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  • Eclipse: Double semi-colon on an import

    - by smp7d
    Using Eclipse, if I have an extra semicolon on an import line (not the last import line), I see a syntax error in the IDE. However, this compiles fine outside of the IDE (Maven in this case). Example: import java.util.ArrayList;; //notice extra semicolon import java.util.List; Does anyone else see this behavior? Why is this showing as a syntax error? I am working with someone who keeps pushing these this to source control and it is irritating me (they clearly aren't using Eclipse). Full disclosure... I am using SpringSource Tool Suite 2.8.0.

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  • Pyjamas import statements

    - by Gordon Worley
    I'm starting to use Pyjamas and I'm running into some annoyances. I have to import a lot of stuff to make a script work well. For example, to make a button I need to first from pyjamas.ui.Button import Button and then I can use Button. Note that import pyjamas.ui.Button and then using Button.Button doesn't work (results in errors when you build to JavaScript, at least in 0.7pre1). Does anyone have a better example of a good way to do the import statements in Pyjamas than what the Pyjamas folks have on their site? Doing things their way is possible, but ugly and overly complicated from my perspective, especially when you want to use a dozen or more ui components.

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  • How to import a module from PyPI when I have another module with the same name

    - by kuzzooroo
    I'm trying to use the lockfile module from PyPI. I do my development within Spyder. After installing the module from PyPI, I can't import it by doing import lockfile. I end up importing anaconda/lib/python2.7/site-packages/spyderlib/utils/external/lockfile.py instead. Spyder seems to want to have the spyderlib/utils/external directory at the beginning of sys.path, or at least none of the polite ways I can find to add my other paths get me in front of spyderlib/utils/external. I'm using python2.7 but with from __future__ import absolute_import. Here's what I've already tried: Writing code that modifies sys.path before running import lockfile. This works, but it can't be the correct way of doing things. Circumventing the normal mechanics of importing in Python using the imp module (I haven't gotten this to work yet, but I'm guessing it could be made to work) Installing the package with something like pip install --install-option="--prefix=modules_with_name_collisions" package_name. I haven't gotten this to work yet either, but I'm guess it could be made to work. It looks like this option is intended to create an entirely separate lib tree, which is more than I need. Source Using pip install --target=lockfile_from_pip. The files show up in the directory where I tell them to go, but import doesn't find them. And in fact pip uninstall can't find them either. I get Cannot uninstall requirement lockfile-from-pip, not installed and I guess I will just delete the directories and hope that's clean. Source So what's the preferred way for me to get access to the PyPI lockfile module?

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  • Crossed import in django

    - by Kuhtraphalji
    On example, i have 2 apps: alpha and beta in alpha/models.py import of model from beta.models and in beta/models.py import of model from alpha.models manage.py validate says that ImportError: cannot import name ModelName how to solve this problem?

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  • php import larg table to phpmyadmin database

    - by safaali
    hi, I am so worry :( I dropped one of the tables from the database accidentally. fortunately, I have back-up. (I have used the "Auto backup for mysql") The back-up of the table is stored as .txt file (56 Megabytes) on my PC. I tried to import it by PhpMyAdmin and the import failed because the file is too large to import. then I uploaded the file to /home/tablebk directory. I have some experiences in php. I know that I would import it with this code, but i don't know the sql statment for this import. what is have to put as $line variable? please help me :( :( <?php $dbhost = 'localhost'; $dbuser = 'mysite'; $dbpw = 'password'; $dbname = 'databasename'; $file = @fopen('country.txt', 'r'); if ($file) { while (!feof($file)) { $line = trim(fgets($file)); $flag = mysql_query($line); if (isset($flag)) { echo 'Insert Successfully<br />'; } else { echo mysql_error() . '<br/>'; } flush(); } fclose($file); } echo '<br />End of File'; ?>

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  • Win32 C++ Import path based on OS?

    - by Zenox
    I'm working with some legacy code that has an import like so: #import "C:\Program Files\Common Files\System\ado\msado15.dll" rename("EOF", "EndOfFile") The problem is, on a x64 machine the path for this import is in the 'Program Files (x86)' directory. Is there a preprocessor macro I can wrap around this to make it work on either? Edit: I think I found it. _M_X64, but im not 100% sure if this is correct.

