Search Results

Search found 5180 results on 208 pages for 'binary serialization'.

Page 18/208 | < Previous Page | 14 15 16 17 18 19 20 21 22 23 24 25  | Next Page >

  • efficient video format/codec for sparse & binary blob tracking

    - by user391339
    I am working on a blob tracking project and have many high-definition videos that I would like to reduce in size for storage and downstream tracking/shape-analysis. I want to use a lossless method that takes advantage of the black and white nature of the video as well as the fact that not much is moving between individual frames. The videos are quite sparse, with 5 to 10 b&w blobs per frame occupying <30% of the space in total, with each blob moving <5-10% of the field of view between frames and not changing shape too much between 2-3 frames. I will work in Python, Matlab, or LabView for this project, and could use a batch utility if available. It may be worthwhile to export the files as compressed image stacks if a proper video format can't be found. What are the pros and cons of this? A video codec uses correlations between neighboring frames, so it should be more efficient, but not if the wrong one is chosen or if it is improperly configured.

    Read the article

  • Binary Search Tree can't delete the root

    - by Ali Zahr
    Everything is working fine in this function, but the problem is that I can't delete the root, I couldn't figure out what's the bug here.I've traced the "else part" it works fine until the return, it returns the old value I don't know why. Plz Help! node *removeNode(node *Root, int key) { node *tmp = new node; if(key > Root->value) Root->right = removeNode(Root->right,key); else if(key < Root->value) Root->left = removeNode(Root->left, key); else if(Root->left != NULL && Root->right != NULL) { node *minNode = findNode(Root->right); Root->value = minNode->value; Root->right = removeNode(Root->right,Root->value); } else { tmp = Root; if(Root->left == NULL) Root = Root->right; else if(Root->right == NULL) Root = Root->left; delete tmp; } return Root; }

    Read the article

  • Better way to download a binary file?

    - by geoff
    I have a site where a user can download a file. Some files are extremely large (the largest being 323 MB). When I test it to try and download this file I get an out of memory exception. The only way I know to download the file is below. The reason I'm using the code below is because the URL is encoded and I can't let the user link directly to the file. Is there another way to download this file without having to read the whole thing into a byte array? FileStream fs = new FileStream(context.Server.MapPath(url), FileMode.Open, FileAccess.Read); BinaryReader br = new BinaryReader(fs); long numBytes = new FileInfo(context.Server.MapPath(url)).Length; byte[] bytes = br.ReadBytes((int) numBytes); string filename = Path.GetFileName(url); context.Response.Buffer = true; context.Response.Charset = ""; context.Response.Cache.SetCacheability(HttpCacheability.NoCache); context.Response.ContentType = "application/x-rar-compressed"; context.Response.AddHeader("content-disposition", "attachment;filename=" + filename); context.Response.BinaryWrite(bytes); context.Response.Flush(); context.Response.End();

    Read the article

  • How many posibilities on a binary ?

    - by Val
    in hexadecimal "10 10 10 10" system you have 0-255 posibilities right? in total 256 different posibilities as there are 8 1s and 0s. how many different posibilities would i get? if i had 10 digits. instead of 8? or how would i calculate that in php ?

