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  • DirectX particle system. ConstantBuffer

    - by Liuka
    I'm new in DirectX and I'm making a 2D game. I want to use a particle system to simulate a 3D starfield, so each star has to set its own constant buffer for the vertexshader es. to set it's world matrix. So if i have 500 stars (that move every frame) i need to call 500 times VSsetconstantbuffer, and map/unmap each buffer. with 500 stars i have an average of 220 fps and that's quite good. My bottelneck is Vs/PsSetconstantbuffer. If i dont call this function i have 400 fps(obliviously nothing is display, since i dont set the position of the stars). So is there a method to speed up the render of the particle system?? Ps. I'm using intel integrate graphic (hd 2000-3000). with a nvidia (or amd) gpu will i have the same bottleneck?? If, for example, i dont call setshaderresource i have 10-20 fps more (for 500 objcets), that is not 180.Why does SetConstantBuffer take so long?? LPVOID VSdataPtr = VSmappedResource.pData; memcpy(VSdataPtr, VSdata, CszVSdata); context->Unmap(VertexBuffer, 0); result = context->Map(PixelBuffer, 0, D3D11_MAP_WRITE_DISCARD, 0, &PSmappedResource); if (FAILED(result)) { outputResult.OutputErrorMessage(TITLE, L"Cannot map the PixelBuffer", &result, OUTPUT_ERROR_FILE); return; } LPVOID PSdataPtr = PSmappedResource.pData; memcpy(PSdataPtr, PSdata, CszPSdata); context->Unmap(PixelBuffer, 0); context->VSSetConstantBuffers(0, 1, &VertexBuffer); context->PSSetConstantBuffers(0, 1, &PixelBuffer); this update and set the buffer. It's part of the render method of a sprite class that contains a the vertex buffer and the texture to apply to the quads(it's a 2d game) too. I have an array of 500 stars (sprite setup with a star texture). Every frame: clear back buffer; draw the array of stars; present the backbuffer; draw also call the function update( which calculate the position of the sprite on screen based on a "camera class") Ok, create a vertex buffer with the vertices of each quads(stars) seems to be good, since the stars don't change their "virtual" position; so.... In a particle system (where particles move) it's better to have all the object in only one vertices array, rather then an array of different sprite/object in order to update all the vertices' position with a single setbuffer call. In this case i have to use a dynamic vertex buffer with the vertices positions like this: verticesForQuad={{ XMFLOAT3((float)halfDImensions.x-1+pos.x, (float)halfDImensions.y-1+pos.y, 1.0f), XMFLOAT2(1.0f, 0.0f) }, { XMFLOAT3((float)halfDImensions.x-1+pos.x, -(float)halfDImensions.y-1+pos.y, 1.0f), XMFLOAT2(1.0f, 1.0f) }, { XMFLOAT3(-(float)halfDImensions.x-1+pos.x, (float)halfDImensions.y-1.pos.y, 1.0f), XMFLOAT2(0.0f, 0.0f) }, { XMFLOAT3(-(float)halfDImensions.x-1.pos.x, -(float)halfDImensions.y-1+pos.y, 1.0f), XMFLOAT2(0.0f, 1.0f) }, ....other quads} where halfDimensions is the halfsize in pixel of a texture and pos the virtual position of a star. than create an array of verticesForQuad and create the vertex buffer ZeroMemory(&vertexDesc, sizeof(vertexDesc)); vertexDesc.Usage = D3D11_USAGE_DEFAULT; vertexDesc.BindFlags = D3D11_BIND_VERTEX_BUFFER; vertexDesc.ByteWidth = sizeof(VertexType)* 4*numStars; ZeroMemory(&resourceData, sizeof(resourceData)); resourceData.pSysMem = verticesForQuad; result = device->CreateBuffer(&vertexDesc, &resourceData, &CvertexBuffer); and call each frame Context->IASetVertexBuffers(0, 1, &CvertexBuffer, &stride, &offset); But if i want to add and remove obj i have to recreate the buffer each time, havent i?? There is a faster way? I think i can create a vertex buffer with a max size (es. 10000 objs) and when i update it set only the 250 position (for 250 onjs for example) and pass this number as the vertexCount to the draw function (numObjs*4), or i'm worng

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  • Apache2, making my site publicly available

    - by Shackler
    Hello, I want to make my apache 2 development server public to the internet, it is a Django based website. Here is my apache2 config: <VirtualHost *:80> Alias /media /home/user/myproject/statics Alias /admin_media /home/myuser/django/Django-1.1.1/django/contrib/admin/media WSGIScriptAlias / /home/myuser/myproject/myproject_wsgi.py WSGIDaemonProcess myproject user=myuser group=myuser threads=25 WSGIProcessGroup myproject </VirtualHost> When I do netstat -lntup I get: Proto Recv-Q Send-Q Local Address Foreign Address State PID/Program name tcp 0 0 127.0.0.1:3306 0.0.0.0:* LISTEN - tcp 0 0 0.0.0.0:22 0.0.0.0:* LISTEN - tcp 0 0 127.0.0.1:631 0.0.0.0:* LISTEN - tcp6 0 0 :::80 :::* LISTEN - tcp6 0 0 :::22 :::* LISTEN - tcp6 0 0 ::1:631 :::* LISTEN - udp 0 0 0.0.0.0:5353 0.0.0.0:* - udp 0 0 0.0.0.0:38582 0.0.0.0:* I connect with ADSL thus I am behind a router. For this I have made my computer DMZ enabled to my machine. What can be the problem? When I try to login with my ip, I get my routers config page, when a friend tries to connect to me from internet, he gets "not authorized".

