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  • Java socket bug on linux (0xFF sent, -3 received)

    - by Marius
    While working on a WebSocket server in Java I came across this strange bug. I've reduced it down to two small java files, one is the server, the other is the client. The client simply sends 0x00, the string Hello and then 0xFF (per the WebSocket specification). On my windows machine, the server prints the following: Listening byte: 0 72 101 108 108 111 recieved: 'Hello' While on my unix box the same code prints the following: Listening byte: 0 72 101 108 108 111 -3 Instead of receiving 0xFF it gets -3, never breaks out of the loop and never prints what it has received. The important part of the code looks like this: byte b = (byte)in.read(); System.out.println("byte: "+b); StringBuilder input = new StringBuilder(); b = (byte)in.read(); while((b & 0xFF) != 0xFF){ input.append((char)b); System.out.print(b+" "); b = (byte)in.read(); } inputLine = input.toString(); System.out.println("recieved: '" + inputLine+"'"); if(inputLine.equals("bye")){ break; } I've also uploaded the two files to my server: Server.java Client.java My Windows machine is running windows 7 and my Linux machine is running Debian

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  • Why am I getting a " instance has no attribute '__getitem__' " error?

    - by Kevin Yusko
    Here's the code: class BinaryTree: def __init__(self,rootObj): self.key = rootObj self.left = None self.right = None root = [self.key, self.left, self.right] def getRootVal(root): return root[0] def setRootVal(newVal): root[0] = newVal def getLeftChild(root): return root[1] def getRightChild(root): return root[2] def insertLeft(self,newNode): if self.left == None: self.left = BinaryTree(newNode) else: t = BinaryTree(newNode) t.left = self.left self.left = t def insertRight(self,newNode): if self.right == None: self.right = BinaryTree(newNode) else: t = BinaryTree(newNode) t.right = self.right self.right = t def buildParseTree(fpexp): fplist = fpexp.split() pStack = Stack() eTree = BinaryTree('') pStack.push(eTree) currentTree = eTree for i in fplist: if i == '(': currentTree.insertLeft('') pStack.push(currentTree) currentTree = currentTree.getLeftChild() elif i not in '+-*/)': currentTree.setRootVal(eval(i)) parent = pStack.pop() currentTree = parent elif i in '+-*/': currentTree.setRootVal(i) currentTree.insertRight('') pStack.push(currentTree) currentTree = currentTree.getRightChild() elif i == ')': currentTree = pStack.pop() else: print "error: I don't recognize " + i return eTree def postorder(tree): if tree != None: postorder(tree.getLeftChild()) postorder(tree.getRightChild()) print tree.getRootVal() def preorder(self): print self.key if self.left: self.left.preorder() if self.right: self.right.preorder() def inorder(tree): if tree != None: inorder(tree.getLeftChild()) print tree.getRootVal() inorder(tree.getRightChild()) class Stack: def __init__(self): self.items = [] def isEmpty(self): return self.items == [] def push(self, item): self.items.append(item) def pop(self): return self.items.pop() def peek(self): return self.items[len(self.items)-1] def size(self): return len(self.items) def main(): parseData = raw_input( "Please enter the problem you wished parsed.(NOTE: problem must have parenthesis to seperate each binary grouping and must be spaced out.) " ) tree = buildParseTree(parseData) print( "The post order is: ", + postorder(tree)) print( "The post order is: ", + postorder(tree)) print( "The post order is: ", + preorder(tree)) print( "The post order is: ", + inorder(tree)) main() And here is the error: Please enter the problem you wished parsed.(NOTE: problem must have parenthesis to seperate each binary grouping and must be spaced out.) ( 1 + 2 ) Traceback (most recent call last): File "C:\Users\Kevin\Desktop\Python Stuff\Assignment 11\parseTree.py", line 108, in main() File "C:\Users\Kevin\Desktop\Python Stuff\Assignment 11\parseTree.py", line 102, in main tree = buildParseTree(parseData) File "C:\Users\Kevin\Desktop\Python Stuff\Assignment 11\parseTree.py", line 46, in buildParseTree currentTree = currentTree.getLeftChild() File "C:\Users\Kevin\Desktop\Python Stuff\Assignment 11\parseTree.py", line 15, in getLeftChild return root[1] AttributeError: BinaryTree instance has no attribute '__getitem__'

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  • Issue with getting 2 chars from string using indexer

