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  • How to pass content in response from Exception filter in Asp.net WebAPI?

    - by jaffa
    Consider following code: My problem is: 1) I can't seem to cast the errors to HttpContent 2) I can't use the CreateContent extension method as this doesn't exist on the context.Response.Content.CreateContent public class ServiceLayerExceptionFilter : ExceptionFilterAttribute { public override void OnException(HttpActionExecutedContext context) { if (context.Response == null) { var exception = context.Exception as ModelValidationException; if ( exception != null ) { var modelState = new ModelStateDictionary(); modelState.AddModelError(exception.Key, exception.Description); var errors = modelState.SelectMany(x => x.Value.Errors).Select(x => x.ErrorMessage); // Cannot cast errors to HttpContent?? // var resp = new HttpResponseMessage(HttpStatusCode.BadRequest) {Content = errors}; // throw new HttpResponseException(resp); // Cannot create response from extension method?? //context.Response.Content.CreateContent } else { context.Response = new HttpResponseMessage(context.Exception.ConvertToHttpStatus()); } } base.OnException(context); } }

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  • How can you ask a sensitive work question anonymously but still inform readers of your credibility a

    - by Rob
    I would like to request opinions about my career/situation at work with a software development project. I would like to ask anonymously or created a new stackoverflow.com account because I think I may be identified by co-workers at my employer since I have referred them to (non-sensititive) technical questions I have asked here. So they might know my account and be able to follow my activity. If I create a new account it will have no reputation and some readers may ignore it, for example, because they might think that the user only wishes to take ideas from here and not contribute, i.e. not a committed stackoverflow poster. What are your thoughts? (I do feel that it is appropriate to ask such pogramming career/situational questions here as many others have and there are some good questions -and answers and it seems that the stackoverflow community accepts such questions even thought the site's strict guidelines are for specific answers and not discussion, and non-subjective questions. And thank goodness that is the case - not all problems faced by programmers are about the craft but also the human factors around it - where else would folks go?)

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  • JSF, writeAttribute("value", str, null) fails with strings obtained through ValueExpression.getValue

    - by Roma
    Hello, I'm having a somewhat weird problem with custom JSF component. Here's my renderer code: public class Test extends Renderer { public void encodeBegin(final FacesContext context, final UIComponent component) throws IOException { ResponseWriter writer = context.getResponseWriter(); writer.startElement("textarea", component); String clientId = component.getClientId(context); if (clientId != null) writer.writeAttribute("name", clientId, null); ValueExpression exp = component.getValueExpression("value"); if (exp != null && exp.getValue(context.getELContext()) != null) { String val = (String) exp.getValue(context.getELContext()); System.out.println("Value: " + val); writer.writeAttribute("value", val, null); } writer.endElement("textarea"); writer.flush(); } } The code generates: <textarea name="j_id2:j_id12:j_id19" value=""></textarea> Property binding contains "test" and as it should be, "Value: test" is successfully printed to console. Now, if I change the code to: public void encodeBegin(final FacesContext context, final UIComponent component) throws IOException { ResponseWriter writer = context.getResponseWriter(); writer.startElement("textarea", component); String clientId = component.getClientId(context); if (clientId != null) writer.writeAttribute("name", clientId, null); ValueExpression exp = component.getValueExpression("value"); if (exp != null && exp.getValue(context.getELContext()) != null) { String val = (String) exp.getValue(context.getELContext()); String str = "new string"; System.out.println("Value1: " + val + ", Value2: " + str); writer.writeAttribute("value", str, null); } writer.endElement("textarea"); writer.flush(); } generated html is: <textarea name="j_id2:j_id12:j_id19" value="new string"></textarea> and console output is "Value1: test, Value2: new string" What's going on here? This doesn't make sense. Why would writeAttribute differentiate between the two strings? Additional info: The component extends UIComponentBase I am using it with facelets

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  • Can't use method return value in write context--how to fix for include_once?

    - by Bill Paetzke
    I'm getting this error in CodeIgniter when trying to load the email library: Can't use method return value in write context It's happening on line 827 of Loader.php in [codeigniter root]/system/libraries/Loader.php include_once($filepath); where $filepath equals "/var/www/system/libraries/Email.php" I called it like this in another php file: $this->load->library('email'); where $this is the CodeIgniter instance. According to the CodeIgniter email doc page, I'm doing it right. But it's not working...

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  • How to find WindowRef of Apple Help Viewer application?

    - by Mark
    Hi, In my Carbon application upon display of Preference Panes, I have a link which when clicked opens up Apple Help Viewer. The problem I am facing is the Help Viewer Window is behind my preference pane window. I would like to keep the Help Viewer window on top of the Preference Pane. Is there any way to get the WindowRef of the Help Viewer app so that I can use SendBehind API to send the help viewer behind the current window. Thanks a lot Regards, Marc

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  • How do i set Savepoints for Linq to SQL and use "NO" ExecuteCommand ?

    - by nik
    TransactionScope TransactionABC = new TransactionScope(); try { context.Connection.Open(); { context.ExecuteCommand("insert into test (test) values (1)") context.SubmitChanges(); context.ExecuteCommand("savepoint test"); context.ExecuteCommand("insert into test (test) values (2)") context.SubmitChanges(); context.ExecuteCommand("rollback to test"); } TransactionABC.Complete(); TransactionABC.Dispose(); } catch (Exception ec) { MessageBox.Show(" ", ec.Message); } finally { context.Connection.Close(); } It works, but only with ExecuteCommand. I want to use a function, because i can't see what happens in the savepoint !

