Search Results

Search found 13776 results on 552 pages for 'python appengine'.

Page 182/552 | < Previous Page | 178 179 180 181 182 183 184 185 186 187 188 189  | Next Page >

  • Creating Auto Incrementing column in Google Appengine

    - by demos
    What is the easiest and most efficient way to create an auto-increment counter for every data row in google appengine? basically I want to give every row a unique row_number so that I can overcome the issue of only being able to get the first 1000 results in a select query. I can thus add a counter lies between condition and mine all the entires in the table.

    Read the article

  • Python Profiling not installed in Ubuntu? How do I get it in a virtualenv and without apt-get?

    - by interstar
    According to the Python documentation, the "profile" module is part of the standard library. But I can't find it. On my home machine, I was able to add it using apt-get install. (ie. it's split out into a separate ubuntu package.) On my work machine, (also ubuntu) I'm running in a virtualenv, so apt-get install isn't relevant. I can install python modules from pypi using easy-install, but I can't see anything on pypi which corresponds to the profiling module. (Presumably because it's meant to be part of the standard python install.) So how can I install it in this environment?

    Read the article

  • Appengine JDO dataclasses to python model

    - by M.A. Cape
    Does anyone have tried to implement an app in GAE having both java and python? I have an existing app and my front end is in java. Now I want to use the existing datastore to be interfaced by python. My problem is i don't know how to define the relationships and model that would be equivalent to the one in java. I have tried the one-to-many relationship in python but when stored in the datastore, the fields are different than the one-to-many of java. My data classes are as follows. //one-to-many owned Parent Class public class Parent{ @PrimaryKey @Persistent private String unitID; //some other fields... @Persistent @Order(extensions = @Extension(vendorName="datanucleus", key="list-ordering", value="dateCreated desc")) private List <Child> child; //methods & constructors were omitted } Child public class Child{ @PrimaryKey @Persistent(valueStrategy = IdGeneratorStrategy.IDENTITY) private Key uId; @Persistent private String name; /* etc... */ }

    Read the article

  • Comments on this assumption about running on dev server vs a real instance in app engine (python)?

    - by Jacob Oscarson
    Hello app engineers! I'm on an app engine project where I'd like to put in a link to a Javascript test runner that I'd like to only exist when running the development server. I've made some experiments on a local shell with configuration loaded using the technique found in NoseGAE versus live on the 'App Engine Console' [1] and it looks to me like a distinction btw real instance and dev server is the presence of the module google.appengine.tools. Which lead me to this utility function: def is_dev(): """ Tells us if we're running under the development server or not. :return: ``True`` if the code is running under the development server. """ try: from google.appengine import tools return True except ImportError: return False The question (finally!) would be: is this a bad idea? And in that case, can anyone suggest a better approach? [1] http://con.appspot.com/console/ (try it! very handy indeed)

    Read the article

  • Does anyone know a way to interact with HP OV(NNM) with python, perl or bash?

    - by marc.riera
    Do anyone know if there is out there any API/library to access NNM database from perl or python? We have a NNM 7.53 which give us access to its data with its java based applet through http. And of course through the 'ovw' GUI interface. I've tried to use Mechanize and selenium2(webdriver) to automatize some checks. The pourpose is to integrate it with our other monitoring services on our "general master console". Many thanks. Marc

    Read the article

  • Python CGI on Amazon AWS EC2 micro-instance -- a how-to!

