user group - Page 17 - Developer IT

Remove Live ID authentication from user account

- by slugster

I've just run in to a really annoying issue with Windows 8.1 - it seems I cannot remove the need to use Live ID credentials from an account without completely deleting that account. I know the process to do it - use the Disconnect link from the Accounts-Your account screen. The trouble comes when you get to the Switch to a local account screen, it will not let you enter the current account for the user name, instead you must enter a new one thus creating a new user account. Can I revert back to using just a local login without having to recreate the account? It seems quite retarded that I have to recreate the account, as deep down the only change required is which credential provider is used to authenticate the login. (Note that this Live ID linkage was created by using the Windows Store, not as a result of an upgrade from 8 to 8.1).

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non-privileged normal user passing environment variables to /bin/login [closed]

- by AAAAAAAA

Suppose that in FreeBSD (or linux maybe) there is a non-privileged normal user (non-superuser). And there is a telnet standalone (I know that telnet is usually run under inetd) running under (owned by) this user. (Suppose that there was no original, root-owned telnet running.) This telnet server is programmed so that it does not check ld_* environment variables before passing it to /bin/login owned by root that has setuid set up. The question would be: 1. Will this telnet work? 2. If it does work, will it even be able to pass environment variables to /bin/login?

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Cannot schedule task to run under domain user account other than current user

- by Filburt

On our Win 2008 machines I can't schedule tasks for domain users because the domain name does not resolve to network name but the AD dc name. The "network name" looks like ABCDEFGE-HIJKLM and the "dc" / "name" would look like ABCDEFGE-HIJKLMN. When selecting the domain user account the account qualifier will look like ABCDEFGE-HIJKLMN\task.user. This results in an "invalid account" error. When however keeping the currently logged in user it will display ABCDEFGE-HIJKLM\current.user. Does this behaviour result from the presumable "illegal" domain name? Is there a workaround for this? update I could of course log in as the desired domain account and create the task but since this account is a account used for running services I want to avoid creating a user profile on the machine.

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How to create limited user accounts in Linux

- by James Willson

I want to create a user account for each of the key programs installed on my debian server. For example, for the following programs: Tomcat Nginx Supervisor PostgreSQL This seems to be recommended based on my reading online. However, I want to restrict these user accounts as much as possible, so that they dont have a shell login, dont have access to the other programs and are as limited as possible but still functional. Would anyone mind telling me how this could be achieved? My reading so far suggests this: echo "/usr/sbin/nologin" /etc/shells useradd -s /usr/sbin/nologin tomcat But I think there may be a more complete way of doing it. EDIT: I'm using debian squeeze

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deleting first user from Ubuntu install

- by Joseph

I noticed that the username I used to install Ubuntu got added to a bunch of groups in the /etc/group file. I'm getting rid of unneeded accounts. Would anything break if I removed that first account?

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Limit user to one CPU core in windows 7

- by Dean Ward

I let my family members use my pc over rdp to play their flash-based games as their laptops overheat if they use them directly. I have it setup so I can use the pc at the same time as them. The pc has a quad core cpu and I would like to be able to assign one of those cores to the user logged in via RDP so that the other 3 cores are left alone. Is this possible? They login via a specific user account setup for the purpose. Thanks for any advice!

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Link to user directory displayed with wrong name in start menu

- by wierob

In the start menu the link to my user directory is displayed with a wrong name e.g. foo When I click on the link in the start menu the explorer opens my correct user directory but the addressbar still names it foo. However, when I open a cmd from that directory the location is correctly shown as C:\Users\myUserName. Furthermore there is no C:\Users\foo directory. How can I fix this (i.e. ths link in the startmenu should be named myUserName)?

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Transition from GPO to GPP

- by spelk

I have a Windows network with a 2003 server as the PDC, and a 2008R2 server as a DC. We have used GPO sparsely when the majority of our workstations were WinXP, but now we have Windows 7 clients and we're having some issues with printer mapping. I'm not quite sure how I would go about taking up GPP, would it involve shifting the PDC over to the 2008R2 server? Any advice on what to do, and how to accomplish it would be very much appreciated.

