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  • cannot override sys.excepthook

    - by Mert Nuhoglu
    I try to customize behavior of sys.excepthook as described by the recipe. in ipython: :import pdb, sys, traceback :def info(type, value, tb): : traceback.print_exception(type, value, tb) : pdb.pm() :sys.excepthook = info :-- >>> x[10] = 5 ------------------------------------------------- Traceback (most recent call last): File "<ipython console>", line 1, in <module> NameError: name 'x' is not defined >>> pdb.pm() is not being called. It seems that sys.excepthook = info doesn't work in my python 2.5 installation. What should I look into? Any suggestion? Thank you

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  • Prettify working using python idle but not when using python script

    - by Loclip
    So when I use print soup.prettify() on idle it's prettifying my html but when I calling the script from server the prettify() not working #!/usr/bin/python import cgi, cgitb, urllib2, sys from bs4 import BeautifulSoup styles = [] i = 1 site = "www.example.com" page = urllib2.urlopen(site) soup = BeautifulSoup(page) table = soup.find('table', {'class' :'style5'}) alltd = table.findAll('td') allspans = table.findAll('span') while i<55: styles.append("style" + str(i)) i+=1 for td in alltd: if any(x in td["class"] for x in styles): td["class"] = "align" for span in allspans: span.replaceWithChildren() print "Content-type: text/html" print print "<!DOCTYPE html>" print "<html>" print "<head>" print '<meta http-equiv="content-type" content="text/html; charset=utf-8">' print '<link rel="stylesheet" href="lightbox/css/lightbox.css" type="text/css" media="screen">' print '<style type="text/css">' print "body {background-color:#b0c4de;}" print '.align {text-align: center;}' print "</style>" print "</head>" print "<body>" print table.pretiffy() print "</body>" print "</html>"

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  • Mac OS X: Update Python for Shell

    - by Nathan G.
    So, I see similar questions, but none of the answers work for me. I updated Python to 3.1.3 from 2.6.1. Everything works, except: When I type python into Terminal, I get: Python 2.6.1 (r261:67515, Jun 24 2010, 21:47:49) [GCC 4.2.1 (Apple Inc. build 5646)] on darwin Type "help", "copyright", "credits" or "license" for more information. >>> So, how do I change the version of Python that runs in the Shell? I've tried the script that they provide. It adds their directory to my $PATH, but it still doesn't change the version that'd displayed from Terminal. Here's what I get when I echo $PATH: /Library/Frameworks/Python.framework/Versions/3.1/bin:/Library/Frameworks/Python.framework/Versions/3.1/bin:/Library/Frameworks/Python.framework/Versions/3.1/bin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin:/usr/X11/bin It appears that the script provided has added their directory for every time I ran the script (I tried it a few times, naturally). I'll gives links to caps of what is in the other relevant folders it mentions: /Library/Frameworks/Python.framework/Versions/3.1/bin /usr/local/bin /usr/bin Thakns in advance for any ideas!

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  • Python - CSV: Large file with rows of different lengths

    - by dassouki
    In short, I have a 20,000,000 line csv file that has different row lengths. This is due to archaic data loggers and proprietary formats. We get the end result as a csv file in the following format. MY goal is to insert this file into a postgres database. How Can I do the following: Keep the first 8 columns and my last 2 columns, to have a consistent CSV file Add a Column to the file. 1, 2, 3, 4, 5, 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0, img_id.jpg, -50 1, 2, 3, 4, 5, 0,0,0,0,0,0,0,0,0, img_id.jpg, -50 1, 2, 3, 4, 5, 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0, img_id.jpg, -50 1, 2, 3, 4, 5, 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0, img_id.jpg, -50 1, 2, 3, 4, 5, 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0, img_id.jpg, -50 1, 2, 3, 4, 5, 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0, img_id.jpg, -50 1, 2, 3, 4, 5, 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0, img_id.jpg, -50 1, 2, 3, 4, 5, 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0, img_id.jpg, -50 1, 2, 3, 4, 5, 0,0,0,0,0,0, img_id.jpg, -50 1, 2, 3, 4, 5, 0,0,0,0,0,0,0,0,0,0,0 img_id.jpg, -50