    - by user595585
    How can you make an EC2 micro instance serve CGI scripts from lighthttpd? For instance Python CGI? Well, it took half a day, but I have gotten Python cgi running on a free Amazon AWS EC2 micro-instance, using the lighttpd server. I think it will help my fellow noobs to put all the steps in one place. Armed with the simple steps below, it will take you only 15 minutes to set things up! My question for the more experienced users reading this is: Are there any security flaws in what I've done? (See file and directory permissions.) Step 1: Start your EC2 instance and ssh into it. [Obviously, you'll need to sign up for Amazon EC2 and save your key pairs to a *.pem file. I won't go over this, as Amazon tells you how to do it.] Sign into your AWS account and start your EC2 instance. The web has tutorials on doing this. Notice that default instance-size that Amazon presents to you is "small." This is not "micro" and so it will cost you money. Be sure to manually choose "micro." (Micro instances are free only for the first year...) Find the public DNS code for your running instance. To do this, click on the instance in the top pane of the dashboard and you'll eventually see the "Public DNS" field populated in the bottom pane. (You may need to fiddle a bit.) The Public DNS looks something like: ec2-174-129-110-23.compute-1.amazonaws.com Start your Unix console program. (On Max OS X, it's called Terminal, and lives in the Applications - Utilities folder.) cd to the directory on your desktop system that has your *.pem file containing your AWS keypairs. ssh to your EC2 instance using a command like: ssh -i <<your *.pem filename>> ec2-user@<< Public DNS address >> So, for me, this was: ssh -i amzn_ec2_keypair.pem [email protected] Your EC2 instance should let you in. Step 2: Download lighttpd to your EC2 instance. To install lighttpd, you will need root access on your EC2 instance. The problem is: Amazon will not let you sign in as root. (Not straightforwardly, at least.) But there is a workaround. Type this command: sudo /bin/bash The system prompt-character will change from $ to #. We won't exit from "sudo" until the very last step in this whole process. Install the lighttpd application (version 1.4.28-1.3.amzn1 for me): yum install lighttpd Install the FastCGI libraries for lighttpd (not needed, but why not?): yum install lighttpd-fastcgi Test that your server is working: /etc/init.d/lighttpd start Step 3: Let the outside world see your server. If you now tried to hit your server from the browser on your desktop, it would fail. The reason: By default, Amazon AWS does not open any ports to your EC2 instance. So, you have to open the ports manually. Go to your EC2 dashboard in your desktop's browser. Click on "Security Groups" in the left pane. One or more security groups will appear in the upper right pane. Choose the one that was assigned to your EC2 instance when you launched your instance. A table called "Allowed Connections" will appear in the lower right pane. A pop-up menu will let you choose "HTTP" as the connection method. The other values in that line of the table should be: tcp, 80, 80, 0.0.0.0/0 Now hit your EC2 instance's server from the desktop in your browser. Use the Public DNS address that you used earlier to SSH in. You should see the lighttpd generic web page. If you don't, I can't help you because I am such a noob. :-( Step 4: Configure lighttpd to serve CGI. Back in the console program, cd to the configuration directory for lighttpd: cd /etc/lighttpd To enable CGI, you want to uncomment one line in the < modules.conf file. (I could have enabled Fast CGI, but baby steps are best!) You can do this with the "ed" editor as follows: ed modules.conf /include "conf.d\/cgi.conf"/ s/#// w q Create the directory where CGI programs will live. (The /etc/lighttpd/lighttpd.conf file determines where this will be.) We'll create our directory in the default location, so we don't have to do any editing of configuration files: cd /var/www/lighttpd mkdir cgi-bin chmod 755 cgi-bin Almost there! Of course you need to put a test CGI program into the cgi-bin directory. Here is one: cd cgi-bin ed a #!/usr/bin/python print "Content-type: text/html\n\n" print "<html><body>Hello, pyworld.</body></html>" . w hellopyworld.py q chmod 655 hellopyworld.py Restart your lighttpd server: /etc/init.d/lighttpd restart Test your CGI program. In your desktop's browser, hit this URL, substituting your EC2 instance's public DNS address: http://<<Public DNS>>/cgi-bin/hellopyworld.py For me, this was: http://ec2-174-129-110-23.compute-1.amazonaws.com/cgi-bin/hellopyworld.py Step 5: That's it! Clean up, and give thanks! To exit from the "sudo /bin/bash" command given earlier, type: exit Acknowledgements: Heaps of thanks to: wiki.vpslink.com/Install_and_Configure_lighttpd www.cyberciti.biz/tips/lighttpd-howto-setup-cgi-bin-access-for-perl-programs.html aws.typepad.com/aws/2010/06/building-three-tier-architectures-with-security-groups.html Good luck, amigos! I apologize for the non-traditional nature of this "question" but I have gotten so much help from Stackoverflow that I was eager to give something back.

