Search Results

Search found 72054 results on 2883 pages for 'file hosting'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 174/2883 | < Previous Page | 170 171 172 173 174 175 176 177 178 179 180 181  | Next Page >

  • Recursive function with for loop python

    - by user134743
    I have a question that should not be too hard but it has been bugging me for a long time. I am trying to write a function that searches in a directory that has different folders for all files that have the extension jpg and which size is bigger than 0. It then should print the sum of the size of the files that are in these categories. What I am doing right now is def myFuntion(myPath, fileSize): for myfile in glob.glob(myPath): if os.path.isdir(myFile): myFunction(myFile, fileSize) if (fnmatch.fnmatch(myFile, '*.jpg')): if (os.path.getsize(myFile) > 1): fileSize = fileSize + os.path.getsize(myFile) print "totalSize: " + str(fileSize) THis is not giving me the right result. It sums the sizes of the files of one directory but it does not keep suming the rest. For example if I have these paths C:/trial/trial1/trial11/pic.jpg C:/trial/trial1/trial11/pic1.jpg C:/trial/trial1/trial11/pic2.jpg and C:/trial/trial2/trial11/pic.jpg C:/trial/trial2/trial11/pic1.jpg C:/trial/trial2/trial11/pic2.jpg I will get the sum of the first three and the the size of the last 3 but I won´t get the size of the 6 together, if that makes sense. Thank you so much for your help!

    Read the article

  • Requisite of file.append

    - by Jeff Strunk
    Is it possible to make salt require that a particular file was appended to as opposed to the file merely existing? It seems like I can only require a file state. The source looks like it strips out any method names from a require attribute. In the example below, I only want the foo service to run if my lines have been appended to /etc/security/limits.conf. file.append: - name: /etc/security/limits.conf - text: - root hard nofile 65535 - root soft nofile 65535 foo: service.running: - enable: True - require: - file.append: /etc/security/limits.conf

    Read the article

  • how to fetch data using jquery

    - by user3566029
    I have tried to connect my index.php file in 000webhost.com using jQuery. From the site menu I have connected with 000webhost using FTP details available in 000webhost.com. When I tried to read data from jQuery it doesn’t working. Anyone please tell me what should I need to change? Should I need to connect my Dreamweaver database to webhost? If yes please explain? This is what I have done. index.php $mysql_host = "mysql0.000webhost.com"; $mysql_database = "a000000_mydb"; $mysql_user = "a000000_root"; $mysql_password = "******"; $conn=@mysql_connect ( $mysql_host,$mysql_user,$mysql_password )or die('aa'); mysql_select_db($mysql_database,$conn) or die('eoor on db'); $quer=mysql_query("SELECT * FROM sam"); $res=array(); while($row=mysql_fetch_row($quer)) { $res[]=$row; } print(json_encode($res)); return json_encode($res); mysql_close(); index.html $.get('public_html/index.php', function( data ) { alert( 'Successful' +data); });

    Read the article

  • How can I use django.core.files.File

    - by Jake
    The docs for django.core.files.File imply I can do this: print File(open(path)).url but the File object has no attribute 'url' However, django.db.models.fields.files.FieldFile extends File and does have all the attributes described in the docs for File, but I can't create one without giving it a model field. All I want it something that does what the docs for django.core.files.File (link above) say it does, take a python file and give it attributes like 'url' and 'path' and 'name', can anyone help? Cheers, Jake

