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  • Registrar with good security, DNS hosting, and DNSSEC and IPv6 resolvers?

    - by semenko
    I'm looking to move my domains away from GoDaddy, but I'm having a tough time finding anyone with comparable features at a (even remotely) similar price. I've looked at the usual suggestions (NameCheap, Gandi.net, etc.), but they all seem to lack many of the GoDaddy feature base. I'm looking for: DNSSEC IPv6 Resolvers (dig pdns01.domaincontrol.com AAAA; etc. ) SSL-Logins by default HTTP-only login cookies No stupid password restrictions Two-factor authentications No DNS record limits Rough DNS statistics (queries/day, etc.) Audit trails GoDaddy has all of these, except two-factor, for $3/month. See http://www.godaddy.com/domains/dns-hosting.aspx I can't seem to find any other registrar that supports even a few of these. Is there a registrar that offers comparable features? Or, barring that, a DNS hosting service that offers similar features? (AWS Route53 doesn't offer DNSSEC or IPv6)

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  • DNS: forward part of a managed domain to one host, but sub domain services to another (Google Apps)

    - by Paul Zee
    I was going to post this as a comment against DNS: Forward domain to another host, but I don't seem able to do that. I'm in a similar situation. I have a DNS registered/managed by enom, except with the slight twist that the domain was originally registered with enom through a Google Apps account creation. The domain currently supports a Google Apps site/account. I now want to direct the bare primary domain and www entries to a hosting provider for the website component, but leave the Google Apps setup intact for its services such as calendar, mail etc. For now, I'm leaving the domain managed by enom. Also note that when I registered my account with the hosting provider, I gave the same domain name as the existing domain (e.g. example.com), so at their end I'm working with the same domain name in cpanel, etc. In my case, the existing enom DNS entries don't have an A record for the www.example.com, or the bare example.com domain. Instead, there are 4 x @ records with the Google Apps IP Address, 2 x TXT records with what I assume are Google Apps site verification strings/tokens, and a bunch of CNAME records for the various features of Google Apps (mail, calendar, docs, sites, etc). So, my questions: How do I point the www.example.com and example.com DNS entries at enom to my web site hosting provider, while leaving the domain managed by enom, and the Google Apps services working as they are now (with the obvious exception of Google Sites)? How do I setup the example.com mail-related DNS records (MX, etc) at the web site hosting provider, so that outbound email to [email protected] gets correctly sent to the google apps mail account, and doesn't get trapped inside the pseudo domain within the hosting providers servers?

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  • Recommendations for managing DNS issues when hosting customer sites.

    - by Thomas
    I'm working at a company which primarily provides SaaS products but also will host some of our customers corporate websites. My question relates to recommendations for managing DNS for client's domain names. My objectives: Not restrict my ability to change the server's IP address such as might happen when I move my servers to a new host. Not have to contact the customer to change their domain's DNS if I need to change the server's IP address. Often times, customers lose this information or have to track down the one person with any knowledge of the domain settings. Map both .clientdomain.com and www.clientdomain.com to the proper IIS site. However, I'm running into a couple of common problems: Sometimes, the DNS console provided by the client's hosting company does not allow for CNAME records. Sometimes, the DNS console provided by the client's hosting company will not let me create a CNAME entry for .spiffydomain.com because the given hosting company has created a SOA record for that entry or simply requires that .spiffydomain.com be an A record. I believe one solution to #2 is to use a wildcard for a CNAME entry (i.e. *.spiffydomain.com). Is that correct? How do other folks that are hosting many customer's site manage change of DNS entries on their servers?

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  • Problems with DNS propagation 10 days after a change was made

