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  • How do I traverse the filesystem looking for a regex match?

    - by editor
    I know this is teeball for veteran sysadmins, but I'm looking to search a directory tree for file contents that match a regex (here, the word "Keyword"). I've gotten that far, but now I'm having trouble ignoring files in a hidden (.svn) file tree. Here's what I'm working with: find . -exec grep "Keyword" '{}' \; -print Reading sites via search I know that I need to negate the name flag, but I can't it working in the right order.

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  • Is your team is a high-performing team?

    As a child I can remember looking out of the car window as my father drove along the Interstate in Florida while seeing prisoners wearing bright orange jump suits and prison guards keeping a watchful eye on them. The prisoners were taking part in a prison road gang. These road gangs were formed to help the state maintain the state highway infrastructure. The prisoner’s primary responsibilities are to pick up trash and debris from the roadway. This is a prime example of a work group or working group used by most prison systems in the United States. Work groups or working groups can be defined as a collection of individuals or entities working together to achieve a specific goal or accomplish a specific set of tasks. Typically these groups are only established for a short period of time and are dissolved once the desired outcome has been achieved. More often than not group members usually feel as though they are expendable to the group and some even dread that they are even in the group. "A team is a small number of people with complementary skills who are committed to a common purpose, performance goals, and approach for which they are mutually accountable." (Katzenbach and Smith, 1993) So how do you determine that a team is a high-performing team?  This can be determined by three base line criteria that include: consistently high quality output, the promotion of personal growth and well being of all team members, and most importantly the ability to learn and grow as a unit. Initially, a team can successfully create high-performing output without meeting all three criteria, however this will erode over time because team members will feel detached from the group or that they are not growing then the quality of the output will decline. High performing teams are similar to work groups because they both utilize a collection of individuals or entities to accomplish tasks. What distinguish a high-performing team from a work group are its characteristics. High-performing teams contain five core characteristics. These characteristics are what separate a group from a team. The five characteristics of a high-performing team include: Purpose, Performance Measures, People with Tasks and Relationship Skills, Process, and Preparation and Practice. A high-performing team is much more than a work group, and typically has a life cycle that can vary from team to team. The standard team lifecycle consists of five states and is comparable to a human life cycle. The five states of a high-performing team lifecycle include: Formulating, Storming, Normalizing, Performing, and Adjourning. The Formulating State of a team is first realized when the team members are first defined and roles are assigned to all members. This initial stage is very important because it can set the tone for the team and can ultimately determine its success or failure. In addition, this stage requires the team to have a strong leader because team members are normally unclear about specific roles, specific obstacles and goals that my lay ahead of them.  Finally, this stage is where most team members initially meet one another prior to working as a team unless the team members already know each other. The Storming State normally arrives directly after the formulation of a new team because there are still a lot of unknowns amongst the newly formed assembly. As a general rule most of the parties involved in the team are still getting used to the workload, pace of work, deadlines and the validity of various tasks that need to be performed by the group.  In this state everything is questioned because there are so many unknowns. Items commonly questioned include the credentials of others on the team, the actual validity of a project, and the leadership abilities of the team leader.  This can be exemplified by looking at the interactions between animals when they first meet.  If we look at a scenario where two people are walking directly toward each other with their dogs. The dogs will automatically enter the Storming State because they do not know the other dog. Typically in this situation, they attempt to define which is more dominating via play or fighting depending on how the dogs interact with each other. Once dominance has been defined and accepted by both dogs then they will either want to play or leave depending on how the dogs interacted and other environmental variables. Once the Storming State has been realized then the Normalizing State takes over. This state is entered by a team once all the questions of the Storming State have been answered and the team has been tested by a few tasks or projects.  Typically, participants in the team are filled with energy, and comradery, and a strong alliance with team goals and objectives.  A high school football team is a perfect example of the Normalizing State when they start their season.  The player positions have been assigned, the depth chart has been filled and everyone is focused on winning each game. All of the players encourage and expect each other to perform at the best of their abilities and are united by competition from other teams. The Performing State is achieved by a team when its history, working habits, and culture solidify the team as one working unit. In this state team members can anticipate specific behaviors, attitudes, reactions, and challenges are seen as opportunities and not problems. Additionally, each team member knows their role in the team’s success, and the roles of others. This is the most productive state of a group and is where all the time invested working together really pays off. If you look at an Olympic figure skating team skate you can easily see how the time spent working together benefits their performance. They skate as one unit even though it is comprised of two skaters. Each skater has their routine completely memorized as well as their partners. This allows them to anticipate each other’s moves on the ice makes their skating look effortless. The final state of a team is the Adjourning State. This state is where accomplishments by the team and each individual team member are recognized. Additionally, this state also allows for reflection of the interactions between team members, work accomplished and challenges that were faced. Finally, the team celebrates the challenges they have faced and overcome as a unit. Currently in the workplace teams are divided into two different types: Co-located and Distributed Teams. Co-located teams defined as the traditional group of people working together in an office, according to Andy Singleton of Assembla. This traditional type of a team has dominated business in the past due to inadequate technology, which forced workers to primarily interact with one another via face to face meetings.  