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  • Where does django look for sqlite3 installation/libraries?

    - by gath
    Am having a bit of a problem making my django application run in SUSE linux 9. I have Python2.5 installed well, Django 1.0 installed well. Am able to execute django command django-admin startproject fine But when i run the runserver command i get the error below. i have a folder with sqlite3, i can go in there and actually run the sqlite3* application, now am wondering where does Django look for the sqlite libraries? and how can i fix this? Validating models... Unhandled exception in thread started by <function inner_run at 0x2a96cb4f50> Traceback (most recent call last): File "/usr/local/lib/python2.5/site-packages/django/core/management/commands/runserver.py", line 48, in inner_run self.validate(display_num_errors=True) File "/usr/local/lib/python2.5/site-packages/django/core/management/base.py", line 122, in validate num_errors = get_validation_errors(s, app) File "/usr/local/lib/python2.5/site-packages/django/core/management/validation.py", line 22, in get_validation_errors from django.db import models, connection File "/usr/local/lib/python2.5/site-packages/django/db/__init__.py", line 16, in <module> backend = __import__('%s%s.base' % (_import_path, settings.DATABASE_ENGINE), {}, {}, ['']) File "/usr/local/lib/python2.5/site-packages/django/db/backends/sqlite3/base.py", line 27, in <module> raise ImproperlyConfigured, "Error loading %s module: %s" % (module, exc) django.core.exceptions.ImproperlyConfigured: Error loading sqlite3 module: No module named _sqlite3 Gath

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  • Django: DatabaseLockError exception with Djapian

    - by jul
    Hi, I've got the exception shown below when executing indexer.update(). I have no idea about what to do: it used to work and now index database seems "locked". Anybody can help? Thanks Environment: Request Method: POST Request URL: http://piem.org:8000/restaurant/add/ Django Version: 1.1.1 Python Version: 2.5.2 Installed Applications: ['django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.comments', 'django.contrib.sites', 'django.contrib.admin', 'registration', 'djapian', 'resto', 'multilingual'] Installed Middleware: ('django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.middleware.locale.LocaleMiddleware', 'multilingual.middleware.DefaultLanguageMiddleware') Traceback: File "/var/lib/python-support/python2.5/django/core/handlers/base.py" in get_response 92. response = callback(request, *callback_args, **callback_kwargs) File "/home/jul/atable/../atable/resto/views.py" in addRestaurant 639. Restaurant.indexer.update() File "/home/jul/python-modules/Djapian-2.3.1-py2.5.egg/djapian/indexer.py" in update 181. database = self._db.open(write=True) File "/home/jul/python-modules/Djapian-2.3.1-py2.5.egg/djapian/database.py" in open 20. xapian.DB_CREATE_OR_OPEN, File "/usr/lib/python2.5/site-packages/xapian.py" in __init__ 2804. _xapian.WritableDatabase_swiginit(self,_xapian.new_WritableDatabase(*args)) Exception Type: DatabaseLockError at /restaurant/add/ Exception Value: Unable to acquire database write lock on /home/jul/atable /djapian_spaces/resto/restaurant/resto.index.restaurantindexer: already locked

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  • Rebuilding old (2010) django project in 2012

    - by birgit
    I am trying to make an old Django project run again. After seemingly having solved issues with old sorl.thumbnail versions and deprecated expressions I now get this error when running python manage.py runserver I also tried to copy & paste my old files into a new Django project and get the exactly same error. Maybe someone here has a clue where the problem lies? Unhandled exception in thread started by <bound method Command.inner_run of <django.contrib.staticfiles.management.commands.runserver.Command object at 0x2a80510>> Traceback (most recent call last): File "/usr/lib/python2.7/dist-packages/django/core/management/commands/runserver.py", line 88, in inner_run self.validate(display_num_errors=True) File "/usr/lib/python2.7/dist-packages/django/core/management/base.py", line 249, in validate num_errors = get_validation_errors(s, app) File "/usr/lib/python2.7/dist-packages/django/core/management/validation.py", line 35, in get_validation_errors for (app_name, error) in get_app_errors().items(): File "/usr/lib/python2.7/dist-packages/django/db/models/loading.py", line 146, in get_app_errors self._populate() File "/usr/lib/python2.7/dist-packages/django/db/models/loading.py", line 61, in _populate self.load_app(app_name, True) File "/usr/lib/python2.7/dist-packages/django/db/models/loading.py", line 78, in load_app models = import_module('.models', app_name) File "/usr/lib/python2.7/dist-packages/django/utils/importlib.py", line 35, in import_module __import__(name) File "/home/me/Documents/wdws/wdws/../wdws/cityofwindows/models.py", line 73, in <module> class Image(models.Model): File "/home/me/Documents/wdws/wdws/../wdws/cityofwindows/models.py", line 83, in Image 'large': {'size': (640, 640)}, File "/usr/lib/python2.7/dist-packages/django/db/models/fields/files.py", line 233, in __init__ super(FileField, self).__init__(verbose_name, name, **kwargs) TypeError: __init__() got an unexpected keyword argument 'extra_thumbnails' I need to re-build the project just for visual documentation locally... so also any hints on how to quickly re-run outdated django-projects are very welcome!! Thanks a lot (using Ubuntu 12.04)