    Read the article

  • Problems in Binary Search Tree

    - by user2782324
    This is my first ever trial at implementing the BST, and I am unable to get it done. Please help The problem is that When I delete the node if the node is in the right subtree from the root or if its a right child in the left subtree, then it works fine. But if the node is in the left subtree from root and its any left child, then it does not get deleted. Can someone show me what mistake am I doing?? the markedNode here gets allocated to the parent node of the node to be deleted. the minValueNode here gets allocated to a node whose left value child is the smallest value and it will be used to replace the value to be deleted. package DataStructures; class Node { int value; Node rightNode; Node leftNode; } class BST { Node rootOfTree = null; public void insertintoBST(int value) { Node markedNode = rootOfTree; if (rootOfTree == null) { Node newNode = new Node(); newNode.value = value; rootOfTree = newNode; newNode.rightNode = null; newNode.leftNode = null; } else { while (true) { if (value >= markedNode.value) { if (markedNode.rightNode != null) { markedNode = markedNode.rightNode; } else { Node newNode = new Node(); newNode.value = value; markedNode.rightNode = newNode; newNode.rightNode = null; newNode.leftNode = null; break; } } if (value < markedNode.value) { if (markedNode.leftNode != null) { markedNode = markedNode.leftNode; } else { Node newNode = new Node(); newNode.value = value; markedNode.leftNode = newNode; newNode.rightNode = null; newNode.leftNode = null; break; } } } } } public void searchBST(int value) { Node markedNode = rootOfTree; if (rootOfTree == null) { System.out.println("Element Not Found"); } else { while (true) { if (value > markedNode.value) { if (markedNode.rightNode != null) { markedNode = markedNode.rightNode; } else { System.out.println("Element Not Found"); break; } } if (value < markedNode.value) { if (markedNode.leftNode != null) { markedNode = markedNode.leftNode; } else { System.out.println("Element Not Found"); break; } } if (value == markedNode.value) { System.out.println("Element Found"); break; } } } } public void deleteFromBST(int value) { Node markedNode = rootOfTree; Node minValueNode = null; if (rootOfTree == null) { System.out.println("Element Not Found"); return; } if (rootOfTree.value == value) { if (rootOfTree.leftNode == null && rootOfTree.rightNode == null) { rootOfTree = null; return; } else if (rootOfTree.leftNode == null ^ rootOfTree.rightNode == null) { if (rootOfTree.rightNode != null) { rootOfTree = rootOfTree.rightNode; return; } else { rootOfTree = rootOfTree.leftNode; return; } } else { minValueNode = rootOfTree.rightNode; if (minValueNode.leftNode == null) { rootOfTree.rightNode.leftNode = rootOfTree.leftNode; rootOfTree = rootOfTree.rightNode; } else { while (true) { if (minValueNode.leftNode.leftNode != null) { minValueNode = minValueNode.leftNode; } else { break; } } // Minvalue to the left of minvalue node rootOfTree.value = minValueNode.leftNode.value; // The value has been swapped if (minValueNode.leftNode.leftNode == null && minValueNode.leftNode.rightNode == null) { minValueNode.leftNode = null; } else { if (minValueNode.leftNode.leftNode != null) { minValueNode.leftNode = minValueNode.leftNode.leftNode; } else { minValueNode.leftNode = minValueNode.leftNode.rightNode; } // Minvalue deleted } } } } else { while (true) { if (value > markedNode.value) { if (markedNode.rightNode != null) { if (markedNode.rightNode.value == value) { break; } else { markedNode = markedNode.rightNode; } } else { System.out.println("Element Not Found"); return; } } if (value < markedNode.value) { if (markedNode.leftNode != null) { if (markedNode.leftNode.value == value) { break; } else { markedNode = markedNode.leftNode; } } else { System.out.println("Element Not Found"); return; } } } // Parent of the required element found // //////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////// if (markedNode.rightNode != null) { if (markedNode.rightNode.value == value) { if (markedNode.rightNode.rightNode == null && markedNode.rightNode.leftNode == null) { markedNode.rightNode = null; return; } else if (markedNode.rightNode.rightNode == null ^ markedNode.rightNode.leftNode == null) { if (markedNode.rightNode.rightNode != null) { markedNode.rightNode = markedNode.rightNode.rightNode; return; } else { markedNode.rightNode = markedNode.rightNode.leftNode; return; } } else { if (markedNode.rightNode.value == value) { minValueNode = markedNode.rightNode.rightNode; } else { minValueNode = markedNode.leftNode.rightNode; } if (minValueNode.leftNode == null) { // MinNode has no left value markedNode.rightNode = minValueNode; return; } else { while (true) { if (minValueNode.leftNode.leftNode != null) { minValueNode = minValueNode.leftNode; } else { break; } } // Minvalue to the left of minvalue node if (markedNode.leftNode != null) { if (markedNode.leftNode.value == value) { markedNode.leftNode.value = minValueNode.leftNode.value; } } if (markedNode.rightNode != null) { if (markedNode.rightNode.value == value) { markedNode.rightNode.value = minValueNode.leftNode.value; } } // MarkedNode exchanged if (minValueNode.leftNode.leftNode == null && minValueNode.leftNode.rightNode == null) { minValueNode.leftNode = null; } else { if (minValueNode.leftNode.leftNode != null) { minValueNode.leftNode = minValueNode.leftNode.leftNode; } else { minValueNode.leftNode = minValueNode.leftNode.rightNode; } // Minvalue deleted } } } // //////////////////////////////////////////////////////////////////////////////////////////////////////////////// if (markedNode.leftNode != null) { if (markedNode.leftNode.value == value) { if (markedNode.leftNode.rightNode == null && markedNode.leftNode.leftNode == null) { markedNode.leftNode = null; return; } else if (markedNode.leftNode.rightNode == null ^ markedNode.leftNode.leftNode == null) { if (markedNode.leftNode.rightNode != null) { markedNode.leftNode = markedNode.leftNode.rightNode; return; } else { markedNode.leftNode = markedNode.leftNode.leftNode; return; } } else { if (markedNode.rightNode.value == value) { minValueNode = markedNode.rightNode.rightNode; } else { minValueNode = markedNode.leftNode.rightNode; } if (minValueNode.leftNode == null) { // MinNode has no left value markedNode.leftNode = minValueNode; return; } else { while (true) { if (minValueNode.leftNode.leftNode != null) { minValueNode = minValueNode.leftNode; } else { break; } } // Minvalue to the left of minvalue node if (markedNode.leftNode != null) { if (markedNode.leftNode.value == value) { markedNode.leftNode.value = minValueNode.leftNode.value; } } if (markedNode.rightNode != null) { if (markedNode.rightNode.value == value) { markedNode.rightNode.value = minValueNode.leftNode.value; } } // MarkedNode exchanged if (minValueNode.leftNode.leftNode == null && minValueNode.leftNode.rightNode == null) { minValueNode.leftNode = null; } else { if (minValueNode.leftNode.leftNode != null) { minValueNode.leftNode = minValueNode.leftNode.leftNode; } else { minValueNode.leftNode = minValueNode.leftNode.rightNode; } // Minvalue deleted } } } } // //////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////// } } } } } } public class BSTImplementation { public static void main(String[] args) { BST newBst = new BST(); newBst.insertintoBST(19); newBst.insertintoBST(13); newBst.insertintoBST(10); newBst.insertintoBST(20); newBst.insertintoBST(5); newBst.insertintoBST(23); newBst.insertintoBST(28); newBst.insertintoBST(16); newBst.insertintoBST(27); newBst.insertintoBST(9); newBst.insertintoBST(4); newBst.insertintoBST(22); newBst.insertintoBST(17); newBst.insertintoBST(30); newBst.insertintoBST(40); newBst.deleteFromBST(5); newBst.deleteFromBST(4); newBst.deleteFromBST(9); newBst.deleteFromBST(10); newBst.deleteFromBST(13); newBst.deleteFromBST(16); newBst.deleteFromBST(17); newBst.searchBST(5); newBst.searchBST(4); newBst.searchBST(9); newBst.searchBST(10); newBst.searchBST(13); newBst.searchBST(16); newBst.searchBST(17); System.out.println(); newBst.deleteFromBST(20); newBst.deleteFromBST(23); newBst.deleteFromBST(27); newBst.deleteFromBST(28); newBst.deleteFromBST(30); newBst.deleteFromBST(40); newBst.searchBST(20); newBst.searchBST(23); newBst.searchBST(27); newBst.searchBST(28); newBst.searchBST(30); newBst.searchBST(40); } }

