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  • Remote SQL login page C#

    - by Crazyd22
    Hey, I am trying to create a login page that checks the username and password with the database on the server. The server is located in a different country. This is the code I have so far: #region Building the connection string string Server = "XX.XXX.XX.XX, XXXX"; string Username = "_Username_"; string Password = "_Password_"; string Database = "_Database_"; string ConnectionString = "Data Source=" + Server + ";"; ConnectionString += "User ID=" + Username + ";"; ConnectionString += "Password=" + Password + ";"; ConnectionString += "Initial Catalog=" + Database; #endregion SqlConnection SQLConnection = new SqlConnection(); try { SQLConnection.ConnectionString = ConnectionString; SQLConnection.Open();   // You can get the server version // SQLConnection.ServerVersion } catch (Exception Ex) { // Try to close the connection if (SQLConnection != null) SQLConnection.Dispose();   // Create a (useful) error message string ErrorMessage = "A error occurred while trying to connect to the server."; ErrorMessage += Environment.NewLine; ErrorMessage += Environment.NewLine; ErrorMessage += Ex.Message;   // Show error message (this = the parent Form object) MessageBox.Show(this, ErrorMessage, "Connection error", MessageBoxButtons.OK, MessageBoxIcon.Error);   // Stop here return; } I am getting the error message: Non-negative number required. Parameter name: count I have accepted wildcards on my server and I have no idea what that error means? Any help would be appreciated, Thanks.

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  • Parameters lost on login form submitted with post in JBoss

    - by Supowski
    My login page contains two forms: one for logging in and one for signing up. Shorten like this: <form name="LoginForm" id="LoginForm" method="post" action="j_security_check" > <input type="text" name="j_username" /> <input type="text" name="j_password" /> <input type="submit" value="Sing In" /> <form> <form name="SignUpForm" id="SignUpForm" method="post" action="/homepage" > <input type="text" name="loginName" /> <input type="password" name="password1" /> <input type="password" name="password2" /> <input type="submit" value="Sing Up" /> <form> I If 'Sing Up', than values of input are lost during processing and not passed into my Servlet. It works fine with GET, but than there is password in URL, so it's not the right solution :) Similar problem has been posted to community.jboss.org, but with no response: http://community.jboss.org/message/7150#7150. I'm using JBoss 4.3eap. Any help?

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  • What could cause these "failed to authenticate" logs other than failed login attempts (OSX)?

    - by Tom
    I've found this in the Console logs: 10/03/10 3:53:58 PM SecurityAgent[156] User info context values set for tom 10/03/10 3:53:58 PM authorizationhost[154] Failed to authenticate user (tDirStatus: -14090). 10/03/10 3:54:00 PM SecurityAgent[156] User info context values set for tom 10/03/10 3:54:00 PM authorizationhost[154] Failed to authenticate user (tDirStatus: -14090). 10/03/10 3:54:03 PM SecurityAgent[156] User info context values set for tom 10/03/10 3:54:03 PM authorizationhost[154] Failed to authenticate user (tDirStatus: -14090). There are about 11 of these "failed to authenticate" messages logged in quick succession. It looks to me like someone is sitting there trying to guess the password. However, when I tried to replicate this I get the same log messages except that this extra message appears after five attempts: 13/03/10 1:18:48 PM DirectoryService[11] Failed Authentication return is being delayed due to over five recent auth failures for username: tom. I don't want to accuse someone of trying to break into an account without being sure that they were actually trying to break in. My question is this: is it almost definitely someone guessing a password, or could the 11 "failed to authenticate" messages be caused by something else?

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  • Asp.net login problem.

