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Search found 768 results on 31 pages for 'cakephp 2 0'.

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  • Does CakePHP treat all INT fields as ID's for join tables?

    - by Jonnie
    I am trying to save a User, their Profile, and some tags and my join table that links the profile and the tags keeps getting messed up. The profile model is called Instructor, the tag model is called Subject. The Instructor has a phone number and a zip code and for some reason CakePHP thinks these are the fields it should use when creating entries in my join table. My Join table always comes out as: id | instructor_id | subject_id | 1 | 90210 | 1 | // thinks that the zip code is an instructor_id 2 | 1112223333 | 1 | // thinks that the phone number is an instructor_id 3 | 1 | 1 | // thinks that user_id is an instructor_id 4 | 1 | 1 | // the actual instructor_id, this one's correct 5 | 90210 | 2 | 6 | 1112223333 | 2 | 3 | 1 | 2 | 4 | 1 | 2 | My Models: class Instructor extends AppModel { var $name = 'Instructor'; var $belongsTo = array('User', 'State'); var $hasAndBelongsToMany = array( 'Subject' = array( 'className' = 'Subject', 'joinTable' = 'instructors_subjects', 'foreignKey' = 'instructor_id', 'associationForeignKey' = 'subject_id', 'unique' = true, 'conditions' = '', 'fields' = '', 'order' = '', 'limit' = '', 'offset' = '', 'finderQuery' = '', 'deleteQuery' = '', 'insertQuery' = '' ) ); } class Subject extends AppModel { var $name = 'Subject'; var $hasAndBelongsToMany = array( 'Instructor' = array( 'className' = 'Instructor', 'joinTable' = 'instructors_subjects', 'foreignKey' = 'subject_id', 'associationForeignKey' = 'instructor_id', 'unique' = true, 'conditions' = '', 'fields' = '', 'order' = '', 'limit' = '', 'offset' = '', 'finderQuery' = '', 'deleteQuery' = '', 'insertQuery' = '' ) ); } My Model Associations: User hasOne Instructor Instructor belongsTo User Instructor hasAndBelongsToMany Subject Subject hasAndBelongsToMany Instructor My form data looks like: Array ( [User] = Array ( [username] = MrInstructor [password] = cddb06c93c72f34eb9408610529a34645c29c55d [group_id] = 2 ) [Instructor] = Array ( [name] = Jimmy Bob [email] = [email protected] [phone] = 1112223333 [city] = Beverly Hills [zip_code] = 90210 [states] = 5 [website] = www.jimmybobbaseballschool.com [description] = Jimmy Bob is an instructor. [user_id] = 1 [id] = 1 ) [Subject] = Array ( [name] = hitting, pitching ) ) My function for processing the form looks like: function instructor_register() { $this-set('groups', $this-User-Group-find('list')); $this-set('states', $this-User-Instructor-State-find('list')); if (!empty($this-data)) { // Set the group to Instructor $this-data['User']['group_id'] = 2; // Save the user data $user = $this-User-save($this-data, true, array( 'username', 'password', 'group_id' )); // If the user was saved, save the instructor's info if (!empty($user)) { $this-data['Instructor']['user_id'] = $this-User-id; $instructor = $this-User-Instructor-save($this-data, true, array( 'user_id', 'name', 'email', 'phone', 'city', 'zip_code', 'state_id', 'website', 'description' )); // If the instructor was saved, save the rest if(!empty($instructor)) { $instructorId = $this-User-Instructor-id; $this-data['Instructor']['id'] = $instructorId; // Save each subject seperately $subjects = explode(",", $this-data['Subject']['name']); foreach ($subjects as $_subject) { // Get the correct subject format $_subject = strtolower(trim($_subject)); $this-User-Instructor-Subject-create($this-data); $this-User-Instructor-Subject-set(array( 'name' = $_subject )); $this-User-Instructor-Subject-save(); echo ''; print_r($this-data); echo ''; } } } } }

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  • What does this snippet work? It uses session cookie [closed]

    - by Emerald214
    My website is a gadget application. It uses CakePHP framework. It has the below snippet in AppController. I searched the cookie variable in the project but can't find any other occurences. I also don't understand what it works. Why does it always check this in every request. if ( isset( $_COOKIE[session_name()] ) ) { if ( !isset( $this->sns_id ) ) { // ????????? $this->cakeError( 'session' ); } } else { // ?????????????????? if ( !isset( $_REQUEST['post_pf_params'] ) ) { $this->cakeError( 'cookie' ); } }