Team meetings are primarily lead by the person with the highest status in the company. Having personally, participated in meetings of this type, usually a select few of the team members dominate the flow of communication which reduces the input of others in group discussions. Since discussions are dominated by a select few individuals the discussions and group discussion are skewed in favor of the individuals who communicate the most in meetings. In addition, Team members might not give their full opinions on a topic of discussion in part not to offend or create controversy amongst the team and can alter decision made in meetings towards those of the opinions of the dominating team members. Distributed teams are by definition spread across an area or subdivided into separate sections. That is exactly what distributed teams when compared to a more traditional team. It is common place for distributed teams to have team members across town, in the next state, across the country and even with the advances in technology over the last 20 year across the world. These teams allow for more diversity compared to the other type of teams because they allow for more flexibility regarding location. A team could consist of a 30 year old male Italian project manager from New York, a 50 year old female Hispanic from California and a collection of programmers from India because technology allows them to communicate as if they were standing next to one another.  In addition, distributed team members consult with more team members prior to making decisions compared to traditional teams, and take longer to come to decisions due to the changes in time zones and cultural events. However, team members feel more empowered to speak out when they do not agree with the team and to notify others of potential issues regarding the work that the team is doing. Virtual teams which are a subset of the distributed team type is changing organizational strategies due to the fact that a team can now in essence be working 24 hrs a day because of utilizing employees in various time zones and locations.  A primary example of this is with customer services departments, a company can have multiple call centers spread across multiple time zones allowing them to appear to be open 24 hours a day while all a employees work from 9AM to 5 PM every day. Virtual teams also allow human resources departments to go after the best talent for the company regardless of where the potential employee works because they will be a part of a virtual team all that is need is the proper technology to be setup to allow everyone to communicate. In addition to allowing employees to work from home, the company can save space and resources by not having to provide a desk for every team member. In fact, those team members that randomly come into the office can actually share one desk amongst multiple people. This is definitely a cost cutting plus given the current state of the economy. One thing that can turn a team into a high-performing team is leadership. High-performing team leaders need to focus on investing in ongoing personal development, provide team members with direction, structure, and resources needed to accomplish their work, make the right interventions at the right time, and help the team manage boundaries between the team and various external parties involved in the teams work. A team leader needs to invest in ongoing personal development in order to effectively manage their team. People have said that attitude is everything; this is very true about leaders and leadership. A team takes on the attitudes and behaviors of its leaders. This can potentially harm the team and the team’s output. Leaders must concentrate on self-awareness, and understanding their team’s group dynamics to fully understand how to lead them. In addition, always learning new leadership techniques from other effective leaders is also very beneficial. Providing team members with direction, structure, and resources that they need to accomplish their work collectively sounds easy, but it is not.  Leaders need to be able to effectively communicate with their team on how their work helps the company reach for its organizational vision. Conversely, the leader needs to allow his team to work autonomously within specific guidelines to turn the company’s vision into a reality.  This being said the team must be appropriately staffed according to the size of the team’s tasks and their complexity. These tasks should be clear, and be meaningful to the company’s objectives and allow for feedback to be exchanged with the leader and the team member and the leader and upper management. Now if the team is properly staffed, and has a clear and full understanding of what is to be done; the company also must supply the workers with the proper tools to achieve the tasks that they are asked to do. No one should be asked to dig a hole without being given a shovel.  Finally, leaders must reward their team members for accomplishments that they achieve. Awards could range from just a simple congratulatory email, a party to close the completion of a large project, or other monetary rewards. Managing boundaries is very important for team leaders because it can alter attitudes of team members and can add undue stress to the team which will force them to loose focus on the tasks at hand for the group. Team leaders should promote communication between team members so that burdens are shared amongst the team and solutions can be derived from hearing the opinions of multiple sources. This also reinforces team camaraderie and working as a unit. Team leaders must manage the type and timing of interventions as to not create an even bigger mess within the team. Poorly timed interventions can really deflate team members and make them question themselves. This could really increase further and undue interventions by the team leader. Typically, the best time for interventions is when the team is just starting to form so that all unproductive behaviors are removed from the team and that it can retain focus on its agenda. If an intervention is effectively executed the team will feel energized about the work that they are doing, promote communication and interaction amongst the group and improve moral overall. High-performing teams are very import to organizations because they consistently produce high quality output and develop a collective purpose for their work. This drive to succeed allows team members to utilize specific talents allowing for growth in these areas.  In addition, these team members usually take on a sense of ownership with their projects and feel that the other team members are irreplaceable. References: http://blog.assembla.com/assemblablog/tabid/12618/bid/3127/Three-ways-to-organize-your-team-co-located-outsourced-or-global.aspx Katzenbach, J.R. & Smith, D.K. (1993). The Wisdom of Teams: Creating the High-performance Organization. Boston: Harvard Business School.

