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  • Nested IF statement on Google Spreadsheet, second part same as the first [migrated]

    - by lazfish
    I have a spreadsheet for my budget. Payments are either drawn from my bank or my Amex card and then my Amex card is drawn from my bank as well. So I add up all my monthly total like this: =sumif(I3:I20,"<>AMEX",D3:D20) Where I3:I20 = account bill is paid from and D3:D20 is monthly amount due. So I am not including bills that come from my Amex card in the total since the Amex bill itself covers those. Next I have a column that has the day of the month 1-10 (when everything gets paid) and it does this: =sumif(H3:H20,E24:E33,D3:D20) Where H3:H20 = date bill is paid and E25:E35 = range from 1-10. What I want to do is make this second part do the same check as the first. Something like this: =sumif(H3:H19,E24:E33,IF(I3:I19"<>SPG",D3:D19,0)) But I get error: "Parse error" What am I doing wrong?

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  • Failed dependency while installing browser Iron(A google chrome clone)

    - by Krishnadas PC
    Installation failed while trying to install Iron browser. [root@localhost softwares]# rpm -ivh iron64.rpm error: Failed dependencies: libc.so.6(GLIBC_2.15)(64bit) is needed by iron64-29.0.1600-2.x86_64 libudev.so.1()(64bit) is needed by iron64-29.0.1600-2.x86_64 libudev.so.1(LIBUDEV_183)(64bit) is needed by iron64-29.0.1600-2.x86_64 and when tried to install using yum it failed also.

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  • Keyboard Shortcut for Navigating to a Text Field in Google Chrome

    - by Micky McQuade
    I am trying to use keyboard shortcuts more and more and have run across something I've not been able to figure out. If there is a text box on the page that I want to enter text into, how can I navigate to that field quickly without actually clicking on it with the mouse? I know I can just start tabbing and eventually get to it I've tried using Ctrl-F to find text near it and then tab to it Any ideas?

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  • Pasting a download link into google chrome

    - by fakeit
    When I want to download something in Safari, like http://foo.com/bar.zip, all I have to do is paste that link into the dowloads window. Is there a way to do this in Chrome? I've gotten used to Safari, hitting cmd-alt-L (dowloads window), and then pasting. It's quick, neat, and saves me going to FileSave As... I like to keep my hands on the keyboard, so if there is a quick way to do this without using a mouse, that's my ideal solution.

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  • Lightest way to run Google Hangouts Chrome app on Mac

    - by jadengore
    I recently transitioned to Safari because I'm really tired of how Chrome hogs memory and drains my battery like crazy. The only thing that has been keeping the Chrome icon open is the Hangouts plugin. Basically, I am looking for the lightest way to run Hangouts on my Mac. By light, I mean the least amount of RAM usage, and preferably a way to do it without Chrome open/light version of Chrome that only opens extensions. Any suggestions? EDIT: Another thing I noticed was that Hangouts ignores your default browser if links are sent to you by chat, and when clicked they open in Chrome. My question doesn't relate to this at all, but I found it interesting...

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  • Put Google Chrome, AVG on a flash drive

    - by duncan12
    I often install programs on others' computers such as LibreOffice, which, when they only have a dial-up connection, takes forever to download. So instead I keep it on a flash drive and install it from there. This works fine for LibreOffice. However, some programs, when you download them all you are downloading is a downloader - when you download ChromeSetup and open it, a installer window opens which actually downloads Chrome. Dial-up users then see that it will take 4 hours. Another example is AVG free antivirus - you download an installer, which when opened actually downloads AVG. However this doesn't work too well for dial-up users. How do I put the entire program of things like Chrome and AVG on a flash drive for fast installation on others' slow connections?

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  • Prevent history deletion on Google Chrome

    - by ProstheticHead
    One of the guys I'm in charge of hasn't been pulling his weight. His productivity and quality of workmanship are way down and his computer's been getting malware infections lately. You can see where this is going. I'm generally an easy going guy (and I don't want any trouble but I still have to address this issue). Is there a way to disable browser history deletion on Chrome? I'm hoping this alone will be enough of a deterrent to put things right.

