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Regex for date.

- by Harikrishna

What should be the regex for matching date of any format like 26FEB2009 30 Jul 2009 27 Mar 2008 29/05/2008 27 Aug 2009 What should be the regular expression for that ? I have regex that matches with 26-Feb-2009 and 26 FEB 2009 with but not with 26FEB2009. So if any one know then please update it. (?:^|[^\d\w:])(?'day'\d{1,2})(?:-?st\s+|-?th\s+|-?rd\s+|-?nd\s+|-|\s+)(?'month'Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec)[uarychilestmbro]*(?:\s*,?\s*|-)(?:'?(?'year'\d{2})|(?'year'\d{4}))(?=$|[^\d\w]) EDIT The date 26FEB2009 is substring of other string like FUTIDX 26FEB2009 NIFTY 0 and parsed from html page, so I can not set the whitespace or delimiter.

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Python Regex To VB.net

- by user316758

Hi everyone, I made a program in Python and now I whant to transfert it to vb.net. But I have some difficulties with the vb.net regular expression.... Someone can help me please? There are my Python regex: id = re.search('(?<=watch\?v\=)[\w|-]+|(?<=/v/)[\w|-]+', src) id = id.group(0) t = re.search('(?<=\&t\=)[\w|-]+', src) t = t.group() It's supposed to fin the value of ?v=Value&SomeOtherContent and &t=Value&SomeOtherContent Thank you

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What's wrong with my regex

- by Tom Brown

Yes I know its usually a bad idea to parse HTML using RegEx, but that aside can someone explain the fault here: string outputString = Regex.Replace(inputString, @"<?(?i:script|embed|object|frameset|frame|iframe|metalink|style|html|img|layer|ilayer|meta|applet)(.|\n)*?>", ""); if (outputString != inputString) { Console.WriteLine("unwanted tags detected"); } It certainly detects the intended tags like: <script> and <html>, but it also rejects strings I want to allow such as <B>Description</B> and <A href="http://www.mylink.com/index.html">A Link containing 'HTML'</A>

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Regex matching very slow

- by Ali Lown

I am trying to parse a PDF to extract the text from it (please don't suggest any libraries to do this, as this is part of learning the format). I have already handled deflating it to put it in the alphanumeric format. I now need to extract the text from the text blocks. So, my current pattern is "BT.*?((.*?)).*?ET" (with DOTMATCHALL set) to match something like: BT /F13 12 Tf 288 720 Td (ABC) Tj ET The only bit I want is the text ABC in the brackets. The above pattern works, but is really slow, I assume it is because the regex library is failing to match the pattern that matches the text between BT and the (ABC) many times. The regex is pre-compiled in an attempt to speed it up, but it seems negligible. How may I speed this up?

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RegEx for MetaMap in Java

- by Christian

MetaMap files have following lines: mappings([map(-1000,[ev(-1000,'C0018017','Objective','Goals',[objective],[inpr],[[[1,1],[1,1],0]],yes,no)])]). The format is explained as mappings( [map(negated overall score for this mapping, [ev(negated candidate score,'UMLS concept ID','UMLS concept','preferred name for concept - may or may not be different', [matched word or words lowercased that this candidate matches in the phrase - comma separated list], [semantic type(s) - comma separated list], [match map list - see below],candidate involved with head of phrase - yes or no, is this an overmatch - yes or no ) ] ) ] ). I want to run a RegEx query in java that gives me the Strings 'UMLS concept ID', semantic type and match map list. Is RegEx the right tool or what is the most efficent way to accomplish this in Java?

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Regex matching into multiple groups per line?

- by dmose

I'm trying to come up with a regex to be able to parse the following type of strings into groups. <link rel="alternate" type="application/rss+xml" title="[!PageTitle!]" href="[!SiteRoot!]/feed.xml" /> My regular expression is: \[\!(.+)\!\] The problem with this expression is that it seems to pull it all into 1 group: Found 1 match: "[!PageTitle!]" href="[!SiteRoot!]" has 1 group: 1. "PageTitle!]" href="[!SiteRoot" I want dont want the regex to continue...am I missing a boundary? Ideally I want it to find 2 groups, [!PageTitle!] and [!SiteRoot!]

