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  • How to use jquery to paginate json data?

    - by Pandiya Chendur
    My json Data looks like this {"Table" : [{"Emp_Id" : "3","Identity_No" : "","Emp_Name" : "Jerome","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Supervisior","Desig_Description" : "Supervisior of the Construction","SalaryBasis" : "Monthly","FixedSalary" : "25000.00"},{"Emp_Id" : "4","Identity_No" : "","Emp_Name" : "Mohan","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Acc ","Desig_Description" : "Accountant","SalaryBasis" : "Monthly","FixedSalary" : "200.00"},{"Emp_Id" : "5","Identity_No" : "","Emp_Name" : "Murugan","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Mason","Desig_Description" : "Mason","SalaryBasis" : "Weekly","FixedSalary" : "150.00"},{"Emp_Id" : "6","Identity_No" : "","Emp_Name" : "Ram","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Mason","Desig_Description" : "Mason","SalaryBasis" : "Weekly","FixedSalary" : "120.00"},{"Emp_Id" : "7","Identity_No" : "","Emp_Name" : "Raja","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Mason","Desig_Description" : "Mason","SalaryBasis" : "Weekly","FixedSalary" : "135.00"},{"Emp_Id" : "8","Identity_No" : "","Emp_Name" : "Raja kumar","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Mason Helper","Desig_Description" : "Mason Helper","SalaryBasis" : "Weekly","FixedSalary" : "105.00"},{"Emp_Id" : "9","Identity_No" : "","Emp_Name" : "Lakshmi","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Mason Helper","Desig_Description" : "Mason Helper","SalaryBasis" : "Weekly","FixedSalary" : "100.00"},{"Emp_Id" : "10","Identity_No" : "","Emp_Name" : "Palani","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Carpenter","Desig_Description" : "Carpenter","SalaryBasis" : "Weekly","FixedSalary" : "200.00"},{"Emp_Id" : "11","Identity_No" : "","Emp_Name" : "Annamalai","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Carpenter","Desig_Description" : "Carpenter","SalaryBasis" : "Weekly","FixedSalary" : "220.00"},{"Emp_Id" : "12","Identity_No" : "","Emp_Name" : "David","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Steel Fixer","Desig_Description" : "Steel Fixer","SalaryBasis" : "Weekly","FixedSalary" : "220.00"},{"Emp_Id" : "13","Identity_No" : "","Emp_Name" : "Chandru","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Steel Fixer","Desig_Description" : "Steel Fixer","SalaryBasis" : "Weekly","FixedSalary" : "220.00"},{"Emp_Id" : "14","Identity_No" : "","Emp_Name" : "Mani","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Steel Helper","Desig_Description" : "Steel Helper","SalaryBasis" : "Weekly","FixedSalary" : "175.00"},{"Emp_Id" : "15","Identity_No" : "","Emp_Name" : "Karthik","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Wood Fixer","Desig_Description" : "Wood Fixer","SalaryBasis" : "Weekly","FixedSalary" : "195.00"},{"Emp_Id" : "16","Identity_No" : "","Emp_Name" : "Bala","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Wood Fixer","Desig_Description" : "Wood Fixer","SalaryBasis" : "Weekly","FixedSalary" : "185.00"},{"Emp_Id" : "17","Identity_No" : "","Emp_Name" : "Tamil arasi","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Wood Helper","Desig_Description" : "Wood Helper","SalaryBasis" : "Weekly","FixedSalary" : "185.00"},{"Emp_Id" : "18","Identity_No" : "","Emp_Name" : "Perumal","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Cook","Desig_Description" : "Cook","SalaryBasis" : "Weekly","FixedSalary" : "105.00"},{"Emp_Id" : "19","Identity_No" : "","Emp_Name" : "Andiappan","Address" : "Madurai","Date_Of_Birth" : "","Desig_Name" : "Watchman","Desig_Description" : "Watchman","SalaryBasis" : "Weekly","FixedSalary" : "150.00"}]} There are 22 records in this json... How to paginate this json data 5 per page using jquery? EDIT: The above image is my summary view of employee list iterated using jquery var jsonObj = JSON.parse(HfJsonValue); for (var i = jsonObj.Table.length - 1; i >= 0; i--) { var employee = jsonObj.Table[i]; $('<div class="resultsdiv"><br /><span class="resultName">' + employee.Emp_Name + '</span><span class="resultfields" style="padding-left:100px;">Category&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Desig_Name + '</span><br /><br /><span id="SalaryBasis" class="resultfields">Salary Basis&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.SalaryBasis + '</span><span class="resultfields" style="padding-left:25px;">Salary&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.FixedSalary + '</span><span style="font-size:110%;font-weight:bolder;padding-left:25px;">Address&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Address + '</span></div>').insertAfter('#ResultsDiv'); } I get 22 records now it may grow how to paginate json date by using jquery pagination.. Any suggestion...

