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• local variable 'sresult' referenced before assignment

  - by user288558

  I have had multiple problems trying to use PP. I am running python2.6 and pp 1.6.0 rc3. Using the following test code: import pp nodes=('mosura02','mosura03','mosura04','mosura05','mosura06', 'mosura09','mosura10','mosura11','mosura12') def pptester(): js=pp.Server(ppservers=nodes) tmp=[] for i in range(200): tmp.append(js.submit(ppworktest,(),(),('os',))) return tmp def ppworktest(): return os.system("uname -a") gives me the following result: In [10]: Exception in thread run_local: Traceback (most recent call last): File "/usr/lib64/python2.6/threading.py", line 525, in __bootstrap_inner self.run() File "/usr/lib64/python2.6/threading.py", line 477, in run self.__target(*self.__args, **self.__kwargs) File "/home/wkerzend/python_coala/lib/python2.6/site-packages/pp.py", line 751, in _run_local job.finalize(sresult) UnboundLocalError: local variable 'sresult' referenced before assignment Exception in thread run_local: Traceback (most recent call last): File "/usr/lib64/python2.6/threading.py", line 525, in __bootstrap_inner self.run() File "/usr/lib64/python2.6/threading.py", line 477, in run self.__target(*self.__args, **self.__kwargs) File "/home/wkerzend/python_coala/lib/python2.6/site-packages/pp.py", line 751, in _run_local job.finalize(sresult) UnboundLocalError: local variable 'sresult' referenced before assignment Exception in thread run_local: Traceback (most recent call last): File "/usr/lib64/python2.6/threading.py", line 525, in __bootstrap_inner self.run() File "/usr/lib64/python2.6/threading.py", line 477, in run self.__target(*self.__args, **self.__kwargs) File "/home/wkerzend/python_coala/lib/python2.6/site-packages/pp.py", line 751, in _run_local job.finalize(sresult) UnboundLocalError: local variable 'sresult' referenced before assignment Exception in thread run_local: Traceback (most recent call last): File "/usr/lib64/python2.6/threading.py", line 525, in __bootstrap_inner self.run() File "/usr/lib64/python2.6/threading.py", line 477, in run self.__target(*self.__args, **self.__kwargs) File "/home/wkerzend/python_coala/lib/python2.6/site-packages/pp.py", line 751, in _run_local job.finalize(sresult) UnboundLocalError: local variable 'sresult' referenced before assignment any help greatly appreciated

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• Getting message in android app: Binary XML file line #2: You must supply a layout_width attribute.

  - by opike

  I'm trying to use a ListView inside of a RelativeLayout but when I run my app I get a runtimeexception with the message: Binary XML file line #2: You must supply a layout_width attribute. I tried putting layout_width attributes in every conceivable place in the xml resource files but so far no luck. I attempt to populate the listview with this line of code: setListAdapter(new ArrayAdapter(this, R.layout.tablerow3, R.id.label, items)); Here's the tablerow3.xml contents: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"> android:layout_width="20dp" android:layout_height="5dp" android:id="@+id/tablerow01"> <Label android:id="@+id/label01" android:layout_width="5dp" android:layout_height="5dp" android:textColor="@color/solid_white" android:singleLine="true"/> <Label android:id="@+id/label02" android:layout_width="5dp" android:layout_height="5dp" android:textColor="@color/solid_white" android:singleLine="true"/> </LinearLayout> Here's the xml that contains the RelativeLayout(forex2.xml): <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent"> <Button android:text="Static Button" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_alignParentLeft="true" android:layout_alignParentTop="true" android:id="@+id/button_id"> </Button> <Spinner android:id="@+id/spinner1" android:layout_width="match_parent" android:layout_toRightOf="@id/button_id" android:layout_alignParentTop="true" android:layout_height="wrap_content" android:drawSelectorOnTop="true" /> <ListView android:id="@android:id/list" android:layout_width="5dp" android:layout_height="5dp" android:layout_alignParentBottom="true" /> <!-- android:layout_width="wrap_content" android:layout_height="wrap_content" --> </RelativeLayout>

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• jruby rubygems update breaks jgem

