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  • UIScrollView not scrolling...

    - by Mark
    I have a UIScrollView which contains many UIImageView's UILabel's etc... the labels are well longer that the UIScrollView, but when I run the app, I cannot click and scroll down... Why might this be? Thanks

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  • iOS Development: How can I encapsulate a string in an NSData object?

    - by BeachRunnerJoe
    Hello. I'm building a multiplayer game on the iPhone and I need to send string data to the other players in the game. To do that, I need to encapsulate my NSString* string data in an NSData object somehow. Here's an example of how my code is structured... typedef struct { PACKETTYPE packetType; ??? stringToSend; //<---not sure how to store this } StringPacket; StringPacket msg; msg.packetType = STRING_PACKET; msg.stringToSend = ... // <---not sure what to do here NSData *packet = [NSData dataWithBytes:&msg length:sizeof(StringPacket)]; So my question is, if StringPacket is a struct defined in my header, what type should the stringToSend property be so that I can easily call the dataWithBytes method of NSData to encapsulate the packet data in an NSData object? Thanks for your wisdom!

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  • iPhone/iPad C++ Example

    - by MLS
    Does anyone know where or how to obtain a C++ example to create iPhone apps? What I am looking for is just using C++ (no objective-C or just the bare essential objective-C) and no interface builder, source only. Can ayone help me locate such a beast?

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  • previousFailureCount always stays on 0 (zero)

    - by itai alter
    Hello all, First of all, I'd like to thank the good people who helped me around on this site. Thanks. I'm trying to detect a failed authentication attempt in my app... I'm using the didReceiveAuthenticationChallenge method, and the checking if [challenge previousFailureCount] is equal to 0. The problem is that it's always stays on zero, even if the username and password that I send with the credentials are incorrect. I couldn't find any info about this kind of issue, any help will be much appreciated. Thanks!

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  • SELECT GROUP BY latest entry in INBOX msg sent by user

    - by Mohatir S
    i am building a simple PM for my personal website where a user can join and send message to the registered users on my website, i am stuck in grouping and selecting latest user (by latest msg time) in INBOX page my table : id msg_from msg_to msg date in_del out_del i want to show latest user's id each in a group here is my SQL query : SELECT ttalk.id, ttalk.msg_from, users.first_name, users.last_name FROM ttalk INNER JOIN users ON ttalk.msg_from = users.id WHERE ttalk.msg_to = '$_SESSION[user_id]' AND ttalk.in_del='0' GROUP BY ttalk.msg_from DESC LIMIT 500 Thanks in advance :-)

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  • UISplitViewController Common View

    - by saikamesh
    is it possible to have a common view for both master and detail view controllers. What if I need to add a header image(at top, the very first view) common for both the master and detail view controllers. When the device is in the portrait mode the width of the header image view has to shrink to fit to the detail view controller's view and when the orientation changes to landscape the width of the same header image view has to be expanded that is the width of it has to be 1024. Please tell me whether doing this is possible. or any workaround for this?

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  • Want to 'sandbox' user form submitted HTML

    - by pmmenneg
    Hi all. I have a user form with a textarea that allows users to submit html formatted data. The html itself is limited by PHP strip_tags, but of course that does no completion checking etc. My basic problem is that should a user leave a tag unclosed, such as the tag, then all the content following that, including page content that follows that is 'outside' the user content display area, could now be malformed. Checking for proper tag completion is one solution I will look at, but ideally I'd like to firewall the user htmlified content away from the rest of the site somehow. Any suggestions on the best approach? Thanks!

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  • Joomla User Login Question

    - by user277127
    I would like to enable users of my existing web app to login to Joomla with the credentials already stored in my web app's database. By using the Joomla 1.5 authentication plugin system -- http://docs.joomla.org/Tutorial:Creating_an_Authentication_Plugin_for_Joomla_1.5 -- I would like to bypass the Joomla registration process and bypass creating users in the Joomla database altogether. My thought had been that I could simply populate a User object, which would be stored in the Session, and that this would replace the need to store a user in the Joomla database. After looking through the code surrounding user management in Joomla, it seems like any time you interact with the User object, the database is being queried. It therefore seems like my initial idea won't work. Is that right? It looks like, in order to achieve the effect I want, I will have to actually register a user from within the authentication plugin at the time they first login. This is not ideal, so before I go forward with it, I wanted to check with Joomla developers whether it is possible to do what I described above. Thanks in advance -- I am new to Joomla and greatly appreciate your help!

