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  • System wide Proxy settings when on a windows network with a password

    - by sav
    I'm using Ubuntu on a windows network. I want to connect to the world wide web. I have followed the steps here which I have found very useful. However when I try to ping a website (eg: ping www.wikipedia.org) I get no reply. I can ping local computers on my network, but I need to go through our proxy to get to the world wide web. I can even browse wikipedia using firefox, I just needed to enter the proxy configuration script location and my username and password. I'm quite sure the reason I'm having this trouble is because I havn't entered a username and password. I'm not sure how to do this on a system wide level. ultimately I would like to be able to use package managers like synaptic but first I need them to be able to connect to the internet. EDIT As sugested I created a /etc/apt/apt.conf file like Acquire::http::Proxy "http://chrisav:[email protected]:8080"; Acquire::https::Proxy "https://chrisav:[email protected]:8080"; Acquire::ftp::Proxy "ftp://chrisav:[email protected]:8080"; Acquire::socks::Proxy "socks://chrisav:[email protected]:8080"; However I still cant ping wikipedia when I try installing stuff I get chris@chris-Ubuntu:~$ sudo apt-get install kate Reading package lists... Done Building dependency tree Reading state information... Done E: Unable to locate package kate

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  • PDFtk Password Protection Help

    - by Dave W.
    I am using Ubuntu 11.10 and am looking for a solution to password protect a bunch of pdf files in a directory in batch. I came across PDFtk and it looks like it might do what I need, but I've reviewed the command line PDFtk examples and can't figure out if there is a way to do it in batch without having to individually specify the output file name for every file. I'm hoping a command-line guru can take a look at the PDFtk syntax and tell me if there is some trick / command that will allow me to password protect a directory of pdf files (e.g., *.pdf) and overwrite the existing files using the same name, or consistently rename the individual output files without having to specify each output name individually. Here's a link to the PDFtk command line examples page: http://www.pdflabs.com/tools/pdftk-the-pdf-toolkit/ Thanks for your help. I think I've answered my own question. Here's a bash script that appears to do the trick. I'd welcome help evaluating why the code I've commented out doesn't work... #!/bin/bash # Created by Dave, 2012-02-23 # This script uses PDFtk to password protect every PDF file # in the directory specified. The script creates a directory named "protected_[DATE]" # to hold the password protected version of the files. # # I'm using the "user_pw" parameter, # which means no one will be able to open or view the file without # the password. # # PDFtk must be installed for this script to work. # # Usage: ./protect_with_pdftk.bsh [FILE(S)] # [FILE(S)] can use wildcard expansion (e.g., *.pdf) # This part isn't working.... ignore. The goal is to avoid errors if the # directory to be created already exists by only attempting to create # it if it doesn't exists # #TARGET_DIR="protected_$(date +%F)" #if [ -d "$TARGET_DIR" ] #then #echo # echo "$TARGET_DIR directory exists!" #else #echo # echo "$TARGET_DIR directory does not exist!" #fi # mkdir protected_$(date +%F) for i in *pdf ; do pdftk "$i" output "./protected_$(date +%F)/$i" user_pw [PASSWORD]; done echo "Complete. Output is in the directory: ./protected_$(date +%F)"

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  • Still prompted for a password after adding SSH public key to a server