    Read the article

  • SerializationException Occurring Only in Release Mode

    - by Calvin Nguyen
    Hi, I am working on an ASP.NET web app using Visual Studio 2008 and a third-party library. Things are fine in my development environment. Things are also good if the web app is deployed in Debug configuration. However, when it is deployed in Release mode, SerializationExceptions appear intermittently, breaking other functionality. In the Windows event log, the following error can be seen: "An unhandled exception occurred and the process was terminated. Application ID: DefaultDomain Process ID: 3972 Exception: System.Runtime.Serialization.SerializationException Message: Unable to find assembly 'MyThirdPartyLibrary, Version=1.234.5.67, Culture=neutral, PublicKeyToken=3d67ed1f87d44c89'. StackTrace: at System.Runtime.Serialization.Formatters.Binary.BinaryAssemblyInfo.GetAssembly( ) at System.Runtime.Serialization.Formatters.Binary.ObjectReader.GetType(BinaryAsse mblyInfo assemblyInfo, String name) at System.Runtime.Serialization.Formatters.Binary.ObjectMap..ctor(String objectName, String[] memberNames, BinaryTypeEnum[] binaryTypeEnumA, Object[] typeInformationA, Int32[] memberAssemIds, ObjectReader objectReader, Int32 objectId, BinaryAssemblyInfo assemblyInfo, SizedArray assemIdToAssemblyTable) at System.Runtime.Serialization.Formatters.Binary.ObjectMap.Create(String name, String[] memberNames, BinaryTypeEnum[] binaryTypeEnumA, Object[] typeInformationA, Int32[] memberAssemIds, ObjectReader objectReader, Int32 objectId, BinaryAssemblyInfo assemblyInfo, SizedArray assemIdToAssemblyTable) at System.Runtime.Serialization.Formatters.Binary._BinaryParser.ReadObjectWithMa pTyped(BinaryObjectWithMapTyped record) at System.Runtime.Serialization.Formatters.Binary._BinaryParser.ReadObjectWithMa pTyped(BinaryHeaderEnum binaryHeaderEnum) at System.Runtime.Serialization.Formatters.Binary.__BinaryParser.Run() at System.Runtime.Serialization.Formatters.Binary.ObjectReader.Deserialize(Header Handler handler, __BinaryParser serParser, Boolean fCheck, Boolean isCrossAppDomain, IMethodCallMessage methodCallMessage) at System.Runtime.Serialization.Formatters.Binary.BinaryFormatter.Deserialize(Str eam serializationStream, HeaderHandler handler, Boolean fCheck, Boolean isCrossAppDomain, IMethodCallMessage methodCallMessage) at System.Runtime.Remoting.Channels.CrossAppDomainSerializer.DeserializeObject(Me moryStream stm) at System.AppDomain.Deserialize(Byte[] blob) at System.AppDomain.UnmarshalObject(Byte[] blob) For more information, see Help and Support Center at http://go.microsoft.com/fwlink/events.asp." Using FUSLOGVW.exe (i.e., Assembly Binding Log Viewer), I can see the problem is that IIS attempts to find MyThirdPartyLibrary in directory C:\windows\system32\inetsrv. It refuses to look in the bin folder of the web app, where the DLL is actually located. Does anyone know what the problem is? Thanks, Calvin

