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  • Facebook: I became Admin of a Page but can't edit it

    - by Michael G.
    Hello! I'm testing around with facebook and made a test-page with a workmate. He made me an admin. I clicked the link in the mail from facebook, i got to the side and there's no "edit the page" link under the picture. So we added an other workmate as admin. Even he isn't supposed to edit the page. What can it be?

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  • Page Load Time - "Waiting on..." taking ages. What part of page request process is hung?

    - by James
    I have a new cluster site running on Magento that's on a development server that is made up of 2 x web servers and 1 x database server. I have optimized the site in all areas I know (gzip, increasing php memory limits, increasing database memory limits etc) but sometimes the page loading gets stuck on 'waiting for xxx.xx.xx.xxx' (Chrome and other broswers, chrome just shows it that way). It can sit there for 40 + seconds, sometimes it just never loads and I close it in frustration. What part of the page loading process is this hung at? Is it a server issue, database issue, platform issue? I need to know where to start or whether to push the hosting provider about it.

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  • How can one detect if a server/script is accessing their site through cURL/file_get_contents()? (excluding user-agents and IP addresses)

    - by navnav
    I've come across a question where a user is having difficulties accessing an image through a script (using cURL/file_get_contents()): How to save an image from url using PHP? The image link seems to return a 403 error when using file_get_contents() to request it. But in cURL, a more detailed error is returned: You were denied access to the system. Turn off the engine or Surf Proxy, Fake IP if you really want to access. Proxy or not accepted from any Web tools Intrusion Prevention System. Binh Minh Online Data Services @ 2008 - 2012 I also failed to access the same image after fiddling around with a cURL request myself. I tried changing the user-agent to my exact browsers user-agent which can successfully access the image. I've also tried the script on my personal local server, which (obviously) uses the same IP address as my browser... So as far as I know, user-agents and IP addresses are out of the situation. How else can someone detect a script performing a request? BTW, this is not for anything crazy. I'm just curious xD

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  • How do I pass a cookie to a Sinatra app using curl?

    - by Brandon Toone
    I'm using the code from the example titled "A Slightly Bigger Example" from this tutorial http://rubylearning.com/blog/2009/09/30/cookie-based-sessions-in-sinatra/ to figure out how to send a cookie to a Sinatra application but I can't figure out how to set the values correctly When I set the name to be "brandon" in the application it creates a cookie with a value of BAh7BiIJdXNlciIMYnJhbmRvbg%3D%3D%0A which is a url encoding (http://ostermiller.org/calc/encode.html) of the value BAh7BiIJdXNlciIMYnJhbmRvbg== Using that value I can send a cookie to the app correctly curl -b "rack.session=BAh7BiIJdXNlciIMYnJhbmRvbg==" localhost:9393 I'm pretty sure that value is a base64 encoding of the ruby hash for the session since the docs (http://rack.rubyforge.org/doc/classes/Rack/Session/Cookie.html) say The session is a Ruby Hash stored as base64 encoded marshalled data set to :key (default: rack.session). I thought that meant all I had to do was base64 encode {"user"=>"brandon"} and use it in the curl command. Unfortunately that creates a different value than BAh7BiIJdXNlciIMYnJhbmRvbg==. Next I tried taking the base64 encoded value and decoding it at various base64 decoders online but that results in strange characters (a box symbol and others) so I don't know how to recreate the value to even encode it. So my question is do you know what characters/format I need to get the proper base64 encoding and/or do you know of another way to pass a value using curl such that it will register as a proper cookie for a Sinatra app?

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  • How can I send GET data to multiple URLs at the same time using cURL?

    - by Rob
    My apologies, I've actually asked this question multiple times, but never quite understood the answers. Here is my current code: while($resultSet = mysql_fetch_array($SQL)){ $ch = curl_init($resultSet['url'] . $fullcurl); //load the urls and send GET data curl_setopt($ch, CURLOPT_TIMEOUT, 2); //Only load it for two seconds (Long enough to send the data) curl_exec($ch); //Execute the cURL curl_close($ch); //Close it off } //end while loop What I'm doing here, is taking URLs from a MySQL Database ($resultSet['url']), appending some extra variables to it, just some GET data ($fullcurl), and simply requesting the pages. This starts the script running on those pages, and that's all that this script needs to do, is start those scripts. It doesn't need to return any output. Just the load the page long enough for the script to start. However, currently it's loading each URL (currently 11) one at a time. I need to load all of them simultaneously. I understand I need to use curl_multi_*, but I haven't the slightest idea on how cURL functions work, so I don't know how to change my code to use curl_multi_* in a while loop. So my questions are: How can I change this code to load all of the URLs simultaneously? Please explain it and not just give me code. I want to know what each individual function does exactly. Will curl_multi_exec even work in a while loop, since the while loop is just sending each row one at a time? And of course, any references, guides, tutorials about cURL functions would be nice, as well. Preferably not so much from php.net, as while it does a good job of giving me the syntax, its just a little dry and not so good with the explanations.