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  • Apache virtualhost - only apply script if file does not exist in document root

    - by Brett Thomas
    Sorry for the newbie apache question. I'm wondering if it's possible to set up the following non-conventional apache virtualhost (for a Django app): -- If a file exists in the DocumentRoot (/var/www) it will be shown. So if /var/www/foo.html exists, then it can be seen at www.example.com/foo.html. -- If file does not exist, it is served via a virtualhost. I'm using mod_wsgi with a WSGIScriptAlias directive that points to a Django app. So if there is no /var/www/bar.html, www.example.com/bar.html will be passed to the Django app, which may or may not be a 404 error. One option is to create an Alias for each individual file/directory, but people want to be able to post a file without adding an alias, and we want to keep the above URL structure for legacy reasons. Simplified Virtualhost is: <VirtualHost *:80> ServerName www.example.com DocumentRoot /var/www WSGIScriptAlias / /path/to/django.wsgi <Directory /path/to/app> Order allow,deny Allow from all </Directory> Alias /hi.html /var/www/hi.html </VirtualHost> The goal is to have www.example.com/hi.html work as above, without the Alias line

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  • Why is lighttpd and fastcgi keeping sending me the *.scgi file instead of the website content?

    - by e-satis
    I have the following config: server.modules = ( "mod_compress", "mod_access", "mod_alias", "mod_rewrite", "mod_redirect", "mod_secdownload", "mod_h264_streaming", "mod_flv_streaming", "mod_accesslog", "mod_auth", "mod_status", "mod_expire", "mod_fastcgi" ) [...] fastcgi.server = ( ".php" => (( "bin-path" => "/usr/bin/php-cgi", "socket" => "/var/tmp/lighttpd/php-fastcgi.socket" + var.PID, "max-procs" => 1, "kill-signal" => 9, "idle-timeout" => 10, "bin-environment" => ( "PHP_FCGI_CHILDREN" => "200", "PHP_FCGI_MAX_REQUESTS" => "1000" ), "/pyapps/essai/blondes.fcgi" => ( "main" => ( "socket" => "/var/tmp/lighttpd/django-fastcgi.socket", ), ), "bin-copy-environment" => ( "PATH", "SHELL", "USER" ), "broken-scriptfilename" => "enable" ))) [...] $HTTP["host"] =~ "(^|www\.)cam\.com(\:[0-9]*)?$" { server.document-root = "/home/cam/web/" accesslog.filename = "/home/cam/log/access.log" server.errorlog = "/home/cam/log/error.log" server.follow-symlink = "enable" # files to check for if .../ is requested server.indexfiles = ( "index.php", "index.html", "index.htm", "index.rb") url.rewrite = ( "^(/blondes/.*)$" => "/pyapps/essai/blondes.fcgi$1" ) } I have the following dir tree: /home/tv/web/ `-- pyapps `-- essai `-- __init__.py `-- blondes.fcgi `-- blondes.pid `-- django-fcgi.py `-- manage.py `-- manage.pyo `-- plop `-- settings.py `-- urls.py No error when restarting lighthttpd. The I run: ./manage.py runfcgi method=prefork socket=/var/tmp/lighttpd/django-fastcgi.socket daemonize=false pidfile=blondes.pid No errors neither. I then go to http://cam.com/blondes/. I offers me to download an empty file. I checked permissions but everything is set to the same user and group, and they work for the PHP site. The file /var/tmp/lighttpd/django-fastcgi.socket exists. When I reload the page, I got no output in error logs, nor in the manage.py runfcgi command. I probably missed something obvious, but what ?

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  • Apache runs in console but not as a service?

    - by danspants
    I have an apache 2.2 server running Django. We have a network drive T: which we need constant access to within our Django app. When running Apache as a service, we cannot access this drive, as far as any django code is concerned the drive does not exist. If I add... <Directory "t:/"> Options Indexes FollowSymLinks MultiViews AllowOverride None Order allow,deny allow from all </Directory> to the httpd.conf file the service no longer runs, but I can start apache as a console and it works fine, Django can find the network drive and all is well. Why is there a difference between the console and the service? Should there be a difference? I have the service using my own log on so in theory it should have the same access as I do. I'm keen to keep it running as a service as it's far less obtrusive when I'm working on the server (unless there's a way to hide the console?). Any help would be most appreciated.

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  • Reporting services 2008: ReportExecution2005.asmx does not exist

    - by Shimrod
    Hi everyone, I'm trying to generate a report directly from the code (to send it by mail after). I make this in a windows service. So here is what I'm doing: Dim rview As New ReportViewer() Dim reportServerAddress As String = "http://server/Reports_client" rview.ServerReport.ReportServerUrl = New Uri(reportServerAddress) Dim paramList As New List(Of Microsoft.Reporting.WinForms.ReportParameter) paramList.Add(New Microsoft.Reporting.WinForms.ReportParameter("param1", t.Value)) paramList.Add(New Microsoft.Reporting.WinForms.ReportParameter("CurrentDate", Date.Now)) Dim reportsDirectory As String = "AppName.Reports" Dim reportPath As String = String.Format("/{0}/{1}", reportsDirectory, reportName) rview.ServerReport.ReportPath = reportPath rview.ServerReport.SetParameters(paramList) 'This is where I get the exception Dim mimeType, encoding, extension, deviceInfo As String Dim streamids As String() Dim warnings As Microsoft.Reporting.WinForms.Warning() deviceInfo = "<DeviceInfo><SimplePageHeaders>True</SimplePageHeaders></DeviceInfo>" Dim format As String = "PDF" Dim bytes As Byte() = rview.ServerReport.Render(format, deviceInfo, mimeType, encoding, extension, streamids, warnings) When debugging this code, I can see it throws a MissingEndpointException where I make the SetParameters(paramList) with this message: The attempt to connect to the report server failed. Check your connection information and that the report server is a compatible version. Looking in the server's log file, I can see this: ui!ReportManager_0-8!878!06/02/2010-11:34:36:: Unhandled exception: System.Web.HttpException: The file '/Reports_client/ReportExecution2005.asmx' does not exist. at System.Web.UI.Util.CheckVirtualFileExists(VirtualPath virtualPath) at System.Web.Compilation.BuildManager.GetVPathBuildResultInternal(VirtualPath virtualPath, Boolean noBuild, Boolean allowCrossApp, Boolean allowBuildInPrecompile) at System.Web.Compilation.BuildManager.GetVPathBuildResultWithNoAssert(HttpContext context, VirtualPath virtualPath, Boolean noBuild, Boolean allowCrossApp, Boolean allowBuildInPrecompile) at System.Web.Compilation.BuildManager.GetVPathBuildResult(HttpContext context, VirtualPath virtualPath, Boolean noBuild, Boolean allowCrossApp, Boolean allowBuildInPrecompile) at System.Web.Compilation.BuildManager.GetVPathBuildResult(HttpContext context, VirtualPath virtualPath) at System.Web.UI.WebServiceParser.GetCompiledType(String inputFile, HttpContext context) at System.Web.Services.Protocols.WebServiceHandlerFactory.GetHandler(HttpContext context, String verb, String url, String filePath) at System.Web.HttpApplication.MapHttpHandler(HttpContext context, String requestType, VirtualPath path, String pathTranslated, Boolean useAppConfig) at System.Web.HttpApplication.MapHandlerExecutionStep.System.Web.HttpApplication.IExecutionStep.Execute() at System.Web.HttpApplication.ExecuteStep(IExecutionStep step, Boolean& completedSynchronously) I didn't find any resource on the web that fits my problem. Does anyone have a clue ? I'm able to view the reports from a web application, so I'm sure the server is running. Thanks in advance.

