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  • Polling a running php cli script

    - by B_
    I want to run a php script from the command line that is always running and constantly updating a variable. I then want any php script that is run in the meantime (probably but not necessarily from the web) to be able to read that variable at any time. Anyone know how I can do this? Thanks.

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  • PHP SASL(PECL) sasl_server_init(app) works with CLI but not with ApacheModule

    - by ZokRadonh
    I have written a simple auth script so that Webusers can type in their username and password and my PHP script verifies them by SASL. The SASL Library is initialized by php function sasl_server_init("phpfoo"). So phpfoo.conf in /etc/sasl2/ is used. phpfoo.conf: pwcheck_method: saslauthd mech_list: PLAIN LOGIN log_level: 9 So the SASL library now tries to connect to saslauthd process by socket. saslauthd command line looks like this: /usr/sbin/saslauthd -r -V -a pam -n 5 So saslauthd uses PAM to authenticate. In the php script I have created sasl connection by sasl_server_new("php", null, "myRealm"); The first argument is the servicename. So PAM uses the file /etc/pam.d/php to see for further authentication information. /etc/pam.d/php: auth required pam_mysql.so try_first_pass=0 config_file=/etc/pam.d/mysqlconf.nss account required pam_permit.so session required pam_permit.so mysqlconf.nss has all information that is needed for a useful MySQL Query to user table. All of this works perfectly when I run the script by command line. php ssasl.php But when I call the same script via webbrowser(php apache module) I get an -20 return code (SASL_NOUSER). In /var/log/messages there is May 18 15:27:12 hostname httpd2-prefork: unable to open Berkeley db /etc/sasldb2: No such file or directory I do not have anything with a Berkeley db for authentication with SASL. I think authentication using /etc/sasldb2 is the default setting. In my opinion it does not read my phpfoo.conf file. For some reason the php-apache-module ignores the parameter in sasl_server_init("phpfoo"). My first thought was that there is a permission issue. So back in shell: su -s /bin/bash wwwrun php ssasl.php "Authentication successful". - No file-permission issue. In the source of the sasl-php-extension we can find: PHP_FUNCTION(sasl_server_init) { char *name; int name_len; if (zend_parse_parameters(1 TSRMLS_CC, "s", &name, &name_len) == FAILURE) { return; } if (sasl_server_init(NULL, name) != SASL_OK) { RETURN_FALSE; } RETURN_TRUE; } This is a simple pass through of the string. Are there any differences between the PHP CLI and PHP ApacheModule version that I am not aware of? Anyway, there are some interesting log entries when I run PHP in CLI mode: May 18 15:44:48 hostname php: SQL engine 'mysql' not supported May 18 15:44:48 hostname php: auxpropfunc error no mechanism available May 18 15:44:48 hostname php: _sasl_plugin_load failed on sasl_auxprop_plug_init for plugin: sqlite May 18 15:44:48 hostname php: sql_select option missing May 18 15:44:48 hostname php: auxpropfunc error no mechanism available May 18 15:44:48 hostname php: _sasl_plugin_load failed on sasl_auxprop_plug_init for plugin: sql Those lines are followed by lines of saslauthd and PAM which results in authentication success.(I do not get any of them in ApacheModule mode) Looks like that he is trying auxprop pwcheck before saslauthd. I have no other .conf file in /etc/sasl2. When I change the parameter of sasl_server_init to something other then I get the same error in CLI mode as in ApacheModule mode.

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  • Does PHP have job control like bash does?

    - by Andrew
    Hello, does PHP support something like ampersand in bash (forking)? Let's say I wanted to use cURL on 2 web pages concurrently, so script doesn't have to wait before first cURL command finnishes, how could one achieve that in PHP? Something like this in bash: curl www.google.com & curl www.yahoo.com & wait

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  • Problems with CGI wrapper for PHP