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  • Cannot install Visual Editor Plugin on Eclipse

    - by lyuba
    I try to follow the instructions from here to install a Visual editor pulgin for Eclipse: http://wiki.eclipse.org/VE/Update Both online and offline installations fails with the following mistake: Cannot complete request. Generating details. Here is the complete log: Cannot complete the install because of a conflicting dependency. Software being installed: Java EMF Model 1.4.0.v20090826-1446-7H-FPbAcggQleH8hJifHfUd (org.eclipse.jem.feature.group 1.4.0.v20090826-1446-7H-FPbAcggQleH8hJifHfUd) Software currently installed: Eclipse IDE for Java EE Developers 1.2.2.20100217-2310 (epp.package.jee 1.2.2.20100217-2310) Only one of the following can be installed at once: Java EMF Model BeanInfo (Introspection) Support 2.0.300.v200905030615 (org.eclipse.jem.beaninfo 2.0.300.v200905030615) Java EMF Model BeanInfo (Introspection) Support 2.0.300.R3_1_maintenance (org.eclipse.jem.beaninfo 2.0.300.R3_1_maintenance) Cannot satisfy dependency: From: Eclipse IDE for Java EE Developers 1.2.2.20100217-2310 (epp.package.jee 1.2.2.20100217-2310) To: org.eclipse.epp.package.jee.feature.feature.group [1.2.2.20100217-2310] Cannot satisfy dependency: From: Java EE IDE Feature 1.2.2.20100217-2310 (org.eclipse.epp.package.jee.feature.feature.group 1.2.2.20100217-2310) To: org.eclipse.jst.web_ui.feature.feature.group 0.0.0 Cannot satisfy dependency: From: Java EMF Model 1.4.0.v20090826-1446-7H-FPbAcggQleH8hJifHfUd (org.eclipse.jem.feature.group 1.4.0.v20090826-1446-7H-FPbAcggQleH8hJifHfUd) To: org.eclipse.jem.beaninfo [2.0.300.R3_1_maintenance] Cannot satisfy dependency: From: JST Web Core 3.1.1.v200908121609-7S7CFyvFIhIehVidwyfk0m (org.eclipse.jst.web_core.feature.feature.group 3.1.1.v200908121609-7S7CFyvFIhIehVidwyfk0m) To: org.eclipse.jem.beaninfo [2.0.300.v200905030615] Cannot satisfy dependency: From: JST Web Core 3.1.1.v200908121609-7S7CG-dFIhIeq7kV6qxaLD (org.eclipse.jst.web_core.feature.feature.group 3.1.1.v200908121609-7S7CG-dFIhIeq7kV6qxaLD) To: org.eclipse.jem.beaninfo [2.0.300.v200905030615] Cannot satisfy dependency: From: JST Web UI 3.1.1.v200908121609-7E77FBfDlwYa_9sdy2q77doi14gl (org.eclipse.jst.web_ui.feature.feature.group 3.1.1.v200908121609-7E77FBfDlwYa_9sdy2q77doi14gl) To: org.eclipse.jst.web_core.feature.feature.group [3.1.1.v200908121609-7S7CFyvFIhIehVidwyfk0m] Cannot satisfy dependency: From: JST Web UI 3.1.1.v200908121609-7E77FBiDlwYcICNdz-5z-9PGqZCy (org.eclipse.jst.web_ui.feature.feature.group 3.1.1.v200908121609-7E77FBiDlwYcICNdz-5z-9PGqZCy) To: org.eclipse.jst.web_core.feature.feature.group [3.1.1.v200908121609-7S7CG-dFIhIeq7kV6qxaLD] Has anybody encountered something like this? Appreciate your ideas!

