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  • Creating new table entry when updating another entry of another table - Ruby on Rails

    - by Michaël
    Hi, I have written this code in my "show" view of estimates and I want that, when submitting (update), it creates a new repairs (Repair.new(???)) with some parameters. I don't know where to write the "new repairs" code, in this view or the controller (in update part). I need that the Repair is created one time, not each time the @estimate is updated. <% form_for @estimate, :url => {:controller => "estimates", :action => "update"} do |f| %> <%= f.error_messages %> <select id="estimate_accept" name="estimate[accept]"> <option value="1" selected="selected">accept</option> <option value="2">refuse</option> </select> <%= f.submit "Update" %> <% end %> Thank you for your help, I hope my explanations are clear!

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  • SSL + Jquery + Ajax

    - by chobo2
    Hi I starting too look at a bit of security into my site. My site I would consider a very low security risk as it has really no personal information from the user other than email. However the security risk will go up a bit as I am partnering with a company and the initial password for this companies users will be the same password they use essentially to get onto the network and every piece of software. So I have up my security( what is fine by me...I wanted to get around to this anyways). So one of my security concerns is this. A user logs in. form submit(non ajax is done). Password is hashed & Salted and compared to one in the database. Reject or let them proceed. So this uses no jquery or ajax but is just asp.net mvc and C#. Still if my understanding is right the password is sent in clear text. So if a use SSL and I would not need to worry about that is this correct? If that is true is that all I need? Second the user can change their password at anytime. This is done through ajax. So when the password is sent it is sent in clear text( and I can verify this by looking at firebug). So if I have SSL enabled on this page is that all I need or do I need to do more? So I am just kinda confused of what I need to make the password being sent to the server(both ajax and full post ways secure). I am not sure if I need to do more then SSL or if that is enough and if it is not enough what is the next layer of security?

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  • Address family not supported by protocol exception

    - by srg
    I'm trying to send a couple of values from an android application to a web service which I've setup. I'm using Http Post to send them but when I run the application I get the error- request time failed java.net.SocketException: Address family not supported by protocol. I get this while debugging with both the emulator as well as a device connected by wifi. I've already added the internet permission using: <uses-permission android:name="android.permission.INTERNET" /> This is the code i'm using to send the values void insertData(String name, String number) throws Exception { String url = "http://192.168.0.12:8000/testapp/default/call/run/insertdbdata/"; HttpClient client = new DefaultHttpClient(); HttpPost post = new HttpPost(url); try { List<NameValuePair> params = new ArrayList<NameValuePair>(2); params.add(new BasicNameValuePair("a", name)); params.add(new BasicNameValuePair("b", number)); post.setEntity(new UrlEncodedFormEntity(params)); HttpResponse response = client.execute(post); }catch(Exception e){ e.printStackTrace(); } Also I know that my web service work fine because when I send the values from an html page it works fine - <form name="form1" action="http://192.168.0.12:8000/testapp/default/call/run/insertdbdata/" method="post"> <input type="text" name="a"/> <input type="text" name="b"/> <input type="submit"/> I've seen questions of similar problems but haven't really found a solution. Thanks

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  • Insert Stored Procedure does not Create Database Record

