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  • Django: Only one of two fields can be filled in

    - by Giovanni Di Milia
    I have this model: class Journals(models.Model): jid = models.AutoField(primary_key=True) code = models.CharField("Code", max_length=50) name = models.CharField("Name", max_length=2000) publisher = models.CharField("Publisher", max_length=2000) price_euro = models.CharField("Euro", max_length=2000) price_dollars = models.CharField("Dollars", max_length=2000) Is there a way to let people fill out either price_euro or price_dollars? I do know that the best way to solve the problem is to have only one field and another table that specify the currency, but I have constraints and I cannot modify the DB. Thanks!

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  • django admin site make CharField a PasswordInput

    - by Paul
    I have a Django site in which the site admin inputs their Twitter Username/Password in order to use the Twitter API. The Model is set up like this: class TwitterUser(models.Model): screen_name = models.CharField(max_length=100) password = models.CharField(max_length=255) def __unicode__(self): return self.screen_name I need the Admin site to display the password field as a password input, but can't seem to figure out how to do it. I have tried using a ModelAdmin class, a ModelAdmin with a ModelForm, but can't seem to figure out how to make django display that form as a password input...

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  • jqgrid and django models

    - by Andrew Gee
    Hi, I have the following models class Employee(Person): job = model.Charfield(max_length=200) class Address(models.Model): street = models.CharField(max_length=200) city = models.CharField(max_length=200) class EmpAddress(Address): date_occupied = models.DateField() date_vacated = models.DateField() employee = models.ForeignKey() When I build a json data structure for an EmpAddress object using the django serialzer it does not include the inherited fields only the EmpAddress fields. I know the fields are available in the object in my view as I can print them but they are not built into the json structure. Does anyone know how to overcome this? Thanks Andrew

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  • Pass object using JSON

    - by Pankaj
    Hello All right now i am using Json for passing status and message like return Json(new { Success = true, Message = "Save successfully" }); Project model=new Project() Is there any way, i can send model in json also? I am using c# and asp.net mvc

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  • How To Implement The Query Side Of CQS in DDD?

    - by Laz
    I have implemented the command side of DDD using the domain model and repositories, but how do I implement the query side? Do I create an entirely new domain model for the UI, and where is this kept in the project structure...in the domain layer, the UI layer, etc? Also, what do I use as my querying mechanism, do I create new repositories specifically for the UI domain objects, something other than repositories, or something else?

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  • I get error "A potentially dangerous Request.Form value was detected from the client" inspite of the

    - by VJ
    I am using ASP.NET 4.0 and MVC 2 I have added these lines which i found in other articles - To the Web-Config - <httpRuntime requestValidationMode="2.0"/> To the Controller - <ValidateInput(False), AcceptVerbs(HttpVerbs.Post)> To the View Page - <%@ Page ValidateRequest="false" %> But still gives me "A potentially dangerous Request.Form value was detected from the client" I am trying to use the Markitp editor in this way - <%= Html.TextAreaFor( model => model.Description,"markitup")%>

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  • Rails, Deleting Children without Deleting Parent using :has_many

    - by Dex
    I have a model called MyContainer, which :has_many MyObjects. I want to delete all the MyObjects in the container without having to delete the MyContainer. My model does have :dependent = :destroy, however I don't want to have to delete and re-create the object because it is slower. Something like this does not work: @obj = MyContainer.find_by_id(10) @obj.my_objects.delete_all How can I accomplish this?

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  • Understanding Smarty and MVC Frameworks

    - by Korrupzion
    Hello there, I just created this thread to discuss with people who have adopted the smarty system, and how many time it took to you to understand it, because i just can't get the idea, instead of making every easier as everybody says i think it just make more complex to code. More than a problem with only smarty is with the whole MVC model, with CakePHP or KohanaPHP i experience the same problems, u need to do 3x lines of code and files for something that u can do with a few lines of simple php. Maybe u can tell how did u learned to code using MVC model :)

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  • django sync db question

    - by Hulk
    In django models say this model exist in details/models.py class OccDetails(models.Model): title = models.CharField(max_length = 255) occ = models.ForeignKey(Occ) So when sync db is made the following fields get created and later to this of two more fields are added and sync db is made the new fields doesnt get created.How is this to be solved,Also what is auto_now=true in the below these are the new fields created_date = models.DateTimeField(auto_now_add=True) modified_date = models.DateTimeField(auto_now_add=True, auto_now=True)

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  • wierd FileField url in admin site

    - by panchicore
    My model class TheFile(models.Model): document = models.FileField(upload_to="archivos") The wierd HTML admin link: <a hacking_google_maps_and_google_earth.pdf="" archivos="" media="" localhost:8000="" http:="" href="" target="_blank">archivos/Hacking_Google_Maps_And_Google_Earth.pdf</a> If I firebug-edit the href="" it works :S

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  • Ruby on Rails testing: How can I test or at the very least see a form_for's error_messages_for?