  - by brad

  Has anyone seen this: ?? No jgem command works at all?? Though jruby -S gem list does work. I'm using jruby 1.3.1 and Sun Java6 jre root@test:/usr/local: jgem --version 1.3.3 root@test:/usr/local: jgem update --system JRuby limited openssl loaded. gem install jruby-openssl for full support. http://wiki.jruby.org/wiki/JRuby_Builtin_OpenSSL Updating RubyGems Updating rubygems-update Successfully installed rubygems-update-1.3.6 /usr/local/jruby/lib/ruby/site_ruby/1.8/rubygems/commands/update_command.rb:103:Warning: Gem::SourceIndex#search support for String patterns is deprecated Updating RubyGems to 1.3.6 Installing RubyGems 1.3.6 RubyGems 1.3.6 installed root@test:/usr/local: jgem list /usr/local/jruby/bin/jgem: line 8: require: command not found /usr/local/jruby/bin/jgem: line 9: require: command not found /usr/local/jruby/bin/jgem: line 10: require: command not found /usr/local/jruby/bin/jgem: line 12: required_version: command not found /usr/local/jruby/bin/jgem: line 14: unless: command not found /usr/local/jruby/bin/jgem: line 15: abort: command not found /usr/local/jruby/bin/jgem: line 16: end: command not found /usr/local/jruby/bin/jgem: line 18: args: command not found /usr/local/jruby/bin/jgem: line 20: begin: command not found /usr/local/jruby/bin/jgem: line 21: Gem::GemRunner.new.run: command not found /usr/local/jruby/bin/jgem: line 22: rescue: command not found /usr/local/jruby/bin/jgem: line 23: exit: e.exit_code: numeric argument required

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• How to make <asp:Menu and <asp:DropDownList on one line ?

  - by nCdy

  I've tried this : <div id="xDiv" align="left"> <div id="divX" runat="server" style="margin-left:40px; width: 650px;" align="center"> <asp:Menu ID="Menu3" runat="server" Orientation="Horizontal" Width="100%" StaticSelectedStyle-CssClass="StaticSelectedStyle" Height="52px" StaticSubMenuIndent="18px" oninit="Menu3_Init"> <StaticSelectedStyle CssClass="StaticSelectedStyle"></StaticSelectedStyle> <Items> <asp:MenuItem Text="Test" /> </Items> </asp:Menu> </div> <div runat="server"> <asp:DropDownList ID="DropDownList3" runat="server" DataSourceID="SqlDataSource1" DataTextField="RepGroup_Name" DataValueField="RepGroup_ID" Width="162px"> </asp:DropDownList> </div> </div> but it puts DropDownList not to the end of line , it puts it on a new line.

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• Dynamically create a text file from a C# program

  - by techstu

  Can I dynamically create a text file from a C# program, using data from a previously created xml file and text file, I have written half the code, but can't go any further please help using System; using System.IO; using System.Xml; namespace Task3 { class TextFileReader { static void Main(string[] args) { String strn=" ", strsn=String.Empty; XmlTextReader reader = new XmlTextReader("my.xml"); while (reader.Read()) { switch (reader.NodeType) { case XmlNodeType.Element: // The node is an element. if (reader.HasAttributes) { strn = reader.GetAttribute(0); strsn = reader.GetAttribute(1); int counter = 0; string line; // Read the file and display it line by line. System.IO.StreamReader file = new System.IO.StreamReader("read_file.txt"); string ch, ch1; while ((line = file.ReadLine()) != null) { if (line.Substring(0, 1).Equals("%")) { int a = line.IndexOf('%'); int b = line.LastIndexOf('%'); ch = line.Substring(a + 1, b - 1); ch1 = line.Substring(a, b+1); if (ch == "name") { string test = line.Replace(ch1, strn); Console.WriteLine(test); } else if (ch == "sirname") { string test = line.Replace(ch1, strsn); Console.WriteLine(test); } } else { Console.WriteLine(line); } counter++; } file.Close(); } break; } } // Suspend the screen. Console.ReadLine(); } } } the xml file from which i am reading is: <?xml version="1.0" encoding="utf-8" ?> - <Workflow> <User UserName="pqr" Sirname="sbd" /> <User UserName="abc" Sirname="xyz" /> </Workflow> and the text file is: hi this is me %sirname% %name% but this is not wat i want..please help

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• httplib2 giving internal server error 500 with proxy

