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  • How to write the Visitor Pattern for Abstract Syntax Tree in Python?

    - by bodacydo
    My collegue suggested me to write a visitor pattern to navigate the AST. Can anyone tell me more how would I start writing it? As far as I understand, each Node in AST would have visit() method (?) that would somehow get called (from where?). That about concludes my understanding. To simplify everything, suppose I have nodes Root, Expression, Number, Op and the tree looks like this: Root | Op(+) / \ / \ Number(5) \ Op(*) / \ / \ / \ Number(2) Number(444) Can anyone think of how the visitor pattern would visit this tree to produce output: 5 + 2 * 444 Thanks, Boda Cydo.

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  • ExtJs: Tree: how download then select using AJAX calls ?

    - by Olivier Pons
    Hi, Here's my goal : - open a tree - download the root nodes - expand automatically one specific node using AJAX (and loop n times here) until i find a leaf then select the leaf Here's the function that works when I declare the Tree : listeners: { load: function(n) { console.log('load(n)'); n.eachChild( function(n) { if ((n.id=='lys/2007') || (n.id=='lys/2007/08') || (n.id=='lys/2007/08/29')) { n.expand(false,false); } }); } } But if I don't know how to make it more "generic" (almost exactly like the ExtJs documentation). But they don't jump automatically to a specific node (i.e. I want no user interaction). Any idea / advice how to do this? Don't hesitate to edit my post to make it proper English :)

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  • LINQ to XML, a problem conceptualizing how the tree should look.

    - by snark
    Have you ever had one of those days when you've dug a hole but your so deep in now that the only option is to keep on digging and see where you come out? I thought just for giggles in the latest component I'm writing to use LINQ to XML because it was about time I saw what all the hooplah was about. The problem: I am making a graph component that contains series of data that get graphed and then you can apply a formula to that series and graph another series then apply a formula to that series and so on. So I figured that I would do so in 2 steps, create (and manage) an XML representaion of the series and how they relate to each other, then pass this xml to a draw engine which draws. Conceptually its a tree, with the exception of the root all child series being based upon a parent (1 parent can have many children. So I should always be adding child nodes to their parent and if I delete a node(series) then I can simply delete the series and its descendants (then draw) and voila all the messy iterating through each node finding parents and children is unneccessary. Trouble is I dont know how to represent this tree in XML i.e. the structure. My first attempt saw me programatically adding each series as siblings, which worked like a treat because I ended up with an ordered list and thus my order of rendering was maintained. I had this <Chart> <Series id="1">seriesText1</Series> <Series id="2">seriesText2</Series> <Series id="3">seriesText3</Series> <Series id="4">seriesText4</Series> </Chart> I'm in a muddle now ... how can I represent a series and a series that has children series. If some-one can give me a hint to how my tree should look (perhaps with a snippet on how to programatically add nodes to their parents) All the examples I have read usually have some container elements such as <ContactS> or <BookS> but my head says I have <series> some of them parent some of them children. Would appreciate a nudge in the right direction.

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  • Implementation of a distance matrix of a binary tree that is given in the adjacency-list representation

    - by Denise Giubilei
    Given this problem I need an O(n²) implementation of this algorithm: "Let v be an arbitrary leaf in a binary tree T, and w be the only vertex connected to v. If we remove v, we are left with a smaller tree T'. The distance between v and any vertex u in T' is 1 plus the distance between w and u." This is a problem and solution of a Manber's exercise (Exercise 5.12 from U. Manber, Algorithms: A Creative Approach, Addison-Wesley (1989).). The thing is that I can't deal properly with the adjacency-list representation so that the implementation of this algorithm results in a real O(n²) complexity. Any ideas of how the implementation should be? Thanks.

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  • make a tree based on the key of each element in list.