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  • Trying to include a library, but keep getting 'undefined reference to' messages

    - by KU1
    I am attempting to use the libtommath library. I'm using the NetBeans IDE for my project on Ubuntu linux. I have downloaded and built the library, I have done a 'make install' to put the resulting .a file into /usr/lib/ and the .h files into /usr/include It appears to be finding the files appropriately (since I no longer get those errors, which I did before installing into the /usr directories). However, when I create a simple main making a call to mp_init (which is in the library), I get the following error when I attempt to make my project: mkdir -p build/Debug/GNU-Linux-x86 rm -f build/Debug/GNU-Linux-x86/main.o.d gcc -c -g -MMD -MP -MF build/Debug/GNU-Linux-x86/main.o.d -o build/Debug/GNU-Linux-x86/main.o main.c mkdir -p dist/Debug/GNU-Linux-x86 gcc -o dist/Debug/GNU-Linux-x86/cproj1 build/Debug/GNU-Linux-x86/main.o build/Debug/GNU-Linux-x86/main.o: In function 'main': /home/[[myusername]]/NetBeansProjects/CProj1/main.c:18: undefined reference to `mp_init' collect2: ld returned 1 exit status make[2]: *** [dist/Debug/GNU-Linux-x86/cproj1] Error 1 So, it looks like the linker can't find the function within the library, however it IS there, so I just don't know what could be causing this. Any help would be appreciated. I get the same error if I type the gcc command directly and skip the makefile, I also made sure the static library got compiled with gcc as well. Edited to Add: I get these same errors if I do the compile directly and add the library with -l or -L: $ gcc -l /usr/lib/libtommath.a main.c /usr/bin/ld: cannot find -l/usr/lib/libtommath.a collect2: ld returned 1 exit status $ gcc -llibtommath.a main.c /usr/bin/ld: cannot find -llibtommath.a collect2: ld returned 1 exit status $ gcc -Llibtommath.a main.c /tmp/ccOxzclw.o: In function `main': main.c:(.text+0x18): undefined reference to `mp_init' collect2: ld returned 1 exit status $ gcc -Llibtommath.a main.c /tmp/ccOxzclw.o: In function `main': main.c:(.text+0x18): undefined reference to `mp_init' collect2: ld returned 1 exit status I am very rusty on this stuff, so I'm not sure I'm using the right command here, in the -L examples are the libraries being found? If the library isn't being found how on earth do I get it to find the library? It's in /usr/lib, I've tried it with the .a file in the current directory, etc. Is there an environment variable I need to set? If so, how, etc. Thanks so much for the help. I've tried a completely different library (GMP) and had the EXACT same problem. This has got to be some kind of Ubuntu environment issue? Anyone have any idea how to fix this?

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  • LINQ to XML Cloning

    - by Sir Psycho
    Can anyone explain why the original address XElement street node changes? It looks like customer1 holds a reference to the address XElement but customer2 and customer3 have taken copies. Why did the original address change? (LINQPad example) var address = new XElement ("address", new XElement ("street", "Lawley St"), new XElement ("town", "North Beach") ); var customer1 = new XElement ("customer1", address); var customer2 = new XElement ("customer2", address); var customer3 = new XElement ("customer3", address); customer1.Element ("address").Element ("street").Value = "Another St"; Console.WriteLine (customer2.Element ("address").Element ("street").Value); Console.WriteLine (); address.Dump(); Console.WriteLine (); customer1.Dump(); Console.WriteLine (); customer2.Dump(); Console.WriteLine (); customer3.Dump(); OUTPUT Lawley St <address> <street>Another St</street> <town>North Beach</town> </address> <customer1> <address> <street>Another St</street> <town>North Beach</town> </address> </customer1> <customer2> <address> <street>Lawley St</street> <town>North Beach</town> </address> </customer2> <customer3> <address> <street>Lawley St</street> <town>North Beach</town> </address> </customer3>

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  • Davicom Semiconductor, Inc. 21x4x DEC-Tulip not detected by Wireshark but IP operational

    - by deepsix86
    Recently flipped to Ubuntu 11.10 on a Dell 4300 (Intel). Getting IP address and no issues (ping/surf) but Wireshark unable to detect eth0 interface. I see references in forums to blacklist tulip but looks like I am running dmfe. Not sure if the blacklist is required and where to go from here. Maybe Driver update? Got a little lost looking in that area. Some h/w details below (IP/MAC/HOSTNAME removed) Linux xxxxxx 3.0.0-17-generic #30-Ubuntu SMP Thu Mar 8 17:34:21 UTC 2012 i686 i686 i386 GNU/Linux network-admin (HOSTS TAB) does not list eth0, only loopback and bunch of IPv6 interfaces ifconfig eth0 Link encap:Ethernet HWaddr xxxxxxxx inet addr:192.168.x.xx Bcast:192.168.2.255 Mask:255.255.255.0 inet6 addr: xxxxxxxxxxx 64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:36662 errors:0 dropped:1 overruns:0 frame:0 TX packets:24975 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:42115779 (42.1 MB) TX bytes:3056435 (3.0 MB) Interrupt:18 Base address:0xe800 lspci 02:09.0 Ethernet controller: Davicom Semiconductor, Inc. 21x4x DEC-Tulip compatible 10/100 Ethernet (rev 31) Subsystem: Device 4554:434e Flags: bus master, medium devsel, latency 64, IRQ 18 I/O ports at e800 [size=256] Memory at fe1ffc00 (32-bit, non-prefetchable) [size=256] Expansion ROM at fe200000 [disabled] [size=256K] Capabilities: [50] Power Management version 2 Kernel driver in use: dmfe Kernel modules: dmfe hwinfo --netcard 20: PCI 209.0: 0200 Ethernet controller [Created at pci.318] Unique ID: rBUF.0NgK5ZS9c0D Parent ID: 6NW+.siohrLUzzI4 SysFS ID: /devices/pci0000:00/0000:00:1e.0/0000:02:09.0 SysFS BusID: 0000:02:09.0 Hardware Class: network Model: "Davicom 21x4x DEC-Tulip compatible 10/100 Ethernet" Vendor: pci 0x1282 "Davicom Semiconductor, Inc." Device: pci 0x9102 "21x4x DEC-Tulip compatible 10/100 Ethernet" SubVendor: pci 0x4554 SubDevice: pci 0x434e Revision: 0x31 Driver: "dmfe" Driver Modules: "dmfe" Device File: eth0 I/O Ports: 0xe800-0xe8ff (rw) Memory Range: 0xfe1ffc00-0xfe1ffcff (rw,non-prefetchable) Memory Range: 0xfe200000-0xfe23ffff (ro,non-prefetchable,disabled) IRQ: 18 (61379 events) HW Address: 00:08:a1:01:35:70 Link detected: yes Module Alias: "pci:v00001282d00009102sv00004554sd0000434Ebc02sc00i00" Driver Info #0: Driver Status: dmfe is active Driver Activation Cmd: "modprobe dmfe" Config Status: cfg=new, avail=yes, need=no, active=unknown Attached to: #11 (PCI bridge)