    - by Nathan Arthur
    I'm attempting to setup a git repository on my Dreamhost web server by following the "Setup: For the Impatient" instructions here. I'm having difficulty setting up public key access to the server. After successfully creating my public key, I ran the following command: cat ~/.ssh/[MY KEY].pub | ssh [USER]@[MACHINE] "mkdir ~/.ssh; cat >> ~/.ssh/authorized_keys" ...replacing the appropriate placeholders with the correct values. Everything seemed to go through fine. The server asked for my password, and, as far as I can tell, executed the command. There is indeed a ~/.ssh/authorized_keys file on the server. The problem: When I try to SSH into the server, it still asks for my password. My understanding is that it shouldn't be asking for my password anymore. What am I missing? EDIT: SSH -v Log: Macbook:~ michaeleckert$ ssh -v [USER]@[SERVER URL] OpenSSH_6.2p2, OSSLShim 0.9.8r 8 Dec 2011 debug1: Reading configuration data /etc/ssh_config debug1: /etc/ssh_config line 20: Applying options for * debug1: /etc/ssh_config line 53: Applying options for * debug1: Connecting to [SERVER URL] [[SERVER IP]] port 22. debug1: Connection established. debug1: identity file /Users/michaeleckert/.ssh/id_rsa type -1 debug1: identity file /Users/michaeleckert/.ssh/id_rsa-cert type -1 debug1: identity file /Users/michaeleckert/.ssh/id_dsa type -1 debug1: identity file /Users/michaeleckert/.ssh/id_dsa-cert type -1 debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_6.2 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.5p1 Debian-6+squeeze3 debug1: match: OpenSSH_5.5p1 Debian-6+squeeze3 pat OpenSSH_5* debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Server host key: RSA [STRING OF NUMBERS AND LETTERS SEPARATED BY SEMI-COLONS] debug1: Host ‘[SERVER URL]' is known and matches the RSA host key. debug1: Found key in /Users/michaeleckert/.ssh/known_hosts:2 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: Roaming not allowed by server debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,password debug1: Next authentication method: publickey debug1: Trying private key: /Users/michaeleckert/.ssh/id_rsa debug1: Trying private key: /Users/michaeleckert/.ssh/id_dsa debug1: Next authentication method: password [USER]@[SERVER URL]'s password: debug1: Authentication succeeded (password). Authenticated to [SERVER URL] ([[SERVER IP]]:22). debug1: channel 0: new [client-session] debug1: Requesting [email protected] debug1: Entering interactive session. debug1: Sending environment. debug1: Sending env LANG = en_US.UTF-8 Welcome to [SERVER URL] Any malicious and/or unauthorized activity is strictly forbidden. All activity may be logged by DreamHost Web Hosting. Last login: Sun Nov 3 12:04:21 2013 from [MY IP] [[SERVER NAME]]$

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  • change password.......

    - by shimaTun
    I've created a code to change a password. Now it seem contain an error. When I fill in the form to change password, and click save the error message: You forgot enter your userid! Please try again. I really don’t know what the error message means. Please guys. Help me fix it. Here's is the code: <?php # change password.php //set the page title and include the html header. $page_title = 'Change Your Password'; //include('templates/header.inc'); if(isset($_POST['submit'])){//handle the form require_once('connectioncomplaint.php');//connect to the db. //include "connectioncomplaint.php"; //create a function for escaping the data. function escape_data($data){ global $dbc;//need the connection. if(ini_get('magic_quotes_gpc')){ $data=stripslashes($data); } return mysql_real_escape_string($data); }//end function $message=NULL;//create the empty new variable. //check for a username if(empty($_POST['userid'])){ $u=FALSE; $message .='<p> You forgot enter your userid!</p>'; }else{ $u=escape_data($_POST['userid']); } //check for existing password if(empty($_POST['password'])){ $p=FALSE; $message .='<p>You forgot to enter your existing password!</p>'; }else{ $p=escape_data($_POST['password']); } //check for a password and match againts the comfirmed password. if(empty($_POST['password1'])) { $np=FALSE; $message .='<p> you forgot to enter your new password!</p>'; }else{ if($_POST['password1'] == $_POST['password2']){ $np=escape_data($_POST['password1']); }else{ $np=FALSE; $message .='<p> your new password did not match the confirmed new password!</p>'; } } if($u && $p && $np){//if everything's ok. $query="SELECT userid FROM access WHERE (userid='$u' AND password=PASSWORD('$p'))"; $result=@mysql_query($query); $num=mysql_num_rows($result); if($num == 1){ $row=mysql_fetch_array($result, MYSQL_NUM); //make the query $query="UPDATE access SET password=PASSWORD('$np') WHERE userid=$row[0]"; $result=@mysql_query($query);//run the query. if(mysql_affected_rows() == 1) {//if it run ok. //send an email,if desired. echo '<p><b>your password has been changed.</b></p>'; //include('templates/footer.inc');//include the HTML footer. exit();//quit the script. }else{//if it did not run OK. $message= '<p>Your password could not be change due to a system error.We apolpgize for any inconvenience.</p><p>' .mysql_error() .'</p>'; } }else{ $message= '<p> Your username and password do not match our records.</p>'; } mysql_close();//close the database connection. }else{ $message .='<p>Please try again.</p>'; } }//end of the submit conditional. //print the error message if there is one. if(isset($message)){ echo'<font color="red">' , $message, '</font>'; } ?> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">

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  • What guarantees are there on the run-time complexity (Big-O) of LINQ methods?