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  • nhibernate : a different object with the same identifier value was already associated with the sessi

    - by frosty
    I am getting the following error when i tried and save my "Company" entity in my mvc application a different object with the same identifier value was already associated with the session: 2, of entity: I am using an IOC container private class EStoreDependencies : NinjectModule { public override void Load() { Bind<ICompanyRepository>().To<CompanyRepository>().WithConstructorArgument("session", NHibernateHelper.OpenSession()); } } My CompanyRepository public class CompanyRepository : ICompanyRepository { private ISession _session; public CompanyRepository(ISession session) { _session = session; } public void Update(Company company) { using (ITransaction transaction = _session.BeginTransaction()) { _session.Update(company); transaction.Commit(); } } } And Session Helper public class NHibernateHelper { private static ISessionFactory _sessionFactory; const string SessionKey = "MySession"; private static ISessionFactory SessionFactory { get { if (_sessionFactory == null) { var configuration = new Configuration(); configuration.Configure(); configuration.AddAssembly(typeof(UserProfile).Assembly); configuration.SetProperty(NHibernate.Cfg.Environment.ConnectionStringName, System.Environment.MachineName); _sessionFactory = configuration.BuildSessionFactory(); } return _sessionFactory; } } public static ISession OpenSession() { var context = HttpContext.Current; //.GetCurrentSession() if (context != null && context.Items.Contains(SessionKey)) { //Return already open ISession return (ISession)context.Items[SessionKey]; } else { //Create new ISession and store in HttpContext var newSession = SessionFactory.OpenSession(); if (context != null) context.Items[SessionKey] = newSession; return newSession; } } } My MVC Action [HttpPost] public ActionResult Edit(EStore.Domain.Model.Company company) { if (company.Id > 0) { _companyRepository.Update(company); _statusResponses.Add(StatusResponseHelper.Create(Constants .RecordUpdated(), StatusResponseLookup.Success)); } else { company.CreatedByUserId = currentUserId; _companyRepository.Add(company); } var viewModel = EditViewModel(company.Id, _statusResponses); return View("Edit", viewModel); }

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  • log4j:WARN No appenders could be found for logger in web.xml

    - by cometta
    I already put the log4jConfigLocation in web.xml, but still, i get warning log4j:WARN No appenders could be found for logger (org.springframework.web.context.ContextLoader). log4j:WARN Please initialize the log4j system properly. what did i missed out? <context-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/applicationContext.xml </param-value> </context-param> <context-param> <param-name>log4jConfigLocation</param-name> <param-value>/WEB-INF/classes/log4j.properties</param-value> </context-param> <listener> <listener-class>org.springframework.web.util.Log4jConfigListener</listener-class> </listener> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <servlet> <servlet-name>suara2</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>suara2</servlet-name> <url-pattern>/*</url-pattern> </servlet-mapping>

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  • ASP.net MVC HttpException strange file not found

    - by Paddy
    I'm running asp.net MVC site on IIS6 - I've edited my routing to look like the following: routes.MapRoute( "Default", "{controller}.aspx/{action}/{id}", new { controller = "Home", action = "Index", id = "" } ); routes.MapRoute( "Root", "", new { controller = "Home", action = "Index", id = "" } ); So all my urls now contain .aspx (as per one of the solutions from Phil Haack). Now, I catch all unhandled exceptions using Elmah, and for almost every page request, I get the following error caught by Elmah, that I never see on the front end (everything works perfectly): System.Web.HttpException: The file '/VirtualDirectoryName/Home.aspx' does not exist. System.Web.HttpException: The file '/VirtualDirectoryName/Home.aspx' does not exist. at System.Web.UI.Util.CheckVirtualFileExists(VirtualPath virtualPath) at System.Web.Compilation.BuildManager.GetVPathBuildResultInternal(VirtualPath virtualPath, Boolean noBuild, Boolean allowCrossApp, Boolean allowBuildInPrecompile) at System.Web.Compilation.BuildManager.GetVPathBuildResultWithNoAssert(HttpContext context, VirtualPath virtualPath, Boolean noBuild, Boolean allowCrossApp, Boolean allowBuildInPrecompile) at System.Web.Compilation.BuildManager.GetVirtualPathObjectFactory(VirtualPath virtualPath, HttpContext context, Boolean allowCrossApp, Boolean noAssert) at System.Web.Compilation.BuildManager.CreateInstanceFromVirtualPath(VirtualPath virtualPath, Type requiredBaseType, HttpContext context, Boolean allowCrossApp, Boolean noAssert) at System.Web.UI.PageHandlerFactory.GetHandlerHelper(HttpContext context, String requestType, VirtualPath virtualPath, String physicalPath) at System.Web.UI.PageHandlerFactory.System.Web.IHttpHandlerFactory2.GetHandler(HttpContext context, String requestType, VirtualPath virtualPath, String physicalPath) at System.Web.HttpApplication.MapHttpHandler(HttpContext context, String requestType, VirtualPath path, String pathTranslated, Boolean useAppConfig) at System.Web.HttpApplication.MapHandlerExecutionStep.System.Web.HttpApplication.IExecutionStep.Execute() at System.Web.HttpApplication.ExecuteStep(IExecutionStep step, Boolean& completedSynchronously) There is a Home controller, and it should be found, but I'm not sure a) where this is being called from, and b) why I don't see this error on the front end. Any ideas? Edited with answer: I think the answer for this can be found in this question: http://stackoverflow.com/questions/34194/asp-net-mvc-on-iis6

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  • How do I copy a python function to a remote machine and then execute it?