    - by SidC
    Hello All, I have the following stored procedure: ALTER PROCEDURE Pro_members_Insert @id int outPut, @LoginName nvarchar(50), @Password nvarchar(15), @FirstName nvarchar(100), @LastName nvarchar(100), @signupDate smalldatetime, @Company nvarchar(100), @Phone nvarchar(50), @Email nvarchar(150), @Address nvarchar(255), @PostalCode nvarchar(10), @State_Province nvarchar(100), @City nvarchar(50), @countryCode nvarchar(4), @active bit, @activationCode nvarchar(50) AS declare @usName as varchar(50) set @usName='' select @usName=isnull(LoginName,'') from members where LoginName=@LoginName if @usName <> '' begin set @ID=-3 RAISERROR('User Already exist.', 16, 1) return end set @usName='' select @usName=isnull(email,'') from members where Email=@Email if @usName <> '' begin set @ID=-4 RAISERROR('Email Already exist.', 16, 1) return end declare @MemID as int select @memID=isnull(max(ID),0)+1 from members INSERT INTO members ( id, LoginName, Password, FirstName, LastName, signupDate, Company, Phone, Email, Address, PostalCode, State_Province, City, countryCode, active,activationCode) VALUES ( @Memid, @LoginName, @Password, @FirstName, @LastName, @signupDate, @Company, @Phone, @Email, @Address, @PostalCode, @State_Province, @City, @countryCode, @active,@activationCode) if @@error <> 0 set @ID=-1 else set @id=@memID Note that I've "inherited" this sproc and the database. I am trying to insert a new record from my signup.aspx page. My SQLDataSource is as follows: <asp:SqlDataSource runat="server" ID="dsAddMember" ConnectionString="rmsdbuser" InsertCommandType="StoredProcedure" InsertCommand="Pro_members_Insert" ProviderName="System.Data.SqlClient"> The click handler for btnSave is as follows: Protected Sub btnSave_Click(ByVal sender As Object, ByVal e As EventArgs) Handles btnSave.Click Try dsAddMember.DataBind() Catch ex As Exception End Try End Sub When I run this page, signup.aspx, provide required fields and click submit, the page simply reloads and the database table does not reflect the newly-inserted record. Questions: 1. How do I catch the error messages that might be returned from the sproc? 2. Please advise how to change signup.aspx so that the insert occurs. Thanks, Sid

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  • HTML: Nesting DIVs problem

    - by mawg
    I am coding a form generator. So far, so good, then I decided to give it a real test. I made a form with some nested each holding a few controls. I will post the HTML at the end. If you load it into a browser, it renders, but is obviously wrong. I had previously tested using the W3C validator and things were fine, but that was for non nested. When I validate a form with nested I get errors: Error Line 13, Column 117: document type does not allow element "DIV" here …style="position: absolute; top:88px; left: 256px; width: 145px; height: 21px;"> So, how do I correct that? What do I do with nested FIELDSETs? Here's the complete HTML <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN""http://www.w3.org/TR/html4/strict.dtd"> <html> <head> <title></title> <meta http-equiv="Content-type" content="text/html;charset=UTF-8"> </head> <body> <form action="C:\temp\an_elogger_test.php" method="get"><div class="TGroupBox" id="GroupBox1"> <fieldset style="position: absolute; top:24px; left:24px; width: 449px; height: 473px;"> <legend>GroupBox1</legend> <div class="TPanel" id="Panel1"> <fieldset style="position: absolute; top:64px; left:64px; width: 361px; height: 217px;"> <div class="TComboBox" id="ComboBox1" style="position: absolute; top:88px; left: 256px; width: 145px; height: 21px;"> <select name="ComboBox1"> </select> </div> <div class="TGroupBox" id="GroupBox2"> <fieldset style="position: absolute; top:80px; left:88px; width: 145px; height: 177px;"> <legend>GroupBox2</legend> <div class="TCheckBox" id="CheckBox1" style="position: absolute; top:112px; left: 104px; width: 97px; height: 17px;">CheckBox1<input type="checkbox" name="CheckBox1" value="CheckBox1Checked"></div> <div class="TCheckBox" id="CheckBox2" style="position: absolute; top:152px; left: 112px; width: 97px; height: 17px;">CheckBox2<input type="checkbox" name="CheckBox2" value="CheckBox2Checked"checked="checked"></div> </fieldset> </div> <div class="TRadioGroup" id="RadioGroup2"> <fieldset style="position: absolute; top:128px; left: 264px; width: 145px; height: 137px;"><legend>RadioGroup2</legend> eins: <input type="radio" name="RadioGroup2" value="eins" checked><br> zwei: <input type="radio" name="RadioGroup2" value="zwei"><br> drei: <input type="radio" name="RadioGroup2" value="drei"><br> </fieldset> </div> </fieldset> </div> <div class="TMemo" id="Memo1"><textarea name="Memo1" rows="8" cols="13" style="position: absolute; top:320px; left: 88px; width: 185px; height: 89px;"> </textarea> </div> <div class="TComboBox" id="ComboBox2" style="position: absolute; top:328px; left: 296px; width: 145px; height: 21px;"> <select name="ComboBox2"> <option value="a">a</option> <option value="b">b</option> <option value="c">c</option> <option value="d" selected="selected">d</option> <option value="e">e</option> </select> </div> </fieldset> </div> <div class="TPanel" id="Panel2"> <fieldset style="position: absolute; top:32px; left:520px; width: 425px; height: 449px;"> <div class="TPanel" id="Panel3"> <fieldset style="position: absolute; top:64px; left:552px; width: 345px; height: 185px;"> <div class="TMemo" id="Memo2"><textarea name="Memo2" rows="8" cols="13" style="position: absolute; top:88px; left: 584px; width: 185px; height: 89px;"> You may wish to leave this memo emptyOr perpahaps give instructions aboout what should be written here</textarea> </div> <div class="TEdit" id="Edit1" style="position: absolute; top:200px; left: 600px; width: 121px; height: 21px;"><input type="text" name="Edit1"value="Insert text here"></div> </fieldset> </div> <div class="TGroupBox" id="GroupBox3"> <fieldset style="position: absolute; top:272px; left:552px; width: 345px; height: 185px;"> <legend>GroupBox3</legend> <div class="TPanel" id="Panel4"> <fieldset style="position: absolute; top:304px; left:584px; width: 177px; height: 137px;"> <div class="TRadioGroup" id="RadioGroup1"> <fieldset style="position: absolute; top:312px; left: 600px; width: 97px; height: 105px;"><legend>RadioGroup1</legend> one: <input type="radio" name="RadioGroup1" value="one"><br> two: <input type="radio" name="RadioGroup1" value="two" checked><br> three: <input type="radio" name="RadioGroup1" value="three"><br> </fieldset> </div> </fieldset> </div> <div class="TEdit" id="Edit2" style="position: absolute; top:320px; left: 776px; width: 105px; height: 21px;"><input type="text" name="Edit2"></div> </fieldset> </div> </fieldset> </div> <div align="center" style="margin: auto"><input type="submit" name="submitButton" value="Submit" style="position:absolute;top:522px;"></div> </form> </body> </html>