    - by runlevel6
    The engineering team I work with has been in the process of moving equipment from one datacenter to another. Ten days ago we moved one of our name servers authoritative for our client's domains (ns1.faithhiway.com) and updated its IP address with its respective DNS provider (register.com) to point to the new datacenter. All tests done show that this name server is correctly running at its new location and when queried, returning the correct response for any domains it is responsible for. The problem is that well after 72 hours had gone by we were still seeing more DNS activity at its old IP address than at the new. The good news is that we kept a name server responding on the old IP address for the time being so we are not seeing any issues with the domains our nameserver is responsible for but the goal is to retire that as soon as possible. As you can see from WhatsMyDNS.net, a decent amount of propagation has occurred over the last 10 days since we made this change, but still there are some locations reporting our original IP. Considering that the TTL is only 3600 with the name servers responsible for this domain, it does not make any sense to myself or the other engineers working with me that we are having this issue. Now if I run a DNS check using one of the Register.com DNS servers (direct nameservers for faithhiway.com), I get the following (correct) result: # dig @dns01.gpn.register.com ns1.faithhiway.com A ; <<>> DiG 9.3.6-P1-RedHat-9.3.6-4.P1.el5_5.3 <<>> @dns01.gpn.register.com. ns1.faithhiway.com A ; (1 server found) ;; global options: printcmd ;; Got answer: ;; ->>HEADER<<- opcode: QUERY, status: NOERROR, id: 43232 ;; flags: qr aa; QUERY: 1, ANSWER: 1, AUTHORITY: 5, ADDITIONAL: 5 ;; QUESTION SECTION: ;ns1.faithhiway.com. IN A ;; ANSWER SECTION: ns1.faithhiway.com. 3601 IN A 206.127.2.71 ;; AUTHORITY SECTION: faithhiway.com. 3600 IN NS dns01.gpn.register.com. faithhiway.com. 3600 IN NS dns02.gpn.register.com. faithhiway.com. 3600 IN NS dns03.gpn.register.com. faithhiway.com. 3600 IN NS dns04.gpn.register.com. faithhiway.com. 3600 IN NS dns05.gpn.register.com. ;; ADDITIONAL SECTION: dns01.gpn.register.com. 3600 IN A 98.124.192.1 dns02.gpn.register.com. 3600 IN A 98.124.197.1 dns03.gpn.register.com. 3600 IN A 98.124.193.1 dns04.gpn.register.com. 3600 IN A 69.64.145.225 dns05.gpn.register.com. 3600 IN A 98.124.196.1 ;; Query time: 50 msec ;; SERVER: 98.124.192.1#53(98.124.192.1) ;; WHEN: Thu Jan 27 15:16:57 2011 ;; MSG SIZE rcvd: 269 Just as a reference, here are the results when the same query is checked against a variety of Public DNS servers: Google: # dig @8.8.8.8 ns1.faithhiway.com A ; <<>> DiG 9.3.6-P1-RedHat-9.3.6-4.P1.el5_5.3 <<>> @8.8.8.8. ns1.faithhiway.com A ; (1 server found) ;; global options: printcmd ;; Got answer: ;; ->>HEADER<<- opcode: QUERY, status: NOERROR, id: 12773 ;; flags: qr rd ra; QUERY: 1, ANSWER: 1, AUTHORITY: 0, ADDITIONAL: 0 ;; QUESTION SECTION: ;ns1.faithhiway.com. IN A ;; ANSWER SECTION: ns1.faithhiway.com. 997 IN A 206.127.2.71 ;; Query time: 29 msec ;; SERVER: 8.8.8.8#53(8.8.8.8) ;; WHEN: Thu Jan 27 15:17:31 2011 ;; MSG SIZE rcvd: 52 Level 3: # dig @4.2.2.1 ns1.faithhiway.com A ; <<>> DiG 9.3.6-P1-RedHat-9.3.6-4.P1.el5_5.3 <<>> @4.2.2.1. ns1.faithhiway.com A ; (1 server found) ;; global options: printcmd ;; Got answer: ;; ->>HEADER<<- opcode: QUERY, status: NOERROR, id: 46505 ;; flags: qr rd ra; QUERY: 1, ANSWER: 1, AUTHORITY: 0, ADDITIONAL: 0 ;; QUESTION SECTION: ;ns1.faithhiway.com. IN A ;; ANSWER SECTION: ns1.faithhiway.com. 2623 IN A 206.127.2.71 ;; Query time: 7 msec ;; SERVER: 4.2.2.1#53(4.2.2.1) ;; WHEN: Thu Jan 27 15:18:35 2011 ;; MSG SIZE rcvd: 52 Verizon: # dig @151.197.0.38 ns1.faithhiway.com A ; <<>> DiG 9.3.6-P1-RedHat-9.3.6-4.P1.el5_5.3 <<>> @151.197.0.38. ns1.faithhiway.com A ; (1 server found) ;; global options: printcmd ;; Got answer: ;; ->>HEADER<<- opcode: QUERY, status: NOERROR, id: 32658 ;; flags: qr rd ra; QUERY: 1, ANSWER: 1, AUTHORITY: 0, ADDITIONAL: 0 ;; QUESTION SECTION: ;ns1.faithhiway.com. IN A ;; ANSWER SECTION: ns1.faithhiway.com. 3601 IN A 206.127.2.71 ;; Query time: 81 msec ;; SERVER: 151.197.0.38#53(151.197.0.38) ;; WHEN: Thu Jan 27 15:19:15 2011 ;; MSG SIZE rcvd: 52 Cisco: # dig @64.102.255.44 ns1.faithhiway.com A ; <<>> DiG 9.3.6-P1-RedHat-9.3.6-4.P1.el5_5.3 <<>> @64.102.255.44. ns1.faithhiway.com A ; (1 server found) ;; global options: printcmd ;; Got answer: ;; ->>HEADER<<- opcode: QUERY, status: NOERROR, id: 39689 ;; flags: qr rd ra; QUERY: 1, ANSWER: 1, AUTHORITY: 5, ADDITIONAL: 0 ;; QUESTION SECTION: ;ns1.faithhiway.com. IN A ;; ANSWER SECTION: ns1.faithhiway.com. 3601 IN A 206.127.2.71 ;; AUTHORITY SECTION: faithhiway.com. 3600 IN NS dns01.gpn.register.com. faithhiway.com. 3600 IN NS dns04.gpn.register.com. faithhiway.com. 3600 IN NS dns05.gpn.register.com. faithhiway.com. 3600 IN NS dns02.gpn.register.com. faithhiway.com. 3600 IN NS dns03.gpn.register.com. ;; Query time: 105 msec ;; SERVER: 64.102.255.44#53(64.102.255.44) ;; WHEN: Thu Jan 27 15:20:05 2011 ;; MSG SIZE rcvd: 165 OpenDNS: # dig @208.67.222.222 ns1.faithhiway.com A ; <<>> DiG 9.3.6-P1-RedHat-9.3.6-4.P1.el5_5.3 <<>> @208.67.222.222. ns1.faithhiway.com A ; (1 server found) ;; global options: printcmd ;; Got answer: ;; ->>HEADER<<- opcode: QUERY, status: NOERROR, id: 12328 ;; flags: qr rd ra; QUERY: 1, ANSWER: 1, AUTHORITY: 0, ADDITIONAL: 0 ;; QUESTION SECTION: ;ns1.faithhiway.com. IN A ;; ANSWER SECTION: ns1.faithhiway.com. 169507 IN A 207.200.19.162 ;; Query time: 6 msec ;; SERVER: 208.67.222.222#53(208.67.222.222) ;; WHEN: Thu Jan 27 15:19:29 2011 ;; MSG SIZE rcvd: 52 SpeakEasy: # dig @66.93.87.2 ns1.faithhiway.com A ; <<>> DiG 9.3.6-P1-RedHat-9.3.6-4.P1.el5_5.3 <<>> @66.93.87.2. ns1.faithhiway.com A ; (1 server found) ;; global options: printcmd ;; Got answer: ;; ->>HEADER<<- opcode: QUERY, status: NOERROR, id: 9342 ;; flags: qr rd ra; QUERY: 1, ANSWER: 1, AUTHORITY: 0, ADDITIONAL: 0 ;; QUESTION SECTION: ;ns1.faithhiway.com. IN A ;; ANSWER SECTION: ns1.faithhiway.com. 169323 IN A 207.200.19.162 ;; Query time: 69 msec ;; SERVER: 66.93.87.2#53(66.93.87.2) ;; WHEN: Thu Jan 27 15:19:51 2011 ;; MSG SIZE rcvd: 52 As you can see above, the majority of queries are returning the correct result. But a few (OpenDNS and SpeakEasy in the examples above) are still showing the old IP address. Considering the length of time that has gone by, it seems obvious to me that either we have made a mistake and not thoroughly handled the DNS changes on our end (likely) or there is a problem with either the DNS provider for this domain (Register) or with some of the DNS servers out in the wild (rather unlikely). Any advice on how I can proceed with this? UPDATE (January 31, 2011): First of all, I apologize for the length of both the original question and this update. I contemplated removing some of the excess from the original post but just in case this problem and its solution are helpful to someone else in the future I'm just going to leave everything as it is. Anyway, I've been doing some more research into this problem, and have discovered the following interesting occurrence. While running a check on the glue records for faithhiway.com always resolve correctly, if I go and check a client domain (where ns1.faithhiway.com is authoritative), I get a strange response. It looks like the root servers are returning nsX.faithhiway.com as their old IP addresses still (under Additional Section). Because we have a server still there responding to DNS queries, the trace finishes and returns the correct IP addresses as the final step (again, under Additional Section). The example below uses one of the domains that we use that uses ns1.faithhiway.com as its authoritative DNS server. # dig +trace +nosearch +all +norecurse ignitemail.com ; <<>> DiG 9.2.4 <<>> +trace +nosearch +all +norecurse ignitemail.com ;; global options: printcmd ;; Got answer: ;; ->>HEADER<<- opcode: QUERY, status: NOERROR, id: 46856 ;; flags: qr ra; QUERY: 1, ANSWER: 13, AUTHORITY: 0, ADDITIONAL: 0 ;; QUESTION SECTION: ;. IN NS ;; ANSWER SECTION: . 7986 IN NS a.root-servers.net. . 7986 IN NS b.root-servers.net. . 7986 IN NS c.root-servers.net. . 7986 IN NS d.root-servers.net. . 7986 IN NS e.root-servers.net. . 7986 IN NS f.root-servers.net. . 7986 IN NS g.root-servers.net. . 7986 IN NS h.root-servers.net. . 7986 IN NS i.root-servers.net. . 7986 IN NS j.root-servers.net. . 7986 IN NS k.root-servers.net. . 7986 IN NS l.root-servers.net. . 7986 IN NS m.root-servers.net. ;; Query time: 39 msec ;; SERVER: 8.8.8.8#53(8.8.8.8) ;; WHEN: Mon Jan 31 09:22:17 2011 ;; MSG SIZE rcvd: 228 ;; Got answer: ;; ->>HEADER<<- opcode: QUERY, status: NOERROR, id: 16325 ;; flags: qr; QUERY: 1, ANSWER: 0, AUTHORITY: 13, ADDITIONAL: 14 ;; QUESTION SECTION: ;ignitemail.com. IN A ;; AUTHORITY SECTION: com. 172800 IN NS h.gtld-servers.net. com. 172800 IN NS m.gtld-servers.net. com. 172800 IN NS i.gtld-servers.net. com. 172800 IN NS l.gtld-servers.net. com. 172800 IN NS c.gtld-servers.net. com. 172800 IN NS k.gtld-servers.net. com. 172800 IN NS d.gtld-servers.net. com. 172800 IN NS f.gtld-servers.net. com. 172800 IN NS b.gtld-servers.net. com. 172800 IN NS a.gtld-servers.net. com. 172800 IN NS e.gtld-servers.net. com. 172800 IN NS g.gtld-servers.net. com. 172800 IN NS j.gtld-servers.net. ;; ADDITIONAL SECTION: a.gtld-servers.net. 172800 IN A 192.5.6.30 a.gtld-servers.net. 172800 IN AAAA 2001:503:a83e::2:30 b.gtld-servers.net. 172800 IN A 192.33.14.30 b.gtld-servers.net. 172800 IN AAAA 2001:503:231d::2:30 c.gtld-servers.net. 172800 IN A 192.26.92.30 d.gtld-servers.net. 172800 IN A 192.31.80.30 e.gtld-servers.net. 172800 IN A 192.12.94.30 f.gtld-servers.net. 172800 IN A 192.35.51.30 g.gtld-servers.net. 172800 IN A 192.42.93.30 h.gtld-servers.net. 172800 IN A 192.54.112.30 i.gtld-servers.net. 172800 IN A 192.43.172.30 j.gtld-servers.net. 172800 IN A 192.48.79.30 k.gtld-servers.net. 172800 IN A 192.52.178.30 l.gtld-servers.net. 172800 IN A 192.41.162.30 ;; Query time: 64 msec ;; SERVER: 198.41.0.4#53(a.root-servers.net) ;; WHEN: Mon Jan 31 09:22:17 2011 ;; MSG SIZE rcvd: 504 ;; Got answer: ;; ->>HEADER<<- opcode: QUERY, status: NOERROR, id: 12860 ;; flags: qr; QUERY: 1, ANSWER: 0, AUTHORITY: 2, ADDITIONAL: 2 ;; QUESTION SECTION: ;ignitemail.com. IN A ;; AUTHORITY SECTION: ignitemail.com. 172800 IN NS ns1.faithhiway.com. ignitemail.com. 172800 IN NS ns2.faithhiway.com. ;; ADDITIONAL SECTION: ns1.faithhiway.com. 172800 IN A 207.200.19.162 ns2.faithhiway.com. 172800 IN A 207.200.50.142 ;; Query time: 152 msec ;; SERVER: 192.54.112.30#53(h.gtld-servers.net) ;; WHEN: Mon Jan 31 09:22:17 2011 ;; MSG SIZE rcvd: 111 ;; Got answer: ;; ->>HEADER<<- opcode: QUERY, status: NOERROR, id: 43016 ;; flags: qr aa; QUERY: 1, ANSWER: 1, AUTHORITY: 2, ADDITIONAL: 2 ;; QUESTION SECTION: ;ignitemail.com. IN A ;; ANSWER SECTION: ignitemail.com. 3600 IN A 206.127.2.64 ;; AUTHORITY SECTION: ignitemail.com. 3600 IN NS ns1.faithhiway.com. ignitemail.com. 3600 IN NS ns2.faithhiway.com. ;; ADDITIONAL SECTION: ns1.faithhiway.com. 3600 IN A 206.127.2.71 ns2.faithhiway.com. 3600 IN A 206.127.2.72 ;; Query time: 25 msec ;; SERVER: 206.127.2.71#53(ns1.faithhiway.com) ;; WHEN: Mon Jan 31 09:22:18 2011 ;; MSG SIZE rcvd: 127 I really think this is a problem we have somewhere in our setup, but whether it is ignorance of something with DNS on my or my fellow engineer's end or just a dumb mistake we made, I have yet to find it.

