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  • Why can't Perl's WWW::Machanize find the form by field names?

    - by FRESHTER
    #!/usr/bin/perl use WWW::Mechanize; use Compress::Zlib; my $mech = WWW::Mechanize->new(); my $username = ""; #fill in username here my $keyword = ""; #fill in password here my $mobile = $ARGV[0]; my $text = $ARGV[1]; $deb = 1; print length($text)."\n" if($deb); $text = $text."\n\n\n\n\n" if(length($text) < 135); $mech->get("http://wwwl.way2sms.com/content/index.html"); unless($mech->success()) { exit; } $dest = $mech->response->content; print "Fetching...\n" if($deb); if($mech->response->header("Content-Encoding") eq "gzip") { $dest = Compress::Zlib::memGunzip($dest); $mech->update_html($dest); } $dest =~ s/<form name="loginForm"/<form action='..\/auth.cl' name="loginForm"/g; $mech->update_html($dest); $mech->form_with_fields(("username","password")); $mech->field("username",$username); $mech->field("password",$keyword); print "Loggin...\n" if($deb); $mech->submit_form(); $dest= $mech->response->content; if($mech->response->header("Content-Encoding") eq "gzip") { $dest = Compress::Zlib::memGunzip($dest); $mech->update_html($dest); } $mech->get("http://wwwl.way2sms.com//jsp/InstantSMS.jsp?val=0"); $dest= $mech->response->content; if($mech->response->header("Content-Encoding") eq "gzip") { $dest = Compress::Zlib::memGunzip($dest); $mech->update_html($dest); } print "Sending ... \n" if($deb); $mech->form_with_fields(("MobNo","textArea")); $mech->field("MobNo",$mobile); $mech->field("textArea",$text); $mech->submit_form(); if($mech->success()) { print "Done \n" if($deb); } else { print "Failed \n" if($deb); exit; } $dest = $mech->response->content; if($mech->response->header("Content-Encoding") eq "gzip") { $dest = Compress::Zlib::memGunzip($dest); #print $dest if($deb); } if($dest =~ m/successfully/sig) { print "Message sent successfully" if($deb); } exit; When run this code halts with an error saying: There is no form with the requested fields at ./sms.pl line 65 Can't call method "value" on an undefined value at /usr/share/perl5/vendor_perl/WWW/Mechanize.pm line 1348.

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  • How can I create a user registration form using datastore - google appengine ??

    - by srivigneshwar
    I am very new to jsp and google appengine , but still I can do something if I get some basic idea , I wanna create an user registration form with fields like name, user id , password, confirm password, etc,. using google appengine datastore feature. and I wanna retrieve user information . Please help me .. Thanks in advance. Thanks for the replies, I need to get some information from user and I want to store it in database, and I will use that information for my application. How can I do that?

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  • how to add a entry to tables with relationships?

    - by siulamvictor
    I have 2 models, Users & Accounts. They are in one-to-many relationship, i.e. each accounts have many users. Accounts company_id company_name company_website Users user_id user_name password company_id email How can I add these entries to database using ActiveRecord? Supposed I don't is the company existed in the database when I add a new entry. Name Email Password Company ----------------------------------------------------------------------------- Albert [email protected] 123456 ABC Company Betty [email protected] 234567 ABC Company Carmen [email protected] 765432 XXX Company David [email protected] 654321 ABC Company

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  • How to retrieve the GUID for Yahoo's Contacts API

    - by Jack Marchetti
    I'm attemping to use the Yahoo Contacts API to add an "invite your friends" feature on a site I'm building. I've found the correct web service to call (http://social.yahooapis.com/v1/user/{guid}/contacts) but it is asking for the user's GUID, not their username/password. I've searched, and am unable to find a "lookup" feature through the Yahoo API which lets me get the user's guid from their username/password. Does anyone have any experience with the Contacts API. I've reaad over the documentation, and looked at YQL as well, but I still haven't found how to get the user's guid. Thanks guys.

