Search Results

Search found 87514 results on 3501 pages for 'open file'.

Page 174/3501 | < Previous Page | 170 171 172 173 174 175 176 177 178 179 180 181  | Next Page >

  • MonoTouch & SQLite - Cannot open database after previous successful connections

    - by Tanis Draven
    I am having difficulty in reading data from my SQLite database from MonoTouch. I can read and write without any difficulty for the first few screens and then suddenly I am unable to create any further connections with the error: Mono.Data.Sqlite.SqliteException: Unable to open the database file at Mono.Data.Sqlite.SQLite3.Open (System.String strFilename, SQLiteOpenFlagsEnum flags, Int32 maxPoolSize, Boolean usePool) [0x0007e] in /Developer/MonoTouch/Source/mono/mcs/class/Mono.Data.Sqlite/Mono.Data.Sqlite_2.0/SQLite3.cs:136 at Mono.Data.Sqlite.SqliteConnection.Open () [0x002aa] in /Developer/MonoTouch/Source/mono/mcs/class/Mono.Data.Sqlite/Mono.Data.Sqlite_2.0/SQLiteConnection.cs:888 I ensure that i dispose and close every connection each time i use it but still i have this problem. For example: var mySqlConn = new SqliteConnection(GlobalVars.connectionString); mySqlConn.Open(); SqliteCommand mySqlCommand = new SqliteCommand(SQL, mySqlConn); mySqlCommand.ExecuteNonQuery(); mySqlConn.Close(); mySqlCommand.Dispose(); mySqlConn.Dispose(); I'm guessing that I'm not closing the connections correctly. Any help would be greatly appreciated.

    Read the article

  • Images saved with D3DXSaveSurfaceToFile will open in Paint, not Photoshop

    - by bsruth
    I'm using D3DXSaveSurfaceToFile to save windowed Direct3D 9 surfaces to PNG, BMP and JPG files. There are no errors returned from the D3DXSaveSurfaceToFile call and all files open fine in Windows Photo Viewer and Paint. But they will not open in a higher end image editing program such as Paint Shop Pro or Photoshop. The error messages from these programs basically say that the file is corrupted. If I open the files in Paint and then save them in the same file format with a different file name, then they'll open fine in the other programs. This leads me to believe that D3DXSaveSurfaceToFile is writing out non-standard versions of these file formats. Is there some way I can get this function to write out files that can be opened in programs like Photoshop without the intermediate step of resaving the files in Paint? Or is there another function I should be using that does a better job of saving a Direct3D surfaces to an image?

    Read the article

  • Symfony and uploadify

    - by Thomas
    Hi! I want to use uploadify with Symfony 1.4, but so far I couldn't. Uploadify loads correctly, I choose my files, it says that the files were successfully uploaded, but the are nowhere. (I'm doing this on localhost) Is there anybody who met this problem before? Thanks, Tom $file = $request->getParameter('file'); $filename = sha1($file->getOriginalName()).$file->getExtension($file->getOriginalExtension()); $file->save(sfConfig::get('sf_upload_dir').'/'.$filename);

    Read the article

  • Open a dialog box in same window on selectOneMenu change

    - by Pravingate
    I have a jsf page where I have a selectOneMenu and , I want to open a dialog box on selectOneMenu changes. As a example if user selects a value ="passive" from jsf selectOneMenu it should open a dialog box or a light box on same page where I want to display a small jsf form like as here done. http://www.primefaces.org/showcase-labs/ui/dialogLogin.jsf and I also want save that submitted data in my backing bean somewhere so I can store it in to database later. I dont know how to open a dialog box or light box from backing bean in same window,as we will identify value change using valueChangeListener event or by using ajax event. I am able to identify which value is selected from selectOneMenu(DropdownMenu), but dont know how to open a dialog box on selecting particular value. <h:outputLabel value="* Country: "/> <h:selectOneMenu id="someSelect" value="#{testController.countryName}" required="true"> <f:selectItem itemLabel="Select Country" itemValue=""/> <f:selectItems value="#{testController.countryNamesSelectItems}"/> </h:selectOneMenu> Supoose we have 2 options in selectItems as India and Austrlia, then If a user choose India a dialog box should open on same page where a user need to fill some information and need to submit if he is from india (like here in example http://www.primefaces.org/showcase-labs/ui/dialogLogin.jsf user will put his username and password and submits data) Hope this helps How can I achieve that by using jsf or javascript or ajax or by any else way?