    - by Catarrunas
    Hello, im building a asp.net web site with 2.0 framework. I've been "fighting" with web.config, i've changed it quiet some times. So to start from scracht this is what i have: <?xml version="1.0" encoding="utf-16"?> <configuration> <connectionStrings> <remove name="LocalSqlServer"/> <add name="ABC" connectionString="Database=jsilvaqqc.mdf; Data Source=213.175.208.3;Initial Catalog=jsilvaqqc;User ID=jsilva;Password=joao123#;" providerName="System.Data.SqlClient"/> <add name="LocalSqlServer" connectionString="Database=jsilvaqqc.mdf; Data Source=213.175.208.3;Initial Catalog=jsilvaqqc;User ID=jsilva;Password=joao123#;" providerName="System.Data.SqlClient"/> </connectionStrings> <location path="Members"> <system.web> <authorization> <allow users="*"/> <deny users="?"/> </authorization> </system.web> </location> <system.web> <compilation debug="true"/> </system.web></configuration> It works fine im my machine. I've created the users for the login and the role to access the "Members" folder. But in my host company, it doesnt work. I have the aspnet database from my computer in that databese "jsilvaqqc.mdf". When i try to log on pops up box requiring autentication. But i've alreadu given that in the log in form. Do i need aspnet "authentication" tag? Why dont i need it in my machine if i access the same database? Thanks for you help.

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  • Using the login Details via Application

    - by ramin ss
    I have a CURL(in C++) to send my user and pass to remauth.php file so i think i do something wrong on remuth.php ( because i am basic in php and my program can not run because the auth not passed.) I use login via Application. my CURL: bool Auth_PerformSessionLogin(const char* username, const char* password) { curl_global_init(CURL_GLOBAL_ALL); CURL* curl = curl_easy_init(); if (curl) { char url[255]; _snprintf(url, sizeof(url), "http://%s/remauth.php", "SITEADDRESS.com"); char buf[8192] = {0}; char postBuf[8192]; _snprintf(postBuf, sizeof(postBuf), "%s&&%s", username, password); curl_easy_setopt(curl, CURLOPT_URL, url); curl_easy_setopt(curl, CURLOPT_WRITEFUNCTION, AuthDataReceived); curl_easy_setopt(curl, CURLOPT_WRITEDATA, (void*)&buf); curl_easy_setopt(curl, CURLOPT_USERAGENT, "IW4M"); curl_easy_setopt(curl, CURLOPT_FAILONERROR, true); curl_easy_setopt(curl, CURLOPT_POST, 1); curl_easy_setopt(curl, CURLOPT_POSTFIELDS, postBuf); curl_easy_setopt(curl, CURLOPT_POSTFIELDSIZE, -1); curl_easy_setopt(curl, CURLOPT_SSL_VERIFYPEER, false); CURLcode code = curl_easy_perform(curl); curl_easy_cleanup(curl); curl_global_cleanup(); if (code == CURLE_OK) { return Auth_ParseResultBuffer(buf); } else { Auth_Error(va("Could not reach the SITEADDRESS.comt server. Error code from CURL: %x.", code)); } return false; } curl_global_cleanup(); return false; } and my remauth.php: <?php ob_start(); $host=""; // Host name $dbusername=""; // Mysql username $dbpassword=""; // Mysql password $db_name=""; // Database name $tbl_name=""; // Table name // Connect to server and select databse. mysql_connect("$host", "$dbusername", "$dbpassword") or die(mysql_error()); mysql_select_db("$db_name") or die(mysql_error()); // Define $username and $password //$username=$username; //$password=md5($_POST['password']); //$password=$password; $username=$_POST['username']; $password=$_POST['password']; //$post_item[]='action='.$_POST['submit']; // To protect MySQL injection (more detail about MySQL injection) $username = stripslashes($username); $password = stripslashes($password); $username = mysql_real_escape_string($username); $password = mysql_real_escape_string($password); $sql="SELECT * FROM $tbl_name WHERE username='$username'"; $result=mysql_query($sql); // Mysql_num_row is counting table row $count=mysql_num_rows($result); // If result matched $username and $password, table row must be 1 row if($count==1){ $row = mysql_fetch_assoc($result); if (md5(md5($row['salt']).md5($password)) == $row['password']){ session_register("username"); session_register("password"); echo "#"; return true; } else { echo "o"; return false; } } else{ echo "o"; return false; } ob_end_flush(); ?> ///////////////////////////////////