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  • MySQL get content from web page (or other network resource)

    - by Rescommunes
    Is it possible to open a curl like object in MySQL? What I would like to do is create procedure which would check to see if a certain value is returned from a specific URL like http://example.com/inschedule?id=200&time=20m. The returned result would be a simple string like 1 or 0. I know it is better to have a script do this by putting a entry into a table etc. However, it would be much less complex for me to be able to do it this way. Thanks

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  • Handling responses in libcurl

    - by sfactor
    i have a code to send a Form Post with login credentials to a webpage. it looks like this CURL *curl; CURLcode res; struct curl_httppost *formpost=NULL; struct curl_httppost *lastptr=NULL; struct curl_slist *headerlist=NULL; static const char buf[] = "Expect:"; curl_global_init(CURL_GLOBAL_ALL); /* Fill in the username */ curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "user", CURLFORM_COPYCONTENTS, "username", CURLFORM_END); /* Fill in the password */ curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "pass", CURLFORM_COPYCONTENTS, "password", CURLFORM_END); /* Fill in the submit field too, even if this is rarely needed */ curl_formadd(&formpost, &lastptr, CURLFORM_COPYNAME, "submit", CURLFORM_COPYCONTENTS, "send", CURLFORM_END); curl = curl_easy_init(); /* initalize custom header list (stating that Expect: 100-continue is not wanted */ headerlist = curl_slist_append(headerlist, buf); if(curl) { /* what URL that receives this POST */ curl_easy_setopt(curl, CURLOPT_URL, "http://127.0.0.1:8000/index.html"); /* only disable 100-continue header if explicitly requested */ curl_easy_setopt(curl, CURLOPT_HTTPHEADER, headerlist); curl_easy_setopt(curl, CURLOPT_HTTPPOST, formpost); res = curl_easy_perform(curl); /* always cleanup */ curl_easy_cleanup(curl); /* then cleanup the formpost chain */ curl_formfree(formpost); /* free slist */ curl_slist_free_all (headerlist); } now i need to know is how do i handle the responses i get back from the server? i need to store the response into a string and then work on it.

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  • Loading main javascript on every page? Or breaking it up to relevant pages?

    - by Kyle
    I have a 700kb decompressed JS file which is loaded on every page. Before I had 12 javascript files on each page but to reduce http requests I compressed them all into 1 file. This file is ~130kb gzipped and is served over gzip. However on the local computer it is still unpacked and loaded on every page. Is this a performance issue? I've profiled the javascript with firebug profiler but did not see any issues. The problem/illusion I am facing is there are jquery libraries compressed in that file that are sometimes not used on the current page. For example jquery datatables is 200kb compressed and that is only loaded on 2 of my website pages. Another is jqplot and that is another 200kb. I now have 400kb of excess code that isn't executed on 80% of the pages. Should I leave everything in 1 file? Should I take out the jquery libraries and load only relevant JS on the current page?

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  • What is the impact of a CMS on page load time versus a static site?

    - by PleaseStand
    I am creating a 20-page site that will go on shared hosting. Each page will be about 20 KB (including HTML, CSS, and images common to all pages). To avoid manually adding navigation elements to each page, I am considering using a CMS. However, I am concerned that on a busy server, using a CMS would make the site load more slowly. In a shared hosting environment where PHP is run as a CGI binary, how much does a CMS (WordPress, Drupal, etc.) generally affect page load time, compared to both "plain HTML" static sites and those using PHP as merely a templating language?

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  • curl blocked at TMG firewall

    - by jemtube100
    i using TMG (threat management gateway) firewall at my web server. when i try to use Curl from outside, this firewall was blocked the connection. what rule/setting that i need to create at TMG to allow it. the error state as below : Refresh page: Search for the page again by clicking the Refresh button. The timeout may have occurred due to Internet congestion. Check spelling: Check that you typed the Web page address correctly. The address may have been mistyped. Access from a link: If there is a link to the page you are looking for, try accessing the page from that link. </UL> <HR color=#c0c0c0 noShade> <P id=L_defaultr_11>Technical Information (for support personnel)</P> <UL> <LI id=L_defaultr_12>Error Code: 403 Forbidden. The server denied the specified Uniform Resource Locator (URL). Contact the server administrator. (12202)

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  • ASP.Net Cross Page Posting

    - by John
    Currently I have two pages: The first page contains an input form, and the 2nd page generates an excel document. The input form's button posts to this 2nd page. What I'd like to do is add a second button which also posts to the 2nd page; however, I'll need requests created from this new button to act differently, which brings me to my question: Is there a way I can tell, from the 2nd page, which button was pressed to submit the request? The main reason I'm asking is I'd like to re-use the 2nd page's logic in parsing the information from the first page if possible; I'd rather not have to copy it to a new page and have the new button post to that. Thanks!