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  • How do I set up a virtual network interface with its own IP address?

    - by Stefano Palazzo
    I vaguely remember that it's possible to set up virtual network interfaces with their own IP addresses, using only one physical network connection. I can find a few guides on the internet that recommend setting these up in /etc/network/interfaces, but Ubuntu doesn't use this file. Therefore my question: What's the correct way of setting these up in recent versions of Ubuntu? As this is a laptop, and I need it to connect to all kinds of different networks, I want to keep the network manager and all its configuration. To be more clear: at the end of this, I want to have a new network interface (e.g. "eth42") with its own IP address, but using whatever is connected in network manager to send the actual packets. In NM, it should appear as if I just had a second ethernet adapter installed in my system.

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  • Bridging 10GbE with 12.04 - bridging works but the bridging computer has no internet access

    - by Donal
    I have been trying to get 12.04 bridging working with two 10GbE cards. I have 2 10GbE cards in a linux box being used only for this bridge, 1 with 2 10GbaseT ports and another with a single CX4 port. I have 2 client computers connected with 10GbaseT cards and the CX4 card connects to a procurve switch. I can get the bridging happening mostly the way that I want, The clients receive dhcp information from the dhcp server (not the bridging machine) and can connect to and properly see the rest of the network. Speeds are ok, not amazing but working on that is another matter. My problem is that the bridging machine has no internet access ... meaning I can't update anything or apt-get anything It can ping all other machines on the local network. I've tried the helpful hints from: https://help.ubuntu.com/community/NetworkConnectionBridge "Enabling Internet Use on the Bridging Computer" and get the following RTNETLINK answers: File exists but dhclient br0 does nothing for me :( I think if it is anything it a multiple route problem as both br0 and eth4 have ipaddresses ... even though I have only set it up so that br0 has one ... Bridge setup details: /etc/network/interface auto br0 iface br0 inet static address 192.168.0.246 netmask 255.255.255.0 gateway 192.168.0.1 broadcast 192.168.0.255 dns-nameservers 192.168.0.1 dns-search example.com dns-domain example.com #(eth2 & eth3 are the 10GbaseT) #(eth4 is the CX4 connection) pre-up ip link set eth2 down pre-up ip link set eth3 down pre-up ip link set eth4 down pre-up brctl addbr br0 pre-up brctl addif br0 eth4 eth3 eth2 pre-up ip addr flush dev eth3 pre-up ip addr flush dev eth2 pre-up ip addr flush dev eth4 post-down ip link set eth4 down post-down ip link set eth2 down post-down ip link set eth3 down post-down ip link set br0 down post-down brctl delif br0 eth2 eth3 eth4 post-down brctl delbr br0 ifconfig -a br0 Link encap:Ethernet HWaddr 00:15:17:22:20:34 inet addr:192.168.0.102 Bcast:192.168.0.255 Mask:255.255.255.0 inet6 addr: fe80::215:17ff:fe22:2034/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:4957 errors:0 dropped:0 overruns:0 frame:0 TX packets:1077 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:0 RX bytes:596320 (596.3 KB) TX bytes:139952 (139.9 KB) eth4 Link encap:Ethernet HWaddr 00:60:dd:47:7c:05 inet addr:192.168.0.57 Bcast:192.168.0.255 Mask:255.255.255.0 inet6 addr: fe80::260:ddff:fe47:7c05/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:9000 Metric:1 RX packets:15391 errors:0 dropped:51 overruns:0 frame:0 TX packets:1207 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:5916769 (5.9 MB) TX bytes:154312 (154.3 KB) Interrupt:70 route -n Kernel IP routing table Destination Gateway Genmask Flags Metric Ref Use Iface 0.0.0.0 192.168.0.1 0.0.0.0 UG 0 0 0 eth4 0.0.0.0 192.168.0.1 0.0.0.0 UG 100 0 0 br0 169.254.0.0 0.0.0.0 255.255.0.0 U 1000 0 0 br0 192.168.0.0 0.0.0.0 255.255.255.0 U 0 0 0 br0 192.168.0.0 0.0.0.0 255.255.255.0 U 1 0 0 eth4

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  • Which is a better practice - helper methods as instance or static?

    - by Ilian Pinzon
    This question is subjective but I was just curious how most programmers approach this. The sample below is in pseudo-C# but this should apply to Java, C++, and other OOP languages as well. Anyway, when writing helper methods in my classes, I tend to declare them as static and just pass the fields if the helper method needs them. For example, given the code below, I prefer to use Method Call #2. class Foo { Bar _bar; public void DoSomethingWithBar() { // Method Call #1. DoSomethingWithBarImpl(); // Method Call #2. DoSomethingWithBarImpl(_bar); } private void DoSomethingWithBarImpl() { _bar.DoSomething(); } private static void DoSomethingWithBarImpl(Bar bar) { bar.DoSomething(); } } My reason for doing this is that it makes it clear (to my eyes at least) that the helper method has a possible side-effect on other objects - even without reading its implementation. I find that I can quickly grok methods that use this practice and thus help me in debugging things. Which do you prefer to do in your own code and what are your reasons for doing so?

