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• Exceptional DBA 2011 Jeff Moden on why you should enter in 2012

  - by RedAndTheCommunity

  My "reign" as the Red Gate Exceptional DBA is almost over and I was asked to say a few words about this wonderful award. Having been one of those folks that shied away from entering the contest during the first 3 years of the award, I thought I'd spend the time encouraging DBAs of all types to enter. Winning this award has some obvious benefits. You win a trip to PASS including money towards your flight, paid hotel stay, and, of course, paid admission. You win a wonderful bundle of software from Red Gate to make your job as a DBA a whole lot easier. You also win some pretty incredible notoriety for your resume. After all, it's not everyone who wins a worldwide contest. To date, there are only 4 of us in the world who have won this award. You could be number 5! For me, all of that pales in comparison to what I found out during the entry process. I'm very confident in my skills, but I'm also humble. It was suggested to me that I enter the contest when it first started. I just couldn't bring myself to nominate myself. When the 2011 nomination period opened up, several people again suggested that I enter, so I swallowed hard and asked several co-workers to have a look at the online nomination form and, if they thought me worthy, to write a nomination for me. I won't bore you with the details, but what they wrote about me was one of the most incredible rewards that I could ever have hoped to receive. I had no idea of the impact that I'd made on my co-workers. Even if I hadn't made it to the top 5 for the award, I had already won something very near and dear that no one can ever top. "Even if I hadn't made it to the top 5 for the award, I had already won something very near and dear that no one can ever top." There's only one named winner and 4 "runners up" in this competition every year but don't let that discourage you. Enter this competition. Even if you work in the proverbial "Mom'n'Pop" shop, get your boss and the people you work with directly to nominate you. Even if you don't make it to the top 5, you might just find out that you're more of a winner than you think. If you're too proud to ask them, then take the time to nominate yourself instead of shying away like I did for the first 3 years. You work hard as a DBA and, as David Poole once said, if you're the first person that people ask for help rather than one of the last, then you're probably an Exceptional DBA. It's time to stand up and be counted! Win or lose, the entry process can be a huge reward in itself. It was for me. Thank you, Red Gate, for giving me such a wonderful opportunity. Thanks for listening folks and for all that you do as DBAs. As 'Red Green' says, "We're all in this together and I'm pullin' for ya". --Jeff Moden Red Gate Exceptional DBA 2011

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• Exceptional DBA 2011 Jeff Moden on why you should enter in 2012

  - by RedAndTheCommunity

  My "reign" as the Red Gate Exceptional DBA is almost over and I was asked to say a few words about this wonderful award. Having been one of those folks that shied away from entering the contest during the first 3 years of the award, I thought I'd spend the time encouraging DBAs of all types to enter. Winning this award has some obvious benefits. You win a trip to PASS including money towards your flight, paid hotel stay, and, of course, paid admission. You win a wonderful bundle of software from Red Gate to make your job as a DBA a whole lot easier. You also win some pretty incredible notoriety for your resume. After all, it's not everyone who wins a worldwide contest. To date, there are only 4 of us in the world who have won this award. You could be number 5! For me, all of that pales in comparison to what I found out during the entry process. I'm very confident in my skills, but I'm also humble. It was suggested to me that I enter the contest when it first started. I just couldn't bring myself to nominate myself. When the 2011 nomination period opened up, several people again suggested that I enter, so I swallowed hard and asked several co-workers to have a look at the online nomination form and, if they thought me worthy, to write a nomination for me. I won't bore you with the details, but what they wrote about me was one of the most incredible rewards that I could ever have hoped to receive. I had no idea of the impact that I'd made on my co-workers. Even if I hadn't made it to the top 5 for the award, I had already won something very near and dear that no one can ever top. "Even if I hadn't made it to the top 5 for the award, I had already won something very near and dear that no one can ever top." There's only one named winner and 4 "runners up" in this competition every year but don't let that discourage you. Enter this competition. Even if you work in the proverbial "Mom'n'Pop" shop, get your boss and the people you work with directly to nominate you. Even if you don't make it to the top 5, you might just find out that you're more of a winner than you think. If you're too proud to ask them, then take the time to nominate yourself instead of shying away like I did for the first 3 years. You work hard as a DBA and, as David Poole once said, if you're the first person that people ask for help rather than one of the last, then you're probably an Exceptional DBA. It's time to stand up and be counted! Win or lose, the entry process can be a huge reward in itself. It was for me. Thank you, Red Gate, for giving me such a wonderful opportunity. Thanks for listening folks and for all that you do as DBAs. As 'Red Green' says, "We're all in this together and I'm pullin' for ya". --Jeff Moden Red Gate Exceptional DBA 2011