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  • How to build a control programatically?

    - by W_K
    I have custom control written in Java. For the sake of simplicity lets assume that it looks like this: public class HelloworldControl extends UIComponentBase { @Override public void decode(FacesContext context) { String cid = this.getClientId(context); ... super.decode(context); } @Override public void encodeBegin(FacesContext context) throws IOException { ResponseWriter writer = context.getResponseWriter(); writer.writeText("Hello world!", this); // I want a view!! } @Override public void encodeEnd(FacesContext context) throws IOException { ResponseWriter writer = context.getResponseWriter(); ... } public void restoreState(FacesContext context, Object state) { Object values[] = (Object[]) state; ... super.restoreState(context, values[0]); } public Object saveState(FacesContext context) { Object values[] = ... } } I would like to add programatically child control to it. For example I would like a child view control to render a view just under the Hellow world text. How can i do this? What is the standard procedure to build dynamically a control? To put it simply - I want programatically build a hierarchy of standard components and I want to attach it to my control.

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  • Missing part of the image when taking screenshot while supporting Retina Display

    - by Spaft
    I'm currently working on enabling support for retina display for my game. In the game, we have a feature that the user can take screenshot. We are using these part of code we found online a while ago and it's working fine when we are not supporting retina display: CCDirector* director = [CCDirector sharedDirector]; CGSize size = [director winSizeInPixels]; //Create buffer for pixels GLuint bufferLength = size.width * size.height * 4; GLubyte* buffer = (GLubyte*)malloc(bufferLength); //Read Pixels from OpenGL glReadPixels(0, 100, size.width, size.height, GL_RGBA, GL_UNSIGNED_BYTE, buffer); //Make data provider with data. CGDataProviderRef provider = CGDataProviderCreateWithData(NULL, buffer, bufferLength, NULL); //Configure image int bitsPerComponent = 8; int bitsPerPixel = 32; int bytesPerRow = 4 * size.width; CGColorSpaceRef colorSpaceRef = CGColorSpaceCreateDeviceRGB(); CGBitmapInfo bitmapInfo = kCGBitmapByteOrderDefault; CGColorRenderingIntent renderingIntent = kCGRenderingIntentDefault; CGImageRef iref = CGImageCreate(size.width, size.height, bitsPerComponent, bitsPerPixel, bytesPerRow, colorSpaceRef, bitmapInfo, provider, NULL, NO, renderingIntent); uint32_t* pixels = (uint32_t*)malloc(bufferLength); CGContextRef context = CGBitmapContextCreate(pixels, size.width, size.height, 8, size.width * 4, CGImageGetColorSpace(iref), kCGImageAlphaPremultipliedLast | kCGBitmapByteOrder32Big); CGContextTranslateCTM(context, 0, size.height); CGContextScaleCTM(context, 1.0f, -1.0f); switch (director.deviceOrientation) { case CCDeviceOrientationPortrait: break; case CCDeviceOrientationPortraitUpsideDown: CGContextRotateCTM(context, CC_DEGREES_TO_RADIANS(180)); CGContextTranslateCTM(context, -size.width, -size.height); break; case CCDeviceOrientationLandscapeLeft: CGContextRotateCTM(context, CC_DEGREES_TO_RADIANS(-90)); CGContextTranslateCTM(context, -size.width, 0); break; case CCDeviceOrientationLandscapeRight: CGContextRotateCTM(context, CC_DEGREES_TO_RADIANS(90)); CGContextTranslateCTM(context, size.width * 0.5f, -size.height); break; } CGContextDrawImage(context, CGRectMake(0.0f, 0.0f, size.width, size.height), iref); UIImage *outputImage = [UIImage imageWithCGImage:CGBitmapContextCreateImage(context)]; //Dealloc CGDataProviderRelease(provider); CGImageRelease(iref); CGContextRelease(context); free(buffer); free(pixels); return outputImage; But when we enabled retina display in cocos 0.99.5. This functionality is a little messed up since it will miss a little left part of the image while the high is still correct. So I'm wondering if there is anything wrong with the code or am I doing anything wrong here? Thank you in advance for any reply!

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  • How to re-enable the context menu in this case?

    - by lemonedo
    document.addEventListener('contextmenu', function (e) { e.preventDefault() e.stopPropagation() e.returnValue = false e.cancleBubble = true }) No way? Edit: document.oncontextmenu = null does not work. P.S. I cannot have the reference of the listener function since I am not the owner of the site preventing the context menu.

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  • Better way to download a binary file?

    - by geoff
    I have a site where a user can download a file. Some files are extremely large (the largest being 323 MB). When I test it to try and download this file I get an out of memory exception. The only way I know to download the file is below. The reason I'm using the code below is because the URL is encoded and I can't let the user link directly to the file. Is there another way to download this file without having to read the whole thing into a byte array? FileStream fs = new FileStream(context.Server.MapPath(url), FileMode.Open, FileAccess.Read); BinaryReader br = new BinaryReader(fs); long numBytes = new FileInfo(context.Server.MapPath(url)).Length; byte[] bytes = br.ReadBytes((int) numBytes); string filename = Path.GetFileName(url); context.Response.Buffer = true; context.Response.Charset = ""; context.Response.Cache.SetCacheability(HttpCacheability.NoCache); context.Response.ContentType = "application/x-rar-compressed"; context.Response.AddHeader("content-disposition", "attachment;filename=" + filename); context.Response.BinaryWrite(bytes); context.Response.Flush(); context.Response.End();

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