Search Results

Search found 68815 results on 2753 pages for 'paging file'.

Page 18/2753 | < Previous Page | 14 15 16 17 18 19 20 21 22 23 24 25  | Next Page >

  • How to compare two file structures in PHP?

    - by OM The Eternity
    I have a function which gives me the complete file structure upto n-level, function getDirectory($path = '.', $ignore = '') { $dirTree = array (); $dirTreeTemp = array (); $ignore[] = '.'; $ignore[] = '..'; $dh = @opendir($path); while (false !== ($file = readdir($dh))) { if (!in_array($file, $ignore)) { if (!is_dir("$path/$file")) { //display of file and directory name with their modification time $stat = stat("$path/$file"); $statdir = stat("$path"); $dirTree["$path"][] = $file. " === ". date('Y-m-d H:i:s', $stat['mtime']) . " Directory == ".$path."===". date('Y-m-d H:i:s', $statdir['mtime']) ; } else { $dirTreeTemp = getDirectory("$path/$file", $ignore); if (is_array($dirTreeTemp))$dirTree = array_merge($dirTree, $dirTreeTemp); } } } closedir($dh); return $dirTree; } $ignore = array('.htaccess', 'error_log', 'cgi-bin', 'php.ini', '.ftpquota'); //function call $dirTree = getDirectory('.', $ignore); //file structure array print print_r($dirTree); Now here my requirement is , I have two sites The Development/Test Site- where i do testing of all the changes The Production Site- where I finally post all the changes as per test in development site Now, for example, I have tested an image upload in the Development/test site, and i found it appropriate to publish on Production site then i will completely transfer the Development/Test DB detail to Production DB, but now I want to compare the files structure as well to transfer the corresponding image file to Production folder. There could be the situation when I update the image by editing the image and upload it with same name, now in this case the image file would be already present there, which will restrict the use of "file_exist" logic, so for these type of situations....HOW CAN I COMPARE THE TWO FILE STRUCTURE TO GET THE SYNCHRONIZATION DONE AS PER REQUIREMENT??

    Read the article

  • File mkdirs() method not working in android/java

    - by Leif Andersen
    I've been pulling out my hair on this for a while now. The following method is supposed to download a file, and save it to the location specified on the hard drive. private static void saveImage(Context context, boolean backgroundUpdate, URL url, File file) { if (!Tools.checkNetworkState(context, backgroundUpdate)) return; // Get the image try { // Make the file file.getParentFile().mkdirs(); // Set up the connection URLConnection uCon = url.openConnection(); InputStream is = uCon.getInputStream(); BufferedInputStream bis = new BufferedInputStream(is); // Download the data ByteArrayBuffer baf = new ByteArrayBuffer(50); int current = 0; while ((current = bis.read()) != -1) { baf.append((byte) current); } // Write the bits to the file OutputStream os = new FileOutputStream(file); os.write(baf.toByteArray()); os.close(); } catch (Exception e) { // Any exception is probably a newtork faiilure, bail return; } } Also, if the file doesn't exist, it is supposed to make the directory for the file. (And if there is another file already in that spot, it should just not do anything). However, for some reason, the mkdirs() method never makes the directory. I've tried everything from explicit parentheses, to explicitly making the parent file class, and nothing seems to work. I'm fairly certain that the drive is writable, as it's only called after that has already been determined, also that is true after running through it while debugging. So the method fails because the parent directories aren't made. Can anyone tell me if there is anything wrong with the way I'm calling it? Also, if it helps, here is the source for the file I'm calling it in: https://github.com/LeifAndersen/NetCatch/blob/master/src/net/leifandersen/mobile/android/netcatch/services/RSSService.java Thank you

    Read the article

  • Unset the system immutable bit in Mac OS X

    - by skylarking
    In theory I believe you can unlock and remove the system immutable bit with: chflags noschg /Path/To/File But how can you do this when you've set the bit as root? I have a file that is locked, and even running this command as root will not work as the operation is not permitted. I tried logging in as Single-User mode to no avail. I seem to remember that even though you are in as root you are in at level '1'. And to be able to remove the system-immutable flag you need to be logged in at level '0'. Does this have something to do with this issue?