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  • CakePHP Missing Database Table Error

    - by BRADINO
    I am baking a new project management application at work and added a couple new tables to the database today. When I went into the console to bake the new models, they were not in the list... php /path/cake/console/cake.php bake all -app /path/app/ So I manually typed in the model name and I got a missing database table for model error. I checked and double-checked and the database table was named properly. Turns out that some files inside the /app/tmp/cache/ folder were causing Cake not to recognize that I had added new tables to my database. Once I deleted the cache files cake instantly recognized my new database tables and I was baking away! rm -Rf /path/app/tmp/cache/cake*

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  • StackCenter 2 - Now in Public Beta!

    - by George Edison
    Visit now: http://stackcenter.quickmediasolutions.com/beta/ Feedback is appreciated! About StackCenter 2 has been brewing for quite some time now. Since the global inbox was introduced, the original StackCenter was rendered mostly useless and the need for a replacement was born. And now, I present StackCenter 2! Its goal is to be a dashboard for everything StackExchange such as rep. graphs, images, or whatever! Currently, there are 3 widgets and it is now possible to write your own - just follow the link on your dashboard's home page. After registering, simply click on the 'add widgets...' link to get started. Some things might not work quite right. (This is in beta after all.) Any feedback you can provide is welcome! License Closed source at this point. Platform StackCenter should run fine on any web browser that has JavaScript enabled. (StackCenter 2 uses a lot of JavaScript.) Contact Email: [email protected] Code PHP (using the CakePHP framework), JavaScript, and of course, HTML

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  • .htaccess time on godaddy

    - by doug
    Hi there I'm trying to run a cakephp application on a godaddy linux account. The problem is that i get the error 500. I've read on cakephp discussion group that i have to edit the .htaccess file. 1) How much do i have to wait until i see the result? 2) More information about this error may be available in the server error log. Where are those servers log on a godaddy linux hosted account?

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  • Adding events in Fullcalendar on CodeIgniter

    - by Naem Iqbal
    I just implemented Adam Shaw's popular calendar called 'fullcalendar' (http://arshaw.com/fullcalendar/) using CodeIgniter. But I require addition and other operations on events from my database. I was able to find one CakePHP plugin with the same purpose from here, http://bakery.cakephp.org/articles/view/events-plugin. Since I'm not in touch with CakePHP, Can anyone help with this on CodeIgniter..?

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  • CakePHP, CodeIgniter or Rails for multi-user Tumblr clone?

    - by Jordan
    I'm about to start building a tumblr clone that handles multiple users (so premade clones like Gelato won't cut it) and I'm not sure which framework I'd like to build this is. Right now, I'm only intending to build a prototype. Something I can get a dozen friends on to test the concept and grow to maybe a couple hundred users to prove the market, so I'm not worried about long term scale. My biggest concern right now is quick deployment. I'd like to get from zero to signups in as short a time as possible, with as little customization to the framework of choice as possible. I have experience with PHP, but not Ruby. However, I don't think the learning curve would be too steep so I'm not ruling out rails. I just want the framework that is most appropriate for a system like a multi-user tumblr clone so that I can build it with as little hassle, and as quickly, as possible. If anyone has experience with a similar project, or with these frameworks and can offer an insightful perspective, I'd be very appreciative. Thanks for taking the time to read. Cheers, ~Jordan Feldstein

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  • Wordpress Autologin Plugin not working on server

    - by Nishant
    Hello Everyone, I have been busy integrating Wordpress to one of a CakePHP application.Last Monday I cracked the way to integrate it.Now another problem I faced was that Client wanted to auto login the users who are login in CakePHP side,I did that too and it works fine in local.I am using the Session Variable of CakePHP which is set in core.php of cakephp,in the Wordpress also.The Code snippet of the Auto Login plugin is : - session_name("Cake_PHP_Session_Vars"); session_start(); function auto_login(){if (!is_user_logged_in()) { //determine WordPress user account to impersonate $user_login = 'guest'; //get user's ID $sessVars = $_SESSION['User']; $user_id = $sessVars['id']; //login wp_set_current_user($user_id, $user_login); wp_set_auth_cookie($user_id); do_action('wp_login', $user_login); }}add_action('init', 'auto_login'); It all works fine on the Local system but when I am putting it on Server,It is not working out.Please suggest me what could be the problem here. Thanks In Advance

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  • Can I give a different id to define Cakephp model associations?