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  • Views from Abroad: XML Pipelines and Delta XML

    A U.K.-based company uses XML to replicate the advantages of a pipeline in handling complex datasets. It is a simple tool, useful for such tasks as Java regression testing and version control, but the few tricks it does, it does well, according to our columnist.

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  • XML Parsing Error - C#

    - by Indebi
    My code is having an XML parsing error at line 7 position 32 and I'm not really sure why Exact Error Dump 5/1/2010 10:21:42 AM System.Xml.XmlException: An error occurred while parsing EntityName. Line 7, position 32. at System.Xml.XmlTextReaderImpl.Throw(Exception e) at System.Xml.XmlTextReaderImpl.Throw(String res, Int32 lineNo, Int32 linePos) at System.Xml.XmlTextReaderImpl.HandleEntityReference(Boolean isInAttributeValue, EntityExpandType expandType, Int32& charRefEndPos) at System.Xml.XmlTextReaderImpl.ParseAttributeValueSlow(Int32 curPos, Char quoteChar, NodeData attr) at System.Xml.XmlTextReaderImpl.ParseAttributes() at System.Xml.XmlTextReaderImpl.ParseElement() at System.Xml.XmlTextReaderImpl.ParseElementContent() at System.Xml.XmlTextReaderImpl.Read() at System.Xml.XmlLoader.LoadNode(Boolean skipOverWhitespace) at System.Xml.XmlLoader.LoadDocSequence(XmlDocument parentDoc) at System.Xml.XmlLoader.Load(XmlDocument doc, XmlReader reader, Boolean preserveWhitespace) at System.Xml.XmlDocument.Load(XmlReader reader) at System.Xml.XmlDocument.Load(String filename) at Lookoa.LoadingPackages.LoadingPackages_Load(Object sender, EventArgs e) in C:\Users\Administrator\Documents\Visual Studio 2010\Projects\Lookoa\Lookoa\LoadingPackages.cs:line 30 Xml File, please note this is just a sample because I want the program to work before I begin to fill this repository <repo> <Packages> <TheFirstPackage id="00001" longname="Mozilla Firefox" appver="3.6.3" pkgver="0.01" description="Mozilla Firefox is a free and open source web browser descended from the Mozilla Application Suite and managed by Mozilla Corporation. A Net Applications statistic put Firefox at 24.52% of the recorded usage share of web browsers as of March 2010[update], making it the second most popular browser in terms of current use worldwide after Microsoft's Internet Explorer." cat="WWW" rlsdate="4/8/10" pkgloc="http://google.com"/> </Packages> <categories> <WWW longname="World Wide Web" description="Software that's focus is communication or primarily uses the web for any particular reason."> </WWW> <Fun longname="Entertainment & Other" description="Music Players, Video Players, Games, or anything that doesn't fit in any of the other categories."> </Fun> <Work longname="Productivity" description="Application's commonly used for occupational needs or, stuff you work on"> </Work> <Advanced longname="System & Security" description="Applications that protect the computer from malware, clean the computer, and other utilities."> </Advanced> </categories> </repo> Small part of C# Code //Loading the Package and Category lists //The info from them is gonna populate the listboxes for Category and Packages Repository.Load("repo.info"); XmlNodeList Categories = Repository.GetElementsByTagName("categories"); foreach (XmlNode Category in Categories) { CategoryNumber++; CategoryNames[CategoryNumber] = Category.Name; MessageBox.Show(CategoryNames[CategoryNumber]); } The Messagebox.Show() is just to make sure it's getting the correct results

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  • How do I import Amazon MP3s with Banshee and the new Amazon Cloud Player?

    - by adempewolff
    Banshee's Amazon MP3 Import extension until recently allowed seamless importing of songs purchased from Amazon MP3. It did this by a)opening .amz files and using them to connect to and download the purchased files from Amazon's servers, and b) using hooks in Banshee's built-in browser to automatically recognize and open the .amz files when clicked on in the browser. However, recently this functionality stopped working. Banshee will display Contacting Server in the lower left hand corner for a little while and then stop. Furthermore opening the Amazon Cloud Player in the Banshee browser or any other browser on a Linux system to manually download the .amz file now results in the message: On Linux systems, Cloud Player only supports downloading songs one at a time. To download your music, deselect all checkboxes, select the checkbox for the song you want to download, then click the "Download" button. How can I get around this and import my purchased music into Banshee as I used to?