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  • Using httplib2 in python 3 properly? (Timeout problems)

    - by Sho Minamimoto
    Hey, first time post, I'm really stuck on httplib2. I've been reading up on it from diveintopython3.org, but it mentions nothing about a timeout function. I look up the documentation, but the only thing I see is an ability to put a timeout int but there are no units specified (seconds? milliseconds? What's the default if None?) This is what I have (I also have code to check what the response is and try again, but it's never tried more than once) h = httplib2.Http('.cache', timeout=None) for url in list: response, content = h.request(url) more stuff... So the Http object stays around until some arbitrary time, but I'm downloading a ton of pages from the same server, and after a while, it hangs on getting a page. No errors are thrown, the thing just hangs at a page. So then I try: h = httplib2.Http('.cache', timeout=None) for url in list: try: response, content = h.request(url) except: h = httplib2.Http('.cache', timeout=None) more stuff... But then it recreates another Http object every time (goes down the 'except' path)...I dont understand how to keep getting with the same object, until it expires and I make another. Also, is there a way to set a timeout on an individual request? Thanks for the help!

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  • Generating permutation in Python with specific rule

    - by twfx
    Let say a=[A, B, C, D], each element has a weight w, and is set to 1 if selected, 0 if otherwise. I'd like to generate permutation in the below order 1,1,1,1 1,1,1,0 1,1,0,1 1,1,0,0 1,0,1,1 1,0,1,0 1,0,0,1 1,0,0,0 Let's w=[1,2,3,4] for item A,B,C,D ... and max_weight = 4. For each permutation, if the accum weight has exceeded max_weight, stop calculation for that permutation, move to next permutation. For eg. 1,1,1 --> 6 > 4, exceeded, stop, move to next 1,1,1 --> 6 > 4, exceeded, stop, move to next 1,1,0,1 --> 7 > 4 finished, move to next 1,1,0,0 --> 3 finished, move to next 1,0,1,1 --> 8 > 4, finished, stop, move to next 1,0,1,0 --> 4 finished, move to next 1,0,0,1 --> 5 > 4 finished, move to next 1,0,0,0 --> 1 finished, move to next [1,0,1,0] is the best combination which does not exceeded max_weight 4 My questions are What's the algorithm which generate the required permutation? Or any suggestion I could generate the permutation? As the number of element can be up to 10000, and the calculation stop if the accum weight for the branch exceeds max_weight, it is not necessary to generate all permutation first before the calculation. How can the algo in (1) generate permutation on the fly?

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  • How is the 'is' keyword implemented in Python?

    - by Srikanth
    ... the is keyword that can be used for equality in strings. >>> s = 'str' >>> s is 'str' True >>> s is 'st' False I tried both __is__() and __eq__() but they didn't work. >>> class MyString: ... def __init__(self): ... self.s = 'string' ... def __is__(self, s): ... return self.s == s ... >>> >>> >>> m = MyString() >>> m is 'ss' False >>> m is 'string' # <--- Expected to work False >>> >>> class MyString: ... def __init__(self): ... self.s = 'string' ... def __eq__(self, s): ... return self.s == s ... >>> >>> m = MyString() >>> m is 'ss' False >>> m is 'string' # <--- Expected to work, but again failed False >>> Thanks for your help!

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  • How to build sqlite for Python 2.4?

    - by Verrtex
    I would like to use pysqlite interface between Python and sdlite database. I have already Python and SQLite on my computer. But I have troubles with installation of pysqlite. During the installation I get the following error message: error: command 'gcc' failed with exit status 1 As far as I understood the problems appears because version of my Python is 2.4.3 and SQLite is integrated in Python since 2.5. However, I also found out that it IS possible to build sqlite for Python 2.4 (using some tricks, probably). Does anybody know how to build sqlite for Python 2.4? As another option I could try to install higher version of Python. However I do not have root privileges. Does anybody know what will be the easiest way to solve the problem (build SQLite fro Python 2.4, or install newer version of Python)? I have to mention that I would not like to overwrite the old version version of Python. Thank you in advance.

