Search Results

Search found 5274 results on 211 pages for 'submit'.

Page 173/211 | < Previous Page | 169 170 171 172 173 174 175 176 177 178 179 180  | Next Page >

  • $_POST in php 5.3.5 does not work

    - by naji
    dear all iam working in php 5.3.5 this is the html file <html> <body> <form action="welcome.php" method="post"> Name: <input type="text" name="fname" /> Age: <input type="text" name="age" /> <input type="submit" /> </form> </body> </html> and this is the php file <html> <body> Welcome <?php echo $_POST["fname"]; ?>!<br /> You are <?php echo $_POST["age"]; ?> years old. </body> </html> the problem the values are not passed and the output like Welcome ! You are years old. But it has to be like this Welcome John! You are 28 years old. can any one help me please?? naji

    Read the article

  • Javascript XMLHttpRequest Post method

    - by user535617
    Hey So I have a question about posting using an XMLHttpRequest. In theory, if I am to post a username and password to an https domain (which I have yet to get working, unfortunately) would the responseText then change to the next website, or should the text fields become filled in? What normally happens is you navigate to this page via browser, enter a username and password, and it uses a POST method when the submit button is clicked, doing some authentication under the hood and returning a different page. I feel like maybe the responseText should even stay exactly the same (which is what happens now), but I don't know as I have no experience with this kind of thing. this.requests[1].open("POST", "https://" + this.address, true); var query = "target=%2Fcgi-bin%2FStatusConfig.cgi%3FPage%3Dindex&userfile=&username=user&password=pass&log+in=Log+in"; this.requests[1].setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); this.requests[1].setRequestHeader("Content-length", query.length); this.requests[1].setRequestHeader("Keep-Alive", 115); this.requests[1].setRequestHeader("Connection", "keep-alive"); this.requests[1].setRequestHeader("Host", this.address); this.requests[1].send(query); this.requests[1].onreadystatechange = onReadyStateChange1; Then basically onReadyStateChange1 displays the responseText when ready. Any light that could be shed on what SHOULD be happening with the post and responseText would be very appreciated. As would any advice in getting the new, logged into page. For further clarification, what I'm trying to do is log in and then return the new page, because the login page displays only log in information/functionality and the page after logging in has a lot of relevant information. I'm not trying to check the credentials as much as I'm trying to get it (the script) to log in so it can access the next page. Granted, the credentials will have to be valid for that. Thanks all.

    Read the article

  • Python - Problems using mechanize to log into a difficult website

    - by user1781599
    × 139886 I am trying to log in to betfair.com by using mechanize. I have tried several ways but it always fail. This is the code I have developed so far, can anyone help me to identify what is wrong with it and how I can improve it to log into my betfair account? Thanks, import cookielib import urllib import urllib2 from BeautifulSoup import BeautifulSoup import mechanize from mechanize import Browser import re bf_username_name = "username" bf_password_name = "password" bf_form_name = "loginForm" bf_username = "xxxxx" bf_password = "yyyyy" urlLogIn = "http://www.betfair.com/" accountUrl = "https://myaccount.betfair.com/account/home?rlhm=0&" # This url I will use to verify if log in has been successful br = mechanize.Browser(factory=mechanize.RobustFactory()) br.addheaders = [("User-Agent","Mozilla/5.0 (Macintosh; Intel Mac OS X 10_5_8) AppleWebKit/537.1 (KHTML, like Gecko) Chrome/21.0.1180.90 Safari/537.1")] br.open(urlLogIn) br.select_form(nr=0) print br.form br.form[bf_username_name] = bf_username br.form[bf_password_name] = bf_password print br.form #just to check username and psw have been recorded correctly responseSubmit = br.submit() response = br.open(accountUrl) text_file = open("LogInResponse.html", "w") text_file.write(responseSubmit.read()) #this file should show the home page with me logged in, but it show home page as if I was not logged it text_file.close() text_file = open("Account.html", "w") text_file.write(response.read()) #this file should show my account page, but it should a pop up with an error text_file.close()

    Read the article

  • Browser freezes when try to call a JS function along with submission of a form.