    - by tzaman
    I've recently started using LINQ quite a bit, and I haven't really seen any mention of run-time complexity for any of the LINQ methods. Obviously, there are many factors at play here, so let's restrict the discussion to the plain IEnumerable LINQ-to-Objects provider. Further, let's assume that any Func passed in as a selector / mutator / etc. is a cheap O(1) operation. It seems obvious that all the single-pass operations (Select, Where, Count, Take/Skip, Any/All, etc.) will be O(n), since they only need to walk the sequence once; although even this is subject to laziness. Things are murkier for the more complex operations; the set-like operators (Union, Distinct, Except, etc.) work using GetHashCode by default (afaik), so it seems reasonable to assume they're using a hash-table internally, making these operations O(n) as well, in general. What about the versions that use an IEqualityComparer? OrderBy would need a sort, so most likely we're looking at O(n log n). What if it's already sorted? How about if I say OrderBy().ThenBy() and provide the same key to both? I could see GroupBy (and Join) using either sorting, or hashing. Which is it? Contains would be O(n) on a List, but O(1) on a HashSet - does LINQ check the underlying container to see if it can speed things up? And the real question - so far, I've been taking it on faith that the operations are performant. However, can I bank on that? STL containers, for example, clearly specify the complexity of every operation. Are there any similar guarantees on LINQ performance in the .NET library specification?

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  • 1) PasswordResets emails user when requesting password reset

    - by Surge Pedroza
    I've been trying to add a password reset for users that forget their password. The users clicks on forgot password? on sign up page. Then the user types their email and clicks reset password, which creates a token and sends an email with a link to reset their password. For the most part, it was working well, and then it suddenly stopped working. When a user clicks password reset, it brings up the error message: Password cant be blank, password is too short(6 min) Ran into this error in video 275 How I Test. on 11:20 Failure/Error: click_button "Reset Password" ActiveRecord::RecordInvalid: Validation failed: Password can't be blank, Password is too short (minimum is 6 characters), Password confirmation can't be blank # ./app/models/user.rb:30:in send_password_reset' # ./app/controllers/password_resets_controller.rb:7:increate' # (eval):2:in click_button' # ./spec/requests/password_resets_spec.rb:9:inblock (2 levels) in ' Finished in 13.66 seconds 95 examples, 1 failure This is some of the code being used. user.rb # == Schema Information # # Table name: users # # id :integer not null, primary key # name :string(255) # email :string(255) # created_at :datetime not null # updated_at :datetime not null # class User < ActiveRecord::Base attr_accessible :name, :email, :password, :password_confirmation has_secure_password before_save { |user| user.email = email.downcase } before_save :create_remember_token validates :name, presence: true, length: { maximum: 50 } VALID_EMAIL_REGEX = /\A[\w+\-.]+@[a-z\d\-.]+\.[a-z]+\z/i validates :email, presence: true, format: { with: VALID_EMAIL_REGEX }, uniqueness: { case_sensitive: false } validates :password, presence: true, length: { minimum: 6 } validates :password_confirmation, presence: true def send_password_reset generate_token(:password_reset_token) self.password_reset_sent_at = Time.zone.now save! UserMailer.password_reset(self).deliver end def generate_token(column) begin self[column] = SecureRandom.urlsafe_base64 end while User.exists?(column => self[column]) end def self.search(search) if search find(:all, :conditions => ['name LIKE ?', "%#{search}%"]) else find(:all) end end private def create_remember_token self.remember_token = SecureRandom.urlsafe_base64 end end password_resets_controller.rb class PasswordResetsController < ApplicationController def new end def create user = User.find_by_email(params[:email]) user.send_password_reset redirect_to root_url, :notice => "Email sent with password reset instructions." end def edit @user = User.find_by_password_reset_token!(params[:id]) end end new.html.erb <h1>Reset Password</h1> <%= form_tag password_resets_path, :method => :post do %> <div class="field"> <%= label_tag :email %> <%= text_field_tag :email, params[:email] %> </div> <div class="actions"><%= submit_tag "Reset Password" %></div> <% end %>

