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  • CSS - Class hierarchies???

    - by ClarkeyBoy
    Hi, I have a site with a customer front end, which has a catalogue, homepage, contact page, about us page and so on. There is also an administration front end. I would like to implement a kind of hierarchy where any elements within an element with class "admin" will inherit properties set in the admin stylesheet and anything else inherits from the customer stylesheet. The purpose of this is so that admin can login on the admin front end, where they have access to lots of advanced stuff, but they can also navigate to the customer front end where they can execute basic tasks (such as hiding catalogue items, running a debug script if a customer reports an issue and so on). I would like all the admin tools on the customer front end to have properties taken from the admin stylesheet instead of the customer one - this will change the background colour and stuff. Is there any easy way to set up like namespaces to make things simpler, for example: .admin { .list { .list-subtitle { } .list-item { } } a { } } .customer { .list { .list-subtitle { } .list-item { } } a { } } I know it can be like: .admin .list {} .admin .list .list-item {} .admin a I just dont want to have to keep putting .admin all the time. Does anyone have any suggestions on how I could do this? I suppose I could write a .net class which sets this up and writes a stylesheet according to whats put into it, but then I would not be able to read the styles so easily add there would be all sorts of like Classes.Add(blah) and so on. Thanks in advance for any replies... Regards, Richard

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  • kohana project structure

    - by user176217
    Hello Guys. I'm investigating using Kohana for my next project. The site will consist of user registration (and hence user profiles) where users will have certain privileges. The site will also have an admin section where administrators can go to say block a user or delete a post or look at usage statistics for example. A good comparison site would be a multi-user blog, where each blogger depending on her/his permissions can post/edit/delete blogs...just as an example. Firstly, I'm not sure about how to set up the controller/view structure in order to separate the admin section from the front facing site. I'm using Kohana 3, so I was thinking of a controller structure like so: application/classes/controller/front (front facing)...and application/classes/controller/admin (for administrative section). Or I notice you may be able to use the Route class to set up routes, so I could set up an "admin" route. for example: www.example.com/admin will lead to the admin logon screen. www.example.com --- front controller. As well, can I somehow separate the "Admin" views and controllers from the "front facing" views and controllers like divide them up based on folder structure? Any help is very much appreciated. Thank you.

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  • Trouble with pointers and references in C++

    - by KingNestor
    I have a PolygonList and a Polygon type, which are std::lists of Points or lists of lists of points. class Point { public: int x, y; Point(int x1, int y1) { x = x1; y = y1; } }; typedef std::list<Point> Polygon; typedef std::list<Polygon> PolygonList; // List of all our polygons PolygonList polygonList; However, I'm confused on reference variables and pointers. For example, I would like to be able to reference the first Polygon in my polygonList, and push a new Point to it. So I attempted to set the front of the polygonList to a Polygon called currentPolygon like so: Polygon currentPolygon = polygonList.front(); currentPolygon.push_front(somePoint); and now, I can add points to currentPolygon, but these changes end up not being reflected in that same polygon in the polygonList. Is currentPolygon simply a copy of the Polygon in the front of polygonList? When I later iterate over polygonList all the points I've added to currentPolygon aren't shown. It works if I do this: polygonList.front().push_front(somePoint); Why aren't these the same and how can I create a reference to the physical front polygon rather than a copy of it?

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  • Converting "A* Search" code from C++ to Java [on hold]

