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  • How would you structure your entity model for storing arbitrary key/value data with different data t

    - by Nathan Ridley
    I keep coming across scenarios where it will be useful to store a set of arbitrary data in a table using a per-row key/value model, rather than a rigid column/field model. The problem is, I want to store the values with their correct data type rather than converting everything to a string. This means I have to choose either a single table with multiple nullable columns, one for each data type, or a set of value tables, one for each data type. I'm also unsure as to whether I should use full third normal form and separate the keys into a separate table, referencing them via a foreign key from the value table(s), or if it would be better to keep things simple and store the string keys in the value table(s) and accept the duplication of strings. Old/bad: This solution makes adding additional values a pain in a fluid environment because the table needs to be modified regularly. MyTable ============================ ID Key1 Key2 Key3 int int string date ---------------------------- 1 Value1 Value2 Value3 2 Value4 Value5 Value6 Single Table Solution This solution allows simplicity via a single table. The querying code still needs to check for nulls to determine which data type the field is storing. A check constraint is probably also required to ensure only one of the value fields contains non-nulll data. DataValues ============================================================= ID RecordID Key IntValue StringValue DateValue int int string int string date ------------------------------------------------------------- 1 1 Key1 Value1 NULL NULL 2 1 Key2 NULL Value2 NULL 3 1 Key3 NULL NULL Value3 4 2 Key1 Value4 NULL NULL 5 2 Key2 NULL Value5 NULL 6 2 Key3 NULL NULL Value6 Multiple-Table Solution This solution allows for more concise purposing of each table, though the code needs to know the data type in advance as it needs to query a different table for each data type. Indexing is probably simpler and more efficient because there are less columns that need indexing. IntegerValues =============================== ID RecordID Key Value int int string int ------------------------------- 1 1 Key1 Value1 2 2 Key1 Value4 StringValues =============================== ID RecordID Key Value int int string string ------------------------------- 1 1 Key2 Value2 2 2 Key2 Value5 DateValues =============================== ID RecordID Key Value int int string date ------------------------------- 1 1 Key3 Value3 2 2 Key3 Value6 How do you approach this problem? Which solution is better? Also, should the key column be separated into a separate table and referenced via a foreign key or be should it be kept in the value table and bulk updated if for some reason the key name changes?

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  • nonatomic property in model class when using NSOperationQueue (iPhone)?

    - by Andrew B.
    I have a custom model class with an NSMutableData ivar that will be accessed by custom NSOperation subclasses (using an NSOperationQueue). I think I can guarantee thread-safe access to the ivar from multiple NSOperations by using dependencies, and I can guarantee that I don't access the ivar from other code (say my main app thread) by waiting until the Q has finished all operations. Should I use a nonatomic property specification, or leave it atomic? Is there a significant impact on performance?

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  • How to Export a Contact to and Import a Contact from a vCard (.vcf) File in Outlook 2013

    - by Lori Kaufman
    vCard is the abbreviation for Virtual Business Card and is the standard format (.vcf files) for electronic business cards. vCards allow you to create and share contact information over the internet, such as in email messages and instant messaging. You can also use vCards to move contact information from one email or personal information management program to another, as long as both programs support the .vcf file format. vCards can contain name and address information, as well as phone numbers, email addresses, URLs, images, and audio clips. We will show you how to export a contact to and import a contact from a vCard, or .vcf file, in Outlook. First access the People section by clicking People at the bottom of the Outlook window. To view your contact in business card format, click Business Card in the Current View section of the Home tab. Select a contact by clicking on the name bar at the top of the business card. To export the selected contact as a vCard, click the File tab. On the Account Information screen, click Save As in the list of options on the left. The Save As dialog box displays. By default, the name of the contact is used to name the .vcf file in the File name edit box. Change the name, if desired, select a location for the file, and click Save. The contact is saved as a .vcf file. To import a vCard, or .vcf file, into Outlook, simply double-click on the .vcf file. By default, .vcf files are automatically associated with Outlook, so the file is opened in Outlook as a Contact. Make any changes or additions to the contact in the contact editing window. To save the contact, click Save & Close in the Actions section of the Contact tab. NOTE: Notice that because this contact is new, the full contact editing window displays rather than the Contact Card that displays when double-clicking on a contact. You can open the full contact editing window instead of the Contact Card when editing a contact or searching for a contact. The contact is added to the Contacts folder. You can add your contact information to a signature in business card format, and it will display as shown above in emails. We have covered how to create signatures and will be discussing more about signatures and business cards in Outlook.     

