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• Are there any command line tools for controllable XML formatting?

  - by Scott Stafford

  Hi - I am searching for a command-line tool (or XSLT technique, or C# code that can be made into a command-line tool, etc) for Windows that will do XML pretty-printing. Specifically, I want one that has the ability to put attributes one-to-a-line, something like: <Node> <ChildNode value1='5' value2='6' value3='happy' /> </Node> It doesn't have to be EXACTLY like that, but I want to use it for an XML file that has nodes with dozens of attributes and spreading them across multiple lines makes them easier to read, edit, and text-diff.

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• What is your favorite way to read XML files?

  - by stacker

  Let's take this xml structure as example: <?xml version="1.0" encoding="utf-8"?> <Configuration-content> <XFile Name="file name 1" /> <XFile Name="name2" /> <XFile Name="name3" /> <XFile Name="name4" /> </Configuration-content> C# interface to implement: public class Configuration { public XFile[] Files { get; set; } } public interface IConfigurationRipository { Configuration Get(); void Save(Configuration entity); } I wonder what's the best way to do that. The task is to implement IConfigurationRipository using your favorite approach.

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• What is the correct method to load an XML file and re-write it as a CVS? (C# Only)

  - by codesmack

  Hello, I have a XML file that I want to load into an unknown object type. (I say unknown object type because I am not sure what direction to go) Once I have the data loaded I need to do some processing on certain elements that are now loaded into the new object. For sake of example, we can say that the xml file is full of elements named and within the car element I need to process the element. Then once this is all done I need to write the file as a CSV file. I would like to do this is the most direct way possible. (The less code the better) I am using VS 2008 C# Thank you, CodeSmack

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• What is the correct method to load an XML file and re-write it as a CSV?

  - by codesmack

  I have a XML file that I want to load into an unknown object type. (I say unknown object type because I am not sure what direction to go) Once I have the data loaded I need to do some processing on certain elements that are now loaded into the new object. For sake of example, we can say that the xml file is full of elements named <car> and within the car element I need to process the <mileage> element. Then once this is all done I need to write the file as a CSV file. I would like to do this is the most direct way possible. (The less code the better) I am using VS 2008 C#

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• Do I have to worry about escaping XML reserved characters before I return a DataContract object from

  - by Brett Widmeier

  Hi, I am pretty inexperienced with WCF. I have a DataContract that implements the IExtensibleDataObject interface. Some of the members of this object are populated from freetext input and could contain XML reserved characters ('', for example). I imagine that I get escaping of these characters for free with WCF, but I have been looking around and could not find anything commenting on this one way or another. Is this the case? I have set my service to log the messages that it sends and receives for viewing in the Trace Viewer. Part of a message that my service returns looks like this: <sInstructions>"></sInstructions> Now, I have a couple questions about this. 1) Is it actually transmitting "&gt; and just showing it in a more readable form in the trace viewer? 2) If it is actually is transmitting ">, is this legal XML?

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• Using variable for tag in getElementsByTagName() for PHP and XML?

  - by Jared

  See my PHP: $file = "routingConfig.xml"; global $doc; $doc = new DOMDocument(); $doc->load( $file ); $ElTag = "Route"; $tag = $doc->getElementsByTagName($ElTag); XML is: <Routes> <Route></Route> <Route></Route> <Routes> Error returned is: Fatal error: Call to a member function getElementsByTagName() on a non-object I'm not sure how to do this?

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• What is the correct method to load an XML file and re-write it as a CSV? (C# Only)

  - by codesmack

  I have a XML file that I want to load into an unknown object type. (I say unknown object type because I am not sure what direction to go) Once I have the data loaded I need to do some processing on certain elements that are now loaded into the new object. For sake of example, we can say that the xml file is full of elements named <car> and within the car element I need to process the <mileage> element. Then once this is all done I need to write the file as a CSV file. I would like to do this is the most direct way possible. (The less code the better) I am using VS 2008 C#

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• Is it possible to define XML schemata with node names specified via regular expressions?

  - by MartyIX

  Hello, I know it is probably a question against XML philosophy but still is it possible to define schemata for XML like this: <Root> <arbitrary-name-of-node> <Name></Name> <Position></Position> <!-- ... --> </arbitrary-name-of-node> <arbitrary-name-of-node> <Name></Name> <Position></Position> <!-- ... --> </arbitrary-name-of-node> </Root> where arbitrary-name-of-node matches regular expression [a-zA-Z0-9]? Thanks for an answer!