    Read the article

  • Python2.7 / Pip2.7 install in Centos6: root does not see /usr/local/bin

    - by Erotemic
    I am trying to install Python2.7 in Centos 6. It's a pain as centos6 ships with python26 and yum is dependent on it. Furthermore yum does not seem to have python2.7 I ended up building it from source: wget https://www.python.org/ftp/python/2.7.6/Python-2.7.6.tgz gunzip Python-2.7.6.tgz tar -xvf Python-2.7.6.tar cd Python-2.7.6 ./configure --prefix=/usr/local --enable-unicode=ucs4 --enable-shared LDFLAGS="-Wl,-rpath /usr/local/lib" make sudo make altinstall cd ~ This installed python2.7 to /usr/local/bin and I can use it. But I cannot call it with sudo unless I specify the whole pathname To install pip I had to do: wget https://bootstrap.pypa.io/get-pip.py sudo /usr/local/bin/python2.7 get-pip.py Now whenever I want a package I have to call sudo /usr/local/bin/pip2.7 install somepackage Is there a clean way to be able to run: sudo pip2.7 install somepackage without having to specify the absolute path? Is a symlink into /usr/bin safe?

    Read the article

  • Listing packages in a repositiory?

    - by noloader
    I'm working on Ubuntu 12.04 Server. I want to install OpenStack, so I enabled the Cloud Archive repo: sudo add-apt-repository cloud-archive:havana After the subsequent update and upgrade, I noticed python-crypto changed. python-crypto recently fixed a CVE, so I would like to ensure I'm using the patched version of python-crypto. I'd also like to compare the python-crypto in both Ubuntu and Cloud Archive. How does one list the package information for both Ubuntu::python-crypto and CloudArchive::python-crypto? (And sorry I could not tag this with apt-cache. Its not available in the list of tags). Thanks in advance

    Read the article

  • The Zen of Python distils the guiding principles for Python into 20 aphorisms but lists only 19. What's the twentieth?

    - by Jeff Walden
    From PEP 20, The Zen of Python: Long time Pythoneer Tim Peters succinctly channels the BDFL's guiding principles for Python's design into 20 aphorisms, only 19 of which have been written down. What is this twentieth aphorism? Does it exist, or is the reference merely a rhetorical device to make the reader think? (One potential answer that occurs to me is that "You aren't going to need it" is the remaining aphorism. If that were the case, it would both exist and act to make the reader think, and it would be characteristically playful, thus fitting the list all the better. But web searches suggest this to be an extreme programming mantra, not intrinsically Pythonic wisdom, so I'm stumped.)

    Read the article

  • How to "select file" with Python script? . Google App Engine . Python .

    - by draconisthe0ry
    I'm trying to create an online application for a python function i have created. in my script, i input the path of my file for the computer (input_path = '/users/user/desktop/input.txt') but i'm not sure how to go about this using Google App Engine . I have the choice between 3 templates: flask, django, and bottle . I really do believe this question is relevant for people transitioning from scripts to web-based applications. Do I need to incorporate GUI stuff from Tkinter or something? There has to be a way to simply select a file to use for the input path in an interactive way using python scripts

    Read the article

  • How to develop a menu for Linux apps

    - by Antonio Ciccia
    I want to create a python panel for Linux like pypanel or tint2 just for fun and to do practice with python development. Now the problem is: I want to create an auto-generated menu, but I don't know where to start. Where can I find all user's installed software in a Linux distro? I know I should look in the /usr/bin folder, but I don't know if it's really the best thing to do. Is there a way to filter installed apps to avoid dependecies programs?

    Read the article

  • Need a host which supports OSQA

    - by Josip Gòdly Zirdum
    Hi i'm looking to install OSQA and see how it goes I have a great niche which I think may work real well, but till I get a large enough audience I'd like to use shared hosting then move up to a dedicated or vps hosting... Almost all hosts i've looked at don't support something OSQA needs I need relatively cheap shared hosting with cpanel. Any recommendations? It needs to support: Django Python markdown html5lib Python OpenId South

    Read the article

  • What is the historical basis of using Javascript in web programming?

    - by rd108
    I come from a scientific biology background where we also use Python a lot. Now that I've begun to start with Web development, I've consistently found myself wondering just why it is that JavaScript is the primary client-side language on the Web. Is JavaScript's predominance a historical accident or something else? Also, I'm curious if there are any hurdles to integrating Python into client-side scripting?