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  • Password protect user image album

    - by Poland Rocks
    Hi Im making i photo sharint site I want to give the ability for my users to prevent the public to acces their albums with a password. Then they can give the password to the ones they want to be able to see it. To password protect their albums. Im thinking something like this, cant test it on this computer, should work ok. but as im a php/mysql beginner i wanna hear what you experts think if theres a better way/approach Albums id name owner password (if it isnt null the album is considered password protected) The code $id = isset($_GET['albumID']) ? intval($_GET['albumID']) : 0; $result = mysql_query("SELECT * FROM albums WHERE id = $id"); $row = mysql_fetch_object($result); // IS it password protected? if ($row->password != NULL) { echo "This album is password protected."; // User pressed "Enter" if (!empty($_POST['password'])) { $result = mysql_query("SELECT password FROM albums WHERE password = '".mysql_real_escape_string($_POST['password'])."'"); // Was It right password? if (mysql_num_rows($result) == 1) { $authed=1; } echo << <form method="post"> <input type="text" name="password" /> EOT; exit; } else $authed=1; if $authed==1 { // render albumimages etc }

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  • "Password Server: Stopped" on Mac OS Lion Server. Stops with error -1 during startup

    - by V1ru8
    Since I've restored the Open Directory from an archive because my Server crashed and the DB was corrupt. The password server does not start anymore. The log looks like this: Feb 14 2012 21:41:20 156746us Mac OS X Password Service version 376.1 (pid = 2438) was started at: Tue Feb 14 21:41:20 2012. Feb 14 2012 21:41:20 156801us RunAppThread Created Feb 14 2012 21:41:20 156852us RunAppThread Started Feb 14 2012 21:41:20 156879us Initializing Server Globals ... Feb 14 2012 21:41:20 163094us Initializing Networking ... Feb 14 2012 21:41:20 163196us Initializing TCP ... Feb 14 2012 21:41:20 191790us SASL is using realm "SERVER.HOME.POST-NET.CH" Feb 14 2012 21:41:20 191847us Starting Central Thread ... Feb 14 2012 21:41:20 191860us Starting other server processes ... Feb 14 2012 21:41:20 191873us StartCentralThreads: 1 threads to stop Feb 14 2012 21:41:20 191905us Initializing TCP ... Feb 14 2012 21:41:20 191954us Starting TCP/IP Listener on ethernet interface, port 106 Feb 14 2012 21:41:20 192012us Starting TCP/IP Listener on ethernet interface, port 3659 Feb 14 2012 21:41:20 192048us Starting TCP/IP Listener on interface lo0, port 106 Feb 14 2012 21:41:20 192082us Starting TCP/IP Listener on interface lo0, port 3659 Feb 14 2012 21:41:20 192117us StartCentralThreads: Created 4 TCP/IP Connection Listeners Feb 14 2012 21:41:20 192132us Starting UNIX domain socket listener /var/run/passwordserver Feb 14 2012 21:41:20 193034us CRunAppThread::StartUp: caught error -1. Feb 14 2012 21:41:20 193056us ** ERROR: The Server received an error during startup. See error log for details. Feb 14 2012 21:41:20 193075us RunAppThread::StartUp() returned: 4294967295 Feb 14 2012 21:41:20 193107us Stopping server processes ... Feb 14 2012 21:41:20 193119us Stopping Network Processes ... Feb 14 2012 21:41:20 193131us Deinitializing networking ... Feb 14 2012 21:41:20 193149us Server Processes Stopped ... Feb 14 2012 21:41:20 193165us RunAppThread Stopped Feb 14 2012 21:41:20 193202us Aborting Password Service. See error log. The error log repeats the following: Feb 14 2012 21:41:50 409022us Server received error -1 during startup. Feb 14 2012 21:41:50 409141us Aborting Password Service. Anyone an idea what's wrong here and how I can fix this?