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• SQL SERVER – Understanding XML – Contest Win Joes 2 Pros Combo (USD 198) – Day 5 of 5

  - by pinaldave

  August 2011 we ran a contest where every day we give away one book for an entire month. The contest had extreme success. Lots of people participated and lots of give away. I have received lots of questions if we are doing something similar this month. Absolutely, instead of running a contest a month long we are doing something more interesting. We are giving away USD 198 worth gift every day for this week. We are giving away Joes 2 Pros 5 Volumes (BOOK) SQL 2008 Development Certification Training Kit every day. One copy in India and One in USA. Total 2 of the giveaway (worth USD 198). All the gifts are sponsored from the Koenig Training Solution and Joes 2 Pros. The books are available here Amazon | Flipkart | Indiaplaza How to Win: Read the Question Read the Hints Answer the Quiz in Contact Form in following format Question Answer Name of the country (The contest is open for USA and India residents only) 2 Winners will be randomly selected announced on August 20th. Question of the Day: Is following XML a well formed XML Document? <?xml version=”1.0″?> <address> <firstname>Pinal</firstname> <lastname>Dave</lastname> <title>Founder</title> <company>SQLAuthority.com</company> </address> a) Yes b) No c) I do not know Query Hints: BIG HINT POST A common observation by people seeing an XML file for the first time is that it looks like just a bunch of data inside a text file. XML files are text-based documents, which makes them easy to read.  All of the data is literally spelled out in the document and relies on a just a few characters (<, >, =) to convey relationships and structure of the data.  XML files can be used by any commonly available text editor, like Notepad. Much like a book’s Table of Contents, your first glance at well-formed XML will tell you the subject matter of the data and its general structure. Hints appearing within the data help you to quickly identify the main theme (similar to book’s subject), its headers (similar to chapter titles or sections of a book), data elements (similar to a book’s characters or chief topics), and so forth. We’ll learn to recognize and use the structural “hints,” which are XML’s markup components (e.g., XML tags, root elements). The XML Raw and Auto modes are great for displaying data as all attributes or all elements – but not both at once. If you want your XML stream to have some of its data shown in attributes and some shown as elements, then you can use the XML Path mode. If you are using an XML Path stream, then by default all values will be shown as elements. However, it is possible to pick one or more elements to be shown with an attribute(s) as well. Additional Hints: I have previously discussed various concepts from SQL Server Joes 2 Pros Volume 5. SQL Joes 2 Pros Development Series – OpenXML Options SQL Joes 2 Pros Development Series – Preparing XML in Memory SQL Joes 2 Pros Development Series – Shredding XML SQL Joes 2 Pros Development Series – Using Root With Auto XML Mode SQL Joes 2 Pros Development Series – Using Root With Auto XML Mode SQL Joes 2 Pros Development Series – What is XML? SQL Joes 2 Pros Development Series – What is XML? – 2 Next Step: Answer the Quiz in Contact Form in following format Question - Answer Name of the country (The contest is open for USA and India) Bonus Winner Leave a comment with your favorite article from the “additional hints” section and you may be eligible for surprise gift. There is no country restriction for this Bonus Contest. Do mention why you liked it any particular blog post and I will announce the winner of the same along with the main contest. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Joes 2 Pros, PostADay, SQL, SQL Authority, SQL Puzzle, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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• Correct XML serialization and deserialization of "mixed" types in .NET