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  • In Django, what's the best way to handle optional url parameters from the template?

    - by Thierry Lam
    I have the following type of urls which are both valid: hello/ hello/1234/ My urls.py has the following: urlpatterns = patterns('hello.views', url(r'^$', 'index', name='index'), url(r'^(?P<user_id>\d+)/$', 'index', name='index'), ) In my views.py, when I pass user_id to the template, it defaults to 0 if not specified. My template looks like the following, I'm using namespace hello for my hello app: {% url hello:index user_id %} If user_id is not specified, the url defaults to hello/0/. The only way I can think of preventing the default 0 from showing in the url is by an if stmt: {% if user_id %} {% url hello:index user_id %} {% else %} {% url hello:index %} {% endif %} The above will give me hello/ if there are no user_id and hello/1234/ if it's present. Is the above solution the best way to solve this issue?

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  • Django's self.client.login(...) does not work in unit tests

    - by thebossman
    I have created users for my unit tests in two ways: 1) Create a fixture for "auth.user" that looks roughly like this: { "pk": 1, "model": "auth.user", "fields": { "username": "homer", "is_active": 1, "password": "sha1$72cd3$4935449e2cd7efb8b3723fb9958fe3bb100a30f2", ... } } I've left out the seemingly unimportant parts. 2) Use 'create_user' in the setUp function (although I'd rather keep everything in my fixtures class): def setUp(self): User.objects.create_user('homer', '[email protected]', 'simpson') Note that the password is simpson in both cases. I've verified that this info is correctly being loaded into the test database time and time again. I can grab the User object using User.objects.get. I can verify the password is correct using 'check_password.' The user is active. Yet, invariably, self.client.login(username='homer', password='simpson') FAILS. I'm baffled as to why. I think I've read every single Internet discussion pertaining to this. Can anybody help? The login code in my unit test looks like this: login = self.client.login(username='homer', password='simpson') self.assertTrue(login) Thanks.

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  • How can I display multiple django modelformset forms in a grouped fieldsets?

    - by JT
    I have a problem with needing to provide multiple model backed forms on the same page. I understand how to do this with single forms, i.e. just create both the forms call them something different then use the appropriate names in the template. Now how exactly do you expand that solution to work with modelformsets? The wrinkle, of course, is that each 'form' must be rendered together in the appropriate fieldset. For example I want my template to produce something like this: <fieldset> <label for="id_base-0-desc">Home Base Description:</label> <input id="id_base-0-desc" type="text" name="base-0-desc" maxlength="100" /> <label for="id_likes-0-icecream">Want ice cream?</label> <input type="checkbox" name="likes-0-icecream" id="id_likes-0-icecream" /> </fieldset> <fieldset> <label for="id_base-1-desc">Home Base Description:</label> <input id="id_base-1-desc" type="text" name="base-1-desc" maxlength="100" /> <label for="id_likes-1-icecream">Want ice cream?</label> <input type="checkbox" name="likes-1-icecream" id="id_likes-1-icecream" /> </fieldset> I am using a loop like this to process the results (after form validation) base_models = base_formset.save(commit=False) like_models = like_formset.save(commit=False) for base_model, likes_model in map(None, base_models, likes_models): which works as I'd expect (I'm using map because the # of forms can be different). The problem is that I can't figure out a way to do the same thing with the templating engine. The system does work if I layout all the base models together then all the likes models after wards, but it doesn't meet the layout requirements. EDIT: Updated the problem statement to be more clear about what exactly I'm processing (I'm processing models not forms in the for loop)

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  • How to put an InlineFormSet into a ModelFormSet in Django?

