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• Cursor image to the center on mouseout

  - by Milla

  Hi all! I'm a real noobie with flash and I was wondering if somebody could help me with this one. I have this actionsript 3 code, where the cursor image "ball_mc" follows the mouse's position with a slight delay: stage.addEventListener(Event.ENTER_FRAME,followBall); function followBall(event:Event):void { var dx:int = ball_mc.x - mouseX; var dy:int = ball_mc.y - mouseY; ball_mc.x -= dx / 5; ball_mc.y -= dy /5; } 1) How can I get the cursor image automatically return to the center of the stage on mouseout? As of now, it stays at the position where the mouse leaves the stage. 2) How can I reverse the movement of the mouse? So that when I, for example, move mouse to the right, the cursor image would move to the left? And when moving the mouse up, the image would go down. The stage is 800 x 250 pixels, in case that makes any difference.

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• How to keep a trace of a record inside a nested repeater?

  - by Amokrane

  Hi, I have the following implementation: As you can see I have a repeater (listing the Machines) and a nested repeater (listing the WindowsServices inside each Machine). For each Windows Service I can perform an action using a button. However, to perform this action I need to know which Machine and which WindowsService are concerned. This is my code: protected void Page_Init(object sender, EventArgs e) { rptMachine.ItemDataBound += new RepeaterItemEventHandler(rptMachine_ItemDataBound); } protected void Page_Load(object sender, EventArgs e) { // bind the Machine repeater rptMachine.DataSource = _monitoringService.Machines; rptMachine.DataBind(); } protected void rptMachine_ItemDataBound(object sender, RepeaterItemEventArgs e) { if (e.Item.ItemType == ListItemType.Item || e.Item.ItemType == ListItemType.AlternatingItem) { Repeater nestedRepeater = (Repeater) e.Item.FindControl("rptWindowsService"); nestedRepeater.DataSource = ((IMachine) e.Item.DataItem).WindowsServices; nestedRepeater.DataBind(); Button btnActionInner = null; // bind the action button situated inside the nested repeater foreach(RepeaterItem ri in nestedRepeater.Items) { if((Button)ri.FindControl("btnAction") != null) { btnActionInner = (Button) ri.FindControl("btnAction"); btnActionInner.CommandName = "ActionState"; btnActionInner.CommandArgument = strWindowsService; } } } } protected void rptWindowsService_ItemCommand(object source, RepeaterCommandEventArgs e) { // do the specific action stop/run for the windows service if (e.CommandName == "ActionState") { if(((Button)(e.CommandSource)).Text.Equals("Stop")) { } else if(((Button)(e.CommandSource)).Text.Equals("Run")) { } } } } } So basically I need to know (inside rptWindowsService_ItemCommand) what is the pair that is concerned by the operation. What's the best way to do that? Don't hesitate to ask for more clarifications! Thanks

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• Why function Ellipse(...) are needed twice here to draw an ellipse?

  - by John Son

  MFC: I read this code which is to draw an ellipse (not solid interior), but I cannot understand why function "pDC-Ellipse(...)" is needed twice here? CDC *pDC=GetDC(); CPen pen; CBrush brush; getpen(pen,pDC,col,bol); if(do_what>=DRAW_LINE&&do_what<=DRAW_RRECT){ p->p[0]=start; p->p[1]=end; if(sol==1){ getbrush(brush,pDC,col); } if(do_what==DRAW_LINE){ pDC->MoveTo(start); pDC->LineTo(end); } else if(do_what==DRAW_ELLIPSE||do_what==DRAW_CIRCLE){ pDC->SetROP2(R2_NOT); assist=start; if(do_what==DRAW_CIRCLE){ assist.y=end.y-end.x+start.x; } pDC->Ellipse(start.x,assist.y,end.x,end.y); pDC->SetROP2(R2_COPYPEN); if(sol==0){ pDC->SelectStockObject(NULL_BRUSH); } if(do_what==DRAW_CIRCLE){ assist.y=point.y-point.x+start.x; } pDC->Ellipse(start.x,assist.y,point.x,point.y); end=point; } } If I remove the first one, the ellipse will be black solid inside. If I remove the second one, the ellipse will never be drawn but disappears when left mouse button is up. the dialog: when moving mouse: mouse moving when mouse button pops: mouse button pops Besides, what color of CBrush is if I use "CBrush brush; pDC-Ellipse(start.x,assist.y,end.x,end.y);"