  - by NJTechie

  Following is the code and error it throws. It works fine without the proxy http = httplib2.Http() . Any pointers are highly appreciated! Usage : http = httplib2.Http(proxy_info = httplib2.ProxyInfo(socks.PROXY_TYPE_HTTP, '74.115.1.11', 80)) main_url = 'http://www.mywebsite.com' response, content = http.request(main_url, 'GET') Error : File "testproxy.py", line 17, in <module> response, content = http.request(main_url, 'GET') File "/home/kk/bin/pythonlib/httplib2/__init__.py", line 1129, in request (response, content) = self._request(conn, authority, uri, request_uri, method, body, headers, redirections, cachekey) File "/home/kk/bin/pythonlib/httplib2/__init__.py", line 901, in _request (response, content) = self._conn_request(conn, request_uri, method, body, headers) File "/home/kk/bin/pythonlib/httplib2/__init__.py", line 862, in _conn_request conn.request(method, request_uri, body, headers) File "/usr/lib/python2.5/httplib.py", line 866, in request self._send_request(method, url, body, headers) File "/usr/lib/python2.5/httplib.py", line 889, in _send_request self.endheaders() File "/usr/lib/python2.5/httplib.py", line 860, in endheaders self._send_output() File "/usr/lib/python2.5/httplib.py", line 732, in _send_output self.send(msg) File "/usr/lib/python2.5/httplib.py", line 699, in send self.connect() File "/home/kk/bin/pythonlib/httplib2/__init__.py", line 740, in connect self.sock.connect(sa) File "/home/kk/bin/pythonlib/socks.py", line 383, in connect self.__negotiatehttp(destpair[0],destpair[1]) File "/home/kk/bin/pythonlib/socks.py", line 349, in __negotiatehttp raise HTTPError((statuscode,statusline[2])) socks.HTTPError: (500, 'Internal Server Error')

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• Applescript from Mac App says "Expected end of line but found \U201c\"\U201d."

  - by Rasmus Styrk

  I am trying to perform a copy/paste for my to the the last active app, here's my code: NSString *appleScriptSource = [NSString stringWithFormat:@"\ntell application \"%@\" to activate\ntell application \"System Events\" to tell process \"%@\"\nkeystroke \"v\" using command down\nend tell", [lastApp localizedName], [lastApp localizedName]]; NSDictionary *error; NSAppleScript *aScript = [[NSAppleScript alloc] initWithSource:appleScriptSource]; NSAppleEventDescriptor *aDescriptor = [aScript executeAndReturnError:&error]; The problem is that on some computers it works just fine, but on others it fails. My error output from error that is returned by executeAndReturnError is: 2012-06-13 17:43:19.875 Mini Translator[1206:303] (null) (error: { NSAppleScriptErrorBriefMessage = "Expected end of line but found \U201c\"\U201d."; NSAppleScriptErrorMessage = "Expected end of line but found \U201c\"\U201d."; NSAppleScriptErrorNumber = "-2741"; NSAppleScriptErrorRange = "NSRange: {95, 1}"; }) I can't seem to figure out what it means or why it happens. We tried copying the generated apple-script code into the Apple Script editor, and here it works just fine. My App is sandboxed - i have added the bundle identifiers for the key "com.apple.security.temporary-exception.apple-events" for the apps i want to support. Any suggestions?

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• Why is curl in Ruby slower than command-line curl?

  - by Stiivi

  I am trying to download more than 1m pages (URLs ending by a sequence ID). I have implemented kind of multi-purpose download manager with configurable number of download threads and one processing thread. The downloader downloads files in batches: curl = Curl::Easy.new batch_urls.each { |url_info| curl.url = url_info[:url] curl.perform file = File.new(url_info[:file], "wb") file << curl.body_str file.close # ... some other stuff } I have tried to download 8000 pages sample. When using the code above, I get 1000 in 2 minutes. When I write all URLs into a file and do in shell: cat list | xargs curl I gen all 8000 pages in two minutes. Thing is, I need it to have it in ruby code, because there is other monitoring and processing code. I have tried: Curl::Multi - it is somehow faster, but misses 50-90% of files (does not download them and gives no reason/code) multiple threads with Curl::Easy - around the same speed as single threaded Why is reused Curl::Easy slower than subsequent command line curl calls and how can I make it faster? Or what I am doing wrong? I would prefer to fix my download manager code than to make downloading for this case in a different way. Before this, I was calling command-line wget which I provided with a file with list of URLs. Howerver, not all errors were handled, also it was not possible to specify output file for each URL separately when using URL list. Now it seems to me that the best way would be to use multiple threads with system call to 'curl' command. But why when I can use directly Curl in Ruby? Code for the download manager is here, if it might help: Download Manager (I have played with timeouts, from not-setting it to various values, it did not seem help) Any hints appreciated.

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• Python3 and ftplib uploading files

