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  • XP can't read data from transferred HD

    - by Alexander Miller
    Computer A, running XP, died. XP was installed on a fresh HD in computer B. Slaved data-backup HD from A was installed as slave on B. B will not read it; shows only 2 folders, Recycler and System Volume Info. All of these are older machines with IDE drives. What's going on & how can I read/transfer the data from the transferred drive? This was only a trial run. Actually I will need to transfer the master HD from A - which has XP on it - and read from its data partition because (blush) the backup drive was not up to date.

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  • How to select parent row only if has at least one child?

    - by Matt McCormick
    I have a simple one-to-many relationship. I would like to select rows from the parent only when they have at least one child. So, if there are no children, then the parent row is not returned in the result set. Eg. Parent: +--+---------+ |id| text | +--+---------+ | 1| Blah | | 2| Blah2 | | 3| Blah3 | +--+---------+ Children +--+------+-------+ |id|parent| other | +--+------+-------+ | 1| 1 | blah | | 2| 1 | blah2 | | 3| 2 | blah3 | +--+------+-------+ I want the results to be: +----+------+ |p.id|p.text| +----+------+ | 1 | Blah | | 2 | Blah2| +----+------+

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  • SQL query to retrieve financial year data grouped by the year

    - by mlevit
    Hi, I have a database with lets assume two columns (service_date & invoice_amount). I would like to create an SQL query that would retrieve and group the data for each financial year (July to June). I have two years of data so that is two financial years (i.e. 2 results). I know I can do this manually by creating an SQL query to group by month then run the data through PHP to create the financial year data but I'd rather have an SQL query. All ideas welcome. Thanks

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  • [Ruby on Rails] Data Structure

    - by siulamvictor
    I am building a online form, with about 20 multiple choice checkboxes. I can get the nested data with this command. raise params.to_yaml I need to store these data and call them again later. I want to sort out which user chose which specific checkbox, i.e. who chose checkbox no.2? What's the best way to store these data in database?

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  • MySQL database query returns empty result

    - by user1791096
    I am doing a data migration and getting empty result of simple query with one join. Following is the query Select * from users u INNER JOIN temp_users tu ON tu.uid = u.uid There hundreds of records which have same uid in both tables, but this query returns only one record. Following is the structure of tables users table uid: varchar(50) utf8_general_ci Yes NULL temp_users table uid: varchar(50) utf8_general_ci Yes NULL Is there anyone who faced same problem?

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  • Data model for timesheet to task and/or timesheet to project?

    - by John
    Let's say I want to make a simple project tracking system. A manager can create a project. Then he can create tasks for that project. Team members can record the hours they work for each task or for the project as a whole. Is the following design for the t_timesheet table a good idea? timesheet_id - primary key, autoincrement project_id - not null, foreign key constraint to t_project task_id - nullable, foreign key constraint to t_task user_id - not null, foreign key constraint to t_user hours - decimal Or should I do something like this: timesheet_id - primary key, autoincrement task_id - not null, foreign key constraint to t_task user_id - not null, foreign key constraint to t_user hours - decimal In the second option, I intend to always have a record in t_task labelled "miscellaneous items" with a foreign key to the relevant t_project record. Then I'll be able to track all hours for a project that aren't for any particular task. Are any of the ideas above good? What would be better?

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  • PHP While Loops from Arrays

    - by Michael
    I have a table that contains members names and a field with multiple ID numbers. I want to create a query that returns results where any values in the ID fields overlap with any values in the array. For example: lastname: Smith firstname: John id: 101, 103 I have Array #1 with the values 101, 102, 103 I want the query to output all members who have the values 101 or 102 or 103 listed in their id field with multiple ids listed. Array ( [0] => 101 [1] => 102 [2] => 103 ) $sql="SELECT firstname, lastname, id FROM members WHERE id LIKE '%".$array_num_1."%'"; $result=mysql_query($sql); while ($rows=mysql_fetch_array($result)) { echo $rows['lastname'].', '.$rows['firstname'].'-'.$rows['id']; }

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  • mysqli real_escape_string problem

    - by tridat
    When im inserting to the database on my dev server the text goes in fine, for example "that's" is "that's" in the db. when uploading the exact same code to production server (hosted on a reseller account at bluehost) "that's" becomes "that\'s", im not double escaping, its exactly the same code, what could be the issue here?

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  • Is wikipedia a valuable resource for studying data structures? (can we call it complete?)

