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  • SQL SERVER – Fix: Error: 10920 Cannot drop user-defined function. It is being used as a resource governor classifier

    - by pinaldave
    If you have not read my SQL SERVER – Simple Example to Configure Resource Governor – Introduction to Resource Governor yesterday’s detailed primer on Resource Governor, I suggest you go ahead and read it before continuing this article. After reading the article the very first email I received was as follows: “Pinal, I configured resource governor on my development server and it worked fine with tests I ran. After doing some tests, I decided to remove the resource governor and as a first step I disabled it however, I was not able to drop the classification function during the process of the clean up. It was continuously giving me following error. Msg 10920, Level 16, State 1, Line 1 Cannot drop user-defined function myudfname. It is being used as a resource governor classifier. Would you please give me solution?” The original email was really this short and there is no other information. I am glad he has done experiments on development server and not on the production server. Production server must not be the playground of the experiments. I think I have covered the answer of this error in an earlier blog post. If the user disables the Resource Governor it is still not possible to drop the function because it can be enabled again and when enabled it can still use the same function. Here is the simple resolution of the how one can drop the classifier function (do this only if you are not going to use the function). The reason the classifier function can’t be dropped because it is associated with resource governor. Create a new classified function for your resource governor or just assign NULL as described in the following T-SQL Script and you will be able to drop the function without error. ALTER RESOURCE GOVERNOR WITH (CLASSIFIER_FUNCTION = NULL) GO ALTER RESOURCE GOVERNOR DISABLE GO DROP FUNCTION dbo.UDFClassifier GO I am glad that user asked me question instead of doing something radically different, which can leave the server in the unusable state. I am aware of this only method to avoid this error. Is there any better way to achieve the same? Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Error Messages, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • ASP.NET 3.5 Loop Control Structures Using Visual Basic

    Loop statements are one of the most important control structures in any programming language. Control structures are used to control or alter the flow of the program depending on a given situation. This article acquaints you with the most important loop statements and how to use them when developing ASP.NET web applications.... Microsoft Exchange Server 2010 Simplify Administration and Deployment of Messaging - Free Download.

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  • How do you version/track changes to SQL tables?

    - by gabe.
    When working in a team of developers, where everyone is making changes to local tables, and development tables, how do you keep all the changes in sync? A central log file where everyone keeps their sql changes? A wiki page to track alter table statements, individual .sql files that the devs can run to bring their local db's to the latest version? I've used some of these solutions, and I'm tyring to get a good solid solution together that works, so I'd appreciate your ideas.

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  • Adding Column to a SQL Server Table

    - by Dinesh Asanka
    Adding a column to a table is  common task for  DBAs. You can add a column to a table which is a nullable column or which has default values. But are these two operations are similar internally and which method is optimal? Let us start this with an example. I created a database and a table using following script: USE master Go --Drop Database if exists IF EXISTS (SELECT 1 FROM SYS.databases WHERE name = 'AddColumn') DROP DATABASE AddColumn --Create the database CREATE DATABASE AddColumn GO USE AddColumn GO --Drop the table if exists IF EXISTS ( SELECT 1 FROM sys.tables WHERE Name = 'ExistingTable') DROP TABLE ExistingTable GO --Create the table CREATE TABLE ExistingTable (ID BIGINT IDENTITY(1,1) PRIMARY KEY CLUSTERED, DateTime1 DATETIME DEFAULT GETDATE(), DateTime2 DATETIME DEFAULT GETDATE(), DateTime3 DATETIME DEFAULT GETDATE(), DateTime4 DATETIME DEFAULT GETDATE(), Gendar CHAR(1) DEFAULT 'M', STATUS1 CHAR(1) DEFAULT 'Y' ) GO -- Insert 100,000 records with defaults records INSERT INTO ExistingTable DEFAULT VALUES GO 100000 Before adding a Column Before adding a column let us look at some of the details of the database. DBCC IND (AddColumn,ExistingTable,1) By running the above query, you will see 637 pages for the created table. Adding a Column You can add a column to the table with following statement. ALTER TABLE ExistingTable Add NewColumn INT NULL Above will add a column with a null value for the existing records. Alternatively you could add a column with default values. ALTER TABLE ExistingTable Add NewColumn INT NOT NULL DEFAULT 1 The above statement will add a column with a 1 value to the existing records. In the below table I measured the performance difference between above two statements. Parameter Nullable Column Default Value CPU 31 702 Duration 129 ms 6653 ms Reads 38 116,397 Writes 6 1329 Row Count 0 100000 If you look at the RowCount parameter, you can clearly see the difference. Though column is added in the first case, none of the rows are affected while in the second case all the rows are updated. That is the reason, why it has taken more duration and CPU to add column with Default value. We can verify this by several methods. Number of Pages The number of data pages can be obtained by using DBCC IND command. Though, this an undocumented dbcc command, many experts are ok to use this command in production. However, since there is no official word from Microsoft, use this “at your own risk”. DBCC IND (AddColumn,ExistingTable,1) Before Adding the Columns 637 Adding a Column with NULL 637 Adding a column with DEFAULT value 1270 This clearly shows that pages are physically modified. Please note, a high value indicated in the Adding a column with DEFAULT value  column is also a result of page splits. Continues…

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  • Powershell, SMO and Database Files

    - by dbaduck
    In response to some questions about renaming a physical file for a database, I have 2 versions of Powershell scripts that do this for you, including taking the database offline and then online to make the physical change match the meta-data. First, there is an article about this at http://msdn.microsoft.com/en-us/library/ms345483.aspx . This explains that you start by setting the database offline, then alter the database and modify the filename then set it back online. This particular article does...(read more)

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  • More on PHP and Oracle 11gR2 Improvements to Client Result Caching