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  • XPath: Nodes that have a child node that have an attribute

    - by Jonathan Allen
    XML Fragment <component name='Stipulations'> <group name='NoStipulations' required='N'> <field name='StipulationType' required='N' /> <field name='StipulationValue' required='N' /> </group> </component> <component name='NestedParties3'> <group name='NoNested3PartyIDs' required='N'> <field name='Nested3PartyID' required='N' /> <field name='Nested3PartyIDSource' required='N' /> <field name='Nested3PartyRole' required='N' /> <group name='NoNested3PartySubIDs' required='N'> <field name='Nested3PartySubID' required='N' /> <field name='Nested3PartySubIDType' required='N' /> </group> </group> </component> <component name='UnderlyingStipulations'> <group name='NoUnderlyingStips' required='N'> <field name='UnderlyingStipType' required='N' /> <field name='UnderlyingStipValue' required='N' /> </group> </component> What I want is all "group" nodes which have a child node of type "field" and a name "StipulationType". This is what I've tried so far: dictionary.XPathSelectElements("group[field[@name='StipulationType']]") dictionary.XPathSelectElements("group[./field[@name='StipulationType']]")

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  • Django ManyToMany Membership errors making associations

    - by jmitchel3
    I'm trying to have a "member admin" in which they have hundreds of members in the group. These members can be in several groups. Admins can remove access for the member ideally in the view. I'm having trouble just creating the group. I used a ManytoManyField to get started. Ideally, the "member admin" would be able to either select existing Users OR it would be able to Add/Invite new ones via email address. Here's what I have: #views.py def membership(request): group = Group.objects.all().filter(user=request.user) GroupFormSet = modelformset_factory(Group, form=MembershipForm) if request.method == 'POST': formset = GroupFormSet(request.POST, request.FILES, queryset=group) if formset.is_valid(): formset.save(commit=False) for form in formset: form.instance.user = request.user formset.save() return render_to_response('formset.html', locals(), context_instance=RequestContext(request)) else: formset= GroupFormSet(queryset=group) return render_to_response('formset.html', locals(), context_instance=RequestContext(request)) #models.py class Group(models.Model): name = models.CharField(max_length=128) members = models.ManyToManyField(User, related_name='community_members', through='Membership') user = models.ForeignKey(User, related_name='community_creator', null=True) def __unicode__(self): return self.name class Membership(models.Model): member = models.ForeignKey(User, related_name='user_membership', blank=True, null=True) group = models.ForeignKey(Group, related_name='community_membership', blank=True, null=True) date_joined = models.DateField(auto_now=True, blank=True, null=True) class Meta: unique_together = ('member', 'group') Any ideas? Thank you for your help.