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Getting random record from database with group by

- by Saif Bechan

Hello i have a question on picking random entries from a database. I have 4 tables, products, bids and autobids, and users. Products ------- id 20,21,22,23,24(prime_key) price........... etc........... users ------- id(prim_key) name user1,user2,user3 etc bids ------- product_id user_id created autobids -------- user_id product_id Now a multiple users can have an autobid on an product. So for the next bidder I want to select a random user from the autobid table example of the query in language: for each product in the autobid table I want a random user, which is not the last bidder. On product 20 has user1,user2,user3 an autobidding. On product 21 has user1,user2,user3 an autobidding Then I want a resultset that looks for example like this 20 – user2 21 – user3 Just a random user. I tried miximg the GOUP BY (product_id) and making it RAND(), but I just can't get the right values from it. Now I am getting a random user, but all the values that go with it don't match. Can someone please help me construct this query, I am using php and mysql

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Group Video Chat On iPad With Fring App

- by Gopinath

Apple’s Facetime is the simplest and most easy to use video chat application available for iOS devices and Apple Macs. Facetime lets you have a one-to-one video chat, but what about having a group chat on your iPad with a bunch of friends? Here comes Fring App for iPad that lets you group chat up to 4 members at a time. Unlike Facetime Fring does not impose any restriction on the network connectivity for video chatting. You can initiate a group video chatting on any network (3G, Wi-Fi, 4G, etc.) but Wi-Fi is the most preferred option for smooth video streaming. Also Fring is a cross platform application(runs on iOS, Android & Nokia), so your group video chat session can have a mix of devices – iPads, Android smartphones/tablets and Nokia mobiles. Anyone mobile device with a front facing cam and Fring app is allowed to join the party. Here is the promotional ad of Fring’s group video chatting application By the way did I say that Fring is a free app? Group video on iPad at no cost!!! Download Fring from Apple’s AppStore This article titled,Group Video Chat On iPad With Fring App, was originally published at Tech Dreams. Grab our rss feed or fan us on Facebook to get updates from us.

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how to hide webpart from a group?

- by kisin

can i hide (not by code) a webpart ONLY from a specific group?

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Certain SFTP user cannot connect

- by trobrock

I have my Ubuntu Server set up so users with the group of sftponly can connect with sftp, but have a shell of /bin/false, and they connect to their home directories. This is working fine with three of the user accounts I have. But I added a new user account today the same way that I added the others and it will not successfully connect. sftp -vvv user@hostname debug1: Next authentication method: password user@hostname's password: debug3: packet_send2: adding 48 (len 73 padlen 7 extra_pad 64) debug2: we sent a password packet, wait for reply debug1: Authentication succeeded (password). debug2: fd 5 setting O_NONBLOCK debug3: fd 6 is O_NONBLOCK debug1: channel 0: new [client-session] debug3: ssh_session2_open: channel_new: 0 debug2: channel 0: send open debug1: Requesting [email protected] debug1: Entering interactive session. debug1: channel 0: free: client-session, nchannels 1 debug3: channel 0: status: The following connections are open: #0 client-session (t3 r-1 i0/0 o0/0 fd 5/6 cfd -1) debug3: channel 0: close_fds r 5 w 6 e 7 c -1 debug1: fd 0 clearing O_NONBLOCK debug3: fd 1 is not O_NONBLOCK Connection to hostname closed by remote host. Transferred: sent 2176, received 1848 bytes, in 0.0 seconds Bytes per second: sent 127453.3, received 108241.6 debug1: Exit status -1 Connection closed For a successful user: sftp -vvv good_user@hostname debug1: Next authentication method: password good_user@hostname's password: debug3: packet_send2: adding 48 (len 63 padlen 17 extra_pad 64) debug2: we sent a password packet, wait for reply debug1: Authentication succeeded (password). debug2: fd 5 setting O_NONBLOCK debug3: fd 6 is O_NONBLOCK debug1: channel 0: new [client-session] debug3: ssh_session2_open: channel_new: 0 debug2: channel 0: send open debug1: Requesting [email protected] debug1: Entering interactive session. debug2: callback start debug2: client_session2_setup: id 0 debug1: Sending subsystem: sftp debug2: channel 0: request subsystem confirm 1 debug2: fd 3 setting TCP_NODELAY debug2: callback done debug2: channel 0: open confirm rwindow 0 rmax 32768 debug2: channel 0: rcvd adjust 2097152 debug2: channel_input_status_confirm: type 99 id 0 debug2: subsystem request accepted on channel 0 debug2: Remote version: 3 debug2: Server supports extension "[email protected]" revision 1 debug2: Server supports extension "[email protected]" revision 2 debug2: Server supports extension "[email protected]" revision 2 debug3: Sent message fd 3 T:16 I:1 debug3: SSH_FXP_REALPATH . -> / sftp> I cannot figure out why one user will work and the other wont, I have restart the ssh service after adding the user. I have even removed the user and added them again to be sure I am adding it correctly.