    - by Learner
    I am facing an issue in reading char values. See my program below. I want to evaluate an infix expression. As you can see I want to read '10' , '*', '20' and then use them...but if I use string indexer s[0] will be '1' and not '10' and hence I am not able to get the expected result. Can you guys suggest me something? Code is in c# class Program { static void Main(string[] args) { string infix = "10*2+20-20+3"; float result = EvaluateInfix(infix); Console.WriteLine(result); Console.ReadKey(); } public static float EvaluateInfix(string s) { Stack<float> operand = new Stack<float>(); Stack<char> operator1 = new Stack<char>(); int len = s.Length; for (int i = 0; i < len; i++) { if (isOperator(s[i])) // I am having an issue here as s[i] gives each character and I want the number 10 operator1.Push(s[i]); else { operand.Push(s[i]); if (operand.Count == 2) Compute(operand, operator1); } } return operand.Pop(); } public static void Compute(Stack<float> operand, Stack<char> operator1) { float operand1 = operand.Pop(); float operand2 = operand.Pop(); char op = operator1.Pop(); if (op == '+') operand.Push(operand1 + operand2); else if(op=='-') operand.Push(operand1 - operand2); else if(op=='*') operand.Push(operand1 * operand2); else if(op=='/') operand.Push(operand1 / operand2); } public static bool isOperator(char c) { bool result = false; if (c == '+' || c == '-' || c == '*' || c == '/') result = true; return result; } } }

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  • Changing associativity

    - by Sorush Rabiee
    Hi... The associativity of stream insertion operator is rtl, forgetting this fact sometimes cause to runtime or logical errors. for example: 1st- int F() { static int internal_counter c=0; return ++c; } in the main function: //....here is main() cout<<”1st=”<<F()<<”,2nd=”<<F()<<”,3rd=”<<F(); and the output is: 1st=3,2nd=2,3rd=1 that is different from what we expect at first look. 2nd- suppose that we have an implementation of stack data structure like this: // //... a Stack<DataType> class …… // Stack<int> st(10); for(int i=1;i<11;i++) st.push(i); cout<<st.pop()<<endl<<st.pop()<<endl<<st.pop()<<endl<<st.pop()<<endl; expected output is something like: 10 9 8 7 but we have: 7 8 9 10 There is no internal bug of << implementation but it can be so confusing... and finally[:-)] my question: is there any way to change assocativity of an operator by overloading it?

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  • Is there some advantage to filling a stack with nils and interpreting the "top" as the last non-nil value?

    - by dwilbank
    While working on a rubymonk exercise, I am asked to implement a stack with a hard size limit. It should return 'nil' if I try to push too many values, or if I try to pop an empty stack. My solution is below, followed by their solution. Mine passes every test I can give it in my IDE, while it fails rubymonk's test. But that isn't my question. Question is, why did they choose to fill the stack with nils instead of letting it shrink and grow like it does in my version? It just makes their code more complex. Here's my solution: class Stack def initialize(size) @max = size @store = Array.new end def pop empty? ? nil : @store.pop end def push(element) return nil if full? @store.push(element) end def size @store.size end def look @store.last end private def full? @store.size == @max end def empty? @store.size == 0 end end and here is the accepted answer class Stack def initialize(size) @size = size @store = Array.new(@size) @top = -1 end def pop if empty? nil else popped = @store[@top] @store[@top] = nil @top = @top.pred popped end end def push(element) if full? or element.nil? nil else @top = @top.succ @store[@top] = element self end end def size @size end def look @store[@top] end private def full? @top == (@size - 1) end def empty? @top == -1 end end

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  • Intel IA-32 Assembly

    - by Kay
    I'm having a bit of difficulty converting the following java code into Intel IA-32 Assembly: class Person() { char name [8]; int age; void printName() {...} static void printAdults(Person [] list) { for(int k = 0; k < 100; k++){ if (list[k].age >= 18) { list[k].printName(); } } } } My attempt is: Person: push ebp; save callers ebp mov ebp, esp; setup new ebp push esi; esi will hold name push ebx; ebx will hold list push ecx; ecx will hold k init: mov esi, [ebp + 8]; mov ebx, [ebp + 12]; mov ecx, 0; k=0 forloop: cmp ecx, 100; jge end; if k>= 100 then break forloop cmp [ebx + 4 * ecx], 18 ; jl auxloop; if list[k].age < 18 then go to auxloop jmp printName; printName: auxloop: inc ecx; jmp forloop; end: pop ecx; pop ebx; pop esi; pop ebp; Is my code correct? NOTE: I'm not allowed to use global variables.