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  • Yii file upload issue

    - by user1289853
    Couple of months ago,I developed a simple app using YII,one of the feature was to upload file. The feature was working well in my dev machine,couple of days ago client found the file upload feature is not working in his server since deployment. And after that I test my dev machine that was not working too. My controller looks: public function actionEntry() { if (!Yii::app()->user->isGuest) { $model = new TrackForm; if (isset($_POST['TrackForm'])) { $entry = new Track; try { $entry->product_image = $_POST['TrackForm']['product_image']; $entry->product_image = CUploadedFile::getInstance($model, 'product_image'); if ($entry->save()) { if ($entry->product_image) { $entry->product_image->saveAs($entry->product_image->name, '/trackshirt/uploads'); } } $this->render('success', array('model' => $model)); // redirect to success page } } catch (Exception $e) { echo 'Caught exception: ', $e->getMessage(), "\n"; } } else { $this->render('entry', array('model' => $model)); } } } Model is like below: <?php class Track extends CActiveRecord { public static function model($className=__CLASS__) { return parent::model($className); } public function tableName() { return 'product_details'; } } My view looks: <?php $form = $this->beginWidget('CActiveForm', array( 'id' => 'hide-form', 'enableClientValidation' => true, 'clientOptions' => array( 'validateOnSubmit' => true, ), 'htmlOptions' => array('enctype' => 'multipart/form-data'), )); ?> <p class="auto-style2"><strong>Administration - Add New Product</strong></p> <table align="center" style="width: 650px"><td class="auto-style3" style="width: 250px">Product Image</td> <td> <?php echo $form->activeFileField($model, 'product_image'); ?> </td> </tr> </table> <p class="auto-style1"> <div style="margin-leftL:-100px;"> <?php echo CHtml::submitButton('Submit New Product Form'); ?> </div> <?php $this->endWidget(); ?> Any idea where is the problem?I tried to debug it but every time it returns Null. Thanks.

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  • how to generate JMX MXBean compatible java class model from JAXB?

    - by yucubby
    From the JMX MXBean specification, a java class type J must satisfy Either if J has at least one public constructor with a ConstructorProperties annotation, Or if J has a public no-arg constructor, and for every getter in J with type T and name N there is a corresponding setter with the same name and type So how can I use JAXB to generate JAVA class model which satisfy the MXBean constrain? Thanks YU

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  • When would I want to model a class with a private ctor?

    - by dotnetdev
    Hi, I've seen plenty of classes in .NET which have private constructor (Stream is one of them I think). When would I want to model a class like this? I keep thinking that if my class has no internal state/fields, then I can make it have a private constructor. Am I on the right track with this idea? I can understand the use of a factory (I've run into the tipping point a few times), but not with a private constructor class. Thanks

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  • Rails: ruby script/generate model, where are the docs?

    - by yar
    I am running ruby script/generate scaffold or ruby script/generate model and I know the basic syntax, like ruby script/generate scaffold Dude name:string face:boolean but I do not know things like: should names of variables have underscores or be camelCased? what kind of variable types are acceptable? Where can I find such information? THANKS! P.S. The answers to my two questions would help for now, too :)

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  • Can UML be used to model a Functional program?

    - by iestyn
    More specifically, how do you model a functional program, or one developed using the Functional Style (without classes) using a diagram, and not textual representation, is it at all possible and could someone please direct me towards the nearest application that would do this (open source, of free as in beer, if you please)

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  • NHibernate Partial Update

    - by bleevo
    Is there a way in NHibernate to start with an unproxied model var m = new Model() { ID = 1 }; m.Name = "test"; //Model also has .LastName and .Age Now save this model only updating Name without first selecting the model from the session?

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  • Is there any way to get the iPhone Model number ?

    - by makboney
    I just figure out the device on which i'm working by the code given bellow: struct utsname systemInfo; uname(&systemInfo); NSLog(@"%@", [NSString stringWithCString:systemInfo.version encoding:NSUTF8StringEncoding]); But is there any way to find the model of my iPhone??? Thanks in advance ....

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  • Information not getting into the controller from the view. (authologic model)