    - by gacrux
    I have an one to many association in which a Thing can have many Statuses defined as below: Status Model: class Status extends AppModel { var $name = 'Status'; var $belongsTo = array( 'Thing' => array( 'className' => 'Thing', 'foreignKey' => 'thing_id', ); } Thing Model: class Thing extends AppModel { var $name = 'Thing'; var $belongsTo = array( // other associations ); var $hasMany = array( 'Status' => array( 'className' => 'Status', 'foreignKey' => 'thing_id', 'dependent' => false, 'order' => 'datetime DESC', 'limit' => '10', ), // other associations ); } This works OK, but I would like Thing to use a different id to connect to Status. E.g. Thing would use 'id' for all of it's other associations but use 'thing_status_id' for it's Status association. How can I best do this?

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  • Cakephp how to use Set Class to make an assoc array?

    - by michael
    I have the output array from a $Model-find() query which also pulls data from a hasMany relationship: Array( [Parent] => Array ( [id] => 1 ) [Child] => Array ( [0] => Array ( [id] => aaa [score] => 3 [src] => stage6/tn~4bbb38cc-0018-49bf-96a9-11a0f67883f5.jpg [parent_id] => 1 ) [1] => Array ( [id] => bbb [score] => 5 [src] => stage0/tn~4bbb38cc-00ac-4b25-b074-11a0f67883f5.jpg [parent_id] => 1 ) [2] => Array ( [id] => ccc [score] => 2 [src] => stage4/tn~4bbb38cc-01c8-44bd-b71d-11a0f67883f5.jpg [parent_id] => 1 ) ) ) I'd like to transform this output into something like this, where the child id is the key to additional child attributes: Array( [aaa] => Array ( [score] => 3 [src] => stage6/tn~4bbb38cc-0018-49bf-96a9-11a0f67883f5.jpg ) [bbb] => Array ( [score] => 5 [src] => stage0/tn~4bbb38cc-00ac-4b25-b074-11a0f67883f5.jpg ) [ccc] => Array ( [score] => 2 [src] => stage4/tn~4bbb38cc-01c8-44bd-b71d-11a0f67883f5.jpg ) } Is there an easy way to use Set::extract, Set::combine, Set::insert, etc. to do this efficiently? I cannot figure it out.

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  • How can I use a different id field for one of my CakePHP model associations?

    - by gacrux
    I have an one to many association in which a Thing can have many Statuses defined as below: Status Model: class Status extends AppModel { var $name = 'Status'; var $belongsTo = array( 'Thing' => array( 'className' => 'Thing', 'foreignKey' => 'thing_id', ); } Thing Model: class Thing extends AppModel { var $name = 'Thing'; var $belongsTo = array( // other associations ); var $hasMany = array( 'Status' => array( 'className' => 'Status', 'foreignKey' => 'thing_id', 'dependent' => false, 'order' => 'datetime DESC', 'limit' => '10', ), // other associations ); } This works OK, but I would like Thing to use a different id to connect to Status. E.g. Thing would use 'id' for all of it's other associations but use 'thing_status_id' for it's Status association. How can I best do this?

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  • How to combine Translate and Soft Deletable Behavior in CakePHP 1.2.7?

    - by m99
    Hi guys, i'm trying to combine Translate Behavior and Mariano Iglesias' Soft Deletable Behavior Revision 49. But always if a want to soft delete a record which hasMany other records, which are translated (located in the i18n-table partly), the related hasMany records aren't soft deleted. Example: Post hasMany Comments (dependent = true) Post actsAs SoftDeletable Comments actsAs SoftDeletable, Translate Post record get's soft deleted, but I also get an error for the dependent Comment records and they aren't soft deleted. Any suggestions? Thanks in advance Marco

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  • In my cakephp project the save function is not working?