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• Generate texture for a heightmap

  - by James

  I've recently been trying to blend multiple textures based on the height at different points in a heightmap. However i've been getting poor results. I decided to backtrack and just attempt to recreate one single texture from an SDL_Surface (i'm using SDL) and just send that into opengl. I'll put my code for creating the texture and reading the colour values. It is a 24bit TGA i'm loading, and i've confirmed that the rest of my code works because i was able to send the surfaces pixels directly to my createTextureFromData function and it drew fine. struct RGBColour { RGBColour() : r(0), g(0), b(0) {} RGBColour(unsigned char red, unsigned char green, unsigned char blue) : r(red), g(green), b(blue) {} unsigned char r; unsigned char g; unsigned char b; }; // main loading code SDLSurfaceReader* reader = new SDLSurfaceReader(m_renderer); reader->readSurface("images/grass.tga"); // new texture unsigned char* newTexture = new unsigned char[reader->m_surface->w * reader->m_surface->h * 3 * reader->m_surface->w]; for (int y = 0; y < reader->m_surface->h; y++) { for (int x = 0; x < reader->m_surface->w; x += 3) { int index = (y * reader->m_surface->w) + x; RGBColour colour = reader->getColourAt(x, y); newTexture[index] = colour.r; newTexture[index + 1] = colour.g; newTexture[index + 2] = colour.b; } } unsigned int id = m_renderer->createTextureFromData(newTexture, reader->m_surface->w, reader->m_surface->h, RGB); // functions for reading pixels RGBColour SDLSurfaceReader::getColourAt(int x, int y) { Uint32 pixel; Uint8 red, green, blue; RGBColour rgb; pixel = getPixel(m_surface, x, y); SDL_LockSurface(m_surface); SDL_GetRGB(pixel, m_surface->format, &red, &green, &blue); SDL_UnlockSurface(m_surface); rgb.r = red; rgb.b = blue; rgb.g = green; return rgb; } // this function taken from SDL documentation // http://www.libsdl.org/cgi/docwiki.cgi/Introduction_to_SDL_Video#getpixel Uint32 SDLSurfaceReader::getPixel(SDL_Surface* surface, int x, int y) { int bpp = m_surface->format->BytesPerPixel; Uint8 *p = (Uint8*)m_surface->pixels + y * m_surface->pitch + x * bpp; switch (bpp) { case 1: return *p; case 2: return *(Uint16*)p; case 3: if (SDL_BYTEORDER == SDL_BIG_ENDIAN) return p[0] << 16 | p[1] << 8 | p[2]; else return p[0] | p[1] << 8 | p[2] << 16; case 4: return *(Uint32*)p; default: return 0; } } I've been stumped at this, and I need help badly! Thanks so much for any advice.

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• C# Linq List Contains Similar Elements