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MYSQL - Group by limit

- by jono2010

Hello Is there a simple way to LIMIT the GROUP BY results to the top 2. The following query returns all the results. Using 'LIMIT 2' reduces the overall list to the top 2 entries only. select distinct(rating_name), id_markets, sum(rating_good) 'good', sum(rating_neutral)'neutral', sum(rating_bad) 'bad' from ratings where rating_year=year(curdate()) and rating_week= week(curdate(),1) group by rating_name,id_markets order by rating_name, sum(rating_good) desc Results in the following :- poland 78 48 24 12 <- keep poland 1 15 5 0 <- keep poland 23 12 6 3 poland 2 5 0 0 poland 3 0 5 0 poland 4 0 0 5 ireland 1 9 3 0 <- keep ireland 2 3 0 0 <- keep ireland 3 0 3 0 ireland 4 0 0 3 france 12 24 12 6 <- keep france 1 3 1 0 <- keep france 231 1 0 0 france 2 1 0 0 france 4 0 0 1 france 3 0 1 0 Thanks Jon

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Reading Active Directory group users in SharePoint

- by Faiz

Hi, Say that i have an active directory group called "Group1". I add this Group1 to a SharePoint site ( People and Group New User). All the users that are part of Group1 can now access sharepoint site. Now,for a specific custom webpart, i need to target to only users who belong to Group1. But when a user who belongs to Group1 logs into the sharepoint site, i am not finding a way to determine from within SharePoint context if this user belongs to Group1. Any thoughts? Thanks, Faiz

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Two separate fields need to be grouped in one group

- by Sigita

I have two fields: Mother's employer and Father's employer, and I need to group on the employer. Could somebody help me combine the two above fields into one group? Both fields are in one table. FOr example a child named John Lewis is a record in a table and he has a father and a mother and Mother's employer is IBM and Father's employer is ISF. And so forth. I need to come up with a list By employer where it would show: Employer: IBM John Lewis Emplyer: ISF John Lewis Employer: .... Thank you, Sigita

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Odd GROUP BY output DB2 - Results not as expected

- by CallCthulhu

If I run the following query: select load_cyc_num , crnt_dnlq_age_cde , sum(cc_min_pymt_amt) as min_pymt , sum(ec_tot_bal) as budget , case when ec_tot_bal 0 then 'Y' else 'N' end as budget , case when ac_stat_cde in ('A0P','A1P','ARP','A3P') then 'Y' else 'N' end as arngmnt , sum(sn_close_bal) as st_bal from statements where (sn_close_bal 0 or ec_tot_bal 0) and load_cyc_num in (200911) group by load_cyc_num , crnt_dnlq_age_cde , case when ec_tot_bal 0 then 'Y' else 'N' end , case when ac_stat_cde in ('A0P','A1P','ARP','A3P') then 'Y' else 'N' end then I get the correct "BUDGET" grouping, but not the correct "ARRANGEMENT" grouping, only two rows have a "Y". If I change the order of the case statements in the GROUP BY, then I get the correct grouping (full Y-N breakdown for both columns). Am I missing something obvious?