    - by user205878
    I'm having a bugger of a time with a CGI wrapper for PHP. I know very little about CGI and PHP as CGI. Here's what I know about the system: Solaris 10 on a 386 Suhosin PHP normally running as CGI, with cgiwrap (http://cgiwrap.sourceforge.net/). I am not able to find an example wrapper.cgi on the server to look at. Shared hosting (virtual host), so I don't have access to Apache config. But the admins are not helpful. Switching hosts is not an option. Options directive cannot be overridden in .htaccess (ExecCGI, for example). .htaccess: AddHandler php-handler .php Action php-handler "/bin/test.cgi" ~/public_html/bin/test.cgi: #!/usr/bin/sh # Without these 2 lines, I get an Internal Server Error echo "Content-type: text/html" echo "" exec "/path/to/php-cgi" 'foo.php'; /bin/foo.php: <?php echo "this is foo.php!"; Output of http://mysite.com/bin/test.cgi: X-Powered-By: PHP/5.2.11 Content-type: text/html echo "Content-type: text/html" echo "" exec "/path/to//php-cgi" 'foo.php'; Output of http:/ /mysite.com/anypage.php: X-Powered-By: PHP/5.2.11 Content-type: text/html echo "Content-type: text/html" echo "" exec "/path/to//php-cgi" 'foo.php'; The things I note are: PHP is being executed, as noted by the X-Powered-By ... header. The source of /bin/test.cgi is output in the results. No matter what I put as the second argument of exec, it isn't passed to the php binary. I've tried '-i' to get phpinfo, '-v' to get the version... When I execute test.cgi via the shell, I get the expected results (the argument is passed to php, and it is reflected in the output). Any ideas about how to get this to work? UPDATE It appears that the reason the source of the test.cgi was appearing was due to errors. Anytime fatal error occurred, either within the cgi itself or with the command being executed by exec, it would cause the source of the cgi to appear. Within test.cgi, I can get the proper output with exec "/path/to/php-cgi" -h (I get the same thing as I would from CLI).

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  • PHP WAMP install php_tidy

    - by kmunky
    i have installed on my computer WAMP with PHP 5.2.9-2. I want to install php_tidy and i have read some tuts over the internet and i found out that i have to uncomment this extension=php_tidy.dll in php.ini, the problem is that i can't find that line.

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  • PHP WAMP instal php_tidy

    - by kmunky
    i have installed on my computer WAMP with PHP 5.2.9-2. I want to install php_tidy and i have read some tuts over the internet and i found out that i have to uncomment this extension=php_tidy.dll in php.ini, the problem is that i can't find that line.

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  • PHP: Set max_file_uploads for one file rather than php.ini

    - by Jenkz
    Like many variables in PHP using ini_set() on a page doesn't actually work. I've recently upgraded my PHP version and found that my multiple image uploader is now capped. After 3 hours of frustration, I've found that my new PHP install has the new "max_file_uploads" parameter set to "20". So only the first 7 images get uploaded (each is in three sizes, 7*3=21). I can now change my php.ini value of "max_file_uploads" to 300, but I'd rather not do that side wide. Is there any way to set that value just for a single file (upload.php)? Could a .htaccess file be used for this?

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  • Using PHP with the default Mac Apache + PHP installation

    - by Juan Medín
    Hi, I'm starting to unravel the mysteries of PHP and I configured the pre-installed Snow Leopard PHP and activated the Apache server in the system preferences. So far so good: it works if you put a PHP file in your ~/Sites directory. Since I've my projects in a code/projects directory I created a symbolic link from the ~/Sites dir to the code/projects/one-project/php-dir and bang!, a 403 error: access forbidden. I've been changing the permissions of the dirs to 777, but no luck. Is anyone using the default Snow Leoapard configuration for PHP development and if so, how do you link to your codebase? Thanks in advance, Juan

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  • PHP/Javascript - get php variable within javascript

    - by McNabbToSkins
    I have run into an interesting problem. I am currently developing php page and need to access a php variable within the javascript onload. $(document).ready(function() { var temp = <?php $page_id ?> } is this valid? I know that this might seem weird and not be allowed but I am developing a page that has two popup windows. The windows are created using the same view template and there is no way to distinguish between each other. If I stored a hidden value on the page with information unique to the page like so <input type="hidden" value="<?php $page_id ?> id="page_id" /> if there are two views open at the same time there is no way for me to get a unique page id like so var temp = $("#page_id").val(); Because there are two views witht he same input id that is not unique. Long story short is it valid to reference a php variable in the javascript.