    - by mr5
    Updated! I get this code from this site It's A* Search Algorithm(finding shortest path with heuristics) I modify most of variable names and some if conditions from the original version to satisfy my syntactic taste. It works in C++ (as I can't see any trouble with it) but fails in Java version. Java Code: String findPath(int startX, int startY, int finishX, int finishY) { @SuppressWarnings("unchecked") LinkedList<Node>[] nodeList = (LinkedList<Node>[]) new LinkedList<?>[2]; nodeList[0] = new LinkedList<Node>(); nodeList[1] = new LinkedList<Node>(); Node n0; Node m0; int nlIndex = 0; // queueList index // reset the node maps for(int y = 0;y < ROW_COUNT; ++y) { for(int x = 0;x < COL_COUNT; ++x) { close_nodes_map[y][x] = 0; open_nodes_map[y][x] = 0; } } // create the start node and push into list of open nodes n0 = new Node( startX, startY, 0, 0 ); n0.updatePriority( finishX, finishY ); nodeList[nlIndex].push( n0 ); open_nodes_map[startY][startX] = n0.getPriority(); // mark it on the open nodes map // A* search while( !nodeList[nlIndex].isEmpty() ) { LinkedList<Node> pq = nodeList[nlIndex]; // get the current node w/ the highest priority // from the list of open nodes n0 = new Node( pq.peek().getX(), pq.peek().getY(), pq.peek().getIterCount(), pq.peek().getPriority()); int x = n0.getX(); int y = n0.getY(); nodeList[nlIndex].pop(); // remove the node from the open list open_nodes_map[y][x] = 0; // mark it on the closed nodes map close_nodes_map[y][x] = 1; // quit searching when the goal state is reached //if((*n0).estimate(finishX, finishY) == 0) if( x == finishX && y == finishY ) { // generate the path from finish to start // by following the directions String path = ""; while( !( x == startX && y == startY) ) { int j = dir_map[y][x]; int c = '0' + ( j + Node.DIRECTION_COUNT / 2 ) % Node.DIRECTION_COUNT; path = (char)c + path; x += DIR_X[j]; y += DIR_Y[j]; } return path; } // generate moves (child nodes) in all possible directions for(int i = 0; i < Node.DIRECTION_COUNT; ++i) { int xdx = x + DIR_X[i]; int ydy = y + DIR_Y[i]; // boundary check if (!(xdx >= 0 && xdx < COL_COUNT && ydy >= 0 && ydy < ROW_COUNT)) continue; if ( ( gridMap.getData( ydy, xdx ) == GridMap.WALKABLE || gridMap.getData( ydy, xdx ) == GridMap.FINISH) && close_nodes_map[ydy][xdx] != 1 ) { // generate a child node m0 = new Node( xdx, ydy, n0.getIterCount(), n0.getPriority() ); m0.nextLevel( i ); m0.updatePriority( finishX, finishY ); // if it is not in the open list then add into that if( open_nodes_map[ydy][xdx] == 0 ) { open_nodes_map[ydy][xdx] = m0.getPriority(); nodeList[nlIndex].push( m0 ); // mark its parent node direction dir_map[ydy][xdx] = ( i + Node.DIRECTION_COUNT / 2 ) % Node.DIRECTION_COUNT; } else if( open_nodes_map[ydy][xdx] > m0.getPriority() ) { // update the priority info open_nodes_map[ydy][xdx] = m0.getPriority(); // update the parent direction info dir_map[ydy][xdx] = ( i + Node.DIRECTION_COUNT / 2 ) % Node.DIRECTION_COUNT; // replace the node // by emptying one queueList to the other one // except the node to be replaced will be ignored // and the new node will be pushed in instead while( !(nodeList[nlIndex].peek().getX() == xdx && nodeList[nlIndex].peek().getY() == ydy ) ) { nodeList[1 - nlIndex].push( nodeList[nlIndex].pop() ); } nodeList[nlIndex].pop(); // remove the wanted node // empty the larger size queueList to the smaller one if( nodeList[nlIndex].size() > nodeList[ 1 - nlIndex ].size() ) nlIndex = 1 - nlIndex; while( !nodeList[nlIndex].isEmpty() ) { nodeList[1 - nlIndex].push( nodeList[nlIndex].pop() ); } nlIndex = 1 - nlIndex; nodeList[nlIndex].push( m0 ); // add the better node instead } } } } return ""; // no route found } Output1: Legends . = PATH ? = START X = FINISH 3,2,1 = OBSTACLES (Misleading path) Output2: Changing these lines: n0 = new Node( a, b, c, d ); m0 = new Node( e, f, g, h ); to n0.set( a, b, c, d ); m0.set( e, f, g, h ); I get (I'm really confused) C++ Code: std::string A_Star::findPath(int startX, int startY, int finishX, int finishY) { typedef std::queue<Node> List_Container; List_Container nodeList[2]; // list of open (not-yet-tried) nodes Node n0; Node m0; int pqIndex = 0; // nodeList index // reset the node maps for(int y = 0;y < ROW_COUNT; ++y) { for(int x = 0;x < COL_COUNT; ++x) { close_nodes_map[y][x] = 0; open_nodes_map[y][x] = 0; } } // create the start node and push into list of open nodes n0 = Node( startX, startY, 0, 0 ); n0.updatePriority( finishX, finishY ); nodeList[pqIndex].push( n0 ); open_nodes_map[startY][startX] = n0.getPriority(); // mark it on the open nodes map // A* search while( !nodeList[pqIndex].empty() ) { List_Container &pq = nodeList[pqIndex]; // get the current node w/ the highest priority // from the list of open nodes n0 = Node( pq.front().getX(), pq.front().getY(), pq.front().getIterCount(), pq.front().getPriority()); int x = n0.getX(); int y = n0.getY(); nodeList[pqIndex].pop(); // remove the node from the open list open_nodes_map[y][x] = 0; // mark it on the closed nodes map close_nodes_map[y][x] = 1; // quit searching when the goal state is reached //if((*n0).estimate(finishX, finishY) == 0) if( x == finishX && y == finishY ) { // generate the path from finish to start // by following the directions std::string path = ""; while( !( x == startX && y == startY) ) { int j = dir_map[y][x]; char c = '0' + ( j + DIRECTION_COUNT / 2 ) % DIRECTION_COUNT; path = c + path; x += DIR_X[j]; y += DIR_Y[j]; } return path; } // generate moves (child nodes) in all possible directions for(int i = 0; i < DIRECTION_COUNT; ++i) { int xdx = x + DIR_X[i]; int ydy = y + DIR_Y[i]; // boundary check if (!( xdx >= 0 && xdx < COL_COUNT && ydy >= 0 && ydy < ROW_COUNT)) continue; if ( ( pGrid->getData(ydy,xdx) == WALKABLE || pGrid->getData(ydy, xdx) == FINISH) && close_nodes_map[ydy][xdx] != 1 ) { // generate a child node m0 = Node( xdx, ydy, n0.getIterCount(), n0.getPriority() ); m0.nextLevel( i ); m0.updatePriority( finishX, finishY ); // if it is not in the open list then add into that if( open_nodes_map[ydy][xdx] == 0 ) { open_nodes_map[ydy][xdx] = m0.getPriority(); nodeList[pqIndex].push( m0 ); // mark its parent node direction dir_map[ydy][xdx] = ( i + DIRECTION_COUNT / 2 ) % DIRECTION_COUNT; } else if( open_nodes_map[ydy][xdx] > m0.getPriority() ) { // update the priority info open_nodes_map[ydy][xdx] = m0.getPriority(); // update the parent direction info dir_map[ydy][xdx] = ( i + DIRECTION_COUNT / 2 ) % DIRECTION_COUNT; // replace the node // by emptying one nodeList to the other one // except the node to be replaced will be ignored // and the new node will be pushed in instead while ( !( nodeList[pqIndex].front().getX() == xdx && nodeList[pqIndex].front().getY() == ydy ) ) { nodeList[1 - pqIndex].push( nodeList[pqIndex].front() ); nodeList[pqIndex].pop(); } nodeList[pqIndex].pop(); // remove the wanted node // empty the larger size nodeList to the smaller one if( nodeList[pqIndex].size() > nodeList[ 1 - pqIndex ].size() ) pqIndex = 1 - pqIndex; while( !nodeList[pqIndex].empty() ) { nodeList[1-pqIndex].push(nodeList[pqIndex].front()); nodeList[pqIndex].pop(); } pqIndex = 1 - pqIndex; nodeList[pqIndex].push( m0 ); // add the better node instead } } } } return ""; // no route found } Output: Legends . = PATH ? = START X = FINISH 3,2,1 = OBSTACLES (Just right) From what I read about Java's documentation, I came up with the conclusion: C++'s std::queue<T>::front() == Java's LinkedList<T>.peek() Java's LinkedList<T>.pop() == C++'s std::queue<T>::front() + std::queue<T>::pop() What might I be missing in my Java version? In what way does it became different algorithmically from the C++ version?