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  • LDAP Account Locked Out Sporadically after Password change - Finding the source of invalid attempts

    - by CityView
    On a small network of machines (<1000) we have a user whose account is being locked out after an indeterminate interval following a password change. We are having severe difficulties finding the source of the invalid logon attempts and I would appreciate it greatly if some of you could go through your thought process and the checks you would perform in order to fix the problem. All I know for sure is that the account is locked out several (5+) times a day, I can't even be sure it's due to failed login attempts as there is no record of failure until the account is locked. So far I have tried; Logging the account out of everything we can think of and back in with the new password Scanning the user's box for any non standard software which might perform an LDAP lookup Checking all installed services on our production boxes to check none are attempting to run under the account Changing the user back to their old password (Problem persists so perhaps password change is a red herring) Wireshark on a box where lots of LDAP authentication is performed - Rejects only occur after account is already locked out Clearing the credential cache in - Control Panel - User Accounts - Advanced Looking at the local I'm at a loss for what to try. I am happy to try any suggestions you have in order to diagnose the issue. I think my question boils down to a simple request; I need a technique for deriving the source (Application/Host) of the invalid login attempts which are causing the account to be locked. I'm not sure if that's even possible but I suspect there must be more I can try. Many thanks, CityView

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  • Html LogIn form not functioning

    - by Tony C
    Ok, I have a login form that looks like this: <form id="loginForm" name="loginForm" method="post" action="login-exec.php"> <table width="300" border="0" align="center" cellpadding="2" cellspacing="0"> <tr> <td width="112"><b>Login</b></td> <td width="188"><input name="login" type="text" class="textfield" id="login" /></td> </tr> <tr> <td><b>Password</b></td> <td><input name="password" type="password" class="textfield" id="password" /></td> </tr> <tr> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login" /></td> </tr> </table> </form> Now, This form is on a page in a directory called members. When i put it on a page in the home directory and change the action to "members/login-exec.php" When I try to logIn it just refreshes the page, but the name of the page in the browser changes to the actions taking place in the form. Any ideas on making this work guys? EDIT, heres the login-exec.php code: <?php //Start session session_start(); //Include database connection details require_once('config.php'); //Array to store validation errors $errmsg_arr = array(); //Validation error flag $errflag = false; //Connect to mysql server $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } //Select database $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } //Function to sanitize values received from the form. Prevents SQL injection function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } //Sanitize the POST values $login = clean($_POST['login']); $password = clean($_POST['password']); //Input Validations if($login == '') { $errmsg_arr[] = 'Login ID missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'Password missing'; $errflag = true; } //If there are input validations, redirect back to the login form if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; session_write_close(); header("location: login-form.php"); exit(); } //Create query $qry="SELECT * FROM members WHERE login='$login' AND passwd='".md5($_POST['password'])."'"; $result=mysql_query($qry); //Check whether the query was successful or not if($result) { if(mysql_num_rows($result) == 1) { //Login Successful session_regenerate_id(); $member = mysql_fetch_assoc($result); $_SESSION['SESS_MEMBER_ID'] = $member['member_id']; $_SESSION['SESS_FIRST_NAME'] = $member['firstname']; $_SESSION['SESS_LAST_NAME'] = $member['lastname']; session_write_close(); header("location: members.php"); exit(); }else { //Login failed header("location: login-failed.php"); exit(); } }else { die("Query failed"); } ?>

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  • Preventing - Large Number of Failed Login Attempts from IP