    - by Waseem
    I have form in my view like following 1 <div> 2 <% form_tag facebook_user_path do %> 3 <label>Use my photo and name from facebook?</label><br /> 4 <%= check_box_tag 'use_name_and_photo', 'yes', true %> 5 <img src="<%= @user.pic %>" /><% @user.name %> 6 7 <%= submit_tag "Finish", :id => "use_name_and_photo_submit" %> 8 <% end %> 9 </div> I have attached some JS handlers using Jquery to this form. 1 var fb = { 2 extendedPermissions: function () { 3 $("#use_name_and_photo_submit").click(function (event) { 4 FB.Connect.showPermissionDialog("email,read_stream,publish_stream", function (perms) { 5 if (!perms) { 6 alert("You have to grant facebook extended permissions to further browse the application."); 7 } else { 8 $("form").submit(function () { 9 $.post($(this).attr("action"), $(this).serialize(), null, "script"); 10 }); 11 } 12 }); 13 event.preventDefault(); 14 return false; 15 }); 16 } 17 }; 18 19 $(document).ready(function () { 20 fb.extendedPermissions(); 21 }); What I want is that when the user clicks on the "Finish" button, he is prompted for the facebook permissions dialogue and when he gives the permissions, the form is submitted to FacebookUsersController. Right now when I click the "Finish" button, facebook permissions dialogue is initiated but before I am prompted for the actual permission submission window, the browser freezes. Just like I have pressed Esc during the process. In fact status bar of the browser says "Stopped". Any help is highly appreciated.

    Read the article

  • How do I keep users from spoofing data through a form?

    - by Jonathan
    I have a site which has been running for some time now that uses a great deal of user input to build the site. Naturally there are dozens of forms on the site. When building the site, I often used hidden form fields to pass data back to the server so that I know which record to update. an example might be: <input type="hidden" name="id" value="132" /> <input type="text" name="total_price" value="15.02" /> When the form is submitted, these values get passed to the server and I update the records based on the data passed (i.e. the price of record 132 would get changed to 15.02). I recently found out that you can change the attributes and values via something as simple as firebug. So...I open firebug and change the id value to "155" and the price value to "0.00" and then submit the form. Viola! I view product number 155 on the site and it now says that it's $0.00. This concerns me. How can I know which record to update without either a query string (easily modified) or a hidden input element passing the id to the server? And if there's no better way (I've seen literally thousands of websites that pass the data this way), then how would I make it so that if a user changes these values, the data on the server side is not executed (or something similar to solve the issue)? I've thought about encrypting the id and then decrypting it on the other side, but that still doesn't protect me from someone changing it and just happening to get something that matches another id in the database. I've also thought about cookies, but I've heard that those can be manipulated as well. Any ideas? This seems like a HUGE security risk to me.

    Read the article

  • Javascript libraries + JQuery plugins contradict? How to debug?

    - by Metafaniel
    This is somewhat a newbie question... I effort everyday to learn, so please understand ;) I'm not the very best expert, but I can do a decent job good looking and functional websites or web applications. My main tools are PHP5, HTML5, CSS2 y 3, a database (SQLite, MySQL) and Javascript and JQuery. I'm not an expert at all in Javascript. I often find interesting JQuery plugins or tutorials and try to mix them up to do the functionality needed. This time I'm mixing maybe too much plugins and js files from different sources. In fact, my app do what I want except for certain behaviors... There are no errors, everything looks fine, but the misbehavior persists. So maybe I need to specify a class I don't know about, or one contradicts another one from another plugin and I just can't understand, for example, why a <button type="button">DON'T submit</button> just submits the form... Anyway, my point is: Do you people know a way to debug this situations??? Is there a generic tool, suggestion, workflow or something to help me understand conflicts or omissions between libraries or plugins??? (Javascript libraries, my own Javascripts and JQuery plugins)??? I hope it is a way! THANKS A LOT FOR YOUR HELP AND COMPREHENSION! =)

    Read the article

  • unable to use html form post in php

    - by kossibox
    Hello i have an html form and i'm posting data but i'm unable to get the posted data on a php page (same page) can you please help me. thanks in advance <div class="left"> <form name="form_signin" method="post" onsubmit="return signinValid();" > <table> <tr> <td> Email : </td> <td> <input type="text" id="email" length ="40"> </td> </tr> <tr> <td> Mot de Passe : </td> <td> <input type="password" id ="pass" length ="40"> </td> </tr> <tr> <td> &nbsp; </td> <td> <input type="submit" value="Connexion" length ="40"> </td> </tr> </table> </form> <?php include 'includes.php'; include DB_CONNECT_FILE; //session_start(); print_r($_POST); // prints an empty array even if fields are filled $smart->assign('tpl_file',TEMPLATES_DIR.'signin.html'); $smart->display(TEMPLATES_DIR."with_right.html"); include DB_DISCONNECT_FILE; ?>