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  • automatic enter login credentials while testing my app (from visual studio 2008)

    - by Michel
    Hi all, this is something that i don't want to program, but i was looking for a handy way of logging on to my web app. i'm building (and testing and running) my webapp over and over again, and here i've been provided a strong password. needless to say it's not so nice to enter my full user name + strong password 30 times a day. is there a nifty tool which lives in the background and when i open page localhost/mytestpage.aspx, it will say: "hey, let me type in michel and sdfs%^%gfhg in these two textboxes"?

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  • Why always fires OnFailure when return View() to Ajax Form ?

    - by Wahid Bitar
    I'm trying to make a log-in log-off with Ajax supported. I made some logic in my controller to sign the user in and then return simple partial containing welcome message and log-Off ActionLink my Action method looks like this : public ActionResult LogOn(LogOnModel model, string returnUrl) { if (ModelState.IsValid) { if (MembershipService.ValidateUser(model.UserName, model.Password)) { FormsService.SignIn(model.UserName, model.RememberMe); if (Request.IsAjaxRequest()) { //HERE IS THE PROBLEM :( return View("LogedInForm"); } else { if (!String.IsNullOrEmpty(returnUrl)) return Redirect(returnUrl); else return RedirectToAction("Index", "Home"); } } else { ModelState.AddModelError("", "The user name or password provided is incorrect."); if (Request.IsAjaxRequest()) { return Content("There were an error !"); } } } return View(model); } and I'm trying to return this simple partial : Welcome <b><%= Html.Encode(Model.UserName)%></b>! <%= Html.ActionLink("Log Off", "LogOff", "Account") %> and of-course the two partial are strongly-typed to LogOnModel. But if i returned View("PartialName") i always get OnFailure with status code 500. While if i returned Content("My Message") everything is going right. so please tell me why i always get this "StatusCode = 500" ??. where is the big mistake ??. By the way in my Site MasterPage i rendered partial to show long-on simple form this partial looks like this : <script type="text/javascript"> function ShowErrorMessage(ajaxContext) { var response = ajaxContext.get_response(); var statusCode = response.get_statusCode(); alert("Sorry, the request failed with status code " + statusCode); } function ShowSuccessMessage() { alert("Hey everything is OK!"); } </script> <div id="logedInDiv"> </div> <% using (Ajax.BeginForm("LogOn", "Account", new AjaxOptions { UpdateTargetId = "logedInDiv", InsertionMode = InsertionMode.Replace, OnSuccess = "ShowSuccessMessage", OnFailure = "ShowErrorMessage" })) { %> <%= Html.TextBoxFor(m => m.UserName)%> <%= Html.PasswordFor(m => m.Password)%> <%= Html.CheckBoxFor(m => m.RememberMe)%> <input type="submit" value="Log On" /> < <% } %>

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  • How to get the result for return statement from JSON parsing?

    - by blankon91
    I've follow the code for parsing the value with JSON from here, but I get the problem in my return statement. I want to put the parsing result into my return statement. How to do that? Here is my code: public String MASUK(String user, String password) { SoapObject request = new SoapObject(WSDL_TARGET_NAMESPACE,OPERATION_NAME); PropertyInfo pi = new PropertyInfo(); pi.setName("ccduser"); pi.setValue(user); pi.setType(String.class); request.addProperty(pi); PropertyInfo pi2 = new PropertyInfo(); pi2.setName("password"); pi2.setValue(password); pi2.setType(String.class); request.addProperty(pi2); SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); envelope.dotNet = true; envelope.setOutputSoapObject(request); HttpTransportSE httpTransport = new HttpTransportSE(SOAP_ADDRESS); try { httpTransport.call(SOAP_ACTION, envelope); SoapObject resultSOAP = (SoapObject) envelope.bodyIn; /* gets our result in JSON String */ String ResultObject = resultSOAP.getProperty(0).toString(); resultSOAP = (SoapObject) envelope.bodyIn; ResultObject = resultSOAP.getProperty(0).toString(); if (ResultObject.startsWith("{")) { // if JSON string is an object JSONObj = new JSONObject(ResultObject); Iterator<String> itr = JSONObj.keys(); while (itr.hasNext()) { String Key = (String) itr.next(); String Value = JSONObj.getString(Key); BundleResult.putString(Key, Value); // System.out.println(bundleResult.getString(Key)); } } else if (ResultObject.startsWith("[")) { // if JSON string is an array JSONArr = new JSONArray(ResultObject); System.out.println("length" + JSONArr.length()); for (int i = 0; i < JSONArr.length(); i++) { JSONObj = (JSONObject) JSONArr.get(i); BundleResult.putString(String.valueOf(i), JSONObj.toString()); // System.out.println(bundleResult.getString(i)); } } } catch (Exception exception) { } return null; }