    - by christopher.jones
    Oracle 11.2 brought several improvements to Client Result Caching. CRC is way for the results of queries to be cached in the database client process for reuse.  In an Oracle OpenWorld presentation "Best Practices for Developing Performant Application" my colleague Luxi Chidambaran had a (non-PHP generated) graph for the Niles benchmark that shows a DB CPU reduction up to 600% and response times up to 22% faster when using CRC. Sometimes CRC is called the "Consistent Client Cache" because Oracle automatically invalidates the cache if table data is changed.  This makes it easy to use without needing application logic rewrites. There are a few simple database settings to turn on and tune CRC, so management is also easy. PHP OCI8 as a "client" of the database can use CRC.  The cache is per-process, so plan carefully before caching large data sets.  Tables that are candidates for caching are look-up tables where the network transfer cost dominates. CRC is really easy in 11.2 - I'll get to that in a moment.  It was also pretty easy in Oracle 11.1 but it needed some tiny application changes.  In PHP it was used like: $s = oci_parse($c, "select /*+ result_cache */ * from employees"); oci_execute($s, OCI_NO_AUTO_COMMIT); // Use OCI_DEFAULT in OCI8 <= 1.3 oci_fetch_all($s, $res); I blogged about this in the past.  The query had to include a specific hint that you wanted the results cached, and you needed to turn off auto committing during execution either with the OCI_DEFAULT flag or its new, better-named alias OCI_NO_AUTO_COMMIT.  The no-commit flag rule didn't seem reasonable to me because most people wouldn't be specific about the commit state for a query. Now in Oracle 11.2, DBAs can now nominate tables for caching, either with CREATE TABLE or ALTER TABLE.  That means you don't need the query hint anymore.  As well, the no-commit flag requirement has been lifted.  Your code can now look like: $s = oci_parse($c, "select * from employees"); oci_execute($s); oci_fetch_all($s, $res); Since your code probably already looks like this, your DBA can find the top queries in the database and simply tune the system by turning on CRC in the database and issuing an ALTER TABLE statement for candidate tables.  Voila. Another CRC improvement in Oracle 11.2 is that it works with DRCP connection pooling. There is some fine print about what is and isn't cached, check the Oracle manuals for details.  If you're using 11.1 or non-DRCP "dedicated servers" then make sure you use oci_pconnect() persistent connections.  Also in PHP don't bind strings in the query, although binding as SQLT_INT is OK.

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  • Avoid SQL Injection with Parameters

    - by simonsabin
    The best way to avoid SQL Injection is with parameters. With parameters you can’t get SQL Injection. You only get SQL Injection where you are building a SQL statement by concatenating your parameter values in with your SQL statement. Annoyingly many TSQL statements don’t take parameters, CREATE DATABASE for instance, or really annoyingly ALTER USER. In these situations you have to rely on using QUOTENAME or REPLACE to avoid SQL Injection. (Kimberly Tripp takes about this in her recent blog post Little...(read more)

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  • What schema documentation tools exist for PostgreSQL

    - by Brad Koch
    MySQL has MySQL Workbench for designing and documenting your schema, and generates CREATE and ALTER scripts based on your design. We're looking at migrating to PostgreSQL in the near future, and we do need a practical way of documenting and modifying the schema structure. What similar tools exist for Postgres (that are OS X/Linux compatible)? Alternatively, what equivalent conventions would be followed for designing and documenting the structure of your Postgres database?

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  • But what version is the database now?

    - by BuckWoody
    When you upgrade your system to SQL Server 2008 R2, you’ll know that the instance is at that version by using the standard commands like SELECT @@VERSION or EXEC xp_msver. My system came back with this info when I typed those: Microsoft SQL Server 2008 R2 (RTM) - 10.50.1600.1 (Intel X86)   Apr  2 2010 15:53:02   Copyright (c) Microsoft Corporation  Developer Edition on Windows NT 6.0 <X86> (Build 6002: Service Pack 2) (Hypervisor) Index Name Internal_Value Character_Value 1 ProductName NULL Microsoft SQL Server 2 ProductVersion 655410 10.50.1600.1 3 Language 1033 English (United States) 4 Platform NULL NT INTEL X86 5 Comments NULL SQL 6 CompanyName NULL Microsoft Corporation 7 FileDescription NULL SQL Server Windows NT 8 FileVersion NULL 2009.0100.1600.01 ((KJ_RTM).100402-1540 ) 9 InternalName NULL SQLSERVR 10 LegalCopyright NULL Microsoft Corp. All rights reserved. 11 LegalTrademarks NULL Microsoft SQL Server is a registered trademark of Microsoft Corporation. 12 OriginalFilename NULL SQLSERVR.EXE 13 PrivateBuild NULL NULL 14 SpecialBuild 104857601 NULL 15 WindowsVersion 393347078 6.0 (6002) 16 ProcessorCount 1 1 17 ProcessorActiveMask 1 1 18 ProcessorType 586 PROCESSOR_INTEL_PENTIUM 19 PhysicalMemory 2047 2047 (2146934784) 20 Product ID NULL NULL   But a database properties are separate from the Instance. After an upgrade, you always want to make sure that the compatibility options (which have much to do with how NULLs and other objects are treated) is at what you expect. For the most part, as long as the application can handle it, I set my compatibility levels to the latest version. For SQL Server 2008, that was “10.0” or “10”. You can do this with the ALTER DATABASE command or you can just right-click the database and select “Properties” and then “Database Options” in SQL Server Management Studio. To check the database compatibility level, I use this query: SELECT name, cmptlevel FROM sys.sysdatabases When I did that this morning I saw that the databases (all of them) were at 10.0 – not 10.5 like the Instance. That’s expected – we didn’t revise the database format up with the Instance for this particular release. Didn’t want to catch you by surprise on that. While your databases should be at the “proper” level for your situation, you can’t rely on the compatibility level to indicate the Instance level. More info on the ALTER DATABASE command in SQL Server 2008 R2 is here: http://technet.microsoft.com/en-us/library/bb510680(SQL.105).aspx Share this post: email it! | bookmark it! | digg it! | reddit! | kick it! | live it!

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  • How to make sure you see the truth with Management Studio

    - by fatherjack
    LiveJournal Tags: TSQL,How To,SSMS,Tips and Tricks Did you know that SQL Server Management Studio can mislead you with how your code is performing? I found a query that was using a scalar function to return a date and wanted to take the opportunity to remove it in favour of a table valued function that would be more efficient. The original function was simply returning the start date of the current financial year. The code we were using was: ALTER  FUNCTION...(read more)

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  • quickly package --extras doesn't produce /opt/extras.ubuntu.com/../share/locale

    - by user75704
    I'm trying to package an app to /opt, but when installed the app won't run and complains: Traceback (most recent call last): File "/opt/extras.ubuntu.com/drawers/bin/drawers", line 45, in <module> import drawers File "/opt/extras.ubuntu.com/drawers/drawers/__init__.py", line 21, in <module> locale.bindtextdomain('drawers', '/opt/extras.ubuntu.com/drawers/share/locale') NameError: name 'locale' is not defined I can't figure out what I need to change. Is there a config file I need to alter?