    - by Hugh
    I'm trying to create a construct in Python 3 that will allow me to easily execute a function on a remote machine. Assuming I've already got a python tcp server that will run the functions it receives, running on the remote server, I'm currently looking at using a decorator like @execute_on(address, port) This would create the necessary context required to execute the function it is decorating and then send the function and context to the tcp server on the remote machine, which then executes it. Firstly, is this somewhat sane? And if not could you recommend a better approach? I've done some googling but haven't found anything that meets these needs. I've got a quick and dirty implementation for the tcp server and client so fairly sure that'll work. I can get a string representation the function (e.g. func) being passed to the decorator by import inspect string = inspect.getsource(func) which can then be sent to the server where it can be executed. The problem is, how do I get all of the context information that the function requires to execute? For example, if func is defined as follows, import MyModule def func(): result = MyModule.my_func() MyModule will need to be available to func either in the global context or funcs local context on the remote server. In this case that's relatively trivial but it can get so much more complicated depending on when and how import statements are used. Is there an easy and elegant way to do this in Python? The best I've come up with at the moment is using the ast library to pull out all import statements, using the inspect module to get string representations of those modules and then reconstructing the entire context on the remote server. Not particularly elegant and I can see lots of room for error. Thanks for your time

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  • sqlalchemy date type in 0.6 migration using mssql

    - by nosklo
    I'm connection to mssql server through pyodbc, via FreeTDS odbc driver, on linux ubuntu 10.04. Sqlalchemy 0.5 uses DATETIME for sqlalchemy.Date() fields. Now Sqlalchemy 0.6 uses DATE, but sql server 2000 doesn't have a DATE type. How can I make DATETIME be the default for sqlalchemy.Date() on sqlalchemy 0.6 mssql+pyodbc dialect? I'd like to keep it as clean as possible. Here's code to reproduce the issue: import sqlalchemy from sqlalchemy import Table, Column, MetaData, Date, Integer, create_engine engine = create_engine( 'mssql+pyodbc://sa:sa@myserver/mydb?driver=FreeTDS') m = MetaData(bind=engine) tb = sqlalchemy.Table('test_date', m, Column('id', Integer, primary_key=True), Column('dt', Date()) ) tb.create() And here is the traceback I'm getting: Traceback (most recent call last): File "/tmp/teste.py", line 15, in <module> tb.create() File "/home/nosklo/.local/lib/python2.6/site-packages/sqlalchemy/schema.py", line 428, in create bind.create(self, checkfirst=checkfirst) File "/home/nosklo/.local/lib/python2.6/site-packages/sqlalchemy/engine/base.py", line 1647, in create connection=connection, **kwargs) File "/home/nosklo/.local/lib/python2.6/site-packages/sqlalchemy/engine/base.py", line 1682, in _run_visitor **kwargs).traverse_single(element) File "/home/nosklo/.local/lib/python2.6/site-packages/sqlalchemy/sql/visitors.py", line 77, in traverse_single return meth(obj, **kw) File "/home/nosklo/.local/lib/python2.6/site-packages/sqlalchemy/engine/ddl.py", line 58, in visit_table self.connection.execute(schema.CreateTable(table)) File "/home/nosklo/.local/lib/python2.6/site-packages/sqlalchemy/engine/base.py", line 1157, in execute params) File "/home/nosklo/.local/lib/python2.6/site-packages/sqlalchemy/engine/base.py", line 1210, in _execute_ddl return self.__execute_context(context) File "/home/nosklo/.local/lib/python2.6/site-packages/sqlalchemy/engine/base.py", line 1268, in __execute_context context.parameters[0], context=context) File "/home/nosklo/.local/lib/python2.6/site-packages/sqlalchemy/engine/base.py", line 1367, in _cursor_execute context) File "/home/nosklo/.local/lib/python2.6/site-packages/sqlalchemy/engine/base.py", line 1360, in _cursor_execute context) File "/home/nosklo/.local/lib/python2.6/site-packages/sqlalchemy/engine/default.py", line 277, in do_execute cursor.execute(statement, parameters) sqlalchemy.exc.ProgrammingError: (ProgrammingError) ('42000', '[42000] [FreeTDS][SQL Server]Column or parameter #2: Cannot find data type DATE. (2715) (SQLExecDirectW)') '\nCREATE TABLE test_date (\n\tid INTEGER NOT NULL IDENTITY(1,1), \n\tdt DATE NULL, \n\tPRIMARY KEY (id)\n)\n\n' ()

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  • java.io.FileNotFoundException: /target/test.log

