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  • [CakePHP] How to add some action after login (and before redirection)?

    - by user198003
    hello, trying to develop some sort of login tracker for my cakephp application. i know that i need code like: $this->data['LoginSession']['username'] = $_SERVER['REMOTE_ADDR']; $this->data['LoginSession']['ipAddress'] = $_SERVER['REMOTE_ADDR']; $this->LoginSession->save($this->data); ... in (i guess) users_controller, but don't know exactly where. also i would like to track successful, but also unsuccessful logins. can you help me with this please? thank you in advance!

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  • Empty data was able to be stored to the Database in CakePHP even if "Not Null" had been specified.

    - by kwokwai
    Hi all, I was doing some self learning on CakePHP 1.26 with Mysql 5. I got a simple table with only one field and had applied "Not Null" to this field. This field in the table was corresponding to a Input text box in a HTML form. I tried not to enter anything into the Input text field, and then I saw that empty data was able to be stored into the Table even if "Not Null" had been applied to this field. I am confused of this result. Could you help me please?

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  • Copy CakePHP site under IIS webroot?

    - by dan giz
    I've got a CakePHP application that uses a MSSql server running on windows server 2008r2 enterprise using IIS 7.5 My application is the only website running and is installed into wwwroot with cakephp installed to c:\inetpub (one level up from the site) I want to copy this site so i can have a development version to work on, without conflicting with the live site. how do i go about doing this? i'm confused, since previous set ups i've seen have a different folder in wwwroot for the site itself.

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  • Can I use a specific model from within a behavior in CakePHP?

    - by Paul Willy
    I'm trying to write a behavior that will give my models access to a simple workflow engine I've devised. The workflow engine itself works as a CakePHP model, with workflow data stored in the database just as any other model data is stored. Basically what I want to do is have the behavior use the workflow model whenever an action is called on the base model. For example, if the edit() action is executed for Posts, then the Post (with the behavior attached) will trigger the workflow behavior with its own model name, action, and id as arguments (e.g. [Post, edit, 1]). Then the behavior will invoke the functionality of the Workflow model, which has a record for what to do when edit is run on Posts (e.g. send e-mail to users who are subscribed to that post) and will carry that out. My question is, what is the proper way to invoke model/controller methods from within the behavior? The model to be used from within the behavior will always be Workflow, but the behavior should be usable from basically any model (aside from Workflow itself). I know I could run SQL queries directly from the behavior, but of course this is not the Cake way :-) Or, am I going about this in the wrong way? I want to store a certain amount of logic in the database so that it is easily configurable by different users, and not have endless configuration checks within the model/controller logic itself so that workflow steps can be easily added/changed/removed in the future.

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  • Is there a better way to change user password in cakephp using Auth?

    - by sipiatti
    Hi, I am learning cakephp by myself. I tried to create a user controller with a changepassword function. It works, but I am not sure if this is the best way, and I could not googled up useful tutorials on this. Here is my code: class UsersController extends AppController { var $name = 'Users'; function login() { } function logout() { $this->redirect($this->Auth->logout()); } function changepassword() { $session=$this->Session->read(); $id=$session['Auth']['User']['id']; $user=$this->User->find('first',array('conditions' => array('id' => $id))); $this->set('user',$user); if (!empty($this->data)) { if ($this->Auth->password($this->data['User']['password'])==$user['User']['password']) { if ($this->data['User']['passwordn']==$this->data['User']['password2']) { // Passwords match, continue processing $data=$this->data; $this->data=$user; $this->data['User']['password']=$this->Auth->password($data['User']['passwordn']); $this->User->id=$id; $this->User->save($this->data); $this->Session->setFlash('Password changed.'); $this->redirect(array('controller'=>'Toners','action' => 'index')); } else { $this->Session->setFlash('New passwords differ.'); } } else { $this->Session->setFlash('Typed passwords did not match.'); } } } } password is the old password, passwordn is the new one, password2 is the new one retyped. Is there any other, more coomon way to do it in cake?

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  • How to save errors with the handleError in CakePHP 2.0?

    - by jags1988cr
    I have a big problem. Well, I'm trying to save the errors that happen in my web application. For example (only a example), if I make a division by zero, or happens an error in a query or something like that. So, I wanna catch that and save it in the database. But the handleError of CakePHP is static, so I can't use $this-MyModel-saveError(...). In my /app/Lib/AppError.php I have this: class AppError extends ErrorHandler { public $uses = array('Errors.Error'); public static function handleError($code, $description, $file = null, $line = null, $context = null) { //This print the error: echo "Code: ".$code." Description: ".$description." File: ".$file." Line: ".$line."<br>"; //I want to do this, (save to the database): $this->Error->saveError($code, $description, $file, $line); } } Without the $this-Error-saveError($code, $description, $file, $line); it works but I not only want to show the error. I think need an example or something like that. Please help me. Regards and thank you. Thanks... P.D.: Sorry for the English, I'm an english student...