    Read the article

  • Python: How to read huge text file into memory

    - by asmaier
    I'm using Python 2.6 on a Mac Mini with 1GB RAM. I want to read in a huge text file $ ls -l links.csv; file links.csv; tail links.csv -rw-r--r-- 1 user user 469904280 30 Nov 22:42 links.csv links.csv: ASCII text, with CRLF line terminators 4757187,59883 4757187,99822 4757187,66546 4757187,638452 4757187,4627959 4757187,312826 4757187,6143 4757187,6141 4757187,3081726 4757187,58197 So each line in the file consists of a tuple of two comma separated integer values. I want to read in the whole file and sort it according to the second column. I know, that I could do the sorting without reading the whole file into memory. But I thought for a file of 500MB I should still be able to do it in memory since I have 1GB available. However when I try to read in the file, Python seems to allocate a lot more memory than is needed by the file on disk. So even with 1GB of RAM I'm not able to read in the 500MB file into memory. My Python code for reading the file and printing some information about the memory consumption is: #!/usr/bin/python # -*- coding: utf-8 -*- import sys infile=open("links.csv", "r") edges=[] count=0 #count the total number of lines in the file for line in infile: count=count+1 total=count print "Total number of lines: ",total infile.seek(0) count=0 for line in infile: edge=tuple(map(int,line.strip().split(","))) edges.append(edge) count=count+1 # for every million lines print memory consumption if count%1000000==0: print "Position: ", edge print "Read ",float(count)/float(total)*100,"%." mem=sys.getsizeof(edges) for edge in edges: mem=mem+sys.getsizeof(edge) for node in edge: mem=mem+sys.getsizeof(node) print "Memory (Bytes): ", mem The output I got was: Total number of lines: 30609720 Position: (9745, 2994) Read 3.26693612356 %. Memory (Bytes): 64348736 Position: (38857, 103574) Read 6.53387224712 %. Memory (Bytes): 128816320 Position: (83609, 63498) Read 9.80080837067 %. Memory (Bytes): 192553000 Position: (139692, 1078610) Read 13.0677444942 %. Memory (Bytes): 257873392 Position: (205067, 153705) Read 16.3346806178 %. Memory (Bytes): 320107588 Position: (283371, 253064) Read 19.6016167413 %. Memory (Bytes): 385448716 Position: (354601, 377328) Read 22.8685528649 %. Memory (Bytes): 448629828 Position: (441109, 3024112) Read 26.1354889885 %. Memory (Bytes): 512208580 Already after reading only 25% of the 500MB file, Python consumes 500MB. So it seem that storing the content of the file as a list of tuples of ints is not very memory efficient. Is there a better way to do it, so that I can read in my 500MB file into my 1GB of memory?

    Read the article

  • Utility method - Pass a File or String?

    - by James P.
    Here's an example of a utility method: public static Long getFileSize(String fileString) { File file = new File(fileString); if (file == null || !file.isFile()) return null; return file.length(); } Is it a good practise to pass a String rather than a File to a method like this? In general what reasoning should be applied when making utility methods of this style?

    Read the article

  • WCF Self Host Service - Endpoints in C#

    - by Kyle
    My first few attempts at creating a self hosted service. Trying to make something up which will accept a query string and return some text but have have a few issues: All the documentation talks about endpoints being created automatically for each base address if they are not found in a config file. This doesn't seem to be the case for me, I get the "Service has zero application endpoints..." exception. Manually specifying a base endpoint as below seems to resolve this: using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.ServiceModel; using System.ServiceModel.Description; namespace TestService { [ServiceContract] public interface IHelloWorldService { [OperationContract] string SayHello(string name); } public class HelloWorldService : IHelloWorldService { public string SayHello(string name) { return string.Format("Hello, {0}", name); } } class Program { static void Main(string[] args) { string baseaddr = "http://localhost:8080/HelloWorldService/"; Uri baseAddress = new Uri(baseaddr); // Create the ServiceHost. using (ServiceHost host = new ServiceHost(typeof(HelloWorldService), baseAddress)) { // Enable metadata publishing. ServiceMetadataBehavior smb = new ServiceMetadataBehavior(); smb.HttpGetEnabled = true; smb.MetadataExporter.PolicyVersion = PolicyVersion.Policy15; host.Description.Behaviors.Add(smb); host.AddServiceEndpoint(typeof(IHelloWorldService), new BasicHttpBinding(), baseaddr + "SayHello"); //for some reason a default endpoint does not get created here host.Open(); Console.WriteLine("The service is ready at {0}", baseAddress); Console.WriteLine("Press to stop the service."); Console.ReadLine(); // Close the ServiceHost. host.Close(); } } } } I still think I'm doing something wrong as I don't get the normal "This is a web service...etc..." page when I load up the url How would I go about setting this up to return the value of name in SayHello(string name) when requested thusly: localhost:8080/HelloWorldService/SayHello?name=kyle Do I have to create an endpoing for the SayHello contract as well? I'm trying to walk before running, but this just seems like crawling...Service has zero application endpoints...

