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Search found 803 results on 33 pages for 'xpath'.

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  • Problem with relative path to image in XAML?

    - by Giri
    I am trying to reference a PNG file in my applications working directory through XAML with the following: <Image Name="contactImage"> <Image.Source> <BitmapImage UriSource="/Images/contact.png"> </Image.Source> </Image> Now in my code-behind I try to get the height of the image with contactImage.Source.Height This fails with System.IOException - cannot locate resource 'images/contact.png'. If I use something like PngBitmapDecoder p = new PngBitmapDecoder(new Uri("./Images/contact.png"), UriKind.Relative, BitmapCreateOptions.PreservePixelFormat, BitmapCacheOption.Default); Everything is happy. How can I reference an image in xaml to a path relative to the working deirectory of the app. BTW- this is being run on a remote machine (if that makes a difference). I have tried "./Images/contact.png" and ".\Images\contact.png" and several other combinations of back/forward slashes and dots. Here is the primary difference- Any time the file is referenced in XAML, it shows up as pack://aplication:,,, blah blah blah when I use the PngBitmapDecoder, it shows up correctly as "./Images/contact.png". How do I reference the image file in XAML and get it show a source as "./Images/contact.png" instead of a pack://application,,,blah blah blah?

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  • Get content of XML node using c#

    - by Adam S
    Hi all, simple question but I've been dinking around with it for an hour and it's really starting to frustrate me. I have XML that looks like this: <TimelineInfo> <PreTrialEd>Not Started</PreTrialEd> <Ambassador>Problem</Ambassador> <PsychEval>Completed</PsychEval> </TimelineInfo> And all I want to do is use C# to get the string stored between <Ambassador> and </Ambassador>. So far I have: XmlDocument doc = new XmlDocument(); doc.Load("C:\\test.xml"); XmlNode x = doc.SelectSingleNode("/TimelineInfo/Ambassador"); which selects the note just fine, now how in the world do I get the content in there?

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  • Using XSLT, how do I separate nodes based on their value?

    - by Will Goring
    I have a pretty flat XML structure that I need to reorder into categorised sections and, for the life of me, I can't figure out how to do it in XSLT (not that I'm by any means an expert.) Basically, the original XML looks kinda like: <things> <thing> <value>one</value> <type>a</type> </thing> <thing> <value>two</value> <type>b</type> </thing> <thing> <value>thee</value> <type>b</type> </thing> <thing> <value>four</value> <type>a</type> </thing> <thing> <value>five</value> <type>d</type> </thing> </things> And I need to output something like: <data> <a-things> <a>one</a> <a>four</a> </a-things> <b-things> <b>two</b> <b>three</b> </b-things> <d-things> <d>five</d> </d-things> </data> Note that I can't output <c-things> if there aren't any <c> elements, but I do know ahead of time what the complete list of types is, and it's fairly short so handcoding templates for each type is definitely possible. It feels like I could probably hack something together using <xsl:if> and <xsl:for-each> but it also feels like there must be a more ... 'templatey' way to do it. Can anyone help? Cheers.

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  • Remove all nodes from xml excluding specific nodes using XSLT

    - by Grinner
    Hi, I have a bunch of xml files with a varying amount of data nodes in them and I want to change the files using XSLT to include only specific nodes. Example: <?xml version="1.0" encoding="UTF-8"?> <SomeName> <identifier> <UID> 1234 </UID> </identifier> <MainNode1> <SubNode1> <Subnode1a>DATA1a0</Subnode1a> </SubNode1> <SubNode1> <Subnode1a>DATA1a1</Subnode1a> </SubNode1> <SubNode1> <Subnode1a>DATA1a2</Subnode1a> </SubNode1> </MainNode1> <MainNode2> <SubNode2> <Subnode2a>DATA2a0</Subnode2a> </SubNode2> </MainNode2> <MainNodeIDONTCARE> <SubnodeWhatever> </SubnodeWhatever> </MainNodeIDONTCARE> <MainNodeuseless> <SubnodeWhatever> </SubnodeWhatever> </MainNodeuseless> <MainNodewhatever> <SubnodeWhatever> </SubnodeWhatever> </MainNodewhatever> </SomeName> Now my final XML file should look like: <?xml version="1.0" encoding="UTF-8"?> <SomeName> <identifier> <UID> 1234 </UID> </identifier> <MainNode1> <SubNode1> <Subnode1a>DATA1a0</Subnode1a> </SubNode1> <SubNode1> <Subnode1a>DATA1a1</Subnode1a> </SubNode1> <SubNode1> <Subnode1a>DATA1a2</Subnode1a> </SubNode1> </MainNode1> <MainNode2> <SubNode2> <Subnode2a>DATA2a0</Subnode2a> </SubNode2> </MainNode2> </SomeName> I've been trying to get it done with XSLT, but I can't seem to get it done. Thanks for any help.