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  • How to import a pdf in libreoffice? under ubuntu, all pages are blank

    - by Daniele
    I have some .pdf generated by a scanner, that I want to import in LibreOffice and do some small editing. The PDF has only one object per page, a page-size image. If I open it in LibreOffice under Ubuntu 12.10, it imports "successfully" but all pages are blank. I have the libreoffice-pdfimport package installed. That is true with both LibreOffice 3.6 (part of Ubuntu 12.10) and with 4.0.2, from libreoffice ppa. The same .pdf files open perfectly fine on both LibreOffice for Windows and LibreOffice for Mac (yes, I have three computers with all three OSes), but on Ubuntu 12.10, all pages are blank, so I can only conclude this is an issue with Ubuntu packaging, or something really weird prevents it from working under linux. How can I import these kinds of .pdf into LibreOffice for editing?

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  • XElement.Load("~/App_Data/file.xml") Could not find a part of the path

    - by mahdiahmadirad
    hi everybody, I am new in LINQtoXML. I want to use XElement.Load("") Method. but the compiler can't find my file. can you help me to write correct path for my XML file? Note that: I defined a Class in App_Code and I want to use the XML file data in one of methods and my XML file Located in App_Data. settings = XElement.Load("App_Data/AppSettings.xml"); i cant Use Request.ApplicationPath and Page.MapPath() or Server.MapPath() to get the physical path for my file because i am not in a class Inherited form Page class. Brief error Message: *Could not find a part of the path 'C:\Program Files\Microsoft Visual Studio 9.0\Common7\IDE\App_Data\AppSettings.xml'*. you see the path compiled is fully different from my project path(G:\MyProjects\ASP.net Projects\VistaComputer\Website\App_Data\AppSettings.xml) Full error Message is here: System.IO.DirectoryNotFoundException was unhandled by user code Message="Could not find a part of the path 'C:\\Program Files\\Microsoft Visual Studio 9.0\\Common7\\IDE\\App_Data\\AppSettings.xml'." Source="mscorlib" StackTrace: at System.IO.__Error.WinIOError(Int32 errorCode, String maybeFullPath) at System.IO.FileStream.Init(String path, FileMode mode, FileAccess access, Int32 rights, Boolean useRights, FileShare share, Int32 bufferSize, FileOptions options, SECURITY_ATTRIBUTES secAttrs, String msgPath, Boolean bFromProxy) at System.IO.FileStream..ctor(String path, FileMode mode, FileAccess access, FileShare share, Int32 bufferSize) at System.Xml.XmlDownloadManager.GetStream(Uri uri, ICredentials credentials) at System.Xml.XmlUrlResolver.GetEntity(Uri absoluteUri, String role, Type ofObjectToReturn) at System.Xml.XmlReader.Create(String inputUri, XmlReaderSettings settings, XmlParserContext inputContext) at System.Xml.XmlReader.Create(String inputUri, XmlReaderSettings settings) at System.Xml.Linq.XElement.Load(String uri, LoadOptions options) at System.Xml.Linq.XElement.Load(String uri) at ProductActions.Add(Int32 catId, String title, String price, String website, String shortDesc, String fullDesc, Boolean active, Boolean editorPick, String fileName, Stream image) in g:\MyProjects\ASP.net Projects\VistaComputer\Website\App_Code\ProductActions.cs:line 67 at CMS_Products_Operations.Button1_Click(Object sender, EventArgs e) in g:\MyProjects\ASP.net Projects\VistaComputer\Website\CMS\Products\Operations.aspx.cs:line 72 at System.Web.UI.WebControls.Button.OnClick(EventArgs e) at System.Web.UI.WebControls.Button.RaisePostBackEvent(String eventArgument) at System.Web.UI.WebControls.Button.System.Web.UI.IPostBackEventHandler.RaisePostBackEvent(String eventArgument) at System.Web.UI.Page.RaisePostBackEvent(IPostBackEventHandler sourceControl, String eventArgument) at System.Web.UI.Page.RaisePostBackEvent(NameValueCollection postData) at System.Web.UI.Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint) InnerException:

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  • XDocument.Parse fails due to resolution error, how to disable resolution

    - by Frank Krueger
    I am trying to parse the contents of http://feeds.feedburner.com/riabiz using XDocument.Parse(string) (because it gets cached in a DB.) However, it keeps failing with the below stack trace when it tries to resolve some URIs in that XML. I don't care about validation or any of that XML nonsense, I just want the structure parsed. How can I use XDocument without this URI resolution? System.ArgumentException: The specified path is not of a legal form (empty). at System.IO.Path.InsecureGetFullPath (System.String path) [0x00000] in :0 at System.IO.Path.GetFullPath (System.String path) [0x00000] in :0 at System.Xml.XmlResolver.ResolveUri (System.Uri baseUri, System.String relativeUri) [0x00000] in :0 at System.Xml.XmlUrlResolver.ResolveUri (System.Uri baseUri, System.String relativeUri) [0x00000] in :0 at Mono.Xml2.XmlTextReader.ReadStartTag () [0x00000] in :0 at Mono.Xml2.XmlTextReader.ReadContent () [0x00000] in :0 at Mono.Xml2.XmlTextReader.Read () [0x00000] in :0 at System.Xml.XmlTextReader.Read () [0x00000] in :0 at Mono.Xml.XmlFilterReader.Read () [0x00000] in :0 at Mono.Xml.XmlFilterReader.Read () [0x00000] in :0 at System.Xml.XmlReader.ReadEndElement () [0x00000] in :0 at System.Xml.Linq.XElement.LoadCore (System.Xml.XmlReader r, LoadOptions options) [0x00000] in :0 at System.Xml.Linq.XNode.ReadFrom (System.Xml.XmlReader r, LoadOptions options) [0x00000] in :0 ...

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  • Java -Android. Parser problem

    - by Kano
    I am making a very simple app with an RSS reader. The reader works great, but it's only giving me the title, and i want the description too. I'am very new to android, and I have tried a lot of things, but I can't get it to work. I've found a lot of parsers but they are to complicated for me to understand, so I was hoping to find a simple solution, since it's only title and description i want. Can anyone help me? import java.io.IOException; import java.net.MalformedURLException; import java.net.URL; import javax.xml.parsers.ParserConfigurationException; import javax.xml.parsers.SAXParser; import javax.xml.parsers.SAXParserFactory; import org.xml.sax.Attributes; import org.xml.sax.InputSource; import org.xml.sax.SAXException; import org.xml.sax.XMLReader; import org.xml.sax.helpers.DefaultHandler; import android.app.Activity; import android.os.Bundle; import android.widget.TextView; public class NyhedActivity extends Activity { String streamTitle = ""; @Override protected void onCreate(Bundle savedInstanceState) { // TODO Auto-generated method stub super.onCreate(savedInstanceState); setContentView(R.layout.nyheder); TextView result = (TextView)findViewById(R.id.result); try { URL rssUrl = new URL("http://tv2sport.dk/rss/*/*/*/248/*/*"); SAXParserFactory mySAXParserFactory = SAXParserFactory.newInstance(); SAXParser mySAXParser = mySAXParserFactory.newSAXParser(); XMLReader myXMLReader = mySAXParser.getXMLReader(); RSSHandler myRSSHandler = new RSSHandler(); myXMLReader.setContentHandler(myRSSHandler); InputSource myInputSource = new InputSource(rssUrl.openStream()); myXMLReader.parse(myInputSource); result.setText(streamTitle); } catch (MalformedURLException e) { // TODO Auto-generated catch block e.printStackTrace(); result.setText("Cannot connect RSS!"); } catch (ParserConfigurationException e) { // TODO Auto-generated catch block e.printStackTrace(); result.setText("Cannot connect RSS!"); } catch (SAXException e) { // TODO Auto-generated catch block e.printStackTrace(); result.setText("Cannot connect RSS!"); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); result.setText("Cannot connect RSS!"); } } private class RSSHandler extends DefaultHandler { final int stateUnknown = 0; final int stateTitle = 1; int state = stateUnknown; int numberOfTitle = 0; String strTitle = ""; String strElement = ""; @Override public void startDocument() throws SAXException { // TODO Auto-generated method stub strTitle = "Nyheder fra "; } @Override public void endDocument() throws SAXException { // TODO Auto-generated method stub strTitle += ""; streamTitle = "" + strTitle; } @Override public void startElement(String uri, String localName, String qName, Attributes attributes) throws SAXException { // TODO Auto-generated method stub if (localName.equalsIgnoreCase("title")) { state = stateTitle; strElement = ""; numberOfTitle++; } else { state = stateUnknown; } } @Override public void endElement(String uri, String localName, String qName) throws SAXException { // TODO Auto-generated method stub if (localName.equalsIgnoreCase("title")) { strTitle += strElement + "\n"+"\n"; } state = stateUnknown; } @Override public void characters(char[] ch, int start, int length) throws SAXException { // TODO Auto-generated method stub String strCharacters = new String(ch, start, length); if (state == stateTitle) { strElement += strCharacters; } } } }