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  • Access &lt;body element from content page via a nested master page

    - by danwellman
    All I want to do is access the <body element from the code-behind of a content page and add a class name to it. I have a top-level master page with the <body element in it. Then I have a nested master page which is the master page for the content page. From the code behind of the content page I want to add a class name to the body element. That's all. I have this in the top-level master: <body id="bodyNode" runat="server"> I added this to the code-behind for the content page: Master.bodyNode.Attributes.add("class", "home-page"); And I get a message that: System.Web.UI.MasterPage' does not contain a definition for 'bodyNode If I add this to the aspx content page: <% @ MasterType VirtualPath="~/MasterPage.master"%> The message then changes to: bodyNode is inaccessible due to its protection level Please advise, I've wasted like 2 hours on what feels like something that should be really simple to do :(

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  • Newbie question about file formatting in Python

    - by user568041
    I'm writing a simple program in Python 2.7 using pycURL library to submit file contents to pastebin. Here's the code of the program: #!/usr/bin/env python2 import pycurl, os def send(file): print "Sending file to pastebin...." curl = pycurl.Curl() curl.setopt(pycurl.URL, "http://pastebin.com/api_public.php") curl.setopt(pycurl.POST, True) curl.setopt(pycurl.POSTFIELDS, "paste_code=%s" % file) curl.setopt(pycurl.NOPROGRESS, True) curl.perform() def main(): content = raw_input("Provide the FULL path to the file: ") open = file(content, 'r') send(open.readlines()) return 0 main() The output pastebin looks like standard Python list: ['string\n', 'line of text\n', ...] etc. Is there any way I could format it so it looks better and it's actually human-readable? Also, I would be very happy if someone could tell me how to use multiple data inputs in POSTFIELDS. Pastebin API uses paste_code as its main data input, but it can use optional things like paste_name that sets the name of the upload or paste_private that sets it private.

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  • Security Issues with Single Page Apps