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  • Python try...except comma vs 'as' in except

    - by peter
    What is the difference between ',' and 'as' in except statements, eg: try: pass except Exception, exception: pass and: try: pass except Exception as exception: pass Is the second syntax legal in 2.6? It works in CPython 2.6 on Windows but the 2.5 interpreter in cygwin complains that it is invalid. If they are both valid in 2.6 which should I use?

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  • importing files in python

    - by Yosy
    I have that file structure- Blog\DataObjects\User.py Blog\index.py I want to import the function(say_hello) at User.py from index.py. I am trying this code - from Blog.DataObjects.User import say_hello say_hello() And I have that error - Traceback (most recent call last): File "index.py", line 1, in <module> from Blog.DataObjects import User ImportError: No module named Blog.DataObjects

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  • python __getattr__ help

    - by Stefanos Tux Zacharakis
    Reading a Book, i came across this code... # module person.py class Person: def __init__(self, name, job=None, pay=0): self.name = name self.job = job self.pay = pay def lastName(self): return self.name.split()[-1] def giveRaise(self, percent): self.pay = int(self.pay *(1 + percent)) def __str__(self): return "[Person: %s, %s]" % (self.name,self.pay) class Manager(): def __init__(self, name, pay): self.person = Person(name, "mgr", pay) def giveRaise(self, percent, bonus=.10): self.person.giveRaise(percent + bonus) def __getattr__(self, attr): return getattr(self.person, attr) def __str__(self): return str(self.person) It does what I want it to do, but i do not understand the __getattr__ function in the Manager class. I know that it Delegates all other attributes from Person class. but I do not understand the way it works. for example why from Person class? as I do not explicitly tell it to. person(module is different than Person(class) Any help is highly appreciated :)

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  • Python with PIL and Libjpeg on Leopard

    - by thescreamingdrills
    I'm having trouble getting pictures supported with PIL - it throws me this: "IOError: decoder jpeg not available" I installed PIL from binary, not realizing I needed libjpeg. I installed libjpeg and freetype2 through fink. I tried to reinstall PIL using instructions from http://timhatch.com/ (bottom of the page) "* Download PIL 1.1.6 source package and have the Developer Tools already installed * Patch setup.py with this patch so it can find the Freetype you already have. (patch -p0 < leopard_freetype2.diff) * sudo apt-get install libjpeg if you have fink (otherwise, build by hand and adjust paths)" But I'm still getting the same error. I'm on Leopard PPC.

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  • insert multiple elements in string in python

    - by Anurag Sharma
    I have to build a string like this { name: "john", url: "www.dkd.com", email: "[email protected]" } where john, www.dkd.com and [email protected] are to be supplied by variables I tried to do the following s1 = "{'name:' {0},'url:' {1},'emailid:' {2}}" s1.format("john","www.dkd.com","[email protected]") I am getting the following error Traceback (most recent call last): File "<stdin>", line 1, in <module> KeyError: "'name" Dont able to understand what I am doing wrong

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  • importing files at python

    - by Yosy
    I have that file strudctue- Blog\DataObjects\User.py Blog\index.py I want to import the function(say_hello) at User.py from index.py. I am trying this code - from Blog.DataObjects.User import say_hello say_hello() And I have that error - Traceback (most recent call last): File "index.py", line 1, in from Blog.DataObjects import User ImportError: No module named Blog.DataObjects

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  • Python Regular Expressions: Capture lookahead value (capturing text without consuming it)