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  • SIMPLEST way to set up password protection for a static site, with basic admin UI?

    - by Joseph Turian
    I have a static site. I would like the simplest approach to password protecting a directory, with a basic admin UI for adding/removing users. I will have so few users that I don't care about performance. I don't care if it's PHP or Django or whatever, I just want a complete software package. Apache basic auth isn't good, because you can't log out. Nor is there a UI for adding users. I tried throwing everything behind Django auth and serving the files through Django. However, Chrome treats all my text/css headers as text/plain, so I don't get any stylesheets showing. I can't use mod_xsendfile on my server because I can't reconfigure Apache to add new modules. I think this approach is overkill anyway. I can try configuring Nginx's X-Accel-Redirect, however that requires implementing all the Django code for auth myself, and I'd prefer an existing solution. However, this is my backup plan. Is there a code package that implements authentication with basic admin for a static site?

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  • Is multiple domain names and links from same IP causing poor search engine rankings?

    - by John
    I have an ecommerce website which is not doing so well in Google. I am trying to improve this of course, and am looking at some possibilities for why it isn't doing well. The website has four domain names, all of which have been indexed by Google. A few months ago I applied 301 redirects to any requests for two of the domain names so now it is down to two domain names (one is a .net, the other is a .com.au, the others were .net.au and .com). I prefer to use my main domain name (the .com.au), but one of the names has been around for a long time and has more inbound links. According to a PageRank tool, both are PR2. It is a Classic ASP site and up until recently had a lot of querystring parameters. In the last week or so I added URL rewriting so there is now no parameters for most pages. I don't do 301 redirects from the old URLs but instead I add the META canonical tag indicating the preferred new URL. At the same time I redesigned the site and improved title tags, META descriptions, and H tags but it hasn't been long enough yet for Google to index many of these yet. I also looked at what pages Google has indexed and strangely it has some strange pages in the index, there are a lot of pages which are actual keyword searches (more a bunch of random letters than an actual word). What I mean is that it is as if they had typed in something to search for in my search box - there are no links to pages like this and the only way of getting this is to type something in to the search box). So I added a META robots tag with noindex,nofollow anytime that I render pages like this. Years ago I set up a fake price comparison site which lists all my products and links back to my site. It has a different keyword rich domain name but is on the same server and same IP address. It's a completely different layout but does have the same product categories and product descriptions (although I have stripped formatting out of them so they are not identical except in text). I also have a few blog sites which again are on the same server/IP and all have advertising for the website. My questions are: What should I do with the multiple domains, just use one, or continue with two or more? Should I add 301 redirects, not just the META canonical tag? Any idea about Google indexing my search results page, and did I do the right thing with the META robots tag? Is the fake price comparison site likely to be causing problems? Are all the links to the site from other domain names but the same IP address likely to be causing problems? Thanks for any help. Sorry for so many questions in one.

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  • Google se lance encore un peu plus dans la voix sur IP et la vidéo-conférence, au moment où Skype so

    Mise à jour du 19/05/10 Google se lance dans la voix sur IP et la vidéo-conférence Au moment où Skype sort la nouvelle version de son application Les deux faits ne sont pas liés, mais ils montrent que la voix sur Internet (VoIP) au sens large est un secteur en plein devenir. Après Gizmo5 (lire ci-avant), Google vient en effet de lancer une Offre Publique d'Achat (OPA) sur une société norvégienne spécialisée dans la « transmission du son et de la vidéo en temps réel » sur Internet. La définition d'une technologie qui fait furieusement penser à Skype. La direction de Global IP Solutions a d'ores et déjà annoncé qu'...

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  • Why would i need extra IP adresses from my web host?

    - by user4524
    I am moving to a new and cheaper host. My old one raised the prices suddenly by a factor 10. Now what I did not like about the old one, was that each time I set up a new website, I had to set up a new account, with the result that I have to pay for a lot of webspace and a lot of bandwith i don't use. Now I am moving over to a new host, who cheaply offers virtual servers. Now I am a n00b when it comes to server tech. I have two questions about this: 1. Could I install all my webistes on this virtual server, provided it is big enough? 2. They offer the possibility of getting more than one IP address, but it costs more. What would be the advantage of this? Would I be able to suffice with one IP address?

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  • La CNIL autorise les premiers ayants droits à collecter des adresses IP, la machine Hadopi se met en

    Mise à jour du 14.06.2010 par Katleen La CNIL autorise les premiers ayants droits à collecter des adresses IP, la machine Hadopi se met en marche Quelques semaines après la mise en place de l'équipe chargée de la mettre en oeuvre, la loi Hadopi semble prête à décoller. La CNIL (Commission nationale informatique et libertés) viendrait en effet d'autoriser les premiers ayants droits à collecter de manière automatisée les adresses IP d'utilisateurs soupçonnés de téléchargement illégal. Ceci leur permettra de ficher les contrevenants présumés pour ensuite en avertir Hadopi. Concrètement, c'est la société Trident Media Guard qui sera seule habilitée à collecter ces adresses pour le...

