged() for my settings ListView... everything changes perfectly. Very nice. Then I hit the back button to go back to the previous activity thinking everything should be switched; nope. Everything is still in the previous locale. So I added the above code in the onResume() of the activity thinking that would do it; nope. Also, when I click the menu button of this activity again (not first time) I do not get called in onCreateOptionsMenu() it just displays the previous menu. My question is what is the correct way to force existing activities to reload using the new local?

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  • $ is not defined

    - by coffeeaddict
    I cannot figure out why it's still not recognizing jQuery syntax when I clearly have included the jQuery library right before my $(document).ready <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" > <head id="Head1"><title> </title></head> <body> <form name="form1" method="post" action="jQueryDialogTest.aspx" id="form1"> <div> <input type="hidden" name="__VIEWSTATE" id="__VIEWSTATE" value="/wEPDwULLTE2MTY2ODcyMjlkZA==" /> </div> <script src="content/js/jquery-1.3.2.min.js" type="text/javascript"></script> <script src="content/js/popup.js" type="text/javascript"></script> <div id="testDialog" winWidth="400" winHeight="500" winResizable="true"> Some test mark-up, should show inside the dialog </div> <div><input type="button" id="invokeDialog" value="Click Me!" /></div> </form> <script type="text/javascript"> $(document).ready(function() { $("input.invokeDialog").click.showDialog("#testDialog"); }); </script> </body> </html>

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  • Best way to build an application based on R?

    - by Prasad Chalasani
    I'm looking for suggestions on how to go about building an application that uses R for analytics, table generation, and plotting. What I have in mind is an application that: displays various data tables in different tabs, somewhat like in Excel, and the columns should be sortable by clicking. takes user input parameters in some dialog windows. displays plots dynamically (i.e. user-input-dependent) either in a tab or in a new pop-up window/frame Note that I am not talking about a general-purpose fron-end/GUI for exploring data with R (like say Rattle), but a specific application. Some questions I'd like to see addressed are: Is an entirely R-based approach even possible ( on Windows ) ? The following passage from the Rattle article in R-Journal intrigues me: It is interesting to note that the first implementation of Rattle actually used Python for implementing the callbacks and R for the statistics, using rpy. The release of RGtk2 allowed the interface el- ements of Rattle to be written directly in R so that Rattle is a fully R-based application If it's better to use another language for the GUI part, which language is best suited for this? I'm looking for a language where it's relatively "painless" to build the GUI, and that also integrates very well with R. From this StackOverflow question How should I do rapid GUI development for R and Octave methods (possibly with Python)? I see that Python + PyQt4 + QtDesigner + RPy2 seems to be the best combo. Is that the consensus ? Anyone have pointers to specific (open source) applications of the type I describe, as examples that I can learn from?

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  • Show only div of the product hovering in category grid with jQuery

    - by Dane
    On Magento, I'm trying to get avalable attributes per product in a new div (show/ hide onmouseover) as soon as I hover a product. Unfortunately, my jQuery code opens every div with the same name. I think, I need to do it with jQuery(this) but I tried it in a 1000 different ways, and it won't work. Maybe, somebody here can help me with a better code. jQuery(function() { jQuery('.slideDiv').hide().data('over', false); jQuery('#hover').hover(function() { jQuery('.slideDiv').fadeIn(); }, function() { // Check if mouse did not go over .dialog before hiding it again var timeOut = setTimeout(function() { if (!jQuery('.slideDiv').data('over')) { jQuery('.slideDiv').fadeOut(); clearTimeout(timeOut); } }, 100); }); // Set data for filtering on mouse events for #hover-here jQuery('.slideDiv').hover(function() { jQuery(this).data('over', true); }, function() { jQuery(this).fadeOut().data('over', false); }); }); The PHP just prints the attributes needed. <a href="#" id="hover">Custom Attributes</a> <div class="slideDiv"> <?php $attrs = $_product->getTypeInstance(true)->getConfigurableAttributesAsArray($_product); foreach($attrs as $attr) { if(0 == strcmp("shoe_size", $attr['attribute_code'])) { $options = $attr['values']; print "Größen:<br />"; foreach($options as $option) { print "{$option['store_label']}<br />"; } } } ?> </div> I added the script to [new link] http://jsfiddle.net/xsxfr/47/ so you can see there, that it is not working like this right now :(.