    - by Stephen.Walther
    Last week, I was asked to do a code review of a Single Page App built using the ASP.NET Web API, Durandal, and Knockout (good stuff!). In particular, I was asked to investigate whether there any special security issues associated with building a Single Page App which are not present in the case of a traditional server-side ASP.NET application. In this blog entry, I discuss two areas in which you need to exercise extra caution when building a Single Page App. I discuss how Single Page Apps are extra vulnerable to both Cross-Site Scripting (XSS) attacks and Cross-Site Request Forgery (CSRF) attacks. This goal of this blog post is NOT to persuade you to avoid writing Single Page Apps. I’m a big fan of Single Page Apps. Instead, the goal is to ensure that you are fully aware of some of the security issues related to Single Page Apps and ensure that you know how to guard against them. Cross-Site Scripting (XSS) Attacks According to WhiteHat Security, over 65% of public websites are open to XSS attacks. That’s bad. By taking advantage of XSS holes in a website, a hacker can steal your credit cards, passwords, or bank account information. Any website that redisplays untrusted information is open to XSS attacks. Let me give you a simple example. Imagine that you want to display the name of the current user on a page. To do this, you create the following server-side ASP.NET page located at http://MajorBank.com/SomePage.aspx: <%@Page Language="C#" %> <html> <head> <title>Some Page</title> </head> <body> Welcome <%= Request["username"] %> </body> </html> Nothing fancy here. Notice that the page displays the current username by using Request[“username”]. Using Request[“username”] displays the username regardless of whether the username is present in a cookie, a form field, or a query string variable. Unfortunately, by using Request[“username”] to redisplay untrusted information, you have now opened your website to XSS attacks. Here’s how. Imagine that an evil hacker creates the following link on another website (hackers.com): <a href="/SomePage.aspx?username=<script src=Evil.js></script>">Visit MajorBank</a> Notice that the link includes a query string variable named username and the value of the username variable is an HTML <SCRIPT> tag which points to a JavaScript file named Evil.js. When anyone clicks on the link, the <SCRIPT> tag will be injected into SomePage.aspx and the Evil.js script will be loaded and executed. What can a hacker do in the Evil.js script? Anything the hacker wants. For example, the hacker could display a popup dialog on the MajorBank.com site which asks the user to enter their password. The script could then post the password back to hackers.com and now the evil hacker has your secret password. ASP.NET Web Forms and ASP.NET MVC have two automatic safeguards against this type of attack: Request Validation and Automatic HTML Encoding. Protecting Coming In (Request Validation) In a server-side ASP.NET app, you are protected against the XSS attack described above by a feature named Request Validation. If you attempt to submit “potentially dangerous” content — such as a JavaScript <SCRIPT> tag — in a form field or query string variable then you get an exception. Unfortunately, Request Validation only applies to server-side apps. Request Validation does not help in the case of a Single Page App. In particular, the ASP.NET Web API does not pay attention to Request Validation. You can post any content you want – including <SCRIPT> tags – to an ASP.NET Web API action. For example, the following HTML page contains a form. When you submit the form, the form data is submitted to an ASP.NET Web API controller on the server using an Ajax request: <!DOCTYPE html> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title></title> </head> <body> <form data-bind="submit:submit"> <div> <label> User Name: <input data-bind="value:user.userName" /> </label> </div> <div> <label> Email: <input data-bind="value:user.email" /> </label> </div> <div> <input type="submit" value="Submit" /> </div> </form> <script src="Scripts/jquery-1.7.1.js"></script> <script src="Scripts/knockout-2.1.0.js"></script> <script> var viewModel = { user: { userName: ko.observable(), email: ko.observable() }, submit: function () { $.post("/api/users", ko.toJS(this.user)); } }; ko.applyBindings(viewModel); </script> </body> </html> The form above is using Knockout to bind the form fields to a view model. When you submit the form, the view model is submitted to an ASP.NET Web API action on the server. Here’s the server-side ASP.NET Web API controller and model class: public class UsersController : ApiController { public HttpResponseMessage Post(UserViewModel user) { var userName = user.UserName; return Request.CreateResponse(HttpStatusCode.OK); } } public class UserViewModel { public string UserName { get; set; } public string Email { get; set; } } If you submit the HTML form, you don’t get an error. The “potentially dangerous” content is passed to the server without any exception being thrown. In the screenshot below, you can see that I was able to post a username form field with the value “<script>alert(‘boo’)</script”. So what this means is that you do not get automatic Request Validation in the case of a Single Page App. You need to be extra careful in a Single Page App about ensuring that you do not display untrusted content because you don’t have the Request Validation safety net which you have in a traditional server-side ASP.NET app. Protecting Going Out (Automatic HTML Encoding) Server-side ASP.NET also protects you from XSS attacks when you render content. By default, all content rendered by the razor view engine is HTML encoded. For example, the following razor view displays the text “<b>Hello!</b>” instead of the text “Hello!” in bold: @{ var message = "<b>Hello!</b>"; } @message   If you don’t want to render content as HTML encoded in razor then you need to take the extra step of using the @Html.Raw() helper. In a Web Form page, if you use <%: %> instead of <%= %> then you get automatic HTML Encoding: <%@ Page Language="C#" %> <% var message = "<b>Hello!</b>"; %> <%: message %> This automatic HTML Encoding will prevent many types of XSS attacks. It prevents <script> tags from being rendered and only allows &lt;script&gt; tags to be rendered which are useless for executing JavaScript. (This automatic HTML encoding does not protect you from all forms of XSS attacks. For example, you can assign the value “javascript:alert(‘evil’)” to the Hyperlink control’s NavigateUrl property and execute the JavaScript). The situation with Knockout is more complicated. If you use the Knockout TEXT binding then you get HTML encoded content. On the other hand, if you use the HTML binding then you do not: <!-- This JavaScript DOES NOT execute --> <div data-bind="text:someProp"></div> <!-- This Javacript DOES execute --> <div data-bind="html:someProp"></div> <script src="Scripts/jquery-1.7.1.js"></script> <script src="Scripts/knockout-2.1.0.js"></script> <script> var viewModel = { someProp : "<script>alert('Evil!')<" + "/script>" }; ko.applyBindings(viewModel); </script>   So, in the page above, the DIV element which uses the TEXT binding is safe from XSS attacks. According to the Knockout documentation: “Since this binding sets your text value using a text node, it’s safe to set any string value without risking HTML or script injection.” Just like server-side HTML encoding, Knockout does not protect you from all types of XSS attacks. For example, there is nothing in Knockout which prevents you from binding JavaScript to a hyperlink like this: <a data-bind="attr:{href:homePageUrl}">Go</a> <script src="Scripts/jquery-1.7.1.min.js"></script> <script src="Scripts/knockout-2.1.0.js"></script> <script> var viewModel = { homePageUrl: "javascript:alert('evil!')" }; ko.applyBindings(viewModel); </script> In the page above, the value “javascript:alert(‘evil’)” is bound to the HREF attribute using Knockout. When you click the link, the JavaScript executes. Cross-Site Request Forgery (CSRF) Attacks Cross-Site Request Forgery (CSRF) attacks rely on the fact that a session cookie does not expire until you close your browser. In particular, if you visit and login to MajorBank.com and then you navigate to Hackers.com then you will still be authenticated against MajorBank.com even after you navigate to Hackers.com. Because MajorBank.com cannot tell whether a request is coming from MajorBank.com or Hackers.com, Hackers.com can submit requests to MajorBank.com pretending to be