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  • Embedding multiple Google Calendars in one frame

    - by cyruskazemi
    I have multiple secondary calendars under one account. I would like to be able to embed all of these calendars in the same frame on a web page so that anyone is able to view them. I tried making them all public but have only been able to embed one at a time because each calendar has a different address. Does anyone know if they can all be embedded at the same time?

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  • Image Erosion for face detection in C#

    - by Chris Dobinson
    Hi, I'm trying to implement face detection in C#. I currently have a black + white outline of a photo with a face within it (Here). However i'm now trying to remove the noise and then dilate the image in order to improve reliability when i implement the detection. The method I have so far is here: unsafe public Image Process(Image input) { Bitmap bmp = (Bitmap)input; Bitmap bmpSrc = (Bitmap)input; BitmapData bmData = bmp.LockBits(new Rectangle(0, 0, bmp.Width, bmp.Height), ImageLockMode.ReadWrite, PixelFormat.Format24bppRgb); int stride = bmData.Stride; int stride2 = bmData.Stride * 2; IntPtr Scan0 = bmData.Scan0; byte* p = (byte*)(void*)Scan0; int nOffset = stride - bmp.Width * 3; int nWidth = bmp.Width - 2; int nHeight = bmp.Height - 2; var w = bmp.Width; var h = bmp.Height; var rp = p; var empty = CompareEmptyColor; byte c, cm; int i = 0; // Erode every pixel for (int y = 0; y < h; y++) { for (int x = 0; x < w; x++, i++) { // Middle pixel cm = p[y * w + x]; if (cm == empty) { continue; } // Row 0 // Left pixel if (x - 2 > 0 && y - 2 > 0) { c = p[(y - 2) * w + (x - 2)]; if (c == empty) { continue; } } // Middle left pixel if (x - 1 > 0 && y - 2 > 0) { c = p[(y - 2) * w + (x - 1)]; if (c == empty) { continue; } } if (y - 2 > 0) { c = p[(y - 2) * w + x]; if (c == empty) { continue; } } if (x + 1 < w && y - 2 > 0) { c = p[(y - 2) * w + (x + 1)]; if (c == empty) { continue; } } if (x + 2 < w && y - 2 > 0) { c = p[(y - 2) * w + (x + 2)]; if (c == empty) { continue; } } // Row 1 // Left pixel if (x - 2 > 0 && y - 1 > 0) { c = p[(y - 1) * w + (x - 2)]; if (c == empty) { continue; } } if (x - 1 > 0 && y - 1 > 0) { c = p[(y - 1) * w + (x - 1)]; if (c == empty) { continue; } } if (y - 1 > 0) { c = p[(y - 1) * w + x]; if (c == empty) { continue; } } if (x + 1 < w && y - 1 > 0) { c = p[(y - 1) * w + (x + 1)]; if (c == empty) { continue; } } if (x + 2 < w && y - 1 > 0) { c = p[(y - 1) * w + (x + 2)]; if (c == empty) { continue; } } // Row 2 if (x - 2 > 0) { c = p[y * w + (x - 2)]; if (c == empty) { continue; } } if (x - 1 > 0) { c = p[y * w + (x - 1)]; if (c == empty) { continue; } } if (x + 1 < w) { c = p[y * w + (x + 1)]; if (c == empty) { continue; } } if (x + 2 < w) { c = p[y * w + (x + 2)]; if (c == empty) { continue; } } // Row 3 if (x - 2 > 0 && y + 1 < h) { c = p[(y + 1) * w + (x - 2)]; if (c == empty) { continue; } } if (x - 1 > 0 && y + 1 < h) { c = p[(y + 1) * w + (x - 1)]; if (c == empty) { continue; } } if (y + 1 < h) { c = p[(y + 1) * w + x]; if (c == empty) { continue; } } if (x + 1 < w && y + 1 < h) { c = p[(y + 1) * w + (x + 1)]; if (c == empty) { continue; } } if (x + 2 < w && y + 1 < h) { c = p[(y + 1) * w + (x + 2)]; if (c == empty) { continue; } } // Row 4 if (x - 2 > 0 && y + 2 < h) { c = p[(y + 2) * w + (x - 2)]; if (c == empty) { continue; } } if (x - 1 > 0 && y + 2 < h) { c = p[(y + 2) * w + (x - 1)]; if (c == empty) { continue; } } if (y + 2 < h) { c = p[(y + 2) * w + x]; if (c == empty) { continue; } } if (x + 1 < w && y + 2 < h) { c = p[(y + 2) * w + (x + 1)]; if (c == empty) { continue; } } if (x + 2 < w && y + 2 < h) { c = p[(y + 2) * w + (x + 2)]; if (c == empty) { continue; } } // If all neighboring pixels are processed // it's clear that the current pixel is not a boundary pixel. rp[i] = cm; } } bmpSrc.UnlockBits(bmData); return bmpSrc; } As I understand it, in order to erode the image (and remove the noise), we need to check each pixel to see if it's surrounding pixels are black, and if so, then it is a border pixel and we need not keep it, which i believe my code does, so it is beyond me why it doesn't work. Any help or pointers would be greatly appreciated Thanks, Chris