    Read the article

  • Reliable file copy (move) process - mostly Unix/Linux

    - by mfinni
    Short story : We have a need for a rock-solid reliable file mover process. We have source directories that are often being written to that we need to move files from. The files come in pairs - a big binary, and a small XML index. We get a CTL file that defines these file bundles. There is a process that operates on the files once they are in the destination directory; that gets rid of them when it's done. Would rsync do the best job, or do we need to get more complex? Long story as follows : We have multiple sources to pull from : one set of directories are on a Windows machine (that does have Cygwin and an SSH daemon), and a whole pile of directories are on a set of SFTP servers (Most of these are also Windows.) Our destinations are a list of directories on AIX servers. We used to use a very reliable Perl script on the Windows/Cygwin machine when it was our only source. However, we're working on getting rid of that machine, and there are other sources now, the SFTP servers, that we cannot presently run our own scripts on. For security reasons, we can't run the copy jobs on our AIX servers - they have no access to the source servers. We currently have a homegrown Java program on a Linux machine that uses SFTP to pull from the various new SFTP source directories, copies to a local tmp directory, verifies that everything is present, then copies that to the AIX machines, and then deletes the files from the source. However, we're finding any number of bugs or poorly-handled error checking. None of us are Java experts, so fixing/improving this may be difficult. Concerns for us are: With a remote source (SFTP), will rsync leave alone any file still being written? Some of these files are large. From reading the docs, it seems like rysnc will be very good about not removing the source until the destination is reliably written. Does anyone have experience confirming or disproving this? Additional info We will be concerned about the ingestion process that operates on the files once they are in the destination directory. We don't want it operating on files while we are in the process of copying them; it waits until the small XML index file is present. Our current copy job are supposed to copy the XML file last. Sometimes the network has problems, sometimes the SFTP source servers crap out on us. Sometimes we typo the config files and a destination directory doesn't exist. We never want to lose a file due to this sort of error. We need good logs If you were presented with this, would you just script up some rsync? Or would you build or buy a tool, and if so, what would it be (or what technologies would it use?) I (and others on my team) are decent with Perl.

    Read the article

  • Calculate total by javascript in gridview with paging

    - by louis
    Without paging function, i can loop through the gridview by using var sum = 0; var gridViewCtlId = '<%=timesheetView.ClientID%>'; var grid = document.getElementById(gridViewCtlId); var gridLength = grid.rows.length; so with gridLength i can loop through the gridview to sum all rows. However, when I use paging event of gridview, i use the page size to loop through all rows, but it occurs errors because the last page may not have enough rows. So would you please to help me how to get the rows in the each page of gridview?

    Read the article

  • Problem with Efficient Gridview paging without datasource control

    - by Ronnie Overby
    I am trying to do efficient paging with a gridview without using a datasource control. By efficient, I mean I only retrieve the records that I intend to show. I am trying to use the PagerTemplate to build my pager functionality. In short, the problem is that if I bind only the records that I intend to show on the current page, the gridview doesn't render its pager template, so I don't get the paging controls. It's almost as if I MUST bind more records than I intend to show on a given page, which is not something I want to do.

    Read the article

  • Sql Paging/Sorting - Efficent method with dynamic sort?

    - by dmose
    I'm trying to implement this style of paging: http://www.4guysfromrolla.com/webtech/042606-1.shtml CREATE PROCEDURE [dbo].[usp_PageResults_NAI] ( @startRowIndex int, @maximumRows int ) AS DECLARE @first_id int, @startRow int -- A check can be added to make sure @startRowIndex isn't > count(1) -- from employees before doing any actual work unless it is guaranteed -- the caller won't do that -- Get the first employeeID for our page of records SET ROWCOUNT @startRowIndex SELECT @first_id = employeeID FROM employees ORDER BY employeeid -- Now, set the row count to MaximumRows and get -- all records >= @first_id SET ROWCOUNT @maximumRows SELECT e.*, d.name as DepartmentName FROM employees e INNER JOIN Departments D ON e.DepartmentID = d.DepartmentID WHERE employeeid >= @first_id ORDER BY e.EmployeeID SET ROWCOUNT 0 GO This method works great, however, is it possible to use this method and have dynamic field sorting? If we change this to SELECT e.*, d.name as DepartmentName FROM employees e INNER JOIN Departments D ON e.DepartmentID = d.DepartmentID WHERE employeeid >= @first_id ORDER BY e.FirstName DESC It breaks the sorting... Is there any way to combine this method of paging with the ability to sort on different fields?

