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• Problem in updating field in codeigniter please help

  - by pokhara

  It says , you must use the “set” method to update an entry. Pls help My model is $this->db->where('id', $this->uri->segment(3)); $this->db->update('mytable', $data); My controller is $data = $this->db->select('mytable', $_POST); $this->contact_model->model_update_function($data);

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• CodeIgniter - the right way to create "block" elements on web page

  - by kikkoman90

  Hello. I've been searching for a solutions for this problem a while but haven't seen any "valid mvc" solution for this. I hope I can explain my problem clearly enough for you guys. I need to create a dynamic block of HTML on my website. (eg. a block containing user's latest blog comments). I have a template view file (a file containing header, content container and a footer) where I need to add some content AND this block element. The problem is that I don't want to duplicate this block code on every controller. It just feels stupid and I'm sure there's a better way to do this than just duplicating same stuff all over again on all the controller files? I can add view inside another view just fine, but what bugs me is how to actually generate that dynamic content to this block's view-file. I can't call controller from view file, controller from controller filem or model from view file because what I understand that just isn't the "mvc" way? Anyone got any tricks or tips for this?

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• Codeigniter: Get affected fields in update

  - by Roberto

  There's a way to get which fields were modified after a update query? I want to keep track what field XXX user modified... any ways using active records?

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• Codeigniter - selecting children and parents from db

  - by Tomek Buszewski

  I want to pull from my database records corresponding to parent_id, like this: function getChildren($id, $parent_id) { $q = $this->db->select('id, name, slug, plat'); $q = $this->db->from('games'); $q = $this->db->where('parent_id',$id); $q = $this->db->or_where('id',$parent_id); $q = $this->db->get(); return $q->result_array(); } It - if it's a children game - get parent_id and search for a game with such id and for other games that has parent_id same as this one. If it's the parent game, it only looks for games with parent_id same as it's id. The problem is... it's not always working. I have four games in db: id | parent_id | title 15 | 0 | Abe 19 | 15 | Abe 20 | 0 | RE2 21 | 20 | RE2 DS First two works, last two - only children (id = 21) shows parent.

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• Is CodeIgniter's ActiveRecord resource intensive?

  - by iamdadude

  I’m coding an application with server resources in mind, so I don’t want to use too much so that this application scales in the future. I don’t mind writing my own queries. So, is ActiveRecord resource intensive for my application? Or does it not make a difference? Thanks!

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• Running CodeIgniter cron on localhost

  - by stef

  I'm trying to get a cron job to run every 5 min on my localhost. Using the Cronnix app I entered the following command 0,5 * * * * root curl http://localhost:8888/site/ > /dev/null The script runs fine when I visit http://localhost:8888/site/ in my browser. I've read some stuff about getting CI to run on Cron, using wget and various other options but none make a lot of sense. In another SO post I found the following command wget -O - -q -t 1 http://www.example.com/cron/run What is the "-O - -q -t 1" syntax exactly? Are there other options?

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• removing index.php of codeigniter on local

  - by Aldi Aryanto

  i'm trying to remove index.php,in my localhost, but it seems doesn't working,its on http://localhost/testing i put .htacces in 'testing' directory under the htdocs LoadModule rewrite_module modules/mod_rewrite.so at apache/conf also already uncheck here my .htaccess RewriteEngine On RewriteBase /testing/ RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ /testing/index.php/$1 [L] here my config $config['base_url'] = "http://localhost/testing"; $config['index_page'] = ''; $config['uri_protocol'] = 'AUTO'; when i access login controller, it's not found Not Found The requested URL /testing/login was not found on this server. I really don't know what to try next. Any help would be appreciated.

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• Codeigniter passing variable to URL

  - by CyberJunkie

  I have a list of posts and an edit link for each. When clicking edit it goes to a page where I can edit the specific post I clicked on. For this I will have to pull from the db the id of the post. Would this be the correct way to do it? <a href="<?php echo site_url("post/edit/$row->id"); ?>">Edit</a> post is my controller, edit is my function, and $row->id should pull the id of the post.