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  • PHP multiuser login class or script

    - by FFish
    I am looking for a simple but secure login script with mySQL PHP: sessions, MD5 that I can use with my exsisting database. Cookies to store password + password recovery by email. Change login/pass. I do not need registering, I register the user myself with temp login/pass. table agents agent1 agent2 table albums album1, owner: agent1 album2, owner: agent1 album3, owner: agent2 ... login.php agent1 logs in and has access to his albums: - album1 - album2 agent1 can edit his albums: edit.php?ref=album1 but NOT edit.php?ref=album3 by changing the ?ref variable

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  • Consume restful webservice through web proxy

    - by Chico
    Hello, I'm trying to consume a restful webservice in java using the Apache Wink framework through my school web proxy requiring authentification ClientConfig clientConfig = new ClientConfig(); clientConfig.proxyHost("proxy.school.com"); clientConfig.proxyPort(3128); //nothing to set username and password :( RestClient client = new RestClient(clientConfig); Resource resource = client.resource("http://vimeo.com/api/v2/artist/videos.xml"); String response = resource.accept("text/plain").get(String.class); I've also tried to use the BasicAuthSecurityHandler but it seems to be used to authenticate directly to a web server, not the web proxy BasicAuthSecurityHandler basicAuthHandler = new BasicAuthSecurityHandler(); basicAuthHandler.setUserName("username"); basicAuthHandler.setPassword("password"); config.handlers(basicAuthHandler); It still fail with a HTTP 407 error code : Proxy Authentication Required. I've googled the best I could, nothing came up better to consume a webservice from a Java client through a web proxy, if someone has another idea, feel free to respond

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  • How to read an XML file with Java?

    - by Yatendra Goel
    I don't need to read complex XML files. I just want to read the following configuration file with a simplest XML reader <config> <db-host>localhost</db-host> <db-port>3306</db-port> <db-username>root</db-username> <db-password>root</db-password> <db-name>cash</db-name> </config> How to read the above XML file with a XML reader through Java?

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  • How to get JSON back from HTTP POST Request (to another domain)

    - by roman m
    I'm trying to use the API on a website, here's the part of the manual: Authenticated Sessions (taken from here) To create an authenticated session, you need to request an authToken from the '/auth' API resource. URL: http://stage.amee.com/auth (this is not my domain) Method: POST Request format: application/x-www-form-urlencoded Response format: application/xml, application/json Response code: 200 OK Response body: Details of the authenticated user, including API version. Extra data: "authToken" cookie and header, containing the authentication token that should be used for subsequent calls. Parameters: username / password Example Request POST /auth HTTP/1.1 Accept: application/xml Content-Type: application/x-www-form-urlencoded username=my_username&password=my_password Response HTTP/1.1 200 OK Set-Cookie: authToken=1KVARbypAjxLGViZ0Cg+UskZEHmqVkhx/Pm...; authToken: 1KVARbypAjxLGViZ0Cg+UskZEHmqVkhx/PmEvzkPGp...== Content-Type: application/xml; charset=UTF-8 QUESTION: How do I get that to work? I tried jQuery, but it seems to have problem with XSS. Actual code snippet would be greatly appreciated. p.s. All I was looking for was WebClient class in C#

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  • Killing Mysql prcoesses staying in sleep command.