    Read the article

  • Parse a text file into multiple text file

    - by Vijay Kumar Singh
    I want to get multiple file by parsing a input file Through Java. The Input file contains many fasta format of thousands of protein sequence and I want to generate raw format(i.e., without any comma semicolon and without any extra symbol like "", "[", "]" etc) of each protein sequence. A fasta sequence starts form "" symbol followed by description of protein and then sequence of protein. For example ? lcl|NC_000001.10_cdsid_XP_003403591.1 [gene=LOC100652771] [protein=hypothetical protein LOC100652771] [protein_id=XP_003403591.1] [location=join(12190..12227,12595..12721,13403..13639)] MSESINFSHNLGQLLSPPRCVVMPGMPFPSIRSPELQKTTADLDHTLVSVPSVAESLHHPEITFLTAFCL PSFTRSRPLPDRQLHHCLALCPSFALPAGDGVCHGPGLQGSCYKGETQESVESRVLPGPRHRH Like above formate the input file contains 1000s of protein sequence. I have to generate thousands of raw file containing only individual protein sequence without any special symbol or gaps. I have developed the code for it in Java but out put is : Cannot open a file followed by cannot find file. Please help me to solve my problem. Regards Vijay Kumar Garg Varanasi Bharat (India) The code is /*Java code to convert FASTA format to a raw format*/ import java.io.*; import java.util.*; import java.util.regex.*; import java.io.FileInputStream; // java package for using regular expression public class Arrayren { public static void main(String args[]) throws IOException { String a[]=new String[1000]; String b[][] =new String[1000][1000]; /*open the id file*/ try { File f = new File ("input.txt"); //opening the text document containing genbank ids FileInputStream fis = new FileInputStream("input.txt"); //Reading the file contents through inputstream BufferedInputStream bis = new BufferedInputStream(fis); // Writing the contents to a buffered stream DataInputStream dis = new DataInputStream(bis); //Method for reading Java Standard data types String inputline; String line; String separator = System.getProperty("line.separator"); // reads a line till next line operator is found int i=0; while ((inputline=dis.readLine()) != null) { i++; a[i]=inputline; a[i]=a[i].replaceAll(separator,""); //replaces unwanted patterns like /n with space a[i]=a[i].trim(); // trims out if any space is available a[i]=a[i]+".txt"; //takes the file name into an array try // to handle run time error /*take the sequence in to an array*/ { BufferedReader in = new BufferedReader (new FileReader(a[i])); String inline = null; int j=0; while((inline=in.readLine()) != null) { j++; b[i][j]=inline; Pattern q=Pattern.compile(">"); //Compiling the regular expression Matcher n=q.matcher(inline); //creates the matcher for the above pattern if(n.find()) { /*appending the comment line*/ b[i][j]=b[i][j].replaceAll(">gi",""); //identify the pattern and replace it with a space b[i][j]=b[i][j].replaceAll("[a-zA-Z]",""); b[i][j]=b[i][j].replaceAll("|",""); b[i][j]=b[i][j].replaceAll("\\d{1,15}",""); b[i][j]=b[i][j].replaceAll(".",""); b[i][j]=b[i][j].replaceAll("_",""); b[i][j]=b[i][j].replaceAll("\\(",""); b[i][j]=b[i][j].replaceAll("\\)",""); } /*printing the sequence in to a text file*/ b[i][j]=b[i][j].replaceAll(separator,""); b[i][j]=b[i][j].trim(); // trims out if any space is available File create = new File(inputline+"R.txt"); try { if(!create.exists()) { create.createNewFile(); // creates a new file } else { System.out.println("file already exists"); } } catch(IOException e) // to catch the exception and print the error if cannot open a file { System.err.println("cannot create a file"); } BufferedWriter outt = new BufferedWriter(new FileWriter(inputline+"R.txt", true)); outt.write(b[i][j]); // printing the contents to a text file outt.close(); // closing the text file System.out.println(b[i][j]); } } catch(Exception e) { System.out.println("cannot open a file"); } } } catch(Exception ex) // catch the exception and prints the error if cannot find file { System.out.println("cannot find file "); } } } If you provide me correct it will be much easier to understand.