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  • Performing a clean database build with MSBuild part 2

    - by Robert May
    In part 1, I showed a complicated mechanism for performing a clean database build. There’s an easier way.  The easier way is to use the msbuild extension tasks out on codeplex.  While you’ll still need to forcibly take the database offline (ALTER DATABASE [mydb] SET OFFLINE WITH ROLLBACK IMMEDIATE), the other msbuild tasks more easily allow you to create and delete the database.  Eventually, I’ll post an example. Technorati Tags: MSBuild

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  • SSIS object search using T-SQL

    Easily determining what objects are located in all your SSIS packages can be a challenging endeavor. James Greaves brings us a technique that can help you determine which packages might need to be changed based on objects you alter in your database.

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  • Geek City: What gets logged for index rebuild operations?

    - by Kalen Delaney
    This blog post was inspired by a question from a future student. Someone who was already booked for my SQL Server Internals class in June asked for some information on a current problem he was having with transaction log writes causing excessive wait times during index rebuild operations when run in ONLINE mode. He wanted to know if switching to BULK_LOGGED recovery could help. I knew the difference between ALTER INDEX in FULL vs BULK_LOGGED recovery when doing normal OFFLINE rebuilds, but I wasn't...(read more)

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  • What parts of functionality should be refactored into a directive?

    - by Sprottenwels
    I am creating an application from legacy code using AngularJS. I wonder what parts of my code should be moved into a directive. For example, iI had thought of moving a table which is used multiple times across the application into a directive. The tables alter from headings and size. Is it worth the effort or even a good practice to turn such things into their own directives or should I create each table in a unique way?

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  • Resolving "Error accessing a table..." Error

    Are you encountering an error message during DB2 database startup? Or during the execution of Alter Tablespace SQL command? If ';yes';, then the three possible reasons for the error message are, contai... [Author: Mark Willium - Computers and Internet - May 13, 2010]

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  • Banshee won't play correct tracks

    - by Jaykay55
    I've just installed Banshee on Ubuntu 10.04 LTS, and manually imported 2 CDs. I needed to manually insert the track information as I haven't figured out how to access an online database. When I try to play track 17 from CD1, it always plays track 17 from CD2. The metadata should have been enough to differentiate between these tracks. How do I manually alter what is recorded in Banshee's database?

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  • Whar parts of functionality should be refactored into a directive? [AngularJS]

    - by Sprottenwels
    I am creating an application from legacy code using AngularJS. I wonder what parts of my code should be moved into a directive. For example, i had thought of moving a table which is used multiple times across the application into a directive. The tables alter from headings and size. Is it worth the effort or even a good practice to turn such things into their own directives or should i create each table in a unique way?

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  • Change Windows Authentication user for Sql Server Management Studio

    - by Asmor
    We're using Sql Server 2005 with Windows Authentication setup. So normally, when you log in using e.g. Sql Server Management Studio, it forces you to log in at MACHINE_NAME\Username. Anyways, on this one particular computer, the person said they had to make a new account called User01 to do something and showed me where she'd created it under security in the "master" system database. And so now when she logs in, it's listed as MACHINE_NAME\User01 (not the actual Windows user name). It's still set to Windows Authentication, though, and I'm unable to change the login name. Now here's where the real problem comes in... I didn't realize that she was being logged in under this user name at the time, and I disabled it to see what would happen. Now I can't log into the server under her account. I created a new account in Windows called test, and as expected SSMS had the username as MACHINE_NAME\test, and I was able to log in fine. However, the area where the User01 account was listed is not visible to me as far as I can tell and so I can't reenable it. I also tried running the following query: alter login User01 ENABLE And got this error: Msg 15151, Level 16, State 1, Line 1 Cannot alter the login 'User01', because it does not exist or you do not have permission. So in a nutshell, ideally I'd like to reenable User01 somehow, just to get things back to where they used to be. Failing that, how can I force SSMS to log in using the Windows account name as it should be, rather than trying to use User01?

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  • Change Windows Authentication user for Sql Server Management Studio

    - by Asmor
    We're using Sql Server 2005 with Windows Authentication setup. So normally, when you log in using e.g. Sql Server Management Studio, it forces you to log in at MACHINE_NAME\Username. Anyways, on this one particular computer, the person said they had to make a new account called User01 to do something and showed me where she'd created it under security in the "master" system database. And so now when she logs in, it's listed as MACHINE_NAME\User01 (not the actual Windows user name). It's still set to Windows Authentication, though, and I'm unable to change the login name. Now here's where the real problem comes in... I didn't realize that she was being logged in under this user name at the time, and I disabled it to see what would happen. Now I can't log into the server under her account. I created a new account in Windows called test, and as expected SSMS had the username as MACHINE_NAME\test, and I was able to log in fine. However, the area where the User01 account was listed is not visible to me as far as I can tell and so I can't reenable it. I also tried running the following query: alter login User01 ENABLE And got this error: Msg 15151, Level 16, State 1, Line 1 Cannot alter the login 'User01', because it does not exist or you do not have permission. So in a nutshell, ideally I'd like to reenable User01 somehow, just to get things back to where they used to be. Failing that, how can I force SSMS to log in using the Windows account name as it should be, rather than trying to use User01?

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  • Mysql - help me optimize this query