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• C# override WndProc in Control level to detect

  - by Nullstr1ng

  I have overridden WndProc in UserControl level to detect MouseDown, MouseUp, and MouseMove to any Control added in that UserControl. protected override void WndProc(ref Message m) { Point mouseLoc = new Point(); switch (m.Msg) { case WM_LBUTTONDOWN: System.Diagnostics.Debug.WriteLine("mouse down"); //this.OnMouseDown(new MouseEventArgs(MouseButtons.Left, 1, mouseLoc.X, mouseLoc.Y, 0)); break; case WM_LBUTTONUP: System.Diagnostics.Debug.WriteLine("mouse up"); //this.OnMouseDown(new MouseEventArgs(MouseButtons.Left, 1, mouseLoc.X,mouseLoc.Y, 0)); break; case WM_MOUSEMOVE: int lParam = m.LParam.ToInt32(); //mouseLoc.X = lParam & 0xFFFF; //mouseLoc.Y = (int)(lParam & 0xFFFF0000 >> 16); mouseLoc.X = (Int16)m.LParam; mouseLoc.Y = (Int16)((int)m.LParam >> 16); System.Diagnostics.Debug.WriteLine("mouse move: " + mouseLoc.X + ", " + mouseLoc.Y); //this.OnMouseDown(new MouseEventArgs(MouseButtons.Left, 1, mouseLoc.X,mouseLoc.Y, 0)); break; } base.WndProc(ref m); } MouseMove, Down, and Up are working when the mouse pointer is in UserControl but when the mouse pointer is on other control (inside my UserControl) it doesn't work. Am I doing something wrong? Currently developing a flick and scroll control.

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• Java swing hold buttons

  - by Simon Charette

  Hi, I'm trying to create a subclass of JButton or AbstractButton that would call specified .actionPerformed as long as the mouse is held down on the button. So far I was thinking of extending JButton, adding a mouse listener on creation (inside constructor) and calling actionPerformed while the mouse is down. So far i came up with that but I was wondwering if I was on the right track and if so, how to correctly implement the "held down" logic. package components; import java.awt.event.ActionEvent; import java.awt.event.MouseEvent; import java.awt.event.MouseListener; import javax.swing.Action; import javax.swing.Icon; import javax.swing.JButton; public class HoldButton extends JButton { private class HeldDownMouseListener implements MouseListener { private boolean mouseIsHeldDown; private HoldButton button; private long millis; public HeldDownMouseListener(HoldButton button, long millis) { this.button = button; this.millis = millis; } @Override public void mouseClicked(MouseEvent arg0) { } @Override public void mouseEntered(MouseEvent arg0) { } @Override public void mouseExited(MouseEvent arg0) { } @Override public void mousePressed(MouseEvent arg0) { mouseIsHeldDown = true; // This should be run in a sub thread? // while (mouseIsHeldDown) { // button.fireActionPerformed(new ActionEvent(button, ActionEvent.ACTION_PERFORMED, "heldDown")); // try { // Thread.sleep(millis); // } catch (InterruptedException e) { // e.printStackTrace(); // continue; // } // } } @Override public void mouseReleased(MouseEvent arg0) { mouseIsHeldDown = false; } } public HoldButton() { addHeldDownMouseListener(); } public HoldButton(Icon icon) { super(icon); addHeldDownMouseListener(); } public HoldButton(String text) { super(text); addHeldDownMouseListener(); } public HoldButton(Action a) { super(a); addHeldDownMouseListener(); } private void addHeldDownMouseListener() { addMouseListener(new HeldDownMouseListener(this, 300)); } } Thanks a lot for your time.