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  • What does this snippet work? It uses session cookie [closed]

    - by Emerald214
    My website is a gadget application. It uses CakePHP framework. It has the below snippet in AppController. I searched the cookie variable in the project but can't find any other occurences. I also don't understand what it works. Why does it always check this in every request. if ( isset( $_COOKIE[session_name()] ) ) { if ( !isset( $this->sns_id ) ) { // ????????? $this->cakeError( 'session' ); } } else { // ?????????????????? if ( !isset( $_REQUEST['post_pf_params'] ) ) { $this->cakeError( 'cookie' ); } }

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  • CakePHP Missing Database Table Error

    - by BRADINO
    I am baking a new project management application at work and added a couple new tables to the database today. When I went into the console to bake the new models, they were not in the list... php /path/cake/console/cake.php bake all -app /path/app/ So I manually typed in the model name and I got a missing database table for model error. I checked and double-checked and the database table was named properly. Turns out that some files inside the /app/tmp/cache/ folder were causing Cake not to recognize that I had added new tables to my database. Once I deleted the cache files cake instantly recognized my new database tables and I was baking away! rm -Rf /path/app/tmp/cache/cake*

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  • StackCenter 2 - Now in Public Beta!

    - by George Edison
    Visit now: http://stackcenter.quickmediasolutions.com/beta/ Feedback is appreciated! About StackCenter 2 has been brewing for quite some time now. Since the global inbox was introduced, the original StackCenter was rendered mostly useless and the need for a replacement was born. And now, I present StackCenter 2! Its goal is to be a dashboard for everything StackExchange such as rep. graphs, images, or whatever! Currently, there are 3 widgets and it is now possible to write your own - just follow the link on your dashboard's home page. After registering, simply click on the 'add widgets...' link to get started. Some things might not work quite right. (This is in beta after all.) Any feedback you can provide is welcome! License Closed source at this point. Platform StackCenter should run fine on any web browser that has JavaScript enabled. (StackCenter 2 uses a lot of JavaScript.) Contact Email: [email protected] Code PHP (using the CakePHP framework), JavaScript, and of course, HTML

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  • .htaccess time on godaddy

    - by doug
    Hi there I'm trying to run a cakephp application on a godaddy linux account. The problem is that i get the error 500. I've read on cakephp discussion group that i have to edit the .htaccess file. 1) How much do i have to wait until i see the result? 2) More information about this error may be available in the server error log. Where are those servers log on a godaddy linux hosted account?

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  • Adding events in Fullcalendar on CodeIgniter

    - by Naem Iqbal
    I just implemented Adam Shaw's popular calendar called 'fullcalendar' (http://arshaw.com/fullcalendar/) using CodeIgniter. But I require addition and other operations on events from my database. I was able to find one CakePHP plugin with the same purpose from here, http://bakery.cakephp.org/articles/view/events-plugin. Since I'm not in touch with CakePHP, Can anyone help with this on CodeIgniter..?

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  • CakePHP, CodeIgniter or Rails for multi-user Tumblr clone?

    - by Jordan
    I'm about to start building a tumblr clone that handles multiple users (so premade clones like Gelato won't cut it) and I'm not sure which framework I'd like to build this is. Right now, I'm only intending to build a prototype. Something I can get a dozen friends on to test the concept and grow to maybe a couple hundred users to prove the market, so I'm not worried about long term scale. My biggest concern right now is quick deployment. I'd like to get from zero to signups in as short a time as possible, with as little customization to the framework of choice as possible. I have experience with PHP, but not Ruby. However, I don't think the learning curve would be too steep so I'm not ruling out rails. I just want the framework that is most appropriate for a system like a multi-user tumblr clone so that I can build it with as little hassle, and as quickly, as possible. If anyone has experience with a similar project, or with these frameworks and can offer an insightful perspective, I'd be very appreciative. Thanks for taking the time to read. Cheers, ~Jordan Feldstein

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  • Wordpress Autologin Plugin not working on server