    - by Silver89
    I'm running a CentOS 6.3 server and currently receive emails entitled "Large Number of Failed Login Attempts from IP" from my server every 15 minutes or so. Surely with the below configured it should mean only the person using the (my static ip) should be able to even try and log in? If that's the case where are these remote unknown users trying to log into which is generating these emails? Current Security Steps: root login is only allowed without-password StrictModes yes SSH password login is disabled - PasswordAuthentication no SSH public keys are used SSH port has been changed to a number greater than 40k cPHulk is configured and running Logins limited to specific ip address cPanel and WHM limited to my static ip only hosts.allow sshd: (my static ip) vsftpd: (my static ip) whostmgrd: (my static ip) hosts.deny ALL : ALL

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  • Custom fail2ban Filter for phpMyadmin bruteforce attempts

    - by Michael Robinson
    In my quest to block excessive failed phpMyAdmin login attempts with fail2ban, I've created a script that logs said failed attempts to a file: /var/log/phpmyadmin_auth.log Custom log The format of the /var/log/phpmyadmin_auth.log file is: phpMyadmin login failed with username: root; ip: 192.168.1.50; url: http://somedomain.com/phpmyadmin/index.php phpMyadmin login failed with username: ; ip: 192.168.1.50; url: http://192.168.1.48/phpmyadmin/index.php Custom filter [Definition] # Count all bans in the logfile failregex = phpMyadmin login failed with username: .*; ip: <HOST>; phpMyAdmin jail [phpmyadmin] enabled = true port = http,https filter = phpmyadmin action = sendmail-whois[name=HTTP] logpath = /var/log/phpmyadmin_auth.log maxretry = 6 The fail2ban log contains: 2012-10-04 10:52:22,756 fail2ban.server : INFO Stopping all jails 2012-10-04 10:52:23,091 fail2ban.jail : INFO Jail 'ssh-iptables' stopped 2012-10-04 10:52:23,866 fail2ban.jail : INFO Jail 'fail2ban' stopped 2012-10-04 10:52:23,994 fail2ban.jail : INFO Jail 'ssh' stopped 2012-10-04 10:52:23,994 fail2ban.server : INFO Exiting Fail2ban 2012-10-04 10:52:24,253 fail2ban.server : INFO Changed logging target to /var/log/fail2ban.log for Fail2ban v0.8.6 2012-10-04 10:52:24,253 fail2ban.jail : INFO Creating new jail 'ssh' 2012-10-04 10:52:24,253 fail2ban.jail : INFO Jail 'ssh' uses poller 2012-10-04 10:52:24,260 fail2ban.filter : INFO Added logfile = /var/log/auth.log 2012-10-04 10:52:24,260 fail2ban.filter : INFO Set maxRetry = 6 2012-10-04 10:52:24,261 fail2ban.filter : INFO Set findtime = 600 2012-10-04 10:52:24,261 fail2ban.actions: INFO Set banTime = 600 2012-10-04 10:52:24,279 fail2ban.jail : INFO Creating new jail 'ssh-iptables' 2012-10-04 10:52:24,279 fail2ban.jail : INFO Jail 'ssh-iptables' uses poller 2012-10-04 10:52:24,279 fail2ban.filter : INFO Added logfile = /var/log/auth.log 2012-10-04 10:52:24,280 fail2ban.filter : INFO Set maxRetry = 5 2012-10-04 10:52:24,280 fail2ban.filter : INFO Set findtime = 600 2012-10-04 10:52:24,280 fail2ban.actions: INFO Set banTime = 600 2012-10-04 10:52:24,287 fail2ban.jail : INFO Creating new jail 'fail2ban' 2012-10-04 10:52:24,287 fail2ban.jail : INFO Jail 'fail2ban' uses poller 2012-10-04 10:52:24,287 fail2ban.filter : INFO Added logfile = /var/log/fail2ban.log 2012-10-04 10:52:24,287 fail2ban.filter : INFO Set maxRetry = 3 2012-10-04 10:52:24,288 fail2ban.filter : INFO Set findtime = 604800 2012-10-04 10:52:24,288 fail2ban.actions: INFO Set banTime = 604800 2012-10-04 10:52:24,292 fail2ban.jail : INFO Jail 'ssh' started 2012-10-04 10:52:24,293 fail2ban.jail : INFO Jail 'ssh-iptables' started 2012-10-04 10:52:24,297 fail2ban.jail : INFO Jail 'fail2ban' started When I issue: sudo service fail2ban restart fail2ban emails me to say ssh has restarted, but I receive no such email about my phpmyadmin jail. Repeated failed logins to phpMyAdmin does not cause an email to be sent. Have I missed some critical setup? Is my filter's regular expression wrong? Update: added changes from default installation Starting with a clean fail2ban installation: cp /etc/fail2ban/jail.conf /etc/fail2ban/jail.local Change email address to my own, action to: action = %(action_mwl)s Append the following to jail.local [phpmyadmin] enabled = true port = http,https filter = phpmyadmin action = sendmail-whois[name=HTTP] logpath = /var/log/phpmyadmin_auth.log maxretry = 4 Add the following to /etc/fail2ban/filter.d/phpmyadmin.conf # phpmyadmin configuration file # # Author: Michael Robinson # [Definition] # Option: failregex # Notes.: regex to match the password failures messages in the logfile. The # host must be matched by a group named "host". The tag "<HOST>" can # be used for standard IP/hostname matching and is only an alias for # (?:::f{4,6}:)?(?P<host>\S+) # Values: TEXT # # Count all bans in the logfile failregex = phpMyadmin login failed with username: .*; ip: <HOST>; # Option: ignoreregex # Notes.: regex to ignore. If this regex matches, the line is ignored. # Values: TEXT # # Ignore our own bans, to keep our counts exact. # In your config, name your jail 'fail2ban', or change this line! ignoreregex = Restart fail2ban sudo service fail2ban restart PS: I like eggs

