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  • Creating a dictionary with list of lists in Python

    - by ghbhatt
    I have a huge file (with around 200k inputs). The inputs are in the form: A B C D B E F C A B D D I am reading this file and storing it in a list as follows: text = f.read().split('\n') This splits the file whenever it sees a new line. Hence text is like follows: [[A B C D] [B E F] [C A B D] [D]] I have to now store these values in a dictionary where the key values are the first element from each list. i.e the keys will be A, B, C, D. I am finding it difficult to enter the values as the remaining elements of the list. i.e the dictionary should look like: {A: B C D; B: E F; C: A B D; D: 0} I have done the following: inlinkDict = {} for doc in text: adoc= doc.split(' ') docid = adoc[0] inlinkDict[docid] = inlinkDict.get(docid,0) + {I do not understand what to put in here} Please help as to how should i add the values to my dictionary. It should be 0 if there are no elements in the list except for the one which will be the key value. Like in example for 0.

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  • Python: Problems finding string in website source code

    - by j00niner
    I open a website with urlopen. I then put the website sourcecode into a variable like so source = website.read() When I just print the source it comes out formatted correctly, however when I try to iterate through each line each character is it's own line. for example when I just print it looks like this <HTML> title</html> When I do this for line in source: print line it looks like this < H T M L ... etc I need to find a string that starts with "var" and then print that entire line.

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  • Hashing (hidding) strings in Python

    - by Lucas
    What I need is to hash a string. It doesn't really have to be secure because its just going to be a hidden pharse in the text file (simply it doesn't have to be recognizable for a human-eye). It should not be just a random string because when user will be typing the string I would like to hash it and compare it with already hashed one (in the text file). What would be the best for this purpose? Can it be done with the own class?

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  • Problem with python !!

    - by the-ifl
    Well I Have a little problem , i want to Get the sum of all numbers below to 1000000 , and who has 4 Divisors... I Try but i have a problem : http://pastebin.com/bhiDb5fe

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  • Downloading files from an http server in python

    - by cellular
    Using urllib2, we can get the http response from a web server. If that server simply holds a list of files, we could parse through the files and download each individually. However, I'm not sure what the easiest, most pythonic way to parse through the files would be. When you get a whole http response of the generic file server list, through urllib2's urlopen() method, how can we neatly download each file?

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  • Python finding repeating sequence in list of integers?

    - by tijko
    I have a list of lists and each list has a repeating sequence. I'm trying to count the length of repeated sequence of integers in the list: list_a = [111,0,3,1,111,0,3,1,111,0,3,1] list_b = [67,4,67,4,67,4,67,4,2,9,0] list_c = [1,2,3,4,5,6,7,8,9,0,1,2,3,4,5,6,7,8,9,0,23,18,10] Which would return: list_a count = 4 (for [111,0,3,1]) list_b count = 2 (for [67,4]) list_c count = 10 (for [1,2,3,4,5,6,7,8,9,0]) Any advice or tips would be welcome. I'm trying to work it out with re.compile right now but, its not quite right.

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  • Python: Random integer

    - by user3696440
    I been hitting a wall thats been keeping me from tinkering on a game. class Damage: def shortsword(): shortsword=randint(1,6)+1 shortsword=int(shortsword) return shortsword I been wanting this number to pop up as part of a message on print and then use the same number as part of another function to help with subtracting of health on the target. Though each time I grab this it is always going to change.

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  • Convert a python dict to a string and back

    - by AJ00200
    I am writing a program that stores data in a dictionary object, but this data needs to be saved at some point during the program execution and loaded back into the dictionary object when the program is run again. How would I convert a dictionary object into a string that can be written to a file and loaded back into a dictionary object? This will hopefully support dictionaries containing dictionaries.