    - by Amir Nasr
    Can I depend on wikipedia to learn data structures fully using the list of data structures http://en.wikipedia.org/wiki/List_of_data_structures and the links they refer to? The same question for algorithms http://en.wikipedia.org/wiki/List_of_algorithm_general_topics ?... What's after learning algorithms and data structures? Specializing in a certain field of algorithms such as computer graohics, memory management...etc? or what could be the plan for mastering programming after knowing the language syntax and the background about program design and programming logic? I asked about wikipedia because i would like to find a complete resource or are least a resource which would be enough for the field of data structures instead of searching for separate articles in different places in other words an alternative to books which may even be more complete.

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  • How to use Insert .. select, with conditional vars from insert

    - by WmasterJ
    I have two separate tables both with user id columns uid. I want to take a value from all users in one table and insert it into the correct row for the correct user in the other table. INSERT INTO users2 (picture) SELECT pv.value FROM profile_values as pv, users2 as u WHERE pv.uid = u.uid AND pv.fid = 31 AND users2.uid=u.uid; But it's not working because i seem not to have access to users2.uid inside of the select statement. How would I accomplish this?

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  • MySQL error problem

    - by comma
    I keep getting the error listed below but it only says line 1 what does this mean and how do I fix it? Here is the error I keep getting? You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1 here is the code. if (isset($_POST['info_submitted'])) { $user_id = '5'; $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON learned_skills.id = users_skills.skill_id WHERE user_id='$user_id'"); $skill = $_POST['skill']; $experience = $_POST['experience']; $year = $_POST['year']; if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query1 = mysqli_query($mysqli,"INSERT INTO learned_skills (skill, experience, year) VALUES ('" . $skill . "', '" . $experience . "', '" . $year . "')"); } if (!mysqli_query($mysqli, $query1)) { print mysqli_error($mysqli); return; } $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT id FROM learned_skills WHERE id='" . $skill . "' AND experience='" . $experience . "' AND year='" . $year . "'"); if (!$dbc) { print mysqli_error($mysqli); } else { while($row = mysqli_fetch_array($dbc)){ $id = $row["id"]; } } $query2 = "INSERT INTO users_skills (skill_id, user_id, date_created) VALUES ('$id', '$user_id', NOW())"; if (!mysqli_query($mysqli, $query2)) { print mysqli_error($mysqli); return; } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE learned_skills JOIN users_skills ON (users_skills.skill_id = learned_skills.id) SET skill = '$skill', experience = '$experience', year = '$year'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { print mysqli_error($mysqli); return; } }

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  • adding a div with data()

    - by Dizzy Bryan High
    Hi people am generating a list of flash swfs, the information comes from an ajax call which returns a json object which i loop through to create the rows of data using my makeAppRow function. makeAppRow = function(myData){ var myStr = '<div class="fileEntry">' myStr = myStr +'<div class="appDate">'+dateFormat(myData.date_swf, "dS mmmm, yyyy, h:MM TT")+'</div>' myStr = myStr +'<div class="appName">'+myData.name_swf+'</div>' myStr = myStr +'<div class="appOptions" data>' myStr = myStr +'<div class="gotoAppBtn" data-options="'+myData+'">Open App</div>' myStr = myStr +'</div>' myStr = myStr +'</div>' $('#appData').append(myStr); } I need the json data to be attached to the gotoAppBtn so that when its clicked i can read in the data from the attached json object and use it in my click function, as you can see ive been trying to embed the data using the html5 data but i cant get it to work. <div class="gotoAppBtn" data-options="'+myData+'">Open App</div> i have a function so that when the button is clicked it loads in an swf. $('.gotoAppBtn').live('click', function(){ //alert('button clicked') var myData = $(this).data("options") alert('../userfiles/'+myData.id_ugp+'/'+myData.id_swf+'/'+myData.launchfile_swf+'') console.log(myData); var flashvars = {}; var params = {}; params.menu = "false"; params.quality = "best"; params.scale = "noscale"; var attributes = {}; attributes.id = "flashAppDisplay"; attributes.name = "flashAppDisplay"; swfobject.embedSWF( '../userfiles/'+myData.id_ugp+'/'+myData.id_swf+'/'+myData.launchfile_swf+'', 'flashAppDisplay', myData.width_swf, myData.height_swf, myData.version_swf ,"../FAVideo/expressInstall.swf", flashvars, params, attributes) }); but the data does not seem to be there, any pointers on where i am going wrong, or a better way to achive this???