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  • What are some practical uses of generating all permutations of a list, such as ['a', 'b', 'c'] ?

    - by Jian Lin
    I was asked by somebody in an interview for web front end job, to write a function that generates all permutation of a string, such as "abc" (or consider it ['a', 'b', 'c']). so the expected result from the function, when given ['a', 'b', 'c'], is abc acb bac bca cab cba Actually in my past 20 years of career, I have never needed to do something like that, especially when doing front end work for web programming. What are some practical use of this problem nowadays, in web programming, front end or back end, I wonder? As a side note, I kind of feel that expecting a result in 3 minutes might be "either he gets it or he doesn't", especially I was thinking of doing it by a procedural, non-recursive way at first. After the interview, I spent another 10 minutes and thought of how to do it using recursion, but expecting it to be solved within 3 minutes... may not be a good test of how qualified he is, especially for front end work.

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  • Mistake in display and insert methods (double-ended queue)

    - by MANAL
    1) My problem when i make remove from right or left program will be remove true but when i call diplay method the content wrong like this I insert 12 43 65 23 and when make remove from left program will remove 12 but when call display method show like this 12 43 65 and when make remove from right program will remove 23 but when call display method show like this 12 43 Why ?????? ); and when i try to make insert after remove write this Can not insert right because the queue is full . first remove right and then u can insert right where is the problem ?? Please Help me please 2) My code FIRST CLASS class dqueue { private int fullsize; //number of all cells private int item_num; // number of busy cells only private int front,rear; public int j; private double [] dqarr; //========================================== public dqueue(int s) //constructor { fullsize = s; front = 0; rear = -1; item_num = 0; dqarr = new double[fullsize]; } //========================================== public void insert(double data) { if (rear == fullsize-1) rear = -1; rear++; dqarr[rear] = data; item_num++; } public double removeLeft() // take item from front of queue { double temp = dqarr[front++]; // get value and incr front if(front == fullsize) front = 0; item_num --; // one less item return temp; } public double removeRight() // take item from rear of queue { double temp = dqarr[rear--]; // get value and decr rear if(rear == -1) // rear = item_num -1; item_num --; // one less item return temp; } //========================================= public void display () //display items { for (int j=0;j<item_num;j++) // for every element System.out.print(dqarr[j] +" " ); // display it System.out.println(""); } //========================================= public int size() //number of items in queue { return item_num; } //========================================== public boolean isEmpty() // true if queue is empty { return (item_num ==0); } } SECOND CLASS import java.util.Scanner; class dqueuetest { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.println(" ***** Welcome here***** "); System.out.println(" ***** Mind Of Programming Group***** "); System.out.println(" _____________________________________________ "); System.out.println("enter size of your dqueue"); int size = input.nextInt(); dqueue mydq = new dqueue(size); System.out.println(""); System.out.println("enter your itemes"); //===================================== for(int i = 0;i<=size-1;i++) { System.out.printf("item %d:",i+1); double item = input.nextDouble(); mydq.insert(item); System.out.println(""); } //===================================== int queue =size ; int c = 0 ; while (c != 6) { System.out.println(""); System.out.println("************************************************"); System.out.println(" MAIN MENUE"); System.out.println("1- INSERT RIGHT "); System.out.println("2- REMOVE LEFT"); System.out.println("3- REMOVE RIGHT"); System.out.println("4- DISPLAY"); System.out.println("5- SIZE"); System.out.println("6- EXIT"); System.out.println("************************************************"); System.out.println("choose your operation by number(1-6)"); c = input.nextInt(); switch (c) { case 1: if (queue == size) System.out.print("Can not insert right because the queue is full . first remove right and then u can insert right "); else { System.out.print("enter your item: "); double item = input.nextDouble(); mydq.insert(item);} break; case 2: System.out.println("REMOVE FROM REAR :"); if( !mydq.isEmpty() ) { double item = mydq.removeLeft(); System.out.print(item + "\t"); } // end while System.out.println(""); mydq.display(); break; case 3: System.out.println("REMOVE FROM FRONT :"); if( !mydq.isEmpty() ) { double item = mydq.removeRight(); System.out.print(item + "\t"); } // end while System.out.println(""); mydq.display(); break; case 4: System.out.println("The items in Queue are :"); mydq.display(); break; case 5: System.out.println("The Size of the Queue is :"+mydq.size()); break; case 6: System.out.println("Good Bye"); break; default: System.out.println("wrong chiose enter again"); } //end switch } //end while } // end main }//end class