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  • Permutation algorithm without recursion? Java

    - by Andreas Hornig
    Hi, I would like to get all combination of a number without any repetation. Like 0.1.2, 0.2.1, 1.2.0, 1.0.2, 2.0.1, 2.1.0. I tried to find an easy scheme but couldn't find so I drawed a graph/tree for it and this screams to use recursion. But I would like to do it without, if this is possible. So could anyone please help me how to do that? Thank you in advance, Andreas

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  • Permutatation algorithm without recursion? Java

    - by Andreas Hornig
    Hi, I would like to get all combination of a number without any repetation. Like 0.1.2, 0.2.1, 1.2.0, 1.0.2, 2.0.1, 2.1.0. I tried to find an easy scheme but couldn't find so I drawed a graph/tree for it and this screams to use recursion. But I would like to do it without, if this is possible. So could anyone please help mw how to do that? Thank you in advance, Andreas

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  • XSLT 1.0 recursion

    - by DashaLuna
    I'm stuck with recursion, was wondering if anyone can help me out with it. I have <Receipts> and <Deposits> elements, that are not verbose, i.e. that a <Receipts> element doesn't have an attribute to show what <Deposit> it is towards. I need to figure out <Deposits> "still amount due" and when a last receipt towards it was paid if any. I'm trying to do it with the following code: The idea was to take 1st deposit and see if there are receipts. If the deposit isn't fully paid and there are more receipts - call that recorsive function with all the same params except now count in following receipt. If there aren't any more receipts or deposit is payed - process it correctly (add required attributes). Otherwise proceed with 2nd deposit. And so on. However, the XSLT crashes with error message that "a processor stack has overflowed - possible cause is infinite template recursion" I would really appreciate any help/teps... I'm not that great with recursion and can't understand why mine here doesn't work. Thanks! :) <!-- Accumulate all the deposits with @DueAmount attribute --> <xsl:variable name="depositsClassified"> <xsl:call-template name="classifyDeposits"> <!-- a node-list of all Deposits elements ordered by DueDate Acs --> <xsl:with-param name="depositsAll" select="$deposits"/> <xsl:with-param name="depositPrevAmount" select="'0'"/> <!-- a node-list of all Receipts elements ordered by ReceivedDate Acs --> <xsl:with-param name="receiptsAll" select="$receiptsAsc"/> <xsl:with-param name="receiptCount" select="'1'"/> </xsl:call-template> </xsl:variable> <xsl:template name="classifyDeposits"> <xsl:param name="depositsAll"/> <xsl:param name="depositPrevAmount" select="'0'"/> <xsl:param name="receiptsAll"/> <xsl:param name="receiptCount"/> <xsl:if test="$deposits"> <!-- Do required operations for the 1st deposit --> <xsl:variable name="depositFirst" select="$depositsAll[1]"/> <xsl:variable name="receiptSum"> <xsl:choose> <xsl:when test="$receiptsAll"> <xsl:value-of select="sum($receiptsAll[position() &lt;= $receiptCount]/@ActionAmount)"/> </xsl:when> <xsl:otherwise>0</xsl:otherwise> </xsl:choose> </xsl:variable> <xsl:variable name="diff" select="$depositPrevAmount + $depositFirst/@DepositTotalAmount - $receiptSum"/> <xsl:choose> <xsl:when test="$diff &gt; 0 and $receiptCount &lt; $receiptsQuantityOf"> <xsl:call-template name="classifyDeposits"> <xsl:with-param name="depositsAll" select="$depositsAll"/> <xsl:with-param name="depositPrevAmount" select="$depositPrevAmount"/> <xsl:with-param name="receiptsAll" select="$receiptsAll"/> <xsl:with-param name="receiptCount" select="$receiptCount + 1"/> </xsl:call-template> </xsl:when> <xsl:otherwise> <!-- Record changes to the deposit (@DueAmount and receipt ReceivedDate) --> <xsl:apply-templates select="$depositFirst" mode="defineDeposit"> <xsl:with-param name="diff" select="$diff"/> <xsl:with-param name="latestReceiptForDeposit" select="$receiptsAll[position() = $receiptCount]"/> </xsl:apply-templates> <!-- Recursive call to the next deposit --> <xsl:call-template name="classifyDeposits"> <xsl:with-param name="depositsAll" select="$depositsAll[position() &gt; 1]"/> <xsl:with-param name="depositPrevAmount" select="$depositPrevAmount + $depositFirst/@DepositTotalAmount"/> <xsl:with-param name="receiptsAll" select="$receiptsAll"/> <xsl:with-param name="receiptCount" select="'1'"/> </xsl:call-template> </xsl:otherwise> </xsl:choose> </xsl:if> </xsl:template> <!-- Determine deposit's status, due amount and payment received date if any --> <xsl:template match="Deposits" mode="defineDeposit"> <xsl:param name="diff"/> <xsl:param name="latestReceiptForDeposit"/> <xsl:choose> <xsl:when test="$diff &lt;= 0"> <xsl:apply-templates select="." mode="addAttrs"> <xsl:with-param name="status" select="'paid'"/> <xsl:with-param name="dueAmount" select="'0'"/> <xsl:with-param name="receipt" select="$latestReceiptForDeposit"/> </xsl:apply-templates> </xsl:when> <xsl:when test="$diff = ./@DepositTotalAmount"> <xsl:apply-templates select="." mode="addAttrs"> <xsl:with-param name="status" select="'due'"/> <xsl:with-param name="dueAmount" select="$diff"/> </xsl:apply-templates> </xsl:when> <xsl:when test="$diff &lt; ./@DepositTotalAmount"> <xsl:apply-templates select="." mode="addAttrs"> <xsl:with-param name="status" select="'outstanding'"/> <xsl:with-param name="dueAmount" select="$diff"/> <xsl:with-param name="receipt" select="$latestReceiptForDeposit"/> </xsl:apply-templates> </xsl:when> <xsl:otherwise/> </xsl:choose> </xsl:template> <xsl:template match="Deposits" mode="addAttrs"> <xsl:param name="status"/> <xsl:param name="dueAmount"/> <xsl:param name="receipt" select="''"/> <!-- Constract a new MultiDeposits element with required info --> <xsl:copy> <xsl:copy-of select="./@*"/> <xsl:attribute name="Status"><xsl:value-of select="$status"/></xsl:attribute> <xsl:attribute name="DueAmount"><xsl:value-of select="$dueAmount"/></xsl:attribute> <xsl:if test="$receipt"> <xsl:attribute name="latestReceiptDate"> <xsl:value-of select="$receipt/@ActionDate"/> </xsl:attribute> </xsl:if> <xsl:copy-of select="./*"/> </xsl:copy> </xsl:template>

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  • Good use of recursion in chess programming?