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  • Dynamic TextBox on LinkButton click

    - by Alex Peta
    I am creating dynamic TextBoxes in a page by clicking a LinkButton. However, after that, if the page is submitted, I can't find the items created dynamically, thus, can't send the information to the database. protected void lbAddTag_Click(object sender, EventArgs e) { for (int i = 0; i < 3;i++ ) { CreateTextBox("txtTag-" + i.ToString()); } } private void CreateTextBox(string ID) { TextBox txt = new TextBox(); txt.ID = ID; txt.Width = Unit.Pixel(300); //txt.TextChanged += new EventHandler(OnTextChanged); txt.AutoPostBack = false; tagsPanel.Controls.Add(txt); Literal lt = new Literal(); lt.Text = "<br /><br />"; tagsPanel.Controls.Add(lt); } If I put: foreach (Control c in tagsPanel.Controls) { if (c is TextBox) { lblError.Text += c.ClientID + " , "; } } in the lbAddTag_Click method I can see the items, and they exist, but if I submit the page and try to insert the values in the database nothing... Any hint is much appreciated.

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  • jquery append a tr after calling

    - by marharépa
    Hello! I've got a table. <table id="servers" ...> ... {section name=i loop=$ownsites} <tr id="site_id_{$ownsites[i].id}"> ... <td>{$ownsites[i].phone}</td> <td class="icon"><a id="{$ownsites[i].id}" onClick="return makedeleterow(this.getAttribute('id'));" ...></a></td> </tr> {/section} <tbody> </table> And this java script. <script type="text/javascript"> function makedeleterow(id) { $('#delete').remove(); $('#servers').append($(document.createElement("tr")).attr({id: "delete"})); $('#delete').append($(document.createElement("td")).attr({colspan: "9", id: "deleter"})); $('#deleter').text('Biztosan törölni szeretnéd ezt a weblapod?'); $('#deleter').append($(document.createElement("input")).attr({type: "submit", id: id, onClick: "return truedeleterow(this.getAttribute('id'))"})); $('#deleter').append($(document.createElement("input")).attr({type: "hidden", name: "website_del", value: id})); } </script> It's workin fine, it makes a TR after the table's last tr and put the info to it, and the delete also works fine. But i'd like to make this AFTER the tr which calling the script. How can i do this? I've tried it with closest() but not work :(