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Mysql query different group by

- by solomongaby

Hello i have a products table that contains normal products and configurable product It has a basic stucture of: id name price configurable ('yes', 'no') id_configuration Normal products have configurable no and 0 as id configuration, and configurable products have it set to yes and have the same id_configuration value. The current query is: SELECT `products`.* FROM `products`, `categories`, `product_categories` WHERE `categories`.`id` = 23 AND `products`.`id` = `product_categories`.`id_product` AND `categories`.`id` = `product_categories`.`id_category` AND `products`.`active` = 'yes' AND ORDER BY `pos_new` ASC, `created` DESC LIMIT 0,20 I was wondering if there is a way to group by id_configuration, but only for the configurable products. The reason is that i want only one of the configuration products to show in search. I was thinking i could do a join, but was wondering if there is a way to do some kind of special group by. For example for configurable yes the field should be id_configuration otherwise it should be the id field Thanks a lot for any sugestions

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SQL: GROUP BY after JOIN without overriding rows?

- by krismeld

I have a table of basketball leagues, a table af teams and a table of players like this: LEAGUES ID | NAME | ------------------ 1 | NBA | 2 | ABA | TEAMS: ID | NAME | LEAGUE_ID ------------------------------ 20 | BULLS | 1 21 | KNICKS | 2 PLAYERS: ID | TEAM_ID | FIRST_NAME | LAST_NAME | --------------------------------------------- 1 | 21 | John | Starks | 2 | 21 | Patrick | Ewing | Given a League ID, I would like to retrieve all the players' names and their team ID from all the teams in that league, so I do this: SELECT t.id AS team_id, p.id AS player_id, p.first_name, p.last_name FROM teams AS t JOIN players AS p ON p.team_id = t.id WHERE t.league_id = 1 which returns: [0] => stdClass Object ( [team_id] => 21 [player_id] => 1 [first_name] => John [last_name] => Starks ) [1] => stdClass Object ( [team_id] => 21 [player_id] => 2 [first_name] => Patrick [last_name] => Ewing ) + around 500 more objects... Since I will use this result to populate a dropdown menu for each team containing each team's list of players, I would like to group my result by team ID, so the loop to create these dropdowns will only have to cycle through each team ID instead of all 500+ players each time. But when I use the GROUP BY like this: SELECT t.id AS team_id, p.id AS player_id, p.first_name, p.last_name FROM teams AS t JOIN players AS p ON p.team_id = t.id WHERE t.league_id = 1 GROUP BY t.id it only returns one player from each team like this, overriding all the other players on the same team because of the use of the same column names. [0] => stdClass Object ( [team_id] => 21 [player_id] => 2 [first_name] => Patrick [last_name] => Ewing ) [1] => stdClass Object ( [team_id] => 22 [player_id] => 31 [first_name] => Shawn [last_name] => Kemp ) etc... I would like to return something like this: [0] => stdClass Object ( [team_id] => 2 [player_id1] => 1 [first_name1] => John [last_name1] => Starks [player_id2] => 2 [first_name2] => Patrick [last_name2] => Ewing +10 more players from this team... ) +25 more teams... Is it possible somehow?