    Read the article

  • How to use form_tag to update params

    - by Tryskele
    I have been struggling with a problem in Rails for a couple of days and still could not find the solution. Could you help me with that? Problem: I have a search box that puts a :search_string entry in the params structure. I use a form_tag for that and it works fine. <% form_tag :controller=> 'items', :action => 'find' do %> <%= text_field_tag :search_string, params[:search_string] %> <% end %> The problem is when I want to add and update other params key-value (in another view), for instance :start_date, to filter the search_string result. Here is the code snipped that I use in the view: <% form_tag :controller=> "items", :action => "find", :params => params do %> <%= hidden_field_tag :date_start, '2010-04-01' %> <%= submit_tag 'April' %> <% end %> <% form_tag :controller=> "items", :action => "find", :params => params do %> <%= hidden_field_tag :date_start, '2010-03-01' %> <%= submit_tag 'March' %> <% end %> When I first click on "April" submit button, then the params is correctly passed to the controller (i.e. there is a params[:start_date]='April'). However when I try to click "March" button afterwards, the params[:start_date] is not updated. I definitely think this is a stupid newbie mistake, but I cannot figure out how to properly use the form_tag. Could you tell me if I am doing something work? Otherwise, could you advise me which is the best way to update the params using form_tag's ? Thank you very much in advance. Miquel

    Read the article

  • Problem in getting response from server in jquery

    - by Alvin
    Hello, I'm using $.ajax(options) method to pass the request to server based on username and password, but whenever I try to print the response by XMLHttpRequest object when response gets successful, I'm getting an empty value. $(document).ready(function(){ $("#form").submit(function(){ $.ajax({url:"Chat.jsp",type:"POST",data:$("#form").serialize(),success:function(request) { alert(request.responseText); //This is displaying nothing },error:function(){document.write("YOU can't");}}); }); }); This is what I'm doing in my servlets code after executing query: try { String user = request.getParameter("j_username"); String password = request.getParameter("j_password"); if(user != null && password != null) { String query = "Select * from users where user_name="+"\'"+user+"\'"+"&& user_pass="+"\""+password+"\""; DBCheck db= new DBCheck(); boolean b = db.doExecuteQuery(con.createStatement(),query); response.setHeader("Cache-Control", "no-cache"); if(b) { response.getWriter().println("Username already exits"); } else { response.getWriter().println("Username doesn't exit"); } } } catch(SQLException ex) { ex.printStackTrace(); } } May I know the problem, and how can I fix it?

    Read the article

  • why does this knockout method receive a form element instead of the object its nested in?

    - by ladookie
    I have this HTML: <ul class="chat_list" data-bind="foreach: chats"> <li> <div class="chat_response" data-bind="visible: CommentList().length == 0"> <form data-bind="submit: $root.addComment"> <input class="comment_field" placeholder="Comment…" data-bind="value: NewCommentText" /> </form> </div> </li> </ul> and this JavaScript: function ChatListViewModel(chats) { // var self = this; self.chats = ko.observableArray(ko.utils.arrayMap(chats, function (chat) { return { CourseItemDescription: chat.CourseItemDescription, CommentList: ko.observableArray(chat.CommentList), CourseItemID: chat.CourseItemID, UserName: chat.UserName, ChatGroupNumber: chat.ChatGroupNumber, ChatCount: chat.ChatCount, NewCommentText: ko.observable("") }; })); self.newChatText = ko.observable(); self.addComment = function (chat) { var newComment = { CourseItemDescription: chat.NewCommentText(), ParentCourseItemID: chat.CourseItemID, CourseID: $.CourseLogic.dataitem.CourseID, AccountID: $.CourseLogic.dataitem.AccountID, SystemObjectID: $.CourseLogic.dataitem.CommentSystemObjectID, SystemObjectName: "Comments", UserName: chat.UserName }; chat.CommentList.push(newComment); chat.NewCommentText(""); }; } ko.applyBindings(new ChatListViewModel(initialData)); When I go into the debugger it shows that the chat parameter of the addComment() function is a form element instead of a chat object. Why is this happening?

    Read the article

  • When does the call() method get called in a Java Executor using Callable objects?