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  • How to use void*

    - by Rondogiannis Aristophanes
    I am imlementing a simple merge function and I have got stuck, as the compiler gives me errors that I cannot explain. Here is my merge function: void merge(void *a, int beg, int middle, int end, int (*cmp)(const void*, const void* { std::stack<void*> first; std::stack<void*> second; for(int i = beg; i < middle; i++) { first.push(a+i); } for(int i = middle; i < end; i++) { second.push(a+i); } for(int i = beg; i < end; i++) { if(first.empty()) { void *tmp = second.top(); second.pop(); a+i = tmp; } else if(second.empty()) { void *tmp = first.top(); first.pop(); a+i = tmp; } else if(cmp(first.top(), second.top())) { void *tmp = first.top(); first.pop(); a+i = tmp; } else { void *tmp = second.top(); second.pop(); a+i = tmp; } } } And here is the error: sort.h: In function `void merge(void*, int, int, int, int (*)(const void*, const void*))': sort.h:9: error: pointer of type `void *' used in arithmetic sort.h:12: error: pointer of type `void *' used in arithmetic sort.h:19: error: pointer of type `void *' used in arithmetic sort.h:19: error: non-lvalue in assignment sort.h:23: error: pointer of type `void *' used in arithmetic sort.h:23: error: non-lvalue in assignment sort.h:27: error: pointer of type `void *' used in arithmetic sort.h:27: error: non-lvalue in assignment sort.h:31: error: pointer of type `void *' used in arithmetic sort.h:31: error: non-lvalue in assignment Can anyone help me? TIA.

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  • How do I create an "iframe popup" when I hover over an <a> tag?

    - by Angela
    Here is the scenario: a User will see a list of company names, each wrapped in an tag. He is able to see dynamic information and as he hover over each name and then make a request. So Given a list of companies, each wrapped in an tag. When the cursor hovers over an tag Then a "pop-up" appears that contains an -based, dynamic content. Given the pop-up When the User clicks on the "submit" button in the pop-up Then the form (based on the framework" is submitted and ajax displays "request succesful" So, because I am using a php-framework, I'd like to use iframe to contain the form. Some challenges: When the cursor is no longer hovering over the tag, the hover disappears. How do I keep it operating? How do I make it appear in an so I can have full form-submission and POST-ing dynamic values through the URL? How do the "popup" disappear when the cursor is no longer on either the -tag or the pop-up itself? Can I do it without loading a bunch of 's onto the page, because the list of companies could be long.

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  • In Google Chrome, how do I bring an existing popup window to the front using javascript from the par

    - by brahn
    I would like to have a button on a web page with the following behavior: On the first click, open a pop-up. On later clicks, if the pop-up is still open, just bring it to the front. If not, re-open. The below code works in Firefox (Mac & Windows), Safari (Mac & Windows), and IE8. (I have not yet tested IE6 or IE7.) However, in Google Chrome (both Mac & Windows) later clicks fail to bring the existing pop-up to the front as desired. How can I make this work in Chrome? <head> <script type="text/javascript"> var popupWindow = null; var doPopup = function () { if (popupWindow && !popupWindow.closed) { popupWindow.focus(); } else { popupWindow = window.open("http://google.com", "_blank", "width=200,height=200"); } }; </script> </head> <body> <button onclick="doPopup(); return false"> create a pop-up </button> </body> Background: I am re-asking this question specifically for Google Chrome, as I think I my code solves the problem at least for other modern browsers and IE8. If there is a preferred etiquette for doing so, please let me know.

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  • In Firefox, how to bring an existing popup window with multiple tabs to the front using javascript f

    - by brahn
    I would like to have a button on a web page with the following behavior: On the first click, open a pop-up. On later clicks, if the pop-up is still open, just bring it to the front. If not, re-open. The below code generally works in Firefox, Safari, and IE8 (see here for Chrome woes). However, I have found a failure mode in Firefox that I don't know how to deal with: If for some reason the user has opened a second tab in the pop-up window and that second tab has focus within that window, the popupWindow.focus() command fails to have any effect. (If the first tab has focus within that window, everything works just great.) So, how can I focus the popup and the desired tab in Firefox? <head> <script type="text/javascript"> var popupWindow = null; var doPopup = function () { if (popupWindow && !popupWindow.closed) { popupWindow.focus(); } else { popupWindow = window.open("http://google.com", "_blank", "width=200,height=200"); } }; </script> </head> <body> <button onclick="doPopup(); return false"> create a pop-up </button> </body> Background: I am re-asking this question specifically for Google Chrome, as I think I my code solves the problem at least for other modern browsers and IE8. If there is a preferred etiquette for doing so, please let me know.