    - by Nishant
    Hello Everyone, I have been busy integrating Wordpress to one of a CakePHP application.Last Monday I cracked the way to integrate it.Now another problem I faced was that Client wanted to auto login the users who are login in CakePHP side,I did that too and it works fine in local.I am using the Session Variable of CakePHP which is set in core.php of cakephp,in the Wordpress also.The Code snippet of the Auto Login plugin is : - session_name("Cake_PHP_Session_Vars"); session_start(); function auto_login(){if (!is_user_logged_in()) { //determine WordPress user account to impersonate $user_login = 'guest'; //get user's ID $sessVars = $_SESSION['User']; $user_id = $sessVars['id']; //login wp_set_current_user($user_id, $user_login); wp_set_auth_cookie($user_id); do_action('wp_login', $user_login); }}add_action('init', 'auto_login'); It all works fine on the Local system but when I am putting it on Server,It is not working out.Please suggest me what could be the problem here. Thanks In Advance

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  • Cakephp how to use Set Class to make an assoc array?

    - by michael
    I have the output array from a $Model-find() query which also pulls data from a hasMany relationship: Array( [Parent] => Array ( [id] => 1 ) [Child] => Array ( [0] => Array ( [id] => aaa [score] => 3 [src] => stage6/tn~4bbb38cc-0018-49bf-96a9-11a0f67883f5.jpg [parent_id] => 1 ) [1] => Array ( [id] => bbb [score] => 5 [src] => stage0/tn~4bbb38cc-00ac-4b25-b074-11a0f67883f5.jpg [parent_id] => 1 ) [2] => Array ( [id] => ccc [score] => 2 [src] => stage4/tn~4bbb38cc-01c8-44bd-b71d-11a0f67883f5.jpg [parent_id] => 1 ) ) ) I'd like to transform this output into something like this, where the child id is the key to additional child attributes: Array( [aaa] => Array ( [score] => 3 [src] => stage6/tn~4bbb38cc-0018-49bf-96a9-11a0f67883f5.jpg ) [bbb] => Array ( [score] => 5 [src] => stage0/tn~4bbb38cc-00ac-4b25-b074-11a0f67883f5.jpg ) [ccc] => Array ( [score] => 2 [src] => stage4/tn~4bbb38cc-01c8-44bd-b71d-11a0f67883f5.jpg ) } Is there an easy way to use Set::extract, Set::combine, Set::insert, etc. to do this efficiently? I cannot figure it out.

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  • How to combine Translate and Soft Deletable Behavior in CakePHP 1.2.7?

    - by m99
    Hi guys, i'm trying to combine Translate Behavior and Mariano Iglesias' Soft Deletable Behavior Revision 49. But always if a want to soft delete a record which hasMany other records, which are translated (located in the i18n-table partly), the related hasMany records aren't soft deleted. Example: Post hasMany Comments (dependent = true) Post actsAs SoftDeletable Comments actsAs SoftDeletable, Translate Post record get's soft deleted, but I also get an error for the dependent Comment records and they aren't soft deleted. Any suggestions? Thanks in advance Marco

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  • CakePHP: How can I change this find call to include all records that do not exist in the associated

    - by Stephen
    I have a few tables with the following relationships: Company hasMany Jobs, Employees, and Trucks, Users I've got all my foreign keys set up properly, along with the tables' Models, Controllers, and Views. Originally, the Jobs table had a boolean field called "assigned". The following find operation (from the JobsController) successfully returns all employees, all trucks, and any jobs that are not assigned and fall on a certain day for a single company (without returning users by utilizing the containable behavior): $this->set('resources', $this->Job->Company->find('first', array( 'conditions' => array( 'Company.id' => $company_id ), 'contain' => array( 'Employee', 'Truck', 'Job' => array( 'conditions' => array( 'Job.assigned' => false, 'Job.pickup_date' => date('Y-m-d', strtotime('Today')); ) ) ) ))); Now, since writing this code, I decided to do a lot more with the job assignments. So I've created a new model "Assignment" that belongsTo Truck and belongsTo Job. I've added the hasMany Assignments to both the Truck model and the Jobs Model. I have both foreign keys in the assignments table, along with some other assignment fields. Now, I'm trying to get the same information above, only instead of checking the assigned field from the job table, I want to check the assignments table to ensure that the job does not exist there. I can no longer use the containable behavior if I'm going to use the "joins" feature of the find method due to mysql errors (according to the cookbook). But, the following query returns all jobs, even if they fall on different days. $this->set('resources', $this->Job->Company->find('first', array( 'joins' => array( array( 'table' => 'employees', 'alias' => 'Employee', 'type' => 'LEFT', 'conditions' => array( 'Company.id = Employee.company_id' ) ), array( 'table' => 'trucks', 'alias' => 'Truck', 'type' => 'LEFT', 'conditions' => array( 'Company.id = Truck.company_id' ) ), array( 'table' => 'jobs', 'alias' => 'Job', 'type' => 'LEFT', 'conditions' => array( 'Company.id = Job.company_id' ) ), array( 'table' => 'assignments', 'alias' => 'Assignment', 'type' => 'LEFT', 'conditions' => array( 'Job.id = Assignment.job_id' ) ) ), 'conditions' => array( 'Job.pickup_date' => $day, 'Company.id' => $company_id, 'Assignment.job_id IS NULL' ) )));

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  • using ajax to post comments in cakephp results in 404 error, but no errors locally?