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  • Cisco ASA not forwarding traffic from one interface to another

    - by Antoine Benkemoun
    Hello ServerFault, I am needing help in the configuration process of my Cisco ASA 5510. I have set up 4 Cisco ASA interconnected together via a big LAN. Each Cisco ASA has 3 or 4 LANs attached to them. The IP routing part is taken care of by OSPF. My problem is on another level. A computer connected to one of the LANs attached to an ASA has no problem communicating with the outside world. The outside world being anything "after" the ASA. My problem is that I am completely unable to have them communicate with another LAN connected to the same ASA. To rephrase this, I am unable to send traffic from one interface of a given ASA to another interface of the same ASA. My configuration is the following : ! hostname Fuji ! interface Ethernet0/0 speed 100 duplex full nameif outside security-level 0 ip address 10.0.0.2 255.255.255.0 no shutdown ! interface Ethernet0/1 speed 100 duplex full nameif cs4 no shutdown security-level 100 ip address 10.1.4.1 255.255.255.0 ! interface Ethernet0/2 speed 100 duplex full no shutdown ! interface Ethernet0/2.15 vlan 15 nameif cs5 security-level 100 ip address 10.1.5.1 255.255.255.0 ! interface Ethernet0/2.16 vlan 16 nameif cs6 security-level 100 ip address 10.1.6.1 255.255.255.0 ! interface Management0/0 speed 100 duplex full nameif management security-level 100 ip address 10.6.0.252 255.255.255.0 ! access-list nat_cs4 extended permit ip 10.1.4.0 255.255.255.0 any access-list acl_cs4 extended permit ip 10.1.4.0 255.255.255.0 any access-list nat_cs5 extended permit ip 10.1.5.0 255.255.255.0 any access-list acl_cs5 extended permit ip 10.1.5.0 255.255.255.0 any access-list nat_cs6 extended permit ip 10.1.6.0 255.255.255.0 any access-list acl_cs6 extended permit ip 10.1.6.0 255.255.255.0 any ! access-list nat_outside extended permit ip any any access-list acl_outside extended permit ip any 10.1.4.0 255.255.255.0 access-list acl_outside extended permit ip any 10.1.5.0 255.255.255.0 access-list acl_outside extended permit ip any 10.1.6.0 255.255.255.0 ! nat (outside) 0 access-list nat_outside nat (cs4) 0 access-list nat_cs4 nat (cs5) 0 access-list nat_cs5 nat (cs6) 0 access-list nat_cs6 ! static (outside,cs4) 0.0.0.0 0.0.0.0 netmask 0.0.0.0 static (outside,cs5) 0.0.0.0 0.0.0.0 netmask 0.0.0.0 static (outside,cs6) 0.0.0.0 0.0.0.0 netmask 0.0.0.0 ! static (cs4,outside) 10.1.4.0 10.1.4.0 netmask 255.255.255.0 static (cs4,cs5) 10.1.4.0 10.1.4.0 netmask 255.255.255.0 static (cs4,cs6) 10.1.4.0 10.1.4.0 netmask 255.255.255.0 ! static (cs5,outside) 10.1.5.0 10.1.5.0 netmask 255.255.255.0 static (cs5,cs4) 10.1.5.0 10.1.5.0 netmask 255.255.255.0 static (cs5,cs6) 10.1.5.0 10.1.5.0 netmask 255.255.255.0 ! static (cs6,outside) 10.1.6.0 10.1.6.0 netmask 255.255.255.0 static (cs6,cs4) 10.1.6.0 10.1.6.0 netmask 255.255.255.0 static (cs6,cs5) 10.1.6.0 10.1.6.0 netmask 255.255.255.0 ! access-group acl_outside in interface outside access-group acl_cs4 in interface cs4 access-group acl_cs5 in interface cs5 access-group acl_cs6 in interface cs6 ! router ospf 1 network 10.0.0.0 255.255.255.0 area 1 network 10.1.4.0 255.255.255.0 area 1 network 10.1.5.0 255.255.255.0 area 1 network 10.1.6.0 255.255.255.0 area 1 log-adj-changes ! There is nothing really complicated in this configuration. It just NATs from one interface to another and that's it. I have tried enabling same-security-traffic permit inter-interface but that doesn't help. I therefore must be missing something a little bit more complicated. Does anyone know why I cannot foward traffic from one interface to another ? Thank you in advance for your help, Antoine

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  • In ActionScript3 runtime, is there a way to get a list of all static members from a Class

    - by ty
    Let's say we have following class public class PlayerEvent extends Event { public static const PLAYER_INIT:String = "playerInit"; public static const PLAYER_MOVE:String = "playerMove"; public static const PLAYER_USE_SKILL:String = "playerUseSkill"; public function PlayerEvent(type:String) { super(type, false, true); } } } In Flash Player runtime, is there a way I can get a list of all the static members of lass PlayerEvent. Something like: trace(PlayerEvent.staticMethods) // ["PLAYER_INIT", "PLAYER_MOVE", "PLAYER_USE_SKILL"]...