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  • Getting php tips and tutorials as daily emails to improve the knowledge in php programming

    - by Sourabh
    Hi Thanks for your time. This question is related to php programming but not a programming question.I have a young team of php (LAMP + javascript) programmers.I want them to learn better coding and keep themselves updated with the latest advancements in web domain. I was thinking if there was any web site which send daily emails about php questions / problems/ solutions to common problems/ tips which will practically help the people to spend 10-15 minutes daily and enjoy the learning.This will also kind of automate the habit of self learning on daily basis. There are lots of PHP forums and php tutorials website, I tried to google but I did not find any website which does what I am looking for. Please let me know if you know such website.If you have any other ideas to achieve the goal are also welcome. -Sourabh

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  • Error with global variable in php not extending to included php file

    - by phileaton
    I have an html file that calls has a php section in the header like so: $page = basename($_SERVER['PHP_SELF']); Now further down in the html file I have a included footer like so: <?php include("footer.php"); ?> In this script I am referencing the $page variable, but it doesn't find it. I tried echoing the variable and nothing happened. When I place the basename() code in the footer.php file though, it handled it fine. I'd like to be efficient with the coding, so how can I get the footer.php file to get that $page variable? Is there a better way to do this than including the $page variable twice?

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  • Editing PHP using PHP (admin center)

    - by Alec Smart
    Hello, Am developing an admin center where I can edit configuration files (written in PHP). I do NOT want to store these values in a mySQL table (for various reasons). So say my config.php has contents like: <?php $option1 = 1; $option2 = 2; $option4 = 5; $option7 = array('test','a','b',c'); ?> Now say in one of the admin pages I will only be changing a few values like option2 or option4 etc. Any ideas on what would be the best way to go about this. I know one option is to read the PHP file completely and write parts of it using REGEX. Any way to make this more efficent? I don't want the config.php file to break because of some error on the user's end. Any ideas on how to ensure that it works?

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  • php-fpm start error

    - by Sujay
    I am using php-fpm. I recently recompiled php for including imap functions. But on php-fpm start it gives the following error: Starting php_fpm Error in argument 1, char 1: no argument for option - Usage: php-cgi [-q] [-h] [-s] [-v] [-i] [-f ] php-cgi [args...] -a Run interactively -C Do not chdir to the script's directory -c | Look for php.ini file in this directory -n No php.ini file will be used -d foo[=bar] Define INI entry foo with value 'bar' -e Generate extended information for debugger/profiler -f Parse . Implies `-q' -h This help -i PHP information -l Syntax check only (lint) -m Show compiled in modules -q Quiet-mode. Suppress HTTP Header output. -s Display colour syntax highlighted source. -v Version number -w Display source with stripped comments and whitespace. -z Load Zend extension ................................... failed What could be the problem? Is it in php-fpm.conf or php.ini.

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  • How to directly send *.php.html files to browser without passing throught PHP? (Apache)

    - by Cédric Girard
    Hi, on my Apache/PHP server, file test.php.html is parsed by PHP, while test.html is not. PHPDOC create a lot of *.php.html files, with a XML header wich is a pain for PHP parser, but how to tell Apache not to pass *.php.html file to PHP and just send back the file to browser? My php.conf file <IfModule prefork.c> LoadModule php5_module modules/libphp5.so </IfModule> <IfModule worker.c> LoadModule php5_module modules/libphp5-zts.so </IfModule> AddHandler php5-script .php AddType text/html .php What can I do? Thanks, Bests regards Cédric

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  • Apache 2.0.55/PHP 5.3.5 Hangs

    - by Rushyo
    Recently inherited a Windows 2k3 server running XAMPP, including ancient copies of PHP, MySQL and Apache. I'm attempting to install a second, up-to-date PHP installation on the machine so I can reference that in future instead of XAMPP's old one. Apache starts up with this new PHP installation happily. Unfortunately, when Apache references the new PHP install, whenever I try a view a page (even a non-PHP page) it hangs. The server simply doesn't respond to any HTTP request - it doesn't crash either. It just sits there with the connection open. There are no errors/warnings/notices in either the PHP or Apache logs. I've pretty much ruled out PHP's extensions (by process of systematic elimination) and most of the INI settings. I've tried reinstalling PHP from scratch. The PHP installation is PHP 5.3.5 x86 thread-safe compiled w/ VC6. The Apache installation is Apache 2.0.55. Anyone encountered similar behaviour?