  - by Teifion

  My python2 script uploads files nicely using this method but python3 is presenting problems and I'm stuck as to where to go next (googling hasn't helped). from ftplib import FTP ftp = FTP(ftp_host, ftp_user, ftp_pass) ftp.storbinary('STOR myfile.txt', open('myfile.txt')) The error I get is Traceback (most recent call last): File "/Library/WebServer/CGI-Executables/rob3/functions/cli_f.py", line 12, in upload ftp.storlines('STOR myfile.txt', open('myfile.txt')) File "/Library/Frameworks/Python.framework/Versions/3.1/lib/python3.1/ftplib.py", line 454, in storbinary conn.sendall(buf) TypeError: must be bytes or buffer, not str I tried altering the code to from ftplib import FTP ftp = FTP(ftp_host, ftp_user, ftp_pass) ftp.storbinary('STOR myfile.txt'.encode('utf-8'), open('myfile.txt')) But instead I got this Traceback (most recent call last): File "/Library/WebServer/CGI-Executables/rob3/functions/cli_f.py", line 12, in upload ftp.storbinary('STOR myfile.txt'.encode('utf-8'), open('myfile.txt')) File "/Library/Frameworks/Python.framework/Versions/3.1/lib/python3.1/ftplib.py", line 450, in storbinary conn = self.transfercmd(cmd) File "/Library/Frameworks/Python.framework/Versions/3.1/lib/python3.1/ftplib.py", line 358, in transfercmd return self.ntransfercmd(cmd, rest)[0] File "/Library/Frameworks/Python.framework/Versions/3.1/lib/python3.1/ftplib.py", line 329, in ntransfercmd resp = self.sendcmd(cmd) File "/Library/Frameworks/Python.framework/Versions/3.1/lib/python3.1/ftplib.py", line 244, in sendcmd self.putcmd(cmd) File "/Library/Frameworks/Python.framework/Versions/3.1/lib/python3.1/ftplib.py", line 179, in putcmd self.putline(line) File "/Library/Frameworks/Python.framework/Versions/3.1/lib/python3.1/ftplib.py", line 172, in putline line = line + CRLF TypeError: can't concat bytes to str Can anybody point me in the right direction

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• How to wrtie a XML License Line(ended with a forward slash '/') in C#?

  - by Nano HE

  I want to write a XML file as below: <?xml version="1.0" encoding="UTF-8"?> <books xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <License licenseId="" licensePath="" /> Some piece of my code attached here // Create a new file in D:\\ and set the encoding to UTF-8 XmlTextWriter textWriter = new XmlTextWriter("D:\\books.xml", System.Text.Encoding.UTF8); // Format automatically textWriter.Formatting = Formatting.Indented; // Opens the document textWriter.WriteStartDocument(); // Write the namespace declaration. textWriter.WriteStartElement("books", null); // Write the genre attribute. textWriter.WriteAttributeString("xmlns", "xsd", null, "http://www.w3.org/2001/XMLSchema"); textWriter.WriteAttributeString("xmlns", "xsi", null, "http://www.w3.org/2001/XMLSchema-instance"); And now I need to write the License Line below in C# <License licenseId="" licensePath="" /> But I don't know how to move on for I found the Line ended with the forward slash / .Thank you.

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• help('modules') crashing?

  - by Chris

  I was trying to install a module for opencv and added an opencv.pth file to the folder beyond my sites.py file. I have since deleted it and no change. When I try to run help('modules'), I get the following error: Please wait a moment while I gather a list of all available modules... /System/Library/Frameworks/Python.framework/Versions/2.5/Extras/lib/python/twisted/words/im/init.py:8: UserWarning: twisted.im will be undergoing a rewrite at some point in the future. warnings.warn("twisted.im will be undergoing a rewrite at some point in the future.") /System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/pkgutil.py:110: DeprecationWarning: The wxPython compatibility package is no longer automatically generated or actively maintained. Please switch to the wx package as soon as possible. import(name) Traceback (most recent call last): File "", line 1, in File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/site.py", line 348, in call return pydoc.help(*args, **kwds) File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/pydoc.py", line 1644, in call self.help(request) File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/pydoc.py", line 1681, in help elif request == 'modules': self.listmodules() File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/pydoc.py", line 1802, in listmodules ModuleScanner().run(callback) File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/pydoc.py", line 1853, in run for importer, modname, ispkg in pkgutil.walk_packages(): File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/pkgutil.py", line 110, in walk_packages import(name) File "/BinaryCache/wxWidgets/wxWidgets-11~262/Root/System/Library/Frameworks/Python.framework/Versions/2.5/Extras/lib/python/wxaddons/init.py", line 180, in import_hook File "/Library/Python/2.5/site-packages/ctypes_opencv/init.py", line 19, in from ctypes_opencv.cv import * File "/BinaryCache/wxWidgets/wxWidgets-11~262/Root/System/Library/Frameworks/Python.framework/Versions/2.5/Extras/lib/python/wxaddons/init.py", line 180, in import_hook File "/Library/Python/2.5/site-packages/ctypes_opencv/cv.py", line 2567, in ('desc', CvMat_r, 1), # CvMat* desc File "/Library/Python/2.5/site-packages/ctypes_opencv/cxcore.py", line 114, in cfunc return CFUNCTYPE(result, *atypes)((name, dll), tuple(aflags)) AttributeError: dlsym(0x2674d10, cvCreateFeatureTree): symbol not found What gives?!