    - by JDelage
    Hi, As part of a homework assignment, I have to program a simple chess game in Java. I was thinking of taking the opportunity to experiment with recursion, and I was wondering if there's an obvious candidate in chess for recursive code? Thank you, JDelage

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  • Print Alternating Characters From Two Strings (Interleaving) Using Recursion Java

    - by babi2balla
    I'm trying to write a method that uses recursion to print the string formed by "interleaving" the strings str1 and str2. In other words, it should alternate characters from the two strings: the first character from str1, followed by the first character from str2, followed by the second character from str1, followed by the second character from str2, etc. How would I go about this? Any ideas are greatly appreciated!! Thanks

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  • Recursion problem; completely lost

    - by timeNomad
    So I've been trying to solve this assignment whole day, just can't get it. The following function accepts 2 strings, the 2nd (not 1st) possibly containing *'s (asterisks). An * is a replacement for a string (empty, 1 char or more), it can appear appear (only in s2) once, twice, more or not at all, it cannot be adjacent to another * (ab**c), no need to check that. public static boolean samePattern(String s1, String s2) It returns true if strings are of the same pattern. It must be recursive, not use any loops, static & global variables. Can use local variables & method overloading. Can use only these methods: charAt(i), substring(i), substring(i, j), length(). Examples: 1: TheExamIsEasy; 2: "The*xamIs*y" --- true 1: TheExamIsEasy; 2: "Th*mIsEasy*" --- true 1: TheExamIsEasy; 2: "*" --- true 1: TheExamIsEasy; 2: "TheExamIsEasy" --- true 1: TheExamIsEasy; 2: "The*IsHard" --- FALSE I tried comparing the the chars one by one using charAt until an asterisk is encountered, then check if the asterisk is an empty one by comparing is successive char (i+1) with the char of s1 at position i, if true -- continue recursion with i+1 as counter for s2 & i as counter for s1; if false -- continue recursion with i+1 as counters for both. Continue this until another asterisk is found or end of string. I dunno, my brain loses track of things, can't concentrate, any pointers / hints? Am I in the right direction? Also, it's been told that a backtracking technique is to be used to solve this. My code so far (doesn't do the job, even theoretically): public static boolean samePattern(String s1, String s2) { if (s1.equals(s2) || s2 == "*") { return true; } return samePattern(s1, s2, 1); } public static boolean samePattern(String s1, String s2, int i) { if (s1.equals(s2)) return true; if (i == s2.length() - 1) // No *'s found -- not same pattern. return false; if (s1.substring(0, i).equals(s2.substring(0, i))) samePattern(s1, s2, i+1); else if (s2.charAt(i-1) == '*') samePattern(s1.substring(0, i-1), s2.substring(0, i), 1); // new smaller strings. else samePattern(s1.substring(1), s2, i); }

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  • Pyjamas & JavaScript: Too much recursion

    - by Wraith
    I'm doing a Pyjamas example and get this error: TodoApp InternalError: too much recursion Has anyone else encountered this? Some articles around the web recommend adjusting the C++ code of your browser to fix it, but that doesn't seem safe to me.

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  • F# mutual recursion between modules

    - by rwallace
    For recursion in F#, existing documentation is clear about how to do it in the special case where it's just one function calling itself, or a group of physically adjacent functions calling each other. But in the general case where a group of functions in different modules need to call each other, how do you do it?

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  • C++ Recursion Issue

    - by stupidmonkey
    Hi guys, I feel a little dumb asking this, but here we go... When trying to follow the Recursion example at the following website http://www.cplusplus.com/doc/tutorial/functions2/, I ran into a road bump that has me perplexed. I altered the code slightly just to get my head around the code in the recursion example and I pretty much have my head around it, but I can't figure out why the variable 'n' increments in 'Pass B' when I have not told the program to increment 'n'. Could you please help explain this? #include <stdlib.h> #include <iostream> using namespace std; long factorial (long n) { if (n > 1) { long r(0); cout << "Pass A" << endl; cout << "n = " << n << endl; cout << "r = " << r << endl; r = n * factorial (n-1); cout << "Pass B" << endl; cout << "n = " << n << endl; cout << "r = " << r << endl; return (r); } else return (1); } int main () { long number; cout << "Please type a number: "; cin >> number; cout << number << "! = " << factorial (number) << endl; system ("pause"); return 0; }

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  • c++ recursion with arrays

    - by Sam
    I have this project that I'm working on for a class, and I'm not looking for the answer, but maybe just a few tips since I don't feel like I'm using true recursion. The problem involves solving the game of Hi Q or "peg solitaire" where you want the end result to be one peg remaining (it's played with a triangular board and one space is open at the start.) I've represented the board with a simple array, each index being a spot and having a value of 1 if it has a peg, and 0 if it doesn't and also the set of valid moves with a 2 dimensional array that is 36, 3 (each move set contains 3 numbers; the peg you're moving, the peg it hops over, and the destination index.) So my problem is that in my recursive function, I'm using a lot of iteration to determine things like which space is open (or has a value of 0) and which move to use based on which space is open by looping through the arrays. Secondly, I don't understand how you would then backtrack with recursion, in the event that an incorrect move was made and you wanted to take that move back in order to choose a different one. This is what I have so far; the "a" array represents the board, the "b" array represents the moves, and the "c" array was my idea of a reminder as to which moves I used already. The functions used are helper functions that basically just loop through the arrays to find an empty space and corresponding move. : void solveGame(int a[15], int b[36][3], int c[15][3]){ int empSpace; int moveIndex; int count = 0; if(pegCount(a) < 2){ return; } else{ empSpace = findEmpty(a); moveIndex = chooseMove( a, b, empSpace); a[b[moveIndex][0]] = 0; a[b[moveIndex][1]] = 0; a[b[moveIndex][2]] = 1; c[count][0] = b[moveIndex][0]; c[count][1] = b[moveIndex][1]; c[count][2] = b[moveIndex][2]; solveGame(a,b,c); } }

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  • Help using recursion in Java

    - by Mercer
    I have a class Group. In the class I have two fields, idGroup IdGroupGroup. Groups may be part of other groups. My class Group is defined in a HashMap<Integer,Integer>; the key is IdGroupGroup and value is idGroup. I want to search the map for a particular idGroup; can I use recursion to do this?