    - by sandeepan-nath
    About the system: -The system has a total of 8 tables - Users - Tutor_Details (Tutors are a type of User,Tutor_Details table is linked to Users) - learning_packs, (stores packs created by tutors) - learning_packs_tag_relations, (holds tag relations meant for search) - tutors_tag_relations and tags and orders (containing purchase details of tutor's packs), order_details linked to orders and tutor_details. For a more clear idea about the tables involved please check the The tables section in the end. -A tags based search approach is being followed.Tag relations are created when new tutors register and when tutors create packs (this makes tutors and packs searcheable). For details please check the section How tags work in this system? below. Following is a simpler representation (not the actual) of the more complex query which I am trying to optimize:- I have used statements like explanation of parts in the query select SUM(DISTINCT( t.tag LIKE "%Dictatorship%" )) as key_1_total_matches, SUM(DISTINCT( t.tag LIKE "%democracy%" )) as key_2_total_matches, td., u., count(distinct(od.id_od)), if (lp.id_lp > 0) then some conditional logic on lp fields else 0 as tutor_popularity from Tutor_Details AS td JOIN Users as u on u.id_user = td.id_user LEFT JOIN Learning_Packs_Tag_Relations AS lptagrels ON td.id_tutor = lptagrels.id_tutor LEFT JOIN Learning_Packs AS lp ON lptagrels.id_lp = lp.id_lp LEFT JOIN `some other tables on lp.id_lp - let's call learning pack tables set (including Learning_Packs table)` LEFT JOIN Order_Details as od on td.id_tutor = od.id_author LEFT JOIN Orders as o on od.id_order = o.id_order LEFT JOIN Tutors_Tag_Relations as ttagrels ON td.id_tutor = ttagrels.id_tutor JOIN Tags as t on (t.id_tag = ttagrels.id_tag) OR (t.id_tag = lptagrels.id_tag) where some condition on Users table's fields AND CASE WHEN ((t.id_tag = lptagrels.id_tag) AND (lp.id_lp 0)) THEN `some conditions on learning pack tables set` ELSE 1 END AND CASE WHEN ((t.id_tag = wtagrels.id_tag) AND (wc.id_wc 0)) THEN `some conditions on webclasses tables set` ELSE 1 END AND CASE WHEN (od.id_od0) THEN od.id_author = td.id_tutor and some conditions on Orders table's fields ELSE 1 END AND ( t.tag LIKE "%Dictatorship%" OR t.tag LIKE "%democracy%") group by td.id_tutor HAVING key_1_total_matches = 1 AND key_2_total_matches = 1 order by tutor_popularity desc, u.surname asc, u.name asc limit 0,20 ===================================================================== What does the above query do? Does AND logic search on the search keywords (2 in this example - "Democracy" and "Dictatorship"). Returns only those tutors for which both the keywords are present in the union of the two sets - tutors details and details of all the packs created by a tutor. To make things clear - Suppose a Tutor name "Sandeepan Nath" has created a pack "My first pack", then:- Searching "Sandeepan Nath" returns Sandeepan Nath. Searching "Sandeepan first" returns Sandeepan Nath. Searching "Sandeepan second" does not return Sandeepan Nath. ====================================================================================== The problem The results returned by the above query are correct (AND logic working as per expectation), but the time taken by the query on heavily loaded databases is like 25 seconds as against normal query timings of the order of 0.005 - 0.0002 seconds, which makes it totally unusable. It is possible that some of the delay is being caused because all the possible fields have not yet been indexed, but I would appreciate a better query as a solution, optimized as much as possible, displaying the same results ========================================================================================== How tags work in this system? When a tutor registers, tags are entered and tag relations are created with respect to tutor's details like name, surname etc. When a Tutors create packs, again tags are entered and tag relations are created with respect to pack's details like pack name, description etc. tag relations for tutors stored in tutors_tag_relations and those for packs stored in learning_packs_tag_relations. All individual tags are stored in tags table. ==================================================================== The tables Most of the following tables contain many other fields which I have omitted here. CREATE TABLE IF NOT EXISTS users ( id_user int(10) unsigned NOT NULL AUTO_INCREMENT, name varchar(100) NOT NULL DEFAULT '', surname varchar(155) NOT NULL DEFAULT '', PRIMARY KEY (id_user) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=636 ; CREATE TABLE IF NOT EXISTS tutor_details ( id_tutor int(10) NOT NULL AUTO_INCREMENT, id_user int(10) NOT NULL DEFAULT '0', PRIMARY KEY (id_tutor), KEY Users_FKIndex1 (id_user) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=51 ; CREATE