    Read the article

  • Command to find the source package of a binary?

    - by Delan Azabani
    I know there's a which command, that echoes the full name of a binary (e.g. which sh). However, I'm fairly sure there's a command that echoes the package that provides a particular binary. Is there such a command? If so, what is it? I'd like to be able to run this: commandName ls and get coreutils for example.

    Read the article

  • --log-slave-updates is OFF but updates received from master are still logged to slave binary log?

    - by quanta
    MySQL version 5.5.14 According to the document, by the default, slave does not log to its binary log any updates that are received from a master server. Here are my config. on the slave: # egrep 'bin|slave' /etc/my.cnf relay-log=mysqld-relay-bin log-bin = /var/log/mysql/mysql-bin binlog-format=MIXED sync_binlog = 1 log-bin-trust-function-creators = 1 mysql> show global variables like 'log_slave%'; +-------------------+-------+ | Variable_name | Value | +-------------------+-------+ | log_slave_updates | OFF | +-------------------+-------+ 1 row in set (0.01 sec) mysql> select @@log_slave_updates; +---------------------+ | @@log_slave_updates | +---------------------+ | 0 | +---------------------+ 1 row in set (0.00 sec) but slave still logs the updates that are received from a master to its binary logs, let's see the file size: -rw-rw---- 1 mysql mysql 37M Apr 1 01:00 /var/log/mysql/mysql-bin.001256 -rw-rw---- 1 mysql mysql 25M Apr 2 01:00 /var/log/mysql/mysql-bin.001257 -rw-rw---- 1 mysql mysql 46M Apr 3 01:00 /var/log/mysql/mysql-bin.001258 -rw-rw---- 1 mysql mysql 115M Apr 4 01:00 /var/log/mysql/mysql-bin.001259 -rw-rw---- 1 mysql mysql 105M Apr 4 18:54 /var/log/mysql/mysql-bin.001260 and the sample query when reading these binary files with mysqlbinlog utility: #120404 19:08:57 server id 3 end_log_pos 110324763 Query thread_id=382435 exec_time=0 error_code=0 SET TIMESTAMP=1333541337/*!*/; INSERT INTO norep_SplitValues VALUES ( NAME_CONST('cur_string',_utf8'118212' COLLATE 'utf8_general_ci')) /*!*/; # at 110324763 Did I miss something?