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php regex for strong password validation

- by Jason

Hello, I've seen around the web the following regex (?=^.{8,}$)((?=.*\d)|(?=.*\W+))(?![.\n])(?=.*[A-Z])(?=.*[a-z]).*$ which validates only if the string: * contain at least (1) upper case letter * contain at least (1) lower case letter * contain at least (1) number or special character * contain at least (8) characters in length I'd like to know how to convert this regex so that it checks the string to * contain at least (2) upper case letter * contain at least (2) lower case letter * contain at least (2) digits * contain at least (2) special character * contain at least (8) characters in length well if it contains at least 2 upper,lower,digits and special chars then I wouldn't need the 8 characters length. special characters include: `~!@#$%^&*()_-+=[]\|{};:'".,/<? thanks in advance.

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Java RegEx Pattern not matching (works in .NET)

- by CDSO1

Below is an example that is producing an exception in Java (and not matching the input). Perhaps I misunderstood the JavaDoc, but it looks like it should work. Using the same pattern and input in C# will produce a match. import java.util.regex.Matcher; import java.util.regex.Pattern; public class Main { public static void main(String[] args) { String pattern = "aspx\\?uid=([^']*)"; Pattern p = Pattern.compile(pattern); Matcher m = p.matcher("id='page.aspx?uid=123'"); System.out.println(m.groupCount() > 0 ? m.group(1) : "No Matches"); } }

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iphone - Regex for date in user entered textfield

- by vikinara

Hi all, Am a newbie to iphone programming. i have a input box and the user can write his DOB(mm/dd/yyyy) into the box. Before i save the data i like to test for valid input. I am using Regexlite.h and Regexlite.m.i have the regular expression too. i want to compare the regex to the user entered value in text box.But am not knowing how to do it.Please help. Any idea how to test for a valid date? (in .NET i use a simple regex but for the iPhone sdk i am a bit helpless) - but somebody must have been done this before... Thanks Viki

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SBUG --> UK Connected Systems User Group

- by Michael Stephenson

Following a recent user group meeting we have decided that the UK SOA/BPM User Group will be renamed to the UK Connected Systems User Group. The reasons for this are as follows: 1. Other user groups who cover the same topics as us are all called something similar 2. We feel the name change will help to increase user group membership The focus and topics of the user group will remain the same.

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Match d-M-Y with javascript regex how?

- by bakerjr

Hi, my date formatting in PHP is d-M-Y and I'm trying to match the dates with a javascript regex: s.match(new RegExp(/^(\d{1,2})(\-)(\w{3})(\-)(\d{4})$/)) To be used with the jQuery plugin, tablesorter. The problem is it's not working and I'm wondering why not. I tried removing the dashes in my date() formatting (d M Y) and tried the ff and it worked: s.match(new RegExp(/^\d{1,2}[ ]\w{3}[ ]\d{4}$/)); My question is what is the correct regex if I'm using dashes on PHP's date() i.e. d-M-Y? Thanks!

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regex to match postgresql bytea

- by filiprem

In PostgreSQL, there is a BLOB datatype called bytea. It's just an array of bytes. bytea literals are output in the following way: '\\037\\213\\010\\010\\005`Us\\000\\0001.fp3\'\\223\\222%' See PostgreSQL docs for full definition of the format. I'm trying to construct a Perl regular expression which will match any such string. It should also match standard ANSI SQL string literals, like 'Joe', 'Joe''s Mom', 'Fish Called ''Wendy''' It should also match backslash-escaped variant: 'Joe\'s Mom', . First aproach (shown below) works only for some bytea representations. s{ ' # Opening apostrophe (?: # Start group [^\\\'] # Anything but a backslash or an apostrophe | # or \\ . # Backslash and anything | # or \'\' # Double apostrophe )* # End of group ' # Closing apostrophe }{LITERAL_REPLACED}xgo; For other (longer ones, with many escaped apostrophes, Perl gives such warning: Complex regular subexpression recursion limit (32766) exceeded at ./sqa.pl line 33, < line 1. So I am looking for a better (but still regex-based) solution, it probably requires some regex alchemy (avoiding backreferences and all).