    - by MalcomTucker
    This is some sample code from an example. What I need to know is when call() gets called on the callable? What triggers it? public class CallableExample { public static class WordLengthCallable implements Callable { private String word; public WordLengthCallable(String word) { this.word = word; } public Integer call() { return Integer.valueOf(word.length()); } } public static void main(String args[]) throws Exception { ExecutorService pool = Executors.newFixedThreadPool(3); Set<Future<Integer>> set = new HashSet<Future<Integer>>(); for (String word: args) { Callable<Integer> callable = new WordLengthCallable(word); Future<Integer> future = pool.submit(callable); //**DOES THIS CALL call()?** set.add(future); } int sum = 0; for (Future<Integer> future : set) { sum += future.get();//**OR DOES THIS CALL call()?** } System.out.printf("The sum of lengths is %s%n", sum); System.exit(sum); } }

    Read the article

  • a + sing in email address

    - by d.andreykiv
    Hi. I need to submit an email address with a "+" sign and validate in on server. But server receives email like "[email protected]" as "aaa [email protected]". I send all data as POST request with following code NSURL* url = [NSURL URLWithString:[NSString stringWithFormat:@"%@%@", url, @"/signUp"]]; NSString *post = [NSString stringWithFormat:@"&email=%@&userName=%@&password=%@", user.email, user.userName, user.password]; NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:NO]; NSData* data = [self sendRequest:url postData:postData]; post variable before encoding has value &[email protected]&userName=Asdfasdfadsfadsf&password=sdfasdf after encoding it is same &[email protected]&userName=Asdfasdfadsfadsf&password=sdfasdf Method I use to send request looks like following code: -(id) sendRequest:(NSURL*) url postData:(NSData*)postData { // Create request NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init]; NSString *postLength = [NSString stringWithFormat:@"%d",[postData length]]; [request setURL:url]; [request setHTTPMethod:@"POST"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Current-Type"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setHTTPBody:postData]; NSURLResponse *urlResponse; NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:nil]; [request release]; return data; }

    Read the article

  • How can I remove a JPanel from a JFrame?

    - by Roman
    Recently I asked here how to add a new JPanel to JFrame. The answer helped me to get a working code. But not I have a related question: "How can I remove an old JPanel". I need that because of the following problem. A new JPanel appears appears when I want (either time limit is exceeded or user press the "Submit" button). But in several seconds some element of the old JPanel appears together with the component of the new JPanel. I do not understand why it happens. I thought that it is because I have to other threads which update the window. But the first thread just add the old panel once (so, it should be finished). And in the second thread I have a loop which is broken (so, it also should be finished). Here is my code: private Thread controller = new Thread() { public void run() { // First we set the initial pane (for the selection of partner). SwingUtilities.invokeLater(new Runnable() { public void run() { frame.getContentPane().add(generatePartnerSelectionPanel()); frame.invalidate(); frame.validate(); } }); // Update the pane for the selection of the parnter. for (int i=40; i>0; i=i-1) { final int sec = i; SwingUtilities.invokeLater(new Runnable() { public void run() { timeLeftLabel.setText(sec + " seconds left."); } }); try {Thread.sleep(1000);} catch (InterruptedException e) {} if (partnerSubmitted) {break;} } // For the given user the selection phase is finished (either the time is over or form was submitted). SwingUtilities.invokeLater(new Runnable() { public void run() { frame.getContentPane().add(generateWaitForGamePanel()); frame.invalidate(); frame.validate(); } }); } };

    Read the article

  • Other test cases for this openFile function?

    - by igor
    I am trying to figure out why my function to open a file is failing this autograder I submit my homework into. What type of input would fail here, I can't think of anything else? Code: bool openFile(ifstream& ins) { char fileName[256]; cout << "Enter board filename: "; cin.getline(fileName,256); cout << endl << fileName << endl; ins.open(fileName); if(!ins) { ins.clear(); cout<<"Error opening file"<<endl; return false; } return true; } Here is output from the 'Autograder' of what my program's output is, and what the correct output is supposed to be (and I do not know what is in the file they use for the input) Autograder output: ******************************************* ***** ***** ***** Your output is: ***** ***** ***** ******************************************* Testing function openFile Enter board filename: test.txt 1 Enter board filename: not a fileName Error opening file 0 ******************************************* ***** ***** ***** Correct Output ***** ***** ***** ******************************************* Testing function openFile Enter board filename: 1 Enter board filename: Error opening file 0

    Read the article

  • How do I get Asp.net MVC BeginForm to add closing tag correctly?