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• How can I modify my code to line through the bezier control points?

  - by WillyCornbread

  HI all - I am using anchor points and control points to create a shape using curveTo. It's all working fine, but I cannot figure out how to get my lines to go through the center of the control points (blue dots) when the line is not straight. Here is my code for drawing the shape: // clear old line and draw new / begin fill var g:Graphics = graphics; g.clear(); g.lineStyle(2, 0, 1); g.beginFill(0x0099FF,.1); //move to starting anchor point var startX:Number = anchorPoints[0].x; var startY:Number = anchorPoints[0].y; g.moveTo(startX, startY); // Connect the dots var numAnchors:Number = anchorPoints.length; for (var i:Number=1; i<numAnchors; i++) { // curve to next anchor through control g.curveTo(controlPoints[i].x,controlPoints[i].y, anchorPoints[i].x, anchorPoints[i].y); } // Close the loop g.curveTo(controlPoints[0].x,controlPoints[0].y,startX,startY); And the shape I'm drawing for reference: How can I modify my code so that the lines go directly through the blue control points? Thanks in advance! b

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• MySQL 1064 error, works in command line and phpMyAdmin; not in app

  - by hundleyj

  Here is my query: select * from (select *, 3956 * 2 * ASIN(SQRT(POWER(SIN(RADIANS(45.5200077 - lat)/ 2), 2) + COS(RADIANS(45.5200077)) * COS(RADIANS(lat)) * POWER(SIN(RADIANS(-122.6942014 - lng)/2),2))) AS distance from stops order by distance, route asc) as p group by route, dir order by distance asc limit 10 This works fine at the command line and in PHPMyAdmin. I'm using Dbslayer to connect to MySQL via my JavaScript backend, and the request is returning a 1064 error. Here is the encoded DBSlayer request string: http://localhost:9090/db?{%22SQL%22:%22select%20*%20from%20%28select%20*,%203956%20*%202%20*%20ASIN%28SQRT%28POWER%28SIN%28RADIANS%2845.5200077%20-%20lat%29/%202%29,%202%29%20+%20COS%28RADIANS%2845.5200077%29%29%20*%20COS%28RADIANS%28lat%29%29%20*%20POWER%28SIN%28RADIANS%28-122.6942014%20-%20lng%29/2%29,2%29%29%29%20AS%20distance%20from%20%60stops%60%20order%20by%20%60distance%60,%20%60route%60%20asc%29%20as%20p%20group%20by%20%60route%60,%20%60dir%60%20order%20by%20%60distance%60%20asc%20limit%2010%22} And the response: {"MYSQL_ERRNO" : 1064 , "MYSQL_ERROR" : "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '(RADIANS(45.5200077)) * COS(RADIANS(lat)) * POWER(SIN(RADIANS(-122.6942014 - lng' at line 1" , "SERVER" : "trimet"} Thanks!

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• Why are (almost) all the on-line games written in ActionScript (Flash) not Java?

  - by MasterPeter

  I absolutely love good defender games (e.g. Gemcraft, Protector: reclaiming the throne) as they can be intellectually quite challenging; it's like playing chess but a little less thinking a bit more action. Sadly, there are not that many good ones out there and I thought I would create one myself and share it with the rest of the world by making it available on-line. I have never worked with ActionScript but when it comes to on-line games, this is the main choice. I have tried to find a decent 2D game in the form of a Java applet but to no avail. Why is this so? I could write the game, most comfortably, in Delphi for Win32 but then people would need to download the executable, which could deter some form downloading it, and also it would only work on Windows. I am also familiar with Java, having worked with Java for the last four years or so. Although I don't have much experience with games programming. Should I note be deterred by the fact that all online games are written for in Flash and create my defender game as a Java applet, or should I consider learning ActionScript and games development for the ActionScript Virtual Machine (AS3 looks very much like Java... but still, it's an entirely new technology to me and I might never use it professionally.) Could you, please, just answer the the question in the title? Why Flash, not Java applets? Is it only 'politics'?

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• How do I detect proximity of the mouse pointer to a line in Flex?

  - by Hanno Fietz

  I'm working on a charting UI in Flex. One of the features I want to implement is "snapping" of the mousepointer to the data points in the diagram. I. e., if the user hovers the mouse pointer over a line diagram and gets close to the data point, I want the pointer to move to the exact coordinates and show a marker, like this: Currently, the lines are drawn on a Shape, using the Graphics API. The Shape is a child DisplayObject of a custom UIComponent subclass with the exact same dimensions. This means, I already get mouseOver events on the parent of the diagram's canvas. Now I need a way to detect if the pointer is close to one of the data points. I. e. I need an answer to the question "Which data points lie within a radius of x pixels from my current position and which of them is closest?" upon each move of the mouse. I can think of the following possibilities: draw the lines not as simple lines in the graphics API, but as more advanced objects that can have their own mouseOver events. However, I want the snapping to trigger before the mouse is actually over the line. check the original data for possible candidates upon each mouse movement. Using binary search, I might be able to reduce the number of items I have to compare sufficently. prepare some kind of new data structure from the raw data that makes the above search more efficient. I don't know how that would look like. I'm guessing this is a pretty standard problem for a number of applications, but probably the actual code usually is inside of some framework. Is there anything I can read about this topic?