you. For example, Hackers.com can post an HTML form from Hackers.com to MajorBank.com and change your email address at MajorBank.com. Hackers.com can post a form to MajorBank.com using your authentication cookie. After your email address has been changed, by using a password reset page at MajorBank.com, a hacker can access your bank account. To prevent CSRF attacks, you need some mechanism for detecting whether a request is coming from a page loaded from your website or whether the request is coming from some other website. The recommended way of preventing Cross-Site Request Forgery attacks is to use the “Synchronizer Token Pattern” as described here: https://www.owasp.org/index.php/Cross-Site_Request_Forgery_%28CSRF%29_Prevention_Cheat_Sheet When using the Synchronizer Token Pattern, you include a hidden input field which contains a random token whenever you display an HTML form. When the user opens the form, you add a cookie to the user’s browser with the same random token. When the user posts the form, you verify that the hidden form token and the cookie token match. Preventing Cross-Site Request Forgery Attacks with ASP.NET MVC ASP.NET gives you a helper and an action filter which you can use to thwart Cross-Site Request Forgery attacks. For example, the following razor form for creating a product shows how you use the @Html.AntiForgeryToken() helper: @model MvcApplication2.Models.Product <h2>Create Product</h2> @using (Html.BeginForm()) { @Html.AntiForgeryToken(); <div> @Html.LabelFor( p => p.Name, "Product Name:") @Html.TextBoxFor( p => p.Name) </div> <div> @Html.LabelFor( p => p.Price, "Product Price:") @Html.TextBoxFor( p => p.Price) </div> <input type="submit" /> } The @Html.AntiForgeryToken() helper generates a random token and assigns a serialized version of the same random token to both a cookie and a hidden form field. (Actually, if you dive into the source code, the AntiForgeryToken() does something a little more complex because it takes advantage of a user’s identity when generating the token). Here’s what the hidden form field looks like: <input name=”__RequestVerificationToken” type=”hidden” value=”NqqZGAmlDHh6fPTNR_mti3nYGUDgpIkCiJHnEEL59S7FNToyyeSo7v4AfzF2i67Cv0qTB1TgmZcqiVtgdkW2NnXgEcBc-iBts0x6WAIShtM1″ /> And here’s what the cookie looks like using the Google Chrome developer toolbar: You use the [ValidateAntiForgeryToken] action filter on the controller action which is the recipient of the form post to validate that the token in the hidden form field matches the token in the cookie. If the tokens don’t match then validation fails and you can’t post the form: public ActionResult Create() { return View(); } [ValidateAntiForgeryToken] [HttpPost] public ActionResult Create(Product productToCreate) { if (ModelState.IsValid) { // save product to db return RedirectToAction("Index"); } return View(); } How does this all work? Let’s imagine that a hacker has copied the Create Product page from MajorBank.com to Hackers.com – the hacker grabs the HTML source and places it at Hackers.com. Now, imagine that the hacker trick you into submitting the Create Product form from Hackers.com to MajorBank.com. You’ll get the following exception: The Cross-Site Request Forgery attack is blocked because the anti-forgery token included in the Create Product form at Hackers.com won’t match the anti-forgery token stored in the cookie in your browser. The tokens were generated at different times for different users so the attack fails. Preventing Cross-Site Request Forgery Attacks with a Single Page App In a Single Page App, you can’t prevent Cross-Site Request Forgery attacks using the same method as a server-side ASP.NET MVC app. In a Single Page App, HTML forms are not generated on the server. Instead, in a Single Page App, forms are loaded dynamically in the browser. Phil Haack has a blog post on this topic where he discusses passing the anti-forgery token in an Ajax header instead of a hidden form field. He also describes how you can create a custom anti-forgery token attribute to compare the token in the Ajax header and the token in the cookie. See: http://haacked.com/archive/2011/10/10/preventing-csrf-with-ajax.aspx Also, take a look at Johan’s update to Phil Haack’s original post: http://johan.driessen.se/posts/Updated-Anti-XSRF-Validation-for-ASP.NET-MVC-4-RC (Other server frameworks such as Rails and Django do something similar. For example, Rails uses an X-CSRF-Token to prevent CSRF attacks which you generate on the server – see http://excid3.com/blog/rails-tip-2-include-csrf-token-with-every-ajax-request/#.UTFtgDDkvL8 ). For example, if you are creating a Durandal app, then you can use the following razor view for your one and only server-side page: @{ Layout = null; } <!DOCTYPE html> <html> <head> <title>Index</title> </head> <body> @Html.AntiForgeryToken() <div id="applicationHost"> Loading app.... </div> @Scripts.Render("~/scripts/vendor") <script type="text/javascript" src="~/App/durandal/amd/require.js" data-main="/App/main"></script> </body> </html> Notice that this page includes a call to @Html.AntiForgeryToken() to generate the anti-forgery token. Then, whenever you make an Ajax request in the Durandal app, you can retrieve the anti-forgery token from the razor view and pass the token as a header: var csrfToken = $("input[name='__RequestVerificationToken']").val(); $.ajax({ headers: { __RequestVerificationToken: csrfToken }, type: "POST", dataType: "json", contentType: 'application/json; charset=utf-8', url: "/api/products", data: JSON.stringify({ name: "Milk", price: 2.33 }), statusCode: { 200: function () { alert("Success!"); } } }); Use the following code to create an action filter which you can use to match the header and cookie tokens: using System.Linq; using System.Net.Http; using System.Web.Helpers; using System.Web.Http.Controllers; namespace MvcApplication2.Infrastructure { public class ValidateAjaxAntiForgeryToken : System.Web.Http.AuthorizeAttribute { protected override bool IsAuthorized(HttpActionContext actionContext) { var headerToken = actionContext .Request .Headers .GetValues("__RequestVerificationToken") .FirstOrDefault(); ; var cookieToken = actionContext .Request .Headers .GetCookies() .Select(c => c[AntiForgeryConfig.CookieName]) .FirstOrDefault(); // check for missing cookie or header if (cookieToken == null || headerToken == null) { return false; } // ensure that the cookie matches the header try { AntiForgery.Validate(cookieToken.Value, headerToken); } catch { return false; } return base.IsAuthorized(actionContext); } } } Notice that the action filter derives from the base AuthorizeAttribute. The ValidateAjaxAntiForgeryToken only works when the user is authenticated and it will not work for anonymous requests. Add the action filter to your ASP.NET Web API controller actions like this: [ValidateAjaxAntiForgeryToken] public HttpResponseMessage PostProduct(Product productToCreate) { // add product to db return Request.CreateResponse(HttpStatusCode.OK); } After you complete these steps, it won’t be possible for a hacker to pretend to be you at Hackers.com and submit a form to MajorBank.com. The header token used in the Ajax request won’t travel to Hackers.com. This approach works, but I am not entirely happy with it. The one thing that I don’t like about this approach is that it creates a hard dependency on using razor. Your single page in your Single Page App must be generated from a server-side razor view. A better solution would be to generate the anti-forgery token in JavaScript. Unfortunately, until all browsers support a way to generate cryptographically strong random numbers – for example, by supporting the window.crypto.getRandomValues() method — there is no good way to generate anti-forgery tokens in JavaScript. So, at least right now, the best solution for generating the tokens is the server-side solution with the (regrettable) dependency on razor. Conclusion The goal of this blog entry was to explore some ways in which you need to handle security differently in the case of a Single Page App than in the case of a traditional server app. In particular, I focused on how to prevent Cross-Site Scripting and Cross-Site Request Forgery attacks in the case of a Single Page App. I want to emphasize that I am not suggesting that Single Page Apps are inherently less secure than server-side apps. Whatever type of web application you build – regardless of whether it is a Single Page App, an ASP.NET MVC app, an ASP.NET Web Forms app, or a Rails app – you must constantly guard against security vulnerabilities.

