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  • Problem with MySQL query

    - by Psyche
    This time my setup looks like this: one table with galleries names (gallery_id, gallery_name) and another table with galleries photos (photo_id, photo_gallery_id, photo_name). What I need is to get all the galleries with one random picture for each gallery. Is it possible to do this with a single query?

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  • MySQL select date, join statistic data - how?

    - by Webnet
    I have some statistics I need to report on a monthly basis. I need my query to return 0's for statistics which aren't there. The only way I know to do this is to use SQL to generate a list of days within the specified time period and LEFT JOIN the statistic data that I need to report on. Problem is.... I've never not selected from a table like that... how do I do that?

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  • mysql - How select a akin records?

    - by zeroonea
    I have a table with name varchar address varchar country varchar city varchar ..... to store address of location example: name|address|country HaLong hotel|156 blahblah street|Vietnam Hotel Ha Long|156 blah blah|Vietnam Two rows above is duplicate data. I have a form, when user submit new location. The code need to find akin records to give a message (ex: This location already in db, use it or create new?) How to make a query to get akin record like this?

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  • Setting MySQL column names

    - by Richard Mar.
    Say I have these tables: people(id, name), cars(person_id, car) and this query: SELECT c.car FROM people as p, cars as c WHERE c.person_id = p.id AND p.id = 3 I want the c.car column to take its name from the name field in the people table, like this (invalid SQL, just to illustrate): SELECT c.car AS(SELECT name FROM people WHERE id = 3) How do I do that?

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  • mysql query trouble

    - by Bharanikumar
    Hi , in my database i have phone numbers with country code , which look somthing like 0044-123456 0044-123456 0014-123456 0014-123456 0024-123456 0024-123456 0034-123456 0044-123456 0044-123456 0024-123456 0034-123456 084-123456 084-123456 i want to total up the numbers by country, something like this output 0044 (2) 0024 (2) 0034 (1) 084 (2) 064 (5) Is it possible to do this with a SQL query?

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  • PHP MySQL query help

    - by user547794
    Hello, I am trying to use this query to return every instance where the variable $d['userID'] is equal to the User ID in a separate table, and then echo the username tied to that user ID. Here's what I have so far: $uid = $d['userID']; $result = mysql_query("SELECT u.username FROM users u LEFT JOIN comments c ON c.userID = u.id WHERE u.id = $uid;")$row = mysql_fetch_assoc($result); echo $row['username'];

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  • MySQL: Insert into multiple tables in same query with BEGIN&COMMIT

    - by strc
    I want to insert into multiple tables in same query by using BEGIN and COMMIT. It seems the error occur at begin. here is my SQL command BEGIN INSERT INTO Product (pName, pBrand, pCategory, pSize, pQuantity, pPrice, pDetail) VALUES('$name', '$brand', '$category', '$size', '$quantity', '$price', '$detail') INSERT INTO Image (iName, iExt, iSize, pID) VALUES('$img_name', '$img_ext', '$img_size', LAST_INSERT_ID()); COMMIT;

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  • MYSQL UPDATE with IN and Subquery

    - by Johal
    Hi i have tables like this : table entry : id | total_comments ___________ 1 | 0 2 | 0 3 | 0 4 | 0 table comments : id | eid | comment ___________ 1 | 1 | comment sdfd 2 | 1 | testing testing 3 | 1 | comment text 4 | 2 | dummy comment 5 | 2 | sample comment 6 | 1 | fg fgh dfh Query i write : UPDATE entry SET total_comments = total_comments + 1 WHERE id IN ( SELECT eid FROM comments WHERE id IN (1,2,3,4,5,6)) Results i get is : table entry : id | total_comments ___________ 1 | 1 2 | 1 3 | 0 4 | 0 Expected results : table entry : id | total_comments ___________ 1 | 4 2 | 2 3 | 0 4 | 0 Any help will be appreciated.

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  • login not working when changing from mysql to mysqli