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  • Squid - Logging to MySQL without empty rows/skipped records?

    - by Lee Ward
    I'm trying to figure out how to make Squid proxy log to MySQL. I know ACL order is pretty important but I'm not sure if I understand exactly what ACLs are or do, it's difficult to explain, but hopefully you'll see where I'm going with this as you read! I have created the lines to make Squid interact with a helper in squid.conf as follows: external_acl_type mysql_log %LOGIN %SRC %PROTO %URI php /etc/squid3/custom/mysql_lg.php acl ex_log external mysql_log http_access allow ex_log The external ACL helper (mysql_lg.php) is a PHP script and is as follows: error_reporting(0); if (! defined(STDIN)) { define("STDIN", fopen("php://stdin", "r")); } $res = mysql_connect('localhost', 'squid', 'testsquidpw'); $dbres = mysql_select_db('squid', $res); while (!feof(STDIN)) { $line = trim(fgets(STDIN)); $fields = explode(' ', $line); $user = rawurldecode($fields[0]); $cli_ip = rawurldecode($fields[1]); $protocol = rawurldecode($fields[2]); $uri = rawurldecode($fields[3]); $q = "INSERT INTO logs (id, user, cli_ip, protocol, url) VALUES ('', '".$user."', '".$cli_ip."', '".$protocol."', '".$uri."');"; mysql_query($q) or die (mysql_error()); if ($fault) { fwrite(STDOUT, "ERR\n"); }; fwrite(STDOUT, "OK\n"); } The configuration I have right now looks like this: ## Authentication Handler auth_param ntlm program /usr/bin/ntlm_auth --helper-protocol=squid-2.5-ntlmssp auth_param ntlm children 30 auth_param negotiate program /usr/bin/ntlm_auth --helper-protocol=squid-2.5-basic auth_param negotiate children 5 # Allow squid to update log external_acl_type mysql_log %LOGIN %SRC %PROTO %URI php /etc/squid3/custom/mysql_lg.php acl ex_log external mysql_log http_access allow ex_log acl localnet src 172.16.45.0/24 acl AuthorizedUsers proxy_auth REQUIRED acl SSL_ports port 443 acl Safe_ports port 80 # http acl Safe_ports port 21 # ftp acl Safe_ports port 443 # https acl CONNECT method CONNECT acl blockeddomain url_regex "/etc/squid3/bl.acl" http_access deny blockeddomain deny_info ERR_BAD_GENERAL blockeddomain # Deny requests to certain unsafe ports http_access deny !Safe_ports # Deny CONNECT to other than secure SSL ports http_access deny CONNECT !SSL_ports # Allow the internal network access to this proxy http_access allow localnet # Allow authorized users access to this proxy http_access allow AuthorizedUsers # FINAL RULE - Deny all other access to this proxy http_access deny all From testing, the closer to the bottom I place the logging lines the less it logs. Oftentimes, it even places empty rows in to the MySQL table. The file-based logs in /var/log/squid3/access.log are correct but many of the rows in the access logs are missing from the MySQL logs. I can't help but think it's down to the order I'm putting lines in because I want to log everything to MySQL, unauthenticated requests, blocked requests, which category blocked a specific request. The reason I want this in MySQL is because I'm trying to have everything managed via a custom web-based frontend and want to avoid using any shell commands and access to system log files if I can help it. The end result is to make it as easy as possible to maintain without keeping staff waiting on the phone whilst I add a new rule and reload the server! Hopefully someone can help me out here because this is very much a learning experience for me and I'm pretty stumped. Many thanks in advance for any help!

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  • How to get count of another table in a left join

    - by Sinan
    I have multiple tables post id Name 1 post-name1 2 post-name2 user id username 1 user1 2 user2 post_user post_id user_id 1 1 2 1 post_comments post_id comment_id 1 1 1 2 1 3 I am using a query like this: SELECT post.id, post.title, user.id AS uid, username FROM `post` LEFT JOIN post_user ON post.id = post_user.post_id LEFT JOIN user ON user.id = post_user.user_id ORDER BY post_date DESC It works as intended. However I would like the get the number of comments for each post too. So how can i modify the this query so I can get the count of comments. Any ideas?

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  • How can be data oriented programming applied for GUI system?