  - by Stefan

  My current task involves writing a class library for processing HL7 CDA files. These HL7 CDA files are XML files with a defined XML schema, so I used xsd.exe to generate .NET classes for XML serialization and deserialization. The XML Schema contains various types which contain the mixed="true" attribute, specifying that an XML node of this type may contain normal text mixed with other XML nodes. The relevant part of the XML schema for one of these types looks like this: <xs:complexType name="StrucDoc.Paragraph" mixed="true"> <xs:sequence> <xs:element name="caption" type="StrucDoc.Caption" minOccurs="0"/> <xs:choice minOccurs="0" maxOccurs="unbounded"> <xs:element name="br" type="StrucDoc.Br"/> <xs:element name="sub" type="StrucDoc.Sub"/> <xs:element name="sup" type="StrucDoc.Sup"/> <!-- ...other possible nodes... --> </xs:choice> </xs:sequence> <xs:attribute name="ID" type="xs:ID"/> <!-- ...other attributes... --> </xs:complexType> The generated code for this type looks like this: /// <remarks/> [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.3038")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(TypeName="StrucDoc.Paragraph", Namespace="urn:hl7-org:v3")] public partial class StrucDocParagraph { private StrucDocCaption captionField; private object[] itemsField; private string[] textField; private string idField; // ...fields for other attributes... /// <remarks/> public StrucDocCaption caption { get { return this.captionField; } set { this.captionField = value; } } /// <remarks/> [System.Xml.Serialization.XmlElementAttribute("br", typeof(StrucDocBr))] [System.Xml.Serialization.XmlElementAttribute("sub", typeof(StrucDocSub))] [System.Xml.Serialization.XmlElementAttribute("sup", typeof(StrucDocSup))] // ...other possible nodes... public object[] Items { get { return this.itemsField; } set { this.itemsField = value; } } /// <remarks/> [System.Xml.Serialization.XmlTextAttribute()] public string[] Text { get { return this.textField; } set { this.textField = value; } } /// <remarks/> [System.Xml.Serialization.XmlAttributeAttribute(DataType="ID")] public string ID { get { return this.idField; } set { this.idField = value; } } // ...properties for other attributes... } If I deserialize an XML element where the paragraph node looks like this: <paragraph>first line<br /><br />third line</paragraph> The result is that the item and text arrays are read like this: itemsField = new object[] { new StrucDocBr(), new StrucDocBr(), }; textField = new string[] { "first line", "third line", }; From this there is no possible way to determine the exact order of the text and the other nodes. If I serialize this again, the result looks exactly like this: <paragraph> <br /> <br />first linethird line </paragraph> The default serializer just serializes the items first and then the text. I tried implementing IXmlSerializable on the StrucDocParagraph class so that I could control the deserialization and serialization of the content, but it's rather complex since there are so many classes involved and I didn't come to a solution yet because I don't know if the effort pays off. Is there some kind of easy workaround to this problem, or is it even possible by doing custom serialization via IXmlSerializable? Or should I just use XmlDocument or XmlReader/XmlWriter to process these documents?

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• PHP parsing XML file with and without namespaces

  - by Mike

  I need to get a XML File into a Database. Thats not the problem. Cant read it, parse it and create some Objects to map to the DB. Problem is, that sometimes the XML File can contain namespaces and sometimes not. Furtermore sometimes there is no namespace defined at all. So what i first got was something like this: <?xml version="1.0" encoding="UTF-8"?> <struct xmlns:b="http://www.w3schools.com/test/"> <objects> <object> <node_1>value1</node_1> <node_2>value2</node_2> <node_3 iso_land="AFG"/> <coords lat="12.00" long="13.00"/> </object> </objects> </struct> And the parsing: $t = $xml->xpath('/objects/object'); foreach($nodes AS $node) { if($t[0]->$node) { $obj->$node = (string) $t[0]->$node; } } Thats fine as long as there are no namespaces. Here comes the XML File with namespaces: <?xml version="1.0" encoding="UTF-8"?> <b:struct xmlns:b="http://www.w3schools.com/test/"> <b:objects> <b:object> <b:node_1>value1</b:node_1> <b:node_2>value2</b:node_2> <b:node_3 iso_land="AFG"/> <b:coords lat="12.00" long="13.00"/> </b:object> </b:objects> </b:struct> I now came up with something like this: $xml = simplexml_load_file("test.xml"); $namespaces = $xml->getNamespaces(TRUE); $ns = count($namespaces) ? 'a:' : ''; $xml->registerXPathNamespace("a", "http://www.w3schools.com/test/"); $nodes = array('node_1', 'node_2'); $obj = new stdClass(); foreach($nodes AS $node) { $t = $xml->xpath('/'.$ns.'objects/'.$ns.'object/'.$ns.$node); if($t[0]) { $obj->$node = (string) $t[0]; } } $t = $xml->xpath('/'.$ns.'objects/'.$ns.'object/'.$ns.'node_3'); if($t[0]) { $obj->iso_land = (string) $t[0]->attributes()->iso_land; } $t = $xml->xpath('/'.$ns.'objects/'.$ns.'object/'.$ns.'coords'); if($t[0]) { $obj->lat = (string) $t[0]->attributes()->lat; $obj->long = (string) $t[0]->attributes()->long; } That works with namespaces and without. But i feel that there must be a better way. Before that i could do something like this: $t = $xml->xpath('/'.$ns.'objects/'.$ns.'object'); foreach($nodes AS $node) { if($t[0]->$node) { $obj->$node = (string) $t[0]->$node; } } But that just wont work with namespaces.

