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  • Python try/except: Showing the cause of the error after displaying my variables

    - by NealWalters
    I'm not even sure what the right words are to search for. I want to display parts of the error object in an except block (similar to the err object in VBScript, which has Err.Number and Err.Description). For example, I want to show the values of my variables, then show the exact error. Clearly, I am causing a divided-by-zero error below, but how can I print that fact? try: x = 0 y = 1 z = y / x z = z + 1 print "z=%d" % (z) except: print "Values at Exception: x=%d y=%d " % (x,y) print "The error was on line ..." print "The reason for the error was ..."

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  • How do I calculate percentiles with python/numpy?

    - by Uri
    Is there a convenient way to calculate percentiles for a sequence or single-dimensional numpy array? I am looking for something similar to Excel's percentile function. I looked in NumPy's statistics reference, and couldn't find this. All I could find is the median (50th percentile), but not something more specific.

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  • Get Path of Uploaded File using Python

    - by Ali
    Is it possible to get the full path of the file on the user's computer being uploaded to my site? Using os.path.abspath(fileitem.filename) simply gets me the address of where my script is executing from on my shared hosting server. FYI: fileitem = form['file'] and form = cgi.FieldStorage()

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  • Python ctypes argument errors

    - by Patrick Moriarty
    Hello. I wrote a test dll in C++ to make sure things work before I start using a more important dll that I need. Basically it takes two doubles and adds them, then returns the result. I've been playing around and with other test functions I've gotten returns to work, I just can't pass an argument due to errors. My code is: import ctypes import string nDLL = ctypes.WinDLL('test.dll') func = nDLL['haloshg_add'] func.restype = ctypes.c_double func.argtypes = (ctypes.c_double,ctypes.c_double) print(func(5.0,5.0)) It returns the error for the line that called "func": ValueError: Procedure probably called with too many arguments (8 bytes in excess) What am I doing wrong? Thanks.

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  • Small Python optional arguments question

    - by ooboo
    I have two functions: def f(a,b,c=g(b)): blabla def g(n): blabla c is an optional argument in function f. If the user does not specify its value, the program should compute g(b) and that would be the value of c. But the code does not compile - it says name 'b' is not defined. How to fix that? Someone suggested: def g(b): blabla def f(a,b,c=None): if c is None: c = g(b) blabla But this doesn't work, because maybe the user intended c to be None and then c will have another value.

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  • Split a string in python taking care of quotes

    - by santu
    I want to extract key value pairs of some form elements in a html page for example name="frmLogin" method="POST" onSubmit="javascript:return validateAndSubmit();" action="TG_cim_logon.asp?SID=^YcMunDFDQUoWV32WPUMqPxeSxD4L_slp_rhc_rNvW7Fagp7FgH3l0uJR/3_slp_rhc_dYyJ_slp_rhc_vsPW0kJl&RegType=Lite_Home" is there any method using which I can safely get the key and value pairs. I tried using splitting by spaces and then using '=' characters but string inside quotes can also have '='. is there any different kind of split method which can also take care of quotes?

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  • How to show why "try" failed in python

    - by calccrypto
    is there anyway to show why a "try" failed, and skipped to "except", without writing out all the possible errors by hand, and without ending the program? example: try: 1/0 except: someway to show "Traceback (most recent call last): File "<pyshell#0>", line 1, in <module> 1/0 ZeroDivisionError: integer division or modulo by zero" i dont want to doif:print error 1, elif: print error 2, elif: etc.... i want to see the error that would be shown had try not been there

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  • What are the steps taken with pip install in python

    - by Lawrence Chernin
    I am trying to install a package via pip, but there were missing files from the zip file. So I copy the files and then compile with gcc. But now I cannot continue with the installation by calling pip install because it sees a pre-existing directory and will not proceed. This is with pip version 1.5.6, but I thought that with earlier versions of pip that it was less fussy about this. What are the remaining steps to complete the package installation?

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  • Python datetime to Unix timestamp

    - by Off Rhoden
    I have to create an "Expires" value 5 minutes in the future, but I have to supply it in UNIX Timestamp format. I have this so far, but it seems like a hack. def expires(): '''return a UNIX style timestamp representing 5 minutes from now''' epoch = datetime.datetime(1970, 1, 1) seconds_in_a_day = 60 * 60 * 24 five_minutes = datetime.timedelta(seconds=5*60) five_minutes_from_now = datetime.datetime.now() + five_minutes since_epoch = five_minutes_from_now - epoch return since_epoch.days * seconds_in_a_day + since_epoch.seconds Is there a module or function that does the timestamp conversion for me?