    Read the article

  • Tabbed browsing, programaticaly navigating to another open tab

    - by jdr120
    Hello, I'm in a discussion with my co-worker. We have a web application in a tabbed browsing environment, say with 2 tabs open. Tab2 has a link to tab1, when I click the link, it opens tab1 in a new tab. We want to detect if tab 1 is already open, if so then set focus to tab1 (and not open a new window). He has gotten this working in a broswer window environment, but says it is not possible in a tabbed environment. Is it possible to for javascript to determine if tab1 is already open and then just set focus to that tab? Thanks in advance!

    Read the article

  • While try to open the project - getting error.

    - by Gopal
    Using Visual Studio 2008 I have .net file name like UPS.Tek, version - Visual Studio 2005 C# files are UPSReport.cs (Visual C# Source File) UPSConn.Cs (Visual C# Source File) UPSBase.cs (Visual C# Source File) ...., When i try to open the C# files individually in VS 2008, the C# files are opening But When I try to open this UPS.Tek in Visual Studio 2008, It showing error as "make sure the application for the project type .csproj is installed" How to solve this error.

    Read the article

  • Uploading multiple files using Spring MVC 3.0.2 after HiddenHttpMethodFilter has been enabled

    - by Tiny
    I'm using Spring version 3.0.2. I need to upload multiple files using the multiple="multiple" attribute of a file browser such as, <input type="file" id="myFile" name="myFile" multiple="multiple"/> (and not using multiple file browsers something like the one stated by this answer, it indeed works I tried). Although no versions of Internet Explorer supports this approach unless an appropriate jQuery plugin/widget is used, I don't care about it right now (since most other browsers support this). This works fine with commons fileupload but in addition to using RequestMethod.POST and RequestMethod.GET methods, I also want to use other request methods supported and suggested by Spring like RequestMethod.PUT and RequestMethod.DELETE in their own appropriate places. For this to be so, I have configured Spring with HiddenHttpMethodFilter which goes fine as this question indicates. but it can upload only one file at a time even though multiple files in the file browser are chosen. In the Spring controller class, a method is mapped as follows. @RequestMapping(method={RequestMethod.POST}, value={"admin_side/Temp"}) public String onSubmit(@RequestParam("myFile") List<MultipartFile> files, @ModelAttribute("tempBean") TempBean tempBean, BindingResult error, Map model, HttpServletRequest request, HttpServletResponse response) throws IOException, FileUploadException { for(MultipartFile file:files) { System.out.println(file.getOriginalFilename()); } } Even with the request parameter @RequestParam("myFile") List<MultipartFile> files which is a List of type MultipartFile (it can always have only one file at a time). I could find a strategy which is likely to work with multiple files on this blog. I have gone through it carefully. The solution below the section SOLUTION 2 – USE THE RAW REQUEST says, If however the client insists on using the same form input name such as ‘files[]‘ or ‘files’ and then populating that name with multiple files then a small hack is necessary as follows. As noted above Spring 2.5 throws an exception if it detects the same form input name of type file more than once. CommonsFileUploadSupport – the class which throws that exception is not final and the method which throws that exception is protected so using the wonders of inheritance and subclassing one can simply fix/modify the logic a little bit as follows. The change I’ve made is literally one word representing one method invocation which enables us to have multiple files incoming under the same form input name. It attempts to override the method protected MultipartParsingResult parseFileItems(List fileItems, String encoding) {} of the abstract class CommonsFileUploadSupport by extending the class CommonsMultipartResolver such as, package multipartResolver; import java.io.UnsupportedEncodingException; import java.util.HashMap; import java.util.Iterator; import java.util.List; import java.util.Map; import javax.servlet.ServletContext; import org.apache.commons.fileupload.FileItem; import org.springframework.util.StringUtils; import org.springframework.web.multipart.MultipartException; import org.springframework.web.multipart.MultipartFile; import org.springframework.web.multipart.commons.CommonsMultipartFile; import org.springframework.web.multipart.commons.CommonsMultipartResolver; final public class MultiCommonsMultipartResolver extends CommonsMultipartResolver { public MultiCommonsMultipartResolver() { } public MultiCommonsMultipartResolver(ServletContext servletContext) { super(servletContext); } @Override @SuppressWarnings("unchecked") protected MultipartParsingResult parseFileItems(List fileItems, String encoding) { Map<String, MultipartFile> multipartFiles = new HashMap<String, MultipartFile>(); Map multipartParameters = new HashMap(); // Extract multipart files and multipart parameters. for (Iterator it = fileItems.iterator(); it.hasNext();) { FileItem fileItem = (FileItem) it.next(); if (fileItem.isFormField()) { String value = null; if (encoding != null) { try { value = fileItem.getString(encoding); } catch (UnsupportedEncodingException ex) { if (logger.isWarnEnabled()) { logger.warn("Could not decode multipart item '" + fileItem.getFieldName() + "' with encoding '" + encoding + "': using platform default"); } value = fileItem.getString(); } } else { value = fileItem.getString(); } String[] curParam = (String[]) multipartParameters.get(fileItem.getFieldName()); if (curParam == null) { // simple form field multipartParameters.put(fileItem.getFieldName(), new String[] { value }); } else { // array of simple form fields String[] newParam = StringUtils.addStringToArray(curParam, value); multipartParameters.put(fileItem.getFieldName(), newParam); } } else { // multipart file field CommonsMultipartFile file = new CommonsMultipartFile(fileItem); if (multipartFiles.put(fileItem.getName(), file) != null) { throw new MultipartException("Multiple files for field name [" + file.getName() + "] found - not supported by MultipartResolver"); } if (logger.isDebugEnabled()) { logger.debug("Found multipart file [" + file.getName() + "] of size " + file.getSize() + " bytes with original filename [" + file.getOriginalFilename() + "], stored " + file.getStorageDescription()); } } } return new MultipartParsingResult(multipartFiles, multipartParameters); } } What happens is that the last line in the method parseFileItems() (the return statement) i.e. return new MultipartParsingResult(multipartFiles, multipartParameters); causes a compile-time error because the first parameter multipartFiles is a type of Map implemented by HashMap but in reality, it requires a parameter of type MultiValueMap<String, MultipartFile> It is a constructor of a static class inside the abstract class CommonsFileUploadSupport, public abstract class CommonsFileUploadSupport { protected static class MultipartParsingResult { public MultipartParsingResult(MultiValueMap<String, MultipartFile> mpFiles, Map<String, String[]> mpParams) { } } } The reason might be - this solution is about the Spring version 2.5 and I'm using the Spring version 3.0.2 which might be inappropriate for this version. I however tried to replace the Map with MultiValueMap in various ways such as the one shown in the following segment of code, MultiValueMap<String, MultipartFile>mul=new LinkedMultiValueMap<String, MultipartFile>(); for(Entry<String, MultipartFile>entry:multipartFiles.entrySet()) { mul.add(entry.getKey(), entry.getValue()); } return new MultipartParsingResult(mul, multipartParameters); but no success. I'm not sure how to replace Map with MultiValueMap and even doing so could work either. After doing this, the browser shows the Http response, HTTP Status 400 - type Status report message description The request sent by the client was syntactically incorrect (). Apache Tomcat/6.0.26 I have tried to shorten the question as possible as I could and I haven't included unnecessary code. How could be made it possible to upload multiple files after Spring has been configured with HiddenHttpMethodFilter? That blog indicates that It is a long standing, high priority bug. If there is no solution regarding the version 3.0.2 (3 or higher) then I have to disable Spring support forever and continue to use commons-fileupolad as suggested by the third solution on that blog omitting the PUT, DELETE and other request methods forever. Just curiously waiting for a solution and/or suggestion. Very little changes to the code in the parseFileItems() method inside the class MultiCommonsMultipartResolver might make it to upload multiple files but I couldn't succeed in my attempts (again with the Spring version 3.0.2 (3 or higher)).