    Read the article

  • Copy mdf file and use it in run time

    - by Anibas
    After I copy mdf file (and his log file) I tries to Insert data. I receive the following message: "An attempt to attach an auto-named database for file [fileName].mdf failed. A database with the same name exists, or specified file cannot be opened, or it is located on UNC share. When I copied the file manual everything worked normally. Is it correct the order File.Copy leaves the file engaged?

    Read the article

  • Designing a database file format

    - by RoliSoft
    I would like to design my own database engine for educational purposes, for the time being. Designing a binary file format is not hard nor the question, I've done it in the past, but while designing a database file format, I have come across a very important question: How to handle the deletion of an item? So far, I've thought of the following two options: Each item will have a "deleted" bit which is set to 1 upon deletion. Pro: relatively fast. Con: potentially sensitive data will remain in the file. 0x00 out the whole item upon deletion. Pro: potentially sensitive data will be removed from the file. Con: relatively slow. Recreating the whole database. Pro: no empty blocks which makes the follow-up question void. Con: it's a really good idea to overwrite the whole 4 GB database file because a user corrected a typo. I will sell this method to Twitter ASAP! Now let's say you already have a few empty blocks in your database (deleted items). The follow-up question is how to handle the insertion of a new item? Append the item to the end of the file. Pro: fastest possible. Con: file will get huge because of all the empty blocks that remain because deleted items aren't actually deleted. Search for an empty block exactly the size of the one you're inserting. Pro: may get rid of some blocks. Con: you may end up scanning the whole file at each insert only to find out it's very unlikely to come across a perfectly fitting empty block. Find the first empty block which is equal or larger than the item you're inserting. Pro: you probably won't end up scanning the whole file, as you will find an empty block somewhere mid-way; this will keep the file size relatively low. Con: there will still be lots of leftover 0x00 bytes at the end of items which were inserted into bigger empty blocks than they are. Rigth now, I think the first deletion method and the last insertion method are probably the "best" mix, but they would still have their own small issues. Alternatively, the first insertion method and scheduled full database recreation. (Probably not a good idea when working with really large databases. Also, each small update in that method will clone the whole item to the end of the file, thus accelerating file growth at a potentially insane rate.) Unless there is a way of deleting/inserting blocks from/to the middle of the file in a file-system approved way, what's the best way to do this? More importantly, how do databases currently used in production usually handle this?

    Read the article

  • Paging Results - Drupal Module

    - by Krishma
    Hi I have custom drupal module. I receive result from a webservice that I need to page. Here is what I am doing $result = webservice_call_results(); $attributes = array( 'border' = 1, 'cellspacing' = 0, 'cellpadding' = 5, 'width' = 600, ); $rows = array(); foreach ($result-headers-RPMHeader as $data) { $rows[] = array( l(t($data-reg_no), round($data-total_payment,2), $data-prepared_by ); } $headers = array(t(' Reg Number'), t('Total Payment'),t('Prepared By')); $output =theme('table',$headers,$rows,$attributes); $output .= theme('pager', 1); // Not Working -- Paging $form['manufacturer_search']['table'] = array( '#type' = 'markup', '#value' = $output); The paging is not working. Any Idea why, please help