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  • Algorithm detect repeating/similiar strings in a corpus of data -- say email subjects, in Python

    - by RizwanK
    I'm downloading a long list of my email subject lines , with the intent of finding email lists that I was a member of years ago, and would want to purge them from my Gmail account (which is getting pretty slow.) I'm specifically thinking of newsletters that often come from the same address, and repeat the product/service/group's name in the subject. I'm aware that I could search/sort by the common occurrence of items from a particular email address (and I intend to), but I'd like to correlate that data with repeating subject lines.... Now, many subject lines would fail a string match, but "Google Friends : Our latest news" "Google Friends : What we're doing today" are more similar to each other than a random subject line, as is: "Virgin Airlines has a great sale today" "Take a flight with Virgin Airlines" So -- how can I start to automagically extract trends/examples of strings that may be more similar. Approaches I've considered and discarded ('because there must be some better way'): Extracting all the possible substrings and ordering them by how often they show up, and manually selecting relevant ones Stripping off the first word or two and then count the occurrence of each sub string Comparing Levenshtein distance between entries Some sort of string similarity index ... Most of these were rejected for massive inefficiency or likelyhood of a vast amount of manual intervention required. I guess I need some sort of fuzzy string matching..? In the end, I can think of kludgy ways of doing this, but I'm looking for something more generic so I've added to my set of tools rather than special casing for this data set. After this, I'd be matching the occurring of particular subject strings with 'From' addresses - I'm not sure if there's a good way of building a data structure that represents how likely/not two messages are part of the 'same email list' or by filtering all my email subjects/from addresses into pools of likely 'related' emails and not -- but that's a problem to solve after this one. Any guidance would be appreciated.

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  • Redirect print in Python: val = print(arg) to output mixed iterable to file

    - by emcee
    So lets say I have an incredibly nested iterable of lists/dictionaries. I would like to print them to a file as easily as possible. Why can't I just redirect print to a file? val = print(arg) gets a SyntaxError. Is there a way to access stdinput? And why does print take forever with massive strings? Bad programming on my side for outputting massive strings, but quick debugging--and isn't that leveraging the strength of an interactive prompt? There's probably also an easier way than my gripe. Has the hive-mind an answer?

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  • Take the intersection of an arbitrary number of lists in python

    - by thepandaatemyface
    Suppose I have a list of lists of elements which are all the same (i'll use ints in this example) [range(100)[::4], range(100)[::3], range(100)[::2], range(100)[::1]] What would be a nice and/or efficient way to take the intersection of these lists (so you would get every element that is in each of the lists)? For the example that would be: [0, 12, 24, 36, 48, 60, 72, 84, 96]

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  • Python modify an xml file

    - by michele
    I have this xml model. link text So I have to add some node (see the text commented) to this file. How I can do it? I have writed this partial code but it doesn't work: xmldoc=minidom.parse(directory) child = xmldoc.createElement("map") for node in xmldoc.getElementsByTagName("Environment"): node.appendChild(child) Thanks in advance.

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  • How does this If conditional work in Python?

    - by Sergio Boombastic
    from google.appengine.api import users from google.appengine.ext import webapp from google.appengine.ext.webapp.util import run_wsgi_app class MainPage(webapp.RequestHandler): def get(self): user = users.get_current_user() if user: self.response.headers['Content-Type'] = 'text/plain' self.response.out.write('Hello, ' + user.nickname()) else: self.redirect(users.create_login_url(self.request.uri)) application = webapp.WSGIApplication( [('/', MainPage)], debug=True) def main(): run_wsgi_app(application) if __name__ == "__main__": main() I don't understand how this line works: if user: self.response.headers['Content-Type'] = 'text/plain' self.response.out.write('Hello, ' + user.nickname()) else: self.redirect(users.create_login_url(self.request.uri)) I'm guessing the users.get_current_user() return a boolean? Then, if that is the case how can it get a .nickname() method? Thanks for the guidance.

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  • Youtube python: get thumbnail

    - by dkgirl
    Is there a simple way to get the default thumbnail from a youtube entry object gdata.youtube.YouTubeVideoEntry? I tried entry.media.thumbnail, but that gives me four thumbnail objects. Can I always trust that there are four? Can I know which is the default thumbnail that would also appears on the youtube search page? And how would I get that one? Or do I have to alter one of the other ones? When I know the video_id I use: http://i4.ytimg.com/vi/{{video_id}}/default.jpg so, it would also be helpful to get the video_id. Do I really have to parse one of the url's to get at the video_id ? It seems strange that they don't provide this information directly.

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  • How to override built-in getattr in Python?