  - by John Peters

  Hi All, I am looking for linq query to see if there exists a similar object I have an object graph as follows Cart myCart = new Cart { List<CartProduct> myCartProduct = new List<CartProduct> { CartProduct cartProduct1 = new CartProduct { List<CartProductAttribute> a = new List<CartProductAttribute> { CartProductAttribute cpa1 = new CartProductAttribute{ title="red" }, CartProductAttribute cpa2 = new CartProductAttribute{ title="small" } } } CartProduct cartProduct2 = new CartProduct { List<CartProductAttribute> d = new List<CartProductAttribute> { CartProductAttribute cpa3 = new CartProductAttribute{ title="john" }, CartProductAttribute cpa4 = new CartProductAttribute{ title="mary" } } } } } I would like to get from the Cart = a CartProduct that has the exact same CartProductAttribute title values as a CartProduct that I need to compare. No more and no less. E.G. I need to find a similar CartProduct that has a CartProductAttribute with title="red" and a cartProductAttribute with title="small" in myCart (eg 'cartProduct1' in the example) CartProduct cartProductToCompare = new CartProduct { List<CartProductAttribute> cartProductToCompareAttributes = new List<CartProductAttribute> { CartProductAttribute cpa5 = new CartProductAttribute{ title="red" }, CartProductAttribute cpa6 = new CartProductAttribute{ title="small" } } } So from object graph myCart cartProduct1 cpa1 (title=red) cpa2 (title=small) cartProduct2 cpa3 (title=john) cpa4 (title=mary) Linq query looking for cartProductToCompare cpa5 (title=red) cpa6 (title=small) Should find cartProduct1 Hope all this makes sense... Thanks

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• Create array of objects based on another array?

  - by xckpd7

  I want to take an array like this: var food = [ { name: 'strawberry', type: 'fruit', color: 'red', id: 3483 }, { name: 'apple', type: 'fruit', color: 'red', id: 3418 }, { name: 'banana', type: 'fruit', color: 'yellow', id: 3458 }, { name: 'brocolli', type: 'vegetable', color: 'green', id: 1458 }, { name: 'steak', type: 'meat', color: 'brown', id: 2458 }, ] And I want to create something like this dynamically: var foodCategories = [ { name: 'fruit', items: [ { name: 'apple', type: 'fruit', color: 'red', id: 3418 }, { name: 'banana', type: 'fruit', color: 'yellow', id: 3458 } ] }, { name: 'vegetable', items: [ { name: 'brocolli', type: 'vegetable', color: 'green', id: 1458 }, ] }, { name: 'meat', items: [ { name: 'steak', type: 'meat', color: 'brown', id: 2458 } ] } ] What's the best way to go about doing this?

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• How to convert between Enums where values share the same names ?

  - by Ross Watson

  Hi, if I want to convert between two Enum types, the values of which, I hope, have the same names, is there a neat way, or do I have to do it like this...? enum colours_a { red, blue, green } enum colours_b { yellow, red, blue, green } static void Main(string[] args) { colours_a a = colours_a.red; colours_b b; //b = a; b = (colours_b)Enum.Parse(typeof(colours_b), a.ToString()); } Thanks, Ross

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• SQL Joing on a one-to-many relationship

  - by Harley

  Ok, here was my original question; Table one contains ID|Name 1 Mary 2 John Table two contains ID|Color 1 Red 2 Blue 2 Green 2 Black I want to end up with is ID|Name|Red|Blue|Green|Black 1 Mary Y Y 2 John Y Y Y It seems that because there are 11 unique values for color and 1000's upon 1000's of records in table one that there is no 'good' way to do this. So, two other questions. Is there an efficient way to get this result? I can then create a crosstab in my application to get the desired result. ID|Name|Color 1 Mary Red 1 Mary Blue 2 John Blue 2 John Green 2 John Black If I wanted to limit the number of records returned how could I do something like this? Where ((color='blue') AND (color<>'red' OR color<>'green')) So using the above example I would then get back ID|Name|Color 1 Mary Blue 2 John Blue 2 John Black I connect to Visual FoxPro tables via ADODB. Thanks!

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• Trim "Minify" inline css at runtime, expand it at edit time.

  - by Scott B

  My custom WP theme has a text block in the theme options panel that allows the user to create and maintain a custom css block that is applied to the site template at runtime. I would like to trim or "minify" this content before its stored in the database, but retain all the whitespace when its presented back to the user for editing. Would this be possible? For example, if the user has entered the following as their custom css code... .red {color:red;} .green {color:green;} .blue {color:blue;} Then I would like to store it in the database as: .red{color:red;}.green{color:green;}.blue{color:blue;} But still display it as it was input (ie, retain all the white space and line breaks) when the user is editing the content via my theme options panel.