    - by Matt
    I seem to be missing something obvious here, but cannot see what it is. My problem is that the closing form tag for BeginForm is not being added to my markup. I am looping through a collection and creating a form for each item, but the forms arent closing properly. Any suggestions please? Thanks <% foreach (var item in Model) { %> <% using (Html.BeginForm("EditUser","Users")) { %> <tr> <td> <input id="contactID" type="hidden" value="<%= item.ContactID %>" /> <%=item.Email %> </td> <td> <%=item.Market.MarketName%> </td> <td> <%=item.ContactType.ContactTypeName%> </td> <td> <input type="submit" value="Edit" /> </td> </tr> <%} %> <% } %>

    Read the article

  • Why is this ajax call being made even though it shouldn't be

    - by user2921557
    i have this validation script im working on but cant see why im having an issue. You can see that i have a check = false / true, check before it runs the ajax call. However, even if a field is empty and check is set to false, it is still running the call. so: // JavaScript - Update Password AJAX $(document).ready(function () { // When the form is submitted $('.updatepasswordform').submit(function () { var check = true; // Get the values var password1 = $("input[name=password1]").val(); var password2 = $("input[name=password2]").val(); var newpassword = $("input[name=newpassword]").val(); /* Password Validation */ // If fields are empty if (password1 === '') { check = false; $("input[name=password1]").css('border', 'solid 2px red'); } // If fields are empty if (password2 === '') { check = false; $("input[name=password2]").css('border', 'solid 2px red'); } // If fields are empty if (newpassword === '') { check = false; $("input[name=newpassword]").css('border', 'solid 2px red'); } if (check = true) { $.ajax({ type: "POST", url: "process/updatepassword.php", data: $(".updatepasswordform").serialize(), dataType: "json", success: function (response) { /* Checks for database validation, removed for space saving */ } }); } return false; }); });

    Read the article

  • I am unable to upload file to my local host folder in php.

    - by Nauman khan
    Hi, I have the follwing code <form enctype="multipart/form-data" action="upload.php" method="POST"> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> <?php $target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } ?> my page is in http://localhost/nausal/upload.php now I am having the follwing error though i have created a folder in site with name upload. Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 15 Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 17 Sorry, there was a problem uploading your file. Please help me I am very new to php. :(

    Read the article

  • [AS3] Calling Php Script with UTF-8 POST variables

    - by kornelijepetak
    AS3 documentation says that Strings in AS3 are in UTF-16 format. There is a textbox on a Flash Clip where user can type some data. When a button is clicked, I want this data to be sent to a php script. I have everything set up, but it seems that the PHP script gets the data in UTF-16 format. The data in the database (which is utf-8) shows some unrecognizable characters (where special characters are used), meaning that the data has not been sent in a correct encoding. var variables:URLVariables=new URLVariables; var varSend:URLRequest=new URLRequest("http://website.com/systematic/accept.php"); varSend.method=URLRequestMethod.POST; varSend.data=variables; var varLoader:URLLoader=new URLLoader; varLoader.dataFormat=URLLoaderDataFormat.VARIABLES; varLoader.addEventListener(Event.COMPLETE, completeHandler); When submit button is clicked, the following handler gets executed. function sendData(event:MouseEvent) : void { // i guess here is the problem (tbName.text is UTF-16) variables.name = tbName.text; varLoader.load(varSend); } Is there any way to send the data so that PHP script gets the data in UTF-8 format? (PHP script is retrieving the value using the $_POST['name']).

    Read the article

  • jquery .on() toggle div

    - by lollo
    i'm developing a blog with dynamic content loaded via ajax request and i'm trying to hide/show the "post comment" form, of the article, with a button : <div id="post"> ... <ol id="update" class="timeline"> <!-- comments here --> </ol> <button class="mybutton Bhome">Commenta</button><!-- hide/show button --> <div class="mycomment"><!-- div to hide/show --> <form action="#" method="post"> Nome: <input type="text" size="12" id="name" /><br /> Email: <input type="text" size="12" id="email" /><br /> <textarea rows="10" cols="50" class="mytext" id="commentArea"></textarea><br /> <input type="submit" class="Bhome" value=" Post " /> </form> </div><!-- mycomment --> </div><!-- post --> This jquery code works well but has effect on All the posts... $("div").on("click", ".mybutton", function(e){ $(".mycomment").slideToggle("slow"); e.stopPropagation(); }); I want that only the clicked hide/show button has effect on the related article but f i have more than one article on my page the button with .mybutton class hides or shows all the comment form of all the articles.