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• emacs: Inferior-mode python-shell appears "lagged"

  - by Begbie00

  Hi all - I'm a Python(3.1.2)/emacs(23.2) newbie teaching myself tkinter using the pythonware tutorial found here. Relevant code is pasted below the question. Question: when I click the Hello button (which should call the say_hi function) why does the inferior python shell (i.e. the one I kicked off with C-c C-c) wait to execute the say_hi print function until I either a) click the Quit button or b) close the root widget down? When I try the same in IDLE, each click of the Hello button produces an immediate print in the IDLE python shell, even before I click Quit or close the root widget. Is there some quirk in the way emacs runs the Python shell (vs. IDLE) that causes this "lagged" behavior? I've noticed similar emacs lags vs. IDLE as I've worked through Project Euler problems, but this is the clearest example I've seen yet. FYI: I use python.el and have a relatively clean init.el... (setq python-python-command "d:/bin/python31/python") is the only line in my init.el. Thanks, Mike === Begin Code=== from tkinter import * class App: def __init__(self,master): frame = Frame(master) frame.pack() self.button = Button(frame, text="QUIT", fg="red", command=frame.quit) self.button.pack(side=LEFT) self.hi_there = Button(frame, text="Hello", command=self.say_hi) self.hi_there.pack(side=LEFT) def say_hi(self): print("hi there, everyone!") root = Tk() app = App(root) root.mainloop()

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• Nested ListBox in DataGrid? Inherit style?

  - by Chris

  I have a DataGrid with multiple columns. The data grid has a style that changes the forecolor of text on a row where the mouse is over or the row has been selected. So the text color will change from black to white, for example. In one of the columns in the data grid, I have a ListBox. Is it possible for the items in the list box to have the foreground change to that of the data grid row, when you do mouse over or select the data grid row? I don't want to have a style for the list box that is specific to mouse over for the list items, I just want the foreground of the list items to change automatically to the forground of the data grid row when the mouse is over the row or selected the row. So even if the user moves their mouse over a different column (that doesn't contain the listbox) - I would want the foreground for the listbox to change. How can I go about doing this? ValueConverter? Thanks. Chris

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• How to create a new widget for dojox.grid.cells.dijit?

  - by the_drow

  I am trying to create a button widget for dojox.grid. My problems are: 1) The button is only shown when I double click the grid. 2) I can't figure out how to set attributes through declarative markup. It seems that the markupFactory function is responsible for it but it doesn't set the widget's label. The following code demonstrates what I've got so far: dojo.require("dojox.grid.DataGrid"); dojo.require("dojo.data.ItemFileWriteStore"); dojo.require("dijit.form.Button"); dojo.require("dojox.grid.cells.dijit"); dojo.require("dojo.parser"); dojo.declare("dojox.grid.cells.Button", dojox.grid.cells._Widget, { widgetClass: dijit.form.Button, alwaysEditing: true, constructor: function(inCell) { this.inherited(arguments); this.widget = new dijit.form.Button; }, setValue: function(inRowIndex, inValue){ if (this.widget) { this.widget.attr('value', inValue); } else { this.inherited(arguments); } } }); dojox.grid.cells.Button.markupFactory = function(node, cell) { dojox.grid.cells._Widget.markupFactory(node, cell); }

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• JavaScript + Maths: Image zoom with CSS3 Transforms, How to set Origin? (with example)

  - by Sunday Ironfoot

  My Math skills really suck! I'm trying to implement an image zoom effect, a bit like how the Zoom works with Google Maps, but with a grid of fix position images. I've uploaded an example of what I have so far here: http://www.dominicpettifer.co.uk/Files/MosaicZoom.html (uses CSS3 transforms so only works with Firefox, Opera, Chrome or Safari) Use your mouse wheel to zoom in/out. The HTML source is basically an outer div with an inner-div, and that inner-div contains 16 images arranged using absolute position. It's going to be a Photo Mosaic basically. I've got the zoom bit working using CSS3 transforms: $(this).find('div').css('-moz-transform', 'scale(' + scale + ')'); ...however, I'm relying on the mouse X/Y position on the outer div to zoom in on where the mouse cursor is, similar to how Google Maps functions. The problem is that if you zoom right in on an image, move the cursor to the bottom/left corner and zoom again, instead of zooming to the bottom/left corner of the image, it zooms to the bottom/left of the entire mosaic. This has the effect of appearing to jump about the mosaic as you zoom in closer while moving the mouse around, even slightly. That's basically the problem, I want the zoom to work exactly like Google Maps where it zooms exactly to where your mouse cursor position is, but I can't get my head around the Maths to calculate the transform-origin: X/Y values correctly. Please help, been stuck on this for 3 days now. Here is the full code listing for the mouse wheel event: var scale = 1; $("#mosaicContainer").mousewheel(function(e, delta) { if (delta > 0) { scale += 1; } else { scale -= 1; } scale = scale < 1 ? 1 : (scale > 40 ? 40 : scale); var x = e.pageX - $(this).offset().left; var y = e.pageY - $(this).offset().top; $(this).find('div').css('-moz-transform', 'scale(' + scale + ')') .css('-moz-transform-origin', x + 'px ' + y + 'px'); return false; });