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  • In Firefox, how do I bring an existing popup window with multiple tabs to the front using javascript

    - by brahn
    I would like to have a button on a web page with the following behavior: On the first click, open a pop-up. On later clicks, if the pop-up is still open, just bring it to the front. If not, re-open. The below code generally works in Firefox, Safari, and IE8 (see here for Chrome woes). However, I have found a failure mode in Firefox that I don't know how to deal with: If for some reason the user has opened a second tab in the pop-up window and that second tab has focus within that window, the popupWindow.focus() command fails to have any effect. (If the first tab has focus within that window, everything works just great.) So, how can I focus the popup and the desired tab in Firefox? <head> <script type="text/javascript"> var popupWindow = null; var doPopup = function () { if (popupWindow && !popupWindow.closed) { popupWindow.focus(); } else { popupWindow = window.open("http://google.com", "_blank", "width=200,height=200"); } }; </script> </head> <body> <button onclick="doPopup(); return false"> create a pop-up </button> </body>

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  • Getting Started with Boxee

    - by DigitalGeekery
    Boxee is a free Media PC application that runs on Windows, Mac, and Ubuntu Linux. With Boxee, you can integrate online video, music and pictures, with your own local media and social networking. Today we are going to take a closer look at Boxee and some of it’s features. Note: We used Windows 7 for this tutorial. Your experience on a Mac or Ubuntu Linux build may vary slightly. Hardware Requirements x86 (Intel/AMD processor) based system running at 1.0GHz or greater 512MB system memory (RAM) or more Video card capable of OpenGL 1.4, Direct X 9.0 Software Requirements Mac OS X 10.4+ (Intel based processor) Ubuntu Linux 9.04+ x86 only Windows XP / Vista / 7 (64 bit in Vista or 7) Installing Boxee Before downloading and installing Boxee, you’ll need to register for a free account. (See link below) Once your account is registered and verified, you’ll be able to log in and download the application. Installation is pretty straightforward…just take the defaults. Boxee will open in full screen mode and you’ll be prompted to login with your username and password. Before you login, you may want to take a moment to click on the “Guide” icon and learn a bit about navigating in Boxee. Some basic keyboard navigation is as follows. Move right, left, up, & down with the arrow keys. Hit “Enter” to make a selection, the forward slash key “\” to toggle between full screen and windowed mode, and “Esc” to go back to the previous screen. For Playback, the volume is controlled by plus & minus (+/-) keys, you can Play / Pause using the spacebar, and skip using the arrow keys. Boxee will also work with any infrared remote. If you have an iPhone or iPod Touch you can download software to enable them as a Boxee remote. If you’re using a mouse and keyboard, hover over the username and password boxes to enter your login credentials. If using a a remote, click your OK button and enter credentials with the on screen keyboard. Click “Done” when finished.   When you are ready to login, enter your credentials and click “Login.” On first login, you’ll be prompted to calibrate your screen. If you choose “Skip” you can always calibrate your screen later under Settings > Appearance > Screen. When Boxee opens, you’ll be greeted by the Home screen. To the left will be your Feeds. This will be any recommended content from friends on Boxee, and social networks such as Facebook and Twitter. Although, when you first login, it will mainly be info from the Boxee staff. You’ll have “Featured” content in the center and your Queue on the right. You’ll also have the Menu along the top.   Pop Up Menu The Pop Menu can be accessed by hitting the “Esc” key, or back on your remote. Depending on where you are located in Boxee, you may have to hit it a few time to “back out” to the Pop Up menu. From the Pop Up Menu, you can easily access any of the resources, settings, and favorites. Queue The Queue is your playlist of TV shows, movies, or Internet videos you wish to watch. When you find an offering you’d like to watch, select it and then click “Add to Queue.” The selected item will be added to your Queue and can be accessed at any time from the Menu. TV Show Library The TV Show library can contain files from your local hard drive or streaming content from the Web. Boxee pulls content from a variety of online locations such as Hulu and TV network sites. Click on the show to see which specific episodes are currently available. To search for your favorite shows, click on the yellow arrow to the left, or navigate to the left with your keyboard or remote. Enter your selection into the search box. My Apps By default, the “My Apps” section includes a list of the most popular apps, such as Netflix, Pandora, YouTube, and others. You can remove Apps from “My Apps,” or add new Apps from the Apps Library.   To access all the available Apps, click on the left arrow button, or click on the yellow arrow at the left, then select “App Library.” Choose an App from the Library and click it to open… … and then select “Add to My Apps.” Or, you can click start to play the App if you don’t wish to Add it to your “My Apps.”   Music, Pictures, and Movies Boxee will scan your PC for movies, pictures, and music. You can choose to scan specific folders by clicking on “Scan Media Folders…” … or from the Pop Up Menu, selecting Settings > Media, and then browsing for your media.   Conclusion Boxee to be a great way to integrate your local media with online streaming content. It can be run as an application on your home PC, or as a stand alone media PC. It should also be noted, however, that your access to online content will vary depending on your country. If you are a Windows Media Center user and and want to add the additional features of Boxee, check out our article on integrating Boxee with Windows 7 Media Center. Download Boxee Similar Articles Productive Geek Tips Integrate Boxee with Media Center in Windows 7Disable Fast User Switching on Windows XPOops! Sorry About the Feed ErrorsDisplay a list of Started Services from the Command Line (Windows)Feedburner to Google: Worst Transition Ever. TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Discover New Bundled Feeds in Google Reader Play Music in Chrome by Simply Dragging a File 15 Great Illustrations by Chow Hon Lam Easily Sync Files & Folders with Friends & Family Amazon Free Kindle for PC Download Stretch popurls.com with a Stylish Script (Firefox)