    - by Jannis
    Hi, I'd like to display a number of forms via a ModelFormSet where each one of the forms displays in turn InlineFormSets for all objects connected to the object. Now I'm not really sure how to provide the instances for each ModelFormSet. I thought about subclassing BaseModelFormSet but I have no clue on where to start and would like to know whether this is possible at all before I go through all the trouble. Thanks in advance!

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  • How can I display multiple django modelformset forms together?

    - by JT
    I have a problem with needing to provide multiple model backed forms on the same page. I understand how to do this with single forms, i.e. just create both the forms call them something different then use the appropriate names in the template. Now how exactly do you expand that solution to work with modelformsets? The wrinkle, of course, is that each 'form' must be rendered together in the appropriate fieldset. For example I want my template to produce something like this: <fieldset> <label for="id_base-0-desc">Home Base Description:</label> <input id="id_base-0-desc" type="text" name="base-0-desc" maxlength="100" /> <label for="id_likes-0-icecream">Want ice cream?</label> <input type="checkbox" name="likes-0-icecream" id="id_likes-0-icecream" /> </fieldset> <fieldset> <label for="id_base-1-desc">Home Base Description:</label> <input id="id_base-1-desc" type="text" name="base-1-desc" maxlength="100" /> <label for="id_likes-1-icecream">Want ice cream?</label> <input type="checkbox" name="likes-1-icecream" id="id_likes-1-icecream" /> </fieldset> I am using a loop like this to process the results for base_form, likes_form in map(None, base_forms, likes_forms): which works as I'd expect (I'm using map because the # of forms can be different). The problem is that I can't figure out a way to do the same thing with the templating engine. The system does work if I layout all the base models together then all the likes models after wards, but it doesn't meet the layout requirements.

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  • Django: Is there any way to have "unique for date range"?

    - by tomwolber
    If my model for Items is: class Item(models.Model): name = models.CharField(max_length=500) startDate = models.DateField("Start Date", unique="true") endDate = models.DateField("End Date") Each Item needs to have a unique date range. for example, if i create an Item that has a date range of June 1st to June 8th, how can I keep and Item with a date range of June 3rd to June 5th from being created (or render an error with template logic)?

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  • Django - Can you use property as the field in an aggregation function?

    - by orokusaki
    I know the short answer because I tried it. Is there any way to accomplish this though (even if only on account of a hack)? class Ticket(models.Model): account = modelfields.AccountField() uuid = models.CharField(max_length=36, unique=True) created = models.DateTimeField(auto_now_add=True) class Meta: ordering = ['created'] @property def repair_cost(self): # cost is a @property of LineItem(models.Model) return self.lineitem_set.aggregate(models.Sum('cost'))

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  • Django: Can class-based views accept two forms at a time?

    - by Hooman
    If I have two forms: class ContactForm(forms.Form): name = forms.CharField() message = forms.CharField(widget=forms.Textarea) class SocialForm(forms.Form): name = forms.CharField() message = forms.CharField(widget=forms.Textarea) and wanted to use a class based view, and send both forms to the template, is that even possible? class TestView(FormView): template_name = 'contact.html' form_class = ContactForm It seems the FormView can only accept one form at a time. In function based view though I can easily send two forms to my template and retrieve the content of both within the request.POST back. variables = {'contact_form':contact_form, 'social_form':social_form } return render(request, 'discussion.html', variables) Is this a limitation of using class based view (generic views)? Many Thanks

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  • How can I copy a queryset to a new model in django admin?

    - by user3806832
    I'm trying to write an action that allows the user to select the queryset and copy it to a new table. So: John, Mark, James, Tyler and Joe are in a table 1( called round 1) The user selects the action that say to "move to next round" and those same instances that were chosen are now also in the table for "round 2". I started trying with an action but don't really know where to go from here: def Round_2(modeladmin, request, queryset): For X in queryset: X.pk = None perform.short_description = "Move to Round 2" How can I copy them to the next table with all of their information (pk doesn't have to be the same)? Thanks

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  • How to get a single widget to set 2 fields in Django?