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  • Partial string search in boost::multi_index_container

    - by user361699
    I have a struct to store info about persons and multi_index_contaider to store such objects struct person { std::string m_first_name; std::string m_last_name; std::string m_third_name; std::string m_address; std::string m_phone; person(); person(std::string f, std::string l, std::string t = "", std::string a = DEFAULT_ADDRESS, std::string p = DEFAULT_PHONE) : m_first_name(f), m_last_name(l), m_third_name(t), m_address(a), m_phone(p) {} }; typedef multi_index_container , ordered_non_unique, member, member persons_set; operator< and operator<< implementation for person bool operator<(const person &lhs, const person &rhs) { if(lhs.m_last_name == rhs.m_last_name) { if(lhs.m_first_name == rhs.m_first_name) return (lhs.m_third_name < rhs.m_third_name); return (lhs.m_first_name < rhs.m_first_name); } return (lhs.m_last_name < rhs.m_last_name); } std::ostream& operator<<(std::ostream &s, const person &rhs) { s << "Person's last name: " << rhs.m_last_name << std::endl; s << "Person's name: " << rhs.m_first_name << std::endl; if (!rhs.m_third_name.empty()) s << "Person's third name: " << rhs.m_third_name << std::endl; s << "Phone: " << rhs.m_phone << std::endl; s << "Address: " << rhs.m_address << std::endl; return s; } Add several persons into container: person ("Alex", "Johnson", "Somename"); person ("Alex", "Goodspeed"); person ("Petr", "Parker"); person ("Petr", "Goodspeed"); Now I want to find person by lastname (the first member of the second index in multi_index_container) persons_set::nth_index<1::type &names_index = my_set.get<1(); std::pair::type::const_iterator, persons_set::nth_index<1::type::const_iterator n_it = names_index.equal_range("Goodspeed"); std::copy(n_it.first ,n_it.second, std::ostream_iterator(std::cout)); It works great. Both 'Goodspeed' persons are found. Now lets try to find person by a part of a last name: std::pair::type::const_iterator, persons_set::nth_index<1::type::const_iterator n_it = names_index.equal_range("Good"); std::copy(n_it.first ,n_it.second, std::ostream_iterator(std::cout)); This returns nothing, but partial string search works as a charm in std::set. So I can't realize what's the problem. I only wraped strings by a struct. May be operator< implementation? Thanks in advance for any help.