    Read the article

  • JSP JPA Form: how to insert value in a path variable

    - by kajarigd
    I have the following code snippet in a jsp file: <hr> <form:form commandName="newTicketSale" id="reg" action="transactionResult.htm"> <h3>Buy Movie Tickets:</h3> <form:label path="movieName">Movie Name:</form:label> <form:input path="movieName" /> <form:errors class="invalid" path="movieName" /> <form:label path="ticketPrice">Ticket Price:</form:label> <form:input path="ticketPrice" /> <form:errors class="invalid" path="ticketPrice" /> <input type="submit"> <br><br> </form:form> I am using JPA tags in this jsp. Now, in the commandName "newTicketSale" there is another parameter called userId. In the jsp file itself I need to insert value ${name} in userId, so that in the Controller file when I am doing @Valid @ModelAttribute("newTicketSale") MovieTicket newTicket I can retrieve the value ${name} when I am doing newTicket.getUserId(). I don't know how to do this. Please help! Thanks in advance!

    Read the article

  • jQuery Validate PHP Response

    - by Kurt
    Hello Everybody, my problem is, I want to validate an email adresse with jquery. Not only the syntax but rather if the email is already registrated. There are some tutorials but they are not working! At first the Jquery Code: <script id="demo" type="text/javascript"> $(document).ready(function() { // validate signup form on keyup and submit var validator = $("form#signupform").validate({ rules: { Vorname: { required: true, minlength: 3 }, Nachname:{ required: true, minlength: 4 }, password: { required: true, minlength: 5 }, password_confirm: { required: true, minlength: 5, equalTo: "#password" }, Email: { required: true, email: true, type: "POST", remote: "remotemail.php" }, dateformat: "required", ... </script> And now the PHP Code: <?php include('dbsettings.php'); $conn = mysql_connect($dbhost,$dbuser,$dbpw); mysql_select_db($dbdb,$conn); $auslesen1 = "SELECT Email FROM flo_user"; $auslesen2 = mysql_query($auslesen1,$conn); $registered_email = mysql_fetch_assoc($auslesen2); $requested_email = $_POST['Email']; if( in_array($requested_email, $registered_email) ){ echo "false"; } else{ echo "true"; } ?> I tried return TRUE/ return FALSE as well, but this displays "Email is registrated" all the time. json_encode didn't work as well. Thanks a lot!

    Read the article

  • PHP - upload.class image and $_FILES

    - by Ockonal
    Hello, I'm using class.upload.php to upload pictures onto the server. Here is my form: <form action="<?="http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'];?>" method="post" enctype="multipart/form-data"> <table style="width: 100%; padding-top: 20px;"> <tr> <td>Image file:</td> <td><input type="file" name="image_file" /></td> </tr> <tr> <td>&nbsp;</td> <td align="right"><input type="submit" name="add_new" value="Add image" /><td></td> </tr> </table> </form> In php code I do: if( array_key_exists('add_new', $_POST) ) { echo 'add new is in array'; echo '<pre>'; print_r($_POST); print_r($_FILES); echo '</pre>'; $handle = new Upload($_FILES['image_file']); ... } Here is an output of print_r: Array ( [image_file] => somefile.png [add_new] => Add image ) Array ( ) As you can see second array is empty ($_FILES), so image doesn't upload. Why? operating system : Linux PHP version : 5.2.12 GD version : 2.0.34 supported image types : png jpg gif bmp open_basedir : /home/httpd/vhosts/kz-gbi.ru/httpdocs:/tmp

    Read the article

  • asp.net MVC ActionMethod causing null exception on parameter

    - by David Liddle
    I am trying to add filter functionality that sends a GET request to the same page to filter records in my table. The problem I am having is that the textbox complains about null object reference when a parameter is not passed. For example, when the person first views the page the url is '/mycontroller/myaction/'. Then when they apply a filter and submit the form it should be something like 'mycontroller/myaction?name=...' Obviously the problem stems from when the name value has not been passed (null) it is still trying to be bound to the 'name' textbox. Any suggestions on what I should do regarding this problem? UPDATE I have tried setting the DefaultValue attribute but I am assuming this is only for route values and not query string values ActionResult MyAction([DefaultValue("")] string name) //Action - /mycontroler/myaction ActionResult MyAction(string name) { ...do stuff } //View <div id="filter"> <% Html.BeginForm("myaction", "mycontroller", FormMethod.Get); %> Name: <%= Html.TextBox("name") %> .... </div> <table>...my list of filtered data