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  • Using proxy models

    - by smallB
    I've created Proxy model by subclassing QAbstractProxyModel and connected it as a model to my view. I also set up source model for this proxy model. Unfortunately something is wrong because I'm not getting anything displayed on my listView (it works perfectly when I have my model supplied as a model to view but when I supply this proxy model it just doesn't work). Here are some snippets from my code: #ifndef FILES_PROXY_MODEL_H #define FILES_PROXY_MODEL_H #include <QAbstractProxyModel> #include "File_List_Model.h" class File_Proxy_Model: public QAbstractProxyModel { public: explicit File_Proxy_Model(File_List_Model* source_model) { setSourceModel(source_model); } virtual QModelIndex mapFromSource(const QModelIndex & sourceIndex) const { return index(sourceIndex.row(),sourceIndex.column()); } virtual QModelIndex mapToSource(const QModelIndex & proxyIndex) const { return index(proxyIndex.row(),proxyIndex.column()); } virtual int columnCount(const QModelIndex & parent = QModelIndex()) const { return sourceModel()->columnCount(); } virtual int rowCount(const QModelIndex & parent = QModelIndex()) const { return sourceModel()->rowCount(); } virtual QModelIndex index(int row, int column, const QModelIndex & parent = QModelIndex()) const { return createIndex(row,column); } virtual QModelIndex parent(const QModelIndex & index) const { return QModelIndex(); } }; #endif // FILES_PROXY_MODEL_H //and this is a dialog class: Line_Counter::Line_Counter(QWidget *parent) : QDialog(parent), model_(new File_List_Model(this)), proxy_model_(new File_Proxy_Model(model_)), sel_model_(new QItemSelectionModel(proxy_model_,this)) { setupUi(this); setup_mvc_(); } void Line_Counter::setup_mvc_() { listView->setModel(proxy_model_); listView->setSelectionModel(sel_model_); }

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  • Are there any changes in the licensing of Visual Studio 2013 Express editions?

    - by Ramón García-Pérez
    As was going through reading the license.htm file provided as part of the VS2013_RTM_WebExp_ENU.iso offline installation media for the Visual Studio 2013 Express for Web, section 6 reads as follows: 6. PACKAGE MANAGER AND THIRD PARTY SOFTWARE INSTALLATION FEATURES. The software includes the following features (each a “Feature”), each of which enables you to obtain software applications or packages through the Internet from other sources: Extension Manager, New Project Dialog, Web Platform Installer, and Microsoft NuGet-Based Package Manager. Those software applications and packages are offered and distributed in some cases by third parties and in some cases by Microsoft, but each such application or package is under its own license terms. Microsoft is not developing, distributing or licensing any of the third-party applications or packages to you, but instead, as a convenience, enables you to use the Features to access or obtain those applications or packages directly from the third-party application or package providers. By using the Features, you acknowledge and agree that: you are obtaining the applications or packages from such third parties and under separate license terms applicable to each application or package (including, with respect to the package-manager Features, any terms applicable to software dependencies that may be included in the package); MICROSOFT MAKES NO REPRESENTATIONS, WARRANTIES OR GUARANTEES AS TO THE FEED OR GALLERY URL, ANY FEEDS OR GALLERIES FROM SUCH URL, THE INFORMATION CONTAINED THEREIN, OR ANY SOFTWARE APPLICATIONS OR PACKAGES REFERENCED IN OR ACCESSED BY YOU THROUGH SUCH FEEDS OR GALLERIES. MICROSOFT GRANTS YOU NO LICENSE RIGHTS FOR THIRD-PARTY SOFTWARE APPLICATIONS OR PACKAGES THAT ARE OBTAINED USING THE FEATURES. Are there any changes in the licensing of Visual Studio 2013 Express editions? If so, does this means that Visual Studio extensions installation in Express Editions is now allowed? PS: Previous versions of the Express editions did not allow the installation of extensions as per "EULA/TOS" discussed here: Limitations of Visual Studio 2012 Express Desktop

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  • Uninstalling Android Application

    - by Sosukodo
    When I create an Android project in Eclipse and send it to my device for debugging, the app works fine but when I try to uninstall it, I get a strange message. Below are the steps to recreate my problem: Eclipse Version: 4.2.0 Build id: I20120608-1400 ADT Version: 2.0.3 v201208082019-427395 Run Eclipse Click File-New-Project... Select Android/Android Application Project Click Next. Enter Application Name: Test Build SDK: Android 4.1 Minimum Required SDK: API 8 Android 2.2 Enable: Create custom launcher icon / Create project in workspace Click Next thrice. Click Finish. Connect 4.1 Android device to computer via USB. Click Run-Run from menu. Select "Android application" on popup the "Run As" popup. Click Ok. MainActivity application runs on device. Click the Back button on the Android device. Open applications on device and find "MainActivity" app. Long press the MainActivity icon and drag to trash. Here's the puzzling part: Instead of getting a standard Do you want to uninstall this app? I get a dialog with this text: MainActivity is part of the following app: Test Do you want to uninstall this app? Why do I get this message instead of the standard one? Why is MainActivity the name of the app when I specifically stated the name of the app is "Test"?