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  • libxml2 on iPhone

    - by mellkord
    I'm trying to parse HTML file with libxml2. Usually this works fine, but not in this case: <p> <b>Titles</b> (Some Text) <table> <tr> <td valign="top"> …Something1... </td> <td align="right" valign="top"> …Something2... </td> </tr> </table> </p> I do this query to get the first <td> //p[b='Titles']/table/tr/td[0] but nothing is returned because libxml think that <table> tag is not a child of a tag <p> and following him. And finally the question WHY?

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  • Using xsl:key to store result of boolean expression

    - by hielsnoppe
    In my transformation there is an expression some elements are repeatedly tested against. To reduce redundancy I'd like to encapsulate this in an xsl:key like this (not working): <xsl:key name="td-is-empty" match="td" use="not(./node()[normalize-space(.) or ./node()])" /> The expected behaviour is the key to yield a boolean value of true in case the expression is evaluated successfully and otherwise false. Then I'd like to use it as follows: <xsl:template match="td[not(key('td-is-empty', .))]" /> Is this possible and in case yes, how?

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  • xslt test if a variable value is contained in a node set

    - by Aamir
    I have the following two files: <?xml version="1.0" encoding="utf-8" ?> <!-- D E F A U L T H O S P I T A L P O L I C Y --> <xas DefaultPolicy="open" DefaultSubjectsFile="subjects.xss"> <rule id="R1" access="deny" object="record" subject="roles/*[name()!='Staff']"/> <rule id="R2" access="deny" object="diagnosis" subject="roles//Nurse"/> <rule id="R3" access="grant" object="record[@id=$user]" subject="roles/member[@id=$user]"/> </xas> and the other xml file called subjects.xss is: <?xml version="1.0" encoding="utf-8" ?> <subjects> <users> <member id="dupont" password="4A-4E-E9-17-5D-CE-2C-DD-43-43-1D-F1-3F-5D-94-71"> <name>Pierre Dupont</name> </member> <member id="durand" password="3A-B6-1B-E8-C0-1F-CD-34-DF-C4-5E-BA-02-3C-04-61"> <name>Jacqueline Durand</name> </member> </users> <roles> <Staff> <Doctor> <member idref="dupont"/> </Doctor> <Nurse> <member idref="durand"/> </Nurse> </Staff> </roles> </subjects> I am writing an xsl sheet which will read the subject value for each rule in policy.xas and if the currently logged in user (accessible as variable "user" in the stylesheet) is contained in that subject value (say roles//Nurse), then do something. I am not being able to test whether the currently logged in user ($user which is equal to say "durand") is contained in roles//Nurse in the subjects file (which is a different xml file). Hope that clarifies my question. Any ideas? Thanks in advance.

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  • Retrieving XML node from a path specified in an attribute value of another node