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Regex to strip phpdoc multiline comment

- by Reveller

I have this: /** * @file * API for loading and interacting with modules. * More explaination here. * * @author Reveller <me@localhost> * @version 19:05 28-12-2008 */ I'm looking for a regex to strip all but the @token data, so the result would be: @file API for loading and interacting with modules. More explaination here. @author Reveller <me@localhost> @version 19:05 28-12-2008 I now have this: $text = preg_replace('/\r?\n *\* */', ' ', $text); It does the job partially: it only removes the * in front of each line. Who could help me so it also strips /** and the final slash /? Any help would be greatly appreciated! P.S: If, for instance, the commentlbock would contain something like /** * @foo Here's some slashes for ya: / and \ */ Then obviously the slashes after @foo may not be stripped. The reult would have to be: @foo Here's some slashes for ya: / and \ I hope there's a regex guru out there :-)

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RegEx, matching if not containing...

- by Tommy Jakobsen

I've been trying to figure out how to write this regular expression. It is to be used for ISAPI_Rewrite, a module for IIS 6, for doing URL rewriting. I want the url /hg/<parameter> to be mathed, so it can be rewrited to /hg/hgwebdir.cgi/<parameter>. I've matched it using ^/hg/(.*). My problem is, if the URL /hg/hgwebdir.cgi/<parameter> is used, the regex should NOT match. Using the above regex with this URL, will rewrite to /hg/hgwebdig.cgi/hgwebdig.cgi/<parameter> which is not correct. Can you help me create the matching pattern?

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Regex-expression with danish characters

- by timkl

I'm currently trying to wrap my head around regex, I have a validation snippet that tests an input box against a regex-expression: $.validator.addMethod("customerName", function(value, element){ return (/^[a-zA-Z]*$/).test(value); }, "Some text"); That works well, but when I try to add a space and some special danish characters, it doesn't filter the danish characters, only the space. $.validator.addMethod("customerName", function(value, element){ return (/^[a-zA-Z æøåÆØÅ]*$/).test(value); }, "Some text"); Any ideas to what could be wrong?

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Checking if language is set in url with regex

- by Saif Bechan

I have am working on a multi language file. My urls look something like this: http://www.mydomain.com/en/about/info http://www.mydomain.com/nl/about/info Now I use a small regex script that redirect the user when they use a link without language. The script looks like this: preg_match('~^/[a-z]{2}/~', $_SERVER['REQUEST_URI'] This finds out is there is a language set en|nl|de etc. This works fine on all links except for these: http://www.mydomain.com/en http://www.mydomain.com/nl There is no trailing slash so the regex can not find the given values. Anyone know a fix for this?

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Regex to validate SMTP Responses?

- by Alix Axel

I'm writing a regular expression that can interactively validate SMTP responses codes, once the SMTP dialog is completed it should pass the following regex (some parentheses added for better readability): ^(220)(250){3,}(354)(250)(221)$ Or with(out) authentication: ^(220)(250)((334){2}(235))?(250){2,}(354)(250)(221)$ I'm trying to do rewrite the above regexes so that I can interactively check if the dialog is going as expected, otherwise politely send a QUIT command and close the connection saving bandwidth and time, but I'm having a hard time writing an optimal regex. So far I've managed to come up with: ^(220(250(334(235(250(354(250(221)?)?)?){0,})?){0,2})?)?$ Which, besides only matching authenticated connections, has some bugs... For instance, it matches: 220250334235250354250221 220250334334235250354250221 I've also tried the following modification: ^(220(250)?)?((334(235)?){2})?(250(354(250(221)?)?)?){0,}$ This one accepts non-authenticated responses but it fails to match 220250334 and wrongly matches 220250334334235250354250221 (at least 2 250 are needed before the 354 response code). Can someone help me out with this? Thanks in advance.