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  • How to stop a curl while requesting or stop the running php script?

    - by Chris
    I using url to request remote urls that sometimes may very slow or just down. In this case, my php scripts still waiting for the response, it makes apache has to many requests stay in memory and then overload. I need a way to stop curl requesting or stop running php script when specified time passed. I'd tried declare(), it makes no sense for curl. Can someone know how to solve it? BTW: what is the effect of CURLOPT_CONNECTTIMEOUT and CURLOPT_TIMEOUT? They don't work like what I think.

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  • Can a Site get a Virus from using Curl?

    - by Mark Tyler
    I have a script which uses simple php curl requests to get the contents from rss/atom feeds.... now my question is it possible that by using curl, is there a chance i might get a virus? Let's say I do a php curl request to a rss feed in feedburner (I know this site does not contain any viruses, but this is only an example) and let's say this site has a malicious virus of some kind. Is there a chance that I might inherit that virus too? If yes, what precautions can I do to make sure something like that never happens. This is the php code I am currently using to fetch the RSS $headers [] = 'Connection: Keep-Alive'; $headers [] = 'Content-type: application/x-www-form-urlencoded; charset=utf-8'; $headers [] = 'Accept-Encoding: application/xhtml+xml,application/xml,text/xml,text/html;q=0.9,*/*;q=0.8'; $ch = curl_init($url); //curl_setopt($ch, CURLOPT_USERAGENT,'Phenoix/0.1.3 (Feed Parser Beta; Beta ; Allow like Gecko) Build/20111112'); curl_setopt($ch, CURLOPT_USERAGENT,'Mozilla/5.0 (Windows NT 6.1; WOW64; rv:9.0.1) Gecko/20100101 Firefox/9.0.1'); //curl_setopt($ch, CURLOPT_REFERER, "http://google.com/auto/clogger"); //curl_setopt($ch, CURLOPT_ENCODING, 'gzip, deflate' ); curl_setopt($ch, CURLOPT_HTTPHEADER, $headers ); //curl_setopt($channel, CURLOPT_HEADER, 0); curl_setopt($ch, CURLINFO_HEADER_OUT, 1); curl_setopt($ch, CURLOPT_VERBOSE, true); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false); curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_TIMEOUT, 10); curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, 10); curl_setopt($ch, CURLOPT_FAILONERROR, 1); //allow cookie $cookie_file = "cookie1.txt"; curl_setopt($ch, CURLOPT_COOKIESESSION, true); curl_setopt($ch, CURLOPT_COOKIEFILE, $cookie_file); curl_setopt($ch, CURLOPT_COOKIEJAR, $cookie_file); $xml = curl_exec($ch); if(curl_error($ch)){ //$text .= "Error while updating. Please try again later"; return array(0, curl_error($ch)); } $info = curl_getinfo($ch); curl_close($ch);