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  • phpMyAdmin causes php-fpm worker to restart (502 Bad Gateway)

    - by rndbit
    I am trying to set up a test site for myself. Everything works fine except phpMyAdmin. php installation loads my test site scripts, they work fine, however trying to load phpMyAdmin i get 502 Bad Gateway error. Judging from logs (that are not too helpful) it seems that php-fpm worker is crashing each time phpmyadmin is being accessed. No clue how or why.. Does anyone have any idea? nginx log: *3 recv() failed (104: Connection reset by peer) while reading response header from upstream, And php-fpm log: [07-Jun-2012 14:19:51] WARNING: [pool www] child 32179 exited on signal 11 (SIGSEGV) after 3.217902 seconds from start [07-Jun-2012 14:19:51] NOTICE: [pool www] child 32351 started My nginx conf: user nginx; worker_processes 1; error_log /var/log/nginx/error.log; pid /var/run/nginx.pid; events { worker_connections 1024; } http { include /etc/nginx/mime.types; default_type application/octet-stream; log_format main '$remote_addr - $remote_user [$time_local] "$request" ' '$status $body_bytes_sent "$http_referer" ' '"$http_user_agent" "$http_x_forwarded_for"'; access_log /var/log/nginx/access.log main; sendfile on; keepalive_timeout 65; fastcgi_buffers 8 16k; fastcgi_buffer_size 32k; include /etc/nginx/conf.d/*.conf; server { listen 443 ssl; listen 80; server_name testsite.net www.testsite.net; ssl on; ssl_certificate /var/www/html/admin/ssl/certificate.pem; ssl_certificate_key /var/www/html/admin/ssl/privatekey.pem; ssl_session_timeout 1m; ssl_protocols SSLv2 SSLv3 TLSv1; ssl_ciphers HIGH:!aNULL:!MD5:!kEDH; ssl_prefer_server_ciphers on; access_log off; location ~ \.php$ { root /var/www/html; fastcgi_pass 127.0.0.1:9000; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name; include /etc/nginx/fastcgi_params; } location / { root /var/www/html; index index.php; } } } php.ini is standard, with cgi.fix_pathinfo=0 php-fpm.conf: include=/etc/php-fpm.d/*.conf [global] pid = /var/run/php-fpm/php-fpm.pid error_log = /var/log/php-fpm/error.log log_level = notice php-fpm.d/www.conf: [www] listen = 127.0.0.1:9000 listen.allowed_clients = 127.0.0.1 user = nginx group = nginx pm = dynamic pm.max_children = 10 pm.start_servers = 1 pm.min_spare_servers = 1 pm.max_spare_servers = 10 slowlog = /var/log/php-fpm/www-slow.log php_flag[display_errors] = on php_admin_value[error_log] = /var/log/php-fpm/www-error.log php_admin_flag[log_errors] = on

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  • php-fpm start error

    - by Sujay
    I am using php-fpm. I recently recompiled php for including imap functions. But on php-fpm start it gives the following error: Starting php_fpm Error in argument 1, char 1: no argument for option - Usage: php-cgi [-q] [-h] [-s] [-v] [-i] [-f ] php-cgi [args...] -a Run interactively -C Do not chdir to the script's directory -c | Look for php.ini file in this directory -n No php.ini file will be used -d foo[=bar] Define INI entry foo with value 'bar' -e Generate extended information for debugger/profiler -f Parse . Implies `-q' -h This help -i PHP information -l Syntax check only (lint) -m Show compiled in modules -q Quiet-mode. Suppress HTTP Header output. -s Display colour syntax highlighted source. -v Version number -w Display source with stripped comments and whitespace. -z Load Zend extension ................................... failed What could be the problem? Is it in php-fpm.conf or php.ini.