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  • Add login / logout to drupal menu that's not a primary or secondary menu

    - by user367766
    Hello, Im trying to append an item to a menu that I created. I know its get the primary and secondary menus using "menu_secondary_local_tasks()" etc, and then add items within preprocess page. How would I go about this with a menu that I created? Here is the code I am using to check is the user is logged in... function themeName_check_login() { global $user; if ($user->uid) { print l("Log out, " . $user->name,"logout"); } else { print l("Log In ","user"); } } Thanks in advance, -Matt

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  • ASP.NET MVC Login ReturnUrl always NULL?

    - by aherrick
    Using Forms Authentication in ASP.NET MVC when trying to log back into a site, it puts a ReturnUrl parameter in the query string. My Logon action method accepts a "returnUrl" string. However it seems that returnUrl string is always null, even when it is clearly in the query string. Any thoughts on why this might be the case or a possible fix?

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  • Login Script for PostGreSQL and PHP not working =[

    - by MrEnder
    Ok I'm quite new at logins what not so bare with me here lol but I gota learn so don't discourage me. I tried this so far <?php $error = ""; $conn = pg_connect("host=localhost dbname=brittains_db user=brittains password=XXXX" ); $sql = "SELECT * FROM logins"; $result = pg_query($conn, $sql); if($_SERVER["REQUEST_METHOD"] == "GET") { $userName=""; $password=""; } else if($_SERVER["REQUEST_METHOD"] == "POST") { $userName=trim($_POST["userNameLogin"]); $password=trim($_POST["passwordLogin"]); if(pg_fetch_result($results, $userName, "userName")==true && pg_fetch_result($results, $password, "userName")==true) { setcookie("userIDforDV", $userName, time()+43200); } else { $error = "Your username and or password is incorrect"; } } $userName = $_COOKIE['userIDforDV']; if(isset($userName) && $userName!="") { echo "Welcome " . $userName; } echo $error; ?> <form> <table> <tr> <td class="signupTd"> User Name:&nbsp; </td> <td> <input type="text" name="userNameLogin" value="" size="20" /> </td> </tr> <tr> <td class="signupTd"> Password:&nbsp; </td> <td> <input type="password" name="passwordLogin" value="" size="20" /> </td> </tr> <tr> <td class="signupTd" colspan="2"> <input type="submit" name="submit" value="Submit"/> </td> </tr> </table> </form> that was the idea I came up with... but its prolly a really bad idea and it doesn't work... how might I go about this properly? I need really detailed descriptions please. Thanks a tun Shelby