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  • Rails exit controller after rendering

    - by codysehl
    I have an action in my controller that I am having trouble with. This is my first rails app, so I'm not sure of the best practices surrounding rails. I have a model called Group and a few actions that go in it's controller. I have written a test that should cause the controller to render an error in JSON because of an invalid Group ID. Instead of rendering and exiting, it looks like the controller is rendering and continuing to execute. Test test 'should not remove group because of invalid group id' do post(:remove, {'group_id' => '3333'}) response = JSON.parse(@response.body) assert_response :success assert_equal 'Success', response['message'] end Controller action # Post remove # group_id def remove if((@group = Group.find_by_id(params[:group_id])) == nil) render :json => { :message => "group_id not found" } end @group.destroy if(!Group.exists?(@group)) render :json => { :message => "Success" } else render :json => { :errors => @group.errors.full_messages } end end In the controller, the first if statement executes: render :json => { :message => "group_id not found" } but @group.destroy is still being executed. This seems counter-intuitive to me, I would think that the render method should exit the controller. Why is the controller not exiting after render is called? The purpose of this block of code is to recover gracefully when no record can be found with the passed in ID. Is this the correct way of doing something like this?

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  • In a SQL GROUP BY query, what value is used for the non-aggregate columns?

    - by Queencity13
    Say I've got the following data back from a SQL query: Lastname Firstname Age Anderson Jane 28 Anderson Lisa 22 Anderson Jack 37 If I want to know the age of the oldest person with the last name Anderson, I can select MAX(Age) and GROUP BY Lastname. But I also want to know the first name of that oldest person. How can I make sure that, when the Firstname values are collapsed into one row by the GROUP BY, I get the Firstname value from the same row where I got the max age?

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  • Linq-to-SQL: How to perform a count on a sub-select

    - by Peter Bridger
    I'm still trying to get my head round how to use LINQ-to-SQL correctly, rather than just writing my own sprocs. In the code belong a userId is passed into the method, then LINQ uses this to get all rows from the GroupTable tables matching the userId. The primary key of the GroupUser table is GroupUserId, which is a foreign key in the Group table. /// <summary> /// Return summary details about the groups a user belongs to /// </summary> /// <param name="userId"></param> /// <returns></returns> public List<Group> GroupsForUser(int userId) { DataAccess.KINv2DataContext db = new DataAccess.KINv2DataContext(); List<Group> groups = new List<Group>(); groups = (from g in db.Groups join gu in db.GroupUsers on g.GroupId equals gu.GroupId where g.Active == true && gu.UserId == userId select new Group { Name = g.Name, CreatedOn = g.CreatedOn }).ToList<Group>(); return groups; } } This works fine, but I'd also like to return the total number of Users who are in a group and also the total number of Contacts that fall under ownership of the group. Pseudo code ahoy! /// <summary> /// Return summary details about the groups a user belongs to /// </summary> /// <param name="userId"></param> /// <returns></returns> public List<Group> GroupsForUser(int userId) { DataAccess.KINv2DataContext db = new DataAccess.KINv2DataContext(); List<Group> groups = new List<Group>(); groups = (from g in db.Groups join gu in db.GroupUsers on g.GroupId equals gu.GroupId where g.Active == true && gu.UserId == userId select new Group { Name = g.Name, CreatedOn = g.CreatedOn, // ### This is the SQL I would write to get the data I want ### MemberCount = ( SELECT COUNT(*) FROM GroupUser AS GU WHERE GU.GroupId = g.GroupId ), ContactCount = ( SELECT COUNT(*) FROM Contact AS C WHERE C.OwnerGroupId = g.GroupId ) // ### End of extra code ### }).ToList<Group>(); return groups; } }

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  • PowerPoint save group as picture creates asymmetric edge, how to fix?

    - by Se Norm
    I created tons of figures for my thesis in PowerPoint and now I realized that when I try to save the grouped items (= one figure) as a picture (EMF), it somehow asymmetrically adds a border on the left and the bottom. First one is original group, second is the same pasted as a picture. Original group: Pasted as a picture: Does anyone have an idea how to fix that for a huge number of figures? I think it only started happening when I used a page size of 1m x 1m in PowerPoint to be able to zoom in more for some figures. However, I cannot not simply change the page size now as it messes up font and object sizes. Also, copying it into a smaller page and then saving as EMF doesn't do the trick. Maybe it is not related to the page size after all. Cropping every figure individually would be a lot of work, so I hope there is a different solution. I found the origin of the problem: the text label in the left bottom corner of each image (0s, 8s, 16s). I still do not understand why it is happening though, since the text label does not expand over the edge of the image (it was aligned using the align left function). It would still be great if there was an easy way to fix this, especially as I want to keep the text where it is.

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  • Delphi: How to set the default project in a project group?