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• How to deserialize an element as an XmlNode?

  - by mackenir

  When using Xml serialization in C#, I want to deserialize a part of my input XML to an XmlNode. So, given this XML: <Thing Name="George"> <Document> <subnode1/> <subnode2/> </Document> </Thing> I want to deserialize the Document element to an XmlNode. Below is my attempt which given the XML above, sets Document to the 'subnode1' element rather than the 'Document' element. How would I get the code to set the Document property to the Document element? using System; using System.IO; using System.Xml; using System.Xml.Serialization; [Serializable] public class Thing { [XmlAttribute] public string Name {get;set;} public XmlNode Document { get; set; } } class Program { static void Main() { const string xml = @" <Thing Name=""George""> <Document> <subnode1/> <subnode2/> </Document> </Thing>"; var s = new XmlSerializer(typeof(Thing)); var thing = s.Deserialize(new StringReader(xml)) as Thing; } } However, when I use an XmlSerializer to deserialize the XML above to an instance of Thing, the Document property contains the child element 'subnode1', rather than the 'doc' element. How can I get the XmlSerializer to set Document to an XmlNode containing the 'doc' element.

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• Cinema4D XML scene not rendering texture

  - by George Profenza

  I was playing with the Cinema 4D command line options and ran into a problem that might not be specific to the command line options. I saved a basic scene(a textured cube) in two formats: the original .c4d(binary) format and .xml(Cinema 4D XML via File Export). the .c4d file renders with the texture applied, while the .xml file renders without the texture applied. I had a look at the xml file, and there is a node that holds a reference to the image used as texture, and there is another node which seems to store the pixels in xml. When I opened the .xml document in Cinema 4D, the document did store the material with the texture, but it was not applied to the object. Am I missing something when I export to XML ? How can I export a Cinema 4D XML that can render with the texture applied ?

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• How to use the same element name in different purposes ( in XML and DTD ) ?

  - by BugKiller

  Hi, I Want to create a DTD schema for this xml document: <root> <student> <name> <firstname>S1</firstname> <lastname>S2</lastname> </name> </student> <course> <name>CS101</name> </course> </root> as you can see , the element name in the course contains plain text ,but the element name in the student is complex type ( first-name, last-name ). The following is the DTD: <!ELEMENT root (course|student)*> <!ELEMENT student (name)> <!ELEMENT name (lastname|firstname)> <!ELEMENT firstname (#PCDATA)> <!ELEMENT lastname (#PCDATA)> <!ELEMENT course (name)> When I want to validate it , I get an error because the course's name has different structure then the student's name . My Question: how can I make a work-around solution for this situation without changing the name of element name using DTD not xml schema . Thanks.

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• XML Catalog in Eclipse is not working

  - by svaret

  Where I work we do not have any internet connection. We still want to have validation and code completion when editing xml files. I have tried the instructions here http://www.helmers.nu/?p=276 However, I try the instructions, restarts eclipse, do reload dependencies. I still cannot get any code completion nor validation. Can anyone point me in the right direction? I have tried both with Eclipse Galileo and Helios. My catalog.xml <?xml version="1.0" encoding="UTF-8" standalone="no"?> <catalog xmlns="urn:oasis:names:tc:entity:xmlns:xml:catalog"> <uri name="http://www.liquibase.org/xml/ns/dbchangelog/1.9" uri="file:///C:/dev/XMLSchemaDefinition/dbchangelog-1.9.xsd"/> </catalog> My xml-file: <?xml version="1.0" encoding="UTF-8" standalone="no"?> <databaseChangeLog xmlns="http://www.liquibase.org/xml/ns/dbchangelog/1.9" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.liquibase.org/xml/ns/dbchangelog/1.9 http://www.liquibase.org/xml/ns/dbchangelog/dbchangelog-1.9.xsd"> </databaseChangeLog>

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• How to use the same element name for different purposes ( in XML and DTD ) ?