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  • How to call Java code from Javascript and assign a value to a JSP page?

    - by Frank
    I have the following "form.jsp" program, it generates a drop down list, below the list is a textarea to show the display_name of a selected item, now when user selected a item, it shows the selected item id in the textarea, how to call the DB from my code and get the display_name in the javascript so the result display_name will be shown in the textarea ? <%@ taglib prefix="s" uri="/struts-tags"%> <script type="text/javascript"> function callme(Display_Name) { alert('callme : Display_Name = '+Display_Name); var v=document.getElementById('hiddenValue').value; alert('hiddenValue : v = '+v); document.getElementById('defaultDisplayName').value=Display_Name; } </script> <s:hidden id="pricelist.id" name="pricelist.id" value="%{pricelist.id}"/> <div class="dialog"> <table> <tbody> <s:if test="%{enableProductList}"> <tr class="prop"> <td valign="top" class="name required"><label for="description">Product:</label></td> <td valign="top"> <s:select id="productPrice.product" name="productPrice.product" headerKey="0" headerValue="-- Select Product --" list="products" listKey="id" listValue="name" value="productPrice.product.id" theme="simple" displayName1='value' onchange="callme(value)" /> <s:hidden id="hiddenValue" name="hiddenValue" value="123"/> </td> </tr> </s:if> <tr class="prop"> <td valign="top" class="name"><label for="description">Default Display Name:</label></td> <td valign="top"><s:textarea id="defaultDisplayName" name="defaultDisplayName" theme="simple" readonly="true"/></td> </tr> See attached image for details, in the DB, a product table has the product Id and display_name, I know the Id, how to use Java to get the display_name and plug it into the jsp ?

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  • Cannot create a new VS data connection in Server Explorer

    - by Seventh Element
    I have a local instance of SQL Server 2008 express edition running on my development PC. I'm trying to create a new data connection through Visual Studio Server Explorer. The steps are the following: Right click the "Data Connections" node = Choose Data Source. I select "Microsoft SQL Server" as the data source. The "Add Connection" dialog window appears. I select my local server instance = "Test connection" works fine. I select "AdventureWorks" as the database name = "Test connection" works fine. Next I hit the "Ok" button = Error message: "This server version is not supported. Only servers up to MS SQL Server 2005 are supported." I'm using Visual Studio 2008 Professional Edition. The target framework of the application is ".NET framework 3.5". I have a reference to System.Data (framework v2.0) and cannot find another version of the assembly on my system. Am I referencing the wrong assembly? How can I fix this problem?

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  • Is there a project setting that controls getting to Game Center's Sandbox?

    - by CBGraham
    This is different from the others; it's cool. I know that your Bundle Identifier needs to match your iTunes Connect's version. I know you need to make a new AppleID through your dev app and not through Game Center. Most people get this fixed when they force quit their app and game center and launch theirs first. I am not one of those people. If I take the GKTapper tutorial and use my game's Bundle Identifier as the only change, things are good. On launch, it asks me if I want to use an existing or make a new account. But more importantly, it says * Sandbox *. (Before I log in, mind you; this is not an account problem at all.) Once inside I can see my achievements. If I load my game, I has a sad. On launch I get the same dialog, but it does not say Sandbox. My game is two weeks away from being done after many long months. Moving everything in to a new project is possible, but a pain. So the question is: What magic setting does GKTapper or a new project have that my game that I started in June does not that lets you get to Game Center's Sandbox?

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  • Can I create an activity for a particular task without that task coming to the foreground?

    - by Neil Traft
    Here's my use case: The app starts at a login screen. You enter your credentials and hit the "Login" button. Then a progress dialog appears and you wait for some stuff to download. Once the stuff has downloaded, you are taken to a new activity. Exactly which activity you are taken to depends on the server response. Here's my problem: If you go HOME during this login/download process, at some point in the near future your download will complete and will invoke startActivity(). So then the new activity will be pushed to the foreground, rudely interrupting the user. I can't start the activity before I start the download, because, as I mentioned earlier, the activity I start depends on the result of the download. I would obviously not like to interrupt the user like this. One way to solve this is to refrain from calling startActivity() until the user returns to the app. I can do this by keeping track of the LoginActivity's onStop() and onRestart(). But I'm wondering, is there any way to create the activity while it is in the background? That way the user returns to the app and he is ready to go... otherwise he would have to wait for the new activity to be created (which could take some time because the new activity also has to download and display some data). Update: Guess what? I LIED! I could have sworn that starting this activity was causing it to come to the foreground, but I went back to test it again and the problem has magically disappeared. I tested in both 1.6 and 2.0.1 and both OSes were smart enough not to bring a backgrounded task to the front.