    - by Olivier PAYEN
    From this XML source : <?xml version="1.0" encoding="utf-8" ?> <ROOT> <STRUCT> <COL order="1" nodeName="FOO/BAR" colName="Foo Bar" /> <COL order="2" nodeName="FIZZ" colName="Fizz" /> </STRUCT> <DATASET> <DATA> <FIZZ>testFizz</FIZZ> <FOO> <BAR>testBar</BAR> <LIB>testLib</LIB> </FOO> </DATA> <DATA> <FIZZ>testFizz2</FIZZ> <FOO> <BAR>testBar2</BAR> <LIB>testLib2</LIB> </FOO> </DATA> </DATASET> </ROOT> I want to generate this HTML : <html> <head> <title>Test</title> </head> <body> <table border="1"> <tr> <td>Foo Bar</td> <td>Fizz</td> </tr> <tr> <td>testBar</td> <td>testFizz</td> </tr> <tr> <td>testBar2</td> <td>testFizz2</td> </tr> </table> </body> </html> Here is the XSLT I currently have : <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"> <xsl:output method="html" indent="yes"/> <xsl:template match="/ROOT"> <html> <head> <title>Test</title> </head> <body> <table border="1"> <tr> <!--Generate the table header--> <xsl:apply-templates select="STRUCT/COL"> <xsl:sort data-type="number" select="@order"/> </xsl:apply-templates> </tr> <xsl:apply-templates select="DATASET/DATA" /> </table> </body> </html> </xsl:template> <xsl:template match="COL"> <!--Template for generating the table header--> <td> <xsl:value-of select="@colName"/> </td> </xsl:template> <xsl:template match="DATA"> <xsl:variable name="pos" select="position()" /> <tr> <xsl:for-each select="/ROOT/STRUCT/COL"> <xsl:sort data-type="number" select="@order"/> <xsl:variable name="elementName" select="@nodeName" /> <td> <xsl:value-of select="/ROOT/DATASET/DATA[$pos]/*[name() = $elementName]" /> </td> </xsl:for-each> </tr> </xsl:template> </xsl:stylesheet> It almost works, the problem I have is to retrieve the correct DATA node from the path specified in the "nodeName" attribute value of the STRUCT block.

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  • Removing elements using XSLT 1.0

    - by pmdarrow
    I'm attempting to remove Component elements from the XML below that have File children with the extension "config." I've managed to do this part, but I also need to remove the matching ComponentRef elements that have the same IDs as these Components. <Fragment> <DirectoryRef Id="MyWebsite"> <Component Id="Comp1"> <File Source="Web.config" /> </Component> <Component Id="Comp2"> <File Source="Default.aspx" /> </Component> </DirectoryRef> </Fragment> <Fragment> <ComponentGroup Id="MyWebsite"> <ComponentRef Id="Comp1" /> <ComponentRef Id="Comp2" /> </ComponentGroup> </Fragment> Based on other SO answers, I've come up with the following XSLT to remove these Component elements: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes" /> <xsl:template match="Component[File[substring(@Source, string-length(@Source)- string-length('config') + 1) = 'config']]" /> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> </xsl:stylesheet> Unfortunately, this doesn't remove the matching ComponentRef elements. The XSLT will remove the component with the Id "Comp1" but not the ComponentRef with Id "Comp1". How do I achieve this using XSLT 1.0?

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  • Optional Fields in Infopath; Getting the xml node with VBA

    - by Sunscreen
    Hi all, I use vb to get data through my form. I have some optional fileds in my form and I have this problem with the following code: MsgBox(myXPathNavigator.SelectSingleNode("/my:Status/my:Questions/my:Questions1", _ Me.NamespaceManager).IsNode.ToString) When the optional filed 'Questions1' is inserted to the form I get the value 'true' by the IsNode function. If the field it is not inserted I have an exception, stating that the reference is not correct (and it is indeed true). Is there a way to verify about a node, whether it is present or not in my form? Thanks in advance, Sun

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  • XML parsing and transforming (XSLT or otherwise)

    - by observ
    I have several xml files that are formated this way: <ROOT> <OBJECT> <identity> <id>123</id> </identity> <child2 attr = "aa">32</child2> <child3> <childOfChild3 att1="aaa" att2="bbb" att3="CCC">LN</childOfChild3> </child3> <child4> <child5> <child6>3ddf</child6> <child7> <childOfChild7 att31="RR">1231</childOfChild7> </child7> </child5> </child4> </OBJECT> <OBJECT> <identity> <id>124</id> </identity> <child2 attr = "bb">212</child2> <child3> <childOfChild3 att1="ee" att2="ccc" att3="EREA">OP</childOfChild3> </child3> <child4> <child5> <child6>213r</child6> <child7> <childOfChild7 att31="EE">1233</childOfChild7> </child7> </child5> </child4> </OBJECT> </ROOT> How can i format it this way?: <ROOT> <OBJECT> <id>123</id> <child2>32</child2> <attr>aa</attr> <child3></child3> <childOfChild3>LN</childOfChild3> <att1>aaa</att1> <att2>bbb</att2> <att3>CCC</att3> <child4></child4> <child5></child5> <child6>3ddf</child6> <child7></child7> <childOfChild7>1231</childOfChild7> <att31>RR</att31> </OBJECT> <OBJECT> <id>124</id> <child2>212</child2> <attr>bb</attr> <child3></child3> <childOfChild3>LN</childOfChild3> <att1>ee</att1> <att2>ccc</att2> <att3>EREA</att3> <child4></child4> <child5></child5> <child6>213r</child6> <child7></child7> <childOfChild7>1233</childOfChild7> <att31>EE</att31> </OBJECT> </ROOT> I know some C# so maybe a parser there? or some generic xslt? The xml files are some data received from a client, so i can't control the way they are sending it to me. L.E. Basically when i am trying to test this data in excel (for example i want to make sure that the attribute of childOfChild7 corresponds to the correct identity id) i am getting a lot of blank spaces. If i am importing in access to get only the data i want out, i have to do a thousands subqueries to get them all in a nice table. Basically i just want to see for one Object all its data (one object - One row) and then just delete/hide the columns i don't need.