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  • Where is php executable on Ubuntu?

    - by user601L
    I have installed apache and php. I know php works as I have tested a simple php file on apache server. I'm writing a simple webserver which should be able to process php files. So what I want to do is once I get a request for a php file, something like 'exec php test.php' and get the output and pass it to the client. As I'm not much into Ubuntu, I don't know where is the php executable (should be in \bin right?) to do it. But there is no php file inside \bin or \usr\bin. When I run 'which php' it shows nothing. How do I do this?

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  • APC on PHP 5.4 does not seem to be installed after installation

    - by Burning the Codeigniter
    I've recently upgraded to PHP 5.4 from 5.3.6, I did the command apt-get upgrade php5 with the custom PHP 5.4 repo which I added to the apt-get repositories, now that I upgraded, I restarted php-fastcgi and php5-fpm the APC does not seem to be installed with it after I did pecl install apc it seems to configure and install with the details below: Configuring for: PHP Api Version: 20090626 Zend Module Api No: 20090626 Zend Extension Api No: 220090626 But in my phpinfo() I get this: PHP API 20100412 PHP Extension 20100525 Zend Extension 220100525 Which I don't understand, how can I configure PECL to install with PHP 5.4 with my version, my installation with apc.so is stored to /usr/lib/php5/20090626/ however in /usr/lib/php5/ I have two PHP versions: 20090626 20100525 How can I remove either one and leave PHP 5.4 and manage it to install apc in the correct PHP version? I'm running Ubuntu 11.04 on my server. I need help on this please.

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  • How to get PHP command line to work with PDO?

    - by Sabya
    I want to work with PDO, through PHP command line. It works perfect through the PHP web API, but not through the command line. But when I execute the command: php test.php, it says unknown class PDO. I think it has something to do with the thread-safety difference. Because, when I execute the above command, the following warnings come: - F:\shema\htdocs>php test.php PHP Warning: PHP Startup: soap: Unable to initialize module Module compiled with module API=20060613, debug=0, thread-safety=0 PHP compiled with module API=20060613, debug=0, thread-safety=1 These options need to match in Unknown on line 0 PHP Warning: PHP Startup: sockets: Unable to initialize module Module compiled with module API=20060613, debug=0, thread-safety=0 PHP compiled with module API=20060613, debug=0, thread-safety=1 These options need to match in Unknown on line 0 PHP Warning: PHP Startup: mysql: Unable to initialize module Module compiled with module API=20060613, debug=0, thread-safety=0 PHP compiled with module API=20060613, debug=0, thread-safety=1 These options need to match in Unknown on line 0 PHP Warning: PHP Startup: pdo_mysql: Unable to initialize module Module compiled with module API=20060613, debug=0, thread-safety=0 PHP compiled with module API=20060613, debug=0, thread-safety=1 These options need to match in Unknown on line 0 PHP Warning: PHP Startup: pdo_pgsql: Unable to initialize module Module compiled with module API=20060613, debug=0, thread-safety=0 PHP compiled with module API=20060613, debug=0, thread-safety=1 These options need to match in Unknown on line 0 PHP Fatal error: Class 'PDO' not found in F:\shema\htdocs\test.php on line 2 PHP version: 5.2.9-2, downloaded from here. OS: Windows Vista If the problem is with the modules, where do I get the thread safe modules for those modules?