    - by Lattyware
    I wish to use regular expressions to split words into groups of (vowels, not_vowels, more_vowels), using a marker to ensure every word begins and ends with a vowel. import re MARKER = "~" VOWELS = {"a", "e", "i", "o", "u", MARKER} word = "dog" if word[0] not in VOWELS: word = MARKER+word if word[-1] not in VOWELS: word += MARKER re.findall("([%]+)([^%]+)([%]+)".replace("%", "".join(VOWELS)), word) In this example we get: [('~', 'd', 'o')] The issue is that I wish the matches to overlap - the last set of vowels should become the first set of the next match. This appears possible with lookaheads, if we replace the regex as follows: re.findall("([%]+)([^%]+)(?=[%]+)".replace("%", "".join(VOWELS)), word) We get: [('~', 'd'), ('o', 'g')] Which means we are matching what I want. However, it now doesn't return the last set of vowels. The output I want is: [('~', 'd', 'o'), ('o', 'g', '~')] I feel this should be possible (if the regex can check for the second set of vowels, I see no reason it can't return them), but I can't find any way of doing it beyond the brute force method, looping through the results after I have them and appending the first character of the next match to the last match, and the last character of the string to the last match. Is there a better way in which I can do this? The two things that would work would be capturing the lookahead value, or not consuming the text on a match, while capturing the value - I can't find any way of doing either.

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  • Testing subpackage modules in Python 3

    - by Mitchell Model
    I have been experimenting with various uses of hierarchies like this and the differences between absolute and relative imports, and can't figure out how to do routine things with the package, subpackages, and modules without simply putting everything on sys.path. I have a two-level package hierarchy: MyApp __init__.py Application __init__.py Module1 Module2 ... Domain __init__.py Module1 Module2 ... UI __init__.py Module1 Module2 ... I want to be able to do the following: Run test code in a Module's "if main" when the module imports from other modules in the same directory. Have one or more test code modules in each subpackage that runs unit tests on the modules in the subpackage. Have a set of unit tests that reside in someplace reasonable, but outside the subpackages, either in a sibling package, at the top-level package, or outside the top-level package (though all these might end up doing is running the tests in each subpackage) "Enter" the structure from any of the three subpackage levels, e.g. run code that just uses Domain modules, run code that just uses Application modules, but Application uses code from both Application and Domain modules, and run code from GUI uses code from both GUI and Application; for instance, Application test code would import Application modules but not Domain modules. After developing the bulk of the code without subpackages, continue developing and testing after organizing the modules into this hierarchy. I know how to use relative imports so that external code that puts MyApp on its sys.path can import MyApp, import any subpackages it wants, and import things from their modules, while the modules in each subpackage can import other modules from the same subpackage or from sibling packages. However, the development needs listed above seem incompatible with subpackage structuring -- in other words, I can't have it both ways: a well-structured multi-level package hierarchy used from the outside and also used from within, in particular for testing but also because modules from one design level (in particular the UI) should not import modules from a design level below the next one down. Sorry for the long essay, but I think it fairly represents the struggles a lot of people have been having adopting to the new relative import mechanisms.

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  • python can't start a new thread

    - by Giorgos Komnino
    I am building a multi threading application. I have setup a threadPool. [ A Queue of size N and N Workers that get data from the queue] When all tasks are done I use tasks.join() where tasks is the queue . The application seems to run smoothly until suddently at some point (after 20 minutes in example) it terminates with the error thread.error: can't start new thread Any ideas? Edit: The threads are daemon Threads and the code is like: while True: t0 = time.time() keyword_statuses = DBSession.query(KeywordStatus).filter(KeywordStatus.status==0).options(joinedload(KeywordStatus.keyword)).with_lockmode("update").limit(100) if keyword_statuses.count() == 0: DBSession.commit() break for kw_status in keyword_statuses: kw_status.status = 1 DBSession.commit() t0 = time.time() w = SWorker(threads_no=32, network_server='http://192.168.1.242:8180/', keywords=keyword_statuses, cities=cities, saver=MySqlRawSave(DBSession), loglevel='debug') w.work() print 'finished' When the daemon threads are killed? When the application finishes or when the work() finishes? Look at the thread pool and the worker (it's from a recipe ) from Queue import Queue from threading import Thread, Event, current_thread import time event = Event() class Worker(Thread): """Thread executing tasks from a given tasks queue""" def __init__(self, tasks): Thread.__init__(self) self.tasks = tasks self.daemon = True self.start() def run(self): '''Start processing tasks from the queue''' while True: event.wait() #time.sleep(0.1) try: func, args, callback = self.tasks.get() except Exception, e: print str(e) return else: if callback is None: func(args) else: callback(func(args)) self.tasks.task_done() class ThreadPool: """Pool of threads consuming tasks from a queue""" def __init__(self, num_threads): self.tasks = Queue(num_threads) for _ in range(num_threads): Worker(self.tasks) def add_task(self, func, args=None, callback=None): ''''Add a task to the queue''' self.tasks.put((func, args, callback)) def wait_completion(self): '''Wait for completion of all the tasks in the queue''' self.tasks.join() def broadcast_block_event(self): '''blocks running threads''' event.clear() def broadcast_unblock_event(self): '''unblocks running threads''' event.set() def get_event(self): '''returns the event object''' return event