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• CodeIgniter URI routing (dynamic, multilingual)

  - by koteko

  I'm trying to redirect all routs to one main controller. Here is my routes.php $route['default_controller'] = "main"; $route['scaffolding_trigger'] = ""; //$route['(\w{2})/(.*)'] = '$2'; //$route['(\w{2})'] = $route['default_controller']; $route['(en|ge)/(:any)'] = $route['default_controller']."/index/$1"; $route['(:any)'] = $route['default_controller']."/index/$1"; I need language id to be passed with every link (like: http://site.com/en/hello-world) Here is my main controller: class Main extends Controller { function __construct() { parent::Controller(); } function index($page_type=false, $param=false) { die($page_type.' | '.$param.'| Aaa!'); } } I want to check if predefined file type exists (like: http://site.com/en/archive/05-06-2010 - here predefined type would be archive) then do something. If not then search in the database for slug. If not found then go to 404. The problem is that I can't get index function parameters ($page_type, $param). Thanks for help.

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• CodeIgniter - Calling a function from inside a view

  - by Chris

  Hey, Is it possible to call a function which is located in a controller from a view. This is what i have in my controller, as an example function checkKeyExists($userid, $key){ } Then inside my view i have the following if(checkKeyExists($row->id, $role->key)){ } But when i run it, it says that checkKeyExists is not defined. If anyone can let me know how i could do this, that would be great. Cheers

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• ajax not working in codeigniter

  - by user1800797

  I'm trying to send a post request using the ajax jquery function and return some data into a window asynchronously. Here's what I have so far. It doesn't seem to be working. in the view: $.ajax({ url: '/dashboard/presskits/media/get_video_link/', type: 'POST', dataType: 'json', data: { encoded_link : encoded_link }, cache: false, success: function(output_string){ // $('#edit_video_info').append(output_string); alert(output_string.url_data); } // End of success function of ajax form }); // End of ajax call }); in the controller: public function get_video_link() { $temp_url = $this->input->post('encoded_link'); $output_string = json_encode(array('url_data' => $temp_url)); return $output_string; }

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• Multidimensional Array To Mysql Codeigniter

  - by rochellecanale

  A little help how can I create an input query using this array? Or how can I pass it in the table? my table layout sample is this: sales_table id | product_name | price | qty | subtotal This is derived from the var_dump() function. Here is my code in array //array code from unserialized function $products = unserialize($this->session->userdata('product_list')); //This is the output. Array ( [2] => Array ( [id] => 2 [product_name] => NOKIA 5110 [product_desc] => Cellphone [product_price] => 500.00 [product_qty] => 1 [product_amount] => 500 [product_code] => NOKI2012-84353 ) [3] => Array ( [id] => 3 [product_name] => HP IPAQ RW6828 [product_desc] => Cellphone [product_price] => 1500.00 [product_qty] => 1 [product_amount] => 1500 [product_code] => HP I2012-08386 ) )

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• Use where clause with Like in codeigniter

  - by user2524013

  I am working on a project. I am implementing the Search functionality in my System. I will have to show the search record from two tables base on the current use login. I have tried the following code: function searchActivity($limit,$offset,$keyword1,$keyword2,$recruiter_id) { $q=$this->db->select('*')->from('tbl_activity')->limit($limit,$offset); $this->db->join('tbl_job', 'tbl_job.job_id = tbl_activity.job_id_fk', 'left outer'); $this->db->order_by("activity_id", "ASC"); $this->db->like('job_title',$keyword1,'both'); $this->db->or_like('job_title',$keyword2,'both'); $this->db->or_like('activity_subject',$keyword1,'both'); $this->db->or_like('activity_subject',$keyword2,'both'); $this->db->or_like('activity_details',$keyword1,'both'); $this->db->or_like('activity_details',$keyword2,'both'); $this->db->where('tbl_activity.recruiter_id_fk',$recruiter_id); $ret['rows']=$q->get()->result(); return $ret; } I want to show search results based on the current user id, which is currently store in $recruiter. Thanks in advance.