    - by Shino88
    Hey I am connecting a MYSQL database through hibernate and i seem to have processes that are not being killed after they are finished in the session. I have called flush and close on each session but when i check the server the last processes are still there with a sleep command. This is a new problem which i am having and was not the case yesterday. Is there any way i can ensure the killng of theses processes when i am done with a session. Below is an example of one of my classes. public JSONObject check() { //creates a new session needed to add elements to a database Session session = null; //holds the result of the check in the database JSONObject check = new JSONObject(); try{ //creates a new session needed to add elements to a database SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory(); session = sessionFactory.openSession(); if (justusername){ //query created to select a username from user table String hquery = "Select username from User user Where username = ? "; //query created Query query = session.createQuery(hquery); //sets the username of the query the values JSONObject contents query.setString(0, username); // executes query and adds username string variable String user = (String) query.uniqueResult(); //checks to see if result is found (null if not found) if (user == null) { //adds false to Jobject if not found check.put("indatabase", "false"); } else { check.put("indatabase", "true"); } //adds check to Jobject to say just to check username check.put("justusername", true); } else { //query created to select a username and password from user table String hquery = "Select username from User user Where username = :user and password = :pass "; Query query = session.createQuery(hquery); query.setString("user", username); query.setString("pass", password); String user = (String) query.uniqueResult(); if(user ==null) { check.put("indatabase", false); } else { check.put("indatabase", true); } check.put("justusername", false); } }catch(Exception e){ System.out.println(e.getMessage()); //logg.log(Level.WARNING, " Exception", e.getMessage()); }finally{ // Actual contact insertion will happen at this step session.flush(); session.close(); } //returns Jobject return check; }

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  • how to show all method and data when the object not has "__iter__" function in python..

    - by zjm1126
    i find a way : (1):the dir(object) is : a="['__class__', '__contains__', '__delattr__', '__delitem__', '__dict__', '__doc__', '__getattribute__', '__getitem__', '__hash__', '__init__', '__iter__', '__metaclass__', '__module__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__setattr__', '__setitem__', '__str__', '__weakref__', '_errors', '_fields', '_prefix', '_unbound_fields', 'confirm', 'data', 'email', 'errors', 'password', 'populate_obj', 'process', 'username', 'validate']" (2): b=eval(a) (3)and it became a list of all method : ['__class__', '__contains__', '__delattr__', '__delitem__', '__dict__', '__doc__', '__getattribute__', '__getitem__', '__hash__', '__init__', '__iter__', '__metaclass__', '__module__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__setattr__', '__setitem__', '__str__', '__weakref__', '_errors', '_fields', '_prefix', '_unbound_fields', 'confirm', 'data', 'email', 'errors', 'password', 'populate_obj', 'process', 'username', 'validate'] (3)then show the object's method,and all code is : s='' a=eval(str(dir(object))) for i in a: s+=str(i)+':'+str(object[i]) print s but it show error : KeyError: '__class__' so how to make my code running . thanks

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  • My PowerShell functions do not appear to be registered

    - by Frank
    Hi there, I have a script saved in a ps1 file in which I define 2 functions as such: function Invoke-Sql([string]$query) { Invoke-Sqlcmd -ServerInstance $Server -Database $DB -User $User -Password $Password -Query $query } function Get-Queued { Invoke-Sql "Select * From Comment where AwaitsModeration = 1" } In the PowerShell console I then call the ps1 file by typing it in (it's in a folder in the path, and autocompletion works) However, I cannot start using the functions. I am confused, because when I copy / paste the functions into the console, all is fine and they work. I also have a function defined in my profile, and it works. Where am I thinking wrong, why doesn't it work what I'm trying to do?

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  • ASP.NET plug-in architecture, settings problem

    - by Xaqron
    I want to divide business layer (BLL) of an asp.net application into multiple components. Each component is a .NET class library which is compiled as a standalone DLL. These components should have their own configuration files. For example "MyNameSpace.Users.dll" contains classes about users of the website and there's a password policy to check if password length is at least x characters. When webmaster edits the config file of this DLL and set x to y then component (DLL) should use new value (y) in the future and enforce passwords to be at least y characters. I want each component as a single project and compile them separaely (and not to put all projects in a solution in Visual Studio), and put the DLLs of these libraries into the "Bin" folder of my ASP.NET application. Is it possible ? Where should I put these config files ?