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• Is there a way to catch a MOUSE_UP Event over a static textfield in Flash?

  - by Jovica Aleksic

  When the user presses the mouse, and releases it over a static textfield with selectable text, no MOUSE_UP event is fired - not on the stage and also nowhere else. I experienced this when using a scrollbar class on a movieclip with a nested static textfield. When the user drags the scroll handle and releases the mouse over the textfield, the dragging/scrolling is stuck. To test this, create a new AS3 fla file, place a static textfield somewhere, and put in some text. Make sure the selectable property is checked in the properties panel. Add this script to the timeline: import flash.events.* function down(event:Event):void { trace('down'); } function up(event:Event):void { trace('up'); } stage.addEventListener(MouseEvent.MOUSE_DOWN, down) stage.addEventListener(MouseEvent.MOUSE_UP, up) Now test the movie and click the mouse. You will notice that trace('up') will not occur when you release the mouse over the textfield.

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• Sliding doors HTML buttons in Safari Win

  - by RyanP13

  Hi, I have the following HTML for buttons implementing sliding doors technique that look fine in everything but Safari on Windows: <button type="submit"> <span>Button</span> </button> This is the corresponding CSS: button { background:url("../images/sprBgBtn.png") no-repeat right -47px; border:0; cursor:pointer; font-weight:bold; height:27px; line-height:27px; overflow:visible; padding:0 26px 0 0; position:relative; text-align:center; text-transform:uppercase; width:auto; } button::-moz-focus-inner { border: none; /* overrides extra padding in Firefox */ padding:0; } button span { background:url("../images/sprBgBtn.png") no-repeat left top; display:block; height:27px; line-height:27px; padding:0 0 0 26px; position:relative; white-space:nowrap; } If i omit the following code then the same issue will appear in FFOX: button::-moz-focus-inner { border: none; /* overrides extra padding in Firefox */ padding:0; }

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• Android Video Layout and backbutton to activity

  - by Marcjc

  I have an application where you can click on a button, this takes you to a new activity with four new buttons, listen, bio, ringtone, and watch. My watch button kicks off the following code: Button cmd_watchme = (Button)this.findViewById(R.id.watch); cmd_watchme.setOnClickListener(new View.OnClickListener() { public void onClick(View view) { setContentView(R.layout.tvvideo); VideoView video=(VideoView)findViewById(R.id.VideoView); MediaController mediaController = new MediaController(andy.this); mediaController.setAnchorView(video); video.setMediaController(mediaController); video.setVideoURI(videopath); video.start(); } }); After the video is displayed I am trying to get the backbutton on the phone itself to take the user back to the four button selection activity, listen, bio, ringtone, and watch. Question is, how do i do this? I was figuring if there was a way to change the ContentView after the video is displayed back to the main one for the four button page but could not figure it out. When I press the backbutton on the device, it takes me two levels up to the main selection activity not the four button activity. I hope this was somewhat clear. Thanks for any help.

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• about onmouseout event.