    - by Ian Boyd
    i have two projects in a project group: ProjectA ProjectB Whenever i open the ProjectGroup.bpg in Delphi, it always starts with the 2nd project as the active one: ProjectA ProjectB And every time i have to flip it to the the "real" project: ProjectA ProjectB How can i make ProjectA the default project that opens with the project group? ProjectGroup.bpg #------------------------------------------------------------------------------ VERSION = BWS.01 #------------------------------------------------------------------------------ !ifndef ROOT ROOT = $(MAKEDIR)\.. !endif #------------------------------------------------------------------------------ MAKE = $(ROOT)\bin\make.exe -$(MAKEFLAGS) -f$** DCC = $(ROOT)\bin\dcc32.exe $** BRCC = $(ROOT)\bin\brcc32.exe $** #------------------------------------------------------------------------------ PROJECTS = ProjectA.exe ProjectB.exe #------------------------------------------------------------------------------ default: $(PROJECTS) #------------------------------------------------------------------------------ ProjectA.exe: ProjectA.dpr $(DCC) ProjectB.exe: childfolder\ProjectB.dpr $(DCC)

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  • How to update a table using a select group by in a second one as the data source in MySQL?

    - by Jader Dias
    I can't do this in MySQL UPDATE tableA, tableB SET tableA.column1 = SUM(tableB.column2) WHERE tableA.column3 = tableB.column4 GROUP BY tableB.column4 ; Neither can I UPDATE tableA, ( SELECT SUM(tableB.column2) sumB, tableB.column4 FROM tableB GROUP BY tableB.column4 ) t1 SET tableA.column1 = sumB WHERE tableA.column3 = column4 ; Besides it being illegal code, I think you can understand what I tried to do with the queries above. Both of them had the same intent. How can I do that in MySQL?

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  • How to access items by "group" in an Outlook VB macro?

    - by Noah Yetter
    By "group" I mean the collapsible classifications that you get when you enable View-Arrange By-Show in Groups. This divides e.g. messages in a folder into Today, Yesterday, Last Week, Two Weeks Ago, and so on. What I'd like to be able to do is iterate over the messages that are currently classified within a given group. Is this possible?

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  • Help With LINQ: Mixed Joins and Specifying Default Values

    - by Corey O.
    I am trying to figure out how to do a mixed-join in LINQ with specific access to 2 LINQ objects. Here is an example of how the actual TSQL query might look: SELECT * FROM [User] AS [a] INNER JOIN [GroupUser] AS [b] ON [a].[UserID] = [b].[UserID] INNER JOIN [Group] AS [c] ON [b].[GroupID] = [c].[GroupID] LEFT JOIN [GroupEntries] AS [d] ON [a].[GroupID] = [d].[GroupID] WHERE [a].[UserID] = @UserID At the end, basically what I would like is an enumerable object full of GroupEntry objects. What am interested is the last two tables/objects in this query. I will be displaying Groups as a group header, and all of the Entries underneath their group heading. If there are no entries for a group, I still want to see that group as a header without any entries. Here's what I have so far: So from that I'd like to make a function: public void DisplayEntriesByUser(int user_id) { MyDataContext db = new MyDataContext(); IEnumberable<GroupEntries> entries = ( from user in db.Users where user.UserID == user_id join group_user in db.GroupUsers on user.UserID = group_user.UserID into a from join1 in a join group in db.Groups on join1.GroupID equals group.GroupID into b from join2 in b join entry in db.Entries.DefaultIfEmpty() on join2.GroupID equals entry.GroupID select entry ); Group last_group_id = 0; foreach(GroupEntry entry in entries) { if (last_group_id == 0 || entry.GroupID != last_group_id) { last_group_id = entry.GroupID; System.Console.WriteLine("---{0}---", entry.Group.GroupName.ToString().ToUpper()); } if (entry.EntryID) { System.Console.WriteLine(" {0}: {1}", entry.Title, entry.Text); } } } The example above does not work quite as expected. There are 2 problems that I have not been able to solve: I still seem to be getting an INNER JOIN instead of a LEFT JOIN on the last join. I am not getting any empty results, so groups without entries do not appear. I need to figure out a way so that I can fill in the default values for blank sets of entries. That is, if there is a group without an entry, I would like to have a mostly blank entry returned, except that I'd want the EntryID to be null or 0, the GroupID to be that of of the empty group that it represents, and I'd need a handle on the entry.Group object (i.e. it's parent, empty Group object). Any help on this would be greatly appreciated. Note: Table names and real-world representation were derived purely for this example, but their relations simplify what I'm trying to do.