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• get value from database based on array in codeigniter

  - by Developer

  I have an array $user = array([0]=>1 [1]=>2 [2]=>3) which contains id's of certain users. I need to get the countries of these users from database. foreach($userid as $user){ $this->db->select('country'); $this->db->where('user_id',$user); $this->db->from('company'); $usercountry = $this->db->get(); $count = $usercountry->row(); $country = $count->country; } Suppose user1 has country ES, user2 has IN, user3 has US, user4 has UK. then if array contains 1,2,3. Then i need to get the countries ES,IN,US.

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• CodeIgniter: help with this query

  - by iamjonesy

  Hi, I have just started my first CI app. I have a view that displays some posts. Each post can have multiple comments and I want to display the total number of comments next to each post. So far all my db call are in my controller (will be changing this). function index(){ $data['query'] = $this->db->get('posts'); $this->load->view('blog_view', $data); } In my view: <?php foreach($query->result() as $row): <div class="post-box"> <p><?php echo $row->body; ?><small>&nbsp;added by <?php echo $row->username; ?> on <?php echo date ('d/m/Y',strtotime($row->created)); ?>&nbsp;<a href="<?php echo base_url(); ?>blog/comments/<?php echo $row->id; ?>"><img src="<?php echo base_url(); ?>images/comments_icon.png" />&nbsp;0</a></small></p> </div> <?php endforeach; ?> I want to get the total number of comments where comment.post_id = the current record's id. and display it next to the comments icon. Any help with this most appreciated, Billy

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• generation of multiple reports and zipping in codeigniter php

  - by Suj

  I want to generate multiple pdf reports on click of single print button and zip all the pdf's and store it in a folder. Any help please. I need this functionality in my project.

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• Defautlt Contoller in CodeIgniter

  - by gregavola

  Hello everyone, I am wondering if there is any other configuration options for a default controller. For example - if I have a controller called "site" and I set the default controller in the following file: application/config/routes.php to: $route['default_controller'] = "site"; I should be able to go to http://localhost and that brings up the index(); function in the site controller. However, if I try to do go to http://localhost/index.php/index2 to load the index2(); function I get a 404 error. If i change the URL to http://localhost/index.php/site/index2 it works fine - but I thought already set the default controller. Is there any way around this? Any thoughts?

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• Using Wildcards in CodeIgniter

  - by tpae

  Wildcards are cool. I am trying to do this: $route["(:any)/controller"] = "controller"; basically, I want to put the wildcard in the front. It doesn't quite work, and I don't know any work around.

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• Displaying Data from a Join in Codeigniter

  - by Brad

  I am using a simple join to pull data from two databases. This is the join in the model function com_control(){ $this->db->select('*'); $this->db->from('comments'); $this->db->join('posts', 'comments.entry_id = posts.id'); $query = $this->db->get(); return $query->result; } My desired method of display is going to be in a table so I am starting out to use like this foreach($comm_control as $row){ $this->table->add_row( $row->entry_id, $row->comments.id, $row->comment, $row->title ); }//end of foreach My problem is the display of data from comments.id. What is the proper format to add the comment.id into the table rows? I need the ID from both tables for display, edit and delete further on in the table. The only display I get at this time for "comment.id" is the word id. The Any help would be appreciated.

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• How to send the my sql result to controller in codeigniter as a variable

  - by udaya

  Hi In my mode I am selecting a field as $query1 = $this->db->query("SELECT dPassword FROM tbl_login WHERE dEmailID='[email protected]'"); How to return dpassword as a variable to my controller I tried this way return dpassword;

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• CodeIgniter copying an instance - performance issues?

  - by fire

  I have quite a few libraries and models that get loaded into a controller, and each library/model creates an instance of CI using $this->CI =& get_instance(); in the __construct function. Are there any performance issues with this and is there a better way?