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  • How to validate selects / inserts are hitting the right server with MySQL Master/Slave

    - by bwizzy
    I've got a rails app using the master_slave_adapter plugin (http://github.com/mauricio/master_slave_adapter/tree/master) to send all selects to a slave, and all other statements to the master. Replication is setup using Mysql master / slave. I'm trying to validate that all the SQL statements are indeed going to the right place. Selects to the slave (db2), inserts to the master (db1) but I'm not sure how to do it. I've tried using tcpdump on the webservers: sudo /usr/sbin/tcpdump -q -i eth0 dst port 3306 and this is the output for a page request with a ton of selects: 10:32:36.570930 IP web2.mydomain.com.57524 > db1.mydomain.com.mysql: tcp 0 10:32:36.576805 IP web2.mydomain.com.57524 > db1.mydomain.com.mysql: tcp 0 10:32:36.577201 IP web2.mydomain.com.57524 > db1.mydomain.com.mysql: tcp 0 10:32:36.577980 IP web2.mydomain.com.57524 > db1.mydomain.com.mysql: tcp 86 10:32:36.578186 IP web2.mydomain.com.57524 > db1.mydomain.com.mysql: tcp 21 10:32:36.578359 IP web2.mydomain.com.57524 > db1.mydomain.com.mysql: tcp 27 10:32:36.578522 IP web2.mydomain.com.57524 > db1.mydomain.com.mysql: tcp 5 10:32:36.578741 IP web2.mydomain.com.57524 > db1.mydomain.com.mysql: tcp 13 10:32:36.579611 IP web2.mydomain.com.57524 > db1.mydomain.com.mysql: tcp 29 10:32:36.588201 IP web2.mydomain.com.45978 > db2.mydomain.com.mysql: tcp 0 10:32:36.588323 IP web2.mydomain.com.45978 > db2.mydomain.com.mysql: tcp 0 10:32:36.588677 IP web2.mydomain.com.45978 > db2.mydomain.com.mysql: tcp 0 10:32:36.588784 IP web2.mydomain.com.45978 > db2.mydomain.com.mysql: tcp 86 It doesn't look like all the selects are going to the slave. Maybe this isn't the right way to test, anyone know a better way?

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  • What is the actual MSMQ address used by the respective WCF binding?

    - by mark
    Dear ladies and sirs. This question is related to this one. Given that WCF binding uses net.msmq:// URL, for instance net.msmq://server/private/nc_queue, how can one know what is the actual MSMQ address to which this URL is translated? Is there some kind of a trace that can be activated? Or an external tool that would help one capture the address? Thanks. EDIT1 OK, I owe a clarification. One can talk directly to MSMQ through the respective .NET API. In the case of MSMQ over its native port 1801, I would use this MSMQ address: FormatName:Direct=OS:server\private$\nc_queue When MSMQ is configured over HTTP, the address changes to something like this: FormatName:Direct=http://server/msmq/nc_queue But the WCF binding uses a standard URL to describe the address, like: net.msmq://server/private/nc_queue So, how can I know what is the actual MSMQ address (the one with the FormatName) to which the net.msmq:// is translated?

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  • Is there a way to attach Ruby Net::HTTP request to a specific IP address / network interface?

    - by Dan Sosedoff
    Hello, Im looking a way to use different IP addresses for each GET request with standard Net::HTTP library. Server has 5 ip addresses and assuming that some API`s are blocking access when request limit per IP is reached. So, only way to do it - use another server. I cant find anything about it in ruby docs. For example, curl allows you to attach it to specific ip address (in PHP): $req = curl_init($url) curl_setopt($req, CURLOPT_INTERFACE, 'ip.address.goes.here'; $result = curl_exec($req); Is there any way to do it with Net::HTTP library? As alternative - CURB (ruby curl binding). But it will be the latest thing i`ll try. Suggestions / Ideas?

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  • Java - Draw Cards and Eliminate Cards Problem

    - by Jen
    I am having a problem in this question. I want a system inside a game wherein the player draws 2 cards randomly, and the enemy draws 2 cards randomly. Then, what the program does is to print out to the console the cards the player draw and the enemy's. The cards should not conflict and must not be the same. Then lastly, the program prints out the card that was not drawn by both the player and the enemy. Here's how I did it but it was lengthy and full of errors: import java.util.Random; public class Draw { public static Random random = new Random(); public static String cards[] = {"Hall", "Kitchen", "Billiard", "Study", "Pool"}; public static int playercounter; public static int enemycounter; public static String playercardA = null; public static String playercardB = null; public static String enemycardA = null; public static String enemycardB = null; public String lastcard = null; public static void playercardAdraw() { playercounter = random.nextInt(5); playercardA = cards[playercounter]; } public static void playercardBdraw() { playercounter=random.nextInt(5); playercardB= cards[playercounter]; if (playercardB==playercardA || playercardB == enemycardA || playercardB == enemycardB) { return; } } public static void enemycardAdraw () { enemycounter = random.nextInt(5); enemycardA=cards[enemycounter]; if (enemycardA == playercardA || enemycardA == playercardB) { return; } } public static void enemycardBdraw () { enemycounter = random.nextInt(5); enemycardB=cards[enemycounter]; if (enemycardB == playercardA || enemycardB == playercardB || enemycardB == enemycardA) { return; } } public static void main (String args []) { System.out.println("Starting to draw..."); System.out.println("Player's Turn: "); playercardAdraw(); System.out.println("Player's first card: " + playercardA); playercardBdraw(); System.out.println("Player's second card: " + playercardB); System.out.println("Enemy's Turn: "); enemycardAdraw(); System.out.println("Enemy's first card: " + enemycardA); enemycardBdraw(); System.out.println("Enemy's Second card: " + enemycardB); } }

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  • Draw Cards and Eliminate Cards Problem