    Read the article

  • Xml Serialization and the [Obsolete] Attribute

    - by PSteele
    I learned something new today: Starting with .NET 3.5, the XmlSerializer no longer serializes properties that are marked with the Obsolete attribute.  I can’t say that I really agree with this.  Marking something Obsolete is supposed to be something for a developer to deal with in source code.  Once an object is serialized to XML, it becomes data.  I think using the Obsolete attribute as both a compiler flag as well as controlling XML serialization is a bad idea. In this post, I’ll show you how I ran into this and how I got around it. The Setup Let’s start with some make-believe code to demonstrate the issue.  We have a simple data class for storing some information.  We use XML serialization to read and write the data: public class MyData { public int Age { get; set; } public string FirstName { get; set; } public string LastName { get; set; } public List<String> Hobbies { get; set; }   public MyData() { this.Hobbies = new List<string>(); } } Now a few simple lines of code to serialize it to XML: static void Main(string[] args) { var data = new MyData {    FirstName = "Zachary", LastName = "Smith", Age = 50, Hobbies = {"Mischief", "Sabotage"}, }; var serializer = new XmlSerializer(typeof (MyData)); serializer.Serialize(Console.Out, data); Console.ReadKey(); } And this is what we see on the console: <?xml version="1.0" encoding="IBM437"?> <MyData xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Age>50</Age> <FirstName>Zachary</FirstName> <LastName>Smith</LastName> <Hobbies> <string>Mischief</string> <string>Sabotage</string> </Hobbies> </MyData>   The Change So we decided to track the hobbies as a list of strings.  As always, things change and we have more information we need to store per-hobby.  We create a custom “Hobby” object, add a List<Hobby> to our MyData class and we obsolete the old “Hobbies” list to let developers know they shouldn’t use it going forward: public class Hobby { public string Name { get; set; } public int Frequency { get; set; } public int TimesCaught { get; set; }   public override string ToString() { return this.Name; } } public class MyData { public int Age { get; set; } public string FirstName { get; set; } public string LastName { get; set; } [Obsolete("Use HobbyData collection instead.")] public List<String> Hobbies { get; set; } public List<Hobby> HobbyData { get; set; }   public MyData() { this.Hobbies = new List<string>(); this.HobbyData = new List<Hobby>(); } } Here’s the kicker: This serialization is done in another application.  The consumers of the XML will be older clients (clients that expect only a “Hobbies” collection) as well as newer clients (that support the new “HobbyData” collection).  This really shouldn’t be a problem – the obsolete attribute is metadata for .NET compilers.  Unfortunately, the XmlSerializer also looks at the compiler attribute to determine what items to serialize/deserialize.  Here’s an example of our problem: static void Main(string[] args) { var xml = @"<?xml version=""1.0"" encoding=""IBM437""?> <MyData xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema""> <Age>50</Age> <FirstName>Zachary</FirstName> <LastName>Smith</LastName> <Hobbies> <string>Mischief</string> <string>Sabotage</string> </Hobbies> </MyData>"; var serializer = new XmlSerializer(typeof(MyData)); var stream = new StringReader(xml); var data = (MyData) serializer.Deserialize(stream);   if( data.Hobbies.Count != 2) { throw new ApplicationException("Hobbies did not deserialize properly"); } } If you run the code above, you’ll hit the exception.  Even though the XML contains a “<Hobbies>” node, the obsolete attribute prevents the node from being processed.  This will break old clients that use the new library, but don’t yet access the HobbyData collection. The Fix This fix (in this case), isn’t too painful.  The XmlSerializer exposes events for times when it runs into items (Elements, Attributes, Nodes, etc…) it doesn’t know what to do with.  We can hook in to those events and check and see if we’re getting something that we want to support (like our “Hobbies” node). Here’s a way to read in the old XML data with full support of the new data structure (and keeping the Hobbies collection marked as obsolete): static void Main(string[] args) { var xml = @"<?xml version=""1.0"" encoding=""IBM437""?> <MyData xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema""> <Age>50</Age> <FirstName>Zachary</FirstName> <LastName>Smith</LastName> <Hobbies> <string>Mischief</string> <string>Sabotage</string> </Hobbies> </MyData>"; var serializer = new XmlSerializer(typeof(MyData)); serializer.UnknownElement += serializer_UnknownElement; var stream = new StringReader(xml); var data = (MyData)serializer.Deserialize(stream);   if (data.Hobbies.Count != 2) { throw new ApplicationException("Hobbies did not deserialize properly"); } }   static void serializer_UnknownElement(object sender, XmlElementEventArgs e) { if( e.Element.Name != "Hobbies") { return; }   var target = (MyData) e.ObjectBeingDeserialized; foreach(XmlElement hobby in e.Element.ChildNodes) { target.Hobbies.Add(hobby.InnerText); target.HobbyData.Add(new Hobby{Name = hobby.InnerText}); } } As you can see, we hook in to the “UnknownElement” event.  Once we determine it’s our “Hobbies” node, we deserialize it ourselves – as well as populating the new HobbyData collection.  In this case, we have a fairly simple solution to a small change in XML layout.  If you make more extensive changes, it would probably be easier to do some custom serialization to support older data. A sample project with all of this code is available from my repository on bitbucket. Technorati Tags: XmlSerializer,Obsolete,.NET

    Read the article

  • Understanding Application binary interface (ABI)

    - by Tim
    I am trying to understand the concept of Application binary interface (ABI). From The Linux Kernel Primer: An ABI is a set of conventions that allows a linker to combine separately compiled modules into one unit without recompilation, such as calling conventions, machine interface, and operating-system interface. Among other things, an ABI defines the binary interface between these units. ... The benefits of conforming to an ABI are that it allows linking object files compiled by different compilers. From Wikipedia: an application binary interface (ABI) describes the low-level interface between an application (or any type of) program and the operating system or another application. ABIs cover details such as data type, size, and alignment; the calling convention, which controls how functions' arguments are passed and return values retrieved; the system call numbers and how an application should make system calls to the operating system; and in the case of a complete operating system ABI, the binary format of object files, program libraries and so on. I was wondering whether ABI depends on both the instruction set and the OS. Are the two all that ABI depends on? What kinds of role does ABI play in different stages of compilation: preprocessing, conversion of code from C to Assembly, conversion of code from Assembly to Machine code, and linking? From the first quote above, it seems to me that ABI is needed for only linking stage, not the other stages. Is it correct? When is ABI needed to be considered? Is ABI needed to be considered during programming in C, Assembly or other languages? If yes, how are ABI and API different? Or is it only for linker or compiler? Is ABI specified for/in machine code, Assembly language, and/or of C?