TABLE IF NOT EXISTS orders ( id_order int(10) unsigned NOT NULL AUTO_INCREMENT, PRIMARY KEY (id_order), KEY Orders_FKIndex1 (id_user), ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=275 ; ALTER TABLE orders ADD CONSTRAINT Orders_ibfk_1 FOREIGN KEY (id_user) REFERENCES users (id_user) ON DELETE NO ACTION ON UPDATE NO ACTION; CREATE TABLE IF NOT EXISTS order_details ( id_od int(10) unsigned NOT NULL AUTO_INCREMENT, id_order int(10) unsigned NOT NULL DEFAULT '0', id_author int(10) NOT NULL DEFAULT '0', PRIMARY KEY (id_od), KEY Order_Details_FKIndex1 (id_order) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=284 ; ALTER TABLE order_details ADD CONSTRAINT Order_Details_ibfk_1 FOREIGN KEY (id_order) REFERENCES orders (id_order) ON DELETE NO ACTION ON UPDATE NO ACTION; CREATE TABLE IF NOT EXISTS learning_packs ( id_lp int(10) unsigned NOT NULL AUTO_INCREMENT, id_author int(10) unsigned NOT NULL DEFAULT '0', PRIMARY KEY (id_lp), KEY Learning_Packs_FKIndex2 (id_author), KEY id_lp (id_lp) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=23 ; CREATE TABLE IF NOT EXISTS tags ( id_tag int(10) unsigned NOT NULL AUTO_INCREMENT, tag varchar(255) DEFAULT NULL, PRIMARY KEY (id_tag), UNIQUE KEY tag (tag), KEY id_tag (id_tag), KEY tag_2 (tag), KEY tag_3 (tag) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=3419 ; CREATE TABLE IF NOT EXISTS tutors_tag_relations ( id_tag int(10) unsigned NOT NULL DEFAULT '0', id_tutor int(10) DEFAULT NULL, KEY Tutors_Tag_Relations (id_tag), KEY id_tutor (id_tutor), KEY id_tag (id_tag) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; ALTER TABLE tutors_tag_relations ADD CONSTRAINT Tutors_Tag_Relations_ibfk_1 FOREIGN KEY (id_tag) REFERENCES tags (id_tag) ON DELETE NO ACTION ON UPDATE NO ACTION; CREATE TABLE IF NOT EXISTS learning_packs_tag_relations ( id_tag int(10) unsigned NOT NULL DEFAULT '0', id_tutor int(10) DEFAULT NULL, id_lp int(10) unsigned DEFAULT NULL, KEY Learning_Packs_Tag_Relations_FKIndex1 (id_tag), KEY id_lp (id_lp), KEY id_tag (id_tag) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; ALTER TABLE learning_packs_tag_relations ADD CONSTRAINT Learning_Packs_Tag_Relations_ibfk_1 FOREIGN KEY (id_tag) REFERENCES tags (id_tag) ON DELETE NO ACTION ON UPDATE NO ACTION; =================================================================================== Following is the exact query (this includes classes also - tutors can create classes and search terms are matched with classes created by tutors):- select count(distinct(od.id_od)) as tutor_popularity, CASE WHEN (IF((wc.id_wc 0), ( wc.wc_api_status = 1 AND wc.wc_type = 0 AND wc.class_date '2010-06-01 22:00:56' AND wccp.status = 1 AND (wccp.country_code='IE' or wccp.country_code IN ('INT'))), 0)) THEN 1 ELSE 0 END as 'classes_published', CASE WHEN (IF((lp.id_lp 0), (lp.id_status = 1 AND lp.published = 1 AND lpcp.status = 1 AND (lpcp.country_code='IE' or lpcp.country_code IN ('INT'))),0)) THEN 1 ELSE 0 END as 'packs_published', td . * , u . * from Tutor_Details AS td JOIN Users as u on u.id_user = td.id_user LEFT JOIN Learning_Packs_Tag_Relations AS lptagrels ON td.id_tutor = lptagrels.id_tutor LEFT JOIN Learning_Packs AS lp ON lptagrels.id_lp = lp.id_lp LEFT JOIN Learning_Packs_Categories AS lpc ON lpc.id_lp_cat = lp.id_lp_cat LEFT JOIN Learning_Packs_Categories AS lpcp ON lpcp.id_lp_cat = lpc.id_parent LEFT JOIN Learning_Pack_Content as lpct on (lp.id_lp = lpct.id_lp) LEFT JOIN Webclasses_Tag_Relations AS wtagrels ON td.id_tutor = wtagrels.id_tutor LEFT JOIN WebClasses AS wc ON wtagrels.id_wc = wc.id_wc LEFT JOIN Learning_Packs_Categories AS wcc ON wcc.id_lp_cat = wc.id_wp_cat LEFT JOIN Learning_Packs_Categories AS wccp ON wccp.id_lp_cat = wcc.id_parent LEFT JOIN Order_Details as od on td.id_tutor = od.id_author LEFT JOIN Orders as o on od.id_order = o.id_order LEFT JOIN Tutors_Tag_Relations as ttagrels ON td.id_tutor = ttagrels.id_tutor JOIN Tags as t on (t.id_tag = ttagrels.id_tag) OR (t.id_tag = lptagrels.id_tag) OR (t.id_tag = wtagrels.id_tag) where (u.country='IE' or u.country IN ('INT')) AND CASE WHEN ((t.id_tag = lptagrels.id_tag) AND (lp.id_lp 0)) THEN lp.id_status = 1 AND lp.published = 1 AND lpcp.status = 1 AND (lpcp.country_code='IE' or lpcp.country_code IN ('INT')) ELSE 1 END AND CASE WHEN ((t.id_tag = wtagrels.id_tag) AND (wc.id_wc 0)) THEN wc.wc_api_status = 1 AND wc.wc_type = 0 AND wc.class_date '2010-06-01 22:00:56' AND wccp.status = 1 AND (wccp.country_code='IE' or wccp.country_code IN ('INT')) ELSE 1 END AND CASE WHEN (od.id_od0) THEN od.id_author = td.id_tutor and o.order_status = 'paid' and CASE WHEN (od.id_wc 0) THEN od.can_attend_class=1 ELSE 1 END ELSE 1 END AND 1 group by td.id_tutor order by tutor_popularity desc, u.surname asc, u.name asc limit 0,20 Please note - The provided database structure does not show all the fields and tables as in this query