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  • Can I create an xml that specifies element from 2 nested xsd's without using a prefixes?

    - by TweeZz
    I have 2 xsd's which are nested: DefaultSchema.xsd: <?xml version="1.0" encoding="utf-8"?> <xs:schema id="DefaultSchema" targetNamespace="http://myNamespace.com/DefaultSchema.xsd" elementFormDefault="qualified" xmlns="http://myNamespace.com/DefaultSchema.xsd" xmlns:xs="http://www.w3.org/2001/XMLSchema" > <xs:complexType name="ZForm"> <xs:sequence minOccurs="0" maxOccurs="unbounded"> <xs:element name="Part" minOccurs="0" maxOccurs="unbounded" type="Part"/> </xs:sequence> <xs:attribute name="Title" use="required" type="xs:string"/> <xs:attribute name="Version" type="xs:int"/> </xs:complexType> <xs:complexType name="Part"> <xs:sequence minOccurs="0" maxOccurs="unbounded"> <xs:element name="Label" type="Label" minOccurs="0"></xs:element> </xs:sequence> <xs:attribute name="Title" use="required" type="xs:string"/> </xs:complexType> <xs:complexType name="Label"> <xs:simpleContent> <xs:extension base="xs:string"> <xs:attribute name="Title" type="xs:string"/> </xs:extension> </xs:simpleContent> </xs:complexType> </xs:schema> ExportSchema.xsd: (this one kinda wraps 1 more element (ZForms) around the main element (ZForm) of the DefaultSchema) <?xml version="1.0" encoding="utf-8"?> <xs:schema id="ExportSchema" targetNamespace="http://myNamespace.com/ExportSchema.xsd" elementFormDefault="qualified" xmlns="http://myNamespace.com/DefaultSchema.xsd" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:es="http://myNamespace.com/ExportSchema.xsd" > <xs:import namespace="http://myNamespace.com/DefaultSchema.xsd" schemaLocation="DefaultSchema.xsd"/> <xs:element name="ZForms" type="es:ZFormType"></xs:element> <xs:complexType name="ZFormType"> <xs:sequence> <xs:element name="ZForm" type="ZForm" maxOccurs="unbounded" /> </xs:sequence> </xs:complexType> </xs:schema> And then finally I have a generated xml: <?xml version="1.0" encoding="utf-8"?> <ZForms xmlns="http://myNamespace.com/ExportSchema.xsd"> <ZForm Version="1" Title="FormTitle"> <Part Title="PartTitle" > <Label Title="LabelTitle" /> </Part> </ZForm> </ZForms> Visual studio complains it doesn't know what 'Part' is. I was hoping I do not need to use xml namespace prefixes (..) to make this xml validate, since ExportSchema.xsd has a reference to the DefaultSChema.xsd. Is there any way to make that xml structure valid without explicitly specifying the DefaultSchema.xsd? Or is this a no go?

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  • Vim is spellchecking in XML files where I don't want it to, and only there

    - by Kazark
    I'm trying to use Vim's builtin spellchecking in some XML documents. This happens merely by having the XML syntax loaded, as seen in the following minimalistic example (which reproduces what I also see in large XML documents): Note that given two buffers with exactly the same content, when Filetype is text, the spellchecking works; when it is xml, it does not. spell is set in both buffers. However, given this view of the top three lines of a large XML document, you can see that the spellchecking is certainly on: but it is only checking attributes. The nuisance is that none of the things it is actually finding are mispelled, and it isn't finding any of the numerous misspellings in the document. I would like it at a minimum to find the spelling errors in the body of the document, and being able to turn off the checking on attributes would be a nice option. I've searched for @NoSpell in the xml.vim file, but that returns no hits.