  - by BugKiller

  Hi, I Want to create a DTD schema for this xml document: <root> <student> <name> <firstname>S1</firstname> <lastname>S2</lastname> </name> </student> <course> <name>CS101</name> </course> </root> as you can see , the element name in the course contains plain text ,but the element name in the student is complex type ( first-name, last-name ). The following is the DTD: <!ELEMENT root (course|student)*> <!ELEMENT student (name)> <!ELEMENT name (lastname|firstname)> <!ELEMENT firstname (#PCDATA)> <!ELEMENT lastname (#PCDATA)> <!ELEMENT course (name)> When I want to validate it , I get an error because the course's name has different structure then the student's name . My Question: how can I make a work-around solution for this situation without changing the name of element name using DTD not xml schema . Thanks.

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• use multiple xsl files with one xml document

  - by paracaudex

  I have a single xml document (data.xml), which I display as HTML using an XSLT document (transform.xsl) with the following line in data.xml. <?xml-stylesheet type="text/xsl" href="transform.xsl"?> Suppose, however, I want to display this information in two different ways, one at http://www.domain.com/data.xml and one at http://www.domain.com/data2.xml. Both of these displays will use the same xml document but with different xsl's. Is there a way to do this without duplicating the xml file?

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• XML Schema: Can I make some of an attribute's values be required but still allow other values?

  - by scrotty

  (Note: I cannot change structure of the XML I receive, I am only able to change how I validate it.) Let's say I can get XML like this: <Address Field="Street" Value="123 Main"/> <Address Field="StreetPartTwo" Value="Unit B"/> <Address Field="State" Value="CO"/> <Address Field="Zip" Value="80020"/> <Address Field="SomeOtherCrazyValue" Value="Foo"/> I need to create an XSD schema that validates that "Street", "State" and "Zip" must be present. But I don't care if "StreetPartTwo" or "SomeOTherCrazyValue" is present. If I knew that only the three I care about could be included, I could do this: <xs:element name="Address" type="addressType" maxOccurs="unbounded" minOccurs="3"/> <xs:complexType name="addressType"> <xs:attribute name="Field" use="required"> <xs:simpleType> <xs:restriction base="xs:string"> <xs:enumeration value="Street"/> <xs:enumeration value="State"/> <xs:enumeration value="Zip"/> </xs:restriction> </xs:simpleType> </xs:attribute> </xs:complexType> But this won't work with my case because I may also receive those other Address elements (that also have "Field" attributes) that I don't care about. Any ideas how I can ensure the stuff I care about is present but let the other stuff in too? TIA! Sean

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• Advance: Parsing XML into another XML page using only javascript or jquery; Can't use PhP, Java or MySQL

  - by UrBestFriend

  Current site: http://cardwall.tk/ Example of intended outcome: http://www.shockwave.com/downloadWall.jsp I have an embeded flash object that uses XML/RSS (Picasa) to feed itself pictures. Now I created my own XML/RSS feed so that I can add additional XML tags and values. Now here's my big problem: enabling search. Since I'm not relying on Picasa's API anymore to return custom RSS/XML for the user's search, how can I create xml from another xml based on the user's search queries using only JavaScript and Jquery? Here is the current code: <script type="text/javascript"> var flashvars = { feed : "http%3A%2F%2Frssfeed.ucoz.com%2Frssfeed.xml", backgroundColor : "#FFFFFF", metadataFont : "Arial", wmode : "opaque", iFrameScrolling: "no", numRows : "3", }; var params = { allowFullScreen: "true", allowscriptaccess : "always", wmode: "opaque" }; swfobject.embedSWF("http://apps.cooliris.com/embed/cooliris.swf", "gamewall", "810", "410", "9.0.0", "", flashvars, params); $(document).ready(function() { $("#cooliris input").keydown(function(e) { if(e.keyCode == 13) { $("#cooliris a#searchCooliris").click(); return false; } }); doCoolIrisSearch = function() { cooliris.embed.setFeedContents( '** JAVA STRING OF PARSED RSS/XML based on http%3A%2F%2Frssfeed.ucoz.com%2Frssfeed.xml and USER'S SEARCH INPUT** ' ) }); <form id="searchForm" name="searchForm" class="shockwave"> <input type="text" name="coolIrisSearch" id="coolIrisSearch" value="Search..." class="field text short" onfocus="this.value='';" /> <a id="searchCooliris" href="#" onclick="doCoolIrisSearch();return false;" class="clearLink">Search Cooliris</a> </form> <div id="gamewall"></div> So basically, I want to replace cooliris.embed.setFeedContents's value with a Javastring based on the parsed RSS/XML and user search input. Any code or ideas would be greatly appreciated.