    - by Stephen Gross
    I know how to override an object's getattr() to handle calls to undefined object functions. However, I would like to achieve the same behavior for the builtin getattr() function. For instance, consider code like this: call_some_undefined_function() Normally, that simply produces an error: Traceback (most recent call last): File "<stdin>", line 1, in <module> NameError: name 'call_some_undefined_function' is not defined I want to override getattr() so that I can intercept the call to "call_some_undefined_function()" and figure out what to do. Is this possible? Thanks, --Steve

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  • Sending http headers with python

    - by Niklas R
    I've set up a little script that should feed a client with html. import socket sock = socket.socket() sock.bind(('', 8080)) sock.listen(5) client, adress = sock.accept() print "Incoming:", adress print client.recv(1024) print client.send("Content-Type: text/html\n\n") client.send('<html><body></body></html>') print "Answering ..." print "Finished." import os os.system("pause") But it is shown as plain text in the browser. Can you please tell what I need to do ? I just can't find something in google that helps me.. Thanks.

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  • Python and urllib2: how to make a GET request with parameters

    - by Infinity
    I'm building an "API API", it basically a wrapper for a in house REST web service that the web app will be making a lot of requests to. Some of the web service calls need to be GET rather than post, but passing parameters. Is there a "best practice" way to encode a dictionary into a query string? e.g.: ?foo=bar&bla=blah I'm looking at the urllib2 docs, and it looks like it decides by itself wether to use POST or GET based on if you pass params or not, but maybe someone knows how to make it transform the params dictionary into a GET request. Maybe there's a package for something like this out there? It would be great if it supported keep-alive, as the web server will be constantly requesting things from the REST service. Thanks!

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  • Assign to a slice of a Python list from a lambda

    - by Bushman
    I know that there are certain "special" methods of various objects that represent operations that would normally be performed with operators (i.e. int.__add__ for +, object.__eq__ for ==, etc.), and that one of them is list.__setitem, which can assign a value to a list element. However, I need a function that can assign a list into a slice of another list. Basically, I'm looking for the expression equivalent of some_list[2:4] = [2, 3].

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  • Python: Problem Importing Function From Another Module

    - by Rafid K. Abdullah
    I have a module called nbemail.py and in this module I want to use the function package_post defined in the module main.py. I am using this statement: from api.main import package_post But I am getting this error: ImportError: cannot import name package_post I really don't know why I am getting this error! I do have _init_.py files in the api directory (which contains the files nbemail.py and main.py) and I do have the function package_post defined in main.py. Any idea to help fixing this problem?

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  • Python File Search Line And Return Specific Number of Lines after Match

    - by Simos Anderson
    I have a text file that has lines representing some data sets. The file itself is fairly long but it contains certain sections of the following format: Series_Name INFO Number of teams : n1 | Team | # | wins | | TeamName1 | x | y | . . . | TeamNamen1 | numn | numn | Some Irrelevant lines Series_Name2 INFO Number of teams : n1 | Team | # | wins | | TeamName1 | num1 | num2 | . where each section has a header that begins with the Series_Name. Each Series_Name is different. The line with the header also includes the number of teams in that series, n1. Following the header line is a set of lines that represents a table of data. For each series there are n1+1 rows in the table, where each row shows an individual team name and associated stats. I have been trying to implement a function that will allow the user to search for a Team name and then print out the line in the table associated with that team. However, certain team names show up under multiple series. To resolve this, I am currently trying to write my code so that the user can search for the header line with series name first and then print out just the following n1+1 lines that represent the data associated with the series. Here's what I have come up with so far: import re print fname = raw_input("Enter filename: ") seriesname = raw_input("Enter series: ") def findcounter(fname, seriesname): logfile = open(fname, "r") pat = 'INFO Number of teams :' for line in logfile: if seriesname in line: if pat in line: s=line pattern = re.compile(r"""(?P<name>.*?) #starting name \s*INFO #whitespace and success \s*Number\s*of\s*teams #whitespace and strings \s*\:\s*(?P<n1>.*)""",re.VERBOSE) match = pattern.match(s) name = match.group("name") n1 = int(match.group("n1")) print name + " has " + str(n1) + " teams" lcount = 0 for line in logfile: if line.startswith(name): if pat in line: while lcount <= n1: s.append(line) lcount += 1 return result The first part of my code works; it matches the header line that the person searches for, parses the line, and then prints out how many teams are in that series. Since the header line basically tells me how many lines are in the table, I thought that I could use that information to construct a loop that would continue printing each line until a set counter reached n1. But I've tried running it, and I realize that the way I've set it up so far isn't correct. So here's my question: How do you return a number of lines after a matched line when given the number of desired lines that follow the match? I'm new to programming, and I apologize if this question seems silly. I have been working on this quite diligently with no luck and would appreciate any help.

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