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  • How to check for a null object reference when validating forms in MVC

    - by quakkels
    Hello SO, I'm experimenting with validating forms in the asp.net MVC framework. I'm focusing on server side validation for the time being. I've come across an error that I'm not sure how to rectify. System.NullReferenceException: Object reference not set to an instance of an object. The code that throws the error is: [AcceptVerbs(HttpVerbs.Post)] public ActionResult Create([Bind(Exclude="ID")] MembersCreate mc ) { mc.Modules = ModuleListDataContext.GetModuleList(); ViewData.Model = mc; //Validation using ModelState // // //line below errors when form field is empty // if ((string)mc.Member.Username.Trim() == "") ModelState.AddModelError("Member.Username", "Username is required."); if (!ModelState.IsValid) return View(); try { // TODO: Add insert logic here return RedirectToAction("Index","Home"); } catch { return View(); } } When I put spaces in the field it performs exactly as i want, but if I leave the field blank and press submit I get the error. What's the best way to avoid this error and still validate blank form fields? Thanks all -

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  • Safari Web Inspector is not updating when I update an element with ajax

    - by Ashley
    I have a checkout page http://www.oipolloi.com/oipolloi/shop/viewbasket.php with multiple ajax calls after certain items update (EG look up postage cost when country is changed, then update discount boxes etc). I've asked for help in the past about the best method of making sure ALL calls have returned before allowing the form to be submitted for payment processing: http://stackoverflow.com/questions/2290372/how-do-i-prevent-form-submission-until-multiple-ajax-calls-have-finished-jquery I was fairly happy that the logic in the finished solution was correct, but I have still been receiving reports that people using Safari are able to submit the form without the ajax calls returning properly. I have tried using the Safari Web Inspector to debug but it seems that when you Inspect Element, then update an element with an ajax call, the Inspector doesn't seem to update. I am updating hidden fields, so it's hard to be able to know whether the problem lies with the DOM not being updated properly, or the Inspector itself. I'm using Safari 4.0.5 on PC and you can reproduce the problem above by looking for a div id="countryFieldsBilling" with Web Inspector. It should contain three hidden fields that are initially empty. You can try to make it update (or not) by choosing a country from the select menu at the bottom of 'Shipping Address' box, and then clicking the 'click to use Shipping Address' link at the top of the 'Billing Address' just below. The behaviour I am seeing is that the country chosen in the shipping select gets copied correctly to the country in the billing select, but the hidden inputs in the Web Inspector do not get updated. When these hidden inputs do not get updated, this causes the problem that Mac Safari users report. If you can let me know either how to get Web Inspector to work properly, or something else I may have missed in the behaviour of Mac Safari that may cause these problems, that would be great. Thanks in advance

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  • Running code/script as a result of a form submission in ASP.NET

    - by firmbeliever
    An outside vendor did some html work for us, and I'm filling in the actual functionality. I have an issue that I need help with. He created a simple html page that is opened as a modal pop-up. It contains a form with a few input fields and a submit button. On submitting, an email should be sent using info from the input fields. I turned his simple html page into a simple aspx page, added runat=server to the form, and added the c# code inside script tags to create and send the email. It technically works but has a big issue. After the information is submitted and the email is sent, the page (which is supposed to just be a modal pop-up type thing) gets reloaded, but it is now no longer a pop-up. It's reloaded as a standalone page. So I'm trying to find out if there is a way to get the form to just execute those few lines of c# code on submission without reloading the form. I'm somewhat aware of cgi scripts, but from what I've read, that can be buggy with IIS and all. Plus I'd like to think I could get these few lines of code to run without creating a separate executable. Any help is greatly appreciated.

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  • How to link different Servlet together?