  - by lazyanno

  as follow codes: <div id="outerBox" style="border:1px solid red;width:300;height:300" onmouseout="alert('out')"> <div id="innerBox" style="border:1px solid blue;width:50;height:50">inner</div> </div> why when i move mouse on the "innerBox", it was trigger alert('out') ? i want mouse out "outerBox" trigger alert('out') only, mouse on "innerBox" don't trigger alert. hot to do this? thanks all :)

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• Autocomplete problem with scrollbar

  - by Geetha

  Hi All, I am using autocomplete with scrollbar for my textbox. Autocomplete for touch screen. I can scroll up and down using the mouse wheel but i want to Use the mouse button to scroll up or down by dragging the scroll bar. if i use mouse button it moves the focus away from the text box field. Autocomplete is working only when using the keyboard not with the user defined keys. Geetha

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• c# change global cursor

  - by andySF

  Hi, it is possible to change global mouse cursor from c#? the thing is i use a global hook shortcut key to capture a window like spywindow and i want to change mouse cursor globally when i select my handle and restore it when i click left mouse. Another question is about the click itself. When I'm in capture mode can i take click just for my purpose?it will be nice if i didn't press stuff on screen when i select my window!. Thanks!

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• Color picker does not give gradient appearance

  - by ykaratoprak

  i added below codes. But it generates to me 16 color. but i need 16 color between "red" and "khaki". i don't need gradient flow. My colors look like gradient flow. My colors must not closer to each other. Because i will use this codes return values in chart columns. they are too near each other. static class Program { [STAThread] static void Main() { Form form = new Form(); Color start = Color.Red, end = Color.Khaki; for (int i = 0; i < 16; i++) { int r = Interpolate(start.R, end.R, 15, i), g = Interpolate(start.G, end.G, 15, i), b = Interpolate(start.B, end.B, 15, i); Button button = new Button(); button.Dock = DockStyle.Top; button.BackColor = Color.FromArgb(r, g, b); form.Controls.Add(button); button.BringToFront(); } Application.Run(form); } static int Interpolate(int start, int end, int steps, int count) { float s = start, e = end, final = s + (((e - s) / steps) * count); return (int)final; } }

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• Using javascript to add form fields, but what will the new name be?

  - by user1322844

  After reading this post: using javascript to add form fields.. but below, not to the side? I've made the button work! But I don't know how to receive the output. This is what I entered. var counter = 0; function addNew() { // Get the main Div in which all the other divs will be added var mainContainer = document.getElementById('mainContainer'); // Create a new div for holding text and button input elements var newDiv = document.createElement('div'); // Create a new text input var newText = document.createElement('input'); newText.type = "input"; newText.maxlength = "50"; newText.maxlimit = "50"; newText.size = "60"; newText.value = counter; // Create a new button input var newDelButton = document.createElement('input'); newDelButton.type = "button"; newDelButton.value = "Delete"; // Append new text input to the newDiv newDiv.appendChild(newText); // Append new button input to the newDiv newDiv.appendChild(newDelButton); // Append newDiv input to the mainContainer div mainContainer.appendChild(newDiv); counter++; // Add a handler to button for deleting the newDiv from the mainContainer newDelButton.onclick = function() { mainContainer.removeChild(newDiv); } } </script> With this in the form: <input type="button" size="3" cols="30" value="Add" onClick="addNew()"> So, what will the new field names be? I don't understand enough of the coding to figure out what I'm telling it to. Good thing there are other smart folks out there for me to lean on! Thanks for any answers.

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• JavaFX 2.0 - How to change legend color of a LineChart dynamically?

  - by marie

  I am trying to style my JavaFX linechart but I have some trouble with the legend. I know how to change the legend color of a line chart in the css file: .default-color0.chart-series-line { -fx-stroke: #FF0000, white; } .default-color1.chart-series-line { -fx-stroke: #00FF00, white; } .default-color2.chart-series-line { -fx-stroke: #0000FF, white; } .default-color0.chart-line-symbol { -fx-background-color: #FF0000, white; } .default-color1.chart-line-symbol { -fx-background-color: #00FF00, white; } .default-color2.chart-line-symbol { -fx-background-color: #0000FF, white; } But this is not enough for my purposes. I have three or more colored toggle buttons and a series of data for every button. The data should be displayed in the same color the button has after I have selected the button. This should be possible with a multiselection of the buttons, so that more than one series of data can be displayed simultaneously. For the chart lines I have managed it by changing the style after I clicked the button: .. dataList.add(series); .. series.getNode().setStyle("-fx-stroke: rgba(" + rgba + ")"); If I deselect the button I remove the data from the list. dataList.remove(series); That is working fine for the strokes, but how can I do the same for the legend? You can see an example below. First I clicked the red button, thus the stroke and the legend is red (default-color0). After that I clicked the blue button. Here you can see the problem. The stroke is blue but the legend is green, because default color1 is used and I do not know how to change the legend color.