    - by sword101
    Greetings all I am using Apache Camel and Apache CXF in this example: http://camel.apache.org/better-jms-transport-for-cxf-webservice-using-apache-camel.data/cxfcamelexample.zip I followed the readme and when tried to run the client & server classes i got this exception: log4j:ERROR setFile(null,true) call failed. java.io.FileNotFoundException: /target/test.log (No such file or directory) at java.io.FileOutputStream.openAppend(Native Method) at java.io.FileOutputStream.<init>(FileOutputStream.java:177) at java.io.FileOutputStream.<init>(FileOutputStream.java:102) at org.apache.log4j.FileAppender.setFile(FileAppender.java:289) at org.apache.log4j.FileAppender.activateOptions(FileAppender.java:163) at org.apache.log4j.config.PropertySetter.activate(PropertySetter.java:256) at org.apache.log4j.config.PropertySetter.setProperties(PropertySetter.java:132) at org.apache.log4j.config.PropertySetter.setProperties(PropertySetter.java:96) at org.apache.log4j.PropertyConfigurator.parseAppender(PropertyConfigurator.java:654) at org.apache.log4j.PropertyConfigurator.parseCategory(PropertyConfigurator.java:612) at org.apache.log4j.PropertyConfigurator.configureRootCategory(PropertyConfigurator.java:509) at org.apache.log4j.PropertyConfigurator.doConfigure(PropertyConfigurator.java:415) at org.apache.log4j.PropertyConfigurator.doConfigure(PropertyConfigurator.java:441) at org.apache.log4j.helpers.OptionConverter.selectAndConfigure(OptionConverter.java:470) at org.apache.log4j.LogManager.<clinit>(LogManager.java:122) at org.apache.log4j.Logger.getLogger(Logger.java:104) at org.apache.commons.logging.impl.Log4JLogger.getLogger(Log4JLogger.java:283) at org.apache.commons.logging.impl.Log4JLogger.<init>(Log4JLogger.java:108) at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:39) at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:27) at java.lang.reflect.Constructor.newInstance(Constructor.java:513) at org.apache.commons.logging.impl.LogFactoryImpl.createLogFromClass(LogFactoryImpl.java:1040) at org.apache.commons.logging.impl.LogFactoryImpl.discoverLogImplementation(LogFactoryImpl.java:838) at org.apache.commons.logging.impl.LogFactoryImpl.newInstance(LogFactoryImpl.java:601) at org.apache.commons.logging.impl.LogFactoryImpl.getInstance(LogFactoryImpl.java:333) at org.apache.commons.logging.impl.LogFactoryImpl.getInstance(LogFactoryImpl.java:307) at org.apache.commons.logging.LogFactory.getLog(LogFactory.java:645) at org.springframework.context.support.AbstractApplicationContext.<init>(AbstractApplicationContext.java:146) at org.springframework.context.support.AbstractRefreshableApplicationContext.<init>(AbstractRefreshableApplicationContext.java:84) at org.springframework.context.support.AbstractRefreshableConfigApplicationContext.<init>(AbstractRefreshableConfigApplicationContext.java:59) at org.springframework.context.support.AbstractXmlApplicationContext.<init>(AbstractXmlApplicationContext.java:58) at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:136) at org.springframework.context.support.ClassPathXmlApplicationContext.<init>(ClassPathXmlApplicationContext.java:93) at com.example.customerservice.impl.CustomerServiceClient.main(CustomerServiceClient.java:34) so any ideas, how to solve this exception ?

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  • OpenEjb DeploymentLoader.getWebDescriptors NullPointerException

    - by jwmajors81
    I am currently getting the following error when I try to startup an EAR that includes OpenEJB. The error is: java.lang.NullPointerException at org.apache.openejb.config.DeploymentLoader.getWebDescriptors(DeploymentLoader.java:1057) at org.apache.openejb.config.DeploymentLoader.discoverModuleType(DeploymentLoader.java:1162) at org.apache.openejb.config.DeploymentsResolver.processUrls(DeploymentsResolver.java:294) at org.apache.openejb.config.DeploymentsResolver.loadFromClasspath(DeploymentsResolver.java:248) at org.apache.openejb.spring.ClassPathApplication.loadApplications(ClassPathApplication.java:56) at org.apache.openejb.spring.AbstractApplication.deployApplication(AbstractApplication.java:106) at org.apache.openejb.spring.OpenEJB.deployApplication(OpenEJB.java:342) at org.apache.openejb.spring.AbstractApplication.start(AbstractApplication.java:94) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:79) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:618) at org.springframework.beans.factory.annotation.InitDestroyAnnotationBeanPostProcessor$LifecycleElement.invoke(InitDestroyAnnotationBeanPostProcessor.java:340) The environment consists of: - Spring 3.0 - OpenEJB 3.1 - WebSphere 6.1 (Without EJB/Web Service feature packs) - OpenEJB-Spring jar The app-config.xml that configures Spring and OpenEJB looks like: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xmlns:p="http://www.springframework.org/schema/p" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd" Also please note that I do have a JUnit test that runs against the app-config.xml specified above that can successfully load the application context file. It is just when I deploy it to WebSphere I encounter the error provided at the beginning of this message. Any assistance would be greatly appreciated. Thanks, Jeremy

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  • Idiomatic default sort using WCF RIA, EF4, Silverlight?

    - by Duncan Bayne
    I've got two Silverlight 4.0 ComboBoxes; the second displays the children of the entity selected in the first: <ComboBox Name="cmbThings" ItemsSource="{Binding Path=Things,Mode=TwoWay}" DisplayMemberPath="Name" SelectionChanged="CmbThingsSelectionChanged" /> <ComboBox Name="cmbChildThings" ItemsSource="{Binding Path=SelectedThing.ChildThings,Mode=TwoWay}" DisplayMemberPath="Name" /> The code behind the view provides a (simple, hacky) way to databind those ComboBoxes, by loading Entity Framework 4.0 entities through a WCF RIA service: public EntitySet<Thing> Things { get; private set; } public Thing SelectedThing { get; private set; } protected override void OnNavigatedTo(NavigationEventArgs e) { var context = new SortingDomainContext(); context.Load(context.GetThingsQuery()); context.Load(context.GetChildThingsQuery()); Things = context.Things; DataContext = this; } private void CmbThingsSelectionChanged(object sender, SelectionChangedEventArgs e) { SelectedThing = (Thing) cmbThings.SelectedItem; if (PropertyChanged != null) { PropertyChanged.Invoke(this, new PropertyChangedEventArgs("SelectedThing")); } } public event PropertyChangedEventHandler PropertyChanged; What I'd like to do is have both combo boxes sort their contents alphabetically, and I'd like to specify that behaviour in the XAML if at all possible. Could someone please tell me what is the idiomatic way of doing this with the SL4 / EF4 / WCF RIA technology stack?