    - by Harry Pham
    First of all, I did not use Spring MVC. :) :) Just want to get it out first. Now what I have is different JSP pages that making calls to different Servlets. All the pieces work great individually but I kind of need to link them together. If all of jsp pages make GET request then it would be easy, since I would just pass a type via the web address, and on my servlet side, I would just enumerated through all the parameter, determine which type is it, and delegate to the right servlet. But not all jsp pages make GET request, some make POST request via form. Let see example A.jsp $.getJSON('GenericServlet?type=A', ... GenericServlet.java String type = request.getParameter("type"); if(type.equals("A")){ //Somehow delegate to Servlet A (Not sure how to do that yet :)) } but in B.jsp I would have something like this B.jsp <form action="GenericServlet" method="post"> <table border=0 cellspacing=10 cellpadding=0> <tr> <td>User Name:</td> <td><input type="text" name="username" size=22/></td> </tr> <tr> <td>Password:</td> <td><input type="password" name="password" size=22/></td> </tr> </table> <input type="submit" value="Create User" /> </form> It kind of hard for me to determine in GenericServlet.java that this need to go to servletB

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  • jQuery Form Validation being bypassed

    - by user1953681
    Can someone tell me what is wrong with my jQuery validation? It is not validating my form, rather, just ignoring the code resulting in no check of the inputs. Form: <form class="form" accept-charset="UTF-8" action="URL-to-complete-form" method="POST" onsubmit="return validateForm();"> <input class="form-name" type="text" placeholder="Name"></div> <input class="form-email" type="text"placeholder="Email"></div> <input style="background-color: #fc8f12;" type="submit" value="Subscribe"> </div> </form> Javascript: function validateForm() { // Validate Name var title = $(".form-name").val(); if (title=="" ||title=="Name" || title==null) { } else { alert("Please enter a name!"); } // Validate Email var email = $(".form-email").val(); if ((/(.+)@(.+){2,}\.(.+){2,}/.test(email)) || email=="" || email=="Email" || email==null) { } else { alert("Please enter a valid email"); } return false; } Thank you all for your time and help.

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  • confirm alert not working ....

    - by user318068
    I want the work of the Control Panel in my site for members ... I designed the page is displayed all the registered members on my site And i but it checkbox front each member name ,becuase it allowed to select multiple name then click delete button The following code works but now i want confirm alert before delete code working even , if clicked on ok the deletion is working , and if clicked on cancel the is not working .. how i can work it ?? while($row = mysql_fetch_array($sql1)) { ?> <tr> <td align="center" bgcolor="#FFFFFF"><input name="checkbox[]" type="checkbox" id="checkbox[]" value="<?php echo $row['MemberID']; ?>"></td> <td bgcolor="#FFFFFF"><?php echo $row['MemberName']; ; ?></td></tr> <?php } ?> <tr> <td colspan="5" align="center" bgcolor="#FFFFFF"><input name="delete" type="submit" id="delete" value="delete" onclick="javascript:return confirm('are you sure to delete this record???? ')"/></td> </tr> <?php $delete = $_REQUEST['delete']; $checkbox = $_REQUEST['checkbox']; $count = count($_REQUEST['checkbox']); // Check if delete button active, start this if($delete){ echo "<script language=\"Javascript\">\n"; for($i=0;$i<$count;$i++){ $del_id = $checkbox[$i]; $sql = "Delete FROM members where MemberID ='$del_id'"; $sq2 = "Delete FROM joinroom where MemberID ='$del_id'"; $result1 = mysql_query($sql); $result2 = mysql_query($sq2); echo "else {\n"; echo "alert ('Nothing deleted');\n }"; echo "</script>"; } } Thanks a lot.........

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  • JQuery Tabbed Nav Menu and PHP Forms Question?

    - by SlAcKeR
    I'm using a JQuery Tabbed Menu which holds different types of forms and when I select a different form located under a different tab and submit the form the tab will jump to the default tab instead of the current tab the form is located in. I was wondering how would I go about fixing this so that when the form is submitted the current tab is still selected, is it the JQuery or PHP problem? Here is the JQuery. $(document).ready(function() { //When page loads... $(".form-content").hide(); //Hide all content var firstMenu = $("#home-menu ul li:first"); firstMenu.show(); firstMenu.find("a").addClass("selected-link"); //Activate first tab $(".form-content:first").show(); //Show first tab content //On Click Event $("#home-menu ul li").click(function() { $("#home-menu ul li a").removeClass("selected-link"); //Remove any "selected-link" class $(this).find("a").addClass("selected-link"); //Add "selected-link" class to selected tab $(".form-content").hide(); //Hide all tab content var activeTab = $(this).find("a").attr("href"); //Find the href attribute value to identify the selected-link tab + content $(activeTab).fadeIn(); //Fade in the selected-link ID content return false; }); });

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  • Does anyone know of any good open source voting software?