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  • Dismiss android activity displayed as Popup

    - by Sit
    So i have a service, that starts an activity displayed as a Popup thank's to "android:style/Theme.Dialog" This Activity shows a Listview, with a list of application. On each element of the listview, there is a short description of the application, and two buttons. 1 for launching the application 2 for displaying a toast with more informations. Here is the code in my service : it starts the activity Intent intent = new Intent(this, PopUpActivity.class); intent.addFlags(Intent.FLAG_DEBUG_LOG_RESOLUTION); intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK); getApplicationContext().startActivity(intent); this activity uses a custom layout, with a listview, adapted with a custom ArrayAdapter In this adaptater, i've put an action on the start button in order to start the current application Button lanceur = (Button) v.findViewById(R.id.Buttonlancer); lanceur.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { p.start(mcontext); } }); with p.start, i start the application. But now, if i press "back" from the application, i go back to the popup... and i can start another application. I don't want it to be possible. That's why i wish i could dismiss/destroy/finish my PopupActivity, but i can't manage to do it with the code i have.

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  • auto div height

    - by Geln
    <html><head><title>Test</title> <style> .main{width:600px;border:1px solid red; } .main .left{background:lightblue; width:100px;clear:both; float:left;} .main .right{margin-left:100px;background:lightyellow; } </style> </head><body> <div class="main"> <div class="left"> title </div> <div class="right"> <div id="item">item</div> <div id="item">item</div> <div id="item">item</div> <div id="item">item</div> <div id="item">item</div> <div id="item">item</div> <div id="item">item</div> </div> </div> </body></html> How to change the CSS to make the page display like the dialog shows? PS,I think it's a way that to make the "left" div's height auto expend when the height of the "right" div or parent div expend, but I don't know how.

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  • I want to prevent ASP.NET GridView from reacting to the enter button

    - by StephaneT
    I have an ASP.NET page with a gridview control on it with a CommandButton column with delete and select commands active. Pressing the enter key causes the first command button in the gridview to fire, which deletes a row. I don't want this to happen. Can I change the gridview control in a way that it does not react anymore to pressing the enter key? There is a textbox and button on the screen as well. They don't need to be responsive to hitting enter, but you must be able to fill in the textbox. Currently we popup a confirmation dialog to prevent accidental deletes, but we need something better than this. This is the markup for the gridview, as you can see it's inside an asp.net updatepanel (i forgot to mention that, sorry): (I left out most columns and the formatting) <asp:UpdatePanel ID="upContent" runat="server" UpdateMode="Conditional"> <Triggers> <asp:AsyncPostBackTrigger ControlID="btnFilter" /> <asp:AsyncPostBackTrigger ControlID="btnEdit" EventName="Click" /> </Triggers> <ContentTemplate> <div id="CodeGrid" class="Grid"> <asp:GridView ID="dgCode" runat="server"> <Columns> <asp:CommandField SelectImageUrl="~/Images/Select.GIF" ShowSelectButton="True" ButtonType="Image" CancelText="" EditText="" InsertText="" NewText="" UpdateText="" DeleteImageUrl="~/Images/Delete.GIF" ShowDeleteButton="True" /> <asp:BoundField DataField="Id" HeaderText="ID" Visible="False" /> </Columns> </asp:GridView> </div> </ContentTemplate> </asp:UpdatePanel>

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  • Bootstrap stop Modal showing on page load

    - by Subby
    I only want the Modal to show when I click on a certain button. At the moment, the Modal shows itself whenever I load the page. Can someone please tell me where I am going horribly wrong? <a href="#myModal" role="button" class="btn" data-toggle="modal">Launch demo modal</a> <div class="modal" id="myModal" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true"> <div class="modal-header"> <button type="button" class="close" data-dismiss="modal" aria-hidden="true">×</button> <h3 id="myModalLabel">Modal header</h3> </div> <div class="modal-body"> <p>One fine body…</p> </div> <div class="modal-footer"> <button class="btn" data-dismiss="modal" aria-hidden="true">Close</button> <button class="btn btn-primary">Save changes</button> </div> </div> I am using ASP.NET MVC 3 EDIT: I am NOT using any Javascript at the moment.