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SCHA API for resource group failover / switchover history

- by krishna.k.murthy

The Oracle Solaris Cluster framework keeps an internal log of cluster events, including switchover and failover of resource groups. These logs can be useful to Oracle support engineers for diagnosing cluster behavior. However, till now, there was no external interface to access the event history. Oracle Solaris Cluster 4.2 provides a new API option for viewing the recent history of resource group switchovers in a program-parsable format. Oracle Solaris Cluster 4.2 provides a new option tag argument RG_FAILOVER_LOG for the existing API command scha_cluster_get which can be used to list recent failover / switchover events for resource groups. The command usage is as shown below: # scha_cluster_get -O RG_FAILOVER_LOG number_of_days number_of_days : the number of days to be considered for scanning the historical logs. The command returns a list of events in the following format. Each field is separated by a semi-colon [;]: resource_group_name;source_nodes;target_nodes;time_stamp source_nodes: node_names from which resource group is failed over or was switched manually. target_nodes: node_names to which the resource group failed over or was switched manually. There is a corresponding enhancement in the C API function scha_cluster_get() which uses the SCHA_RG_FAILOVER_LOG query tag. In the example below geo-infrastructure (failover resource group), geo-clusterstate (scalable resource group), oracle-rg (failover resource group), asm-dg-rg (scalable resource group) and asm-inst-rg (scalable resource group) are part of Geographic Edition setup. # /usr/cluster/bin/scha_cluster_get -O RG_FAILOVER_LOG 3 geo-infrastructure;schost1c;;Mon Jul 21 15:51:51 2014 geo-clusterstate;schost2c,schost1c;schost2c;Mon Jul 21 15:52:26 2014 oracle-rg;schost1c;;Mon Jul 21 15:54:31 2014 asm-dg-rg;schost2c,schost1c;schost2c;Mon Jul 21 15:54:58 2014 asm-inst-rg;schost2c,schost1c;schost2c;Mon Jul 21 15:56:11 2014 oracle-rg;;schost2c;Mon Jul 21 15:58:51 2014 geo-infrastructure;;schost2c;Mon Jul 21 15:59:19 2014 geo-clusterstate;schost2c;schost2c,schost1c;Mon Jul 21 16:01:51 2014 asm-inst-rg;schost2c;schost2c,schost1c;Mon Jul 21 16:01:10 2014 asm-dg-rg;schost2c;schost2c,schost1c;Mon Jul 21 16:02:10 2014 oracle-rg;schost2c;;Tue Jul 22 16:58:02 2014 oracle-rg;;schost1c;Tue Jul 22 16:59:05 2014 oracle-rg;schost1c;schost1c;Tue Jul 22 17:05:33 2014 Note that in the output some of the entries might have an empty string in the source_nodes. Such entries correspond to events in which the resource group is switched online manually or during a cluster boot-up. Similarly, an empty destination_nodes list indicates an event in which the resource group went offline. - Arpit Gupta, Harish Mallya

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How to perform a literal match with regex using wildcard

- by kashif4u

I am trying to perform literal match with regular expression using wildcard. string utterance = "Show me customer id 19"; string pattern 1 = "*tom*"; string patter 2 = "*customer id [0-9]*"; Desired results: if (Regex.IsMatch(utterance, pattern 1 )) { MATCH NOT FOUND } if (Regex.IsMatch(utterance, pattern 2 )) { MATCH FOUND } I have tried looking for literal match solution/syntax in wildcard but having difficulty. Could you also enlighten me with with an example on possible Pattern Matching Strength algorithm i.e. if code match 90 select? Note: I have table with 100000 records to perform literal matches from user utterances. Thanks in advance.

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Regex for url formatting (www.domain.tld to anchors)

- by Kristaps

Hi. I'm currently developing a little browser-based Twitter widget. Currently, I'm stuck with getting the URLs to work. I'm kinda newbie, when it comes to regex (I know, how to get parts of a string, but this one – tough one). So, I need a regex that would search/replace www.domain.tld -> <a href="http://www.domain.tld">http://www.domain.tld</a> With/without http://, preferably. Any advice is welcome. Thanks.