    - by mezoid
    I'm looking for a voting system that we can implement at work amongst our developers. We need something that allows developers to submit ideas about what we can do to improve our development practices (amongst other things) and then have all the developers vote on the ideas to give everyone an idea of what ideas we should attempt to implement first. For example, our developers could list ideas for parts of our code base that should be improved/cleaned up and we'd be able to collectively vote on which parts to start on first. Something like www.uservoice.com might be one way of getting what we need but I'm still wanting to look at alternatives. Unfortunately, googling for voting and polling systems just doesn't seem to bring up any useful results because most of them seem geared towards elections and surveys rather than a way for people to make suggestions and vote on them. Does anyone here know of any sort of software system that might be able to do what I'm looking for? Better yet, does anyone have such a system set up for the developers at their work place? I'd be interested in knowing if it is useful at all.

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  • Creating DOM elements on the fly - check if the data is not harmful

    - by user313353
    I already posted a question closely related to the this one. I watched the Mix10 video with P. Haacked and S. Hanselman. I am building an AJAX-powered site whose input forms are created on the fly. All the code to accomplish this is done within a script tag or a javascript file. For example the following DOM elements are created when the page loads and are wrapped into an existing div defined in a view: $('#myform').append('); $('#myform').append(''); When I click the submit button I need to get the values of the input form whose id is 'Name': $("#Name").val() and then I return a Json object: { Name: name }; For this kind of scenario there is no way to use Html.Encode() or AntiXss.HtmlEncode() on the client-side. The only way to check if the input is not harmful is done on the server-side (via a service layer). This seems a limitation. All is fine if and only if a view has a set of predefined inputs. When it is time to create them on the fly, the situation is different. Have you thought of that situation guys? Thanks for the attention you have put on this. Roland Brussels, Belgium

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  • unable to use html form post in php

    - by kossibox
    Hello i have an html form and i'm posting data but i'm unable to get the posted data on a php page (same page) can you please help me. thanks in advance <div class="left"> <form name="form_signin" method="post" onsubmit="return signinValid();" > <table> <tr> <td> Email : </td> <td> <input type="text" id="email" length ="40"> </td> </tr> <tr> <td> Mot de Passe : </td> <td> <input type="password" id ="pass" length ="40"> </td> </tr> <tr> <td> &nbsp; </td> <td> <input type="submit" value="Connexion" length ="40"> </td> </tr> </table> </form> <?php include 'includes.php'; include DB_CONNECT_FILE; //session_start(); print_r($_POST); // prints an empty array even if fields are filled $smart->assign('tpl_file',TEMPLATES_DIR.'signin.html'); $smart->display(TEMPLATES_DIR."with_right.html"); include DB_DISCONNECT_FILE; ?>

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  • Problem in getting response from server in jquery

    - by Alvin
    Hello, I'm using $.ajax(options) method to pass the request to server based on username and password, but whenever I try to print the response by XMLHttpRequest object when response gets successful, I'm getting an empty value. $(document).ready(function(){ $("#form").submit(function(){ $.ajax({url:"Chat.jsp",type:"POST",data:$("#form").serialize(),success:function(request) { alert(request.responseText); //This is displaying nothing },error:function(){document.write("YOU can't");}}); }); }); This is what I'm doing in my servlets code after executing query: try { String user = request.getParameter("j_username"); String password = request.getParameter("j_password"); if(user != null && password != null) { String query = "Select * from users where user_name="+"\'"+user+"\'"+"&& user_pass="+"\""+password+"\""; DBCheck db= new DBCheck(); boolean b = db.doExecuteQuery(con.createStatement(),query); response.setHeader("Cache-Control", "no-cache"); if(b) { response.getWriter().println("Username already exits"); } else { response.getWriter().println("Username doesn't exit"); } } } catch(SQLException ex) { ex.printStackTrace(); } } May I know the problem, and how can I fix it?

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  • Deploying DotNetNuke and separate ASP.NET Application together - Possible Issues?