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  • iPhone - return from an NSOperation

    - by lostInTransit
    Hi I am using a subclass of NSOperation to do some background processes. I want the operation to be cancelled when the user clicks a button. Here's what my NSOperation subclass looks like - (id)init{ self = [super init]; if(self){ //initialization code goes here _isFinished = NO; _isExecuting = NO; } return self; } - (void)start { if (![NSThread isMainThread]) { [self performSelectorOnMainThread:@selector(start) withObject:nil waitUntilDone:NO]; return; } [self willChangeValueForKey:@"isExecuting"]; _isExecuting = YES; [self didChangeValueForKey:@"isExecuting"]; //operation goes here } - (void)finish{ //releasing objects here [self willChangeValueForKey:@"isExecuting"]; [self willChangeValueForKey:@"isFinished"]; _isExecuting = NO; _isFinished = YES; [self didChangeValueForKey:@"isExecuting"]; [self didChangeValueForKey:@"isFinished"]; } - (void)cancel{ [self willChangeValueForKey:@"isCancelled"]; [self didChangeValueForKey:@"isCancelled"]; [self finish]; } And this is how I am adding objects of this class to a queue and listening for KVO notifications operationQueue = [[NSOperationQueue alloc] init]; [operationQueue setMaxConcurrentOperationCount:5]; [operationQueue addObserver:self forKeyPath:@"operations" options:0 context:&OperationsChangedContext]; - (void)observeValueForKeyPath:(NSString *)keyPath ofObject:(id)object change:(NSDictionary *)change context:(void *)context { if (context == &OperationsChangedContext) { NSLog(@"Queue size: %u", [[operationQueue operations] count]); } else { [super observeValueForKeyPath:keyPath ofObject:object change:change context:context]; } } To cancel an operation (on a button click for instance), I tried calling -cancel but it doesn't make a difference. Also tried calling -finish but even that doesn't change anything. Every time I add an operation to the queue, the queue size only increases. finish is called (checked using NSLog statements) but it doesn't really end the operation. I'm still not very confident I'm doing this right Can someone please tell me where I am going wrong? Thanks a lot

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  • Jersey / ServletContext and resource loading on startup.

    - by Raphael Jolivet
    Hello, I'm kind of new in web development with Java. I am developing a web service and I've chosen REST / Jersey for it. I want to init some stuff on startup of the service and to keep them all along the life of the service. First question : Is the constructor of the Jersey Servlet a good place to do that ? Basically, what I want to do is to load a config.ini file located in my WEB-INF directory. Following this help, I understand I need a ServletContext to load my file as a resource. However, it is not clear to me how to get this ServletContext in a Jersey Servlet, as it is not really an instance of a servlet, but rather a POJO with some annotations. I wanted to try this tip, but the attribute "context" is null in the constructor. I think that Jersey might populate it after the constructor. Right ? So how is the right way to do this ? Here is my code so far : /** Main REST servlet */ @Path("/") public class Servlet { // ---------------------------------------------------- // Constants // ---------------------------------------------------- static private final String CONFIG_PATH = "/WEB-INF/config.ini"; // ---------------------------------------------------- // Attributes // ---------------------------------------------------- /** Context */ @Context ServletContext context; // ---------------------------------------------------- // Constructor // ---------------------------------------------------- /** Init the servlet */ public Servlet() { // Load config.ini from WEB-INF Config.config = new Config( this.context.getResourceAsStream(CONFIG_PATH)); // FAIL! this.context is null ... } // ---------------------------------------------------- // URI Handlers // ---------------------------------------------------- /** Welcome page */ @GET @Path("/") @Produces(MediaType.TEXT_HTML) public String welcome() { return "<h1>Hi there.</h1>"; } } Any help would be much appreciated. Thanks in advance, Raphael

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  • issue in property file

    - by devuser
    I want to load the property file when tomcat is starting.so I'm using servletContextListener to do that and i can get values of property file to my web application. But i want to keep the same value after changing the property file once log into web application.But when i change the value of property file and log into system again it change the value to new one.I want to keep the same value that loaded when tomcat was starting.how can i implement this? My coding is as below import javax.servlet.*; import java.io.IOException; import java.util.Properties; import java.util.logging.Level; import java.util.logging.Logger; import java.io.*; import java.util.ResourceBundle; public final class sysProperties implements javax.servlet.ServletContextListener { private static Properties props = new Properties(); private static String file_name = "com/util/contact.properties"; public addSystemProperties() { } public void contextInitialized(ServletContextEvent servletContextEvent) { // Get the context ServletContext servletContext = servletContextEvent.getServletContext(); // Set a context attribute try { // props.load(servletContext.getResourceAsStream(file_name)); props.load(getClass().getClassLoader().getResourceAsStream(file_name)); System.out.println(" Application X is starting"); servletContext.setAttribute("h1",props.getProperty("home.h1")); servletContext.setAttribute("h2",props.getProperty("home.h2")); System.out.println("h1"+servletContext.getAttribute("h1")); System.out.println("h2"+ servletContext.getAttribute("h2")); ; } catch (Exception e) { System.out.println(" Error setting context attribute: " + e.getMessage()); } } public void contextDestroyed(ServletContextEvent servletContextEvent) { // Get the context ServletContext servletContext = servletContextEvent.getServletContext(); // Output the context variable we set earlier System.out.println(" Application X is shutting down"); System.out.println(" Value of h1 is: " + servletContext.getAttribute("h1")); System.out.println(" Value of h2 is: " + servletContext.getAttribute("h2")); // Clean up (not really necessary as the context is being destroyed, but let's be neat) servletContext.removeAttribute(props.getProperty("h1")); servletContext.removeAttribute(props.getProperty("h2")); } }

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  • Image animation over CGContextDrawPDFPage