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  • .htaccess Redirect Loop, adding multiple .php extensions

    - by Ryan Smith
    I have sort of a small parent/teacher social network set up for my school. I use my .htaccess file to make the links to teacher profiles cleaner and to add a trailing slash to all urls. I get this problem when going to /teachers/teacher-name/ the link (sometimes) redirects to /teachers/teacher-name.php.php.php.php.php.php.php.php... Below is my .htaccess file. Sometimes if I clear my browser cache in Chrome it temporarily fixes it. I can't exactly wright .htaccess syntax, but I'm pretty familiar with it. Any suggestions are appreciated! RewriteEngine on RewriteBase / #remove php ext RewriteEngine on RewriteCond %{REQUEST_FILENAME} !-d RewriteCond %{REQUEST_FILENAME}\.php -f RewriteRule ^([^/]+)/$ $1.php RewriteRule ^([^/]+)/([^/]+)/$ $1/$2.php #force trailing slash/ RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^(.*)([^/])$ /$1$2/ [L,R=301] #other rewrites RewriteRule ^teachers/([^/\.]+)/$ /teachers/profile.php?u=$1 RewriteRule ^teachers/([^/\.]+)/posts/$ /teachers/posts.php?u=$1 RewriteRule ^teachers/([^/\.]+)/posts/([^/\.]+)/$ /teachers/post.php?u=$1&p=$2 RewriteRule ^gallery/([^/\.]+)/$ /gallery/album.php?n=$1 RewriteRule ^gallery/([^/\.]+)/slideshow/$ /gallery/slideshow.php?n=$1 RewriteRule ^gallery/([^/\.]+)/([^/\.]+)/([^/\.]+)/$ /gallery/photo.php?a=$1&p=$2&e=$3 EDIT:I have attached a screenshot of exactly what I'm talking about.

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  • Why is this PHP loop rendering every row twice?

    - by Christopher
    I'm working on a real frankensite here not of my own design. There's a rudimentary CMS and one of the pages shows customer records from a MySQL DB. For some reason, it has no probs picking up the data from the DB - there's no duplicate records - but it renders each row twice. <?php $limit = 500; $area = 'customers_list'; $prc = 'customer_list.php'; if($_GET['page']) { include('inc/functions.php'); $page = $_GET['page']; } else { $page = 1; } $limitvalue = $page * $limit - ($limit); $customers_check = get_customers(); $customers = get_customers($limitvalue, $limit); $totalrows = count($customers_check); ?> <!-- pid: customer_list --> <table border="0" width="100%" cellpadding="0" cellspacing="0" style="float: left; margin-bottom: 20px;"> <tr> <td class="col_title" width="200">Name</td> <td></td> <td class="col_title" width="200">Town/City</td> <td></td> <td class="col_title">Telephone</td> <td></td> </tr> <?php for ($i = 0; $i < count($customers); $i++) { ?> <tr> <td colspan="2" class="cus_col_1"><a href="customer_details.php?id=<?php echo $customers[$i]['customer_id']; ?>"><?php echo $customers[$i]['surname'].', '.$customers[$i]['first_name']; ?></a></td> <td colspan="2" class="cus_col_2"><?php echo $customers[$i]['town']; ?></td> <td class="cus_col_1"><?php echo $customers[$i]['telephone']; ?></td> <td class="cus_col_2"> <a href="javascript: single_execute('prc/customers.prc.php?delete=yes&id=<?php echo $customers[$i]['customer_id']; ?>')" onClick="return confirmdel();" class="btn_maroon_small" style="margin: 0px; float: right; margin-right: 10px;"><div class="btn_maroon_small_left"> <div class="btn_maroon_small_right">Delete Account</div> </div></a> <a href="customer_edit.php?id=<?php echo $customers[$i]['customer_id']; ?>" class="btn_black" style="margin: 0px; float: right; margin-right: 10px;"><div class="btn_black_left"> <div class="btn_black_right">Edit Account</div> </div></a> <a href="mailto: <?php echo $customers[$i]['email']; ?>" class="btn_black" style="margin: 0px; float: right; margin-right: 10px;"><div class="btn_black_left"> <div class="btn_black_right">Email Customer</div> </div></a> </td> </tr> <tr><td class="col_divider" colspan="6"></td></tr> <?php }; ?> </table> <!--///////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////--> <!--// PAGINATION--> <!--///////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////--> <div class="pagination_holder"> <?php if($page != 1) { $pageprev = $page-1; ?> <a href="javascript: change('<?php echo $area; ?>', '<?php echo $prc; ?>?page=<?php echo $pageprev; ?>');" class="pagination_left">Previous</a> <?php } else { ?> <div class="pagination_left, page_grey">Previous</div> <?php } ?> <div class="pagination_middle"> <?php $numofpages = $totalrows / $limit; for($i = 1; $i <= $numofpages; $i++) { if($i == $page) { ?> <div class="page_number_selected"><?php echo $i; ?></div> <?php } else { ?> <a href="javascript: change('<?php echo $area; ?>', '<?php echo $prc; ?>?page=<?php echo $i; ?>');" class="page_number"><?php echo $i; ?></a> <?php } } if(($totalrows % $limit) != 0) { if($i == $page) { ?> <div class="page_number_selected"><?php echo $i; ?></div> <?php } else { ?> <a href="javascript: change('<?php echo $area; ?>', '<?php echo $prc; ?>?page=<?php echo $i; ?>');" class="page_number"><?php echo $i; ?></a> <?php } } ?> </div> <?php if(($totalrows - ($limit * $page)) > 0) { $pagenext = $page+1; ?> <a href="javascript: change('<?php echo $area; ?>', '<?php echo $prc; ?>?page=<?php echo $pagenext; ?>');" class="pagination_right">Next</a> <?php } else { ?> <div class="pagination_right, page_grey">Next</div> <?php } ?> </div> <!--///////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////--> <!--// END PAGINATION--> <!--///////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////--> I'm not the world's best PHP expert but I think I can see an error in a for loop when there is one... But everything looks ok to me. You'll notice that the customer name is clickable; clicking takes you to another page where you can view their full info as held in the DB - and for both rows, the customer ID is identical, and manually checking the DB shows there's no duplicate entries. The code is definitely rendering each row twice, but for what reason I have no idea. All pointers / advice appreciated.