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  • Python - creating a list with 2 characteristics bug

    - by user2733911
    The goal is to create a list of 99 elements. All elements must be 1s or 0s. The first element must be a 1. There must be 7 1s in total. import random import math import time # constants determined through testing generation_constant = 0.96 def generate_candidate(): coin_vector = [] coin_vector.append(1) for i in range(0, 99): random_value = random.random() if (random_value > generation_constant): coin_vector.append(1) else: coin_vector.append(0) return coin_vector def validate_candidate(vector): vector_sum = sum(vector) sum_test = False if (vector_sum == 7): sum_test = True first_slot = vector[0] first_test = False if (first_slot == 1): first_test = True return (sum_test and first_test) vector1 = generate_candidate() while (validate_candidate(vector1) == False): vector1 = generate_candidate() print vector1, sum(vector1), validate_candidate(vector1) Most of the time, the output is correct, saying something like [1, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 1, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0] 7 True but sometimes, the output is: [0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0] 2 False What exactly am I doing wrong?

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  • Reading from CSVs in Python repeatedly?

    - by matt
    I'm trying to check the value of extracted data against a csv I already have. It will only loop through the rows of the CSV once, I can only check one value of feed.items(). Is there a value I need to reset somewhere? Is there a better/more efficient way to do this? Thanks. orig = csv.reader(open("googlel.csv", "rb"), delimiter = ';') goodrows = [] for feed in gotfeeds: for link,comments in feed.items(): for row in orig: print link if link in row[1]: row.append(comments) goodrows.append(row)

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  • Search inside dynamic array in python

    - by user2091683
    I want to implement a code that loops inside an array that its size is set by the user that means that the size isn't constant. for example: A=[1,2,3,4,5] then I want the output to be like this: [1],[2],[3],[4],[5] [1,2],[1,3],[1,4],[1,5] [2,3],[2,4],[2,5] [3,4],[3,5] [4,5] [1,2,3],[1,2,4],[1,2,5] [1,3,4],[1,3,5] and so on [1,2,3,4],[1,2,3,5] [2,3,4,5] [1,2,3,4,5] Can you help me implement this code?

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  • Recurrent yearly date alert in Python

    - by coulix
    Hello Hackerz, Here is the idea A user can set a day alert for a birthday. (We do not care about the year of birth) He also picks if he wants to be alerted 0, 1, 2, ou 7 days (Delta) before the D day. Users have a timezone setting. I want the server to send the alerts at 8 am on the the D day - deleta +- user timezone Example: 12 jun, with "alert me 3 days before" will give 9 of Jun. My idea was to have a trigger_datetime extra field saved on the 'recurrent event' object. Like this a cron Job running every hour on my server will just check for all events matching irs current time hour, day and month and send to the alert. The problem from a year to the next the trigger_date could change ! If the alert is set on 1st of March, with a one day delay that could be either 28 or 29 of February .. Maybe i should not use the trigger date trick and use some other kind of scheme. All plans are welcome.

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  • Python | How to append elements to a list randomly

    - by MMRUser
    Is there a way to append elements to a list randomly, built in function ex: def random_append(): lst = ['a'] lst.append('b') lst.append('c') lst.append('d') lst.append('e') return print lst this will out put ['a', 'b', 'c', 'd', 'e'] But I want it to add elements randomly and out put something like this: ['b', 'd', 'b', 'e', 'c'] And yes there's a function random.shuffle() but it shuffles a list at once which I don't require, I just want to perform random inserts only.