    - by williamjones
    I'm working on creating a tests, and I can't figure out why the creation of a model from a form_for is failing in the test but works in real browsers. Is there a straightforward way for me to see what the problems are in the model creation? Even better would be, is there a straightforward way for me to test the error outputs that I access via error_messages_for? In that case, I'd like to also add in tests that make sure that malformed forms are outputting the correct errors.

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  • How to read the selected items in an Html.ListBox at postback time

    - by EasyTimer
    I have a search page on my MVC site that contains a list of strings that I think the user might wish to search for in my database. This list of strings is available in my model class, so I can populate an Html.ListBox with those strings thus: <%=Html.ListBox("SearchStrings", new SelectList(Model.SearchStrings)) % My problem is, how can I tell which strings the user selected in that list in my postback action? Any help would be most appreciated.

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  • What are some models that you know of for PHP OOP?

    - by Doug
    I recently learned a lot about MVC model which is a very interesting concept. I would assume there are a lot more models out there, and I thought it would be great for people to share some models. Here's my contribution: MVC Model: http://en.wikipedia.org/wiki/Model%E2%80%93view%E2%80%93controller

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  • Rails Controller

    - by Steve
    Hi...In Rails, is it ok to define logic in a controller with a model. For example, take there is an User Model, which is good design. 1)Leaving the UserModel with the CRUD models and moving all the other User Specific actions to a separate controller or 2)Add the user specific actions to the same UserModels Thanks :)

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  • MySQL Workbench - How to synchronize the EER Diagram

    - by Tiago Alves
    I am creating a visual representation of my existing database with MySQL Workbench and I am able to synchronize the models with the "Database - Synchronize Model..." menu. However, every time I synchronize (update) my model, I have to recreate the EER Diagram and rearrange all the tables. Is there a way to update or synchronize the EER Diagram as well? Thanks.

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  • Django ForeignKey created empty?

    - by Scott Willman
    This seems very basic and I must be missing something, but here goes anyways... With two models like so: class School(models.Model): name = models.CharField("Official School Name", max_length=128) address = models.TextField("Address of the School", max_length=256) mascot = models.CharField("Name of the School Mascot", max_length=128) class StudentProfile(models.Model): name = models.CharField(max_length=128) school = models.ForeignKey(School) If the student gets created before the school, how do I give 'school' a default empty value? Is it blank or null or what? Thanks!

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  • Sockets receiving null (Android)

    - by Henrik
    I have a android app that is communicating with a server (written in java). Between these two parts I have established a Socket connection and want to send data. The problem I am having is that sometimes, for some users, the information that reaches the server is null. This works (for all phones, all users): Server: int a = Integer.parseInt(in.readLine()); int b = Integer.parseInt(in.readLine()); int c = Integer.parseInt(in.readLine()); int d = Integer.parseInt(in.readLine()); String checksum = in.readLine(); String model = in.readLine(); String device = in.readLine(); String name = in.readLine(); Client: out.println(a); out.println(b); out.println(c); out.println(d); out.println(hash); out.println(Build.MODEL); out.println(Build.DEVICE); String name = fixName(); out.print(name); out.flush(); This does not work (for some users): Server: int a = Integer.parseInt(in.readLine()); String checksum = in.readLine(); String model = in.readLine(); String device = in.readLine(); String name = in.readLine(); String msg = in.readLine(); int version = -1; String test = "hej"; try{ test = in.readLine(); version = Integer.parseInt(test); }catch(Exception e){ e.printStackTrace(); } Client: out.println(a); out.println(hash); out.println(Build.MODEL); out.println(Build.DEVICE); String name = fixName(); if(name == null) name = "John Doe"; out.println(name); String msg = fixMsg(); if(msg == null) name = "nada"; out.println(msg); out.println(curversion); out.flush(); Sometimes, in the second case, the name, msg, and version (the string test) are null at the server side. The catch is triggered because test is null. curversion,a are ints, the rest are strings. Any ideas?

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  • how to count all distinct records in many-to-many relations in django ORM?