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  • recursion resulting in extra unwanted data

    - by spacerace
    I'm writing a module to handle dice rolling. Given x die of y sides, I'm trying to come up with a list of all potential roll combinations. This code assumes 3 die, each with 3 sides labeled 1, 2, and 3. (I realize I'm using "magic numbers" but this is just an attempt to simplify and get the base code working.) int[] set = { 1, 1, 1 }; list = diceroll.recurse(0,0, list, set); ... public ArrayList<Integer> recurse(int index, int i, ArrayList<Integer> list, int[] set){ if(index < 3){ // System.out.print("\n(looping on "+index+")\n"); for(int k=1;k<=3;k++){ // System.out.print("setting i"+index+" to "+k+" "); set[index] = k; dump(set); recurse(index+1, i, list, set); } } return list; } (dump() is a simple method to just display the contents of list[]. The variable i is not used at the moment.) What I'm attempting to do is increment a list[index] by one, stepping through the entire length of the list and incrementing as I go. This is my "best attempt" code. Here is the output: Bold output is what I'm looking for. I can't figure out how to get rid of the rest. (This is assuming three dice, each with 3 sides. Using recursion so I can scale it up to any x dice with y sides.) [1][1][1] [1][1][1] [1][1][1] [1][1][2] [1][1][3] [1][2][3] [1][2][1] [1][2][2] [1][2][3] [1][3][3] [1][3][1] [1][3][2] [1][3][3] [2][3][3] [2][1][3] [2][1][1] [2][1][2] [2][1][3] [2][2][3] [2][2][1] [2][2][2] [2][2][3] [2][3][3] [2][3][1] [2][3][2] [2][3][3] [3][3][3] [3][1][3] [3][1][1] [3][1][2] [3][1][3] [3][2][3] [3][2][1] [3][2][2] [3][2][3] [3][3][3] [3][3][1] [3][3][2] [3][3][3] I apologize for the formatting, best I could come up with. Any help would be greatly appreciated. (This method was actually stemmed to use the data for something quite trivial, but has turned into a personal challenge. :) edit: If there is another approach to solving this problem I'd be all ears, but I'd also like to solve my current problem and successfully use recursion for something useful.

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  • Dynamic DNS registration for VPN clients

    - by Eric Falsken
    I've got a VPN server set up in my Active Directory on a remote network. (VPN Server is separate box from DNS/AD) When I dial into the network (client machine is not a member of the AD) the machine does not register its IP or Hostname in the DNS. I've played with all possible combinations of DHCP and RRAS-allocated IP pools, and none of them seem to cause my client to register. Is it because my client has to be a member of the domain? Are there some security settins I can tweak so that it can register its hostname/ip? I've looked in the event logs (System and Security) for the AD, DNS, DHCP, RRAS, and the client machine, and don't see anything relating to DNS Registration. Here's the IPConfig on the client machine (once connected): PPP adapter My VPN Name: Connection-specific DNS Suffix . : mydomain.local Description . . . . . . . . . . . : My VPN Name Physical Address. . . . . . . . . : DHCP Enabled. . . . . . . . . . . : No Autoconfiguration Enabled . . . . : Yes IPv4 Address. . . . . . . . . . . : 192.168.1.22(Preferred) Subnet Mask . . . . . . . . . . . : 255.255.255.255 Default Gateway . . . . . . . . . : DNS Servers . . . . . . . . . . . : 192.168.1.52 <- DC1 192.168.1.53 <- DC2 NetBIOS over Tcpip. . . . . . . . : Enabled Edit: It looks like my clients are not recieving the DHCP Scoope Options. I found this great article in Microsoft's KB. So the problem here is that the VPN Server "pre-reserves" the DHCP addresses, but then you have to add the DHCP Relay Agent to relay the secondary request for scope options. My problem is that the DHCP Relay Agent isn't relaying to the local DHCP server (same box as the VPN/RRAS). I've configured the DHCP Relay Agent according to this KB, but it dosn't work for a local DHCP server. (I see the request count increasing, but no responses) I was able to get everything working by specifying the DNS server and domain name in the VPN connection properties on the client. But am still unable to assign it (or the default gateway) dynamically via DHCP. The client also has to be a member of the remote domain.

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  • DNS problems on CentOS fresh install