    Read the article

  • opening and viewing a file in php

    - by Christian Burgos
    how do i open/view for editing an uploaded file in php? i have tried this but it doesn't open the file. $my_file = 'file.txt'; $handle = fopen($my_file, 'r'); $data = fread($handle,filesize($my_file)); i've also tried this but it wont work. $my_file = 'file.txt'; $handle = fopen($my_file, 'w') or die('Cannot open file: '.$my_file); $data = 'This is the data'; fwrite($handle, $data); what i have in mind is like when you want to view an uploaded resume,documents or any other ms office files like .docx,.xls,.pptx and be able to edit them, save and close the said file. edit: latest tried code... <?php // Connects to your Database include "configdb.php"; //Retrieves data from MySQL $data = mysql_query("SELECT * FROM employees") or die(mysql_error()); //Puts it into an array while($info = mysql_fetch_array( $data )) { //Outputs the image and other data //Echo "<img src=localhost/uploadfile/images".$info['photo'] ."> <br>"; Echo "<b>Name:</b> ".$info['name'] . "<br> "; Echo "<b>Email:</b> ".$info['email'] . " <br>"; Echo "<b>Phone:</b> ".$info['phone'] . " <hr>"; //$file=fopen("uploadfile/images/".$info['photo'],"r+"); $file=fopen("Applications/XAMPP/xamppfiles/htdocs/uploadfile/images/file.odt","r") or exit("unable to open file");; } ?> i am getting the error: Warning: fopen(Applications/XAMPP/xamppfiles/htdocs/uploadfile/images/file.odt): failed to open stream: No such file or directory in /Applications/XAMPP/xamppfiles/htdocs/uploadfile/view.php on line 17 unable to open file the file is in that folder, i don't know it wont find it.

    Read the article

  • Reading data from text file in C

    - by themake
    I have a text file which contains words separated by space. I want to take each word from the file and store it. So i have opened the file but am unsure how to assign the word to a char. FILE *fp; fp = fopen("file.txt", "r"); //then i want char one = the first word in the file char two = the second word in the file

    Read the article

  • Copied a file with winscp; only winscp can see it

    - by nilbus
    I recently copied a 25.5GB file from another machine using WinSCP. I copied it to C:\beth.tar.gz, and WinSCP can still see the file. However no other app (including Explorer) can see the file. What might cause this, and how can I fix it? The details that might or might not matter WinSCP shows the size of the file (C:\beth.tar.gz) correctly as 27,460,124,080 bytes, which matches the filesize on the remote host Neither explorer, cmd (command line prompt w/ dir C:\), the 7Zip archive program, nor any other File Open dialog can see the beth.tar.gz file under C:\ I have configured Explorer to show hidden files I can move the file to other directories using WinSCP If I try to move the file to Users/, UAC prompts me for administrative rights, which I grant, and I get this error: Could not find this item The item is no longer located in C:\ When I try to transfer the file back to the remote host in a new directory, the transfer starts successfully and transfers data The transfer had about 30 minutes remaining when I left it for the night The morning after the file transfer, I was greeted with a message saying that the connection to the server had been lost. I don't think this is relevant, since I did not tell it to disconnect after the file was done transferring, and it likely disconnected after the file transfer finished. I'm using an old version of WinSCP - v4.1.8 from 2008 I can view the file properties in WinSCP: Type of file: 7zip (.gz) Location: C:\ Attributes: none (Ready-only, Hidden, Archive, or Ready for indexing) Security: SYSTEM, my user, and Administrators group have full permissions - everything other than "special permissions" is checked under Allow for all 3 users/groups (my user, Administrators, SYSTEM) What's going on?!