    - by cocobear
    >>> s [{'000000': [['apple', 'pear']]}, {'100000': ['good', 'bad']}, {'200000': ['yeah', 'ogg']}, {'300000': [['foo', 'foo']]}, {'310000': [['#'], ['#']]}, {'320000': ['$', ['1']]}, {'321000': [['abc', 'abc']]}, {'322000': [['#'], ['#']]}, {'400000': [['yeah', 'baby']]}] >>> for i in s: ... print i ... {'000000': [['apple', 'pear']]} {'100000': ['good', 'bad']} {'200000': ['yeah', 'ogg']} {'300000': [['foo', 'foo']]} {'310000': [['#'], ['#']]} {'320000': ['$', ['1']]} {'321000': [['abc', 'abc']]} {'322000': [['#'], ['#']]} {'400000': [['yeah', 'baby']]} i want to make a tree based on the key of each element in list. result in logic will be: {'000000': [['apple', 'pear']]} {'100000': ['good', 'bad']} {'200000': ['yeah', 'ogg']} {'300000': [['foo', 'foo']]} {'310000': [['#'], ['#']]} {'320000': ['$', ['1']]} {'321000': [['abc', 'abc']]} {'322000': [['#'], ['#']]} {'400000': [['yeah', 'baby']]} perhaps a nested list can implement this or I need a tree type?

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  • What do I do with a Concrete Syntax Tree?

    - by Cap
    I'm using pyPEG to create a parse tree for a simple grammar. The tree is represented using lists and tuples. Here's an example: [('command', [('directives', [('directive', [('name', 'retrieve')]), ('directive', [('name', 'commit')])]), ('filename', [('name', 'f30502')])])] My question is what do I do with it at this point? I know a lot depends on what I am trying to do, but I haven't been able to find much about consuming/using parse trees, only creating them. Does anyone have any pointers to references I might use? Thanks for your help.

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  • minimax depth first search game tree

    - by Arvind
    Hi I want to build a game tree for nine men's morris game. I want to apply minimax algorithm on the tree for doing node evaluations. Minimax uses DFS to evaluate nodes. So should I build the tree first upto a given depth and then apply minimax or can the process of building the tree and evaluation occur together in recursive minimax DFS? Thank you Arvind

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  • How do you display a binary search tree?

    - by fakeit
    I'm being asked to display a binary search tree in sorted order. The nodes of the tree contain strings. I'm not exactly sure what the best way is to attack this problem. Should I be traversing the tree and displaying as I go? Should I flatten the tree into an array and then use a sorting algorithm before I display? I'm not looking for the actual code, just a guide where to go next.

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  • Maintaing list order in binary tree.

    - by TheBigO
    Given a sequence of numbers, I want to insert the numbers into a balanced binary tree such that when I do a preorder traversal on the tree, it gives me the sequence back. How can I construct the insert method corresponding to this requirement? Remember that the tree must be balanced, so there isn't a completely trivial solution. I was trying to do this with a modified version of an AVL tree, but I'm not sure if this can work out.

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  • Convert a post-order binary tree traversal index to an level-order (breadth-first) index

    - by strfry
    Assuming a complete binary tree, each node can be adressed with the position it appears in a given tree traversal algorithm. For example, the node indices of a simple complete tree with height 3 would look like this: breadth first (aka level-order): 0 / \ 1 2 / \ / \ 3 4 5 6 post-order dept first: 6 / \ 2 5 / \ / \ 0 1 3 4 The height of the tree and an index in the post-order traversal is given. How can i calculate the breadth first index from this information?

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  • Layer 3 switch routing

    - by Yoshiwaan
    I need help moving over to using our layer 3 switch as the inter vlan routing device rather than our cisco router. I've mostly got it working but I've got stuck near the end and need some advice (I think I just need a bit of education on the subject really). Cur I have a Dell PowerConnect 7048 connecting to a Cisco 1841 router. I've got a few key excerpts from the configs to provide the key information. On the powerconnect I have the following: ip routing ip default-gateway 172.31.14.1 ip route 0.0.0.0 0.0.0.0 172.31.14.1 253 ! interface vlan 1 ip address 172.31.14.254 255.255.255.0 exit interface vlan 2 ip address 172.31.19.254 255.255.255.0 exit interface vlan 4 ip address 172.31.16.254 255.255.255.0 ! interface Gi1/0/1 description 'Link to L7Router01' switchport mode trunk switchport trunk allowed vlan except 3,7-4093 exit ! and on the Cisco the following: interface FastEthernet0/0 ip address 172.31.14.1 255.255.255.0 ip nat inside ip virtual-reassembly ! interface FastEthernet0/0.2 description Accounts VLAN encapsulation dot1Q 2 ip address 172.31.19.1 255.255.255.0 ip nat inside ip virtual-reassembly ! interface FastEthernet0/0.4 description Voice VLAN encapsulation dot1Q 4 ip address 172.31.16.1 255.255.255.0 ip nat inside ip virtual-reassembly ! So what I'm doing is moving clients over so that their default gateway is a 172.31.x.254 address rather than a 172.31.x.1 address. This works great for inter-vlan routing, I have no issues with this. The switch can also access the router no worries, and users on the 172.31.14.0/24 network can access all interfaces and sub-interfaces on the router, including 172.31.14.1. They can also access all of the interfaces that the router connects off to, no worries there. The problem I have is that users on the 172.31.16.0/24 and 172.31.19.0/24 subnets cannot access either 172.31.14.1 or any of the subnets the router connects to. They can, however, connect to BOTH of the sub interfaces on the router from either subnet. What am I missing here? Why can't the vlans connect to the non-sub interface on the router? Are tagged packets being sent to this interface?