    - by BittenApple
    I'm modifying the QuartzDemo sample app from Apple. In QuartzViewController.m I have modifications (by DyingCactus) which replac the back button and add a method to handle the back button press as follows: -(void)viewDidLoad { // Add the QuartzView [scrollView addSubview:self.quartzView]; //add custom back button if this is the PDF view... if ([self.quartzView isKindOfClass:[QuartzPDFView class]]) { self.navigationItem.leftBarButtonItem = [[UIBarButtonItem alloc] initWithTitle:@"QuartzDemo" style:UIBarButtonItemStyleBordered target:self action:@selector(myBackButtonHandler:)]; } } - (void)myBackButtonHandler:(id)sender { [self.quartzView setFrame:CGRectMake(150, -200, 100, 200)]; [UIView beginAnimations:nil context:nil]; [UIView setAnimationDelegate:self]; [UIView setAnimationDidStopSelector:@selector(animationDidStop:finished:context:)]; [UIView setAnimationDuration:1.0]; [self.quartzView setFrame:CGRectMake(150, 0, 100, 200)]; [UIView commitAnimations]; } - (void)animationDidStop:(NSString *)animationID finished:(NSNumber *)finished context:(void *)context { [self.navigationController popViewControllerAnimated:YES]; } I have a PNG image in resources folder called "bookmark.png" and would like to have that image animate as in animation in the example above. The image can be loaded in an UImageview or something and lets say that I have one called bookmark. How do I call that instead of self.quartzview in this part of code: [self.quartzView setFrame:CGRectMake(150, -200, 100, 200)]; [UIView beginAnimations:nil context:nil]; [UIView setAnimationDelegate:self]; [UIView setAnimationDidStopSelector:@selector(animationDidStop:finished:context:)]; [UIView setAnimationDuration:1.0]; [self.quartzView setFrame:CGRectMake(150, 0, 100, 200)]; [UIView commitAnimations];

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  • Duplicate method 'ProcessRequest' in ASPX

    - by Mauricio Scheffer
    I'm trying to code ASP.NET MVC views (WebForms view engine) in F#. I can already write regular ASP.NET WebForms ASPX and it works ok, e.g. <%@ Page Language="F#" %> <% for i in 1..2 do %> <%=sprintf "%d" i %> so I assume I have everything in my web.config correctly set up. However, when I make the page inherit from ViewPage: <%@ Page Language="F#" Inherits="System.Web.Mvc.ViewPage" %> I get this error: Compiler Error Message: FS0442: Duplicate method. The abstract method 'ProcessRequest' has the same name and signature as an abstract method in an inherited type. The problem seems to be this piece of code generated by the F# CodeDom provider: [<System.Diagnostics.DebuggerNonUserCodeAttribute>] abstract ProcessRequest : System.Web.HttpContext -> unit [<System.Diagnostics.DebuggerNonUserCodeAttribute>] default this.ProcessRequest (context:System.Web.HttpContext) = let mutable context = context base.ProcessRequest(context) |> ignore when I change the Page directive to use C# instead, the generated code is: [System.Diagnostics.DebuggerNonUserCodeAttribute()] public new virtual void ProcessRequest(System.Web.HttpContext context) { base.ProcessRequest(context); } which of course works fine and AFAIK is not semantically the same as the generated F# code. I'm using .NET 4.0.30319.1 (RTM) and MVC 2 RTM

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  • Google Javascript v8 - multithreading

    - by willem
    Hi guys Suppose I have the following piece of code bool run (void) { HandleScope hande_scope; Handle<String> source; Local<Script> script; Persistent<Context> context; context = Context::New(); Context::Scope context_scope(context); script = Script::Compile("var a = 1; var b = 2;"); Local<Value> result = script->Run(); if (result.IsEmpty()) return false; else return true; } Is it true that one cannot execute this code using multiple threads? It seems like HandleScope is not designed to be used in multithreaded applications. I can use the v8::Locker and v8::Unlocker methodes but that would always give me execution traces as this: t1: a = 1 t1: b = 2 t2: a = 1 t2: b = 2 I hope someone can give me a hint on getting this code multithreaded so that a possible execution trace could like this: t1: a = 1 t2: a = 1 t1: b = 2 t2: b = 2 Thanks already in advance! Willem -- EDIT -- So I guess that this question has no answer :)

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  • Send a public broadcast from an AppWidget in Android

    - by greve
    I have a widget for a music player and want to be able to send broadcasts when pushing the different buttons. What I want to do is when a button is pushed, the widget sends a public broadcast to another BroadcastReceiver so it can handle the different actions. In my activity class with the BroadcastReceiver: private BroadcastReceiver broadcastReceiver = new BroadcastReceiver() { @Override public void onReceive(Context context, Intent intent) { String action = intent.getAction(); if (action.equals(Constants.ACTION_NEXT)) { Log.d("RECEIVER", "ACTION_NEXT"); } } }; @Override protected void onStart() { super.onStart(); IntentFilter filter = new IntentFilter(); //Widget actions filter.addAction(Constants.ACTION_NEXT); registerReceiver(broadcastReceiver, new IntentFilter(filter)); } In my Widget: public void onUpdate(Context context, AppWidgetManager appWidgetManager, int[] appWidgetIds) { RemoteViews views = new RemoteViews(context.getPackageName(), R.layout.widget); PendingIntent pendingIntent = PendingIntent.getBroadcast(context, 0, new Intent(Constants.ACTION_NEXT), 0); views.setOnClickPendingIntent(R.id.WidgetNextButton, pendingIntent); appWidgetManager.updateAppWidget(appWidgetId, views); } Any help or other solutions are very much appreciated!

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  • Why ClassCastException on JMS ConnectionFactory lookup in JNDI?

    - by Derek Mahar
    What might be the cause of the following ClassCastException in a standalone JMS client application when it attempts to retrieve a connection factory from the JNDI provider? Exception in thread "main" java.lang.ClassCastException: javax.naming.Reference cannot be cast to javax.jms.ConnectionFactory Here is an abbreviated version of the JMS client that includes only its start() and stop() methods. The exception occurs on the first line in method start() which attempts to retrieve the connection factory from the JNDI provider, a remote LDAP server. The JMS connection factory and destination objects are on a remote JMS server. class JmsClient { private ConnectionFactory connectionFactory; private Connection connection; private Session session; private MessageConsumer consumer; private Topic topic; public void stop() throws JMSException { consumer.close(); session.close(); connection.close(); } public void start(Context context, String connectionFactoryName, String topicName) throws NamingException, JMSException { // ClassCastException occurs when retrieving connection factory. connectionFactory = (ConnectionFactory) context.lookup(connectionFactoryName); connection = connectionFactory.createConnection("username","password"); session = connection.createSession(false, Session.AUTO_ACKNOWLEDGE); topic = (Topic) context.lookup(topicName); consumer = session.createConsumer(topic); connection.start(); } private static Context getInitialContext() throws NamingException, IOException { String filename = "context.properties"; Properties props = new Properties(); props.load(new FileInputStream(filename)); return new InitialContext(props); } }

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  • How do I implement repository pattern and unit of work when dealing with multiple data stores?