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  • How to get node without children in xQuery?

    - by mbrevoort
    So I have two nodes of elements that I'm essentially trying to join. I want the top level node to stay the same but the child nodes to be replaced by those cross referenced. Given: <stuff> <item foo="foo" boo="1"/> <item foo="bar" boo="2" /> <item foo="baz" boo="3"/> <item foo="blah boo="4""/> </stuff> <list a="1" b="2"> <foo>bar</foo> <foo>baz</foo> </list> I want to loop through "list" and cross reference elements in "stuff" for this result: <list a="1" b="2"> <item foo="bar" boo="2" /> <item foo="baz" boo="3"/> </list> I want to do this without having to know about what attributes might be on "list". In other words I don't want to have to explicitly call them out like attribute a { $list/@a }, attribute b { $list/@b }

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  • etree.findall: 'OR'-lookup?

    - by piquadrat
    I want to find all stylesheet definitions in a XHTML file with lxml.etree.findall. This could be as simple as elems = tree.findall('link[@rel="stylesheet"]') + tree.findall('style') But the problem with CSS style definitions is that the order matters, e.g. <link rel="stylesheet" type="text/css" href="/media/css/first.css" /> <style>body:{font-size: 10px;}</style> <link rel="stylesheet" type="text/css" href="/media/css/second.css" /> if the contents of the style tag is applied after the rules in the two link tags, the result may be completely different from the one where the rules are applied in order of definition. So, how would I do a lookup that inlcudes both link[@rel="stylesheet"] and style?

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  • Tentative date casting in tsql

    - by Tewr
    I am looking for something like TRYCAST in TSQL or an equivalent method / hack. In my case I am extracting some date data from an xml column. The following query throws "Arithmetic overflow error converting expression to data type datetime." if the piece of data found in the xml cannot be converted to datetime (in this specific case, the date is "0001-01-01" in some cases). Is there a way to detect this exception before it occurs? select [CustomerInfo].value('(//*:InceptionDate/text())[1]', 'datetime') FROM Customers An example of what I am trying to achieve in pseudocode with an imagined tsql function TRYCAST(expr, totype, defaultvalue): select TRYCAST( [CustomerInfo].value('(//*:InceptionDate/text())[1]', 'nvarchar(100)'), datetime, null) FROM Customers

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  • Removing related elements using XSLT 1.0

    - by pmdarrow
    I'm attempting to remove Component elements from the XML below that have File children with the extension "config." I've managed to do this part, but I also need to remove the matching ComponentRef elements that have the same "Id" values as these Components. <Fragment> <DirectoryRef Id="MyWebsite"> <Component Id="Comp1"> <File Source="Web.config" /> </Component> <Component Id="Comp2"> <File Source="Default.aspx" /> </Component> </DirectoryRef> </Fragment> <Fragment> <ComponentGroup Id="MyWebsite"> <ComponentRef Id="Comp1" /> <ComponentRef Id="Comp2" /> </ComponentGroup> </Fragment> Based on other SO answers, I've come up with the following XSLT to remove these Component elements: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" indent="yes" /> <xsl:template match="Component[File[substring(@Source, string-length(@Source)- string-length('config') + 1) = 'config']]" /> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> </xsl:stylesheet> Unfortunately, this doesn't remove the matching ComponentRef elements (i.e. those that have the same "Id" values). The XSLT will remove the component with the Id "Comp1" but not the ComponentRef with Id "Comp1". How do I achieve this using XSLT 1.0?