    - by Miro
    I've just learned basics of Data oriented programming design, but I'm not very familiar with that yet. I've also read Pitfalls of Object Oriented Programming GCAP 09. It seems that data oriented programming is much better idea for games, than OOP. I'm just creating my own GUI system and it's completely OOP. I'm thinking if is data oriented programming design applicable for structured things like GUI. The main problem I see is that every type widget has different data, so I can hardly group them into arrays. Also every type of widget renders differently so I still need to call virtual functions.

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  • Invalid SQL Query

    - by svovaf
    I have the next query that in my opinion is a valid one, but I keep getting error telling me that there is a proble on "WHERE em.p4 = ue.p3" - Unknown column 'ue.p3' in 'where clause'. This is the query: SELECT DISTINCT ue.p3 FROM table1 AS ue INNER JOIN table2 AS e ON ue.p3 = e.p3 WHERE EXISTS( SELECT 1 FROM ( SELECT (COUNT(*) >= 1) AS MinMutual FROM table4 AS smm WHERE smm.p1 IN ( SELECT sem.p3 FROM table3 AS sem INNER JOIN table2 AS em ON sem.p3 = em.p3 WHERE em.p4 = ue.p3 AND sem.type = 'friends' AND em.p2 = 'normal' ) AND smm.p5 IN ( 15000,15151 ) ) AS Mutual WHERE Mutual.MinMutual = TRUE) LIMIT 11 If I execute the sub-query which is inside the EXISTS function, everything is O.K. PLEASE HELP!

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  • Get current updated column name to use in a trigger

    - by Serge
    Is there a way to actually get the column name that was updated in order to use it in a trigger? Basically I'm trying to have an audit trail whenever a user inserts or updates a table (in this case it has to do with a Contact table) CREATE TRIGGER `after_update_contact` AFTER UPDATE ON `contact` FOR EACH ROW BEGIN INSERT INTO user_audit (id_user, even_date, table_name, record_id, field_name, old_value, new_value) VALUES (NEW.updatedby, NEW.lastUpdate, 'contact', NEW.id_contact, [...]) END How can I get the name of the column that's been updated and from that get the OLD and NEW values of that column. If multiple columns have been updated in a row or even multiple rows would it be possible to have an audit for each update?

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  • (mySQL) Unable to query 2 tables properly for data

    - by Devner
    I have 2 tables. One is 'page_links' and the other is 'rpp'. Table page_links is the superset of table rpp. The following is the schema of my tables: -- Table structure for table `page_links` -- CREATE TABLE IF NOT EXISTS `page_links` ( `page` varchar(255) NOT NULL, `page_link` varchar(100) NOT NULL, `heading_id` tinyint(3) unsigned NOT NULL, PRIMARY KEY (`page`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; -- -- Dumping data for table `page_links` -- INSERT INTO `page_links` (`page`, `page_link`, `heading_id`) VALUES ('a1.php', 'A1', 8), ('b1.php', 'B1', 8), ('c1.php', 'C1', 5), ('d1.php', 'D1', 5), ('e1.php', 'E1', 8), ('f1.php', 'F1', 8), ('g1.php', 'G1', 8), ('h1.php', 'H1', 1), ('i1.php', 'I1', 1), ('j1.php', 'J1', 8), ('k1.php', 'K1', 8), ('l1.php', 'L1', 8), ('m1.php', 'M1', 8), ('n1.php', 'N1', 8), ('o1.php', 'O1', 8), ('p1.php', 'P1', 4), ('q1.php', 'Q1', 5), ('r1.php', 'R1', 4); -- Table structure for table `rpp` -- CREATE TABLE IF NOT EXISTS `rpp` ( `role_id` tinyint(3) unsigned NOT NULL, `page` varchar(255) NOT NULL, `is_allowed` tinyint(1) NOT NULL, PRIMARY KEY (`role_id`,`page`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; -- -- Dumping data for table `rpp` -- INSERT INTO `rpp` (`role_id`, `page`, `is_allowed`) VALUES (3, 'a1.php', 1), (3, 'b1.php', 1), (3, 'c1.php', 1), (3, 'd1.php', 1), (3, 'e1.php', 1), (3, 'f1.php', 1), (3, 'h1.php', 1), (3, 'i1.php', 1), (3, 'l1.php', 1), (3, 'm1.php', 1), (3, 'n1.php', 1), (4, 'a1.php', 1), (4, 'b1.php', 1), (4, 'q1.php', 1), (5, 'r1.php', 1); WHAT I AM TRYING TO DO: I am trying to query both the above tables (in a single query) in such a way that all the pages from page_links are displayed along with the is_allowed value from rpp for a particular role. For example, I want to get the is_allowed value of all the pages from rpp for role_id = 3 and at the same time, list all the available pages from page_links. A clear example of my expected result would be: page is_allowed role_id ---------------------------------------- a1.php 1 3 b1.php 1 3 c1.php 1 3 d1.php 1 3 e1.php 1 3 f1.php 1 3 g1.php NULL NULL h1.php 1 3 i1.php 1 3 j1.php NULL NULL k1.php NULL NULL l1.php 1 3 m1.php 1 3 n1.php 1 3 o1.php NULL NULL p1.php NULL NULL q1.php NULL NULL r1.php NULL NULL One more example of my desired result could be achieved by doing a LEFT JOIN rpp ON page_links.page = rpp.page but we need to omit using role_id = 3 (or any value) to be able to get that. But I do want to specify the role_id as well and get the results. I need the query to be able to get this result. I would appreciate any replies that could help me with this. If you can suggest me any changes as well to the table(s) design to be able to achieve the desired result, that's good as well. Thanks in advance.