    - by TheTXI
    I am making this in a proactive attempt to head off any potential problems which could arise from this. The situation is that we are developing an ASP.NET application for a client which will handle the online ordering from their customers. This application is going to be using the same database that their current WinForms application uses (no real issue here). At the same time we are developing a new front-end website for them using DotNetNuke. The DotNetNuke app will simply be linking to the ASP.NET application for the customers to submit their orders (no need for them to communicate back and forth, etc.) The plan is to host both applications on the same box at the client location. What I am looking for are potential problems or setup tips which would prevent possible conflict between the two apps (web.config conflicts, etc.) Is there a problem with having both hosted on the same location, how should IIS be set up, etc.? If there are any external resources also available which could address this, please feel free to link them as well.

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  • ASP.NET MVC - ValidationSummary set from a different controller

    - by Rap
    I have a HomeController with an Index action that shows the Index.aspx view. It has a username/password login section. When the user clicks the submit button, it POSTs to a Login action in the AccountController. <% Html.BeginForm("Login", "Account", FormMethod.Post); %> In that action, it tests for Username/Password validity and if invalid, sends the user back to the Login page with a message that the credentials were bad. [HttpPost] public ActionResult Login(LoginViewModel Model, string ReturnUrl) { User user = MembershipService.ValidateUser(Model.UserName, Model.Password); if (user != null) { //Detail removed here FormsService.SignIn(user.ToString(), Model.RememberMe); return Redirect(ReturnUrl); } else { ModelState.AddModelError("", "The user name or password provided is incorrect."); } // If we got this far, something failed, redisplay form return RedirectToAction("Index", "Home"); // <-- Here is the problem. ModelState is lost. } But here's the problem: the ValidationSummary is always blank because we're losing the Model when we RedirectToAction. How do I send the user to the action on a different controller without a Redirect?

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  • Drupal: allowing users to sign up to content using a form

    - by james6848
    My apologies if this is a little broad, but I'm struggling to know where to start here! OK, so I have a Drupal site and I need users to be able to sign up for certain content, here is the workflow in detail: I need a form within a block consisting of the following elements: First Name (required) Last Name (required) Organisation (optional) Email Address (required) Then there will be a choice of content to sign up to (using checkboxes): Policy Bulletin Action News eBulletin (which only members can sign up to) Then the usual submit button of course! Upon submission, users will: 1) Be taken to a confirmation page, or 2) Be informed about incorrectly filled in fields, and/or the need to become a user to be able to sign up for the eBulletin. Users will then receive an email when new content of the type(s) they signed up to is created, along with a link to the node. There should be details about how to unsubscribe within this email. I have used the Subscriptions module in the past, but I am not sure if it is possible to use a sign-up form with it. Plus, there is the added complexity that one of the content types, eBulletin, is only available for site members. Like I say, I'm struggling to know where to start, and any ideas would be gratefully received!

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  • Why is my PHP upload script not working?

    - by Turner
    Hello all, I am doing some simple work with uploading a file. I am ignoring error checking and exceptions at this point just to get my uploads working. I have this HTML form: <form action='addResult.php' method='post' enctype='multipart/form-data' target='results_iFrame' onsubmit='startUpload();'> Entry: <input type='text' id='entry' /> Stop: <input type='text' id='stop' /> Final: <input type='text' id='final' /> Chart: <input type='file' id='chart' /> <input type='submit' value='Add' /></form> As you can see, it calls 'addResult.php' within the iFrame 'results_iFrame'. The Javascript is just for animation purposes and to tell me when things are finished. addResult.php has this code in it (along with processing the other inputs): $upload_dir = "../img/"; $chart_loc = $upload_dir.basename($_FILES['chart']['name']); move_uploaded_file($_FILES['chart']['tmp_name'], $chart_loc); print_r($_FILES); It uses the 'chart' input from the form and tries to upload it. I have the print_r() function to display some information on $_FILES, but the array is empty, thus making this fail. What could I be doing wrong?