    Read the article

  • Safari Web Inspector is not updating when I update an element with ajax

    - by Ashley
    I have a checkout page http://www.oipolloi.com/oipolloi/shop/viewbasket.php with multiple ajax calls after certain items update (EG look up postage cost when country is changed, then update discount boxes etc). I've asked for help in the past about the best method of making sure ALL calls have returned before allowing the form to be submitted for payment processing: http://stackoverflow.com/questions/2290372/how-do-i-prevent-form-submission-until-multiple-ajax-calls-have-finished-jquery I was fairly happy that the logic in the finished solution was correct, but I have still been receiving reports that people using Safari are able to submit the form without the ajax calls returning properly. I have tried using the Safari Web Inspector to debug but it seems that when you Inspect Element, then update an element with an ajax call, the Inspector doesn't seem to update. I am updating hidden fields, so it's hard to be able to know whether the problem lies with the DOM not being updated properly, or the Inspector itself. I'm using Safari 4.0.5 on PC and you can reproduce the problem above by looking for a div id="countryFieldsBilling" with Web Inspector. It should contain three hidden fields that are initially empty. You can try to make it update (or not) by choosing a country from the select menu at the bottom of 'Shipping Address' box, and then clicking the 'click to use Shipping Address' link at the top of the 'Billing Address' just below. The behaviour I am seeing is that the country chosen in the shipping select gets copied correctly to the country in the billing select, but the hidden inputs in the Web Inspector do not get updated. When these hidden inputs do not get updated, this causes the problem that Mac Safari users report. If you can let me know either how to get Web Inspector to work properly, or something else I may have missed in the behaviour of Mac Safari that may cause these problems, that would be great. Thanks in advance

    Read the article

  • Insert Stored Procedure does not Create Database Record

    - by SidC
    Hello All, I have the following stored procedure: ALTER PROCEDURE Pro_members_Insert @id int outPut, @LoginName nvarchar(50), @Password nvarchar(15), @FirstName nvarchar(100), @LastName nvarchar(100), @signupDate smalldatetime, @Company nvarchar(100), @Phone nvarchar(50), @Email nvarchar(150), @Address nvarchar(255), @PostalCode nvarchar(10), @State_Province nvarchar(100), @City nvarchar(50), @countryCode nvarchar(4), @active bit, @activationCode nvarchar(50) AS declare @usName as varchar(50) set @usName='' select @usName=isnull(LoginName,'') from members where LoginName=@LoginName if @usName <> '' begin set @ID=-3 RAISERROR('User Already exist.', 16, 1) return end set @usName='' select @usName=isnull(email,'') from members where Email=@Email if @usName <> '' begin set @ID=-4 RAISERROR('Email Already exist.', 16, 1) return end declare @MemID as int select @memID=isnull(max(ID),0)+1 from members INSERT INTO members ( id, LoginName, Password, FirstName, LastName, signupDate, Company, Phone, Email, Address, PostalCode, State_Province, City, countryCode, active,activationCode) VALUES ( @Memid, @LoginName, @Password, @FirstName, @LastName, @signupDate, @Company, @Phone, @Email, @Address, @PostalCode, @State_Province, @City, @countryCode, @active,@activationCode) if @@error <> 0 set @ID=-1 else set @id=@memID Note that I've "inherited" this sproc and the database. I am trying to insert a new record from my signup.aspx page. My SQLDataSource is as follows: <asp:SqlDataSource runat="server" ID="dsAddMember" ConnectionString="rmsdbuser" InsertCommandType="StoredProcedure" InsertCommand="Pro_members_Insert" ProviderName="System.Data.SqlClient"> The click handler for btnSave is as follows: Protected Sub btnSave_Click(ByVal sender As Object, ByVal e As EventArgs) Handles btnSave.Click Try dsAddMember.DataBind() Catch ex As Exception End Try End Sub When I run this page, signup.aspx, provide required fields and click submit, the page simply reloads and the database table does not reflect the newly-inserted record. Questions: 1. How do I catch the error messages that might be returned from the sproc? 2. Please advise how to change signup.aspx so that the insert occurs. Thanks, Sid

    Read the article

< Previous Page | 169 170 171 172 173 174 175 176 177 178 179 180  | Next Page >