    - by Faheem
    My controller action is: function add() { if (!empty($this-data)) { $this-Customer-create(); if ($this-Customer-save($this-data)) { $this-Session-setFlash('A new Customer has been added'); $this-redirect(array('action'='index')); } else { $this-Session-setFlash('The customer cannot be added this time. Try again later.'); $this-redirect(array('action'='index')); } } } My model is: class Customer extends AppModel { var $name = 'Customer'; var $validate = array( 'name' = array( 'length'= array( 'rule' = array('between', 4,50), 'message' = 'Name must be minimum 4 and maximum 50 characters long.' ), 'checkUnique'= array( 'rule' = 'isUnique', 'message' = 'This Name is already registered' ) )); and this is my view: create('Customer',array('action'='add'));? input('Customer.name'); echo $form-input('Customer.balance',array('type'='hidden','default'=0)); ? end('Submit');? every time I submit the form it splashes: The customer cannot be added this time. Try again later.

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  • CakePHP: How can I change this find call to include all records that do not exist in the associated

    - by Stephen
    I have a few tables with the following relationships: Company hasMany Jobs, Employees, and Trucks, Users I've got all my foreign keys set up properly, along with the tables' Models, Controllers, and Views. Originally, the Jobs table had a boolean field called "assigned". The following find operation (from the JobsController) successfully returns all employees, all trucks, and any jobs that are not assigned and fall on a certain day for a single company (without returning users by utilizing the containable behavior): $this->set('resources', $this->Job->Company->find('first', array( 'conditions' => array( 'Company.id' => $company_id ), 'contain' => array( 'Employee', 'Truck', 'Job' => array( 'conditions' => array( 'Job.assigned' => false, 'Job.pickup_date' => date('Y-m-d', strtotime('Today')); ) ) ) ))); Now, since writing this code, I decided to do a lot more with the job assignments. So I've created a new model "Assignment" that belongsTo Truck and belongsTo Job. I've added the hasMany Assignments to both the Truck model and the Jobs Model. I have both foreign keys in the assignments table, along with some other assignment fields. Now, I'm trying to get the same information above, only instead of checking the assigned field from the job table, I want to check the assignments table to ensure that the job does not exist there. I can no longer use the containable behavior if I'm going to use the "joins" feature of the find method due to mysql errors (according to the cookbook). But, the following query returns all jobs, even if they fall on different days. $this->set('resources', $this->Job->Company->find('first', array( 'joins' => array( array( 'table' => 'employees', 'alias' => 'Employee', 'type' => 'LEFT', 'conditions' => array( 'Company.id = Employee.company_id' ) ), array( 'table' => 'trucks', 'alias' => 'Truck', 'type' => 'LEFT', 'conditions' => array( 'Company.id = Truck.company_id' ) ), array( 'table' => 'jobs', 'alias' => 'Job', 'type' => 'LEFT', 'conditions' => array( 'Company.id = Job.company_id' ) ), array( 'table' => 'assignments', 'alias' => 'Assignment', 'type' => 'LEFT', 'conditions' => array( 'Job.id = Assignment.job_id' ) ) ), 'conditions' => array( 'Job.pickup_date' => $day, 'Company.id' => $company_id, 'Assignment.job_id IS NULL' ) )));

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  • using ajax to post comments in cakephp results in 404 error, but no errors locally?