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  • Mistake in dispaly and insert method (double - ended queue)

    - by MANAL
    1) My problem when i make remove from right or left program will be remove true but when i call diplay method the content wrong like this I insert 12 43 65 23 and when make remove from left program will remove 12 but when call display method show like this 12 43 65 and when make remove from right program will remove 23 but when call display method show like this 12 43 Why ?????? ); and when i try to make insert after remove write this Can not insert right because the queue is full . first remove right and then u can insert right where is the problem ?? Please Help me please 2) My code FIRST CLASS class dqueue { private int fullsize; //number of all cells private int item_num; // number of busy cells only private int front,rear; public int j; private double [] dqarr; //========================================== public dqueue(int s) //constructor { fullsize = s; front = 0; rear = -1; item_num = 0; dqarr = new double[fullsize]; } //========================================== public void insert(double data) { if (rear == fullsize-1) rear = -1; rear++; dqarr[rear] = data; item_num++; } public double removeLeft() // take item from front of queue { double temp = dqarr[front++]; // get value and incr front if(front == fullsize) front = 0; item_num --; // one less item return temp; } public double removeRight() // take item from rear of queue { double temp = dqarr[rear--]; // get value and decr rear if(rear == -1) // rear = item_num -1; item_num --; // one less item return temp; } //========================================= public void display () //display items { for (int j=0;j //========================================= public int size() //number of items in queue { return item_num; } //========================================== public boolean isEmpty() // true if queue is empty { return (item_num ==0); } } SECOND CLASS import java.util.Scanner; class dqueuetest { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.println(" Welcome here** "); System.out.println(" * Mind Of Programming Group*** "); System.out.println(" _________________________ "); System.out.println("enter size of your dqueue"); int size = input.nextInt(); dqueue mydq = new dqueue(size); System.out.println(""); System.out.println("enter your itemes"); //===================================== for(int i = 0;i<=size-1;i++) { System.out.printf("item %d:",i+1); double item = input.nextDouble(); mydq.insert(item); System.out.println(""); } //===================================== int queue =size ; int c = 0 ; while (c != 6) { System.out.println(""); System.out.println("**************************"); System.out.println(" MAIN MENUE"); System.out.println("1- INSERT RIGHT "); System.out.println("2- REMOVE LEFT"); System.out.println("3- REMOVE RIGHT"); System.out.println("4- DISPLAY"); System.out.println("5- SIZE"); System.out.println("6- EXIT"); System.out.println("**************************"); System.out.println("choose your operation by number(1-6)"); c = input.nextInt(); switch (c) { case 1: if (queue == size) System.out.print("Can not insert right because the queue is full . first remove right and then u can insert right "); else { System.out.print("enter your item: "); double item = input.nextDouble(); mydq.insert(item);} break; case 2: System.out.println("REMOVE FROM REAR :"); if( !mydq.isEmpty() ) { double item = mydq.removeLeft(); System.out.print(item + "\t"); } // end while System.out.println(""); mydq.display(); break; case 3: System.out.println("REMOVE FROM FRONT :"); if( !mydq.isEmpty() ) { double item = mydq.removeRight(); System.out.print(item + "\t"); } // end while System.out.println(""); mydq.display(); break; case 4: System.out.println("The items in Queue are :"); mydq.display(); break; case 5: System.out.println("The Size of the Queue is :"+mydq.size()); break; case 6: System.out.println("Good Bye"); break; default: System.out.println("wrong chiose enter again"); } //end switch } //end while } // end main }//end class

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  • So, I guess I can't use "&&" in the Python if conditional. What should I use in this case? Any help?

    - by Sergio Tapia
    Here's my code: # F. front_back # Consider dividing a string into two halves. # If the length is even, the front and back halves are the same length. # If the length is odd, we'll say that the extra char goes in the front half. # e.g. 'abcde', the front half is 'abc', the back half 'de'. # Given 2 strings, a and b, return a string of the form # a-front + b-front + a-back + b-back def front_back(a, b): # +++your code here+++ if len(a) % 2 == 0 && len(b) % 2 == 0: return a[:(len(a)/2)] + b[:(len(b)/2)] + a[(len(a)/2):] + b[(len(b)/2):] else: #todo! Not yet done. :P return I'm getting an error in the IF conditional. What am I doing wrong? Edit: I meant no arrogance here. Someone edited my question title to make it sound douchy. I was genuinely confused about what to use, didn't think 'and' would be a keyword. Please don't downvote as other newbies might be confused about it as well.

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  • Display cube when overlapped?