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  • Cladogram, tree of life, cladistics, taxonomy in JS or canvas?

    - by boblet
    Good people - I need some help to find a way to create an interactive cladogram or phylogenetic tree (yes, I have read all related posts, and do not find what I am looking for). The thing is, I need the nodes to be name-able. An example would be something like this Most scripts I find are either applets, flash, or simply do not show the node classification, ie it would skip "feliformia" in this example. This is useless to me, as I would then end up with carnivore - anonymous node - anonymous node - anonymous node - tiger, and that is not good. This tree will in theory cover all life, so it could get rather large, and get links and names in english and latin from database. So: no flash, no applets. It must be horizontal, no supertrees (circular). I have gone through this http://bioinfo.unice.fr/biodiv/Tree_editors.html but most of them seems to be either old, not displaying sub-node levels, applets, or way too complex. I imagine this would be a delightful job for canvas/jQuery..? And chances are, someone got there before me? Any pointers much appreciated. Note: if anyone out there would like to do something like this as a project, I will be happy to help, even though it would not benefit me for this project.This type of taxonomy is not as simple as it may seem, and I would be happy see this happen.

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  • How can you get the call tree with python profilers?

    - by Oliver
    I used to use a nice Apple profiler that is built into the System Monitor application. As long as your C++ code was compiled with debug information, you could sample your running application and it would print out an indented tree telling you what percent of the parent function's time was spent in this function (and the body vs. other function calls). For instance, if main called function_1 and function_2, function_2 calls function_3, and then main calls function_3: main (100%, 1% in function body): function_1 (9%, 9% in function body): function_2 (90%, 85% in function body): function_3 (100%, 100% in function body) function_3 (1%, 1% in function body) I would see this and think, "Something is taking a long time in the code in the body of function_2. If I want my program to be faster, that's where I should start." Does anyone know how I can most easily get this exact profiling output for a python program? I've seen people say to do this: import cProfile, pstats prof = cProfile.Profile() prof = prof.runctx("real_main(argv)", globals(), locals()) stats = pstats.Stats(prof) stats.sort_stats("time") # Or cumulative stats.print_stats(80) # 80 = how many to print but it's quite messy compared to that elegant call tree. Please let me know if you can easily do this, it would help quite a bit. Cheers!

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  • A data structure based on the R-Tree: creating new child nodes when a node is full, but what if I ha

    - by Tom
    I realize my title is not very clear, but I am having trouble thinking of a better one. If anyone wants to correct it, please do. I'm developing a data structure for my 2 dimensional game with an infinite universe. The data structure is based on a simple (!) node/leaf system, like the R-Tree. This is the basic concept: you set howmany childs you want a node (a container) to have maximum. If you want to add a leaf, but the node the leaf should be in is full, then it will create a new set of nodes within this node and move all current leafs to their new (more exact) node. This way, very populated areas will have a lot more subdivisions than a very big but rarely visited area. This works for normal objects. The only problem arises when I have more than maxChildsPerNode objects with the exact same X,Y location: because the node is full, it will create more exact subnodes, but the old leafs will all be put in the exact same node again because they have the exact same position -- resulting in an infinite loop of creating more nodes and more nodes. So, what should I do when I want to add more leafs than maxChildsPerNode with the exact same position to my tree? PS. if I failed to explain my problem, please tell me, so I can try to improve the explanation.