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• I have problem loading all items from XML with for each

  - by vaha

  Hi all, I'm low level as3 programmer and I need help whit this code: I have gallery XML file: 1 0 Lokacije 1 1.jpg 2 2 Coaching 1 2.jpg 3 0 0 3.jpg And: var loader: URLLoader = new URLLoader(); loader.load(new URLRequest("gallery.xml"); var xml = new XML(evt.target.data); for each(var item in xml..item) { centralniText.htmlText = item.slika; } only shows last item from XML file: 3.jpg I want all. Please help.

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• Why can't I start XML entity names with 'xml''?

  - by flamey

  <XmlInfo /> I ran into problem using Perl's popular SOAP::Lite module, where it wouldn't accept XML entity names starting with "xml" (regardles letters' case). The author of the module replied to email saying that entity names starting with "xml" are not permitted in XML specification, but I couldn't find it in W3C's documents for 1.0 and 1.1 specs, I also couldn't find it in any of the articles or guidelines docs about XML entity naming. In fact some guideline documents used names starting with xml as an example, and lots of people are using it, as I see via Google Code Search. So are there any restrictions (besides which characters to use as defined in W3C's documents) in Entity naming in XML? Is there a restriction saying you can't name entities starting with "xml"?

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• format an xml string in Ruby

  - by user1476512

  given an xml string like this : <some><nested><xml>value</xml></nested></some> what's the best option(using ruby) to format it readable like : <some> <nested> <xml>value</xml> </nested> </some> I've found an answer here: what's the best way to format an xml string in ruby?, which is really helpful. But it formats xml like: <some> <nested> <xml> value </xml> </nested> </some> As my xml string is a little big in length. So it is not readable in this format. Thanks in advance!

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• Oracle 10.1 and 11.2 produce different XML using the same statement

  - by MindFyer

  I am migrating a database from Oracle 10.1 to 11.2 and I have the following problem. The statement SELECT '<?xml version="1.0" encoding="utf-8" ?>' || (Xml).getClobVal() AS XmlClob FROM ( SELECT XmlElement( "Element1", ( SELECT XmlAgg(tpx.Xml) FROM ( SELECT XmlElement("Element3",XmlForest('content' as Element4)) AS Xml FROM dual ) tpx ) AS "Element2" ) AS Xml FROM dual ) On the original 10.1 database produces XML like this... <?xml version="1.0" encoding="utf-8"?> <Element1> <Element2> <Element3> <ELEMENT4>content</ELEMENT4> </Element3> </Element2> </Element1> On the new 11.2 system it looks like this... <?xml version="1.0" encoding="utf-8"?> <Element1> <Element3> <ELEMENT4>content</ELEMENT4> </Element3> </Element1> Is there some environmental variable I am missing that tells Oracle how to format its XML. There are hundreds of thousands of lines of PL/SQL in the database; it would be a mammoth task to rewrite if it turned out they had changed they way Oracle formats XML between versions. Hopefully someone has come accross this before. Thanks

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• loading an xml in web apps directory from a library dll

  - by Blankman

  my web application has an xml file here: /files/xml/test.xml I need to load a XDocument from within a class library project, how will I reference the xml? I don't want to pass any path parameters to this method. I want to assume the location is fixed at /files/xml/test.xml. How can I load a XDocument know this? I don't seem to have access to server.mappath either.

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• XML Schema For MBSA Reports

  - by Steve Hawkins

  I'm in the process of creating a script to run the command line version of Microsoft Baseline Security Analyzer (mbsacli.exe) against all of our servers. Since the MBSA reports are provided as XML documents, I should be able to write a script or small program to parse the XML looking for errors / issues. I'm wondering if anyone knows whether or not the XML schema for the MBSA reports is documented anywhere -- I have goggled this, and cant seem to find any trace of it. I've run across a few articles that address bits and pieces, but nothing that addresses the complete schema. Yes, I could just reverse engineer the XML, but I would like to understand a little more about the meaning of some of the tags. Thanks...

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