    - by user1438647
    I have a code below where it logs a teacher in by matching it's username and password in the database, if correct, then log in, if incorrect, then display a message. <?php session_start(); $username="xxx"; $password="xxx"; $database="mobile_app"; $link = mysqli_connect('localhost',$username,$password); mysqli_select_db($link, $database) or die( "Unable to select database"); foreach (array('teacherusername','teacherpassword') as $varname) { $$varname = (isset($_POST[$varname])) ? $_POST[$varname] : ''; } ?> <form action="<?php echo htmlentities($_SERVER['PHP_SELF']); ?>" method="post" id="teachLoginForm"> <p>Username</p><p><input type="text" name="teacherusername" /></p> <!-- Enter Teacher Username--> <p>Password</p><p><input type="password" name="teacherpassword" /></p> <!-- Enter Teacher Password--> <p><input id="loginSubmit" type="submit" value="Login" name="submit" /></p> </form> <?php if (isset($_POST['submit'])) { $query = " SELECT * FROM Teacher t WHERE (t.TeacherUsername = '".mysqli_real_escape_string($teacherusername)."') AND (t.TeacherPassword = '".mysqli_real_escape_string($teacherpassword)."') "; $result = mysqli_query($link, $query); $num = mysqli_num_rows($result); $loged = false; while($row = mysqli_fetch_array($result)) { if ($_POST['teacherusername'] == ($row['TeacherUsername']) && $_POST['teacherpassword'] == ($row['TeacherPassword'])) { $loged = true; } $_SESSION['teacherforename'] = $row['TeacherForename']; $_SESSION['teachersurname'] = $row['TeacherSurname']; $_SESSION['teacherusername'] = $row['TeacherUsername']; } if ($loged == true){ header( 'Location: menu.php' ) ; }else{ echo "The Username or Password that you Entered is not Valid. Try Entering it Again."; } mysqli_close($link); } ?> Now the problem is that even if the teacher has entered in the correct username and password, it still doesn't let the teacher log in. When the code above was the old mysql() code, it worked fine as teacher was able to login when username and password match, but when trying to change the code into mysqli then it causes login to not work even though username and password match. What am I doing wrong?

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  • getting rows which including a value with mysql

    - by sundowatch
    I have a mysq query which gets including some vars like that: messages TABLE receiver cols user1 rows : 1,3,5 user2 rows : 2,3 user3 rows : 1,4 I want to get rows which includes '3' value. So I will get 'user1' and 'user2'. I tried that but naturally it doesn't work. mysql_query("SELECT * FROM messages WHERE receiver='3'"); How can I do this?

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  • CodeIgniter - numbers in sql query are masked with ``

    - by Checkson
    Hello, i'm using CodeIgniter for developing a community board. As I'm using nested sets to get a nested forum hierarchy, I have to run a lot of queries such as: SELECT `id` FROM `forums` WHERE 1 BETWEEN `lft` AND `rgt` My problem: CodeIgniter is replacing the "1" by "`1`" because the "1" is recognized as a column name. Of course, the query does not work any more. Is there a way to get it working? thx in advance

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  • MySQL - generate numbers for groups of a result

    - by FreeIX
    I need a query to return this result: +---------+-----+-------+ | ref_nid | nid | delta | +---------+-----+-------+ | AA | 97 | 1 | | BB | 97 | 2 | | CC | 97 | 3 | | DD | 98 | 1 | | EE | 98 | 2 | | FF | 98 | 3 | +---------+-----+-------+ However, I do not have the delta column. I need to generate it for each nid group. In other words, I need an auto incremented number for each group of the result.

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  • Is it possible to download a large database using mysql query

    - by Rose
    i am downloading files from server using WinSCP.Is it possible to write a query to download a large database using mysql query? Or using any other method i have tried with this code but i am not able to get the whole database structure <?php if(file_exists('backup_sql/my_backup.zip')) { unlink('backup_sql/my_backup.zip'); } $tables='*'; $host='MY HOST NAME'; $user='MY_USERNAME'; $pass='MYPASSWORD'; $name='MY_DB_NAME'; $link = mysql_connect($host,$user,$pass); mysql_select_db($name,$link); //get all of the tables if($tables == '*') { $tables = array(); $result = mysql_query('SHOW TABLES'); while($row = mysql_fetch_row($result)) { $tables[] = $row[0]; } } else { $tables = is_array($tables) ? $tables : explode(',',$tables); } $return=''; //cycle through foreach($tables as $table) { $result = mysql_query('SELECT * FROM '.$table); $num_fields = mysql_num_fields($result); //$return.= 'DROP TABLE '.$table.';'; $row2 = mysql_fetch_row(mysql_query('SHOW CREATE TABLE '.$table)); $return.= "\n\n".$row2[1].";\n\n"; for ($i = 0; $i < $num_fields; $i++) { while($row = mysql_fetch_row($result)) { $return.= 'INSERT INTO '.$table.' VALUES('; for($j=0; $j<$num_fields; $j++) { $row[$j] = addslashes($row[$j]); //$row[$j] = ereg_replace("\n","\\n",$row[$j]); if (isset($row[$j])) { $return.= '"'.$row[$j].'"' ; } else { $return.= '""'; } if ($j<($num_fields-1)) { $return.= ','; } } $return.= ");\n"; } } $return.="\n\n\n"; } $rand_var=time(); $files_to_zip = array( "'backup_sql/db-backup-'.$rand_var.'.sql'", ); $name = 'db-backup-'.$rand_var.'.sql'; $data = $return; ?> any one please help me... thank you

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  • Selecting two specific mysql table rows in a single query

    - by Scotta
    Lets say I have a table with 20 entries. They are sorted by date (date is a column name _) in descending order. How would I go about selecting ONLY the newest entry and the 15th oldest entry? I am getting all 15 results by doing the following query SELECT * FROM mytable m WHERE col1 = "zzz" ORDER BY date DESC LIMIT 15;

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  • mysql select help

    - by user344766
    Hi I have a table that looks like this id : productid : featureid and would have the following data: (1, 1, 16) (2, 1, 21) (3, 1, 25) (4, 2, 16) (5, 2, 21) (6, 2, 27) where featureid is a foreign key to another table. I need to select products that have both featureids of 16 and 25, in which case productid 1 but not productid 2 Can someone show me an example of how to format this query.