    - by lptrung
    Hi all! I have a problem when run animation with three.j. See example: http://jsfiddle.net/5ywdE/13/ When the green cube is rotated to position of the blue cube, the red cube will be rotated. Question: why is the blue cube displayed while the green blue is in front of it. I want the green cube is displayed in front of the blue cube (like so the red cube is displayed in front of all). Can I set the cube which will be displayed in front of other cube in case of overlapped? What am I doing wrong?? Thanks in advance

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  • making a queue program

    - by seventhief
    Hi can someone help me making a queue program. i want to set the array[0] to be array[1] just in display but in real i am adding value at array[0]. i got how to run the add function to it. but i can't do the view and delete command that will view from ex. array[0] to array[4], when displayed array[1] to array[5] with the value inserted. #include <stdio.h> #include <stdlib.h> #define p printf #define s scanf int rear = 0; int front = 0; int *q_array = NULL; int size = 0; main() { int num, opt; char cont[] = { 'y' }; clrscr(); p("Queue Program\n\n"); p("Queue size: "); s("%d", &size); p("\n"); if(size > 0) { q_array = malloc(size * sizeof(int)); if(q_array == NULL) { p("ERROR: malloc() failed\n"); exit(2); } } else { p("ERROR: size should be positive integer\n"); exit(1); } while((cont[0] == 'y') || (cont[0] == 'Y')) { clrscr(); p("Queue Program"); p("\n\nQueue size: %d\n\n", size); p("MAIN MENU\n1. Add\n2. Delete\n3. View"); p("\n\nYour choice: "); s("%d", &opt); p("\n"); switch(opt) { case 1: if(rear==size) { p("You can't add more data"); } else { p("Enter data for Queue[%d]: ", rear+1); s("%d", &num); add(num); } break; case 2: delt(); break; case 3: view(); break; } p("\n\nDo you want to continue? (Y\/N)"); s("%s", &cont[0]); } } add(int a) { q_array[rear]=a; rear++; } delt() { if(front==rear) { p("Queue Empty"); } else { p("Queue[%d] = %d removed.", front, q_array[front]); front++; } } view() { int i; for(i=front;i<=rear;i++) p("\nQueue[%d] = %d", i, q_array[i]); }

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  • Silverlight Cream for December 18, 2010 -- #1012

    - by Dave Campbell
    In this Issue: Mark Monster, Kevin Dockx, Jeremy Likness(-2-,-3-), Timmy Kokke, Den Delimarsky, Mike Snow, Samuel Jack(-2-), and Renuka Prasad(-2-). Above the Fold: Silverlight: "Trigger a Storyboard on ViewModel changes" Mark Monster WP7: "Microsoft Push Notification in Windows Phone 7" Renuka Prasad Shoutouts: SilverlightGal sent me the link to The Silverlight Dossier ... I think it's a pretty good start... additions I'd like to see are ways to submit to the various areas. Michael Crump put up a contest that runs from now to January 1st... Win a set of Infragistics Silverlight Controls with Data Visualization!... pretty cool, Michael! If you visit WynApse.com, you'll see I have a subscription to LearnVisualStudio.net... and now they have posted a batch of WP7 videos... 64 of them to be exact... wow!: New video series From SilverlightCream.com: Trigger a Storyboard on ViewModel changes Mark Monster has a great post up about triggering Storyboard on ViewModel changes using the DataTrigger from Blend... cool stuff, and you can also do GoToStateAction or other actions or build yourowndang Trigger Action... fun awaits! ... sorry it took a while to post, Mark... been a tad overloaded here! Working with the Silverlight Rich Text Box control Kevin Dockx has had a post up for a while at SilverlightShow where he takes a good look at the RichText control and it's various capabilities, including source so you can give it a dance yourself. Lessons Learned in Personal Web Page Part 3: Custom Panel and Listbox Jeremy Likness's part 3 of his Personal Web Page lessons learned is covering the tres-cool 3D Panel he did... and he's got it all explained out... building from scratch via a custom panel and a Listbox control... A Silverlight MVVM Feed Reader from Scratch in 30 Minutes Jeremy Likness has a video tutorial showing building an MVVM/Silverlight feedreader in 30 minutes ... plus a couple mods that he noticed after the fact... beat that HTML5 :) Jounce Part 8: Raising Property Changed In Jeremy Likness's latest post, he has number 8 in his series on his MVVM platform, Jounce. This time he's explaining the property changed notification, has a very cool way of doing it, and some interesting comments from readers. Dependency Injection, MVVM, Ninject and Silverlight Timmy Kokke has a great tutorial up with associated demo project on Dependency Injection in MVVM and Silverlight. Some hidden features in the Windows Phone 7 emulator Den Delimarsky shows how to get some of the hidden features on your WP7 emulator like the Call History, Call Settings, and Details about the numbers. Playing sound effects on Windows Phone 7 Mike Snow's latest tip is playing sound effects on your WP7 ... a little bit of XNA here and there, and badabing, badaboom, you got sound! Day 3 of my “Build a Windows Phone 7 game in 3 days” Challenge Samuel Jack has a couple more posts up about his 'Build a WP7 game in 3 Days' challenge... first up is Day 3 from 8:50 to 22:30 ... wow... long day! ... but he's got something good going now... some good external links also Day 3.5 of my “Build a Windows Phone 7 game in 3 days” Challenge Samuel Jack's 3rd day ended with another half-day added on to put on some finishing touches... again, some good external links... and he finished with this Say hello to Simon Squared, my 3.5 day old WP7 Game Microsoft Push Notification in Windows Phone 7 Renuka Prasad has a bunch of material up that I've not been aware of (how did that happen, people??) ... here's the first of a couple of his posts on Code Project ... a very nice tutorial on the Push Notification process... great diagrams and external links. Windows Phone 7 – Toast Notification Using Windows Azure Cloud Service Renuka Prasad has another WP7 post on CodeProject... this one on Toast Notification... and he's using Azure and WCF all rolled into it as well... great diagrams, descriptions and all the code. Stay in the 'Light! Twitter SilverlightNews | Twitter WynApse | WynApse.com | Tagged Posts | SilverlightCream Join me @ SilverlightCream | Phoenix Silverlight User Group Technorati Tags: Silverlight    Silverlight 3    Silverlight 4    Windows Phone MIX10