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  • Password Cracking Windows Accounts

    - by Kevin
    At work we have laptops with encrypted harddrives. Most developers here (on occasion I have been guilty of it too) leave their laptops in hibernate mode when they take them home at night. Obviously, Windows (i.e. there is a program running in the background which does it for windows) must have a method to unencrypt the data on the drive, or it wouldn't be able to access it. That being said, I always thought that leaving a windows machine on in hibernate mode in a non-secure place (not at work on a lock) is a security threat, because someone could take the machine, leave it running, hack the windows accounts and use it to encrypt the data and steal the information. When I got to thinking about how I would go about breaking into the windows system without restarting it, I couldn't figure out if it was possible. I know it is possible to write a program to crack windows passwords once you have access to the appropriate file(s). But is it possible to execute a program from a locked Windows system that would do this? I don't know of a way to do it, but I am not a Windows expert. If so, is there a way to prevent it? I don't want to expose security vulnerabilities about how to do it, so I would ask that someone wouldn't post the necessary steps in details, but if someone could say something like "Yes, it's possible the USB drive allows arbitrary execution," that would be great! EDIT: The idea being with the encryption is that you can't reboot the system, because once you do, the disk encryption on the system requires a login before being able to start windows. With the machine being in hibernate, the system owner has already bypassed the encryption for the attacker, leaving windows as the only line of defense to protect the data.

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  • php regex for strong password validation

    - by Jason
    Hello, I've seen around the web the following regex (?=^.{8,}$)((?=.*\d)|(?=.*\W+))(?![.\n])(?=.*[A-Z])(?=.*[a-z]).*$ which validates only if the string: * contain at least (1) upper case letter * contain at least (1) lower case letter * contain at least (1) number or special character * contain at least (8) characters in length I'd like to know how to convert this regex so that it checks the string to * contain at least (2) upper case letter * contain at least (2) lower case letter * contain at least (2) digits * contain at least (2) special character * contain at least (8) characters in length well if it contains at least 2 upper,lower,digits and special chars then I wouldn't need the 8 characters length. special characters include: `~!@#$%^&*()_-+=[]\|{};:'".,/<? thanks in advance.

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  • How can I make an expect script prompt for a password?

    - by MiniQuark
    I have an expect script that connects to a few routers through ssh. All these routers have the same password (I know, it's wrong), and the script needs to know that password in order to be able to connect to the routers. Currently, the password is passed to my script as an argument on the command line, but this means that there's a trace of that password in my .bash_history file as well as in the running processes. So instead I would like the user to be prompted for a password, if possible silently. Do you know whether or not it's possible to prompt the user for a password with expect? Thank you. Edit: if I was connecting to servers instead of routers, I would probably use ssh keys instead of passwords. But the routers I'm using just support passwords.

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  • C# - Password Database

    - by user335932
    So I want to make a program that allows you to store and search for user names/passwords for online sites there signed up to. I know C# has some database options but I don't know much about it. I also heard that it can read/write excel files. Whats do you think is best for storing the data? ALSO do databases need to be stored online on a sever, or can they reside in the program files?

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  • Form, function and complexity in rule processing

    Tim Bass posted on Orwellian Event Processing.I was involved in a heated exchange in the comments, and he has more recently published a post entitled Disadvantages of Rule-Based Systems (Part 1).Whatever the rights and wrongs of our exchange, it clearly failed to generate any agreement or understanding of our different positions.I don't particularly want to promote further argument of that kind, but I do want to take the opportunity of offering a different perspective on rule-processing and an explanation...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Python — Time complexity of built-in functions versus manually-built functions in finite fields

    - by stackuser
    Generally, I'm wondering about the advantages versus disadvantages of using the built-in arithmetic functions versus rolling your own in Python. Specifically, I'm taking in GF(2) finite field polynomials in string format, converting to base 2 values, performing arithmetic, then output back into polynomials as string format. So a small example of this is in multiplication: Rolling my own: def multiply(a,b): bitsa = reversed("{0:b}".format(a)) g = [(b<<i)*int(bit) for i,bit in enumerate(bitsa)] return reduce(lambda x,y: x+y,g) Versus the built-in: def multiply(a,b): # a,b are GF(2) polynomials in binary form .... return a*b #returns product of 2 polynomials in gf2 Currently, operations like multiplicative inverse (with for example 20 bit exponents) take a long time to run in my program as it's using all of Python's built-in mathematical operations like // floor division and % modulus, etc. as opposed to making my own division, remainder, etc. I'm wondering how much of a gain in efficiency and performance I can get by building these manually (as shown above). I realize the gains are dependent on how well the manual versions are built, that's not the question. I'd like to find out 'basically' how much advantage there is over the built-in's. So for instance, if multiplication (as in the example above) is well-suited for base 10 (decimal) arithmetic but has to jump through more hoops to change bases to binary and then even more hoops in operating (so it's lower efficiency), that's what I'm wondering. Like, I'm wondering if it's possible to bring the time down significantly by building them myself in ways that maybe some professionals here have already come across.