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  • Slow query execution time

    - by rotor
    select p.id,p.title,p.slug,p.content, (select url from gallery where postid=p.id limit 1) as url, t.name from posts as p inner join termrel as tr on (tr.object = p.id) inner join termtax as tx on (tx.id = tr.termtax_id) inner join terms as t on (t.id = tx.term_id) where tx.taxonomy_id=3 and p.post_status is null order by t.name asc This query took about 0.2407s to execute. How to make it fast?

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  • limiting a query to a specific item

    - by Dev-Ria
    I have a db with thousands of domains and data. I want to list only 100 rows of each domain. i can't use LIMIT 100 cause that only limits 100 records but I want dom1 to list 100 dom2 to list 100 dom3 to list 100 all in one query. This is what I have so far. SELECT domain COUNT(Key) AS DomCount FROM table_domain GROUP BY user,location ORDER BY domain,DomCount DESC Could I use a CASE?

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  • What does the below query explain?

    - by Parth
    What does the below query explain? SELECT * FROM `jos_menu` WHERE (id = 69 OR id = 72) I know its very silly question, but sometimes easy things creates mess in my skulls interpreter.. Pls help EDIT Its giving me record for both IDs, why is it doing so? It should five me the record for either 69 or 72....

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  • Check value existance while performing a UPDATE query

    - by nimo
    Hi, I need to perform a simple update query where the update should only be done, if there is no value with updating value (item_name). For example, DB table [item_types] item_id(PK) | item_name Assuming there exist item_id with 6, My attempt is UPDATE item_types as k SET k.item_name = 'item_1' WHERE NOT EXISTS (SELECT * FROM item_types as a WHERE a.item_name = 'item_1') AND k.item_id = '6' But this gives me error "You can't specify target table 'k' for update in FROM clause" Could you please explain the error here and how can I achieve this ? Thank you

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  • Problem with PHP & SQL Query

    - by Shahd
    Hi .... i have a problem in php code (inserting values in database) i use PHPMyAdmin my DATABASE has 3 tables: 1) Member with this fields: MemberID, MemberName 2) Room with this fields: RoomID, RoomName 3) Join with this fields: MemberID, RoomID the idea is to join the member in the room. My query was mysql_query("INSERT INTO join (RoomID, MemberID) VALUES ('121', '131')"); but unfortunately it is not work

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  • Update query not effecting all rows in database

    - by Webnet
    I have the following query.... UPDATE vehicle_catalog SET parent_id = 0 WHERE parent_id = SUBSTR(id, 0, 5) I need to set all parent_ids to 0 where the first 5 characters of id is the same as the parent_id. This is effecting 0 rows when I'm looking at the data and it should be effecting over 10,000. Any ideas on why this wouldn't be effecting all rows?

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  • Set default MySQL connect charset for PHP (in RHEL)?

    - by Martijn Heemels
    We're running a hundred or so legacy PHP websites on an older server which runs Gentoo Linux. When these sites were built latin1 was still the common charset, both in PHP and MySQL. To make sure those older sites used latin1 by default, while still allowing newer sites to use utf8 (our current standard), we set the default connect charset in php.ini: mysql.connect_charset = latin1 mysqli.connect_charset = latin1 pdo_mysql.connect_charset = latin1 Specific more modern sites could override this in their bootstrapping code with: <?php mysql_set_charset("utf8", $dsn ); ...and all was well. Now the server is overloaded and we're no longer with that hoster, so we're moving all these sites to a faster server at our standard hoster, which uses RHEL 5 as their OS of choice. In setting up this new server I discover to my surprise that the *.connect_charset directives are a Gentoo specific patch to PHP, and RHEL's version of PHP doesn't recognize them! Now how do I set PHP to connect to MySQL with the latin1 charset? I thought about setting a default in my.cnf but would prefer not to force every app and client to default to latin1. Our policy is to use utf8, and we'd like to restrict the exception to PHP only. Also, converting every legacy site to properly use utf8 is not doable since many are of the touch 'm and you break 'm kind. We simply don't have the time to go fix them all. How would I set a default mysql/mysqli/pdo_mysql connection charset to latin1 for PHP, while still allowing individual scripts to override this to utf8 with mysql_set_charset()?

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