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  • How to use Linq to select and group complex child object from a parents list.

    - by Daoming Yang
    How to use Linq to select and group complex child object from a parents list. I have an OrderList each of order object has a OrderProductVariantList(OrderLineList), and each of OrderProductVariant object has ProductVariant, and then the ProductVariant object will have a Product object which contains product information. My goal is to select and group the most popular products from the order list. Can anyone help me with this? Many thanks.

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  • Firefox url / link to a group of saved bookmarks?

    - by This_Is_Fun
    In Firefox you can easily save a group of tabs together. When (re-)accessing this group, the 'cascading' bookmark menu shows each individual bookmark (and under a line) it says "open all in tabs" I'm looking for a way to launch those tabs without going up through the bookmark menu. Possible options: A) Record a simple macro w/ any number of "superuser" utilities* ('A' is not the preferred option, since many 'little-macros' are hard to keep track of) b) Use Autohotkey (similar to option 'A' and more flexible once you learn the basics) c) How does Firefox load all those tabs? The info must be stored somewhere (as a type of URL??) Quick Summary: The moment I click on "open all in tabs", I am clicking on something very similar to a hyper-link. How do I find the content (exact code) of that 'hyper-link', and / or "How do I easily launch the tabs?" .. . New EDIT #1: I'm looking for a way to launch those tabs without going up through the bookmark menu, or cluttering the bookmarks toolbar which I hide anyway :o) .. . New EDIT #2: I tried to keep the question simple and not mentioning Autohotkey programming. The objective is to launch all tabs using a button on an AHK gui. When grawity said, "It's just an ordinary folder containing ordinary bookmarks," he (she) reminds me I can easily find the folder / Now how to launch to urls inside that folder? .. FYI: (Basic-level) AHK works like this: ; Open one folder ButtonWinMerge_Files: Run, C:\Program Files\WinMerge\ Return .. ; Use default web browser for one link ButtonGoogle: Run, http://google.com Return .. . Question still open: The moment I click on "open all in tabs", I am clicking on something very similar to a hyper-link. "How to 'replicate' the way Firefox launches the tabs with one click?"

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  • Cakephp beforeFind() - How do I add a JOIN condition AFTER the belongsTo association is added?

    - by michael
    I'm in Model-beforeFind($queryData), trying to add a JOIN condition to the queryData on a model which has belongsTo associations. Unfortunately, the new JOIN references a table in the belongsTo association, so it must appear AFTER the belongsTo in the query. Here is my Tagged-belongsTo association: app\plugins\tags\models\tagged.php (line 192) Array ( [Tag] => Array ( [className] => Tag [foreignKey] => tag_id [conditions] => [fields] => [order] => [counterCache] => ) [Group] => Array ( [className] => Group [foreignKey] => foreign_key [conditions] => Array ( [Tagged.model] => Group ) [fields] => [order] => [counterCache] => ) ) Here is the JOIN added in Tagged-beforeFind(), notice that the belongsTo joins have not yet been added: app\plugins\tags\models\tagged.php (line 194) Array ( [conditions] => Array ( [Tag.keyname] => europe ) [fields] => Array ( [0] => DISTINCT Group.* [1] => GroupPermission.* ) [joins] => Array ( [0] => Array ( [table] => permissions [alias] => GroupPermission [foreignKey] => [type] => INNER [conditions] => Array ( [GroupPermission.model] => Group [0] => GroupPermission.foreignId = Group.id [or] => Array ( ... ) ) ) ) [limit] => [offset] => [order] => Array ( [0] => ) [page] => 1 [group] => [callbacks] => 1 [by] => europe [model] => Group ) When I check the output, it fails with "1054: Unknown column 'Group.id' in 'on clause'" because the Permissions join appeared BEFORE the Groups join. SELECT DISTINCT `Group`.*, `GroupPermission`.* FROM `tagged` AS `Tagged` INNER JOIN permissions AS `GroupPermission` ON (`GroupPermission`.`model` = 'Group' AND `GroupPermission`.`foreignId` = `Group`.`id` AND (...)) LEFT JOIN `tags` AS `Tag` ON (`Tagged`.`tag_id` = `Tag`.`id`) LEFT JOIN `groups` AS `Group` ON (`Tagged`.`foreign_key` = `Group`.`id` AND `Tagged`.`model` = 'Group') WHERE `Tag`.`keyname` = 'europe' But this SQL (with Permissions joined moved to the end) works fine: SELECT DISTINCT `Group`.*, `GroupPermission`.* FROM `tagged` AS `Tagged` LEFT JOIN `tags` AS `Tag` ON (`Tagged`.`tag_id` = `Tag`.`id`) LEFT JOIN `groups` AS `Group` ON (`Tagged`.`foreign_key` = `Group`.`id` AND `Tagged`.`model` = 'Group') INNER JOIN permissions AS `GroupPermission` ON (`GroupPermission`.`model` = 'Group' AND `GroupPermission`.`foreignId` = `Group`.`id` AND (...)) WHERE `Tag`.`keyname` = 'europe' How do I add my join in beforeFind() after the belongsTo join?