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  • T-SQL Tuesday #53-Matt's Making Me Do This!

    - by Most Valuable Yak (Rob Volk)
    Hello everyone! It's that time again, time for T-SQL Tuesday, the wonderful blog series started by Adam Machanic (b|t). This month we are hosted by Matt Velic (b|t) who asks the question, "Why So Serious?", in celebration of April Fool's Day. He asks the contributors for their dirty tricks. And for some reason that escapes me, he and Jeff Verheul (b|t) seem to think I might be able to write about those. Shocked, I am! Nah, not really. They're absolutely right, this one is gonna be fun! I took some inspiration from Matt's suggestions, namely Resource Governor and Login Triggers.  I've done some interesting login trigger stuff for a presentation, but nothing yet with Resource Governor. Best way to learn it! One of my oldest pet peeves is abuse of the sa login. Don't get me wrong, I use it too, but typically only as SQL Agent job owner. It's been a while since I've been stuck with it, but back when I started using SQL Server, EVERY application needed sa to function. It was hard-coded and couldn't be changed. (welllllll, that is if you didn't use a hex editor on the EXE file, but who would do such a thing?) My standard warning applies: don't run anything on this page in production. In fact, back up whatever server you're testing this on, including the master database. Snapshotting a VM is a good idea. Also make sure you have other sysadmin level logins on that server. So here's a standard template for a logon trigger to address those pesky sa users: CREATE TRIGGER SA_LOGIN_PRIORITY ON ALL SERVER WITH ENCRYPTION, EXECUTE AS N'sa' AFTER LOGON AS IF ORIGINAL_LOGIN()<>N'sa' OR APP_NAME() LIKE N'SQL Agent%' RETURN; -- interesting stuff goes here GO   What can you do for "interesting stuff"? Books Online limits itself to merely rolling back the logon, which will throw an error (and alert the person that the logon trigger fired).  That's a good use for logon triggers, but really not tricky enough for this blog.  Some of my suggestions are below: WAITFOR DELAY '23:59:59';   Or: EXEC sp_MSforeach_db 'EXEC sp_detach_db ''?'';'   Or: EXEC msdb.dbo.sp_add_job @job_name=N'`', @enabled=1, @start_step_id=1, @notify_level_eventlog=0, @delete_level=3; EXEC msdb.dbo.sp_add_jobserver @job_name=N'`', @server_name=@@SERVERNAME; EXEC msdb.dbo.sp_add_jobstep @job_name=N'`', @step_id=1, @step_name=N'`', @command=N'SHUTDOWN;'; EXEC msdb.dbo.sp_start_job @job_name=N'`';   Really, I don't want to spoil your own exploration, try it yourself!  The thing I really like about these is it lets me promote the idea that "sa is SLOW, sa is BUGGY, don't use sa!".  Before we get into Resource Governor, make sure to drop or disable that logon trigger. They don't work well in combination. (Had to redo all the following code when SSMS locked up) Resource Governor is a feature that lets you control how many resources a single session can consume. The main goal is to limit the damage from a runaway query. But we're not here to read about its main goal or normal usage! I'm trying to make people stop using sa BECAUSE IT'S SLOW! Here's how RG can do that: USE master; GO CREATE FUNCTION dbo.SA_LOGIN_PRIORITY() RETURNS sysname WITH SCHEMABINDING, ENCRYPTION AS BEGIN RETURN CASE WHEN ORIGINAL_LOGIN()=N'sa' AND APP_NAME() NOT LIKE N'SQL Agent%' THEN N'SA_LOGIN_PRIORITY' ELSE N'default' END END GO CREATE RESOURCE POOL SA_LOGIN_PRIORITY WITH ( MIN_CPU_PERCENT = 0 ,MAX_CPU_PERCENT = 1 ,CAP_CPU_PERCENT = 1 ,AFFINITY SCHEDULER = (0) ,MIN_MEMORY_PERCENT = 0 ,MAX_MEMORY_PERCENT = 1 -- ,MIN_IOPS_PER_VOLUME = 1 ,MAX_IOPS_PER_VOLUME = 1 -- uncomment for SQL Server 2014 ); CREATE WORKLOAD GROUP SA_LOGIN_PRIORITY WITH ( IMPORTANCE = LOW ,REQUEST_MAX_MEMORY_GRANT_PERCENT = 1 ,REQUEST_MAX_CPU_TIME_SEC = 1 ,REQUEST_MEMORY_GRANT_TIMEOUT_SEC = 1 ,MAX_DOP = 1 ,GROUP_MAX_REQUESTS = 1 ) USING SA_LOGIN_PRIORITY; ALTER RESOURCE GOVERNOR WITH (CLASSIFIER_FUNCTION=dbo.SA_LOGIN_PRIORITY); ALTER RESOURCE GOVERNOR RECONFIGURE;   From top to bottom: Create a classifier function to determine which pool the session should go to. More info on classifier functions. Create the pool and provide a generous helping of resources for the sa login. Create the workload group and further prioritize those resources for the sa login. Apply the classifier function and reconfigure RG to use it. I have to say this one is a bit sneakier than the logon trigger, least of all you don't get any error messages.  I heartily recommend testing it in Management Studio, and click around the UI a lot, there's some fun behavior there. And DEFINITELY try it on SQL 2014 with the IO settings included!  You'll notice I made allowances for SQL Agent jobs owned by sa, they'll go into the default workload group.  You can add your own overrides to the classifier function if needed. Some interesting ideas I didn't have time for but expect you to get to before me: Set up different pools/workgroups with different settings and randomize which one the classifier chooses Do the same but base it on time of day (Books Online example covers this)... Or, which workstation it connects from. This can be modified for certain special people in your office who either don't listen, or are attracted (and attractive) to you. And if things go wrong you can always use the following from another sysadmin or Dedicated Admin connection: ALTER RESOURCE GOVERNOR DISABLE;   That will let you go in and either fix (or drop) the pools, workgroups and classifier function. So now that you know these types of things are possible, and if you are tired of your team using sa when they shouldn't, I expect you'll enjoy playing with these quite a bit! Unfortunately, the aforementioned Dedicated Admin Connection kinda poops on the party here.  Books Online for both topics will tell you that the DAC will not fire either feature. So if you have a crafty user who does their research, they can still sneak in with sa and do their bidding without being hampered. Of course, you can still detect their login via various methods, like a server trace, SQL Server Audit, extended events, and enabling "Audit Successful Logins" on the server.  These all have their downsides: traces take resources, extended events and SQL Audit can't fire off actions, and enabling successful logins will bloat your error log very quickly.  SQL Audit is also limited unless you have Enterprise Edition, and Resource Governor is Enterprise-only.  And WORST OF ALL, these features are all available and visible through the SSMS UI, so even a doofus developer or manager could find them. Fortunately there are Event Notifications! Event notifications are becoming one of my favorite features of SQL Server (keep an eye out for more blogs from me about them). They are practically unknown and heinously underutilized.  They are also a great gateway drug to using Service Broker, another great but underutilized feature. Hopefully this will get you to start using them, or at least your enemies in the office will once they read this, and then you'll have to learn them in order to fix things. So here's the setup: USE msdb; GO CREATE PROCEDURE dbo.SA_LOGIN_PRIORITY_act WITH ENCRYPTION AS DECLARE @x XML, @message nvarchar(max); RECEIVE @x=CAST(message_body AS XML) FROM SA_LOGIN_PRIORITY_q; IF @x.value('(//LoginName)[1]','sysname')=N'sa' AND @x.value('(//ApplicationName)[1]','sysname') NOT LIKE N'SQL Agent%' BEGIN -- interesting activation procedure stuff goes here END GO CREATE QUEUE SA_LOGIN_PRIORITY_q WITH STATUS=ON, RETENTION=OFF, ACTIVATION (PROCEDURE_NAME=dbo.SA_LOGIN_PRIORITY_act, MAX_QUEUE_READERS=1, EXECUTE AS OWNER); CREATE SERVICE SA_LOGIN_PRIORITY_s ON QUEUE SA_LOGIN_PRIORITY_q([http://schemas.microsoft.com/SQL/Notifications/PostEventNotification]); CREATE EVENT NOTIFICATION SA_LOGIN_PRIORITY_en ON SERVER WITH FAN_IN FOR AUDIT_LOGIN TO SERVICE N'SA_LOGIN_PRIORITY_s', N'current database' GO   From top to bottom: Create activation procedure for event notification queue. Create queue to accept messages from event notification, and activate the procedure to process those messages when received. Create service to send messages to that queue. Create event notification on AUDIT_LOGIN events that fire the service. I placed this in msdb as it is an available system database and already has Service Broker enabled by default. You should change this to another database if you can guarantee it won't get dropped. So what to put in place for "interesting activation procedure code"?  Hmmm, so far I haven't addressed Matt's suggestion of writing a lengthy script to send an annoying message: SET @[email protected]('(//HostName)[1]','sysname') + N' tried to log in to server ' + @x.value('(//ServerName)[1]','sysname') + N' as SA at ' + @x.value('(//StartTime)[1]','sysname') + N' using the ' + @x.value('(//ApplicationName)[1]','sysname') + N' program. That''s why you''re getting this message and the attached pornography which' + N' is bloating your inbox and violating company policy, among other things. If you know' + N' this person you can go to their desk and hit them, or use the following SQL to end their session: KILL ' + @x.value('(//SPID)[1]','sysname') + N'; Hopefully they''re in the middle of a huge query that they need to finish right away.' EXEC msdb.dbo.sp_send_dbmail @recipients=N'[email protected]', @subject=N'SA Login Alert', @query_result_width=32767, @body=@message, @query=N'EXEC sp_readerrorlog;', @attach_query_result_as_file=1, @query_attachment_filename=N'UtterlyGrossPorn_SeriouslyDontOpenIt.jpg' I'm not sure I'd call that a lengthy script, but the attachment should get pretty big, and I'm sure the email admins will love storing multiple copies of it.  The nice thing is that this also fires on Dedicated Admin connections! You can even identify DAC connections from the event data returned, I leave that as an exercise for you. You can use that info to change the action taken by the activation procedure, and since it's a stored procedure, it can pretty much do anything! Except KILL the SPID, or SHUTDOWN the server directly.  I'm still working on those.