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• codeigniter and JSON

  - by ole

  Hello all i having a problem that it only get 1 value in my database and its my title and i want to show content and username from the same table to. here is my JSON kode <script type="text/javascript"> $.getJSON( 'ajax/forumThreads', function(data) { alert(data[0].overskrift); alert(data[0].indhold); } ); </script> my controller <?php class ajax extends Controller { function forumThreads() { $this->load->model('ajax_model'); $data['forum_list'] = $this->ajax_model->forumList(); if ($data['forum_list'] !== false) { echo json_encode($data['forum_list']); } } } my model fle <?php class ajax_model extends Model { function forumList() { $this->db->select('overskrift', 'indhold', 'brugernavn', 'dato'); $this->db->order_by('id', 'desc'); $this->db->limit(5); $forum_list = $this->db->get('forum_traad'); if($forum_list->num_rows() > 0) { return $forum_list->result_array(); } else { return false; } } }

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• Reverse wildcard search in codeigniter

  - by Andy Platt

  I am implementing a snippet-based content management system into my current project. Snippets can be associated with a page either by exact match of the full url falling back to a wildcard match on a partial url or finally a default snippet. To implement this I have a created table of page associations with a wildcard flag, the system first checks the current url against the non-wildcard associations and if it doesn't find a match it checks against the partial url's where the wildcard flag is set. In order to achieve this I am getting all the partial url's from the database and putting them into an array then walking the array to check for a match against the current url: protected function _check_wildcard($url = NULL) { if($url) { $q = $this->db->where('wildcard' ,'Y') ->from('content') ->get(); $wildcards = $q->result_array(); foreach($wildcards AS $wildcard) { if(strpos($url,$wildcard['url']) > 0) { return $wildcard['snipppet_id']; } } } else { return NULL; } } Can anyone suggest a better way to do this - preferably one that doesn't involve having to constantly download the full list of all the wildcards each time I load a page as I am afraid that this will have a negative effect on the scalability of the system down the line?

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• Codeigniter : database configuration

  - by nppCods

  I am beginner for CI so don’t have good knowledge. My problem is: I am not using any database. All the records are fetched from JSON. Therefore I don’t think I need to configure database… As said by CI, it doesn’t necessarily ask for database. So my database.php configuration is : $active_group = ‘default’; $active_record = FALSE; $db[‘default’][‘hostname’] = ‘’; $db[‘default’][‘username’] = ‘’; $db[‘default’][‘password’] = ‘’; $db[‘default’][‘database’] = ‘’; $db[‘default’][‘dbdriver’] = ‘mysql’; $db[‘default’][‘dbprefix’] = ‘’; $db[‘default’][‘pconnect’] = TRUE; $db[‘default’][‘db_debug’] = TRUE; $db[‘default’][‘cache_on’] = FALSE; $db[‘default’][‘cachedir’] = ‘’; $db[‘default’][‘char_set’] = ‘utf8’; $db[‘default’][‘dbcollat’] = ‘utf8_general_ci’; $db[‘default’][‘swap_pre’] = ‘’; $db[‘default’][‘autoinit’] = TRUE; $db[‘default’][‘stricton’] = FALSE; It works in my local system but doesn’t work in live server. I am so surprised. Then I provided hostname, username, password and dbdriver, it works. My question is that, is that necessary to provide all the details if I am not using database? Thank you for your suggestion.

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• CodeIgniter subfolders and URI routing

  - by shummel7845

  I’ve read the manual on URI routing and views and something is not clicking with me. In my views folder, I have a subfolder called products. In there is a file called product_view. In my controller, I have: function index() { $data['title'] = 'Product Overview'; $data['main_content'] = 'products/product_view'; $this->load->view('templates/main.php', $data); } The template loads a header view, a footer view and a navigation view, plus the view as a main content variable. In my URI routing, I have: $route['products/product-overview'] = 'products/product_view']; This causes a 404 error when I try to go to domain.com/products/product-overview. Do I need to do something with my .htaccess? If so, what? Here is my .htaccess: Options +FollowSymLinks Options -Indexes DirectoryIndex index.php RewriteEngine on RewriteCond $1 !^(index\.php|resources|images|css|js|robots\.txt|favicon\.ico) RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ index.php?/$1 [L,QSA] I’d appreciate some specific help, as the documentation isn’t specific on how to address this. I’ve done a little searching in the forums, and didn’t see anything, but I’m posting this while I keep looking.

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