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  • Using unicodedata.normalize in Python 2.7

    - by dpitch40
    Once again, I am very confused with a unicode question. I can't figure out how to successfully use unicodedata.normalize to convert non-ASCII characters as expected. For instance, I want to convert the string u"Cœur" To u"Coeur" I am pretty sure that unicodedata.normalize is the way to do this, but I can't get it to work. It just leaves the string unchanged. >>> s = u"Cœur" >>> unicodedata.normalize('NFKD', s) == s True What am I doing wrong?

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  • python add two list and createing a new list

    - by Adam G.
    lst1 = ['company1,AAA,7381.0 ', 'company1,BBB,-8333.0 ', 'company1,CCC, 3079.999 ', 'company1,DDD,5699.0 ', 'company1,EEE,1640.0 ', 'company1,FFF,-600.0 ', 'company1,GGG,3822.0 ', 'company1,HHH,-600.0 ', 'company1,JJJ,-4631.0 ', 'company1,KKK,-400.0 '] lst2 =['company1,AAA,-4805.0 ', 'company1,ZZZ,-2576.0 ', 'company1,BBB,1674.0 ', 'company1,CCC,3600.0 ', 'company1,DDD,1743.998 '] output I need == ['company1,AAA,2576.0','company1,ZZZ,-2576.0 ','company1,KKK,-400.0 ' etc etc] I need to add it similar product number in each list and move it to a new list. I also need any symbol not being added together to be added to that new list. I am having problems with moving through each list. This is what I have: h = [] z = [] a = [] for g in hhl: spl1 = g.split(",") h.append(spl1[1]) for j in c_hhl: spl2 = j.split(",") **if spl2[1] in h: converted_num =(float(spl2[2]) +float(spl1[2])) pos=('{0},{1},{2}'.format(spl2[0],spl2[1],converted_num)) z.append(pos)** else: pos=('{0},{1},{2}'.format(spl2[0],spl2[1],spl2[2])) z.append(pos) for f in z: spl3 = f.split(",") a.append(spl3[1]) for n in hhl[:]: spl4 = n.split(",") if spl4[1] in a: got = (spl4[0],spl4[1],spl4[2]) hhl.remove(n) smash = hhl+z #for i in smash: for i in smash: print(i) I am having problem iterating through the list to make sure I get all of the simliar product to a new list,(bold) and any product not in list 1 but in lst2 to the new list and vice versa. I am sure there is a much easier way.

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  • Loop colours from variables for graphics.py [Python 3.2]

    - by user1056548
    I am creating a graphics program that draws 100 x 100 squares next to each other depending on the user-specified grid size. The user also inputs 4 colours for the squares to be coloured (e.g. if they enter red,green,blue,yellow the squares will be coloured in that order, repeating the colours). Is it possible to loop the colours from the variables the user has given? Here is what I have so far: def main(): print ("Please enter four comma seperated colours e.g.: 'red,green,blue,yellow'\n\ Allowed colours are: red, green, blue, yellow and cyan") col1, col2, col3, col4 = input("Enter your four colours: ").split(',') win = GraphWin ("Squares", 500, 500) colours = [col1, col2, col3, col4] drawSquare (win, col1, col2, col3, col4, colours) win.getMouse() win.close() def drawSquare(win, col1, col2, col3, col4, colours): for i in range (4): for j in range (len(colours)): colour = colours[j] x = 50 + (i * 50) circle = Circle (Point (x,50), 20) circle.setFill(colour) circle.draw(win) I think I should be using a list in some way, but can't work out exactly how to do it. Can anybody help?

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