    - by Paul
    Using an ajax helper created for use with Jquery I've created a form that posts comments to "/comments/add", and this works as expected on my local wamp server but not on my production server. On my production server I get a '404 error, cannot find /comments/add'. I've spent quite a bit of time searching for a resolution with no luck so far. I've focused on trying to identify a gap but nothing jumps out at me. Here are some observations: works as expected on local wamp server requestHandler is listed as component files on both local and production server are the same controllers folder has write access autoLayout and autoRender are both set to false Here is the form in my view: <div class="comments form"> <?php echo $ajax->form('/comments/add', 'tournament', array('url' => '/comments/add', 'update' => 'Comments', 'indicator' => 'commentSaved'));?> <fieldset> <legend><?php __('Add Comment');?></legend> <div id="commentSaved" style="display: none; float: right;"> <h2>Loading...</h2> </div> <?php echo $form->hidden('Comment.foreign_id', array('value' => $tournament['Tournament']['id'])); echo $form->hidden('Comment.belongs_to', array('value' => 'Tournament')); echo $form->input('Comment.name'); echo $form->input('Comment.email'); echo $form->input('Comment.web', array('value' => 'http://')); echo $form->input('Comment.content'); ?> </fieldset> <?php echo $form->end('Submit');?> </div> And here is my 'comment's controller add action: function add() { if($this->RequestHandler->isAjax()) { $this->autoLayout = false; $this->autoRender=false; $this->Comment->recursive =-1; $commentInfos = $this->Comment->findAllByIp($_SERVER['REMOTE_ADDR']); $spam = FALSE; foreach($commentInfos as $commentInfo) { if ( time() - strtotime($commentInfo['Comment']['created']) < 180) { $spam = TRUE; } } if ($spam === FALSE) { if (!empty($this->data)) { $this->data['Comment']['ip'] = $_SERVER['REMOTE_ADDR']; $this->Comment->create(); if ($this->Comment->save($this->data)) { $this->Comment->recursive =-1; $comments = $this->Comment->findAll(array('Comment.foreign_id' => $this->data['Comment']['foreign_id'], 'Comment.belongs_to' => $this->data['Comment']['belongs_to'], 'Comment.status' =>'approved')); $this->set(compact('comments')); $this->viewPath = 'elements'.DS.'posts'; $this->render('comments'); } } } else { $this->Comment->recursive =-1; $comments = $this->Comment->findAll(array('Comment.foreign_id' => $this->data['Comment']['foreign_id'], 'Comment.belongs_to' => $this->data['Comment']['belongs_to'], 'Comment.status' =>'approved')); $this->set(compact('comments')); $this->viewPath = 'elements'.DS.'posts'; $this->render('spam'); } } else { $this->Session->setFlash(__('Invalid Action. Please view a post to add a comment.', true)); $this->redirect(array('controller' => 'pages', 'action'=>'display', 'home')); } } As you can see I've made sure that 'autoLayout' and 'autoRender' are set to false, but in Firebug I still get a 404 error stating /comments/add cannot be found on the production server. I should also point out that I'm using jquery, jquery.form and jquery.editable as well as a ajax helper created to be used with jquery. Any help or even suggestions about how to trouble shoot this is really appreciated. Cheers, Paul

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  • cakephp why can't I have an admin route and a superuser route?

    - by Jack B Nimble
    In core.php I can define Configure::write('Routing.admin', 'admin'); and /admin/controller/index will work. but if I define both Configure::write('Routing.admin', 'admin'); Configure::write('Routing.superuser', 'superuser'); and try to look at /superuser/blah/index/ instead of it saying the controller doesn't exist it says Error: SuperuserController could not be found. instead of saying Error: BlahController could not be found. When I first read the documentation I was under the impression I could run both routes, and not just one or the other. Is there something more I need to do?

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  • What's the correct place to share application logic in CakePHP?