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  • Dynamic Grouping and Columns

    - by Tim Dexter
    Some good collaboration between myself and Kan Nishida (Oracle BIP Consulting) over at bipconsulting on a question that came in yesterday to an internal mailing list. Is there a way to allow columns to be place into a template dynamically? This would be similar to the Answers Column selector. A customer has said Crystal can do this and I am trying to see how BI Pub can do the same. Example: Report has Regions as a dimension in a table, they want the user to select a parameter that will insert either Units or Dollars without having to create multiple templates. Now whether Crystal can actually do it or not is another question, can Publisher? Yes we can! Kan took the first stab. His approach, was to allow to swap out columns in a table in the report. Some quick steps: 1. Create a parameter from BIP server UI 2. Declare the parameter in RTF template You can check this post to see how you can declare the parameter from the server. http://bipconsulting.blogspot.com/2010/02/how-to-pass-user-input-values-to-report.html 3. Use the parameter value to condition if a particular column needs to be displayed or not. You can use <?if@column:.....?> syntax for Column level IF condition. The if@column is covered in user documentation. This would allow a developer to create a report with the parameter or multiple parameters to allow the user to pick a column to be included in the report. I took a slightly different tack, with the mention of the column selector in the Answers report I took that to mean that the user wanted to select more of a dimensional column and then have the report recalculate all its totals and subtotals based on that selected column. This is a little bit more involved and involves some smart XSL and XPATH expressions, but still very doable. The user can select a column as a parameter, that is passed to the template rather than the query. The parameter value that is actually passed is the element name that you want to regroup the data by. Inside the template we then reference that parameter value in our for-each-group loop. That's where we need the trixy XSL/XPATH code to get the regrouping to happen. At this juncture, I need to hat tip to Klaus, for his article on dynamic sorting that he wrote back in 2006. I basically took his sorting code and applied it to the for-each loop. You can follow both of Kan's first two steps above i.e. Create a parameter from BIP server UI - this just needs to be based on a 'list' type list of value with name/value pairs e.g. Department/DEPARTMENT_NAME, Job/JOB_TITLE, etc. The user picks the 'friendly' value and the server passes the element name to the template. Declare the parameter in RTF template - been here before lots of times right? <?param@begin:group1;'"DEPARTMENT_NAME"'?> I have used a default value so that I can test the funtionality inside the template builder (notice the single and double quotes.) Next step is to use the template builder to build a re-grouped report layout. It does not matter if its hard coded right now; we will add in the dynamic piece next. Once you have a functioning template that is re-grouping correctly. Open up the for-each-group field and modify it to use the parameter: <?for-each-group:ROW;./*[name(.) = $group1]?> 'group1' is my grouping parameter, declared above. We need the XPATH expression to find the column in the XML structure we want to group that matches the one passed by the parameter. Its essentially looking through the data tree for a match. We can show the actual grouping value in the report output with a similar XPATH expression <?./*[name(.) = $group1]?> In my example, I took things a little further so that I could have a dynamic label for the parameter value. For instance if I am using MANAGER as the parameter I want to show: Manager: Tim Dexter My XML elements are readable e.g. DEPARTMENT_NAME. Its a simple case of replacing the underscore with a space and then 'initcapping' the result: <?xdoxslt:init_cap(translate($group1,'_',' '))?> With this in place, the user can now select a grouping column in the BIP report viewer and the layout will re-group the data and any calculations based on that column. I built a group above report but you could equally build the group left version to truly mimic the Answers column selector. If you are interested you can get an example report, sample data and layout template here. Of course, you can combine Klaus' dynamic sorting, Kan's conditional column approach and this dynamic grouping to build a real kick ass report for users that will keep them happy for hours..