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  • htaccess/htpasswd in hierarchical folder structure

    - by chessweb
    I have a folder (folder_1) that is protected by htaccess/htpasswd files. Inside that folder is another folder (folder_2) that is protected by another couple of htaccess/htpasswd files. When a php-script in folder_1 or folder_2 is called, the user has to authenticate herself using the correct username and password as specified in the respective htaccess/htpasswd files. This works as intended. However, as soon as the php-script in folder_2 tries to refer to another script or a css-file that is located in folder_1, the user must enter username and password for folder_1 as well. Is there a way to avoid this that does not involve copying scripts and css-files from folder_1 to folder_2? Regards, Ralf

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  • loading an asp after starting a session

    - by Noam Smadja
    the jQuery $("#loginform").submit(function(){ $.ajax({ type: "POST", url: "loginrespajax.asp", data: $("#loginform").serialize(), success: function(){ $("#loginform").hide("slow"); $("#loginform").load("userheader.asp"); $("#loginform").show("slow"); } }); }); thats userheader.asp <div class="userlinks"> <%if (session("userlevel")) then%> <% select case session("userlevel") case 1 %> <a href="managenews.asp"><%langstring("header_news")%></a> | <a href="managebooks.asp"><%langstring("header_books")%></a> | <a href="manageusers.asp"><%langstring("manage_users")%></a> | <a href="manageorders.asp"><%langstring("manage_orders")%></a> | <a href="managelanguage.asp"><%langstring("manage_language")%></a> | <a href="youthregistration.asp"><%langstring("youthreg_header")%></a> | <a href="manageregistrants.asp"><%langstring("youthlist_header")%></a> | <% case 2 %> <a href="managenews.asp"><%langstring("header_news")%></a> | <a href="managebooks.asp"><%langstring("header_books")%></a> | <a href="youthregistration.asp"><%langstring("youthreg_header")%></a> | <a href="manageregistrants.asp"><%langstring("youthlist_header")%></a> | <% case 3 %> <a href="youthregistration.asp"><%langstring("youthreg_header")%></a> | <a href="manageregistrants.asp"><%langstring("youthlist_header")%></a> | <% End select %> <a href="editprofile.asp"><%langstring("editprofile_header")%></a> | <a href="changepassword.asp"><%langstring("changepassword_header")%></a> | <a href="logout.asp"><%langstring("logout_header")%></a> <%else%> <form action="loginrespajax.asp" method="POST" name="loginform" id="loginform" class="loginform" onSubmit="return false;"> <input type="text" name="username" value="username" class="input inline" onFocus="clearText(this);"> <input type="password" name="password" value="password" class="input inline" onFocus="clearText(this);"> <input type="submit" value="Log In" class="submit inline"> </form> <%End if%> </div> i am submiting the login form using AJAX and the jQuery partially works. it does hide and show again. but it prints the ELSE part of in userheader.asp. the session does start, for sure :)

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  • Pros / Cons displaying list of users at login page

    - by Radu094
    We seem to have a lot of clients asking us to change the login screen in this manner: Display a list of all available users (thumbnail picture + name) User selects a username from the list A password prompt appears near the username User enters password then presses enter This sounds remarcably similar to the Windows XP login, which is probably where they got the ideea in the first place. There are only about 4 - 5 different users that can login at any given station, so implementing that list on one screen is feasable. So I was wondering if there are any usability experts with some word on this method of login. As far as I can tell, MS droped this behaviour in Vista/Win7, didn't they?

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  • PHP secure logon script - md5 hash is not matching the hash i wrote to the database in a previous sc

    - by Chris Sobolewski
    I am trying to cobble together a login script in PHP as a learning project. This is the code for my database write when the user registers. Both of these values are written to the database. $this->salt = md5(uniqid()); $this->password = md5($password.$salt); Upon logging in, the following function is fired. For some function challengeLogin($submittedPassword, $publicSalt, $storedPassword){ if(md5($submittedPassword.$publicSalt) == $actualPassword){ return 0; }else{ return 1; }; } Unfortunately, on stepping through my code, the two values have never equaled. Can someone help me understand why?