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  • How to upload an image to imageshark using curl?

    - by cinek1lol
    Hello: I wrote a program using curl.exe that sends pictures to imageshark and receives a link to the pictures. The problem that I have to specify the path to the image on the disk, and the rest of my so constructed that I have uploaded these pictures to a binary char array And I mean, I can send these pictures to char variable, and not giving the file path (you know what I mean?) Not too much know how to use it to save the library directly to curl. I'll be very grateful for any help sorry I know little English. wants to send a file loaded POST method to the variable char binary. Programs that are written above, send the file to disk. Do you understand what's going on? This is look like I would like to send the file in char variable, rather than on the hard disk I found the program, but he sends the entire file, and I would like to have it sent to the variable char dz

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  • How do I find the speed of an in-progress file upload in cURL?

    - by cinek1lol
    I'd like to know how to check out the speed of a file being uploaded in real time using the cURL library in C++. This is what I have written: void progress_func(void* ptr, double TotalToDownload, double NowDownloaded, double TotalToUpload,double NowUploaded) { cout<<NowUploaded<<endl; } //... int main() { //... curl_easy_setopt(curl, CURLOPT_PROGRESSFUNCTION, progress_func); } But the manual says that it shows average speed, but even this doesn't seem to work with me, because too mach fast is end. How to good write or A well-calculated?

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  • AuthSub token from Google/YouTube API is always returned as invalid