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  • Shared secret length limit on OSX VPN client

    - by Samuel
    I'm trying to setup the built-in VPN client with OS X. The settings I'm using (IPsec GW, shared secret, etc...) work flawlessly using other clients (IPsecuritas, vpnc, etc...) but isn't working with the built-in client. The error I get is: Wrong shared secret (not the exact message, since OS X is localized) The shared secret is 128 chars long so I'm wondering if it's hitting a length limit. I would like to know if that's true, and if so, how I could overcome it?

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  • "Add correct host key in known_hosts" / multiple ssh host keys per hostname?

    - by Samuel Edwin Ward
    Trying to ssh into a computer I control, I'm getting the familiar message: @@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@ @ WARNING: REMOTE HOST IDENTIFICATION HAS CHANGED! @ @@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@ IT IS POSSIBLE THAT SOMEONE IS DOING SOMETHING NASTY! Someone could be eavesdropping on you right now (man-in-the-middle attack)! It is also possible that a host key has just been changed. The fingerprint for the RSA key sent by the remote host is [...]. Please contact your system administrator. Add correct host key in /home/sward/.ssh/known_hosts to get rid of this message. Offending RSA key in /home/sward/.ssh/known_hosts:86 RSA host key for [...] has changed and you have requested strict checking. Host key verification failed. I did indeed change the key. And I read a few dozen postings saying that the way to resolve this problem is by deleting the old key from the known_hosts file. But what I would like is to have ssh accept both the old key and the new key. The language in the error message ("Add correct host key") suggests that there should be some way to add the correct host key without removing the old one. I have not been able to figure out how to add the new host key without removing the old one. Is this possible, or is the error message just extremely misleading?

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  • INFORMIX - listener thread err 25582

    - by Samuel Lao
    I´ve been digging different forums in the last 7 days looking for a possible solution.... Our database is based on informix running in a Linux server (LINUX SUSE 11). Suddenly, last saturday informix began to show an error message: listener-thread err=-25582 oserr=0, network connection is broken End users started to call reporting about slow network performance to this server, moments where the database application lost connection with server...so we proceeded doing a ping to the db server, getting good responses (1ms) without losing packets. I tried typing telnet (ipserver) 1526 which is informix's port for the application, it works. We had to disconnect the server and enable a backup db server which is located on another branch. It has been working in a regular way because the backup server hasn´t good specs (it is an old dell server model). So, I scanned the main server looking for viruses using Trend Micro Server Protect, it didn´t find anything (0 viruses and spywares). I revised the switches and routers, but I haven´t find anything strange... What else could be ? Thanks in advanced for your time and help with this issue.....I would really appreciate any advice...

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  • Trying to use Nginx try_files to emulate Apache MultiViews

    - by Samuel Bierwagen
    I want a request to http://example.com/foobar to return http://example.com/foobar.jpg. (Or .gif, .html, .whatever) This is trivial to do with Apache MultiViews, and it seems like it would be equally easy in Nginx. This question seems to imply that it'd be easy as try_files $uri $uri/ index.php; in the location block, but that doesn't work. try_files $uri $uri/ =404; doesn't work, nor does try_files $uri =404; or try_files $uri.* =404; Moving it between my location / { block and the regexp which matches images has no effect. Crucially, try_files $uri.jpg =404; does work, but only for .jpg files, and it throws a configuration error if I use more than one try_files rule in a location block! The current server { block: server { listen 80; server_name example.org www.example.org; access_log /var/log/nginx/vhosts.access.log; root /srv/www/vhosts/example; location / { root /srv/www/vhosts/example; } location ~* \.(?:ico|css|js|gif|jpe?g|es|png)$ { expires max; add_header Cache-Control public; try_files $uri =404; } } Nginx version is 1.1.14.