    - by Gotjosh
    Right now I'm building a project management app in rails, here is some background info: Right now i have 2 models, one is User and the other one is Client. Clients and Users have a one-to-one relationship (client - has_one and user - belongs_to which means that the foreign key it's in the users table) So what I'm trying to do it's once you add a client you can actually add credentials (add an user) to that client, in order to do so all the clients are being displayed with a link next to that client's name meaning that you can actually create credentials for that client. So in order to do that I'm using a helper the link to helper like this. <%= link_to "Credentials", {:controller => 'user', :action => 'new', :client_id => client.id} %> Meaning that he url will be constructed like this: http://localhost:3000/clients/2/user/new By creating the user for the client with he ID of 2. And then capturing the info into the controller like this: @user = User.new(:client_id => params[:client_id]) The weird thing is that EVERY other information BUT the client id it's getting passed and the client ID should be passed with the params[:client_id]. Any ideas? Perhaps it may have something to do with the fact that model User has "acts_as_authentic" because I'm using authologic for it? Model: class User < ActiveRecord::Base acts_as_authentic belongs_to :client end Controller: def create @user = User.new(:client_id => params[:client_id]) if @user.save flash[:notice] = "Credentials created" else flash[:error] = "Credentials failed" end end View: <% form_for @user do |f| % <p> <%= f.label :login, "Username" %> <%= f.text_field :login %> </p> <p> <%= f.label :password, "Password" %> <%= f.password_field :password %> </p> <p> <%= f.label :password_confirmation, "Password Confirmation" %> <%= f.password_field :password_confirmation %> </p> Let me know if this is sufficient or need more. <%= f.submit "Create", :disable_with => 'Please Wait...' %> <% end %>

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  • Correct way to edit and update complex viewmodel objects using asp.net-mvc2 and entity framework

    - by jslatts
    I have a table in my database with a one to many relationship to another table: ParentObject ID Name Description ChildObject ID Name Description ParentObjectID AnotherObjectID The objects are mapped into Entity Framework and exposed through a data access class. It seemed like ViewModels are recommended when the data to be displayed greatly differs from the domain object, so I created a ViewModel as follows: public class ViewModel { public IList<ParentObject> ParentObjects { get; set; } public ParentObject selectedObject { get; set; } public IList<ChildObject> ChildObjects { get; set; } } I have a view that displays a list of ParentObjects and when clicked will allow a ChildObject to be modified saved. <% using (Html.BeginForm()) { %> <table> <% foreach (var parent in Model.ParentObjects) { %> <tr> <td> ObjectID [<%= Html.Encode(parent.ID)%>] </td> <td> <%= Html.Encode(parent.Name)%> </td> <td> <%= Html.Encode(parent.Description)%> </td> </tr> <% } %> </table> <% if (Model.ParentObject != null) { %> <div> Name:<br /> <%= Html.TextBoxFor(model => model.ParentObject.Name) %> <%= Html.ValidationMessageFor(model => model.ParentObject.Name, "*")%> </div> <div> Description:<br /> <%= Html.TextBoxFor(model => model.ParentObject.Description) %> <%= Html.ValidationMessageFor(model => model.ParentObject.Description, "*")%> </div> <div> Child Objects </div> <% for (int i = 0; i < Model.ParentObject.ChildObjects.Count(); i++) { %> <div> <%= Html.DisplayTextFor(sd => sd.ChildObjects[i].Name) %> </div> <div> <%= Html.HiddenFor(sd => sd.ChildObjects[i].ID )%> <%= Html.TextBoxFor( sd => sd.ChildObjects[i].Description) %> <%= Html.ValidationMessageFor(sd => sd.ChildObjects[i].Description, "*") %> </div> <% } } } %> This all works fine. My question is around the best way to update the EF objects and persist the changes back to the database. I initially tried: [HttpPost] public ActionResult Edit(ViewModel viewModel) { ParentObject parent = myRepository.GetParentObjectByID(viewModel.SelectedObject.ID); if ((!ModelState.IsValid) || !TryUpdateModel(parent, "SelectedObject", new[] { "Name", "Description" })) { || !TryUpdateModel(parent.ChildObjects, "ChildObjects", new[] { "Name", "Description" })) { //Code to handle failure and return the current model snipped return View(viewModel); } myRepository.Save(); return RedirectToAction("Edit"); } When I try to save a change to the child object, I get this exception: Entities in 'MyEntities.ChildObject' participate in the 'FK_ChildObject_AnotherObject' relationship. 0 related 'AnotherObject' were found. 1 'AnotherObject' is expected. Investigation on StackOverflow and generally googling led me to this blog post that seems to describe my problem: TryUpdateModel() does not correctly handle nested collections. Apparently, (and stepping through the debugger confirms this) it creates a new ChildObject instead of associating with the EF objects from my instantiated context. My hacky work around is this: if (viewModel.ChildObjects.Count > 0) { foreach (ChildObject modelChildObject in viewModel.ChildObjects) { ChildObject childToUpdate = ParentObject.ChildObject.Where(a => a.ID == modelChildObject.ID).First(); childToUpdate.Name = modelChildObject.Name; } } This seems to work fine. My question to you good folks: Is there correct way to do this? I tried following the suggestion for making a custom model binder per the blog link I posted above but it didn't work (there was an issue with reflection) and I needed to get something going ASAP. PS - I tried to cleanup the code to hide specific information, so beware I may have hosed something up. I mainly just want to know if other people have solved this problem. Thanks!

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