    - by Rick Koshi
    I'm having some DNS issues on a new box I'm installing with CentOS 6.2. I am able to look up names using nslookup, dig, or host. I am able to ping machines by name or by IP address. However, when I try other tools, such as ssh, wget, or yum, they are unable to resolve names. For example: # wget http://www.google.com --2012-03-08 14:48:06-- http://www.google.com/ Resolving www.google.com... failed: Name or service not known. wget: unable to resolve host address `www.google.com' # ssh www.google.com ssh: Could not resolve hostname www.google.com: Name or service not known # ping -c 1 www.google.com PING www.l.google.com (74.125.113.106) 56(84) bytes of data. 64 bytes from vw-in-f106.1e100.net (74.125.113.106): icmp_seq=1 ttl=46 time=43.6 ms --- www.l.google.com ping statistics --- 1 packets transmitted, 1 received, 0% packet loss, time 59ms rtt min/avg/max/mdev = 43.665/43.665/43.665/0.000 ms # host www.google.com www.google.com is an alias for www.l.google.com. www.l.google.com has address 74.125.113.99 www.l.google.com has address 74.125.113.103 www.l.google.com has address 74.125.113.104 www.l.google.com has address 74.125.113.105 www.l.google.com has address 74.125.113.106 www.l.google.com has address 74.125.113.147 My /etc/nsswitch.conf file is the default, including this (standard) line: hosts: files dns /etc/resolv.conf is as set up by DHCP: ; generated by /sbin/dhclient-script nameserver 192.168.1.254 192.168.1.254 is a working DNS server (my DSL modem, working for years with other machines) Anyone know why ping would work, but ssh/wget would fail? Per NcA's suggestion, I tried changing /etc/resolv.conf to point to 8.8.8.8. Oddly enough, this does make it work. Obviously, my DSL modem is responding to DNS requests in some way that some parts of Linux's resolution system don't like. Looking at the tcpdump, I am unable to see what the difference is. Certainly, both servers are sending the same addresses. Here's the output from tcpdump -nn -X with the server set to the DNS server on the DSL modem. It's clearly replying with the correct addresses, but ssh/wget don't seem happy with it for some reason: 15:53:52.133580 IP 192.168.1.254.53 > 192.168.1.2.54836: 33157 7/0/0 CNAME www.l.google.com., A 74.125.115.105, A 74.125.115.106, A 74.125.115.147, A 74.125.115.99, A 74.125.115.103, A 74.125.115.104 (148) 0x0000: 4500 00b0 e33a 0000 ff11 53b1 c0a8 01fe E....:....S..... 0x0010: c0a8 0102 0035 d634 009c 7528 8185 8180 .....5.4..u(.... 0x0020: 0001 0007 0000 0000 0377 7777 0667 6f6f .........www.goo 0x0030: 676c 6503 636f 6d00 0001 0001 c00c 0005 gle.com......... 0x0040: 0001 0007 acd0 0008 0377 7777 016c c010 .........www.l.. 0x0050: c02c 0001 0001 0000 0001 0004 4a7d 7369 .,..........J}si 0x0060: c02c 0001 0001 0000 0001 0004 4a7d 736a .,..........J}sj 0x0070: c02c 0001 0001 0000 0001 0004 4a7d 7393 .,..........J}s. 0x0080: c02c 0001 0001 0000 0001 0004 4a7d 7363 .,..........J}sc 0x0090: c02c 0001 0001 0000 0001 0004 4a7d 7367 .,..........J}sg 0x00a0: c02c 0001 0001 0000 0001 0004 4a7d 7368 .,..........J}sh 15:53:52.135669 IP 192.168.1.254.53 > 192.168.1.2.54836: 65062- 0/0/0 (32) 0x0000: 4500 003c e33b 0000 ff11 5424 c0a8 01fe E..<.;....T$.... 0x0010: c0a8 0102 0035 d634 0028 98f9 fe26 8000 .....5.4.(...&.. 0x0020: 0001 0000 0000 0000 0377 7777 0667 6f6f .........www.goo 0x0030: 676c 6503 636f 6d00 001c 0001 gle.com..... I'm not enough of an expert to know if this is malformed in some way, but ping seems to do the right thing with it. For comparison, here's the same thing when querying 8.8.8.8: 15:57:27.990270 IP 8.8.8.8.53 > 192.168.1.2.49028: 59114 7/0/0 CNAME www.l.google.com., A 74.125.113.105, A 74.125.113.103, A 74.125.113.106, A 74.125.113.147, A 74.125.113.104, A 74.125.113.99 (148) 0x0000: 4500 00b0 5530 0000 2f11 6453 0808 0808 E...U0../.dS.... 0x0010: c0a8 0102 0035 bf84 009c 39f8 e6ea 8180 .....5....9..... 0x0020: 0001 0007 0000 0000 0377 7777 0667 6f6f .........www.goo 0x0030: 676c 6503 636f 6d00 0001 0001 c00c 0005 gle.com......... 0x0040: 0001 0001 516a 0008 0377 7777 016c c010 ....Qj...www.l.. 0x0050: c02c 0001 0001 0000 0116 0004 4a7d 7169 .,..........J}qi 0x0060: c02c 0001 0001 0000 0116 0004 4a7d 7167 .,..........J}qg 0x0070: c02c 0001 0001 0000 0116 0004 4a7d 716a .,..........J}qj 0x0080: c02c 0001 0001 0000 0116 0004 4a7d 7193 .,..........J}q. 0x0090: c02c 0001 0001 0000 0116 0004 4a7d 7168 .,..........J}qh 0x00a0: c02c 0001 0001 0000 0116 0004 4a7d 7163 .,..........J}qc 15:57:28.018909 IP 8.8.8.8.53 > 192.168.1.2.49028: 31984 1/1/0 CNAME www.l.google.com. (102) 0x0000: 4500 0082 7b1b 0000 2f11 3e96 0808 0808 E...{.../.>..... 0x0010: c0a8 0102 0035 bf84 006e c67e 7cf0 8180 .....5...n.~|... 0x0020: 0001 0001 0001 0000 0377 7777 0667 6f6f .........www.goo 0x0030: 676c 6503 636f 6d00 001c 0001 c00c 0005 gle.com......... 0x0040: 0001 0001 517f 0008 0377 7777 016c c010 ....Q....www.l.. 0x0050: c030 0006 0001 0000 0258 0026 036e 7334 .0.......X.&.ns4 0x0060: c010 0964 6e73 2d61 646d 696e c010 0016 ...dns-admin.... 0x0070: 91f3 0000 0384 0000 0384 0000 0708 0000 ................ 0x0080: 003c .< I still don't know why the server's reply is adequate for ping but not for ssh/wget. If anyone has ideas, I'd be happy to hear them. For now, though, I can either refer to an outside DNS server or set up my own server on the new box. It's a workaround that seems like it should be unnecessary, but will allow me to proceed.

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  • IPV6 causing issue with DNS

    - by Mike Wells
    I have set up an 'internal' DNS at my work, basically we have ourdomain.com that is for internet, email etc and I have created on one of our linux network servers (debian) a DNS using bind9 with the domain ourdomain.inc. So based on my files below and the symptoms I'm describing; what effect could IPV6 be having on my setup? What can I do to fix this? I assume it is not actually the IPV6 causing the issue, but rather something in my setup. These are the critical (I think) files I have modified: named.conf.local zone "ourdomain.inc" { type master; file "/etc/bind/zones/ourdomain.inc.db"; }; zone "201.168.192.in-addr.arpa" { type master; file "/etc/bind/zones/rev.201.168.192.in-addr.arpa"; }; named.conf.options options { directory "/var/cache/bind"; // If there is a firewall between you and nameservers you want // to talk to, you may need to fix the firewall to allow multiple // ports to talk. See http://www.kb.cert.org/vuls/id/800113 // If your ISP provided one or more IP addresses for stable // nameservers, you probably want to use them as forwarders. // Uncomment the following block, and insert the addresses replacing // the all-0's placeholder. forwarders { 1.2.3.4; //IP of our external DNS provider }; auth-nxdomain no; # conform to RFC1035 listen-on-v6 { any; }; }; ourdomain.inc.db $TTL 86400 ourdomain.inc. IN SOA ns1.ipower.com. admin.ourdomain.inc. ( 2006081401 28800 3600 604800 38400 ) serv1 IN A 192.168.201.223 serv2 IN A 192.168.201.220 serv3 IN A 192.168.201.219 ns1.ipower.com. IN A 1.2.3.4 ns2.ipower.com. IN A 1.2.3.5 @ IN NS ns1.ipower.com. @ IN NS ns2.ipower.com. svn IN CNAME serv1 docs IN CNAME serv2 jira IN CNAME serv3 confluence IN CNAME serv3 fisheye IN CNAME serv3 rev.201.168.192.in-addr.arpa $TTL 86400 201.168.192.in-addr.arpa. IN SOA ns1.ipower.com. admin.ourdomain.inc. ( 2006081401; 28800; 604800; 604800; 86400 ) 223 IN PTR serv1 @ IN NS ns1.ipower.com. @ IN NS ns2.ipower.com. named.conf include "/etc/bind/named.conf.options"; include "/etc/bind/named.conf.local"; include "/etc/bind/named.conf.default-zones"; I then made our internal DNS my preferred DNS with the two external DNSs the next in-line. More the most part this seems to work, I can ping svn.ourdomain.inc and it resolves to the correct IP, I can also ping google.com and it also resolves no problem. So all seem good. However, periodically (couple of times a day at least), I loose the ability to ping the svn.domain.inc (and all others defined under the internal DNS). What seem to fix the issue temporarily is to disable IPV6 on the network adapter of the client machine and then re-enable it. Then it works for a bit but will always fail again. System Info Internal DNS Distributor ID: Debian Description: Debian GNU/Linux 6.0.6 (squeeze) Release: 6.0.6 Codename: squeeze Linux 2.6.32-5-686 i686 BIND 9.7.3 PC OS Name: Microsoft Windows 7 Professional OS Version: 6.1.7601 Service Pack 1 Build 7601 System Type: x64-based PC Network Card(s): 2 NIC(s) Installed. [01]: Realtek PCIe GBE Family Controller Connection Name: WORK LAN DHCP Enabled: No IP address(es) [01]: the.ipv4.address [02]: the:ipv6:address The question... So based on my files above and the symptoms I described; what effect could IPV6 be having on my setup? What can I do to fix this? I assume it is not actually the IPV6 causing the issue, but rather something in my setup.