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  • JQuery modal box form validation

    - by vikitor
    Hi, I was using a view to create an object for my specific project, but now I have to adapt this to another requirements, such as the creation of this object must be integrated in the creation of another one. The thing is, that this object must be created before starting to create the other one, and the way of doing it will be poping up a modal dialog box with JQuery with the form to create it. I've got to adapt the creation and it works fine, except for the validation messages. It is made in the controller like : if (not.NotName.Trim().Length == 0) { ModelState.AddModelError("NotName", "Name is required"); } if (_notification.checkIfExists(not.NotName, not.NotRecID)) { ModelState.AddModelError("NotName", "Notification already exists"); } And before with a normal view it worked fine, but now I'm not able to get the validation messages as I did. How can you get this validation messages thrown by the controller in the Modal Box? Because now when I made a mistake on purpose in the form in order to get the error it doesn't appear. I've seen the error is displayed in the site, because I've seen it on firebug, but it doesn't appear in my model box. How can I retrieve this errors? Do you know any tutorial that could help me with this? Thank you

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  • Why junit ComparisonFailure is not used by assertEquals(Object, Object) ?

    - by Philippe Blayo
    In Junit 4, do you see any drawback to throw a ComparisonFailure instead of an AssertionError when assertEquals(Object, Object) fails ? assertEquals(Object, Object) throws a ComparisonFailure if both expected and actual are String an AssertionError if either is not a String @Test(expected=ComparisonFailure.class ) public void twoString() { assertEquals("a String", "another String"); } @Test(expected=AssertionError.class ) public void oneString() { assertEquals("a String", new Object()); } The two reasons why I ask the question: ComparisonFailure provide far more readable way to spot the differences in dialog box of eclipse or Intellij IDEA (FEST-Assert throws this exception) Junit 4 already use String.valueOf(Object) to build message "expected ... but was ..." (format method invoqued by Assert.assertEquals(message, Object, Object) in junit-4.8.2): static String format(String message, Object expected, Object actual) { ... String expectedString= String.valueOf(expected); String actualString= String.valueOf(actual); if (expectedString.equals(actualString)) return formatted + "expected: " + formatClassAndValue(expected, expectedString) +" but was: " + formatClassAndValue(actual, actualString); else return formatted +"expected:<"+ expectedString +"> but was:<"+ actualString +">"; Isn't it possible in assertEquals(message, Object, Object) to replace fail(format(message, expected, actual)); by throw new ComparisonFailure(message, formatClassAndValue(expectedObject, expectedString), formatClassAndValue(actualObject, actualString)); Do you see any compatibility issue with other tool, any algorithmic problem with that... ?

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  • Is SharePoint a good solution for me?

    - by Pam Bullock
    My company has many branches that use the same software suite that we've written for them. We're looking at SharePoint as a way to open a dialog with them about the software - reviews, change requests (not official ones, just for us to get an idea and for them to discuss amongst themselves what would be helpful). We would also like to utilize the document repository feature and possibly the blog. SharePoint is already available to us if we'd like to use it so that's why we're looking into it. I've done a lot of research and watched a lot of starter tutorials. It seems like it has what we're looking for. For those of you that know it well: Do you think it would be a good solution for us? Do you think it would be overkill? If so, Do you have an alternative suggestion? Are there other aspects of SharePoint that I haven't discovered yet that seems like it would be helpful for what we're doing? I will continue to research online but it's always great to hear the opinion of someone experienced with the product. Thanks so much! Pam

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  • PHP Foreach statement issue. Multiple rows are returned

    - by Daniel Patilea
    I'm a PHP beginner and lately i've been having a problem with my source code. Here it is: <html> <head> <title> Bot </title> <link type="text/css" rel="stylesheet" href="main.css" /> </head> <body> <form action="bot.php "method="post"> <lable>You:<input type="text" name="intrebare"></lable> <input type="submit" name="introdu" value="Send"> </form> </body> </html> <?php //error_reporting(E_ALL & ~E_NOTICE); mysql_connect("localhost", "root", "") or die(mysql_error()); mysql_select_db("robo") or die(mysql_error()); $intrebare=$_POST['intrebare']; $query = "SELECT * FROM dialog where intrebare like '%$intrebare%'"; $result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_array($result) or die(mysql_error()); ?> <div id="history"> <?php foreach($row as $rows){ echo "<b>The robot says: </b><br />"; echo $row['raspuns']; } ?> </div> It returns me the result x6 times. This problem appeared when I've made that foreach because I wanted the results to stuck on the page one by one after every sql querry. Can you please tell me what seems to be the problem? Thanks!

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