    - by Jen
    I am having a problem in this question. I want a system inside a game wherein the player draws 2 cards randomly, and the enemy draws 2 cards randomly. Then, what the program does is to print out to the console the cards the player draw and the enemy's. The cards should not conflict and must not be the same. Then lastly, the program prints out the card that was not drawn by both the player and the enemy. Here's how I did it but it was lengthy and full of errors: import java.util.Random; public class Draw { public static Random random = new Random(); public static String cards[] = {"Hall", "Kitchen", "Billiard", "Study", "Pool"}; public static int playercounter; public static int enemycounter; public static String playercardA = null; public static String playercardB = null; public static String enemycardA = null; public static String enemycardB = null; public String lastcard = null; public static void playercardAdraw() { playercounter = random.nextInt(5); playercardA = cards[playercounter]; } public static void playercardBdraw() { playercounter=random.nextInt(5); playercardB= cards[playercounter]; if (playercardB==playercardA || playercardB == enemycardA || playercardB == enemycardB) { return; } } public static void enemycardAdraw () { enemycounter = random.nextInt(5); enemycardA=cards[enemycounter]; if (enemycardA == playercardA || enemycardA == playercardB) { return; } } public static void enemycardBdraw () { enemycounter = random.nextInt(5); enemycardB=cards[enemycounter]; if (enemycardB == playercardA || enemycardB == playercardB || enemycardB == enemycardA) { return; } } public static void main (String args []) { System.out.println("Starting to draw..."); System.out.println("Player's Turn: "); playercardAdraw(); System.out.println("Player's first card: " + playercardA); playercardBdraw(); System.out.println("Player's second card: " + playercardB); System.out.println("Enemy's Turn: "); enemycardAdraw(); System.out.println("Enemy's first card: " + enemycardA); enemycardBdraw(); System.out.println("Enemy's Second card: " + enemycardB); } }

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  • NLB 2 Windows Server 2003 Servers

    - by Paul Hinett
    I need to configure windows NLB on 2 dedicated servers I have. My main machine has been running for some time, with several domain names pointing to the servers primary IP address. Both servers have 2 NIC's installed, and both have several secondary public IP addresses available if needed? What IP address would I use for the cluster IP, does this IP need to be added to the IP list of both public NIC's ip address list? What IP addresses do I use for the host's dedicated IP? Please help, this is driving me nuts...i've taken down the server twice on accident today! Thank you in advance!

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  • Confusion about HSRP Groups

    - by Kyle Brandt
    If I have a router that has several LANs on it, and each of these LAN is attached to a second router, do I need to use different HSRP groups for each LAN? With this set up, each virtual gateway will be on a Layer 2 segment. And within a router, no interface will have multiple gateways. So, For example: Router 1: F0/0: ip address 192.168.1.2 255.255.255.0 standby ip 192.168.1.1 F2/0: ip address 192.168.2.2 255.255.255.0 standby ip 192.168.2.1 Router 2: F0/0: ip address 192.168.1.3 255.255.255.0 standby ip 192.168.1.1 F2/0: ip address 192.168.2.3 255.255.255.0 standby ip 192.168.2.1 Will this work, or do I need standby 1 ip 192.168.2.1 on the F2/0 interfaces? Since according to the RFC, the group number of the packet is in the HSRP multicast packets, my guess is that I don't need different groups, and that multiple groups are only needed when they are all on the same Layer 2 segment. However, I haven't been able to find this setup....

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  • Single-port 2600 router with 2900XL switch

    - by Slava Maslennikov
    I have a setup, where the single port 2600 router is in port 0/2 in the switch, outside network is on port 0/1, and the rest (0/3-0/24) should be clients for the second network that would be managed by the 2600 router. I configured everything with two VLANs: 100 for outside (0/2-0/24), 200 for inside (0/1-0/2). 0/2 is a trunk port for the two VLANs. The issue that came about is that I can't have two VLANs on at once: software doesn't allow it. Now, I can ping the outside network devices (172.16.7.1, 172.16.7.103), and even google (8.8.8.8) from the router, but not the switch. Devices on connected get a DHCP lease properly but can't ping outside the network, just the router - 172.17.7.1 and the switch itself, 172.17.7.7. The configuration for both the router and the switch are here, as well as below. Router: rt.throom#sho run Building configuration... Current configuration : 1015 bytes ! version 12.1 no service single-slot-reload-enable service timestamps debug uptime service timestamps log uptime no service password-encryption ! hostname rt.throom ! enable password To053cret ! ! ! ! ! no ip subnet-zero ip dhcp excluded-address 172.17.7.1 172.17.7.2 ip dhcp excluded-address 172.17.7.3 172.17.7.4 ip dhcp excluded-address 172.17.7.5 ! ip dhcp pool VLAN200 network 172.17.7.0 255.255.255.0 default-router 172.17.7.1 dns-server 8.8.8.8 ! ip audit notify log ip audit po max-events 100 ! ! ! ! ! ! ! interface Ethernet0/0 no ip address ! interface Ethernet0/0.100 encapsulation dot1Q 100 ip address 172.16.7.15 255.255.255.0 ip nat outside ! interface Ethernet0/0.200 encapsulation dot1Q 200 ip address 172.17.7.1 255.255.255.0 ip nat inside ! router eigrp 20 network 172.16.0.0 network 172.17.0.0 no auto-summary no eigrp log-neighbor-changes ! no ip classless no ip http server ! access-list 1 permit 172.17.7.0 0.0.0.255 ! ! line con 0 line aux 0 line vty 0 4 login ! end Switch: sw.throom#sho run Building configuration... Current configuration: ! version 11.2 no service pad no service udp-small-servers no service tcp-small-servers ! hostname sw.throom ! enable password Oh5053cret ! ! no spanning-tree vlan 100 no spanning-tree vlan 200 ip subnet-zero ! ! interface VLAN1 no ip address no ip route-cache ! interface FastEthernet0/1 switchport access vlan 100 spanning-tree portfast ! interface FastEthernet0/2 switchport trunk encapsulation dot1q switchport mode trunk ! interface FastEthernet0/3 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/4 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/5 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/6 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/7 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/8 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/9 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/10 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/11 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/12 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/13 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/14 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/15 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/16 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/17 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/18 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/19 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/20 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/21 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/22 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/23 switchport access vlan 200 spanning-tree portfast ! interface FastEthernet0/24 switchport access vlan 200 spanning-tree portfast ! ! line con 0 stopbits 1 line vty 0 4 login line vty 5 9 login ! end sho ip route gives: Gateway of last resort is 172.16.7.1 to network 0.0.0.0 172.17.0.0/24 is subnetted, 1 subnets C 172.17.7.0 is directly connected, Ethernet0/0.200 172.16.0.0/24 is subnetted, 1 subnets C 172.16.7.0 is directly connected, Ethernet0/0.100 S* 0.0.0.0/0 [1/0] via 172.16.7.1