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SQL GROUP BY with "default values"

- by Christoph Schiessl

I'm trying to create SELECT statement with a GROUP BY clause, which should return "default values". Imagine the following simple MySQL table: CREATE TABLE `tracker` ( `id` INTEGER PRIMARY KEY auto_increment, `date` DATETIME NOT NULL, `customer_id` INTEGER NOT NULL ); The table contains only one record: INSERT INTO `tracker` (`date`, `customer_id`) VALUES('2010-05-03', 1); After wards I'm executing the following SQL query: SELECT DATE(`date`), COUNT(customer_id) FROM tracker WHERE DATE(`date`) >= '2010-05-01' AND DATE(`date`) <= '2010-05-05' GROUP BY DATE(`date`) ORDER BY DATE(`date`); And get the expected result set: +----+---------------------+-------------+ | id | date | customer_id | +----+---------------------+-------------+ | 1 | 2010-05-10 00:00:00 | 1 | +----+---------------------+-------------+ However, I would like the result set to look like this: +--------------+--------------------+ | DATE(`date`) | COUNT(customer_id) | +--------------+--------------------+ | 2010-05-01 | 0 | | 2010-05-02 | 0 | | 2010-05-03 | 1 | | 2010-05-04 | 0 | | 2010-05-05 | 0 | +--------------+--------------------+ Is it possible to achieve this behavior?

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How to specify a group when displaying an ABPeoplePickerNavigationController

- by northern_lite

Does anyone know how to specify a group when initially displaying an ABPeoplePickerNavigationController (so it doesn't automatically display "All Contacts")?

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Determining Cross Domain Active Directory Group Membership

- by thecaptain0220

I am currently working on a project where I need to query Active Directory to determine group membership of a user. I initially was locating the user and retrieving the memberOf attribute. The problem with this is that there is a domain and a child domain. The groups are universal groups so they can be used in both domains and they don't show up in the memberOf attribute. Unfortunately there doesn't seem to be much info around for Active Directory access with C++. Is there anyway to determine group membership in this case in C++?

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PowerShell - Finding all of users' group memberships and kicking it out of them

- by NirPes

as title says, I have to find all the groups that the user is a member of, and deleting its membership from all of them. I've tried this: get-adgroup -filter * | where {(Get-ADGroupMember $_ | foreach {$_.PrimarySmtpAdress}) -contains "[email protected]"} but it doesnt return anything (although THERE ARE some items that have to be returned) as for the deletion I found no way to do it, could someone give me an example of a code that does this? Im talking about security groups.

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Nhibernate linq group by duplicate fields

- by jaspion

Hello, I have a simple query like: from e in endContratoRepository.GetAll() where e.Contrato.idContrato == contrato.idContrato && e.Volume.idVolume == 1 && group e by new { e.dpto.idDepartamento, e.centroCusto.idCentroCusto } into grp select new Entidade { Contagem = grp.Count(), centroCusto = grp.Key.idCentroCusto, dpto = grp.Key.idDepartamento } and the problem: The fields that are in the group by, are duplicated in the generated query. The fields centroCusto and dpto appears twice, so when I try to get the field centroCusto, I get dpto. Anyone know how to solve this? thanks a lot!

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MySQL GROUP BY with three tables

- by Psaniko

I have the following tables: posts (post_id, content, etc) comments (comment_id, post_id, content, etc) posts_categories (post_category_id, post_id, category_id) and this query: SELECT `p`.*, COUNT(comments.comment_id) AS cmts, posts_categories.*,comments.* FROM `posts` AS `p` LEFT JOIN `posts_categories` ON `p`.post_id = `posts_categories`.post_id LEFT JOIN `comments` ON `p`.post_id = `comments`.post_id GROUP BY `p`.`post_id` There are three comments on post_id=1 and four in total. In posts_categories there are two rows, both assigned to post_id=1. I have four rows in posts. But if I query the statement above I get a result of 6 for COUNT(comments.comment_id) at post_id=1. How is this possible? I guess the mistake is somewhere in the GROUP BY clause but I can't figure out where. Any suggestions?

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SELECT * , COUNT( * ) FROM GROUP BY ORDER BY DESC

- by quanganh_developer

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- by slugster

- by AAAAAAAA

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- by Dean Ward

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- by spelk

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