    Read the article

  • JSF Open new window and display bean data

    - by JSFPRINTER
    I am running JSF 2.0 and the latest version of Primefaces 2.2RC1 I believe. I am trying to create a printer friendly window. When the user clicks on a p:commandLink I want a new window to open and display a xhtml file I have named printView.xhtml. Now I can get the window working fine using JavaScript window.open but when I open the new window it will not render any values it just displays everything as #{myBean.value}. Does anyone know how to properly open a window and extend the current scope of the application into that window so I can call all of my managed beans properly and display the values etc. etc.

    Read the article

  • iPhone Network Share Access

    - by user361988
    I am trying to download a data file from a local network share to an iPhone device. I have placed the file on a computer on the network and can view through browsers such as Chrome or Mozilla, from any computer on the local network. However, Safari on a Mac and the iPhone do not find the file! An example of the URL I use is 'file://computer/SharedDocs/file.csv'. Why do Safari and the iPhone fail to find the file?

    Read the article

  • What's the best way to tell if a file exists in a directory?

    - by Nano HE
    I'm trying to move a file but I want to ensure that it exists before I do so. What's the simplest way to do this in Perl? My code is like this. I looked up the open command, but I am not sure it is the simplest way or not. if #Parser.exe exist in directory of Debug { move ("bin/Debug/Parser.exe","Parser.exe"); } elsif #Parser.exe exist in directory of Release { move ("bin/Release/Parser.exe","Parser.exe"); } else { die "Can't find the Parser.exe."; } Thank you.