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• What is the XSLT to write certain node attributes one-to-a-line?

  - by Scott Stafford

  I want an XML stylesheet (XSLT) that will put the attributes of a few, specific, child nodes one-to-a-line. What is the XSLT for this? I recently asked a related question that someone offered a stylesheet to solve but their stylesheet didn't work for some reason, and I am curious why -- the attributes simply didn't end up one-per-line. By way of example, my XML might look like this: <MyXML> <NodeA> <ChildNode value1='5' value2='6' /> </NodeA> <NodeB> <AnotherChildNode value1='5' value2='6' /> </NodeB> <NodeC> <AnotherChildNode value1='5' value2='6' /> </NodeC> </MyXML> And I want a stylesheet that will expand all NodeA's and NodeB's but not NodeCs and make it look like this: <MyXML> <NodeA> <ChildNode value1='5' value2='6' /> </NodeA> <NodeB> <AnotherChildNode value1='5' value2='6' /> </NodeB> <NodeC> <AnotherChildNode value1='5' value2='6' /> </NodeC> </MyXML>

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• Why can’t PHP script write a file on server 2008 via command line or task scheduler?

  - by rg89

  I created a question on serverfault.com, and it was recommended that I ask here. http://serverfault.com/questions/140669/why-cant-php-script-write-a-file-on-server-2008-via-command-line-or-task-schedul I have a PHP script. It runs well when I use a browser. It writes an XML file in the same directory. The script takes ~60 seconds to run, and the resulting XML file is ~16 MB. I am running PHP 5.2.13 via FastCGI on Windows Server Web edition SP1 64 bit. The code pulls inventory from SQL server, runs a loop to build an XML file for a third party. I created a task in task scheduler to run c:\php5\php.exe "D:\inetpub\tools\build.php" The task scheduler shows a time lapse of about a minute, which is how long the script takes to run in a browser. No error returned, but no file created. Each time I make a change to the scheduled task properties, a user password box comes up and I enter the administrator account password. If I run this same path and argument at a command line it does not error and does not create the file. When I right click run command prompt as an administrator, the file is still not created. I get my echo statement "file published" that is after the file creation and no error is returned. I am doing a simple fopen fwrite fclose to save the contents of a php variable to a .xml file, and the file only gets created when the script is run through the browser. Here's what happens after the xml-building loop: $feedContent .= "</feed"; sqlsrv_close( $conn ); echo "<p>feed built</p>"; $feedFile = "feed.xml"; $handler = fopen($feedFile, 'w'); fwrite( $handler, $feedContent ); fclose( $handler ); echo "<p>file published</p>"; Thanks

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• How can I tell when the Text of a System.Windows.Forms.GroupBox wraps to the next line?

  - by fre0n

  I'm creating a GroupBox at runtime and setting its Text property. Usually, the text is only on one line, but sometimes it wraps. The problem is that the controls contained in the GroupBox cover up the GroupBox's text. What I'd like to do is determine if and when the text wraps. Specifically, I'd like to determine how much extra height the wrapped text takes up as compared to a single line. That way, I can reposition the GroupBox's controls and adjust its height. Initially, I thought I'd do this by calling the GroupBox's CreateGraphics() method, and using the Graphics to measure the string. Something like this: private void SetGroupBoxText(GroupBox grp, string text) { const int somePadding = 10; Graphics g = grp.CreateGraphics(); SizeF textSize = g.MeasureString(text, grp.Font); if (textSize.Width > (grp.Width - somePadding)) { // Adjust height, etc. } } The problem is that the size generated by g.MeasureString(text, grp.Font) doesn't seem to be accurate. I determined that it wasn't accurate by putting enough of a single character to cause a wrap, then measuring the resulting string. For example, it took 86 pipes (|) to until a wrap happened. When I measured that string, its width was ~253. And it took 16 capital W's to force a wrap - its string had a width of ~164. These were the two extremes that I tested. My GroupBox's width was 189. (a's took 29 and had a width of ~180, O's took 22 and had a width of ~189) Does anyone have any ideas? (hacks, WinAPI, etc. are welcome solutions)

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• How to wrtie a XML License Line in C#?