    Read the article

  • C++, Ifstream opens local file but not file on HTTP Server

    - by fammi
    Hi, I am using ifstream to open a file and then read from it. My program works fine when i give location of the local file on my system. for eg /root/Desktop/abc.xxx works fine But once the location is on the http server the file fails to open. for eg http://192.168.0.10/abc.xxx fails to open. Is there any alternate for ifstream when using a URL address? thanks. part of the code where having problem: bool readTillEof = (endIndex == -1) ? true : false; // Open the file in binary mode and seek to the end to determine file size ifstream file ( fileName.c_str ( ), ios::in|ios::ate|ios::binary ); if ( file.is_open ( ) ) { long size = (long) file.tellg ( ); long numBytesRead; if ( readTillEof ) { numBytesRead = size - startIndex; } else { numBytesRead = endIndex - startIndex + 1; } // Allocate a new buffer ptr to read in the file data BufferSptr buf (new Buffer ( numBytesRead ) ); mpStreamingClientEngine->SetResponseBuffer ( nextRequest, buf ); // Seek to the start index of the byte range // and read the data file.seekg ( startIndex, ios::beg ); file.read ( (char *)buf->GetData(), numBytesRead ); // Pass on the data to the SCE // and signal completion of request mpStreamingClientEngine->HandleDataReceived( nextRequest, numBytesRead); mpStreamingClientEngine->MarkRequestCompleted( nextRequest ); // Close the file file.close ( ); } else { // Report error to the Streaming Client Engine // as unable to open file AHS_ERROR ( ConnectionManager, " Error while opening file \"%s\"\n", fileName.c_str ( ) ); mpStreamingClientEngine->HandleRequestFailed( nextRequest, CONNECTION_FAILED ); } }

    Read the article

  • How do I open a file in such a way that if the file doesn't exist it will be created and opened automatically?

    - by snakile
    Here's how I open a file for writing+ : if( fopen_s( &f, fileName, "w+" ) !=0 ) { printf("Open file failed\n"); return; } fprintf_s(f, "content"); If the file doesn't exist the open operation fails. What's the right way to fopen if I want to create the file automatically if the file doesn't already exist? EDIT: If the file does exist, I would like fprintf to overwrite the file, not to append to it.

    Read the article

  • ASP.NET Speed up DataView sorting/paging

    - by rlb.usa
    I have a page in ASP.NET where I'm using a Repeater to display a record listing. But it's slow as molasses, I've been tasked with speeding it up (sorting,paging). I've got it set up as follows: When user enters page, grab all of the data from the database (500 records, up to 4 relation'ed records) Store it all in Application["MyDataView"] On sort or paging, simply use the data view's internal sort/page method (no db calls) and rebind. I understand that databases can take time to query, but simply to have the DataView call it's sort method (no db calls) takes 10ish seconds, that's an alarmingly slow. Two questions: Why is it taking so long? How can I speed it up? A gridview is not possible.

    Read the article

  • Problem with File uplolad in javascript.

    - by Nikhil
    I have used javascript to upload more than one file. when user clicks on 'add more' javascript appends new object to older div using innerHTML. Now the problem is if I select a file and then click on "add more" then new file button exist but older selected file removes and two blank file buttons display. I want this old file must be selected when user add new file button. If anybody can, Help Plz!!! tnX.

    Read the article

  • excel cannot open the file xxx.xlsx' because the file format is not valid error

    - by Yavuz
    I have difficulty open opening word and excel files suddenly. Only particular office file give me the problem. These files were previously scanned by combo fix and I believe they were damaged. The error response that I from office is Excel cannot open the file xxx.xlsx because the file format is not valid. Verify that the file has not been corrupted and that the file extension matches the format of the file. This is for excel and a similar kind of error response comes for word. The file looks fine. I mean the size vise... Please help me with this problem. I really appreciate your help and time....

    Read the article

  • Upon clicking on a file, excel opens but not the file itself

    - by william
    Platform: Windows XP SP2, Excel 2007 Problem description: Upon clicking on a file in Windows Explorer (file is either .xls or .xlsx) Excel 2007 opens, but does not open the file itself. I need either to click on a file again in Windows Explorer or open it manually with File/Open ... from Excel. Does anyone know what could cause this rather strange behaviour ? The old versions of Excel worked "normally" ... i.e. upon clicking on a file, an Excel would open along with the file. Please, help !

    Read the article

< Previous Page | 14 15 16 17 18 19 20 21 22 23 24 25  | Next Page >