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  • can't load big files to server with php [closed]

    - by yozhik
    Hi all! I can't load big files to server. The problem is in that file $_FILES["filename"]["tmp_name"] is empty if file a little more bigger then 2mb. I tried to change variables in php.ini upload_max_filesize = 700M post_max_size = 16M but not working to. Also tried to add this variables to my .httaccess file - but 500 error appears. Error code while uploading=1. UPLOAD_ERR_INI_SIZE Value: 1; The uploaded file exceeds the upload_max_filesize directive in php.ini. Here is my uppload.php page, please anwer what I doing wrong? Thanx! <?php if(strlen($_FILES["filename"]["name"])) { $folder = "uploads/"; echo $folder; $error = ""; if($_FILES["filename"]["size"] > 1024*700*1024) { $error .= "<b><p class=ErrorMessage>?????? ????? ????????? 5Mb</p></b><br>"; header("Location: upload.php?error=".$error, true, 303 ); } if(!file_exists($folder.="hh/")) { if(!mkdir($folder, 0700)) $error .= "<b><p class=ErrorMessage>Folder not created</p></b><br>"; } //echo "<br>".$_FILES["filename"]["tmp_name"]."<br>"; echo $folder.$_FILES["filename"]["name"]."<br>"; echo $_FILES["filename"]["error"]."<br>"; if(move_uploaded_file($_FILES["filename"]["tmp_name"], $folder.$_FILES["filename"]["name"])) { echo("???? ??????? ???????? <br>"); echo("?????????????? ?????: <br>"); echo("??? ?????: "); echo($_FILES["filename"]["name"]); echo("<br>?????? ?????: "); echo($_FILES["filename"]["size"]); echo("<br>??????? ??? ????????: "); echo($folder.=$_FILES["filename"]["name"]); echo("<br>??? ?????: "); echo($_FILES["filename"]["type"]); } else { $error .= "<b><p class=ErrorMessage>?????? ???????? ?????</p></b><br>"; } } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>???????? ??? ????????</title> </head> <body> <?php if(isset($_REQUEST["error"])) { echo $_REQUEST["error"]; } ?> <h2><p><b> ????? ??? ???????? ?????? </b></p></h2> <form action="upload.php" method="post" enctype="multipart/form-data"> <input type="file" name="filename" READONLY><br> <input name="Upload" type="submit" value="Upload"><br> </form> </body> </html>

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