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  • Check if User (live) on the Domain Controller

    - by Data-Base
    Hello, when we connect a machine to AD, user will be able to log into the machine with their AD user-name and password, at home they can do that ( when they are not on the work network) which fine and good we need to have a program Auto-start when the user login BUT only when they are at work and in our network! how can I achieve that? (I can build a checking program in c#) but not sure where to start! cheers

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  • Handling multiple post-defined datasource connections based on user

    - by choudeshell
    How should I handle multiple user-connection defined datasource connection in my .NET application? To illustrate this better; the user provides three (3) pieces of information, username, password and data source name. This data source name is then looked-up in a central database telling that application which main database this user should connect to. My question is, in the DataAccess layer, should we only pass down enough information to uniquely identify that user, and query the central database each time in the DAL; or, should we provide another way to pass the datasource connection down to the DAL?

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  • UITextField in UITableViewCell Help

    - by W Dyson
    Hello All, I have scoured the internet looking for a good tutorial or posting about having a UITableView populated with a UITextField in each cell for data entry. I want to keep track of each UITextField and the text written within it while scrolling. The tableView will be sectioned. I have been using a custom UITableViewCell but I'm open to any method. Also, is it possible to use the textFields as ivars? If any of you could point me in the right direction, it would be greatly appreciated. Thank you in advance!

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  • Django forms: prepopulate form with request.user and url parameter

    - by Malyo
    I'm building simple Course Management App. I want Users to sign up for Course. Here's sign up model: class CourseMembers(models.Model): student = models.ForeignKey(Student) course = models.ForeignKey(Course) def __unicode__(self): return unicode(self.student) Student model is extended User model - I'd like to fill the form with request.user. In Course model most important is course_id, which i'm passing into view throught URL parameter (for example http://127.0.0.1:8000/courses/course/1/). What i want to achieve, is to generate 'invisible' (so user can't change the inserted data) form with just input, but containing request.user and course_id parameter.

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  • How do I find the original git user?

    - by Michael
    Hi all, I'm trying to figure out the current installation of git on a slicehost server. Following this guide, one of the early steps is to add a user, git. However, when I do a cat /etc/passwd, I don't see this user name... How do I find where my git user is? Thanks!

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  • How to validate user with SimpleMembership

    - by Rushino
    I am using SimpleMembership for user login stuff in my web application. I wrote a console that actually access my web application classes to avoid duplicate code. However, since my console application doesn't have anything related to user sessions the Login method doesn't work. But is there a way to validate a user only using the SimpleMembership? In case i have to do it manually.. how can i do it ?

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  • Return user to original page after logging in (rails session mgmt)

    - by keruilin
    I'm looking for some general guidance as to how to return a user back to the original page they were viewing after trying to log-in. The way I have the site setup now is that if a user visits the Store page, for example, and then clicks the login button in the upper right, the user is returned to the default landing page. Any help would be greatly appreciated!

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  • Zend Framework How can I print a logged in user name from a Zend_Session_Namespace

    - by IrishStudent76
    Hi all I have created the following login controller for my site and it works fine in relation to logging users in a logging them out. The thing I want to do is echo the logged in users name into the FlashMessenger for the success page how ever as my code stands I only get the following message when redirected to the success page, "you have been successfully logged in as Array". Can I also ask the following does the line $session-user =$adaptergetResultArray('Password'); create an array of user information less the password value from the database. Many Thanks in advance, IrishStudent76 <?php class LoginController extends Zend_Controller_Action { public function init(){ $this->view->doctype('XHTML1_STRICT'); } // login action public function loginAction() { $form = new PetManager_Form_Login; $this->view->form = $form; /* check for valid input from the form and authenticate using adapter Add user record to session and redirect to the original request URL if present */ if ($this->getRequest()->isPost()) { if ($form->isValid($this->getRequest()->getPost())) { $values = $form->getValues(); $adapter = new PetManager_Auth_Adapter_Doctrine( $values['username'], $values['password'] ); $auth = Zend_Auth::getInstance(); $result = $auth->authenticate($adapter); if ($result->isValid()) { $session = new Zend_Session_Namespace('petmanager.auth'); $session->user = $adapter->getResultArray('Password'); if (isset($session->requestURL)) { $url = $session->requestURL; unset($session->requestURL); $this->_redirect($url); } else { $this->_helper->getHelper('FlashMessenger') ->addMessage('You have been successfully logged in as '.$session- >user); $this->_redirect('/login/success'); } } else { $this->view->message = 'You could not be logged in. Please try again.'; } } } } public function successAction() { if ($this->_helper->getHelper('FlashMessenger')->getMessages()) { $this->view->messages = $this->_helper ->getHelper('FlashMessenger') ->getMessages(); } else { $this->_redirect('/login'); } } public function logoutAction() { Zend_Auth::getInstance()->clearIdentity(); Zend_Session::destroy(); $this->_redirect('/'); } }