    Read the article

  • communication between 2 programs written in different language - Serialization ?

    - by trojanwarrior3000
    when is serialization,marshaling etc required during communication between programs residing across 2 different machines /network/Internet? Suppose I have a client program in java/flash and a server program in C. Can't I implement communication using a custom protocol of my own ? I guess so. When is serialization etc needed?I am aware Java RMI,CORBA etc have these mechanisms. But why? Is it a must? please enlighten me?

    Read the article

  • If you use XML Serialization how do you validate data?

    - by chobo2
    Hi I am planning to try to use XML Serialization in C# but I am wondering if I get a .xml file how do I check if the xml file confirms to the right type? Like usually you would make a schema that you can validate against to make sure if it confirms to the right format. Can you hook a schema up to to XML Serialization or does it do this checking automatically? Thanks

    Read the article

  • Collaborative Whiteboard using WebSocket in GlassFish 4 - Text/JSON and Binary/ArrayBuffer Data Transfer (TOTD #189)

    - by arungupta
    This blog has published a few blogs on using JSR 356 Reference Implementation (Tyrus) as its integrated in GlassFish 4 promoted builds. TOTD #183: Getting Started with WebSocket in GlassFish TOTD #184: Logging WebSocket Frames using Chrome Developer Tools, Net-internals and Wireshark TOTD #185: Processing Text and Binary (Blob, ArrayBuffer, ArrayBufferView) Payload in WebSocket TOTD #186: Custom Text and Binary Payloads using WebSocket One of the typical usecase for WebSocket is online collaborative games. This Tip Of The Day (TOTD) explains a sample that can be used to build such games easily. The application is a collaborative whiteboard where different shapes can be drawn in multiple colors. The shapes drawn on one browser are automatically drawn on all other peer browsers that are connected to the same endpoint. The shape, color, and coordinates of the image are transfered using a JSON structure. A browser may opt-out of sharing the figures. Alternatively any browser can send a snapshot of their existing whiteboard to all other browsers. Take a look at this video to understand how the application work and the underlying code. The complete sample code can be downloaded here. The code behind the application is also explained below. The web page (index.jsp) has a HTML5 Canvas as shown: <canvas id="myCanvas" width="150" height="150" style="border:1px solid #000000;"></canvas> And some radio buttons to choose the color and shape. By default, the shape, color, and coordinates of any figure drawn on the canvas are put in a JSON structure and sent as a message to the WebSocket endpoint. The JSON structure looks like: { "shape": "square", "color": "#FF0000", "coords": { "x": 31.59999942779541, "y": 49.91999053955078 }} The endpoint definition looks like: @WebSocketEndpoint(value = "websocket",encoders = {FigureDecoderEncoder.class},decoders = {FigureDecoderEncoder.class})public class Whiteboard { As you can see, the endpoint has decoder and encoder registered that decodes JSON to a Figure (a POJO class) and vice versa respectively. The decode method looks like: public Figure decode(String string) throws DecodeException { try { JSONObject jsonObject = new JSONObject(string); return new Figure(jsonObject); } catch (JSONException ex) { throw new DecodeException("Error parsing JSON", ex.getMessage(), ex.fillInStackTrace()); }} And the encode method looks like: public String encode(Figure figure) throws EncodeException { return figure.getJson().toString();} FigureDecoderEncoder implements both decoder and encoder functionality but thats purely for convenience. But the recommended design pattern is to keep them in separate classes. In certain cases, you may even need only one of them. On the client-side, the Canvas is initialized as: var canvas = document.getElementById("myCanvas");var context = canvas.getContext("2d");canvas.addEventListener("click", defineImage, false); The defineImage method constructs the JSON structure as shown above and sends it to the endpoint using websocket.send(). An instant snapshot of the canvas is sent using binary transfer with WebSocket. The WebSocket is initialized as: var wsUri = "ws://localhost:8080/whiteboard/websocket";var websocket = new WebSocket(wsUri);websocket.binaryType = "arraybuffer"; The important part is to set the binaryType property of WebSocket to arraybuffer. This ensures that any binary transfers using WebSocket are done using ArrayBuffer as the default type seem to be blob. The actual binary data transfer is done using the following: var image = context.getImageData(0, 0, canvas.width, canvas.height);var buffer = new ArrayBuffer(image.data.length);var bytes = new Uint8Array(buffer);for (var i=0; i<bytes.length; i++) { bytes[i] = image.data[i];}websocket.send(bytes); This comprehensive sample shows the following features of JSR 356 API: Annotation-driven endpoints Send/receive text and binary payload in WebSocket Encoders/decoders for custom text payload In addition, it also shows how images can be captured and drawn using HTML5 Canvas in a JSP. How could this be turned in to an online game ? Imagine drawing a Tic-tac-toe board on the canvas with two players playing and others watching. Then you can build access rights and controls within the application itself. Instead of sending a snapshot of the canvas on demand, a new peer joining the game could be automatically transferred the current state as well. Do you want to build this game ? I built a similar game a few years ago. Do somebody want to rewrite the game using WebSocket APIs ? :-) Many thanks to Jitu and Akshay for helping through the WebSocket internals! Here are some references for you: JSR 356: Java API for WebSocket - Specification (Early Draft) and Implementation (already integrated in GlassFish 4 promoted builds) Subsequent blogs will discuss the following topics (not necessary in that order) ... Error handling Interface-driven WebSocket endpoint Java client API Client and Server configuration Security Subprotocols Extensions Other topics from the API