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• Speed of CSS

  - by Ólafur Waage

  This is just a question to help me understand CSS rendering better. Lets say we have a million lines of this. <div class="first"> <div class="second"> <span class="third">Hello World</span> </div> </div> Which would be the fastest way to change the font of Hello World to red? .third { color: red; } div.third { color: red; } div.second div.third { color: red; } div.first div.second div.third { color: red; } Also, what if there was at tag in the middle that had a unique id of "foo". Which one of the CSS methods above would be the fastest. I know why these methods are used etc, im just trying to grasp better the rendering technique of the browsers and i have no idea how to make a test that times it. UPDATE: Nice answer Gumbo. From the looks of it then it would be quicker in a regular site to do the full definition of a tag. Since it finds the parents and narrows the search for every parent found. That could be bad in the sense you'd have a pretty large CSS file though.

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• what is the oldest glib version that a qt application can run with

  - by yan bellavance

  I am trying to build a standalone qt application (built on ubuntu and deployed on Red Hat 5.3, both 64 bits) after building a qt application that is statically linked to the qt library I tried to run the program on red hat and got an error saying libc.so.6 was not found and that GLIBC_2.9 or GLIBC_2.10 is not installed and needed. I tried doing a yum install glibc but then I get a message saying that glibc is up to date (its version is 2.0) I guees I am going to restart the build process but this time from a red hat installation. What do you sugges I should do in this case. My goal is to build a standalone qt application that only needs to run on red hat 5 (im pretty sure there is also going to be an issue with fontconfig.so but I can simply provide this library directly in the same directory as the app)

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• Implementing toString on Java enums

  - by devoured elysium

  Hello It seems to be possible in Java to write something like this: private enum TrafficLight { RED, GREEN; public String toString() { return //what should I return here if I want to return //"abc" when red and "def" when green? } } Now, I'd like to know if it possible to returnin the toString method "abc" when the enum's value is red and "def" when it's green. Also, is it possible to do like in C#, where you can do this?: private enum TrafficLight { RED = 0, GREEN = 15 ... } I've tried this but it but I'm getting compiler errors with it. Thanks

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• How to change the margin of code's frame of showexpl.sty when numbers=none?

  - by suugaku

  Hi all, I want to align the code's frame with the formated text's frame. If the numbers=left,the mission is accomplished by configuring xleftmargin, xrightmargin, framesep, and numbersep. However, when I set numbers=none, I cannot accomplish my mission by configuring those properties. Regardless of the values set to those properties, the code's frame remains unchanged and expands beyond the \textwidth. Please see my code snippet below. Thank you in advance. \documentclass[a4paper,11pt,twoside,final,dvips]{book} \usepackage{xcolor} \usepackage{showexpl} \lstset{% breaklines=true, breakindent=0pt, basicstyle=\color{magenta}\ttfamily\tiny, keywordstyle=\color{blue}\sffamily\bfseries, identifierstyle=\color{black}, commentstyle=\color{cyan}\itshape, stringstyle=\rmfamily, showstringspaces=false, tabsize=2, %========== FRAME ========== frame=single, framerule=0.4pt, rulecolor=\color{red}, framesep=3pt, %========== MARGIN ========== xleftmargin=3.4pt, xrightmargin=3.4pt, %========== NUMBER ========== numbers=left, numberstyle=\color{red}\tiny, numbersep=6.4pt, explpreset={language={[LaTeX]TeX},pos=b}% } \usepackage{lipsum} \usepackage{printlen} %------------------------- MARKER ------------------------ \newlength{\halftextwidth} \setlength{\halftextwidth}{\textwidth*\real{0.5}} \newcommand*{\MARKER}% {% \uselengthunit{cm} \par\noindent\strut\vrule% \hrulefill~% {\color{red}\scriptsize half text area: \printlength{\halftextwidth}}% ~\hrulefill\vrule% \hrulefill~% {\color{red}\scriptsize half text area: \printlength{\halftextwidth}}% ~\hrulefill\vrule% \marginpar% {% \strut\vrule\hrulefill~% {\color{red}\scriptsize margin area: \rndprintlength{\marginparwidth}}% ~\hrulefill\vrule% }% \par% }% \begin{document} \chapter{I love \LaTeXe, but $\cdots$} \section{With numbers=left} \vfill \MARKER \begin{LTXexample} \lipsum[1-1] \end{LTXexample} \MARKER \vfill \pagebreak \section{With numbers=none} \vfill \MARKER % Any values that are assigned to xleftmargin or xrightmargin % have no effect on the margin of the code's frame. \begin{LTXexample}[numbers=none,xleftmargin=10.4pt,xrightmargin=10.4pt] \lipsum[1-1] \end{LTXexample} \MARKER \vfill \end{document}