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  • Windows Login Integration

    - by Dusty Roberts
    Hi Peeps. I am building facial recognition software for a certain purpose, however, as a spin-off i would like to use that same software / concept, to automatically recognize me when i sit in front of the PC, and log me in. recognition is handled.. however, i need to incorporate this into windows, the same way fingerprint logins work. where can i go to get some more info on the doing this?

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  • Making a login Using JavaScript, Will Incorporate PHP Later

    - by TIMOTHY
    not sure why my code wont work, im teaching myself javascript i know php moderatly and i also know the intelligence of using java to hold a password and username, but at the moment i just want the script to work. <html> <head> <title>34webs</title> <link rel="stylesheet" href="css/lightbox.css" type="text/css" media="screen" /> <link rel="stylesheet" type="text/css" media="screen" href="main.css"> <script type="text/javascript" src="js/prototype.js"></script> <script type="text/javascript" src="js/scriptaculous.js?load=effects,builder"></script> <script type="text/javascript" src="js/lightbox.js"></script> <script type="javascript" > function logintry (){ var usern = document.logn.username.value; var passw = document.logn.password.value; if(usern == blue && passw == bluee){ alert('password is correct!'); }else{ alert('password is wrong'); } } </script> </head> <body> <div id="bod"> <div id="nav"> <p id="buttonhead">34 web</p> <a href="#" class="button">HOME</a> <a href="#" class="button">NEWS</a> <a href="#" class="button">DOWNLOADS</a> <a href="#" class="button">ERA</a> <a href="#" class="button">IE BROWSER</a> <a href="#" class="button">DRIVERS</a> <form name="logn"> <table style="margin:0 auto; background:#0174DF; color:white;"> <tr> <td> Username<br> <input type="text" name="username" value=""> </td> </tr> <tr> <td> Password<br> <input type="password" name="password" value=""> </td> </tr> <tr> <td style="text-align:center;"> <input type="button" name="Submit" value="submit" onclick= javascript: logintry()> </td> </tr> </table> </form> </div>

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  • using a stored procedure for login in c#

    - by Jin Yim
    Hi all, If I run a store procedure with two parameter values (admin, admin) (parameters : admin, admin) I get the following message : Session_UID User_Group_Name Sys_User_Name NULLAdministratorsNTMSAdmin No rows affected. (1 row(s) returned) @RETURN_VALUE = 0 Finished running [dbo].[p_SYS_Login]. -- To get the same message in c# I used the code following : string strConnection = Settings.Default.ConnectionString; using (SqlConnection conn = new SqlConnection(strConnection)) { using (SqlCommand cmd = new SqlCommand()) { SqlDataReader rdr = null; cmd.Connection = conn; cmd.CommandText = "p_SYS_Login"; cmd.CommandType = CommandType.StoredProcedure; SqlParameter paramReturnValue = new SqlParameter(); paramReturnValue.ParameterName = "@RETURN_VALUE"; paramReturnValue.SqlDbType = SqlDbType.Int; paramReturnValue.SourceColumn = null; paramReturnValue.Direction = ParameterDirection.ReturnValue; cmd.Parameters.Add(paramReturnValue); cmd.Parameters.Add(paramGroupName); cmd.Parameters.Add(paramUserName); cmd.Parameters.AddWithValue("@Sys_Login", "admin"); cmd.Parameters.AddWithValue("@Sys_Password", "admin"); try { conn.Open(); rdr = cmd.ExecuteReader(); string test = (string)cmd.Parameters["@RETURN_VALUE"].Value; while (rdr.Read()) { Console.WriteLine("test : " + rdr[0]); } } catch (Exception ex) { string message = ex.Message; string caption = "MAVIS Exception"; MessageBoxButtons buttons = MessageBoxButtons.OK; MessageBox.Show( message, caption, buttons, MessageBoxIcon.Warning, MessageBoxDefaultButton.Button1); } finally { cmd.Dispose(); conn.Close(); } } } but I get nothing in SqlDataReader rdr ; is there something I am missing ? Thanks