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  • Value of links on negative review pages

    - by Sam Healey
    A general assumption with SEO is more links = higher rankings. What I would like to know is does Google know what those links are referring to. I.e. if somebody gives a product a good review on their personal blog and links the review to another companies website (who are selling the product), would Google take consideration for the review/description link. Essentially would Google know that this link refers to a product. So if somebody is looking to buy a product, Google would know to include this page because the previous link said it sells products rather than just having information on products. Then to take this further, does Google know if a link is positive or negative. For example, If somebody creates a post saying, do not visit example.com, example.com is bad because of blah blah blah. Would Google know that the link is getting bad feedback and therefore would it have a negative affect on rankings, or would Google go oh its just another link and give it better rankings?

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  • image processing algorithm in MATLAB

    - by user261002
    I am trying to reconstruct an algorithm belong to this paper: Decomposition of biospeckle images in temporary spectral bands Here is an explanation of the algorithm: We recorded a sequence of N successive speckle images with a sampling frequency fs. In this way it was possible to observe how a pixel evolves through the N images. That evolution can be treated as a time series and can be processed in the following way: Each signal corresponding to the evolution of every pixel was used as input to a bank of filters. The intensity values were previously divided by their temporal mean value to minimize local differences in reflectivity or illumination of the object. The maximum frequency that can be adequately analyzed is determined by the sampling theorem and s half of sampling frequency fs. The latter is set by the CCD camera, the size of the image, and the frame grabber. The bank of filters is outlined in Fig. 1. In our case, ten 5° order Butterworth11 filters were used, but this number can be varied according to the required discrimination. The bank was implemented in a computer using MATLAB software. We chose the Butter-worth filter because, in addition to its simplicity, it is maximally flat. Other filters, an infinite impulse response, or a finite impulse response could be used. By means of this bank of filters, ten corresponding signals of each filter of each temporary pixel evolution were obtained as output. Average energy Eb in each signal was then calculated: where pb(n) is the intensity of the filtered pixel in the nth image for filter b divided by its mean value and N is the total number of images. In this way, en values of energy for each pixel were obtained, each of hem belonging to one of the frequency bands in Fig. 1. With these values it is possible to build ten images of the active object, each one of which shows how much energy of time-varying speckle there is in a certain frequency band. False color assignment to the gray levels in the results would help in discrimination. and here is my MATLAB code base on that : clear all for i=0:39 str = num2str(i); str1 = strcat(str,'.mat'); load(str1); D{i+1}=A; end new_max = max(max(A)); new_min = min(min(A)); for i=20:180 for j=20:140 ts = []; for k=1:40 ts = [ts D{k}(i,j)]; %%% kth image pixel i,j --- ts is time series end ts = double(ts); temp = mean(ts); ts = ts-temp; ts = ts/temp; N = 5; % filter order W = [0.00001 0.05;0.05 0.1;0.1 0.15;0.15 0.20;0.20 0.25;0.25 0.30;0.30 0.35;0.35 0.40;0.40 0.45;0.45 0.50]; N1 = 5; for ind = 1:10 Wn = W(ind,:); [B,A] = butter(N1,Wn); ts_f(ind,:) = filter(B,A,ts); end for ind=1:10 imag_test1{ind}(i,j) =sum((ts_f(ind,:)./mean(ts_f(ind,:))).^2); end end end for i=1:10 temp_imag = imag_test1{i}(:,:); x=isnan(temp_imag); temp_imag(x)=0; temp_imag=medfilt2(temp_imag); t_max = max(max(temp_imag)); t_min = min(min(temp_imag)); temp_imag = (temp_imag-t_min).*(double(new_max-new_min)/double(t_max-t_min))+double(new_min); imag_test2{i}(:,:) = temp_imag; end for i=1:10 A=imag_test2{i}(:,:); B=A/max(max(A)); B=histeq(B); figure,imshow(B) colorbar end but I am not getting the same result as paper. has anybody has aby idea why? or where I have gone wrong? Refrence Link to the paper