    Read the article

  • Install Trac on 64bits Windows 7

    - by Tufo
    I'm configuring a new Developing Server that came with Windows 7 64bits. It must have installed Trac with Subversion integration. I install Subversion with VisualSVN 2.1.1, clients with TortoiseSVN 1.6.7 and AnkhSVN 2.1.7 for Visual Studio 2008 SP1 integration. All works fine! my problem begun when going to Trac installation. I install python 2.6 all fine. Trac hasn't a x64 windows installer, so I installed it manually by compiling it with python console (C:\Python26\python.exe C:/TRAC/setup.py install). After that, I can create TRAC projects normally, the Trac core is working fine. And so the problem begins, lets take a look at the Trac INSTALL file: Requirements To install Trac, the following software packages must be installed: Python, version = 2.3. Subversion, version = 1.0. (= 1.1.xrecommended) Subversion SWIG Python bindings (not PySVN). PySQLite,version 1.x (for SQLite 2.x) or version 2.x (for SQLite 3.x) Clearsilver, version = 0.9.3 (0.9.14 recommended) Python: OK Subverion: OK Subversion SWIG Python bindings (not PySVN): Here I face the first issue, he asks me for 'cd' to the swig directory and run the 'configure' file, and the result is: C:\swigwin-1.3.40> c:\python26\python.exe configure File "configure", line 16 DUALCASE=1; export DUALCASE # for MKS sh ^ SyntaxError: invalid syntax PySQLite, version 1.x (for SQLite 2.x) or version 2.x (for SQLite 3.x): Don't need, as Python 2.6 comes with SQLLite Clearsilver, version = 0.9.3 (0.9.14 recommended): Second issue, Clearsilver only has 32bit installer wich does not recognize python installation (as registry keys are in different places from 32 to 64 bits). So I try to manually install it with python console. It returns me a error of the same kind as SWIG: C:\clearsilver-0.10.5>C:\python26\python.exe ./configure File "./configure", line 13 if test -n "${ZSH_VERSION+set}" && (emulate sh) >/dev/null 2>&1; then ^ SyntaxError: invalid syntax When I simulate a web server using the "TRACD" command, it runs fine when I disable svn support but when I try to open the web page it shows me a error regarding ClearSilver is not installed for generating the html content. AND (for making me more happy) This TRAC will run over IIS7, I mustn't install Apache... I'm nearly crazy with this issue... HELP!!!

    Read the article

  • How do I use a ListProperty(users.user) in a djangoforms.ModelForm on Google AppEngine?

    - by Gabriel
    I have been looking around a bit for info on how to do this. Essentially I have a Model: class SharableUserAsset(db.Model): name = StringProperty() users = ListProperty(users.User) My questions are: What is the best way to associate users to this value where they are not authenticated, visa vi invite from contacts list etc.? Is there a reasonable way to present a list control easily in a djangoforms.ModelForm? Once a user logs in I want to be able to check if that user is in the list for any number of SharableUserAsset class "records", how do I do that? Does user evaluate as a match to an email address or is there a way to look up a valid user against an email address?

    Read the article

  • Issue on passing a checkbox set to an AppEngine script through jQuery Ajax/Json

    - by Jorge
    I have a set of checkboxes with multiple choice allowed. I parse the set this way: if ($("input[name='route_day']:checked").length > 0) { $("input[name='route_day']:checked").each(function(){ if(this.value != null) route_days_hook.push(this.value); }); dataTrap.route_days = $.JSON.encode(route_days_hook); } ...and pull the whole dataTrap to an AppEngine Python script via jQuery ajax. However, the Python script just bugs. If i change dataTrap.route_days value to a string instead of the JSON encoded object, everything works fine. My question is: how can i pass a checkbox set to the script using Ajax and still be able to iterate over it on the script?

    Read the article

  • Python appengine Query does not work when using a variable.

    - by Lloyd
    Hi, I am trying to use a fetcher method to retrieve items from my datastore. If I use the following def getItem(item_id): q = Item.all() q.filter("itemid = ", item_id) It fails because nothing is returned. If I hard code in an item like def getItem(item_id): q = Item.all() q.filter("itemid = ", 9000) it fetches just fine, and sings merrily along. I have tried every which way to get this to work. I have used result = db.GqlQuery("SELECT * FROM Item WHERE item_id = :1 LIMIT 1", title).fetch(1) to the same effect. If I hard code in a number, works fine. I have tried setting the select statement as a local string, assembling it that way, casting the int as a string, and nothing. When I output the SELECT statement to the screen, looks fine. I can cut ans paste the output into the string, and whammo, it works. Any help would be appreciated.

    Read the article

< Previous Page | 178 179 180 181 182 183 184 185 186 187 188 189  | Next Page >