    - by marduk-pl
    hi, i have two models: class Project(models.Model): categories = models.ManyToManyField(Category) class Category(models.Model): name = models.CharField() now, i make some queryset: query = Project.objects.filter(id__in=[1,2,3,4]) and i like to get list of all distinct categories in this queryset with count of projects with refering to these categories - exactly i would like to get that results: category1 - 10 projects category2 - 5 projects that is opposite to this query: query2 = query.annotate(Count('categories')) what return me: project1 - 2categories project2 - 7categories how can i make it in django ORM?

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  • Modeling Tools that understand both Relational and LDAP

    - by jm04469
    I am looking to do some modeling and would like to have a tool that can capture not only a relational model like ERWIN but also allow us to easily port to LDAP as an option. NOTE: Visio can connect to an existing LDAP server and draw, but does not allow for you to model first and then deploy, unlike its relational capabilities.

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  • How Can I Populate Default Form Data with a ManyToMany Field?

    - by b14ck
    Ok, I've been crawling google and Django documentation for over 2 hours now (as well as the IRC channel on freenode), and haven't been able to figure this one out. Basically, I have a model called Room, which is displayed below: class Room(models.Model): """ A `Partyline` room. Rooms on the `Partyline`s are like mini-chatrooms. Each room has a variable amount of `Caller`s, and usually a moderator of some sort. Each `Partyline` has many rooms, and it is common for `Caller`s to join multiple rooms over the duration of their call. """ LIVE = 0 PRIVATE = 1 ONE_ON_ONE = 2 UNCENSORED = 3 BULLETIN_BOARD = 4 CHILL = 5 PHONE_BOOTH = 6 TYPE_CHOICES = ( ('LR', 'Live Room'), ('PR', 'Private Room'), ('UR', 'Uncensored Room'), ) type = models.CharField('Room Type', max_length=2, choices=TYPE_CHOICES) number = models.IntegerField('Room Number') partyline = models.ForeignKey(Partyline) owner = models.ForeignKey(User, blank=True, null=True) bans = models.ManyToManyField(Caller, blank=True, null=True) def __unicode__(self): return "%s - %s %d" % (self.partyline.name, self.type, self.number) I've also got a forms.py which has the following ModelForm to represent my Room model: from django.forms import ModelForm from partyline_portal.rooms.models import Room class RoomForm(ModelForm): class Meta: model = Room I'm creating a view which allows administrators to edit a given Room object. Here's my view (so far): def edit_room(request, id=None): """ Edit various attributes of a specific `Room`. Room owners do not have access to this page. They cannot edit the attributes of the `Room`(s) that they control. """ room = get_object_or_404(Room, id=id) if not room.is_owner(request.user): return HttpResponseForbidden('Forbidden.') if is_user_type(request.user, ['admin']): form_type = RoomForm elif is_user_type(request.user, ['lm']): form_type = LineManagerEditRoomForm elif is_user_type(request.user, ['lo']): form_type = LineOwnerEditRoomForm if request.method == 'POST': form = form_type(request.POST, instance=room) if form.is_valid(): if 'owner' in form.cleaned_data: room.owner = form.cleaned_data['owner'] room.save() else: defaults = {'type': room.type, 'number': room.number, 'partyline': room.partyline.id} if room.owner: defaults['owner'] = room.owner.id if room.bans: defaults['bans'] = room.bans.all() ### this does not work properly! form = form_type(defaults, instance=room) variables = RequestContext(request, {'form': form, 'room': room}) return render_to_response('portal/rooms/edit.html', variables) Now, this view works fine when I view the page. It shows all of the form attributes, and all of the default values are filled in (when users do a GET)... EXCEPT for the default values for the ManyToMany field 'bans'. Basically, if an admins clicks on a Room object to edit, the page they go to will show all of the Rooms default values except for the 'bans'. No matter what I do, I can't find a way to get Django to display the currently 'banned users' for the Room object. Here is the line of code that needs to be changed (from the view): defaults = {'type': room.type, 'number': room.number, 'partyline': room.partyline.id} if room.owner: defaults['owner'] = room.owner.id if room.bans: defaults['bans'] = room.bans.all() ### this does not work properly! There must be some other syntax I have to use to specify the default value for the 'bans' field. I've really been pulling my hair out on this one, and would definitely appreciate some help. Thanks!

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  • Recommended NetBeans UML plugins

    - by Thomas Owens
    It appears that the NetBeans UML plugin has been discontinued, as per a discussion on the NetBeans forums. This was a great, free tool with nice model-code and code-model generation. There are a number of other UML NetBeans plugins out there. However, I've never used any of them. Any suggestions?

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