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• Android problem with opening a second activity and fails to launch

  - by Capsud

  Hi there, Bear with me as i'm just learning about Android. What i'm trying to do is to open an Activity when i click on a button. This is my code in my main activity public class MainPage extends Activity { /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); Button restaurants = (Button) findViewById(R.id.widget88); restaurants.setOnClickListener(new View.OnClickListener() { public void onClick(View view) { Intent myIntent = new Intent(view.getContext(), AZRestaurants.class); startActivityForResult(myIntent, 0); } }); //Button location = (Button) findViewById(R.id.location); //location.setOnClickListener(new View.OnClickListener() { //public void onClick(View view) { // Intent myIntent = new Intent(view.getContext(), Location.class); // startActivity(myIntent); //} // }); } The program launches no problem when i just implement the first button (restuarant). But when i try to implement the button that i have commented out it fails to launch. and yes i have added the activity to the manifest file. Can anyone help me please? Thanks.

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• What is the best way to identify which form has been submitted?

  - by Rupert

  Currently, when I design my forms, I like to keep the name of the submit button equal to the id of the form. Then, in my php, I just do if(isset($_POST['submitName'])) in order to check if a form has been submitted and which form has been submitted. Firstly, are there any security problems or design flaws with this method? One problem I have encountered is when I wish to overlay my forms with javascript in order to provide faster validation to the user. For example, whilst I obviously need to retain server side validation, it is more convenient for the user if an error message is displayed inline, upon blurring an input. Additionally, it would be good to provide entire form validation, upon clicking the submit button. Therefore, when the user clicks on the form's submit button, I am stopping the default action, doing my validation, and then attempting to renable the traditional submit functionality, if the validation passes. In order to do this, I am using the form.submit() method but, unfortunately, this doesn't send the submit button variable (as it should be as form.submit() can be called without any button being clicked). This means my PHP script fails to detect that the form has been submitted. What is the correct way to work around this? It seems like the standard solution is to add a hidden field into the form, upon passing validation, which has the name of form's id. Then when form.submit() is called, this is passed along in place of the submit button. However, this solution seems very ungraceful to me and so I am wondering whether I should: a) Use an alternative method to detect which form has been submitted which doesn't rely rely on passing the submit button. If so what alternative is there? Obviously, just having an extra hidden field from the start isn't any better. b) Use an alternative Javascript solution which allows me to retain my non-Javascript design. For example, is there an alternative to form.submit() which allows me to pass in extra data? c) Suck it up and just insert a hidden field using Javascript.

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• Radiobutton in iphone

  - by Harita

  hi, i am using radio button image (empty circle) in button to answer the question from 3 options, and the 3 options are radio button's. i have created 3 uibuttons programmatically in tableview delegate method cellforrowatindexpath. i need when one button is selected(with filled circle image) other one if selected before gets unselected. i am using below code in button clicked method. static int _row; -(IBAction) optionClicked:(id)sender { UIButton *btn = (UIButton)sender; _row = btn.tag; if (btn.tag == 0) { if(btn1On) { [btnrad1 setImage:[UIImage imageNamed:@"unfilled.png"]forState:UIControlStateNormal]; btn1On=FALSE; } else { [btnrad1 setImage:[UIImage imageNamed:@"filled.png"]forState:UIControlStateNormal]; btn1On = TRUE; btn2On = FALSE; btn3On = FALSE; } } else if (btn.tag == 1) { if(btn2On) { [btnrad2 setImage:[UIImage imageNamed:@"unfilled.png"]forState:UIControlStateNormal]; btn2On=FALSE; } else { [btnrad2 setImage:[UIImage imageNamed:@"filled.png"]forState:UIControlStateNormal]; btn2On = TRUE; btn1On = FALSE; btn3On = FALSE; } } else if (btn.tag == 2) { if(btn3On) { [btnrad3 setImage:[UIImage imageNamed:@"unfilled.png"]forState:UIControlStateNormal]; btn3On=FALSE; } else { [btnrad3 setImage:[UIImage imageNamed:@"filled.png"]forState:UIControlStateNormal]; btn3On = TRUE; btn1On = FALSE; btn2On = FALSE; } } else { NSLog(@"Error"); } } above code is doing selection of button in another row. like i am selecting 1st option in 1st row but its is selecting 2nd row button. i don't know how to use _row to check for every cell of table view.