    - by Jason
    I have a unique situation where I am building a DDD based system that needs to access both Active Directory and a SQL database as persistence. Initially this wasnt a problem because our design was setup where we had a unit of work that looked like this: public interface IUnitOfWork { void BeginTransaction() void Commit() } and our repositories looked like this: public interface IRepository<T> { T GetByID() void Save(T entity) void Delete(T entity) } In this setup our load and save would handle the mapping between both data stores because we wrote it ourselves. The unit of work would handle transactions and would contain the Linq To SQL data context that the repositories would use for persistence. The active directory part was handled by a domain service implemented in infrastructure and consumed by the repositories in each Save() method. Save() was responsible with interacting with the data context to do all the database operations. Now we are trying to adapt it to entity framework and take advantage of POCO. Ideally we would not need the Save() method because the domain objects are being tracked by the object context and we would just need to add a Save() method on the unit of work to have the object context save the changes, and a way to register new objects with the context. The new proposed design looks more like this: public interface IUnitOfWork { void BeginTransaction() void Save() void Commit() } public interface IRepository<T> { T GetByID() void Add(T entity) void Delete(T entity) } This solves the data access problem with entity framework, but does not solve the problem with our active directory integration. Before, it was in the Save() method on the repository, but now it has no home. The unit of work knows nothing other than the entity framework data context. Where should this logic go? I argue this design only works if you only have one data store using entity framework. Any ideas how to best approach this issue? Where should I put this logic?

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  • Stall in animation

    - by tech74
    Hi , I am using this code from this site http://ramin.firoozye.com/2009/09/29/semi-modal-transparent-dialogs-on-the-iphone/ to show a modal view and remove it. It displays fine ie drops in from the top but when being removed it stalls just on its way out just for a fraction of second but its noticeable how do i get rid of the stall. The view i am showing is view of a viewcontroller which is a memeber of the parent viewcontroller so i call methods like this to display [self showModal:self.modalController.view] to hide [self hideModal:self.modalController.view]; (void) showModal:(UIView*) modalView { UIWindow* mainWindow = (((SessionTalkAppDelegate*) [UIApplication sharedApplication].delegate).window); //CGPoint middleCenter = modalView.center; CGPoint middleCenter = CGPointMake(160, 205); CGSize offSize = [UIScreen mainScreen].bounds.size; //CGPoint offScreenCenter = CGPointMake(offSize.width / 2.0, offSize.height * 1.5); CGPoint offScreenCenter = CGPointMake(offSize.width / 2.0, -100); // start from top modalView.center = offScreenCenter; // we start off-screen [mainWindow addSubview:modalView]; // Show it with a transition effect [UIView beginAnimations:nil context:nil]; [UIView setAnimationDuration:0.3]; // animation duration in seconds [UIView setAnimationCurve:UIViewAnimationCurveEaseInOut]; modalView.center = middleCenter; [UIView commitAnimations]; } // Use this to slide the semi-modal back up. - (void) hideModal:(UIView*) modalView { CGSize offSize = [UIScreen mainScreen].bounds.size; //CGPoint offScreenCenter = CGPointMake(offSize.width / 2.0, offSize.height * 1.5); CGPoint offScreenCenter = CGPointMake(offSize.width / 2.0, -100); [UIView beginAnimations:nil context:modalView]; [UIView setAnimationDuration:0.3]; [UIView setAnimationCurve:UIViewAnimationCurveEaseInOut]; [UIView setAnimationDelegate:self]; [UIView setAnimationDidStopSelector:@selector(hideModalEnded:finished:context:)]; modalView.center = offScreenCenter; [UIView commitAnimations]; } (void) hideModalEnded:(NSString *)animationID finished:(NSNumber *)finished context:(void )context { UIView modalView = (UIView *)context; [modalView removeFromSuperview]; //[modalView release]; }

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  • Can I use a property placeholder with Spring EL?

    - by David Easley
    Before upgrading to Spring 3 I had this in my applicationContext.xml file: <bean class="com.northgateis.pole.ws.PolePayloadValidatingInterceptor"> <property name="validateRequest" value="${validateRequest}" /> <property name="validateResponse" value="${validateResponse}" /> </bean> where ${validateRequest) and ${validateRequest) refer to properties that may or may not be defined in my properties file. In Spring 2, if these proeprties were not present in the properties file the setters on the bean were not called and so the defaults hard-coded in PolePayloadValidatingInterceptor were used. After upgrading to Spring 3, it seems the behaviour is different: If the properties are not present in the properties file I get the following exception: SEVERE: Exception sending context initialized event to listener instance of class org.springframework.web.context.ContextLoaderListener org.springframework.beans.factory.BeanDefinitionStoreException: Invalid bean definition with name 'annotationMapping' defined in class path resource [com/northgateis/pole/ws/applicationContext-ws.xml]: Could not resolve placeholder 'validateRequest' at org.springframework.beans.factory.config.PropertyPlaceholderConfigurer.processProperties(PropertyPlaceholderConfigurer.java:272) at org.springframework.beans.factory.config.PropertyResourceConfigurer.postProcessBeanFactory(PropertyResourceConfigurer.java:75) at org.springframework.context.support.AbstractApplicationContext.invokeBeanFactoryPostProcessors(AbstractApplicationContext.java:640) at org.springframework.context.support.AbstractApplicationContext.invokeBeanFactoryPostProcessors(AbstractApplicationContext.java:615) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:405) at org.springframework.web.context.ContextLoader.createWebApplicationContext(ContextLoader.java:272) I tried dabbling with Spring EL but the following doesn't seem to work: <bean class="com.northgateis.pole.ws.PolePayloadValidatingInterceptor"> <property name="validateRequest" value="${validateRequest?:true}" /> <property name="validateResponse" value="${validateResponse?:false}" /> </bean> The value after the Elvis operator is always used, even when the properties are defined in the proeprties file. Interesting that the syntax is accepted. Any suggestions?

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