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• filtering for multiple values on one column. All values must exist, else - return zero

  - by Andrew

  Hello All, I would like to filter one column in a table for couple values and show results only if all those values are there. If one or more is missing, then return zero results. example table +----+--------+----------+ | id | Fruit | Color | +----+--------+----------+ | 1 | apple | red | | 2 | mango | yellow | | 3 | banana | yellow | +----+--------+----------+ example "wrong" code: (this must return 3 rows) select Fruit FROM table WHERE Color = red AND Color = yellow but select Fruit FROM table WHERE Color = red AND Color = green must return 0 rows. (If i use select Fruit FROM table WHERE Color = red OR Color = green i get 1 row which is not what i need) I am using PHP with form where user checks different checkboxes that represent different values of the same column. So when he selects multiple checkboxes, all those values should be in the result set, otherwise no result should be given. Thank you, Andrew

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• CSS on Mouse Down

  - by danixd

  Usually I would use :hover, but I want my website to be accessible on touchscreen media too. I know I can use :active, but as soon as I let go of the mouse button, it goes back to its inactive state. Effectively I want: Mouse Down : Div goes green Mouse Up: Div stays green Mouse Down: Div goes red Mouse Up: Div stays red Instead of: Mouse Down: Div goes green Mouse Up: Div goes red

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• css dropdownlist /combox <select

  - by teki

  i am using bassistance.de form validation please look at the demo here i have few dropdownlist and when it validates i want that dropdonwlist to be dotted with red which is not happening and i have even add the .css line please see below. please have a look at the demo to get an idea what i am asking for. div.error { display: none; } input { border: 1px solid black; } input.checkbox { border: none } input:focus { border: 1px dotted black; } input.error { border: 1px dotted red; } textarea.error { border: 1px dotted red; } **select.error { border: 1px dotted red; }** form.cmxform .gray * { color: gray; } PS: some how it ignores "select.error..."

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• Javascript Event Bubbling Not Working As Expected

  - by Dean Bayley

  Hi Guys, Having a nightmare trying to figure out event Bubbling.. Example here: link text From what i understand clicking in the area inside the red border should trigger all 3 event handlers (red, blue & body), only red and body are triggered.. I have tried altering the third value of addEventListener and changing the return values but to no avail, any ideas? D.

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• How can I turn a bunch of rows into aggregated columns WITHOUT using pivot in SQL Server 2005?

  - by cdeszaq

  Here is the scenario: I have a table that records the user_id, the module_id, and the date/time the module was viewed. eg. Table: Log ------------------------------ User_ID Module_ID Date ------------------------------ 1 red 2001-01-01 1 green 2001-01-02 1 blue 2001-01-03 2 green 2001-01-04 2 blue 2001-01-05 1 red 2001-01-06 1 blue 2001-01-07 3 blue 2001-01-08 3 green 2001-01-09 3 red 2001-01-10 3 green 2001-01-11 4 white 2001-01-12 I need to get a result set that has the user_id as the 1st column, and then a column for each module. The row data is then the user_id and the count of the number of times that user viewed each module. eg. --------------------------------- User_ID red green blue white --------------------------------- 1 2 1 2 0 2 0 1 1 0 3 1 2 1 0 4 0 0 0 1 I was initially thinking that I could do this with PIVOT, but no dice; the database is a converted SQL Server 2000 DB that is running in SQL Server 2005. I'm not able to change the compatibility level, so pivot is out. How can I accomplish this?

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• Do Eclipse's Refactoring Tools Violate The Java Language Specification?