    - by kender
    Hi, I got a model with 2 fields: latitude and longitude. Right now they're 2 CharFields, but I want to make a custom widget to set it in admin - was thinking about displaying Google Maps, then getting the coordinates of the marker. But can I have 1 widget (a single map) to set 2 different fields?

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  • What's the straightforward way to implement one to many editing in list_editable in django admin?

    - by Nate Pinchot
    Given the following models: class Store(models.Model): name = models.CharField(max_length=150) class ItemGroup(models.Model): group = models.CharField(max_length=100) code = models.CharField(max_length=20) class ItemType(models.Model): store = models.ForeignKey(Store, on_delete=models.CASCADE, related_name="item_types") item_group = models.ForeignKey(ItemGroup) type = models.CharField(max_length=100) Inline's handle adding multiple item_types to a Store nicely when viewing a single Store. The content admin team would like to be able to edit stores and their types in bulk. Is there a simple way to implement Store.item_types in list_editable which also allows adding new records, similar to horizontal_filter? If not, is there a straightforward guide that shows how to implement a custom list_editable template? I've been Googling but haven't been able to come up with anything. Also, if there is a simpler or better way to set up these models that would make this easier to implement, feel free to comment.

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  • django form ModelChoiceField loads all state names while needed states which are mapped with current selected country

    - by Sonu
    I am using modelChoiceField to display country and state into address form class StateSelectionwidget(forms.Select): """ custom widget to state selection""" class Media: js = ('media/javascript/public/jquery-1.5.2.min.js', 'media/javascript/public/countrystateselection.js', ) class AddressForm(forms.Form): name = forms.CharField(max_length=30) country = forms.ModelChoiceField(queryset=[]) state = forms.ModelChoiceField(CountryState.objects, widget=StateSelectionwidget) def __init__(self, *args, **kwargs): super(AddressForm, self).__init__(*args, **kwargs) self.fields['country'].queryset = Country.objects.all() Country model is used to store country names. CountryState model is used to store all states which is foreign key to Country model At the time of form loading i am getting all state names in dropdown while i want field to be blank by default. If name field is empty at the time of form save i am getting error that name can not be empty but also getting all states into dropdown list while i want only the states which are mapped with current selected country.

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  • Django flatpages raising 404 when DEBUG is False (404 and 500 templates exist)

    - by Adam
    I'm using Django 1.1.1 stable. When DEBUG is set to True Django flatpages works correctly; when DEBUG is False every flatpage I try to access raises a custom 404 error (my error template is obviously working correctly). Searching around on the internet suggests creating 404 and 500 templates which I have done. I've added to FlatpageFallBackMiddleware to middleware_classes and flatpages is added to installed applications. Any ideas how I can make flatpages work?

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  • Subclassed django models with integrated querysets

    - by outofculture
    Like in this question, except I want to be able to have querysets that return a mixed body of objects: >>> Product.objects.all() [<SimpleProduct: ...>, <OtherProduct: ...>, <BlueProduct: ...>, ...] I figured out that I can't just set Product.Meta.abstract to true or otherwise just OR together querysets of differing objects. Fine, but these are all subclasses of a common class, so if I leave their superclass as non-abstract I should be happy, so long as I can get its manager to return objects of the proper class. The query code in django does its thing, and just makes calls to Product(). Sounds easy enough, except it blows up when I override Product.__new__, I'm guessing because of the __metaclass__ in Model... Here's non-django code that behaves pretty much how I want it: class Top(object): _counter = 0 def __init__(self, arg): Top._counter += 1 print "Top#__init__(%s) called %d times" % (arg, Top._counter) class A(Top): def __new__(cls, *args, **kwargs): if cls is A and len(args) > 0: if args[0] is B.fav: return B(*args, **kwargs) elif args[0] is C.fav: return C(*args, **kwargs) else: print "PRETENDING TO BE ABSTRACT" return None # or raise? else: return super(A).__new__(cls, *args, **kwargs) class B(A): fav = 1 class C(A): fav = 2 A(0) # => None A(1) # => <B object> A(2) # => <C object> But that fails if I inherit from django.db.models.Model instead of object: File "/home/martin/beehive/apps/hello_world/models.py", line 50, in <module> A(0) TypeError: unbound method __new__() must be called with A instance as first argument (got ModelBase instance instead) Which is a notably crappy backtrace; I can't step into the frame of my __new__ code in the debugger, either. I have variously tried super(A, cls), Top, super(A, A), and all of the above in combination with passing cls in as the first argument to __new__, all to no avail. Why is this kicking me so hard? Do I have to figure out django's metaclasses to be able to fix this or is there a better way to accomplish my ends?