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  • How to clone a mercurial repository over an ssh connection initiated by fabric when http authorizati

    - by Monika Sulik
    I'm attempting to use fabric for the first time and I really like it so far, but at a certain point in my deployment script I want to clone a mercurial repository. When I get to that point I get an error: err: abort: http authorization required My repository requires http authorization and fabric doesn't prompt me for the user and password. I can get around this by changing my repository address from: https://hostname/repository to: https://user:password@hostname/repository But for various reasons I would prefer not to go this route. Are there any other ways in which I could bypass this problem?

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  • MySQLi Prepared Statement Query Issue

    - by Benjamin Flak
    I'm relatively new to MySQLi prepared statements, and running into an error. Take this code: $user = 'admin'; $pass = 'admin'; if ($stmt = $mysqli->query("SELECT * FROM members WHERE username='$user' AND password='$pass'")) { echo $stmt->num_rows; } This will display "1", as it should. This next piece of code though, returns "0": $user = 'admin'; $pass = 'admin'; if ($stmt = $mysqli->prepare("SELECT * FROM members WHERE username=? AND password=?")) { $stmt->bind_param("ss", $user, $pass); $stmt->execute(); echo $stmt->num_rows; } Any ideas why?

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  • how to include in web.config an external mydll.config file and read its values?

    - by firepol
    Hi, I found this answer about external configuration files. I'm trying to do a similar thing. I have a small webapplication called StatsGen I want to include in other projects, and for convenience I'd like to have the settings inside the bin folder, in a config file with an appropriate name, in my case: StatsGen.config. So I've put these line in the web.config (as explained in the answer I mentioned above): <configSections> <section name="StatsGenSettings" restartOnExternalChanges="true" type="System.Configuration.NameValueFileSectionHandler" /> <!--sectionGroups--> </configSections> <StatsGenSettings configSource="StatsGen.config"></StatsGenSettings> <!--and here comes the rest... appSettings etc.--> Inside the bin folder, I created a StatsGen.xml file, then renamed it to StatsGen.config. It looks like this: <?xml version="1.0" encoding="utf-8" ?> <StatsGenSettings> <add key="Password" value="myStatsPass" /> <add key="ConnectionString" value="Server=mydbsrv;Database=myDB;User ID=myUser;Password=myPass" /> </StatsGenSettings> I created an Helper class, as suggested in the answer. In the Page_Load of my default.aspx.cs file, I've put: goodPassword = StatsGenSettings.Instance["Password"]; When I load my page, I get this error: The type initializer for 'StatsGen.Helpers.StatsGenSettings' threw an exception. I've tried to exlude the helper and just to get access to the key, like this: NameValueCollection _settings = ConfigurationManager.GetSection("StatsGenSettings") as NameValueCollection; And I get this error: Unable to open configSource file 'StatsGen.config'. (C:\Users\pbo\Documents\Visual Studio 2010\Projects\StatsGen\StatsGen\web.config line 21) At line 21 I just have this, as explained above: <StatsGenSettings configSource="StatsGen.config"></StatsGenSettings> So now I'm wondering, what's wrong? Some detailed help would be cool... like: where exactly should I declare the StatsGenSettings element inside the web.config? It was not specified in the answer I've found... or what else am I doing wrong? Thanks for letting me know...

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  • Why do LINQ to Entities does not recognize certain Methods?

    - by Luiscencio
    Why cant I do this: usuariosEntities usersDB = new usuariosEntities(); foreach (DataGridViewRow user in dgvUsuarios.Rows) { var rowtoupdate = usersDB.usuarios.Where( u => u.codigo_usuario == Convert.ToInt32(user.Cells[0].Value) ).First(); rowtoupdate.password = user.Cells[3].Value.ToString(); } usersDB.SaveChanges(); And have to do this: usuariosEntities usersDB = new usuariosEntities(); foreach (DataGridViewRow user in dgvUsuarios.Rows) { int usercode = Convert.ToInt32(user.Cells[0].Value); var rowtoupdate = usersDB.usuarios.Where(u => u.codigo_usuario == usercode).First(); rowtoupdate.password = user.Cells[3].Value.ToString(); } usersDB.SaveChanges(); I must admint it is a more readable code but why cant this be done?

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