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Regex take too long to match the result

- by Joe Ijam

Hi all I have this regex pattern <(\d+)>(\d+\.\d+|\d{4}\-\d+\-\d+\s+\d{2}:\d{2}:\d{2})(?:\..*?)*\s+(ALER|NOTI) and this is my input (will not matched at all) <150>2010-12-29 18:11:30.883 -0700 192.168.2.145 80 192.168.2.87 2795 "-" "-" GET HTTP 192.168.2.145 HTTP/1.1 200 36200 0 1038 544 192.168.2.221 80 540 SERVER DEFAULT PASSIVE VALID /joomla/ "-" http://192.168.2.145/joomla/index.php?option=com_content&view=a be4d44e8f3986183a87991398c1c212e=1; be4d44e8f3986183a87991398c1c212e=1 This will return not matched result but it takes too long to output the result. Since i have a thousand of logs/inputs in a second, it should finish very fast for every single log/input. Sometime it reaches CPU 100%. Can anyone help me to solve this regex problem? Thanks

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Regex to match month name followed by year

- by Jeremy

Is it possible to use a regex to match "February 2009", for example?

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Regex find the first word

- by Pez Cuckow

I'm trying to use regex to add a span to the first word of content for a page, however the content contains HTML so I am trying to ensure just a word gets chosen. The content changes for every page. Current script is: preg_match('/(<(.*?)>)*/i',$page_content,$matches); $stripped = substr($page_content,strlen($matches[0])); preg_match('/\b[a-z]* \b/i',$stripped,$strippedmatch); echo substr($page_content, 0, strlen($matches[0])).'<span class="h1">'.$strippedmatch[0].'</span>'.substr($stripped, strlen($strippedmatch[0])); However if the $page_content is <p><span class="title">This is </span> my title!</p> Then my regex thinks the first word is "span" and adds the tags around that. Is there any way to fix this? (or a better way to do it).

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PHP - preg_match_all - iCalendar - REGEX

- by aSeptik

Hi All guys! ;-) i need help with creating a regex for putting all values into an array! assuming we have a huge file full of theese: Classic iCalendar style: so we know that each segment start with BEGIN:VEVENT and end with END:VEVENT ... END:VEVENT BEGIN:VEVENT UID:e3cafdf3-c5c7-427e-b8c3-653015e9321a SUMMARY:Some Text Here DESCRIPTION:Some Text Here\n555-555-555 ORGANIZER;CN=Some/Text/Here DTSTART;TZID="Some/Text/Here":20100802T190000 DTEND;TZID="Some/Text/Here":20100802T193000 STATUS:CONFIRMED CLASS:PUBLIC X-MICROSOFT-CDO-INTENDEDSTATUS:BUSY TRANSP:OPAQUE X-MICROSOFT-DISALLOW-COUNTER:TRUE DTSTAMP:20100423T021222Z SEQUENCE:1 END:VEVENT BEGIN:VEVENT ... by using preg_match_all that i think is the best choice for doing this, what's the regex that can hold all theese values into array!? PS: between segments there are no line break this is just for example! thank's to All for the time! Regards Luca Filosfi

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php - regex- preg_replace - space after line-break!

- by aSeptik

Hi all guys! still on regex! i want learn it but i'm still crashing the head into my keybord! ;-) ok very trivial for you, i'm sure! Assuming i have this sting, the \s is where the space actualy is... \n where linebreak is.. DESCRIPTION: The quick brown fox jum`\s\n` `\s`ps over the lazy dog now, what i need to do is remove All the space after the A-Z: that i have achieved by this regex: /\s+(?![A-Z:])/m that produce this result DESCRIPTION: The quick brown fox jum ps over the lazy dog as you can see it leave the space between jum and ps how to have a result like this? DESCRIPTION: The quick brown fox jumps over the lazy dog thank's for the time!

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