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  • Don&rsquo;t Kill the Password

    - by Anthony Trudeau
    A week ago Mr. Honan from Wired.com penned an article on security he titled “Kill the Password: Why a String of Characters Can’t Protect Us Anymore.” He asserts that the password is not effective and a new solution is needed. Unfortunately, Mr. Honan was a victim of hacking. As a result he has a victim’s vendetta. His conclusion is ill conceived even though there are smatterings of truth and good advice. The password is a security barrier much like a lock on your door. In of itself it’s not guaranteeing protection. You can have a good password akin to a steel reinforced door with the best lock money can buy, or you can have a poor password like “password” which is like a sliding lock like on a bathroom stall. But, just like in the real world a lock isn’t always enough. You can have a lock, security system, video cameras, guard dogs, and even armed security guards; but none of that guarantees your protection. Even top secret government agencies can be breached by someone who is just that good (as dramatized in movies like Mission Impossible). And that’s the crux of it. There are real hackers out there that are that good. Killer coding ninja monkeys do exist! We still have locks on our doors, because they still serve their role. Passwords are no different. Security doesn’t end with the password. Most people would agree that stuffing your mattress with your life savings isn’t a good idea even if you have the best locks and security system. Most people agree its safest to have the money in a bank. Essentially this is compartmentalization. Compartmentalization extends to the online world as well. You’re at risk if your online banking accounts are linked to the same account as your social networks. This is especially true if you’re lackadaisical about linking those social networks to outside sources including apps. The object here is to minimize the damage that can be done. An attacker should not be able to get into your bank account, because they breached your Twitter account. It’s time to prioritize once you’ve compartmentalized. This simply means deciding how much security you want for the different compartments which I’ll call security zones. Social networking applications like Facebook provide a lot of security features. However, security features are almost always a compromise with privacy and convenience. It’s similar to an engineering adage, but in this case it’s security, convenience, and privacy – pick two. For example, you might use a safe instead of bank to store your money, because the convenience of having your money closer or the privacy of not having the bank records is more important than the added security. The following are lists of security do’s and don’ts (these aren’t meant to be exhaustive and each could be an article in of themselves): Security Do’s: Use strong passwords based on a phrase Use encryption whenever you can (e.g. HTTPS in Facebook) Use a firewall (and learn to use it properly) Configure security on your router (including port blocking) Keep your operating system patched Make routine backups of important files Realize that if you’re not paying for it, you’re the product Security Don’ts Link accounts if at all possible Reuse passwords across your security zones Use real answers for security questions (e.g. mother’s maiden name) Trust anything you download Ignore message boxes shown by your system or browser Forget to test your backups Share your primary email indiscriminately Only you can decide your comfort level between convenience, privacy, and security. Attackers are going to find exploits in software. Software is complex and depends on other software. The exploits are the responsibility of the software company. But your security is always your responsibility. Complete security is an illusion. But, there is plenty you can do to minimize the risk online just like you do in the physical world. Be safe and enjoy what the Internet has to offer. I expect passwords to be necessary just as long as locks.

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  • Missing "log on to" field in Windows 2008 password change dialog

    - by Dmitri Chubarov
    I have to setup an embedded standalone CIFS server outside of domain environment. I shall refer to the server as storage_gateway. The default password setting for the Administrator account is Password must be changed. Until Administrator password is changed other local accounts are disabled. While the server is on default password connecting to a share causes fails with NT_STATUS_PASSWORD_MUST_CHANGE error. $ smbclient -L //storage_gateway -U Administrator session setup failed: NT_STATUS_PASSWORD_MUST_CHANGE I have a mixed Linux/Windows environment and prefer smbclient for diagnostics. To change the password in Windows 2003 Server I could press CTRL-ALT-DEL to get into the Windows Security window and change password for the remote server specifying the server name or ip address (xx.xx.xx.xx) in the system password change dialog. (the name root is just an example, I have edited the dialogs to translate them) However in Windows 2008 the corresponding dialog lacks the Log on to field. Is there a way to change a remote password in Windows 2008 Server/Windows 7?