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  • Web page change monitoring for Mac OS X

    - by brucethehoon
    There is a site that I need to monitor for changes and pop an alarm if the change is over a certain threshold. Ideally it would use Growl to pop the notification but I'm open to alternatives. If there is an application out there that does this for purchase, I'll just buy it. If not, pointers to any Linux / Java / other recompilables that I could just add Growl support to would be very helpful!

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  • How to reduce the Windows 7 menu expansion delay?

    - by ChrisA
    Ok, so you hover over the items pinned to the Win 7 menu, and wait all month for it to pop out the sub menu containing recent items opened with the selected app. Is there a registry hack to speed this up? I want the sub menus quicker. Same applies to the delay before things Control Panel and Administrative Tools pop out their sub menus too. It just takes too long, so how to reduce that delay?

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  • How to determine the UID of a message in IMAP

    - by Emanuel
    I'm working in a mail client project using C#. I'm using both the POP and IMAP protocol to communicate with the server. The problem is than I can not figure out why when I want to get the UID for a message the result from the POP server and the IMAP server are different. POP C: UIDL 1 S: +OK 1 UID2-1269789826 and IMAP C: $ FETCH 1 (UID) S: * 1 FETCH (UID 2) S: $ OK Fetch completed. Why the result for obtaining the UID is so different? In IMAP is another function for this? Any help is welcome. Thanks.

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  • x86 Assembly Question about outputting

    - by jdea
    My code looks like this _declspec(naked) void f(unsigned int input,unsigned int *output) { __asm{ push dword ptr[esp+4] call factorial pop ecx mov [output], eax //copy result ret } } __declspec(naked) unsigned int factorial(unsigned int n) { __asm{ push esi mov esi, dword ptr [esp+8] cmp esi, 1 jg RECURSE mov eax, 1 jmp END RECURSE: dec esi push esi call factorial pop esi inc esi mul esi END: pop esi ret } } Its a factorial function and I'm trying to output the answer after it recursively calculates the number that was passed in But what I get returned as an output is the same large number I keep getting Not sure about what is wrong with my output, by I also see this error CXX0030: Error: expression cannot be evaluated Thanks!

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  • AutoCompleteExtender positioning menu incorrectly when scrolled

    - by Colin
    We have an AutoCompleteExtender linked to a TextBox. Both controls are placed inside an UpdatePanel, and the UpdatePanel is displayed as a pop-up dialog using a Javascript library (Ext.BasicDialog). The pop-up is a div on the page, not a separate window. The problem is that when the user scrolls inside the pop-up, the AutoCompleteExtender shows its menu in the wrong place. It looks like it is taking the visible distance from the top of the popup and positioning the menu from the top of the inner html of the popup (which is not visible) We are using Version 1.0.20229.20821 of the AjaxControlToolkit, and we are targetting ASP.NET Framework vewrsion 2.0. I have tried to fix the menu by attaching the following Javascript to the OnClientShown event, but it pretty much does the same thing: function resetPosition(object, args) { var tb = object._element; // tb is the associated textbox. var offset = $('#' + tb.id).offset(); var ex = object._completionListElement; if (ex) { $('#' + ex.id).offset(offset); } }