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  • Cookie blocked/not saved in IFRAME in Internet Explorer

    - by Piskvor
    I have two websites, let's say they're example.com and anotherexample.net. On anotherexample.net/page.html, I have an IFRAME SRC="http://example.com/someform.asp". That IFRAME displays a form for the user to fill out and submit to http://example.com/process.asp. When I open the form ("someform.asp") in its own browser window, all works well. However, when I load someform.asp as an IFRAME in IE 6 or IE 7, the cookies for example.com are not saved. In Firefox this problem doesn't appear. For testing purposes, I've created a similar setup on http://newmoon.wz.cz/test/page.php . example.com uses cookie-based sessions (and there's nothing I can do about that), so without cookies, process.asp won't execute. How do I force IE to save those cookies? Results of sniffing the HTTP traffic: on GET /someform.asp response, there's a valid per-session Set-Cookie header (e.g. Set-Cookie: ASPKSJIUIUGF=JKHJUHVGFYTTYFY), but on POST /process.asp request, there is no Cookie header at all. Edit3: some AJAX+serverside scripting is apparently capable to sidestep the problem, but that looks very much like a bug, plus it opens a whole new set of security holes. I don't want my applications to use a combination of bug+security hole just because it's easy. Edit: the P3P policy was the root cause, full explanation below.

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  • Form validation

    - by kielie
    Hi guys, I need to create a form that has many of the same fields, that have to be inserted into a database, but the problem I have is that if a user only fills in one or two of the rows, the form will still submit the blank data of the empty fields along with the one or two fields the user has filled in. How can I check for the rows that have not been filled in and leave them out of the query? or check for those that have been filled in and add them to the query. . . The thank_you.php file will capture the $_POST variables and add them to the database. <form method="post" action="thank_you.php"> Name: <input type="text" size="28" name="name1" /> E-mail: <input type="text" size="28" name="email1" /> <br /> Name: <input type="text" size="28" name="name2" /> E-mail: <input type="text" size="28" name="email2" /> <br /> Name: <input type="text" size="28" name="name3" /> E-mail: <input type="text" size="28" name="email3" /> <br /> Name: <input type="text" size="28" name="name4" /> E-mail: <input type="text" size="28" name="email4" /> <input type="image" src="images/btn_s.jpg" /> </form> I am assuming that I could use javascript or jQuery to accomplish this, how would I go about doing this? Thanx in advance for the help.

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  • Flex bar chart with Two Y axis

    - by user345522
    I am trying to create a bar char in action 3 script. But for some reason I am getting 2 y-axis and no x axis. Can some one help spot the error. I have said "placement " bottom. The standalone code snippet is below. enter code here [Bindable] public var QUANTITY:ArrayCollection = new ArrayCollection([ {date:"22-Aug-05", quantity:1575.9}, {date:"23-Aug-05", quantity:1603.}, {date:"24-Aug-05", quantity:1507.1}, {date:"25-Aug-05", quantity:1568.8}, ]); private function getBarChartData(evt:MouseEvent):void{ var title:String = "ASDFZXCVB"; var pnlChart:Panel = new Panel(); pnlChart.title = title; pnlChart.height = 750; { var categoryAxisDate:CategoryAxis = new CategoryAxis(); categoryAxisDate.categoryField = "date"; var linearVolumeAxis:LinearAxis = new LinearAxis(); linearVolumeAxis.minimum = 1500; linearVolumeAxis.maximum = 1700; var colChart:ColumnChart = new ColumnChart(); colChart.showDataTips = true; { var horizontalAxisDateRenderer:AxisRenderer = new AxisRenderer(); horizontalAxisDateRenderer.axis = categoryAxisDate; horizontalAxisDateRenderer.placement = "bottom"; var quantityRenderer:AxisRenderer = new AxisRenderer(); quantityRenderer.axis = linearVolumeAxis; quantityRenderer.placement = "left"; colChart.horizontalAxisRenderers.push(horizontalAxisDateRenderer); colChart.verticalAxisRenderers.push(quantityRenderer); { var quantityColumnSeries:ColumnSeries = new ColumnSeries(); quantityColumnSeries.horizontalAxis = categoryAxisDate; quantityColumnSeries.yField="quantity"; quantityColumnSeries.displayName ="QUANTITY"; quantityColumnSeries.dataProvider = QUANTITY; quantityColumnSeries.verticalAxis = linearVolumeAxis; colChart.series.push(quantityColumnSeries); } } pnlChart.addChild(colChart); } canvasReportId.addChild(pnlChart); } ]] <mx:Button label="Submit" click="getBarChartData(event)" x="293" y="4"/> </mx:Canvas>

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