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  • In Windows 8, how do you disable the unlock password for Microsoft Accounts?

    - by Huckle
    In Windows 8, in the scenario where there is a single user that has a Microsoft Account (i.e., they have created their account via a Microsoft email address) how does one disable the password prompt when unlocking the screen? The Windows 7 analogy would be to disable the screensaver password prompt. I can do this on a "local" account (one not backed by Microsoft) but the setting seems to have no effect on connected accounts. To replicate: create an account using [email protected] or [email protected] Lock the screen with WinKey+L Attempt to unlock, by clicking the mouse, without entering a password.

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  • Linksys router cannot change default password

    - by Jessica M.
    My wireless internet suddenly stopped working today. I have Windows 7 and Lindsys WRT54G router. I tried to log into the Linksys setup router page by typing in www.192.168.1.1 into firefox and it prompted me for a username and password as usual. The problem is when i tried to enter my regular username and password it did not work. I finally solved my problem when I came across this post here and the very last post solved my problem. It suggested I try username: root / password: admin. For some reason the username and password has been changed. When i tried username: root / password: admin , it worked and allowed me to get into the Linksys setup page. The problem is I can't change the username or password anymore. Every time I want to log into my Linksys setup page I have to enter username: root / password: admin. I can't change the "WPA shared key" (password). For the security settings I selected WPA2Personal + AES. Also the post said "If the firmware was upgraded to non-linksys firmware - the default will be different" . The problem is I didn't update anything and I'm worried that someone installed a virus or something or somehow changed the firmware on my router. How did I get non-Linksys firmware on my router? EDIT: I figured out how to change the password when I log into the Lynksys setup page. Administration -- Management -- password. I still don't understand if my router firmware was changed or who changed it or if it happened by mistake.

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  • Expired password change through VPN failure

    - by Tim Alexander
    I am setting up some new accounts to be used by some contractors. they are going to connect via VPN to our network. My requirement is to set the password initially and then have them change it the first time they log in. As a result the "User must Change Password" box is checked. Loading up a laptop and testing has yielded poor results. When logging in I get a notification that the password has expired and a box to fill in, which I do. it then appears again so I dutifully fill in the password details again. I am then presented with a "Sending Password...." error box with Error:619 listed as the reason. Trying to reconnect then gives a 691 error that the password is bad. From the firewall, that is the actualy VPN server, I can see RAD_ACCESS_DENIED and from the DC running NPS (acting as a RADIUS server for the firewall with MS-CHAP-v2 enabled with the "User can change password after it has expired" checked) I cannot see a request to change the password. I can only see Event ID 4776, 4625 and 6273 (reason 16). I can log in with out the change password flag fine so I know logins are being authenticated. Really hoping someone might be able to assist in tracking down the lack of password change processin gon the DC.

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  • Evolution of mainstream programming languages: simplicity versus complexity.

    - by Giorgio
    I had posted this question on http://stackoverflow.com but I was suggested that it may be more appropriate to post it on this forum. I did a quick search on this site and it seems to me that this question has not been asked yet. Please give me a hint if the topic has been raised already by someone else. Update I have rephrased this question, removed personal opinions and made it shorter. I hope in this way it is better suited for this forum. By looking at the recent development of Java (Java 7) and C++ (C++0x) I see that new features are added to these languages. For sure this makes it easier to use certain programming idioms, adding to the productivity of developers. On the other hand, there might be the following risks A language becomes too big, complex, and difficult to understand. It lacks coherence in the design, e.g. if it mixes different paradigms like object-orientation and functional programming, which might not fit well together. Questions: what is more important to you as a developer: to have a rich language that captures a large collection of programming idioms or to have a small language that aims at coherence and simplicity (of course, with a good deal of libraries and tools accompanying it)? Or is it possible to have both? With respect to these issues: How do you judge the current evolutions of main-stream programming languages like Java or C++? Are they becoming too complex, less intuitive? Do they have enough features? Do they need more? Are they still easy enough to understand and use?