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  • Dynamic DNS registration for VPN clients

    - by Eric Falsken
    I've got a VPN server set up in my Active Directory on a remote network. (VPN Server is separate box from DNS/AD) When I dial into the network (client machine is not a member of the AD) the machine does not register its IP or Hostname in the DNS. I've played with all possible combinations of DHCP and RRAS-allocated IP pools, and none of them seem to cause my client to register. Is it because my client has to be a member of the domain? Are there some security settins I can tweak so that it can register its hostname/ip? I've looked in the event logs (System and Security) for the AD, DNS, DHCP, RRAS, and the client machine, and don't see anything relating to DNS Registration. Here's the IPConfig on the client machine (once connected): PPP adapter My VPN Name: Connection-specific DNS Suffix . : mydomain.local Description . . . . . . . . . . . : My VPN Name Physical Address. . . . . . . . . : DHCP Enabled. . . . . . . . . . . : No Autoconfiguration Enabled . . . . : Yes IPv4 Address. . . . . . . . . . . : 192.168.1.22(Preferred) Subnet Mask . . . . . . . . . . . : 255.255.255.255 Default Gateway . . . . . . . . . : DNS Servers . . . . . . . . . . . : 192.168.1.52 <- DC1 192.168.1.53 <- DC2 NetBIOS over Tcpip. . . . . . . . : Enabled

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  • Does this code follow the definition of recursion?

    - by dekz
    Hi All, I have a piece of code which I am doubting it as a implementation of recursion by its definition. My understanding is that the code must call itself, the exact same function. I also question whether writing the code this way adds additional overhead which can be seen with the use of recursion. What are your thoughts? class dhObject { public: dhObject** children; int numChildren; GLdouble linkLength; //ai GLdouble theta; //angle of rot about the z axis GLdouble twist; //about the x axis GLdouble displacement; // displacement from the end point of prev along z GLdouble thetaMax; GLdouble thetaMin; GLdouble thetaInc; GLdouble direction; dhObject(ifstream &fin) { fin >> numChildren >> linkLength >> theta >> twist >> displacement >> thetaMax >> thetaMin; //std::cout << numChildren << std::endl; direction = 1; thetaInc = 1.0; if (numChildren > 0) { children = new dhObject*[numChildren]; for(int i = 0; i < numChildren; ++i) { children[i] = new dhObject(fin); } } } void traverse(void) { glPushMatrix(); //draw move initial and draw transform(); draw(); //draw children for(int i = 0; i < numChildren; ++i) { children[i]->traverse(); } glPopMatrix(); } void update(void) { //Update the animation, if it has finished all animation go backwards if (theta <= thetaMin) { thetaInc = 1.0; } else if (theta >= thetaMax) { thetaInc = -1.0; } theta += thetaInc; //std::cout << thetaMin << " " << theta << " " << thetaMax << std::endl; for(int i = 0; i < numChildren; ++i) { children[i]->update(); } } void draw(void) { glPushMatrix(); glColor3f (0.0f,0.0f,1.0f); glutSolidCube(0.1); glPopMatrix(); } void transform(void) { //Move in the correct way, R, T, T, R glRotatef(theta, 0, 0, 1.0); glTranslatef(0,0,displacement); glTranslatef(linkLength, 0,0); glRotatef(twist, 1.0,0.0,0.0); } };

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  • DNS problems with Google on Windows 7

    - by awishformore
    Hello dear superuser community. I had no idea where to post this because it is a problem that completely baffles me. I have a lot of experience with network configuration, but I am completely out of ideas on how to fix this. I have a Fritz!Box branded router on my ISP 1&1 in Germany. My computer is connected to it with a normal Ethernet cable. I always manually set my IP on the computer and use the Google DNS servers for name resolution. I also tried OpenDNS and the result is the same. With that configuration the following happens: Google search responds with big delay Gmail, Google Calendar & Google Drive requests time out the majority of the time In order to troubleshoot, I set the network connection to DHCP for both IP & DNS. At that point, what happens is the following: Google search times out most of the time Gmail, Google Calendar & Google Drive work most of the time Sometimes, it happens that the sites that time out will come up, but weirdly enough, the pictures on the buttons will be missing. For instance, the magnifying glass on Google will be gone or the circle arrow on Gmail (but all buttons of course). All other websites load just fine - and very quickly. All other network functionality is completely unimpacted. The behaviour of fixed IP & Google DNS vs automatic IP & DNS is easily reproducible. I am going crazy trying to fix this as I have no idea what the hell is going on at this point. Here a list of the things I have tried thus far: Flushed the DNS Tried on different browsers (Works fine on my laptop by the way) Tried disabling Teredo & IPv6 stack Emptied all caches Checked the HOSTS file Rebooted the router Reset the router Reinstalled the network adapter Tracert displayes normal route until timing out at one point Ping usually doesn't work for the unreachable sites either Ran both complete Norton 360 & Kaspersky 2012 scan Ran Kaspersky Virus Removal Tool in safe mode Tried connection in safe mode & networking enabled If you have any ideas, please let me know. I'm getting desperate...

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