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• javascript get text at mose postion

  - by Vasioky

  How can I get text at mouse position? I have now some like this document.body.onmousemove = function(){ //todo:Get text at mouse position }

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• A simple way to put a UIImage in a UIButton

  - by Alice

  I have a UIButton in my iPhone app. I set its size to 100x100. I have an image that is 400x200 that I wish to display in the button. The button STILL needs to stay at 100x100... and I want the image to downsize to fit... but keep the correct aspect ratio. I thought that's what "Aspect Fit" was used for. Do I include my image with setImage, or setBackgroundImage? Do I set AspectFit for the button? or the image? or the background image? (I need the smaller images to INCREASE in size. While larger images should DESCREASE in size. Always keeping the button at 100x100.) I've tried countless combinations of all of the above... and I just can't seem to get everything to work at the same time: Don't change the button's size of 100x100. Don't destroy the image's aspect ratio. Always increase small images to fit the button. Always decrease large images to fit the button. Never clip any of the image edges. Never require the "put UIButtons over all your UIimages" hack. Don't require everyone to upgrade to v4.2.1 just to use new framework methods. I see so many apps, with so many fully-working image-buttons... that I can't believe I can't figure out this very simple, very common thing. Ugh.

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• How to repeatedly show a Dialog with PyGTK / Gtkbuilder?

  - by Julian

  I have created a PyGTK application that shows a Dialog when the user presses a button. The dialog is loaded in my __init__ method with: builder = gtk.Builder() builder.add_from_file("filename") builder.connect_signals(self) self.myDialog = builder.get_object("dialog_name") In the event handler, the dialog is shown with the command self.myDialog.run(), but this only works once, because after run() the dialog is automatically destroyed. If I click the button a second time, the application crashes. I read that there is a way to use show() instead of run() where the dialog is not destroyed, but I feel like this is not the right way for me because I would like the dialog to behave modally and to return control to the code only after the user has closed it. Is there a simple way to repeatedly show a dialog using the run() method using gtkbuilder? I tried reloading the whole dialog using the gtkbuilder, but that did not really seem to work, the dialog was missing all child elements (and I would prefer to have to use the builder only once, at the beginning of the program). [SOLUTION] As pointed out by the answer below, using hide() does the trick. But one has to take care that the dialog is in fact destroyed if one does not catch its "delete-event". A simple example that works is: import pygtk import gtk class DialogTest: def rundialog(self, widget, data=None): self.dia.show_all() result = self.dia.run() def destroy(self, widget, data=None): gtk.main_quit() def closedialog(self, widget, data=None): self.dia.hide() return True def __init__(self): self.window = gtk.Window(gtk.WINDOW_TOPLEVEL) self.window.connect("destroy", self.destroy) self.dia = gtk.Dialog('TEST DIALOG', self.window, gtk.DIALOG_MODAL | gtk.DIALOG_DESTROY_WITH_PARENT) self.dia.vbox.pack_start(gtk.Label('This is just a Test')) self.dia.connect("delete-event", self.closedialog) self.button = gtk.Button("Run Dialog") self.button.connect("clicked", self.rundialog, None) self.window.add(self.button) self.button.show() self.window.show() if __name__ == "__main__": testApp = DialogTest() gtk.main()

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• string combinations

  - by vbNewbie

  I would like to generate a combination of words. For example if I had the following list: {cat, dog, horse, ape, hen, mouse} then the result would be n(n-1)/2 cat dog horse ape hen mouse (cat dog) (dog horse) (horse ape) (ape hen) (hen mouse) (cat dog horse) (dog horse ape) (horse ape hen) etc Hope this makes sense...everything I found involves permutations The list I have would be a 500 long

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