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  • UnicodeEncodeError when uploading files in Django admin

    - by Samuel Linde
    Note: I asked this question on StackOverflow, but I realize this might be a more proper place to ask this kind of question. I'm trying to upload a file called 'Testaråäö.txt' via the Django admin app. I'm running Django 1.3.1 with Gunicorn 0.13.4 and Nginx 0.7.6.7 on a Debian 6 server. Database is PostgreSQL 8.4.9. Other Unicode data is saved to the database with no problem, so I guess the problem must be with the filesystem somehow. I've set http { charset utf-8; } in my nginx.conf. LC_ALL and LANG is set to 'sv_SE.UTF-8'. Running 'locale' verifies this. I even tried setting LC_ALL and LANG in my nginx init script just to make sure locale is set properly. Here's the traceback: Traceback (most recent call last): File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/core/handlers/base.py", line 111, in get_response response = callback(request, *callback_args, **callback_kwargs) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/contrib/admin/options.py", line 307, in wrapper return self.admin_site.admin_view(view)(*args, **kwargs) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/utils/decorators.py", line 93, in _wrapped_view response = view_func(request, *args, **kwargs) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/views/decorators/cache.py", line 79, in _wrapped_view_func response = view_func(request, *args, **kwargs) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/contrib/admin/sites.py", line 197, in inner return view(request, *args, **kwargs) File "/srv/django/letebo/app/cms/admin.py", line 81, in change_view return super(PageAdmin, self).change_view(request, obj_id) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/utils/decorators.py", line 28, in _wrapper return bound_func(*args, **kwargs) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/utils/decorators.py", line 93, in _wrapped_view response = view_func(request, *args, **kwargs) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/utils/decorators.py", line 24, in bound_func return func(self, *args2, **kwargs2) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/db/transaction.py", line 217, in inner res = func(*args, **kwargs) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/contrib/admin/options.py", line 985, in change_view self.save_formset(request, form, formset, change=True) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/contrib/admin/options.py", line 677, in save_formset formset.save() File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/forms/models.py", line 482, in save return self.save_existing_objects(commit) + self.save_new_objects(commit) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/forms/models.py", line 613, in save_new_objects self.new_objects.append(self.save_new(form, commit=commit)) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/forms/models.py", line 717, in save_new obj.save() File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/db/models/base.py", line 460, in save self.save_base(using=using, force_insert=force_insert, force_update=force_update) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/db/models/base.py", line 504, in save_base self.save_base(cls=parent, origin=org, using=using) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/db/models/base.py", line 543, in save_base for f in meta.local_fields if not isinstance(f, AutoField)] File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/db/models/fields/files.py", line 255, in pre_save file.save(file.name, file, save=False) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/db/models/fields/files.py", line 92, in save self.name = self.storage.save(name, content) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/core/files/storage.py", line 48, in save name = self.get_available_name(name) File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/core/files/storage.py", line 74, in get_available_name while self.exists(name): File "/srv/.virtualenvs/letebo/lib/python2.6/site-packages/django/core/files/storage.py", line 218, in exists return os.path.exists(self.path(name)) File "/srv/.virtualenvs/letebo/lib/python2.6/genericpath.py", line 18, in exists st = os.stat(path) UnicodeEncodeError: 'ascii' codec can't encode characters in position 52-54: ordinal not in range(128) I tried running Gunicorn with debugging turned on, and the file uploads without any problem at all. I suppose this must mean that the issue is with Nginx. Still beats me where to look, though. Here are the raw response headers from Gunicorn and Nginx, if it makes any sense: Gunicorn: HTTP/1.1 302 FOUND Server: gunicorn/0.13.4 Date: Thu, 09 Feb 2012 14:50:27 GMT Connection: close Transfer-Encoding: chunked Expires: Thu, 09 Feb 2012 14:50:27 GMT Vary: Cookie Last-Modified: Thu, 09 Feb 2012 14:50:27 GMT Location: http://my-server.se:8000/admin/cms/page/15/ Cache-Control: max-age=0 Content-Type: text/html; charset=utf-8 Set-Cookie: messages="yada yada yada"; Path=/ Nginx: HTTP/1.1 500 INTERNAL SERVER ERROR Server: nginx/0.7.67 Date: Thu, 09 Feb 2012 14:50:57 GMT Content-Type: text/html; charset=utf-8 Transfer-Encoding: chunked Connection: close Vary: Cookie 500 UPDATE: Both locale.getpreferredencoding() and sys.getfilesystemencoding() outputs 'UTF-8'. locale.getdefaultlocale() outputs ('sv_SE', 'UTF8'). This seem correct to me, so I'm still not sure why I keep getting these errors.

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  • Windows 2012 Server Hyper-V: Cannot see LAN

    - by Samuel
    I have one NIC on the machine loaded XP on the Hyper-V and had chosen the network as virtual switch. No LAN and no internet shows up on the client. Am I missing something? it used to work in 2008-R2. Details: One network card on machine (Qualcomm Atheros AR8131 PIC-E Gigabit Ethernet controller) The virtual machine hard disk is pointing to and existing XP-SP2 hard disk created using VPC 2007 The Virtual machine Network Adapter is setup as Virtual Switch to the real ethernet controller with Enable virtual LAN identification set to 2 (no other virtual machine is created in the system) After the virtual machine boots LAN shows empty in Control Panel Network Connections (this is XP client) and I also cannot access the internet. XP is showing activation prompt but as far as I know it should not disable the network! Virtual network switch is set to External

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  • Preserving CDATA Editing Xml File using Microsoft Word 2003

    - by Samuel
    I have an xml file that I need to edit using Microsoft Word 2003. Everything works fine but the CDATA section is lost and is converted to normal html. For example <Description> <![CDATA[ <i> ]]> </Description> Gets converted to <Description> <i> </Description> Is there any way to preserve the CDATA section while editing in MS Word. I want to fix some typos and grammer in the xml file so I am using this approach. Thanks

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  • How to change the $PATH in Mac OSX

    - by Samuel Elgozi
    I've installed git via the instaler and not with terminal with commands, and my $PATH changed, the path to the 'local' git was added the the end of the variable, and my $PATH changed to this: /usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin:/usr/local/git/bin However, that doesnt help me, because i the path to Xcode's git comes first. so what I've done is the next, I added this lines to my '.bash_profile': export PATH="/usr/local/git/bin:$PATH" and now my path is the next: /usr/local/git/bin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin:/usr/local/git/bin And I wanted to know how to remove the duplication from the end of the Path so I end up with: /usr/local/git/bin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin Thanks Ahead! And sorry if my english is too bad..