    Read the article

  • word Application.AddIns.Add throws 'Word cannot open this document template'

    - by Vinay B R
    Hi, I have a template document with a simple macro to insert a file into a document. When i try to load this template file using Application.Addins.Add i am getting an error saying 'Word cannot open this document template'. wordApplication.AddIns.Add( %template file path%, ref trueObj ); This works fine on some machines. Also is there any way to make sure that we load the template file as a global Template always.

    Read the article

  • Ideally How many connections I have to open ?

    - by ranjith-kumar-u
    Hi All, Recently I attended interview in java, the interviewer asked a question like below: I have a request which go throgh A,B,C modules and response go back throgh A , in module A I need to talk to database and again in module C I need to talk to database, so in this situation how many connections you will open and where do you close those connections? My Answer: I said that in module A I will open a connection and I will close it then and there, then control go to module B then module C, in module C again I will open one more connection and i will close it again. then he asked me again another question I want to open one connection per one request processing, how can i do this?

    Read the article

  • How to create a named temporary file in memory?

    - by conradlee
    I would like to use Python's tempfile module to create a temporary file that I will use for communication between processes (use of pipes is awkward). The documentation I've linked to above shows two functions that almost do what I want: tempfile.NamedTemporaryFile # For creating named tempfiles tempfile.SpooledTemporaryFile # For creating tempfiles in memory but actually I want a tempfile that is both named AND in memory. Any ideas?

    Read the article

  • please give me a solution

    - by user327832
    here is the code i have written so far but ended up giving me error import java.io.File; import java.io.FileInputStream; import java.io.IOException; import java.io.InputStream; public class Main { public static void main(String[] args) throws Exception { File file = new File("c:\\filea.txt"); InputStream is = new FileInputStream(file); long length = file.length(); System.out.println (length); bytes[] bytes = new bytes[(int) length]; try { int offset = 0; int numRead = 0; while (numRead >= 0) { numRead = is.read(bytes); } } catch (IOException e) { System.out.println ("Could not completely read file " + file.getName()); } is.close(); Object[] see = new Object[(int) length]; see[1] = bytes; System.out.println ((String[])see[1]); } }

    Read the article

  • Open a file:// protocol with UNC paths in HTML page

    - by ace
    Hi - I'm trying to open a file located on a networkshare by giving the anchor tag path = file://///servername/folder/file.docx This works in IE8 and i'm able to open the file in word, however in Firefox nothing happens. I believe it's due to some secruity settings in Firefox. I tried about:config and turning off the checkloaduri value. But it didnt solve the problem. Does anyone know how I can make this work in both IE and Firefox.

    Read the article

  • How to open links in new window ONLY IF the check box is checked

    - by Travis
    Here is what i have so far. I have it so they open in new windows, but i want it only if the check box is checked... <!DOCTYPE html> <html> <head> <script> function new() { if ( document.getElementById('checkbox').checked ) window.open( 'y', 'n', 't', 'New Window' ); } else { break; } var OpenNew = document.getElementById('opennew'); OpenNew.addEventListener('click', OpenWin, false ); </script> </head> <body> <p> <form name="test"> <p>Open link in a new window &nbsp; <input type="checkbox" id="checkbox" name="check" /></p> </form> </p> <p> <h2>My favorite Websites to visit</h2> <a href="http://www.youtube.com" target="new" id="y">Youtube</a><br /> <a href="http://www.newegg.com" target="new" id="n">Newegg</a><br /> <a href="http://www.twitch.tv" target="new" id="t">Twitch.tv</a><br /> </p> </body> </html> I am unsure how to actually do the if statement if it is checked then open. It does currently open in a new tab.. i just need it to be only when its checked. Any help with this will be greatly appreciated! Thanks!

    Read the article

  • Permission denied on IE using window.open()?

    - by Alex
    Hello all, IE is giving me a permission denied error when I use window.open to open a window from a browser button. I do not get the error in Firefox or Chrome. What do I do? The code: <button type="button" onClick="window.open('https://www.example.com','newWindow');"> My button </button>

    Read the article

  • How Can open root in iphone?

    - by Fatemeh
    Hi , I want to knowing how can i open root directory ? I know Messages saved in sms.db that is in "/var/root/Library/SMS/sms.db" , but I can not see sub folder of root, I know ,the root have password and should enter it to open ,... but how can open this without Unlock or entering password?

    Read the article

< Previous Page | 170 171 172 173 174 175 176 177 178 179 180 181  | Next Page >