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  • Transform OpenCV image data type to Devil image format and vice-verca

    - by D.K
    I want to use a CUDA-enabled SIFT library but I am using the OpenCV driver to get images from the webcam? The Cuda library is using the Devil Library for image data types. Should I transofrm the images from OpenCV data types to Devil? Or Should I use another method for getting images from the webcam[devil compatible data types]? Thanks for your attention

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  • Populate google.visualization.DataTable for a AnnotatedTimeLine using JSON

    - by Lucifer
    Hi I have a HttpHandler which returns some JSON in (i think) the correct format for a google.visualization.DataTable, but the AnnotatedTimeLine fails to work? This is the JSON returned by the Handler: {cols: [{id: 'DATE', label: 'Date', type: 'date'}, {id: 'KEYWORD51', label: 'vw cheltenham', type: 'number'}, {id: 'KEYWORD52', label: 'volkswagen cheltenham', type: 'number'}, {id: 'KEYWORD61', label: 'vw dealer cheltenham', type: 'number'}], rows: [{c: [{v: new Date(2010, 3, 13)}, {v: 20}, {v: 1}, {v: 2}]}, {c: [{v: new Date(2010, 3, 14)}, {v: 19}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 3, 15)}, {v: 19}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 3, 16)}, {v: 18}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 3, 17)}, {v: 17}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 3, 18)}, {v: 17}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 3, 19)}, {v: 12}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 3, 20)}, {v: 13}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 3, 21)}, {v: 11}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 3, 22)}, {v: 10}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 3, 23)}, {v: 10}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 3, 24)}, {v: 8}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 3, 25)}, {v: 6}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 3, 26)}, {v: 6}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 3, 27)}, {v: 5}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 3, 28)}, {v: 4}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 3, 29)}, {v: 4}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 3, 30)}, {v: 2}, {v: 1}, {v: 1}]}, {c: [{v: new Date(2010, 4, 1)}, {v: 2}, {v: 1}, {v: 1}]}, {c: [{v: new Date(2010, 4, 2)}, {v: 1}, {v: 1}, {v: 1}]}, {c: [{v: new Date(2010, 4, 3)}, {v: 2}, {v: 1}, {v: 1}]}, {c: [{v: new Date(2010, 4, 4)}, {v: 0}, {v: 1}, {v: 1}]}, {c: [{v: new Date(2010, 4, 5)}, {v: 0}, {v: 1}, {v: 1}]}, {c: [{v: new Date(2010, 4, 6)}, {v: 0}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 4, 7)}, {v: 0}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 4, 8)}, {v: 0}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 4, 9)}, {v: 0}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 4, 10)}, {v: 0}, {v: 0}, {v: 0}]}, {c: [{v: new Date(2010, 4, 11)}, {v: 0}, {v: 1}, {v: 1}]}, {c: [{v: new Date(2010, 4, 12)}, {v: 2}, {v: 1}, {v: 1}]}]} This is the Javascript, I used JQuery to get the JSON, have also tried $.getJSON() google.load('visualization', '1', { 'packages': ['annotatedtimeline'] }); google.setOnLoadCallback(loadGraph); function loadGraph() { $.get("/GraphDataHandler.axd", function(response) { drawGraph(response); }); } function drawGraph(response) { var visualization = new google.visualization.AnnotatedTimeLine(document.getElementById('chart_div')); var data = new google.visualization.DataTable(response, 0.6); visualization.draw(data, { title: 'Rankings', titleX: 'Date', titleY: 'Position', displayAnnotations: false, allowRedraw: true }); } But, if I write the same JSON to the page like below it works fine!? <script type="text/javascript"> //<![CDATA[ var gData = {cols: [{id: 'DATE', label: 'Date', type: 'date'}, {id: 'KEYWORD51', label: 'vw cheltenham', type: 'number'}], rows: [{c: [{v: new Date(2010, 3, 13)}, {v: 20}]}, {c: [{v: new Date(2010, 3, 14)}, {v: 19}]}, {c: [{v: new Date(2010, 3, 15)}, {v: 19}]}, {c: [{v: new Date(2010, 3, 16)}, {v: 18}]}, {c: [{v: new Date(2010, 3, 17)}, {v: 17}]}, {c: [{v: new Date(2010, 3, 18)}, {v: 17}]}, {c: [{v: new Date(2010, 3, 19)}, {v: 12}]}, {c: [{v: new Date(2010, 3, 20)}, {v: 13}]}, {c: [{v: new Date(2010, 3, 21)}, {v: 11}]}, {c: [{v: new Date(2010, 3, 22)}, {v: 10}]}, {c: [{v: new Date(2010, 3, 23)}, {v: 10}]}, {c: [{v: new Date(2010, 3, 24)}, {v: 8}]}, {c: [{v: new Date(2010, 3, 25)}, {v: 6}]}, {c: [{v: new Date(2010, 3, 26)}, {v: 6}]}, {c: [{v: new Date(2010, 3, 27)}, {v: 5}]}, {c: [{v: new Date(2010, 3, 28)}, {v: 4}]}, {c: [{v: new Date(2010, 3, 29)}, {v: 4}]}, {c: [{v: new Date(2010, 3, 30)}, {v: 2}]}, {c: [{v: new Date(2010, 4, 1)}, {v: 2}]}, {c: [{v: new Date(2010, 4, 2)}, {v: 1}]}, {c: [{v: new Date(2010, 4, 3)}, {v: 2}]}, {c: [{v: new Date(2010, 4, 4)}, {v: 0}]}, {c: [{v: new Date(2010, 4, 5)}, {v: 0}]}, {c: [{v: new Date(2010, 4, 6)}, {v: 0}]}, {c: [{v: new Date(2010, 4, 7)}, {v: 0}]}, {c: [{v: new Date(2010, 4, 8)}, {v: 0}]}, {c: [{v: new Date(2010, 4, 9)}, {v: 0}]}, {c: [{v: new Date(2010, 4, 10)}, {v: 0}]}, {c: [{v: new Date(2010, 4, 11)}, {v: 0}]}, {c: [{v: new Date(2010, 4, 12)}, {v: 2}]}]}; //]]> </script> Please advise how I can get it to work correctly using a the JSON calls? Thanks