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  • Login Problem Windows Authentication

    - by user109280
    Duplicate of: http://stackoverflow.com/questions/881928/windows-authentication-trusted-connection-problem I logged in the Windows Server(Machine 1) as "abc\user1 ". Windows Server machine is in abc domain. MSSQL Server is in the "abc" domain on Machine 1 and have mixed mode.authentication. It has account "abc\user1 " and "abc\user2 ". Both has role of sysadmin and serveradmin. I logged in another machine(Machine 2) using "abc\user2 ". Same Domain. Run the ant which connect to MSSQL Server. URL is formed as follows. jdbc:sqlserver://%DB_IP%:%DB_PORT%;SelectMethod=cursor;integratedSecurity=true;DatabaseName=dbname; 1) From Machine 2, If I use "abc\user2" credential for connection, then it works fine. since integratedSecurity=true. 2) From Machine 2, If I use "abc\user1" credential for connection, then it doesn't fine, since integratedSecurity=true and take System Credentials i.e "abc\user2". Even if I make integratedSecurity=false , then also it doesn't connect using "abc\user1" What changes to URL I have make to work for "abc\user1" from Machine2 for connection. what properties to be added in url? OR Driver doesn't support to use another domain\User Credentials? What need to set on MSSQL Server ?? Deepak

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  • How do I get Facebook Application Login to work

    - by Javaaaa
    I just started making an application for Facebook, however I ran into problem early on. The first step I want people to do is to give permission to access their profile. All over the web are examples of how to do this with: $user_id = $facebook->require_login(); However, this is the way it works using the Old PHP API. I have downloaded and installed the new one in my application folder and it is not working anymore. My question is (and i really have been searching for an answer for a long time) what is the code to do this with the new API? (and related question: is it better to use the old API, or learn to work with the new one when I am just starting making apps right now) I have this code now; <?php // Awesome Facebook Application // // Name: - // require_once 'facebook-php-sdk/src/facebook.php'; // Create our Application instance. $facebook = new Facebook(array( 'appId' => $app_id, 'secret' => $app_secret, 'cookie' => true )); $loginUrl = $facebook->getLoginUrl(array( 'req_perms' => 'email,user_birthday,publish_stream,sms,status_update,user_location' )); echo "<p>hello, <fb:name uid=\"$user_id\" useyou=\"false\" />!</p>"; ?>

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  • REST client website login

    - by Jordan
    I have written a REST service that uses WSSE as an authentication method but i want to be able to use this rest service through a browser by creating a website around the service. I want the user to be able to log in on the website then when they view, for example the "view users" page an ajax request is made to test.com/users and back comes the list. The part i'm trying to get my head around is the logging in/out on the website and keeping the user logged in across pages. Since in a true REST implementation there's no state held on the server, i can't use $_SESSION and now i don't know where to start! What is the best way to go about this? Do i still need to store session information on the server then possibly use cURL to make the request? Thanks Jay

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  • Searching for the right pattern to handle login data

    - by stevebot
    Hi all, I'm working on a controller that handles logins for a Web app. These logins will come from multiple clients but will all contain the same data. However, depending on the client, this data will be interpreted into common entities for our webapp differently. For instance, we have a user code that gets sent in, and in one case we may use the first four digits of the code, and in another case 12 digits of the code to map to a field on a User entity. Instead of handling this all in the controller and having big nasty if blocks of logic, I would like to use a pattern to handle how this information gets ingested into our application. What are your opinions?

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