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  • How to update a table using a select group by in a second one and itself as the data source in MySQL

    - by Jader Dias
    I can do this: SELECT t2.value + sum(t3.value) FROM tableA t2, tableB t3 WHERE t2.somekey = t3.somekey GROUP BY t3.somekey But how to do this? UPDATE tableA t1 SET speed = ( SELECT t2.value + sum(t3.value) FROM tableA t2, tableB t3 WHERE t2.somekey = t3.somekey AND t1.somekey = t3.somekey GROUP BY t3.somekey ) ; MySQL says it's illegal since you can't specify target table t1 for update in FROM clause.

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  • Jquery Content Cycle Next/Previous not working

    - by user340745
    I have a definition list with a lot of text inside of it. When a user comes to the page, I want the jQuery to hide two thirds of that content, add a next and previous button where appropriate, and fade the content in and out. The first third of the content is .issue-group-1, the second third is .issue-group-3, the third, .issue-group-3. I am trying to set it so that when the user hits the next button, the next button changes classes, and thus acts differently the next time the user clicks it (that is, it takes them to the third page instead of the second. Right now, the next/previous buttons are working on the first and second "pages" but the next button to the third page won't work. My code is probably too long and this is maybe not the best way to do it--I'm new to jquery. Any suggestions would be helpful. $(document).ready(function(){ $('.issue-group-2, .issue-group-3').hide(); $('a#next-button.page1').fadeIn(500); $('a#next-button.page1').click(function() { $(this).removeClass('page1').addClass('page2'); $('.issue-group-1').fadeOut(500, function() { $('.issue-group-2').fadeIn(500); }); $('a#previous-button').fadeIn(500); }); $('a#previous-button.page2').click(function() { $('#next-button.page2').removeClass('page2').addClass('page1'); $('.issue-group-2').fadeOut(500, function() { $('.issue-group-1').fadeIn(500); }); $('a#previous-button').fadeOut(500); }); $('a#next-button.page2').click(function() { $('a#previous-button').removeClass('page2').addClass('page3'); $('.issue-group-2').fadeOut(500, function() { $('.issue-group-3').fadeIn(500); }); $('a#next-button').fadeOut(500); }); $('a#previous-button.page3').click(function() { $(this).removeClass('page3').addClass('page2'); $('.issue-group-2').fadeOut(500, function() { $('.issue-group-2').fadeIn(500); }); $('a#next-button').fadeIn(500); }); });

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  • How do I remove &#13 ; from my text file using VBScript Replace() or a regex?

    - by Eric Lachance
    Hi! I'm doing a conversion between two software which both use XML so the actual conversion part is fairly straightforward - adding text here, removing others here, converting a few information. I'm using VBSCript WSH. The only issue I'm still having is the darn &#13; character - that's my problem! I've tried both strText = Replace(strText, "&#13;", "") and using a regex with Regex.pattern = "&#13;" ... neither works. I also tried replacing char(13), VBCR... nothing seems to detect the actual string itself and not the character it's creating. Can anyone help me?

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