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  • Django comments being spammed

    - by John
    Hi, I am using the built in comment system with Django but it has started to be spammed. Can anyone recommend anything I can use to stop this such as captcha for django etc. I'm looking for something that I can use along with the comment system rather than replacing it. Thanks

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  • Django & google openid authentication with socialauth

    - by Zayatzz
    Hello I am trying to use django-socialauth (http://github.com/uswaretech/Django-Socialauth) for authenticating users for my django project. This is firs time working with openid and i've had to figure out how exactly this open id works. I have more or less understood it, by now, but there are few things that elude me. The authentication process starts when the request is put together in in django-socialauth.openid_consumer.views.begin. I can see that the outgoing authentication request is more or less something like this: https://www.google.com/accounts/o8/ud?openid.assoc_handle=AOQobUckRThPUj3K1byG280Aze-dnfc9Iu6AEYaBwvHE11G0zy8kY8GZ& openid.ax.if_available=fname& openid.ax.mode=fetch_request& openid.ax.required=email& openid.ax.type.email=http://axschema.org/contact/email& openid.ax.type.fname=http://example.com/schema/fullname& openid.claimed_id=http://specs.openid.net/auth/2.0/identifier_select& openid.identity=http://specs.openid.net/auth/2.0/identifier_select& openid.mode=checkid_setup&openid.ns=http://specs.openid.net/auth/2.0& openid.ns.ax=http://openid.net/srv/ax/1.0& openid.ns.sreg=http://openid.net/extensions/sreg/1.1& openid.realm=http://localhost/& openid.return_to=http://localhost/social/gmail_login/complete/?janrain_nonce=2010-03-20T11%3A19%3A44ZPZCjNc&openid.sreg.optional=postcode,country,nickname,email This is lot like 2nd example here: http://code.google.com/apis/accounts/docs/OpenID.html#Samples The problem is, that the request, i get back, is nothing like the corresponding example from code.google.com (look at the 3rd example in example responses. Response dict i get is like this: { 'openid.op_endpoint': 'https://www.google.com/accounts/o8/ud', 'openid.sig': 'QWMa4x4ruMUvSCfLwKV6CZRuo0E=', 'openid.ext1.type.email': 'http://axschema.org/contact/email', 'openid.return_to': 'http://localhost/social/gmail_login/complete/?janrain_nonce=2010-03-20T17%3A54%3A06ZHV4cqh', 'janrain_nonce': '2010-03-20T17:54:06ZHV4cqh', 'openid.response_nonce': '2010-03-20T17:54:06ZdC5mMu9M_6O4pw', 'openid.claimed_id': 'https://www.google.com/accounts/o8/id?id=AItOghawkFz0aNzk91vaQWhD-DxRJo6sS09RwM3SE', 'openid.mode': 'id_res', 'openid.ns.ext1': 'http://openid.net/srv/ax/1.0', 'openid.signed': 'op_endpoint,claimed_id,identity,return_to,response_nonce,assoc_handle,ns.ext1,ext1.mode,ext1.type.email,ext1.value.email', 'openid.ext1.value.email': '[email protected]', 'openid.assoc_handle': 'AOQobUfssTJ2IxRlxrIvU4Xg8HHQKKTEuqwGxvwwuPR5rNvag0elGlYL', 'openid.ns': 'http://specs.openid.net/auth/2.0', 'openid.identity': 'https://www.google.com/accounts/o8/id?id=AItOawkghgfhf1FkvaQWhD-DxRJo6sS09RwMKjASE', 'openid.ext1.mode': 'fetch_response'} The socialauth itself has been built to accept my email address this way: elif request.openid and request.openid.ax: email = request.openid.ax.get('email') And obviously this fails. Why i am asking all this is, that perhaps i am doing something wrong and my outgoing request is wrong? Or am i doing all correctly and should change the socialaouth module to accept info in a new way and then commit the change? Alan

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  • Django & google openid authentication (openid.ax) with socialauth