  - by Tom Tresansky

  In Eclipse 3.5, say I have a package structure like this: tom.package1 tom.package1.packageA tom.package1.packageB if I right click on an the tom.package1 package and go to Refactor-Rename, an option "Rename subpackages" appears as a checkbox. If I select it, and then rename tom.package1 to tom.red my package structure ends up like this: tom.red tom.red.packageA tom.red.packageB Yet I hear that Java's packages are not hierarchical. The Java Tutorials back that up (see the section on Apparent Hierarchies of Packages). It certainly seems like Eclipse is treating packages as hierarchical in this case. I was curious why access specifiers couldn't allow/restrict access to "sub-packages" in a previous question because I KNEW I had seen "sub-packages" referenced somewhere before. So are Eclipse's refactoring tools intentionally misleading impressionable young minds by furthering the "sub-package" myth? Or am I misinterpreting something here?

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• i need your advise please help

  - by davit-datuashvili

  for example we have array of color String s[]=new String[]{"red","black..............}; all color is red or black i need algorithm which partition array such that all red came before to black so how compare it and exchange to accomplish this task ,

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• merging tow jquery selections

  - by Praveen Prasad

  var _sel1 = $('.red'); var _sel2 = $('.yellow'); suppose there are 2 jquery sections stored in 2 vars, how can i merge them in one i dont want this way var _sel3=$('.red,.yellow') or $('.red').add('.yellow'); i actually want to merge these 2 selections stored in varaible (_sel1,_sel2) to produce a third varaible

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• Sorting an array with two values

  - by davit-datuashvili

  I have array of colors: String s[]=new String[]{"red","black..............}; The only possible colors are red and black. I need an algorithm which partitions the array such that all red come before all black. How can I compare/exchange them to accomplish that?

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• Parent Child Relationships with Fluent NHibernate?

  - by ElHaix

  I would like to create a cascading tree/list of N number of children for a given parent, where a child can also become a parent. Given the following data structure: CountryType=1; ColorType=3; StateType=5 6,7,8 = {Can, US, Mex} 10, 11, 12 = {Red, White, Blue} 20,21,22= {California, Florida, Alberta} TreeID ListTypeID ParentTreeID ListItemID 1 1 Null 6 (Canada is a Country) 2 1 Null 7 (US is a Country) 3 1 Null 8 (Mexico is a Country) 4 3 3 10 (Mexico has Red) 5 3 3 11 (Mexico has White) 6 5 1 22 (Alberta is in Canada) 7 5 7 20 (California is in US) 8 5 7 21 (Florida is in US) 9 3 6 10 (Alberta is Red) 10 3 6 12 (Alberta is Blue) 11 3 2 10 (US is Red) 12 3 2 11 (Us is Blue) How would this be represented in Fluent NHibernate classes? Some direction would be appreciated. Thanks.

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• How to compare a memory bits in C++?