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  • Connecting to a remote mysql server from a windows machine (XP)

    - by Samuel Martin
    I am trying to connect to mysql server which is installed on my home pc from another pc. I allowed all connection in mysql configuration. There's no firewall blocking on the pc I am trying to connect from. I used the command- mysql -h Some.Host.IP -u SomeUser -p SomePassword I am getting- ERROR 2003 (HY000): Can't connect to MySQL server on 'Some.Host.IP' (10060) I can connect through php!! What's the problem? How do I solve it?

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  • I am unable to connect to my netbook from any machine on my network until the netbook has pinged it

    - by Samuel Husky
    I have a rather strange issue with my netbook on my local network. When trying to connect to it in any way from a remote system it does not appear to find it. However if I get the netbook to ping the machine trying to connect it mystically appears to work. Below is the ping test from my main PC to the netbook. C:\Users\Sam>ping 192.168.8.102 Pinging 192.168.8.102 with 32 bytes of data: Reply from 192.168.8.100: Destination host unreachable. Reply from 192.168.8.100: Destination host unreachable. Reply from 192.168.8.100: Destination host unreachable. Reply from 192.168.8.100: Destination host unreachable. Ping statistics for 192.168.8.102: Packets: Sent = 4, Received = 4, Lost = 0 (0% loss), Now a ping from the netbook to my main PC sam@malamute ~ $ ping 192.168.8.100 PING 192.168.8.100 (192.168.8.100) 56(84) bytes of data. 64 bytes from 192.168.8.100: icmp_req=1 ttl=128 time=2.46 ms 64 bytes from 192.168.8.100: icmp_req=2 ttl=128 time=0.835 ms 64 bytes from 192.168.8.100: icmp_req=3 ttl=128 time=1.60 ms 64 bytes from 192.168.8.100: icmp_req=4 ttl=128 time=1.32 ms 64 bytes from 192.168.8.100: icmp_req=5 ttl=128 time=1.34 ms ^C --- 192.168.8.100 ping statistics --- 5 packets transmitted, 5 received, 0% packet loss, time 4004ms rtt min/avg/max/mdev = 0.835/1.514/2.460/0.536 ms And the same ping again from the main PC after the netbook has made a connection to it C:\Users\Sam>ping 192.168.8.102 Pinging 192.168.8.102 with 32 bytes of data: Reply from 192.168.8.102: bytes=32 time=1ms TTL=64 Reply from 192.168.8.102: bytes=32 time=1ms TTL=64 Reply from 192.168.8.102: bytes=32 time=1ms TTL=64 Reply from 192.168.8.102: bytes=32 time=1ms TTL=64 Ping statistics for 192.168.8.102: Packets: Sent = 4, Received = 4, Lost = 0 (0% loss), Approximate round trip times in milli-seconds: Minimum = 1ms, Maximum = 1ms, Average = 1ms The netbook is running Gentoo and is currently connected via wireless. My main PC is running Windows 7 however I get the same result no matter what PC I use on this network. Please see this example from a CentOS machine on the same network [root@tiger ~]# ping 192.168.8.102 PING 192.168.8.102 (192.168.8.102) 56(84) bytes of data. From 192.168.8.200 icmp_seq=2 Destination Host Unreachable From 192.168.8.200 icmp_seq=3 Destination Host Unreachable From 192.168.8.200 icmp_seq=4 Destination Host Unreachable --- 192.168.8.102 ping statistics --- 6 packets transmitted, 0 received, +3 errors, 100% packet loss, time 5000ms , pipe 3 If you need any more information or require logs or config files please let me know and any assistance is greatly appreciated. Additional info: No responses on TCP dump from the netbook. Same result when booting into Ubuntu from a USB key. No issue when using a wired Ethernet connection.

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  • Sparing level on HP EVA 4000

    - by Samuel
    One of the disks of our EVA4000 died today. This diskgroup (all volumes vraid5 with sparing level 1 and almost no space left for more volumes, 1TiB drives) is being rebuilt with "spare space" right now, and it will take at least 15 hours to do the leveling/rebuilding. We can't get a new disk until Friday. So, the question is, what would happen if another disk dies before the leveling completes? Would we lose data? And after that, how many aditional disks could die before losing data? 1 or 2? In "usual" RAID, we would be vulnerable to data loss while the rebuild takes place, but in this case the space reserved for sparing is two times the size of the bigger disk, so at the very least the effect should be the same of having two spares. Thanks in advance. Update: I have found some interesting threads about this question but still can't answer to this question, so I'm starting a bounty. http://blog.thestoragearchitect.com/2008/10/27/understanding-eva/ http://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=1&url=http%3A%2F%2Fwww.experts-exchange.com%2FStorage%2FStorage_Technology%2FQ_25548177.html (Expert Exchange question from google).

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