    - by Paul
    Using an ajax helper created for use with Jquery I've created a form that posts comments to "/comments/add", and this works as expected on my local wamp server but not on my production server. On my production server I get a '404 error, cannot find /comments/add'. I've spent quite a bit of time searching for a resolution with no luck so far. I've focused on trying to identify a gap but nothing jumps out at me. Here are some observations: works as expected on local wamp server requestHandler is listed as component files on both local and production server are the same controllers folder has write access autoLayout and autoRender are both set to false Here is the form in my view: <div class="comments form"> <?php echo $ajax->form('/comments/add', 'tournament', array('url' => '/comments/add', 'update' => 'Comments', 'indicator' => 'commentSaved'));?> <fieldset> <legend><?php __('Add Comment');?></legend> <div id="commentSaved" style="display: none; float: right;"> <h2>Loading...</h2> </div> <?php echo $form->hidden('Comment.foreign_id', array('value' => $tournament['Tournament']['id'])); echo $form->hidden('Comment.belongs_to', array('value' => 'Tournament')); echo $form->input('Comment.name'); echo $form->input('Comment.email'); echo $form->input('Comment.web', array('value' => 'http://')); echo $form->input('Comment.content'); ?> </fieldset> <?php echo $form->end('Submit');?> </div> And here is my 'comment's controller add action: function add() { if($this->RequestHandler->isAjax()) { $this->autoLayout = false; $this->autoRender=false; $this->Comment->recursive =-1; $commentInfos = $this->Comment->findAllByIp($_SERVER['REMOTE_ADDR']); $spam = FALSE; foreach($commentInfos as $commentInfo) { if ( time() - strtotime($commentInfo['Comment']['created']) < 180) { $spam = TRUE; } } if ($spam === FALSE) { if (!empty($this->data)) { $this->data['Comment']['ip'] = $_SERVER['REMOTE_ADDR']; $this->Comment->create(); if ($this->Comment->save($this->data)) { $this->Comment->recursive =-1; $comments = $this->Comment->findAll(array('Comment.foreign_id' => $this->data['Comment']['foreign_id'], 'Comment.belongs_to' => $this->data['Comment']['belongs_to'], 'Comment.status' =>'approved')); $this->set(compact('comments')); $this->viewPath = 'elements'.DS.'posts'; $this->render('comments'); } } } else { $this->Comment->recursive =-1; $comments = $this->Comment->findAll(array('Comment.foreign_id' => $this->data['Comment']['foreign_id'], 'Comment.belongs_to' => $this->data['Comment']['belongs_to'], 'Comment.status' =>'approved')); $this->set(compact('comments')); $this->viewPath = 'elements'.DS.'posts'; $this->render('spam'); } } else { $this->Session->setFlash(__('Invalid Action. Please view a post to add a comment.', true)); $this->redirect(array('controller' => 'pages', 'action'=>'display', 'home')); } } As you can see I've made sure that 'autoLayout' and 'autoRender' are set to false, but in Firebug I still get a 404 error stating /comments/add cannot be found on the production server. I should also point out that I'm using jquery, jquery.form and jquery.editable as well as a ajax helper created to be used with jquery. Any help or even suggestions about how to trouble shoot this is really appreciated. Cheers, Paul

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  • cakephp why can't I have an admin route and a superuser route?

    - by Jack B Nimble
    In core.php I can define Configure::write('Routing.admin', 'admin'); and /admin/controller/index will work. but if I define both Configure::write('Routing.admin', 'admin'); Configure::write('Routing.superuser', 'superuser'); and try to look at /superuser/blah/index/ instead of it saying the controller doesn't exist it says Error: SuperuserController could not be found. instead of saying Error: BlahController could not be found. When I first read the documentation I was under the impression I could run both routes, and not just one or the other. Is there something more I need to do?

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  • What's the correct place to share application logic in CakePHP?

    - by Pichan
    I guess simple answer to the question would be a component. Although I agree, I feel weird having to write a component for something so specific. For example, let's say I have a table of users. When a user is created, it should form a chain reaction of events, initiating different kinds of data related to the user all around the database. I figured it would be best to avoid directly manipulating the database from different controllers and instead pack all that neatly in a method. However since some logic needs to be accesed separately, I really can't have the whole package in a single method. Instead I thought it would be logical to break it up to smaller pieces(like $userModelOrController->createNew() and $candyStorageModelOrController->createNew()) that only interact with their respective database table. Now, if the logic is put to the model, it works great until I need to use other models. Of course it's possible, but when compared to loading models in a controller, it's not that simple. It's like a Cake developer telling me "Sure, it's possible if you want to do it that way but that's not how I would do it". Then, if the logic is put to the controller, I can access other models really easy through $this->loadModel(), but that brings me back to the previously explained situation since I need to be able to continue the chain reaction indefinitely. Accessing other controllers from a controller is possible, but again there doesn't seem to be any direct way of doing so, so I'm guessing I'm still not doing it right. By using a component this problem could be solved easily, since components are available to every controller I want. But like I wrote at the beginning, it feels awkward to create a component specifically for this one task. To me, components seem more like packages of extra functionality(like the core components) and not something to share controller-specific logic. Since I'm new to this whole MVC thing, I could've completely misunderstood the concept. Once again, I would be thankful if someone pointed me to the right direction :)

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  • cakephp: how to make NOW() work in search condition ?

    - by kaklon
    I'm trying to get all records with date greater then now. I tried this but it doeasnt work: $all_dates = $this->TourDate->find('all', array('conditions' => array('TourDate.date >=' => 'NOW()'), 'order' => array('TourDate.date ASC'))); If I replace NOW() with the current date it works. Why's that?