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  • Browser popup blocker blocking jasper reports generated from flex

    - by pietervn
    Hi all, I have a flex application that uses navigateToURL() to call a servlet. The servlet in turn generates a JasperReport and then uses exportReport() to show the report in a new browser tab. Now, my problem is this. I want to generate multiple reports at once, each opening in its own tab. It all works fine except that in Firefox the built in browser pop-up blocker sees every new tab that is opened after the first report tab as a pop-up. It blocks this and is giving me endless headaches. I also tried this in IE8, Safari, Chrome and Opera with no problems. Any help as to how I can get past the Firefox pop-up blocker would be much appreciated. Pieter

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  • jquery trigger hover on anchor

    - by Ori Gavriel Refael
    im using jqurey to develop in web enviorment. i want to know why $("#a#trigger").trigger('mouseenter'); $("#a#trigger").trigger('hover'); $("#a#trigger").trigger('mouseover'); all 3 of those aren't working to active a hover function i have. $(function() { $('a#trigger').hover(function(e) { $('div#pop-up').show(); }, function() { $('div#pop-up').hide(); }); }); }); a#trigger is the name of the anchor, and #pop-up is a div element in my web. problem is, that i want to mouse over some event in FullCalendar plugin and those functions aint working. Thanks.

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  • Is there a security issue with using javascript to manipulate cookies?

    - by Scarface
    Hey guys, another quick question for the experts. I have an alert box that displays updates processed in php to the user just like this site. I want to make it so that if the user closes the box, then it will not pop up for another 5 minutes (unless they check the messages then it will not pop up because the entries that cause the pop up are deleted in the database). On the close of the box I was thinking of giving the user a javascript cookie, since the alert box is done in javascript. I was wondering if this was a bad coding practice, since I am kind of unfamiliar with cookies and was warned against them before. If anyone has any advice or can recommend a better way, I would really appreciate it.

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  • Is there a security issue with using javascript cookies?

    - by Scarface
    Hey guys, another quick question for the experts. I have an alert box that displays updates processed in php to the user just like this site. I want to make it so that if the user closes the box, then it will not pop up for another 5 minutes (unless they check the messages then it will not pop up because the entries that cause the pop up are deleted in the database). On the close of the box I was thinking of giving the user a javascript cookie, since the alert box is done in javascript. I was wondering if this was a bad coding practice, since I am kind of unfamiliar with cookies and was warned against them before. If anyone has any advice or can recommend a better way, I would really appreciate it.

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  • datagrid column issue with MouseEnter events

    - by prince23
    hi, i have 3 data grid placed working fine with expand and collapse. now i have an requirement where i have an grid with four columns starting from name age mailId address once user moves mouse over the *name column only. i need to call the MouseEnter Event* here i am showing an pop grid whereas when i move mouse over the other columns like i need call the MouseLeave Event here i need to hide the pop grid right now once user click on the row on any column values i am showing an pop up grid with all the details of that row. here i am using Selection Changed Event is there any way i can achieve this functionality like on move mouse over only the first column need to display the data and call the mouse events thanks in advance looking for an help. i am at few steps away from the solution let me know how to solve it. prince

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  • I'm an idiot/blind and I can't find why I'm getting a list index error. Care to take a look at these 20 or so lines?

    - by Meff
    Basically it's supposed to take a set of coordinates and return a list of coordinates of it's neighbors. However, when it hits here:if result[i][0] < 0 or result[i][0] >= board.dimensions: result.pop(i) when i is 2, it gives me an out of index error. I can manage to have it print result[2][0] but at the if statement it throws the errors. I have no clue how this is happening and if anyone could shed any light on this problem I'd be forever in debt. def neighborGen(row,col,board): """ returns lists of coords of neighbors, in order of up, down, left, right """ result = [] result.append([row-1 , col]) result.append([row+1 , col]) result.append([row , col-1]) result.append([row , col+1]) #prune off invalid neighbors (such as (0,-1), etc etc) for i in range(len(result)): if result[i][0] < 0 or result[i][0] >= board.dimensions: result.pop(i) if result[i][1] < 0 or result[i][1] >= board.dimensions: result.pop(i) return result

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