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  • connecting to phpMyAdmin database with PHP/MySQL

    - by user303955
    I've made a database using phpMyAdmin , now I want to make a register form for my site where peaple can register .I know how to work with input tags in HTML and I know how to insert data into a database but my problem is that I don't know how I can connect to the database that is already made in phpMyAdmin.

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  • Killing Mysql processes staying in sleep command.

    - by Shino88
    Hey I am connecting a MYSQL database through hibernate and i seem to have processes that are not being killed after they are finished in the session. I have called flush and close on each session but when i check the server the last processes are still there with a sleep command. This is a new problem which i am having and was not the case yesterday. Is there any way i can ensure the killng of theses processes when i am done with a session. Below is an example of one of my classes. public JSONObject check() { //creates a new session needed to add elements to a database Session session = null; //holds the result of the check in the database JSONObject check = new JSONObject(); try{ //creates a new session needed to add elements to a database SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory(); session = sessionFactory.openSession(); if (justusername){ //query created to select a username from user table String hquery = "Select username from User user Where username = ? "; //query created Query query = session.createQuery(hquery); //sets the username of the query the values JSONObject contents query.setString(0, username); // executes query and adds username string variable String user = (String) query.uniqueResult(); //checks to see if result is found (null if not found) if (user == null) { //adds false to Jobject if not found check.put("indatabase", "false"); } else { check.put("indatabase", "true"); } //adds check to Jobject to say just to check username check.put("justusername", true); } else { //query created to select a username and password from user table String hquery = "Select username from User user Where username = :user and password = :pass "; Query query = session.createQuery(hquery); query.setString("user", username); query.setString("pass", password); String user = (String) query.uniqueResult(); if(user ==null) { check.put("indatabase", false); } else { check.put("indatabase", true); } check.put("justusername", false); } }catch(Exception e){ System.out.println(e.getMessage()); //logg.log(Level.WARNING, " Exception", e.getMessage()); }finally{ // Actual contact insertion will happen at this step session.flush(); session.close(); } //returns Jobject return check; }

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  • Optimising (My)SQL Query

    - by Simon
    I usually use ORM instead of SQL and I am slightly out of touch on the different JOINs... SELECT `order_invoice`.*, `client`.*, `order_product`.*, SUM(product.cost) as net FROM `order_invoice` LEFT JOIN `client` ON order_invoice.client_id = client.client_id LEFT JOIN `order_product` ON order_invoice.invoice_id = order_product.invoice_id LEFT JOIN `product` ON order_product.product_id = product.product_id WHERE (order_invoice.date_created >= '2009-01-01') AND (order_invoice.date_created <= '2009-02-01') GROUP BY `order_invoice`.`invoice_id` The tables/ columns are logically names... it's an shop type application... the query works... it's just very very slow... I use the Zend Framework and would usually use Zend_Db_Table_Row::find(Parent|Dependent)Row(set)('TableClass') but I have to make lots of joins and I thought it'll improve performance by doing it all in one query instead of hundreds... Can I improve the above query by using more appropriate JOINs or a different implementation? Many thanks.

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