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  • When using the Auth component with CakePHP, I keep ketting this error. Why?

    - by Josh Brown
    Warning (2): Cannot modify header information - headers already sent by (output started at /Applications/MAMP/htdocs/iframeworking/iframe/app/models/frame.php:7) [COREcake/libs/controller/controller.php, line 647] here is the code from frame.php: <?php class Frame extends AppModel { var $name = 'Frame'; var $belongsTo = array('User' => array('className' => 'User', 'dependent' => true)); } ?>

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  • Cakephp beforeFind() - How do I add a JOIN condition AFTER the belongsTo association is added?

    - by michael
    I'm in Model-beforeFind($queryData), trying to add a JOIN condition to the queryData on a model which has belongsTo associations. Unfortunately, the new JOIN references a table in the belongsTo association, so it must appear AFTER the belongsTo in the query. Here is my Tagged-belongsTo association: app\plugins\tags\models\tagged.php (line 192) Array ( [Tag] => Array ( [className] => Tag [foreignKey] => tag_id [conditions] => [fields] => [order] => [counterCache] => ) [Group] => Array ( [className] => Group [foreignKey] => foreign_key [conditions] => Array ( [Tagged.model] => Group ) [fields] => [order] => [counterCache] => ) ) Here is the JOIN added in Tagged-beforeFind(), notice that the belongsTo joins have not yet been added: app\plugins\tags\models\tagged.php (line 194) Array ( [conditions] => Array ( [Tag.keyname] => europe ) [fields] => Array ( [0] => DISTINCT Group.* [1] => GroupPermission.* ) [joins] => Array ( [0] => Array ( [table] => permissions [alias] => GroupPermission [foreignKey] => [type] => INNER [conditions] => Array ( [GroupPermission.model] => Group [0] => GroupPermission.foreignId = Group.id [or] => Array ( ... ) ) ) ) [limit] => [offset] => [order] => Array ( [0] => ) [page] => 1 [group] => [callbacks] => 1 [by] => europe [model] => Group ) When I check the output, it fails with "1054: Unknown column 'Group.id' in 'on clause'" because the Permissions join appeared BEFORE the Groups join. SELECT DISTINCT `Group`.*, `GroupPermission`.* FROM `tagged` AS `Tagged` INNER JOIN permissions AS `GroupPermission` ON (`GroupPermission`.`model` = 'Group' AND `GroupPermission`.`foreignId` = `Group`.`id` AND (...)) LEFT JOIN `tags` AS `Tag` ON (`Tagged`.`tag_id` = `Tag`.`id`) LEFT JOIN `groups` AS `Group` ON (`Tagged`.`foreign_key` = `Group`.`id` AND `Tagged`.`model` = 'Group') WHERE `Tag`.`keyname` = 'europe' But this SQL (with Permissions joined moved to the end) works fine: SELECT DISTINCT `Group`.*, `GroupPermission`.* FROM `tagged` AS `Tagged` LEFT JOIN `tags` AS `Tag` ON (`Tagged`.`tag_id` = `Tag`.`id`) LEFT JOIN `groups` AS `Group` ON (`Tagged`.`foreign_key` = `Group`.`id` AND `Tagged`.`model` = 'Group') INNER JOIN permissions AS `GroupPermission` ON (`GroupPermission`.`model` = 'Group' AND `GroupPermission`.`foreignId` = `Group`.`id` AND (...)) WHERE `Tag`.`keyname` = 'europe' How do I add my join in beforeFind() after the belongsTo join?

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  • My choice of fieldname for CakePHP's form helper is not working properly, why?

    - by grokker
    Hi, I'm creating an AJAX form. The problem is when I'm trying to create a input form with formhelper, my input's name attribute is not correctly renedered in the view. Here's my code: $form->input('MainAttribute.'.$i.'.SubAttribute.'.$j.'.score', array('label' => '', 'options' => $scores)); I created it that way because I want SubAttribute to be inside MainAttribute. When I inspect the HTML, the name attribute of the form is cutted of like: name="data[SuperMainAttribute]" How can I specify the name attribute to the one that I'm planning on doing? (e.g. data[MainAttribute][0][SubAttribute][0][score])

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