    - by Zayatzz
    Hello I am trying to use django-socialauth (http://github.com/uswaretech/Django-Socialauth) for authenticating users for my django project. This is firs time working with openid and i've had to figure out how exactly this open id works. I have more or less understood it, by now, but there are few things that elude me. The authentication process starts when the request is put together in in django-socialauth.openid_consumer.views.begin. I can see that the outgoing authentication request is more or less something like this: https://www.google.com/accounts/o8/ud?openid.assoc_handle=AOQobUckRThPUj3K1byG280Aze-dnfc9Iu6AEYaBwvHE11G0zy8kY8GZ& openid.ax.if_available=fname& openid.ax.mode=fetch_request& openid.ax.required=email& openid.ax.type.email=http://axschema.org/contact/email& openid.ax.type.fname=http://example.com/schema/fullname& openid.claimed_id=http://specs.openid.net/auth/2.0/identifier_select& openid.identity=http://specs.openid.net/auth/2.0/identifier_select& openid.mode=checkid_setup&openid.ns=http://specs.openid.net/auth/2.0& openid.ns.ax=http://openid.net/srv/ax/1.0& openid.ns.sreg=http://openid.net/extensions/sreg/1.1& openid.realm=http://localhost/& openid.return_to=http://localhost/social/gmail_login/complete/?janrain_nonce=2010-03-20T11%3A19%3A44ZPZCjNc&openid.sreg.optional=postcode,country,nickname,email This is lot like 2nd example here: http://code.google.com/apis/accounts/docs/OpenID.html#Samples The problem is, that the request, i get back, is nothing like the corresponding example from code.google.com (look at the 3rd example in example responses. Response dict i get is like this: { 'openid.op_endpoint': 'https://www.google.com/accounts/o8/ud', 'openid.sig': 'QWMa4x4ruMUvSCfLwKV6CZRuo0E=', 'openid.ext1.type.email': 'http://axschema.org/contact/email', 'openid.return_to': 'http://localhost/social/gmail_login/complete/?janrain_nonce=2010-03-20T17%3A54%3A06ZHV4cqh', 'janrain_nonce': '2010-03-20T17:54:06ZHV4cqh', 'openid.response_nonce': '2010-03-20T17:54:06ZdC5mMu9M_6O4pw', 'openid.claimed_id': 'https://www.google.com/accounts/o8/id?id=AItOghawkFz0aNzk91vaQWhD-DxRJo6sS09RwM3SE', 'openid.mode': 'id_res', 'openid.ns.ext1': 'http://openid.net/srv/ax/1.0', 'openid.signed': 'op_endpoint,claimed_id,identity,return_to,response_nonce,assoc_handle,ns.ext1,ext1.mode,ext1.type.email,ext1.value.email', 'openid.ext1.value.email': '[email protected]', 'openid.assoc_handle': 'AOQobUfssTJ2IxRlxrIvU4Xg8HHQKKTEuqwGxvwwuPR5rNvag0elGlYL', 'openid.ns': 'http://specs.openid.net/auth/2.0', 'openid.identity': 'https://www.google.com/accounts/o8/id?id=AItOawkghgfhf1FkvaQWhD-DxRJo6sS09RwMKjASE', 'openid.ext1.mode': 'fetch_response'} The socialauth itself has been built to accept my email address this way: elif request.openid and request.openid.ax: email = request.openid.ax.get('email') And obviously this fails. Why i am asking all this is, that perhaps i am doing something wrong and my outgoing request is wrong? Or am i doing all correctly and should change the socialaouth module to accept info in a new way and then commit the change? Alan

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  • How to unit test django middleware?

    - by luc
    I've implemented a django middleware for getting pages from the database (something similar to the flatpage subframework) Unfortunately it seems that it is not possible to test it with the django testing framework. Any suggestion? Thanks in advance Update: maybe a mistake in my test but I can't get an object that should be returned by a middleware. I'll inverstigate more. Does anybody have unit-tested a middleware code?

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  • Filter Django Haystack results like QuerySet?

    - by prometheus
    Is it possible to combine a Django Haystack search with "built-in" QuerySet filter operations, specifically filtering with Q() instances and lookup types not supported by SearchQuerySet? In either order: haystack-searched -> queryset-filtered or queryset-filtered -> haystack-searched Browsing the Django Haystack documentation didn't give any directions how to do this.

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