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  • Remote host: can tracert, can telnet, can*not* browse: what gives?

    - by MacThePenguin
    One of my customers of the company I work for has made a change to their Internet connection, and now we can't connect to them any more from our LAN. To help me troubleshoot this issue, the network guy on the customer's site has configured their firewall so that a HTTPS connection to their public IP address is open to any IP. I should put https://<customer's IP> in my browser and get a web page. Well, it works from any network I've tried (even from my smartphone), just not from my company's LAN. I thought it may be an issue with our firewall (though I checked its rules and it allows outbound TCP port 443 to anywhere), so I just connected a PC directly to the network connection of our provider, bypassing out firewall completely, and still it didn't work (everything else worked). So I asked for help to our Internet provider's customer service, and they asked me to do a tracert to our customer's IP. The tracert is successful, as the final hop shown in the output is the host I want to reach. So they said there's no problem. :( I also tried telnet <customer's IP> 443 and that works as well: I get a blank page with the cursor blinking (I've tried using another random port and that gives me an error message, as it should). Still, from any browser of any PC in my LAN I can't open that URL. I tried checking the network traffic with Wireshark: I see the packages going through and answers coming back, thought the packets I see passing are far less than they are if I successfully connect to another HTTPS website. See the attached screenshot: I had to blur the IPs, anyway the longer string is my PC's local IP address, the shorter one is the customer's public IP. I don't know what else to try. This is the only IP doing this... Any idea what could I try to find a solution to this issue? Thanks, let me know if you need further details. Edit: when I say "it doesn't work" I mean: the page doesn't open, the browser keeps loading for a long time and eventually shows an error saying that the page cannot be opened. I'm not in my office now so I can't paste the exact message, but it's the usual message you get when the browser reaches its timeout. When I say "it works", I mean the browser loads and shows a webpage (it's the logon page for the customers' firewall admin interface: so there's the firewall brand's logo and there are fields to enter a user id and a password). Update 13/09/2012: tried again to connect to the customer's network through our Internet connection without a firewall. This is what I did: Run a Kubuntu 12.04 live distro on a spare laptop; Updated all the packages I could and installed WireShark; Attached it to my LAN and verified that I couldn't open https://<customer's IP>. Verified that the Wireshark trace for this attempt was the same as the one I've already posted; Verified that I could connect to another customer's host using rdesktop (it worked); Tried to rdesktop to <customer's IP>, here's the output: kubuntu@kubuntu:/etc$ rdesktop <customer's IP> Autoselected keyboard map en-us ERROR: recv: Connection reset by peer Disconnected the laptop from the LAN; Disconnected the firewall from the Extranet connection, connected the laptop instead. Set its network configuration so that I could access the Internet; Verified that I could connect to other websites in http and https and in RDP to other customers' hosts - it all worked as expected; Verified that I could still traceroute to <customer's IP>: I could; Verified that I still couldn't open https://<customer's IP> (same exact result as before); Checked the WireShark trace for this attempt and noticed a different behaviour: I could see packets going out to the customer's IP, but no replies at all; Tried to run rdesktop again, with a slightly different result: kubuntu@kubuntu:/etc/network$ rdesktop <customer's IP> Autoselected keyboard map en-us ERROR: <customer's IP>: unable to connect Finally gave up, put everything back as it was before, turned off the laptop and lost the WireShark traces I had saved. :( I still remember them very well though. :) Can you get anything out of it? Thank you very much. Update 12/09/2012 n.2: I followed the suggestion by MadHatter in the comments. From inside the firewall, this is what I get: user@ubuntu-mantis:~$ openssl s_client -connect <customer's IP>:443 CONNECTED(00000003) If I now type GET / the output pauses for several seconds and then I get: write:errno=104 I'm going to try the same, but bypassing the firewall, as soon as I can. Thanks. Update 12/09/2012 n.3: So, I think ISA Server is altering the results of my tests... I tried installing Wireshark directly on the firewall and monitoring the packets on the Extranet network card. When the destination is the customer's IP, whatever service I try to connect to (HTTPS, RDP or SAProuter), I can only see outbound packets and no response packets whatsoever from their side. It looks like ISA Server is "faking" the remote server's replies, that's why I get a connection using telnet or the openSSL client. This is the wireshark trace from inside our LAN: But this is the trace on the Extranet network card: This makes a bit more sense... I'll send this info to the customer's tech and see if he can make anything out of it. Thanks to all that took the time to read my question and post suggestions. I'll update this post again.

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