    Read the article

  • [BST] Deletion procedure

    - by Metz
    Hi all. Consider the deletion procedure on a BST, when the node to delete has two children. Let's say i always replace it with the node holding the minimum key in its right subtree. The question is: is this procedure commutative? That is, deleting x and then y has the same result than deleting first y and then x? I think the answer is no, but i can't find a counterexample, nor figure out any valid reasoning. Thank you. EDIT: Maybe i've got to be clearer. Consider the transplant(node x, node y) procedure: it replace x with y (and its subtree). So, if i want to delete a node (say x) which has two children i replace it with the node holding the minimum key in its right subtree: y = minimum(x.right) transplant(y, y.right) // extracts the minimum (it doesn't have left child) y.right = x.right y.left = x.left transplant(x,y) The question was how to prove the procedure above is not commutative.

    Read the article

  • Why can't the 'NonSerialized' attribute be used at the class level? How to prevent serialization of

    - by ck
    I have a data object that is deep-cloned using a binary serialization. This data object supports property changed events, for example, PriceChanged. Let's say I attached a handler to PriceChanged. When the code attempts to serialize PriceChanged, it throws an exception that the handler isn't marked as serializable. My alternatives: I can't easily remove all handlers from the event before serialization I don't want to mark the handler as serializable because I'd have to recursively mark all the handlers dependencies as well. I don't want to mark PriceChanged as NonSerialized - there are tens of events like this that could potentially have handlers. Ideally, I'd like .NET to just stop going down the object graph at that point and make that a 'leaf'. So why can't I just mark the handler class as 'NonSerialized'? -- I finally worked around this problem by making the handler implement ISerializable and doing nothing in the serialize constructor/ GetDataObject method. But, the handler still is serialized, just with all its dependencies set to null - so I had to account for that as well. Is there a better way to prevent serialization of an entire class?

    Read the article

  • Is there a Tool for see files created with binary serialization?

    - by Néstor Sánchez A.
    I've working without problems serializating object graphs to and from files. Everything was fine until today: A dictionary, created in a constructor and NEVER deleted, was lost (null referece) just after deserialization from file, for the first time in more than a year doing the same without troubles. So, is there a Software Tool to look into binary serialization content showing a human/developer-readable version (a la Reflector) of what is stored? AKA: How to analyze (easy, no binary to IL translation. That would take months) binary serialized content? Thanks!

    Read the article

  • Protect Your Brand with Oracle Pedigree and Serialization Manager in R12.1.3

    The pharmaceutical industry is facing new challenges as counterfeit products enter the ethical drug supply chain. Companies need to better secure the movement of their branded products from manufacturing to distribution to the end customer to insure proper efficacy. Pharmaceuticals are of special targets to "knock-offs", non-authorized generics as pirated-products enter the market. Oracle Pedigree and Serialization Manager (OPSM) helps firms' better track and control their products through a unique monitoring process.

    Read the article

  • USING JSON SERIALIZATION FOR CODE BEHIND-JAVASCRIPT DATA COMMUNICATION

    Many of us went through a scenario like, can us pass a full of C# type/class to the javascript? Modify from there and again return back to C#? The difficulty is that JavaScript only knows string format comared to C# which has many data types. So how we can pass an entires class to JavaScript? Here we need to handle with JSON serialization techniques.

    Read the article

  • New binary analysis tool finds FOSS in device firmware

    <b>ars Technica:</b> "Software development company Loohuis Consulting and process management consultancy OpenDawn have released a new binary analysis tool that is designed to detect Linux and BusyBox in binary firmware. The program, which is freely available for download, is intended to aid open source license compliance efforts."