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  • Set CSV import default to UTF-8 in Calc

    - by picca
    Every time I open a CSV (comma separated values) document in OpenOffice.org Calc I get a dialog with CSV preferences. The current default character set is "Eastern Europe (ISO-8859-2)". I would like "UTF-8" to be selected by default instead.

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  • Excel CSV import treating quoted strings of numbers as numeric values, not strings

    - by MichaelOryl
    I've got a web application that is exporting its data to a CSV file. Here's one example row of the CSV file in question: 28,"65154",02/21/2013 00:00,"false","0316295","8316012,8315844","MALE" Since I can't post an image, I'll have to explain the results in Excel. The "0316295" field gets turned into a number and the leading 0 goes away. The "8316012,8315844" gets interpreted as one single number: 83,160,128,315,844. That is, most obviously, not the intended result. I've seen people recommend a leading single quote for such cases, but that doesn't really work either. 28,"65154",02/21/2013 00:00,"false","'0316295","'8316012,8315844","MALE" The single quote is visible at all times in the cell in Excel, though if I enter a number with a leading single quote myself, it shows just the intended string and not the single quote with the string. Importing is not the same as typing, it seems. Anybody have a solution here?

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  • Excel 2007 save import steps on csv file?

    - by Chris Marisic
    I have a csv file that constantly needs opened into Excel and then have the data copied over to a separate workbook. I find the process of having to click through all of the dialogs, setting the text identifier, setting the columns to all be text extremely tedious. In many actions with data like this in regards to MSSQL or Access the program will ask you if you wish to save these steps however Excel doesn't readily ask that. Is there any way to get a comparable usage with Excel?

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  • Import data in Excel that doesn't have a row delimiter, but number of columns is known

    - by Alex B
    So i have this text file that looks something like this: Header1 Header2 Header3 Header4 A1 B1 C1 D1 A2 B2 C2 D2 and so on. When imported, I'd want the data to format itself in 4 columns. I tried the Get External Data from Text, and it successfully imports it, but it doesn't wrap it around, so it just keeps making columns for every space. I'd want it to go on the next line after 4 (in this case) elements have been added. What's the simplest way to achieve this? EDIT: My answer follows, since I'm not yet allowed to answer my own questions yet. The Excel function I needed is called indirect(). Not sure how it actually works though, so hopefully someone can help out with that, but the function call that worked for me is =INDIRECT(ADDRESS((ROW(A1)-1)*4+COLUMN(A1),1)) which i found over here: http://www.ozgrid.com/forum/showthread.php?t=101584&p=456031#post456031 Note: this required me to add the text to excel where i'd get this row full of columns, and then flip it so that i'd have a column full of rows.

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  • XML generation error.

    - by Janis Peisenieks
    I'm trying to generate an XML output with Zend_Framework, but this nasty thing keeps popping up: XML Parsing Error: XML or text declaration not at start of entity Location: http://cart/index/kurpirkt Line Number 2, Column 1:<?xml version="1.0" encoding="utf-8"?> ^ As far as I know there are no white-spaces in any of my include files, and even if there were, I think that the ob_clean() function should have taken care of it. Here is my code: public function kurpirktAction() { ob_clean(); // XML-related routine $xml = new DOMDocument('1.0', 'utf-8'); $xml->appendChild($xml->createElement('foo', 'bar')); $output = $xml->saveXML(); // Both layout and view renderer should be disabled Zend_Controller_Action_HelperBroker::getStaticHelper('viewRenderer')->setNoRender(true); Zend_Layout::getMvcInstance()->disableLayout(); // Setting up headers and body $this->_response->setHeader('Content-Type', 'text/xml; charset=utf-8') ->setBody($output); } Any help or suggestions?