    - by Pichan
    I guess simple answer to the question would be a component. Although I agree, I feel weird having to write a component for something so specific. For example, let's say I have a table of users. When a user is created, it should form a chain reaction of events, initiating different kinds of data related to the user all around the database. I figured it would be best to avoid directly manipulating the database from different controllers and instead pack all that neatly in a method. However since some logic needs to be accesed separately, I really can't have the whole package in a single method. Instead I thought it would be logical to break it up to smaller pieces(like $userModelOrController->createNew() and $candyStorageModelOrController->createNew()) that only interact with their respective database table. Now, if the logic is put to the model, it works great until I need to use other models. Of course it's possible, but when compared to loading models in a controller, it's not that simple. It's like a Cake developer telling me "Sure, it's possible if you want to do it that way but that's not how I would do it". Then, if the logic is put to the controller, I can access other models really easy through $this->loadModel(), but that brings me back to the previously explained situation since I need to be able to continue the chain reaction indefinitely. Accessing other controllers from a controller is possible, but again there doesn't seem to be any direct way of doing so, so I'm guessing I'm still not doing it right. By using a component this problem could be solved easily, since components are available to every controller I want. But like I wrote at the beginning, it feels awkward to create a component specifically for this one task. To me, components seem more like packages of extra functionality(like the core components) and not something to share controller-specific logic. Since I'm new to this whole MVC thing, I could've completely misunderstood the concept. Once again, I would be thankful if someone pointed me to the right direction :)

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  • cakephp: how to make NOW() work in search condition ?

    - by kaklon
    I'm trying to get all records with date greater then now. I tried this but it doeasnt work: $all_dates = $this->TourDate->find('all', array('conditions' => array('TourDate.date >=' => 'NOW()'), 'order' => array('TourDate.date ASC'))); If I replace NOW() with the current date it works. Why's that?

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  • Cakephp beforeFind() - How do I add a JOIN condition AFTER the belongsTo association is added?

    - by michael
    I'm in Model-beforeFind($queryData), trying to add a JOIN condition to the queryData on a model which has belongsTo associations. Unfortunately, the new JOIN references a table in the belongsTo association, so it must appear AFTER the belongsTo in the query. Here is my Tagged-belongsTo association: app\plugins\tags\models\tagged.php (line 192) Array ( [Tag] => Array ( [className] => Tag [foreignKey] => tag_id [conditions] => [fields] => [order] => [counterCache] => ) [Group] => Array ( [className] => Group [foreignKey] => foreign_key [conditions] => Array ( [Tagged.model] => Group ) [fields] => [order] => [counterCache] => ) ) Here is the JOIN added in Tagged-beforeFind(), notice that the belongsTo joins have not yet been added: app\plugins\tags\models\tagged.php (line 194) Array ( [conditions] => Array ( [Tag.keyname] => europe ) [fields] => Array ( [0] => DISTINCT Group.* [1] => GroupPermission.* ) [joins] => Array ( [0] => Array ( [table] => permissions [alias] => GroupPermission [foreignKey] => [type] => INNER [conditions] => Array ( [GroupPermission.model] => Group [0] => GroupPermission.foreignId = Group.id [or] => Array ( ... ) ) ) ) [limit] => [offset] => [order] => Array ( [0] => ) [page] => 1 [group] => [callbacks] => 1 [by] => europe [model] => Group ) When I check the output, it fails with "1054: Unknown column 'Group.id' in 'on clause'" because the Permissions join appeared BEFORE the Groups join. SELECT DISTINCT `Group`.*, `GroupPermission`.* FROM `tagged` AS `Tagged` INNER JOIN permissions AS `GroupPermission` ON (`GroupPermission`.`model` = 'Group' AND `GroupPermission`.`foreignId` = `Group`.`id` AND (...)) LEFT JOIN `tags` AS `Tag` ON (`Tagged`.`tag_id` = `Tag`.`id`) LEFT JOIN `groups` AS `Group` ON (`Tagged`.`foreign_key` = `Group`.`id` AND `Tagged`.`model` = 'Group') WHERE `Tag`.`keyname` = 'europe' But this SQL (with Permissions joined moved to the end) works fine: SELECT DISTINCT `Group`.*, `GroupPermission`.* FROM `tagged` AS `Tagged` LEFT JOIN `tags` AS `Tag` ON (`Tagged`.`tag_id` = `Tag`.`id`) LEFT JOIN `groups` AS `Group` ON (`Tagged`.`foreign_key` = `Group`.`id` AND `Tagged`.`model` = 'Group') INNER JOIN permissions AS `GroupPermission` ON (`GroupPermission`.`model` = 'Group' AND `GroupPermission`.`foreignId` = `Group`.`id` AND (...)) WHERE `Tag`.`keyname` = 'europe' How do I add my join in beforeFind() after the belongsTo join?

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