    Read the article

  • QotD: Maurizio Cimadamore on Project Lambda Binary Snapshots

    - by $utils.escapeXML($entry.author)
    I'm glad to announce that the first binary snapshots of the lambda repository are available at the following URL:http://jdk8.java.net/lambda/As you can imagine, as the implementation of the compiler/libraries is still under heavy development, there are still many rough corners that need to be polished. I'd like to thank you all for all the patience and the valuable feedback provided so far - please keep it coming!Maurizio Cimadamore announcing the Project Lambda binary snapshots on the lambda-dev OpenJDK mailing list.

    Read the article

  • How to encrypt and save a binary stream after serialization and read it back?

    - by Anindya Chatterjee
    I am having some problems in using CryptoStream when I want to encrypt a binary stream after binary serialization and save it to a file. I am getting the following exception System.ArgumentException : Stream was not readable. Can anybody please show me how to encrypt a binary stream and save it to a file and deserialize it back correctly? The code is as follows: class Program { public static void Main(string[] args) { var b = new B {Name = "BB"}; WriteFile<B>(@"C:\test.bin", b, true); var bb = ReadFile<B>(@"C:\test.bin", true); Console.WriteLine(b.Name == bb.Name); Console.ReadLine(); } public static T ReadFile<T>(string file, bool decrypt) { T bObj = default(T); var _binaryFormatter = new BinaryFormatter(); Stream buffer = null; using (var stream = new FileStream(file, FileMode.OpenOrCreate)) { if(decrypt) { const string strEncrypt = "*#4$%^.++q~!cfr0(_!#$@$!&#&#*&@(7cy9rn8r265&$@&*E^184t44tq2cr9o3r6329"; byte[] dv = {0x12, 0x34, 0x56, 0x78, 0x90, 0xAB, 0xCD, 0xEF}; CryptoStream cs; DESCryptoServiceProvider des = null; var byKey = Encoding.UTF8.GetBytes(strEncrypt.Substring(0, 8)); using (des = new DESCryptoServiceProvider()) { cs = new CryptoStream(stream, des.CreateEncryptor(byKey, dv), CryptoStreamMode.Read); } buffer = cs; } else buffer = stream; try { bObj = (T) _binaryFormatter.Deserialize(buffer); } catch(SerializationException ex) { Console.WriteLine(ex.Message); } } return bObj; } public static void WriteFile<T>(string file, T bObj, bool encrypt) { var _binaryFormatter = new BinaryFormatter(); Stream buffer; using (var stream = new FileStream(file, FileMode.Create)) { try { if(encrypt) { const string strEncrypt = "*#4$%^.++q~!cfr0(_!#$@$!&#&#*&@(7cy9rn8r265&$@&*E^184t44tq2cr9o3r6329"; byte[] dv = {0x12, 0x34, 0x56, 0x78, 0x90, 0xAB, 0xCD, 0xEF}; CryptoStream cs; DESCryptoServiceProvider des = null; var byKey = Encoding.UTF8.GetBytes(strEncrypt.Substring(0, 8)); using (des = new DESCryptoServiceProvider()) { cs = new CryptoStream(stream, des.CreateEncryptor(byKey, dv), CryptoStreamMode.Write); buffer = cs; } } else buffer = stream; _binaryFormatter.Serialize(buffer, bObj); buffer.Flush(); } catch(SerializationException ex) { Console.WriteLine(ex.Message); } } } } [Serializable] public class B { public string Name {get; set;} } It throws the serialization exception as follows The input stream is not a valid binary format. The starting contents (in bytes) are: 3F-17-2E-20-80-56-A3-2A-46-63-22-C4-49-56-22-B4-DA ...

    Read the article

  • Custom XML Serialization, how to write custom root element?

    - by Beta033
    I'm probably just doing this wrong, i know. i'm using custom serialization and when the xml is generated it's putting the class name as the root element Example: <MyClassName> <MyIntendedRootNode> <ObjectType> <Property1/> <Property2/> ... I'm inoking the serialization by calling xmlserializer.Serialize(writer,Me) so i'm sure that has something to do with it. I've tried putting XMLRoot onto the class, but i think as vb is compiling this partial class with it's aspx page, it's either overwriting this property or ignoring it entirely. ideally i'd like to just tell it to either throw away everything it has and use a different root element. Anybody else do this except me? Thanks

    Read the article

  • How to tell Subversion to display binary files using an external program?

    - by lamcro
    I have some code which, like java, is stored in a binary format, and I have the applications to display and modify this code setup in the Subversion's config file. But when I run svn diff for these file, Subversion prevents me =================================================================== Cannot display: file marked as a binary type. svn:mime-type = application/octet-stream I can still view them, but only with the --force argument Since all the files in the repository are of this binary code, how can I permanently force subversion to open the files for diff or edit mode?

    Read the article

< Previous Page | 14 15 16 17 18 19 20 21 22 23 24 25  | Next Page >