  - by Nano HE

  My want to write a XML file as this: <?xml version="1.0" encoding="UTF-8"?> <Equipment xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <License licenseId="" licensePath="" /> Some piece of my code attached here // Create a new file in D:\\ and set the encoding to UTF-8 XmlTextWriter textWriter = new XmlTextWriter("D:\\books.xml", System.Text.Encoding.UTF8); // Format automatically textWriter.Formatting = Formatting.Indented; // Opens the document textWriter.WriteStartDocument(); // Write the namespace declaration. textWriter.WriteStartElement("books", null); // Write the genre attribute. textWriter.WriteAttributeString("xmlns", "xsd", null, "http://www.w3.org/2001/XMLSchema"); textWriter.WriteAttributeString("xmlns", "xsi", null, "http://www.w3.org/2001/XMLSchema-instance"); And now I need to write the License Line below in C# <License licenseId="" licensePath="" /> But I don't know how to move on for I found the Line ended with the special / .Thank you.

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• Java: Inputting text from a file using split

  - by 00PS

  I am inputting an adjacency list for a graph. There are three columns of data (vertex, destination, edge) separated by a single space. Here is my implementation so far: FileStream in = new FileStream("input1.txt"); Scanner s = new Scanner(in); String buffer; String [] line = null; while (s.hasNext()) { buffer = s.nextLine(); line = buffer.split("\\s+"); g.add(line[0]); System.out.println("Added vertex " + line[0] + "."); g.addEdge(line[0], line[1], Integer.parseInt(line[2])); System.out.println("Added edge from " + line[0] + " to " + line[1] + " with a weight of " + Integer.parseInt(line[2]) + "."); } System.out.println("Size of graph = " + g.size()); Here is the output: Added vertex a. Added edge from a to b with a weight of 9. Exception in thread "main" java.lang.NullPointerException at structure5.GraphListDirected.addEdge(GraphListDirected.java:93) at Driver.main(Driver.java:28) I was under the impression that line = buffer.split("\\s+"); would return a 2 dimensional array of Strings to the variable line. It seemed to work the first time but not the second. Any thoughts? I would also like some feedback on my implementation of this problem. Is there a better way? Anything to help out a novice! :)

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• help('modules') crashing? Not sure how to fix..

  - by Chris

  I was trying to install a module for opencv and added an opencv.pth file to the folder beyond my sites.py file. I have since deleted it and no change. When I try to run help('modules'), I get the following error: Please wait a moment while I gather a list of all available modules... /System/Library/Frameworks/Python.framework/Versions/2.5/Extras/lib/python/twisted/words/im/init.py:8: UserWarning: twisted.im will be undergoing a rewrite at some point in the future. warnings.warn("twisted.im will be undergoing a rewrite at some point in the future.") /System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/pkgutil.py:110: DeprecationWarning: The wxPython compatibility package is no longer automatically generated or actively maintained. Please switch to the wx package as soon as possible. import(name) Traceback (most recent call last): File "", line 1, in File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/site.py", line 348, in call return pydoc.help(*args, **kwds) File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/pydoc.py", line 1644, in call self.help(request) File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/pydoc.py", line 1681, in help elif request == 'modules': self.listmodules() File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/pydoc.py", line 1802, in listmodules ModuleScanner().run(callback) File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/pydoc.py", line 1853, in run for importer, modname, ispkg in pkgutil.walk_packages(): File "/System/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/pkgutil.py", line 110, in walk_packages import(name) File "/BinaryCache/wxWidgets/wxWidgets-11~262/Root/System/Library/Frameworks/Python.framework/Versions/2.5/Extras/lib/python/wxaddons/init.py", line 180, in import_hook File "/Library/Python/2.5/site-packages/ctypes_opencv/init.py", line 19, in from ctypes_opencv.cv import * File "/BinaryCache/wxWidgets/wxWidgets-11~262/Root/System/Library/Frameworks/Python.framework/Versions/2.5/Extras/lib/python/wxaddons/init.py", line 180, in import_hook File "/Library/Python/2.5/site-packages/ctypes_opencv/cv.py", line 2567, in ('desc', CvMat_r, 1), # CvMat* desc File "/Library/Python/2.5/site-packages/ctypes_opencv/cxcore.py", line 114, in cfunc return CFUNCTYPE(result, *atypes)((name, dll), tuple(aflags)) AttributeError: dlsym(0x2674d10, cvCreateFeatureTree): symbol not found What gives?!

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• PropertyPlaceholderConfigurer works from Maven command line, but not from Eclipse?