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  • Shell halts while looping and 'transforming' values in dictionary (Python 2.7.5)

    - by Gus
    I'm building a program that will sum digits in a given list in a recursive way. Say, if the source list has 10 elements, the second list will have 9, the third 8 and so on until the last list that will have only one element. This is done by adding the first element to the second, then the second to the third and so on. I'm stuck without feedback from the shell. It halts without throwing any errors, then in a couple of seconds the fan is spinning like crazy. I've read quite a few posts here and changed my approach, but I'm not sure that what have so far can produce the results I'm looking for. Thanks in advance: #--------------------------------------------------- #functions #--------------------------------------------------- #sum up pairs in a list def reduce(inputList): i = 0 while (i < len(inputList)): #ref to current and next item j = i + 1 #don't go for the last item if j != len(inputList): #new number eq current + next number newNumber = inputList[i] + inputList[j] if newNumber >= 10: #reduce newNumber to single digit newNumber = sum(map(int, str(newNumber))) #collect into temp list outputList.append(newNumber) i = i + 1 return outputList; #--------------------------------------------------- #program starts here #--------------------------------------------------- outputList = [] sourceList = [7, 3, 1, 2, 1, 4, 6] counter = len(sourceList) dict = {} dict[0] = sourceList print '-------------' print 'Level 0:', dict[0] for i in range(counter): j = i + 1 if j != counter: baseList = dict.get(i) #check function to understand what it does newList = reduce(baseList) #new key and value from previous/transformed value dict[j] = newList print 'Level %d: %s' % (j, dict[j])

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  • bulls and cows game -- programming algorithm(python)

    - by IcyFlame
    This is a simulation of the game Cows and Bulls with three digit numbers I am trying to get the number of cows and bulls between two numbers. One of which is generated by the computer and the other is guessed by the user. I have parsed the two numbers I have so that now I have two lists with three elements each and each element is one of the digits in the number. So: 237 will give the list [2,3,7]. And I make sure that the relative indices are maintained.the general pattern is:(hundreds, tens, units). And these two lists are stored in the two lists: machine and person. ALGORITHM 1 So, I wrote the following code, The most intuitive algorithm: cows and bulls are initialized to 0 before the start of this loop. for x in person: if x in machine: if machine.index(x) == person.index(x): bulls += 1 print x,' in correct place' else: print x,' in wrong place' cows += 1 And I started testing this with different type of numbers guessed by the computer. Quite randomly, I decided on 277. And I guessed 447. Here, I got the first clue that this algorithm may not work. I got 1 cow and 0 bulls. Whereas I should have got 1 bull and 1 cow. This is a table of outputs with the first algorithm: Guess Output Expected Output 447 0 bull, 1 cow 1 bull, 1 cow 477 2 bulls, 0 cows 2 bulls, 0 cows 777 0 bulls, 3 cows 2 bulls, 0 cows So obviously this algorithm was not working when there are repeated digits in the number randomly selected by the computer. I tried to understand why these errors are taking place, But I could not. I have tried a lot but I just could not see any mistake in the algorithm(probably because I wrote it!) ALGORITHM 2 On thinking about this for a few days I tried this: cows and bulls are initialized to 0 before the start of this loop. for x in range(3): for y in range(3): if x == y and machine[x] == person[y]: bulls += 1 if not (x == y) and machine[x] == person[y]: cows += 1 I was more hopeful about this one. But when I tested this, this is what I got: Guess Output Expected Output 447 1 bull, 1 cow 1 bull, 1 cow 477 2 bulls, 2 cows 2 bulls, 0 cows 777 2 bulls, 4 cows 2 bulls, 0 cows The mistake I am making is quite clear here, I understood that the numbers were being counted again and again. i.e.: 277 versus 477 When you count for bulls then the 2 bulls come up and thats alright. But when you count for cows: the 7 in 277 at units place is matched with the 7 in 477 in tens place and thus a cow is generated. the 7 in 277 at tens place is matched with the 7 in 477 in units place and thus a cow is generated.' Here the matching is exactly right as I have written the code as per that. But this is not what I want. And I have no idea whatsoever on what to do after this. Furthermore... I would like to stress that both the algorithms work perfectly, if there are no repeated digits in the number selected by the computer. Please help me with this issue. P.S.: I have been thinking about this for over a week, But I could not post a question earlier as my account was blocked(from asking questions) because I asked a foolish question. And did not delete it even though I got 2 downvotes immediately after posting the question.

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