    Read the article

  • Jquery request download/open file to the user

    - by CoffeeCode
    I have a Url that returns a file. How should my jquery request looklike to download this file to the user?? the action method looks like this public FileContentResult GetFile(int Id) { if (Id == 0) return File(new byte[0], ""); Survey survey = Repository.GetItem(Id); return File(survey.File.FileContent.ToArray(), survey.File.ContentType, survey.File.Name); }

    Read the article

  • How to determine the format of Excel file in Java?

    - by Samuh
    I am working on a light weight Java client library for Android mobile platform that can read and write to Excel files in .xls(BIFF) and Office 2003 XML format. No sooner we decided to start than we got stuck with a basic question. How do we determine the format of the excel files in Java? Please help. Thanks.

    Read the article

  • java: how to convert a file to utf8

    - by Enrique San Martín
    Hi, i have a file that have some non-utf8 caracters (like "ISO-8859-1"), and so i want to convert that file (or read) to UTF8 encoding, how i can do it? The code it's like this: File file = new File("some_file_with_non_utf8_characters.txt"); /* some code to convert the file to an utf8 file */ ... edit: Put an encoding example

    Read the article

  • loading a file and getting its contents crashes on me.

    - by Richards
    private class Lytterklasse implements ActionListener{ public void actionPerformed(ActionEvent e) { JFileChooser chooser = new JFileChooser(); FileNameExtensionFilter filter = new FileNameExtensionFilter( "Sudoku Tekstfiler", "txt"); chooser.setFileFilter(filter); int returnVal = chooser.showOpenDialog(getParent()); String filnavn=chooser.getName(); In innfil=new In(filnavn); int type=innfil.inInt(); int lengdeBoks=innfil.inInt(); int breddeBoks=innfil.inInt(); for(int i=0;i } Why does this crash on me? I cant figure it out. Please help!

    Read the article

  • Is there a java library equivalent to `file` command in unix

    - by Shervin
    Is there any java libraries that is similar to unix's command file? ie: $ file somepicture.png somepicture.png PNG image, 805 x 292, 8-bit/color RGB, non-interlaced The file command is such a nice tool. I need something that can tell me if the file is really what I want it to be. (ie a picture, document etc) I know I can run the command file, but I am looking for a java library, not running the actual unix command.

    Read the article

  • What's the best simplest way to detect a file from a directory?

    - by Nano HE
    My code like this, I looked up the open command, but I am not sure it is the simplest way or not. if #Parser.exe exist in directory of Debug { move ("bin/Debug/Parser.exe","Parser.exe"); } elsif #Parser.exe exist in directory of Release { move ("bin/Release/Parser.exe","Parser.exe"); } else { die "Can't find the Parser.exe."; } Thank you.

    Read the article

  • how to remove .php from a certain file (with apache .htaccess)

    - by user2015253
    I want a certain file (only this!) to remove the php extension for calling it. BUT: It uses get parameters and they should remain! I tried it with my .htaccess and something like: RewriteEngine on followed by either RewriteRule ^file(.*)$ file.php$1 or RewriteRule ^file(.+)$ file.php$1 but it doesn't work. (First gives error 500, second gives 404) Example what I want to call in the browser: file?param=asd&foo=bar - It should call as: file.php?param=asd&foo=bar

    Read the article

  • How to read the file

    - by muruga
    I want to get the file from one host to another host. We can get the file using the NET::FTP module. In that module we can use the get method to get the file.But I want the file content instead of the file. I know that using the read method we can read the file content. But how to call the read function and how to get the file content. Please help me.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 170 171 172 173 174 175 176 177 178 179 180 181  | Next Page >