  - by Trunet

  Hi, I need help with a memory bit comparison function. I bought a LED Matrix here with 4 x HT1632C chips and I'm using it on my arduino mega2560. There're no code available for this chipset(it's not the same as HT1632) and I'm writing on my own. I have a plot function that get x,y coordinates and a color and that pixel turn on. Only this is working perfectly. But I need more performance on my display so I tried to make a shadowRam variable that is a "copy" of my device memory. Before I plot anything on display it checks on shadowRam to see if it's really necessary to change that pixel. When I enabled this(getShadowRam) on plot function my display has some, just SOME(like 3 or 4 on entire display) ghost pixels(pixels that is not supposed to be turned on). If I just comment the prev_color if's on my plot function it works perfectly. Also, I'm cleaning my shadowRam array setting all matrix to zero. variables: #define BLACK 0 #define GREEN 1 #define RED 2 #define ORANGE 3 #define CHIP_MAX 8 byte shadowRam[63][CHIP_MAX-1] = {0}; getShadowRam function: byte HT1632C::getShadowRam(byte x, byte y) { byte addr, bitval, nChip; if (x>=32) { nChip = 3 + x/16 + (y>7?2:0); } else { nChip = 1 + x/16 + (y>7?2:0); } bitval = 8>>(y&3); x = x % 16; y = y % 8; addr = (x<<1) + (y>>2); if ((shadowRam[addr][nChip-1] & bitval) && (shadowRam[addr+32][nChip-1] & bitval)) { return ORANGE; } else if (shadowRam[addr][nChip-1] & bitval) { return GREEN; } else if (shadowRam[addr+32][nChip-1] & bitval) { return RED; } else { return BLACK; } } plot function: void HT1632C::plot (int x, int y, int color) { if (x<0 || x>X_MAX || y<0 || y>Y_MAX) return; if (color != BLACK && color != GREEN && color != RED && color != ORANGE) return; char addr, bitval; byte nChip; byte prev_color = HT1632C::getShadowRam(x,y); bitval = 8>>(y&3); if (x>=32) { nChip = 3 + x/16 + (y>7?2:0); } else { nChip = 1 + x/16 + (y>7?2:0); } x = x % 16; y = y % 8; addr = (x<<1) + (y>>2); switch(color) { case BLACK: if (prev_color != BLACK) { // compare with memory to only set if pixel is other color // clear the bit in both planes; shadowRam[addr][nChip-1] &= ~bitval; HT1632C::sendData(nChip, addr, shadowRam[addr][nChip-1]); shadowRam[addr+32][nChip-1] &= ~bitval; HT1632C::sendData(nChip, addr+32, shadowRam[addr+32][nChip-1]); } break; case GREEN: if (prev_color != GREEN) { // compare with memory to only set if pixel is other color // set the bit in the green plane and clear the bit in the red plane; shadowRam[addr][nChip-1] |= bitval; HT1632C::sendData(nChip, addr, shadowRam[addr][nChip-1]); shadowRam[addr+32][nChip-1] &= ~bitval; HT1632C::sendData(nChip, addr+32, shadowRam[addr+32][nChip-1]); } break; case RED: if (prev_color != RED) { // compare with memory to only set if pixel is other color // clear the bit in green plane and set the bit in the red plane; shadowRam[addr][nChip-1] &= ~bitval; HT1632C::sendData(nChip, addr, shadowRam[addr][nChip-1]); shadowRam[addr+32][nChip-1] |= bitval; HT1632C::sendData(nChip, addr+32, shadowRam[addr+32][nChip-1]); } break; case ORANGE: if (prev_color != ORANGE) { // compare with memory to only set if pixel is other color // set the bit in both the green and red planes; shadowRam[addr][nChip-1] |= bitval; HT1632C::sendData(nChip, addr, shadowRam[addr][nChip-1]); shadowRam[addr+32][nChip-1] |= bitval; HT1632C::sendData(nChip, addr+32, shadowRam[addr+32][nChip-1]); } break; } } If helps: The datasheet of board I'm using. On page 7 has the memory mapping I'm using. Also, I have a video of display working.

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• jquery problem with simple code

  - by moustafa

  why this code is not working var name = $("#name").val(); var email = $("#email").val(); var web = $("#web").val(); var comment = $("#comment").val(); if(name.length < 5){ $("#name").css("border-color","red"); } elseif (email.length < 5) { $("#email").css("border-color","red"); } elseif (web.length < 5) { $("#web").css("border-color","red"); } elseif (comment.length < 10) { $("#comment").css("border-color","red"); }else{ alert('ok'); } and each val for one like this <input id="name" type="text" size="24" />

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• Single Column Multiple Filter In Mysql Intersection

  - by Jeebus

  Here is a table CarID| Attribute | Value 1 | Color | Red 2 | Color | Blue 3 | Color | Red 1 | Type | Coupe 2 | Type | Hatch Back 3 | Type | Coupe 3 | Make | Honda 2 | Make | Toyota 1 | Make | Ford Now I would like to run a filter Like Select * From Cars WHERE (Attribute = Color AND Value = Red) AND (Attribute = Make AND Value = Honda).... and Hope to get the CarID as 3 ! This is simple case of Intersection of 2 queries but I don't know how to get it done in a single query. Any help appriciated.

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