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  • Preserving multi-byte characters in Flex XML object

    - by Dan Petker
    I'm having an issue with the Flex XML object type mangling multi-byte characters (such as Japanese or Chinese characters). The basic setup is this. I'm getting an XML-formatted string from the server, and in that string there can be multi-byte characters. A lot of the time, these characters are in attributes, for example: <example id="foo" name="[some multi-byte characters]"/> Now, when I examine the raw string, the multi-byte characters display just fine. However, as soon as I convert the string to an XML object using the top-level XML() function, all the multi-byte characters become mangled. I've tried setting the XML's encoding by including an <?xml version="1.0" encoding="utf-8"?> element in the XML-formatted string, but this doesn't seem to have any effect on the resulting XML object. Is there a way to get the XML object to respect the encoding of the XML-formatted string and prevent the multi-byte characters from being mangled?

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  • Insertions into Zipper trees on XML files in Clojure

    - by ivar
    I'm confused as how to idiomatically change a xml tree accessed through clojure.contrib's zip-filter.xml. Should be trying to do this at all, or is there a better way? Say that I have some dummy xml file "itemdb.xml" like this: <itemlist> <item id="1"> <name>John</name> <desc>Works near here.</desc> </item> <item id="2"> <name>Sally</name> <desc>Owner of pet store.</desc> </item> </itemlist> And I have some code: (require '[clojure.zip :as zip] '[clojure.contrib.duck-streams :as ds] '[clojure.contrib.lazy-xml :as lxml] '[clojure.contrib.zip-filter.xml :as zf]) (def db (ref (zip/xml-zip (lxml/parse-trim (java.io.File. "itemdb.xml"))))) ;; Test that we can traverse and parse. (doall (map #(print (format "%10s: %s\n" (apply str (zf/xml-> % :name zf/text)) (apply str (zf/xml-> % :desc zf/text)))) (zf/xml-> @db :item))) ;; I assume something like this is needed to make the xml tags (defn create-item [name desc] {:tag :item :attrs {:id "3"} :contents (list {:tag :name :attrs {} :contents (list name)} {:tag :desc :attrs {} :contents (list desc)})}) (def fred-item (create-item "Fred" "Green-haired astrophysicist.")) ;; This disturbs the structure somehow (defn append-item [xmldb item] (zip/insert-right (-> xmldb zip/down zip/rightmost) item)) ;; I want to do something more like this (defn append-item2 [xmldb item] (zip/insert-right (zip/rightmost (zf/xml-> xmldb :item)) item)) (dosync (alter db append-item2 fred-item)) ;; Save this simple xml file with some added stuff. (ds/spit "appended-itemdb.xml" (with-out-str (lxml/emit (zip/root @db) :pad true))) I am unclear about how to use the clojure.zip functions appropriately in this case, and how that interacts with zip-filter. If you spot anything particularly weird in this small example, please point it out.

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  • Flash AS3 - Display an error if the XML if incorrect

    - by ongoingworlds
    Hi, I'm creating a flash application which loads in some XML which is generated dynamically from the CMS. I want to display an error in case the XML file isn't formatted correctly. When I test this with incorrectly formatted XML, it will just get to the line myXML = XML(myLoader.data); and then just bomb out. How can I catch the error, display a message to the user, but the flash program to continue as normal. var myXMLURL:URLRequest = new URLRequest(XMLfile); var myLoader:URLLoader = new URLLoader(myXMLURL); myLoader.addEventListener(Event.COMPLETE, xmlLoaded); myLoader.addEventListener(IOErrorEvent.IO_ERROR, xmlFailed); var myXML:XML; //--when the xml is loaded, do this function xmlLoaded(e:Event):void { myXML = XML(myLoader.data); trace("XML = "+myXML); } //--if the xml fails to load, do this function xmlFailed(event:IOErrorEvent):void { errorMsg.text = "The XML file cannot be found" }

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  • change a value xml in php but false with a node name id-7

    - by Nataly Nguyen
    I want to change a xml, but fails with this code. I think mistake with name of variable (ID-1) in php. chang.php <?php include 'example.php'; $xml = new SimpleXMLElement($xmlstr); $xml->ID-1 = '8'; $xml->name = 'Big Cliff'; $xml->asXML('test2.xml'); echo $xml->asXML(); ?> example.php <?php $xmlstr = <<<XML <?xml version="1.0" encoding="utf-8"?> <film> <ID-1>29</ID-1> <name>adf</name> </film> XML; ?>

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