    - by Miriam Raphael Roberts
    Anyone out there have experience with the YouTube/Google API? I am trying to login to Google/Youtube using clientLogin, retrieve an AuthSub token, exchange it for a multi-session token and then use it in our upload form. Just a note that we are not going to have other users logging into our (secure) website, this is for our use only (no multi-users). We just want a way to upload videos to our YT account via our own website without having to login/upload to YouTube. Ultimately, everything is dependent on the first step. My AuthSub token is always being returned as invalid (Error '403'). All the steps I used are below with username/password changed. Anyone have an insight on why my AuthSub is always invalid? I am spending an enormous amount of time trying to get this to work. STEP 1: Getting the authsub token from Youtube/Google POST /youtube/accounts/ClientLogin HTTP/1.1 User-Agent: curl/7.10.6 (i386-redhat-linux-gnu) libcurl/7.10.6 OpenSSL/0.9.7a ipv6 zlib/1.1.4 Host: www.google.com Pragma: no-cache Accept: image/gif, image/x-xbitmap, image/jpeg, image/pjpeg, */* Content-Type:application/x-www-form-urlencoded Content-Length: 86 Email=MyGoogleUsername&Passwd=MyGooglePasswd&accountType=GOOGLE&service=youtube&source=Test RESPONSE RECEIVED: Auth=AIwbFAR99f3iACfkT-5PXCB-1tN4vlyP_1CiNZ8JOn6P-......yv4d4zeGRemNm4il1e-M6czgfDXAR0w9fQ YouTubeUser=MyYouTubeUsername CURL COMMAND USED: /usr/bin/curl -S -v --location https://www.google.com/youtube/accounts/ClientLogin --data Email=MyGoogleUsername&Passwd=MyGooglePasswd&accountType=GOOGLE&service=youtube&source=Test --header Content-Type:application/x-www-form-urlencoded STEP 2: Exchanging the AuthSub token for a multi-use token GET /accounts/AuthSubSessionToken HTTP/1.1 User-Agent: curl/7.10.6 (i386-redhat-linux-gnu) libcurl/7.10.6 OpenSSL/0.9.7a ipv6 zlib/1.1.4 Host: www.google.com Pragma: no-cache Accept: image/gif, image/x-xbitmap, image/jpeg, image/pjpeg, */* Content-Type:application/x-www-form-urlencoded Authorization: AuthSub token="AIwbFASiRR3XDKs......p5Oy_VA_9U2yV1enxJoVGSgMlZqTcjKw9mS861vlc9GWTH9D9sQ" Response received: 403 Invalid AuthSub token. curl command used: /usr/bin/curl -S -v --location https://www.google.com/accounts/AuthSubSessionToken --header Content-Type:application/x-www-form-urlencoded -H Authorization: AuthSub token="AIwbFAQR_4xG2g.....vp3BQZW5XEMyIj_wFozHSTEQ-BQRfYuIY-1CyqLeQ" STEP 3: Checking to see if the token is good/valid GET /accounts/AuthSubTokenInfo HTTP/1.1 User-Agent: curl/7.10.6 (i386-redhat-linux-gnu) libcurl/7.10.6 OpenSSL/0.9.7a ipv6 zlib/1.1.4 Host: www.google.com Pragma: no-cache Accept: image/gif, image/x-xbitmap, image/jpeg, image/pjpeg, */* Content-Type:application/x-www-form-urlencoded Authorization: AuthSub token="AIwbFASiRR3XDKsNkaIoPaujN5RQhKs3u.....A_9U2yV1enxJoVGSgMlZqTcjKw9mS861vlc9GWTH9D9sQ" Received response: 403 Invalid AuthSub token. curl command used: /usr/bin/curl -S -v --location https://www.google.com/accounts/AuthSubTokenInfo --header Content-Type:application/x-www-form-urlencoded -H Authorization: AuthSub token="AIwbFAQR_4xG2gHoAKDsNdFqdZdwWjGeNquOLpvp3BQZW5XEMyIj_wFozHSTEQ-BQRfYuIY-1CyqLeQ" STEP 4: Trying to get the upload token using the authsub token POST /action/GetUploadToken HTTP/1.1 User-Agent: curl/7.10.6 (i386-redhat-linux-gnu) libcurl/7.10.6 OpenSSL/0.9.7a ipv6 zlib/1.1.4 Host: gdata.youtube.com Pragma: no-cache Accept: image/gif, image/x-xbitmap, image/jpeg, image/pjpeg, */* Content-Type:application/atom+xml Authorization: AuthSub token="AIwbFASiRR3XDKsNkaIoPaujN5RQhp5Oy_VA_9U2yV1enxJoVGSgMlZqTcjKw9mS861vlc9GWTH9D9sQ" X-Gdata-Key:key="AI39si5EQyo-TZPFAnmGjxJGFKpxd_7a6hEERh_3......R82AShoQ" Content-Length:0 GData-Version:2 Recevied Response: 401 Token invalid - Invalid AuthSub token. Curl command used: /usr/bin/curl -S -v --location http://gdata.youtube.com/action/GetUploadToken -H Content-Type:application/atom+xml -H Authorization: AuthSub token="AIwbFASiRR3XDKs....sYDp5Oy_VA_9U2yV1enxJoVGSgMlZqTcjKw9mS861vlc9GWTH9D9sQ" -H X-Gdata-Key:key="AI39si5EQyo-TZPFAnmGjxJGF......Kpxd6dN2J1oHFQYTj_7a6hEERh_3E48R82AShoQ" -H Content-Length:0 -H GData-Version:2

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  • How to redirect page

    - by sharun
    Hi i created one java application in which i tried to open my company's standard login page and i planned to redirect the link to open my own design page. Standard login page is displayed, instead of going to my own design page as usual its going to mail page. After sign out the mail page i'm gettting my own design page. But my need is, when i sign in the standard login page it should diplay my own design page. Is it possible? Please Help me. And this is code that i followed import java.io.IOException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import com.google.appengine.api.users.UserService; import com.google.appengine.api.users.UserServiceFactory; import com.google.appengine.api.users.User; public class New extends HttpServlet { /** * */ private static final long serialVersionUID = 1L; public void doPost(HttpServletRequest req, HttpServletResponse resp) throws IOException { resp.setHeader("Cache-Control", "no-store, no-cache, must-revalidate"); resp.setContentType("text/html"); UserService userService = UserServiceFactory.getUserService(); User user = userService.getCurrentUser(); if (user != null) { if(user.getEmail().equals("[email protected]")) { resp.getWriter().println("done"); resp.sendRedirect("/login.jsp"); } else { resp.getWriter().println("Hello, " + user.getNickname()+"<br>"); resp.getWriter().println("Thanks for your interest. But this application is still not available to everybody."); resp.getWriter().println("<a href="+UserServiceFactory.getUserService().createLogoutURL(userService.createLoginURL(req.getRequestURI()))+">Log out</a>"); } } else { resp.sendRedirect(userService.createLoginURL("http://mail.yyy.edu.in")); } } } Thanks in advance Regards Sharun.

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  • Web page from the terminal

    - by juanpablo
    Hi, I use snow leopard. how I can send a html page to web browser from the terminal? example: if I am in $HOME dir, where exist myPage.html, I can send this page for see in web browser with a command ? Many thanks.

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