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  • get xml attribute named xlink:href using xsl

    - by awe
    How can I get the value of an attribute called xlink:href of an xml node in xsl template? I have this xml node: <DCPType> <HTTP> <Get> <OnlineResource test="hello" xlink:href="http://localhost/wms/default.aspx" xmlns:xlink="http://www.w3.org/1999/xlink" xlink:type="simple" /> </Get> </HTTP> </DCPType> When I try the following xsl, I get an error saying "Prefix 'xlink' is not defined." : <xsl:value-of select="DCPType/HTTP/Get/OnlineResource/@xlink:href" /> When I try this simple attribute, it works: <xsl:value-of select="DCPType/HTTP/Get/OnlineResource/@test" />

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  • Fastest way to parse XML files in C#?

    - by LifeH2O
    I have to load many XML files from internet. But for testing with better speed i downloaded all of them (more than 500 files) of the following format. <player-profile> <personal-information> <id>36</id> <fullname>Adam Gilchrist</fullname> <majorteam>Australia</majorteam> <nickname>Gilchrist</nickname> <shortName>A Gilchrist</shortName> <dateofbirth>Nov 14, 1971</dateofbirth> <battingstyle>Left-hand bat</battingstyle> <bowlingstyle>Right-arm offbreak</bowlingstyle> <role>Wicket-Keeper</role> <teams-played-for>Western Australia, New South Wales, ICC World XI, Deccan Chargers, Australia</teams-played-for> <iplteam>Deccan Chargers</iplteam> </personal-information> <batting-statistics> <odi-stats> <matchtype>ODI</matchtype> <matches>287</matches> <innings>279</innings> <notouts>11</notouts> <runsscored>9619</runsscored> <highestscore>172</highestscore> <ballstaken>9922</ballstaken> <sixes>149</sixes> <fours>1000+</fours> <ducks>0</ducks> <fifties>55</fifties> <catches>417</catches> <stumpings>55</stumpings> <hundreds>16</hundreds> <strikerate>96.95</strikerate> <average>35.89</average> </odi-stats> <test-stats> . . . </test-stats> <t20-stats> . . . </t20-stats> <ipl-stats> . . . </ipl-stats> </batting-statistics> <bowling-statistics> <odi-stats> . . . </odi-stats> <test-stats> . . . </test-stats> <t20-stats> . . . </t20-stats> <ipl-stats> . . . </ipl-stats> </bowling-statistics> </player-profile> I am using XmlNodeList list = _document.SelectNodes("/player-profile/batting-statistics/odi-stats"); And then loop this list with foreach as foreach (XmlNode stats in list) { _btMatchType = GetInnerString(stats, "matchtype"); //it returns null string if node not availible . . . . _btAvg = Convert.ToDouble(stats["average"].InnerText); } Even i am loading all files offline, parsing is very slow Is there any good faster way to parse them? Or is it problem with SQL? I am saving all extracted data from XML to database using DataSets, TableAdapters with insert command. I

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  • Switching languajes on a website with PHP

    - by jnkrois
    Hello everybody, I'm just looking for some advice. I'm creating a website that offers (at least) 2 languages. The way I'm setting it up is by using XML files for the language, PHP to retrieve the values in the XML nodes. Say you have any XML file, being loaded as follows: <?php $lang = "en"; $xmlFile = simplexml_load_file("$lang/main.xml"); ?> Once the file contents are available, I just output each node into an HTML tag like so: <li><?php echo $xmlFile->navigation->home; ?></li> which in turn is equal to : <li><a href="#">Home</a></li> as a nav bar link. Now, the way in which I'm switching languages is by changing the value of the "$lang" variable, through a "$_POST", like so: if(isset($_POST['es'])){ $lang = "es"; }elseif(isset($_POST['en'])){ $lang = "en"; } The value of the "$lang" variable is reset and the new file is loaded, loading as well all the new nodes from the new XML file, hence changing the language. I'm just wondering if there is another way to reset the "$lang" variable using something else, other than "$_POST" or "$_GET". I don't want to use query string either. I know I could use JavaScript or jQuery to achieve this, but I'd like to make the site not too dependable on JavaScript. I'd appreciate any ideas or advice. Thanks

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  • how to get entire document in scrapy using hxs.select