  - by HDave

  I have Eclipse configured to use an external maven instance. Nonetheless I have an integration test that runs fine from the command line, but fails from within Eclipse. The error is a class Spring application context bean error: Cannot convert value of type [java.lang.String] to required type The culprit it a bean that sets property values using a PropertyPlaceholderConfigurer. <!-- property settings for non-JNDI database connections --> <bean id="placeholderConfigUuid" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"> <property name="systemPropertiesModeName" value="SYSTEM_PROPERTIES_MODE_OVERRIDE" /> <property name="location" value="classpath:database.properties" /> <property name="placeholderPrefix" value="$DS{" /> </bean> I know which bean is failing because it appears in the stack trace and because when I replace the $DS{hibernate.dialect} with a static value it works. I have two questions: 1) Since M2Eclipse is using the same Maven setup as the command line, why does one work and the other fail? 2) How to fix this? I really like the ability to run a single jUnit test from within Eclipse on demand.

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• Can someone answer this for me?

  - by Dcurvez

  okay I am totally stuck. I have been getting some help off and on throughout this project and am anxious to get this problem solved so I can continue on with the rest of this project. I have a gridview that is set to save to a file, and has the option to import into excel. I keep getting an error of this: Invalid cast exception was unhandled. At least one element in the source array could not be cast down to the destination array type. Can anyone tell me in layman easy to understand what this error is speaking of? This is the code I am trying to use: Dim fileName As String = "" Dim dlgSave As New SaveFileDialog dlgSave.Filter = "Text files (*.txt)|*.txt|CSV Files (*.csv)|*.csv" dlgSave.AddExtension = True dlgSave.DefaultExt = "txt" If dlgSave.ShowDialog = Windows.Forms.DialogResult.OK Then fileName = dlgSave.FileName SaveToFile(fileName) End If End Sub Private Sub SaveToFile(ByVal fileName As String) If DataGridView1.RowCount > 0 AndAlso DataGridView1.Rows(0).Cells(0) IsNot Nothing Then Dim stream As New System.IO.FileStream(fileName, IO.FileMode.Append, IO.FileAccess.Write) Dim sw As New System.IO.StreamWriter(stream) For Each row As DataGridViewRow In DataGridView1.Rows Dim arrLine(9) As String Dim line As String **row.Cells.CopyTo(arrLine, 0)** line = arrLine(0) line &= ";" & arrLine(1) line &= ";" & arrLine(2) line &= ";" & arrLine(3) line &= ";" & arrLine(4) line &= ";" & arrLine(5) line &= ";" & arrLine(6) line &= ";" & arrLine(7) line &= ";" & arrLine(8) sw.WriteLine(line) Next sw.Flush() sw.Close() End If I bolded the line where it shows in debug, and I really dont see what all the fuss is about LOL

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• Help with HTTP Intercepting Proxy in Ruby?

  - by Philip

  I have the beginnings of an HTTP Intercepting Proxy written in Ruby: require 'socket' # Get sockets from stdlib server = TCPServer.open(8080) # Socket to listen on port 8080 loop { # Servers run forever Thread.start(server.accept) do |client| puts "** Got connection!" @output = "" @host = "" @port = 80 while line = client.gets line.chomp! if (line =~ /^(GET|CONNECT) .*(\.com|\.net):(.*) (HTTP\/1.1|HTTP\/1.0)$/) @port = $3 elsif (line =~ /^Host: (.*)$/ && @host == "") @host = $1 end print line + "\n" @output += line + "\n" # This *may* cause problems with not getting full requests, # but without this, the loop never returns. break if line == "" end if (@host != "") puts "** Got host! (#{@host}:#{@port})" out = TCPSocket.open(@host, @port) puts "** Got destination!" out.print(@output) while line = out.gets line.chomp! if (line =~ /^<proxyinfo>.*<\/proxyinfo>$/) # Logic is done here. end print line + "\n" client.print(line + "\n") end out.close end client.close end } This simple proxy that I made parses the destination out of the HTTP request, then reads the HTTP response and performs logic based on special HTML tags. The proxy works for the most part, but seems to have trouble dealing with binary data and HTTPS connections. How can I fix these problems?

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• How can I add one line into all php files' beginning?

  - by Tom

  So, ok. I have many php files and one index.php file. All files can't work without index.php file, because I include them in index.php. For example. if somebody click Contact us the URL will become smth like index.php?id=contact and I use $_GET['id'] to include contacts.php file. But, if somebody find the file's path, for example /system/files/contacts.php I don't want that that file would be executed. So, I figured out that I can add before including any files in index.php line like this $check_hacker = 1 and use if in every files beginning like this if($check_hacker <> 1) die();. So, how can I do it without opening all files and adding this line to each of them? Is it possible? Because I actually have many .php files. And maybe there is other way to do disable watching separate file? Any ideas? Thank you.

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