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  • Operator of the week - Assert

    - by Fabiano Amorim
    Well my friends, I was wondering how to help you in a practical way to understand execution plans. So I think I'll talk about the Showplan Operators. Showplan Operators are used by the Query Optimizer (QO) to build the query plan in order to perform a specified operation. A query plan will consist of many physical operators. The Query Optimizer uses a simple language that represents each physical operation by an operator, and each operator is represented in the graphical execution plan by an icon. I'll try to talk about one operator every week, but so as to avoid having to continue to write about these operators for years, I'll mention only of those that are more common: The first being the Assert. The Assert is used to verify a certain condition, it validates a Constraint on every row to ensure that the condition was met. If, for example, our DDL includes a check constraint which specifies only two valid values for a column, the Assert will, for every row, validate the value passed to the column to ensure that input is consistent with the check constraint. Assert  and Check Constraints: Let's see where the SQL Server uses that information in practice. Take the following T-SQL: IF OBJECT_ID('Tab1') IS NOT NULL   DROP TABLE Tab1 GO CREATE TABLE Tab1(ID Integer, Gender CHAR(1))  GO  ALTER TABLE TAB1 ADD CONSTRAINT ck_Gender_M_F CHECK(Gender IN('M','F'))  GO INSERT INTO Tab1(ID, Gender) VALUES(1,'X') GO To the command above the SQL Server has generated the following execution plan: As we can see, the execution plan uses the Assert operator to check that the inserted value doesn't violate the Check Constraint. In this specific case, the Assert applies the rule, 'if the value is different to "F" and different to "M" than return 0 otherwise returns NULL'. The Assert operator is programmed to show an error if the returned value is not NULL; in other words, the returned value is not a "M" or "F". Assert checking Foreign Keys Now let's take a look at an example where the Assert is used to validate a foreign key constraint. Suppose we have this  query: ALTER TABLE Tab1 ADD ID_Genders INT GO  IF OBJECT_ID('Tab2') IS NOT NULL   DROP TABLE Tab2 GO CREATE TABLE Tab2(ID Integer PRIMARY KEY, Gender CHAR(1))  GO  INSERT INTO Tab2(ID, Gender) VALUES(1, 'F') INSERT INTO Tab2(ID, Gender) VALUES(2, 'M') INSERT INTO Tab2(ID, Gender) VALUES(3, 'N') GO  ALTER TABLE Tab1 ADD CONSTRAINT fk_Tab2 FOREIGN KEY (ID_Genders) REFERENCES Tab2(ID) GO  INSERT INTO Tab1(ID, ID_Genders, Gender) VALUES(1, 4, 'X') Let's look at the text execution plan to see what these Assert operators were doing. To see the text execution plan just execute SET SHOWPLAN_TEXT ON before run the insert command. |--Assert(WHERE:(CASE WHEN NOT [Pass1008] AND [Expr1007] IS NULL THEN (0) ELSE NULL END))      |--Nested Loops(Left Semi Join, PASSTHRU:([Tab1].[ID_Genders] IS NULL), OUTER REFERENCES:([Tab1].[ID_Genders]), DEFINE:([Expr1007] = [PROBE VALUE]))           |--Assert(WHERE:(CASE WHEN [Tab1].[Gender]<>'F' AND [Tab1].[Gender]<>'M' THEN (0) ELSE NULL END))           |    |--Clustered Index Insert(OBJECT:([Tab1].[PK]), SET:([Tab1].[ID] = RaiseIfNullInsert([@1]),[Tab1].[ID_Genders] = [@2],[Tab1].[Gender] = [Expr1003]), DEFINE:([Expr1003]=CONVERT_IMPLICIT(char(1),[@3],0)))           |--Clustered Index Seek(OBJECT:([Tab2].[PK]), SEEK:([Tab2].[ID]=[Tab1].[ID_Genders]) ORDERED FORWARD) Here we can see the Assert operator twice, first (looking down to up in the text plan and the right to left in the graphical plan) validating the Check Constraint. The same concept showed above is used, if the exit value is "0" than keep running the query, but if NULL is returned shows an exception. The second Assert is validating the result of the Tab1 and Tab2 join. It is interesting to see the "[Expr1007] IS NULL". To understand that you need to know what this Expr1007 is, look at the Probe Value (green text) in the text plan and you will see that it is the result of the join. If the value passed to the INSERT at the column ID_Gender exists in the table Tab2, then that probe will return the join value; otherwise it will return NULL. So the Assert is checking the value of the search at the Tab2; if the value that is passed to the INSERT is not found  then Assert will show one exception. If the value passed to the column ID_Genders is NULL than the SQL can't show a exception, in that case it returns "0" and keeps running the query. If you run the INSERT above, the SQL will show an exception because of the "X" value, but if you change the "X" to "F" and run again, it will show an exception because of the value "4". If you change the value "4" to NULL, 1, 2 or 3 the insert will be executed without any error. Assert checking a SubQuery: The Assert operator is also used to check one subquery. As we know, one scalar subquery can't validly return more than one value: Sometimes, however, a  mistake happens, and a subquery attempts to return more than one value . Here the Assert comes into play by validating the condition that a scalar subquery returns just one value. Take the following query: INSERT INTO Tab1(ID_TipoSexo, Sexo) VALUES((SELECT ID_TipoSexo FROM Tab1), 'F')    INSERT INTO Tab1(ID_TipoSexo, Sexo) VALUES((SELECT ID_TipoSexo FROM Tab1), 'F')    |--Assert(WHERE:(CASE WHEN NOT [Pass1016] AND [Expr1015] IS NULL THEN (0) ELSE NULL END))        |--Nested Loops(Left Semi Join, PASSTHRU:([tempdb].[dbo].[Tab1].[ID_TipoSexo] IS NULL), OUTER REFERENCES:([tempdb].[dbo].[Tab1].[ID_TipoSexo]), DEFINE:([Expr1015] = [PROBE VALUE]))              |--Assert(WHERE:([Expr1017]))             |    |--Compute Scalar(DEFINE:([Expr1017]=CASE WHEN [tempdb].[dbo].[Tab1].[Sexo]<>'F' AND [tempdb].[dbo].[Tab1].[Sexo]<>'M' THEN (0) ELSE NULL END))              |         |--Clustered Index Insert(OBJECT:([tempdb].[dbo].[Tab1].[PK__Tab1__3214EC277097A3C8]), SET:([tempdb].[dbo].[Tab1].[ID_TipoSexo] = [Expr1008],[tempdb].[dbo].[Tab1].[Sexo] = [Expr1009],[tempdb].[dbo].[Tab1].[ID] = [Expr1003]))              |              |--Top(TOP EXPRESSION:((1)))              |                   |--Compute Scalar(DEFINE:([Expr1008]=[Expr1014], [Expr1009]='F'))              |                        |--Nested Loops(Left Outer Join)              |                             |--Compute Scalar(DEFINE:([Expr1003]=getidentity((1856985942),(2),NULL)))              |                             |    |--Constant Scan              |                             |--Assert(WHERE:(CASE WHEN [Expr1013]>(1) THEN (0) ELSE NULL END))              |                                  |--Stream Aggregate(DEFINE:([Expr1013]=Count(*), [Expr1014]=ANY([tempdb].[dbo].[Tab1].[ID_TipoSexo])))             |                                       |--Clustered Index Scan(OBJECT:([tempdb].[dbo].[Tab1].[PK__Tab1__3214EC277097A3C8]))              |--Clustered Index Seek(OBJECT:([tempdb].[dbo].[Tab2].[PK__Tab2__3214EC27755C58E5]), SEEK:([tempdb].[dbo].[Tab2].[ID]=[tempdb].[dbo].[Tab1].[ID_TipoSexo]) ORDERED FORWARD)  You can see from this text showplan that SQL Server as generated a Stream Aggregate to count how many rows the SubQuery will return, This value is then passed to the Assert which then does its job by checking its validity. Is very interesting to see that  the Query Optimizer is smart enough be able to avoid using assert operators when they are not necessary. For instance: INSERT INTO Tab1(ID_TipoSexo, Sexo) VALUES((SELECT ID_TipoSexo FROM Tab1 WHERE ID = 1), 'F') INSERT INTO Tab1(ID_TipoSexo, Sexo) VALUES((SELECT TOP 1 ID_TipoSexo FROM Tab1), 'F')  For both these INSERTs, the Query Optimiser is smart enough to know that only one row will ever be returned, so there is no need to use the Assert. Well, that's all folks, I see you next week with more "Operators". Cheers, Fabiano