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  • User password rejected on login screen but accepted on text console login

    - by MadsirR
    I had to force shutdown my Ubuntu 12.04 64-bit, after which I restarted and tried to log in as a normal user, which was rejected several times. I then logged in as guest and tty to my regular account with use of my normal password, which succeeded. (So the password is still valid.) How can I gain access again via the normal login procedure (welcome screen)? Update: When I tried to log on with my new password, it again was denied. When I deliberately tried to log on with a faulty password, an error message came back, saying: Access denied - wrong password. I suppose, the first time the password was not rejected, but the procedure was aborted for some reason. Some additional info after trying to find a solution: I am conviced it is a Compiz-issue. Why? before this happened, all sessions came to a grinding halt, regardless of being logged on in a 2D or 3d environment. I found a link saying that I should remove Compiz and proceed in a 2D environment, which initiall worked without a glitch, until my system went into a state of total obivium. Only after that, the above mentioned troubles appeared. In the meantime I have happened to find a thread with reference 17381, describing exactly what I have experienced. For now, I will try to cure this situation (later this week) and revert with the results, hopefully to close this post. In the meantime I cordially thank you all, even if you didn't kill the problem; you gave me the inspiration to look further and find a possible cure. Update2: After 15 hrs of trial-and-error I callled it quits (When I decided to tackle this problem, I've given myself 12 hrs, to avoid massive loss of time.) I decided to re-install Precise, since the "point 1" version has become availabe. Log-in is back to normal, as is the graphic environment. Response to mouse input is stil appalling, especially when I have a series of screens open as "children"of a "parent" screen. It still completely locks up. I have installed Enlightenment, Gnome classic, Gnome 3, Cinnamon and they all behave in a similar fashion. FOR THOSE WHO NEED A WAY-OUT IN SITUATIONS OF THE LIKE: Open a terminal with [Ctrl+Alt+F2]. Type [sudo killall Firefox] (or whatever application you wish to terminate). Key in your password. Return to your graphical screen with [Ctrl+Alt+F7], and Bob's your uncle. Just re-open Firefox like nothing happened. Next time you are stuck: [Ctrl+Alt+F2], upward arrow till you meet the command of your desire, [Ctrl+Alt+F7], etcetera. Hope this is of help. My next move will be to upgrade the kernel to 3.4 from the repositories for 12.10. However, since this entails a totally new situation, I will start a new thread on this site to avoid topic pollution I will keep you posted. Still.

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  • How to make xlock use the first key I hit as a part of my password

    - by alesplin
    I just switched from Arch Linux to Ubuntu 10.10. I'm running the Fluxbox window manager, and I use xlockmore to lock my screen with the following key shortcut: 192 :Exec xlock-mode marquee +usefirst -icongeometry 240x240 -message "back in a minute..." The problem I'm having is that xlock is definitely not using my first key as part of my password. Instead, it uses some randomized fade pattern to fade to the password screen. I find this highly annoying, as when I get back to my desk and start entering my password it doesn't register password characters until the fade pattern is complete. I've also tried the following modifications with no difference: 192 :Exec xlock -mode marquee -usefirst -icongeometry 240x240 -message "back in a minute..." 192 :Exec xlock -mode marquee -icongeometry 240x240 -message "back in a minute..." The first example worked flawlessly on Arch. Does Ubuntu have some sort of system default that you can't override on the command-line?

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  • Force a Windows 7 user to change password when it has expired

    - by Joshua King
    Is it possible to force users (on Windows 7 PCs) to change their password once it has expired? Currently our users get notifications that their passwords will expire in 7, 3, 2 and 1 days but once the password has expired they are still able to log into their machines with the expired password. Most of our users ignore the warnings and don't change their password until we tell them they have to (when they ring Help Desk asking why their email and intranet isn't working). From memory, Windows XP machines would show a message at login that the password had expired and then offer the change password screen. Is it possible to do the same thing under Win7? Similar to how if you set a user's account to "must change password at next login" it gives the change password screen automatically.

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