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  • Offer the posibility to preview a personalized product

    - by bellesebastien
    I want to give my client's the possibility to preview their personalized product. In a nutshell, personalization means the user specifies some text and positions the text somewhere on an image of the product. A great example of what I'd like to achieve is this. Select a frame size and then hit Personalize, after you select the occasion and add the text you can chose to preview the product. The hardest thing to do here, as I see it, is to generate the image. The positioning of text will probably be made in javascript. Do you have any recommendations? Just as a note, using scene7 is not a possibility. Thanks.

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  • Dynamically create and save image with Django and PIL/Django-Photologue

    - by Travis
    I want to generate a page of html with dynamic content and then save the result as an image as well as display the page to the user. So, user signs up to attend conference and gives their name and org. That data is combined with html/css elements to show what their id badge for the conference will look like (their name and org on top of our conference logo background) for preview. Upon approval, the page is saved on the server to an image format (PNG, PDF or JPG) to be printed onto a physical badge by an admin later. I am using Django and django-photologue powered by PIL. The view might look like this # app/views.py def badgepreview(request, attendee_id): u = User.objects.get(id=attendee_id) name = u.name org = u.org return render_to_response('app/badgepreview.html', {'name':name,'org':org,}, context_instance = RequestContext(request), ) The template could look like this {# templates/app/badgepreview.html #} {% extends "base.html" %} {% block page_body %} <div style='background:url(/site_media/img/logo_bg.png) no-repeat;'> <h4>{{ name }}</h4> <h4>{{ org }}</h4> </div> {% endblock %} simple, but how do I save the result? Or is there a better way to get this done?

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