    - by Chris Smith
    I've been at this for 12hrs and I'm hoping someone can give me a leg up. Here is my code all I want is to get the anchor and url of every link on a page as it crawls along. from scrapy.contrib.spiders import CrawlSpider, Rule from scrapy.contrib.linkextractors.sgml import SgmlLinkExtractor from scrapy.selector import HtmlXPathSelector from scrapy.utils.url import urljoin_rfc from scrapy.utils.response import get_base_url from urlparse import urljoin #from scrapy.item import Item from tutorial.items import DmozItem class HopitaloneSpider(CrawlSpider): name = 'dmoz' allowed_domains = ['domain.co.uk'] start_urls = [ 'http://www.domain.co.uk' ] rules = ( #Rule(SgmlLinkExtractor(allow='>example\.org', )), Rule(SgmlLinkExtractor(allow=('\w+$', )), callback='parse_item', follow=True), ) user_agent = 'Mozilla/5.0 (Windows; U; MSIE 9.0; WIndows NT 9.0; en-US))' def parse_item(self, response): #self.log('Hi, this is an item page! %s' % response.url) hxs = HtmlXPathSelector(response) #print response.url sites = hxs.select('//html') #item = DmozItem() items = [] for site in sites: item = DmozItem() item['title'] = site.select('a/text()').extract() item['link'] = site.select('a/@href').extract() items.append(item) return items What I'm doing wrong... my eyes hurt now.

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  • Scrapy Not Returning Additonal Info from Scraped Link in Item via Request Callback

    - by zoonosis
    Basically the code below scrapes the first 5 items of a table. One of the fields is another href and clicking on that href provides more info which I want to collect and add to the original item. So parse is supposed to pass the semi populated item to parse_next_page which then scrapes the next bit and should return the completed item back to parse Running the code below only returns the info collected in parse If I change the return items to return request I get a completed item with all 3 "things" but I only get 1 of the rows, not all 5. Im sure its something simple, I just can't see it. class ThingSpider(BaseSpider): name = "thing" allowed_domains = ["somepage.com"] start_urls = [ "http://www.somepage.com" ] def parse(self, response): hxs = HtmlXPathSelector(response) items = [] for x in range (1,6): item = ScrapyItem() str_selector = '//tr[@name="row{0}"]'.format(x) item['thing1'] = hxs.select(str_selector")]/a/text()').extract() item['thing2'] = hxs.select(str_selector")]/a/@href').extract() print 'hello' request = Request("www.nextpage.com", callback=self.parse_next_page,meta={'item':item}) print 'hello2' request.meta['item'] = item items.append(item) return items def parse_next_page(self, response): print 'stuff' hxs = HtmlXPathSelector(response) item = response.meta['item'] item['thing3'] = hxs.select('//div/ul/li[1]/span[2]/text()').extract() return item

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  • Does an XPathDocument load the whole xml document?

    - by Wires
    If I do XPathDocument doc = new XPathDocument("filename.xml"); Does that load the entire document into memory? I'm writing a mobile phone app and the document might store lots of data that doesn't ever need to all be loaded at the same time. Mobile phones don't usually have too much ram!

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  • XDocument change all attribute names

    - by Dested
    I have an XDocument that looks similar to <root> <a> <b foo="1" bar="2" /> <b foo="3" bar="4" /> <b foo="5" bar="6" /> <b foo="7" bar="8" /> <b foo="9" bar="10" /> </a> </root> I wish to change the attribute foo to something else, and the attribute bar to something else. How can I easily do this? My current version (below) stack overflows with large documents, and has an awful smell to it. string dd=LoadedXDocument.ToString(); foreach (var s in AttributeReplacements) dd = dd.Replace(s.Old+"=", s.New+"=");

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  • Using XSLT to Find Nodes Given a Set of Parameters

    - by davecardwell
    Sorry about the title—wasn’t sure how to word it. Basically I have some XML like this: <countries> <country handle="bangladesh"/> <country handle="india"/> <country handle="pakistan"/> </countries> And some XSLT like this (which doesn’t work): <xsl:template match="/countries"> <xsl:param name="popular"/> <xsl:apply-templates select="country[count($popular/country[@handle = current()/@handle]) &gt; 0]" /> </xsl:template> <xsl:template match="/countries/country"> … </xsl:template> I want to pass in a list of popular destinations like this: <popular> <country handle="india"/> <country handle="pakistan"/> </popular> …to the /countries template and have it only operate on the ones in the $popular param. At the moment this simply does nothing. Changing the selector to country[true()] operates on them all, so at least I know the basic structure is right. Any ideas? I think I may be getting confused by what is currently “current()”.

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