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  • reiserfsck --rebuild-tree failed: Not enough allocable blocks

    - by mojo
    I have a reiserfs volume that required a --rebuild-tree, but is currently failing to complete when I pass it --rebuild-tree. Here is the output that I receive when running it: reiserfsck 3.6.19 (2003 www.namesys.com) # reiserfsck --rebuild-tree started at Mon Oct 26 13:22:16 2009 # Pass 0: # Pass 0 The whole partition (7864320 blocks) is to be scanned Skipping 8450 blocks (super block, journal, bitmaps) 7855870 blocks will be read 0%....20%....40%....60%....80%....100% left 0, 9408 /sec 287884 directory entries were hashed with "r5" hash. "r5" hash is selected Flushing..finished Read blocks (but not data blocks) 7855870 Leaves among those 6105606 Objectids found 287892 Pass 1 (will try to insert 6105606 leaves): # Pass 1 Looking for allocable blocks .. finished 0%....20%....40%....60%....80%....Not enough allocable blocks, checking bitmap...there are 1 allocable blocks, btw out of disk space Aborted I can't mount it, and I can't fsck it. I've tried extending the volume, but that hasn't helped either.

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  • reiserfsck --rebuild-tree failed: Not enough allocable blocks

    - by mojo
    I have a reiserfs volume that required a --rebuild-tree, but is currently failing to complete when I pass it --rebuild-tree. Here is the output that I receive when running it: reiserfsck 3.6.19 (2003 www.namesys.com) # reiserfsck --rebuild-tree started at Mon Oct 26 13:22:16 2009 # Pass 0: # Pass 0 The whole partition (7864320 blocks) is to be scanned Skipping 8450 blocks (super block, journal, bitmaps) 7855870 blocks will be read 0%....20%....40%....60%....80%....100% left 0, 9408 /sec 287884 directory entries were hashed with "r5" hash. "r5" hash is selected Flushing..finished Read blocks (but not data blocks) 7855870 Leaves among those 6105606 Objectids found 287892 Pass 1 (will try to insert 6105606 leaves): # Pass 1 Looking for allocable blocks .. finished 0%....20%....40%....60%....80%....Not enough allocable blocks, checking bitmap...there are 1 allocable blocks, btw out of disk space Aborted I can't mount it, and I can't fsck it. I've tried extending the volume, but that hasn't helped either.

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  • How can I force a tree itemrenderer to redraw during a drag and drop operation?

    - by swidnikk
    I have a tree control with a custom item renderer. The item renderer has different states that should be set while an item is being dragged over the item renderer. I understand from reading this post http://forums.adobe.com/message/2091088 that the 'right way' to do this is to override the 'getCurrentState' method and append some text. I do that. Now in my tree control I handle the drag over event and get a reference to the itemrenderer that is being dragged over and I set the boolean 'dragOver' property to true. Now I just need to force my itemRenderer to redraw. I can't figure that out. A workaround, is to just set the currentState of the itemRenderer. My question then, how can I force my itemRenderer to refresh? (and I've tried calling validateNow, invalideDisplayList/Properties/Size, to no avail) <?xml version="1.0" encoding="utf-8"?> <s:MXTreeItemRenderer xmlns:fx="http://ns.adobe.com/mxml/2009" xmlns:s="library://ns.adobe.com/flex/spark" xmlns:mx="library://ns.adobe.com/flex/mx"> <fx:Script> <![CDATA[ import mx.events.DragEvent; import mx.events.FlexEvent; import spark.layouts.supportClasses.DropLocation; public var dragOver:Boolean = false; override protected function getCurrentRendererState():String { var skinState:String = super.getCurrentRendererState(); if( dragOver ) skinState += "AndDragOver"; trace('getCurrentRendererState', skinState); return skinState; } ]]> </fx:Script> <s:states> <s:State name="normal" /> <s:State name="hovered" /> <s:State name="selected" /> <s:State name="normalAndDragOver" stateGroups="dragOverGroup" /> <s:State name="hoveredAndDragOver" stateGroups="dragOverGroup" /> <s:State name="selectedAndDragOver" stateGroups="dragOverGroup" /> </s:states> ...

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  • How to modify preorder tree traversal algorithm to handle nodes with multiple parents?

    - by poldo
    I've been searching for a while now and can't seem to find an alternative solution. I need the tree traversal algorithm in such a way that a node can have more than 1 parent, if it's possible (found a great article here: Storing Hierarchical Data in a Database). Are there any algorithms so that, starting from a root node, we can determine the sequence and dependencies of nodes (currently reading topological sorting)?

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