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  • Difference between SQL 2005 and SQL 2008 for inserting multiple rows with XML

    - by Sam Dahan
    I am using the following SQL code for inserting multiple rows of data in a table. The data is passed to the stored procedure using an XML variable : INSERT INTO MyTable SELECT SampleTime = T.Item.value('SampleTime[1]', 'datetime'), Volume1 = T.Item.value('Volume1[1]', 'float'), Volume2 = T.Item.value('Volume2[1]', 'float') FROM @xml.nodes('//Root/MyRecord') T(item) I have a whole bunch of unit tests to verify that I am inserting the right information, the right number of records, etc.. when I call the stored procedure. All fine and dandy - that is, until we began to monkey around with the compatibility level of the database. The code above worked beautifully as long as we kept the compatibility level of the DB at 90 (SQL 2005). When we set the compatibility level at 100 (SQL 2008), the unit tests failed, because the stored procedure using the code above times out. The unit tests are dropping the database, re-creating it from scripts, and running the tests on the brand new DB, so it's not - I think - a question of the 'old compatibility level' sticking around. Using the SQL Management studio, I made up a quick test SQL script. Using the same XML chunk, I alter the DB compat level , truncate the table, then use the code above to insert 650 rows. When the level is 90 (SQL 2005), it runs in milliseconds. When the level is 100 (SQL 2008) it sometimes takes over a minute, sometimes runs in milliseconds. I'd appreciate any insight anyone might have into that. EDIT The script takes over a minute to run with my actual data, which has more rows than I show here, is a real table, and has an index. With the following example code, the difference goes between milliseconds and around 5 seconds. --use [master] --ALTER DATABASE MyDB SET compatibility_level =100 use [MyDB] declare @xml xml set @xml = '<?xml version="1.0"?> <Root xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Record> <SampleTime>2009-01-24T00:00:00</SampleTime> <Volume1>0</Volume1> <Volume2>0</Volume2> </Record> ..... 653 records, sample time spaced out 4 hours ........ </Root>' DECLARE @myTable TABLE( ID int IDENTITY(1,1) NOT NULL, [SampleTime] [datetime] NOT NULL, [Volume1] [float] NULL, [Volume2] [float] NULL) INSERT INTO @myTable select T.Item.value('SampleTime[1]', 'datetime') as SampleTime, Volume1 = T.Item.value('Volume1[1]', 'float'), Volume2 = T.Item.value('Volume2[1]', 'float') FROM @xml.nodes('//Root/Record') T(item) I uncomment the 2 lines at the top, select them and run just that (the ALTER DATABASE statement), then comment the 2 lines, deselect any text and run the whole thing. When I change from 90 to 100, it runs all the time in 5 seconds (I change the level once, but I run the series several times to see if I have consistent results). When I change from 100 to 90, it runs in milliseconds all the time. Just so you can play with it too. I am using SQL Server 2008 R2 standard edition.

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  • linux installation cd enviroment

    - by haw3d
    i recently make a custom linux system, for my special need. its on my HDD, but i want to create a cd for installation. multiple day ego, i found a livecd and create install script for that, but in power failure my HDD is gone, and i cant found that live cd again. my install script is based on recoverin tar.gz backup. my requorement is: based on glibc (not uclibc) recognize every devices have you any suggestion? excuse me for my bad english.

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