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  • How to fast rendering UITableView

    - by pubudu
    In my program has two view controller. first one has one button.and second one has tableview with custom cell. in this cell has 5 textviews. when i click button of first tableview.it shows second view controller. Its is very slow rendering table view with 5 , 6 rows.it is working well with simulator.but it is very slow with actual i pad. when i click the button i have to wait 2,3 second with button pressed status.and after it view the second view controller it also very slow rendering.i can see it render rows. [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; this one also i used.when i comment this table from my second view.it navigate first view controller to second view controller very fast. how can i solve this issue?

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  • Write a JavaScript that accepts a number from the user using the “prompt” function

    - by A sw A
    Write a JavaScript that accepts a number from the user using the “prompt” function. Then it draws a table in the HTML document that has the user specified number of rows and columns. In each table data, it displays the result of the math operation (row raised to the power of column). For example, if the user enters the number 3, the JavaScript should draw the following table: 1 1 1 2 4 8 3 9 27

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  • Moving a UIIMageView outside of a UIScrollView

    - by user359570
    Hello, At the bottom part of my main UIView, I've an UIScrollView with an UIImageView inside. I'd like to move the UIIMageView from the UIScrollView to the top part of my UIView. I'm able to move my UIImageView inside the UIScrollView, but outside, I can't. The UIImageView remains in the UIScrollView, it's parent. Any idea? Thanks in advance for any help. Best regards, Alx

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  • Problem getting textfield.text from other view controller

    - by wesleydyson
    Hey guys, I'm trying to add a textfield.text entry to an array. I want to pull the textfield.text from a text field in another view. Here's my code. - (void)addBookmark{ MultiViewViewController *mainView = [[MultiViewViewController alloc] init]; if (mainView.addressTextField.text.length>1) { NSString *addedString = [[NSString alloc] initWithFormat:@"%@", mainView.addressTextField.text]; [bookmarksArray addObject:addedString]; NSLog(@"addBookmark being called %@", mainView.addressTextField.text); } [bmTableView reloadData]; } The NSLog says the mainView.addressTextField.text is (NULL). What am I doing wrong?

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  • Adding the scrollview created by photoscroller to a subview

    - by wierddemon
    I'm trying to modify Apple's PhotoScroller example to make the scrollview that is created into a subview instead of it being a view that takes up the entire screen. Any ideas on how this can be accomplished? - (void)loadView { // Step 1: make the outer paging scroll view CGRect pagingScrollViewFrame = [self frameForPagingScrollView]; pagingScrollView = [[UIScrollView alloc] initWithFrame:pagingScrollViewFrame]; pagingScrollView.pagingEnabled = YES; pagingScrollView.backgroundColor = [UIColor blackColor]; pagingScrollView.showsVerticalScrollIndicator = NO; pagingScrollView.showsHorizontalScrollIndicator = NO; pagingScrollView.contentSize = [self contentSizeForPagingScrollView]; pagingScrollView.delegate = self; // When I do this it fails [self.view addSubview:pagingScrollView]; // Step 2: prepare to tile content recycledPages = [[NSMutableSet alloc] init]; visiblePages = [[NSMutableSet alloc] init]; [self tilePages]; }

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  • Xcode save image to camera roll

    - by user1470914
    I am new to Xcode (using 4.3) and am not sure how to save an image to the device's camera roll. All that I have done so far is an IBAction for the button to save the image (the button resides in the top right of the navigation bar. This tutorial (http://www.youtube.com/watch?v=sSdwjQUXA2Y) is EXACTLY what I would like to be able to do but the code is too blurry to read properly. Any help would be greatly appreciated.

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