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  • Remove the Parent tag in xml using php

    - by Wasim
    I am facing a problem in editing a xml file. <?xml version="1.0" encoding="UTF-8"?> <urlset> <url> <loc>http://www.abc.com/</loc> <lastmod>2010-04-17T17:23:57+00:00</lastmod> <changefreq>daily</changefreq> <priority>0.50</priority> </url> <url> <loc>http://www.abc.com/</loc> <lastmod>2010-04-17T17:23:57+00:00</lastmod> <changefreq>daily</changefreq> <priority>0.50</priority> </url> </urlset> I want to add one more set of records starting with <url> with its other tags, (i.e) "loc,lastmod,changefreq,priority" and than save the xml file.For adding the new record i need to remove the parent closing tag that is </urlset> and than add the rest of the records and close the main tag. Can anyone please help me solving my problem.Thanks

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  • php script redirecting code problem

    - by tibin mathew
    hi, i'm using a php script for redirection after detecting the search word to my websiter from the search engines . and my redirection code is working fine but for some keywods i wat to stay in the same page. for that lines of code i'm getting a warning message in that pages. Warning: headers already sent (output started at /home/friendsj/public_html/index.php:2) in /home/friendsj/public_html/index.php on line 20 below is the code i used in that pages $ref=$_SERVER['HTTP_REFERER']; if(strstr($ref,"test")) { $url="http://www.howtomark.com/robgoyette.html"; } elseif(strstr($ref,"mu+word+gmail")) { $url="http://www.howtomark.com/marketbetter.html"; } else { if(strstr($ref,"how+to+market+better")) { } } if($url !="") { header("Location:$url"); }

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  • getting web page data as json object?

    - by encryptor
    I have a url, the data of which page i need as a json object. I ve tried xmlhttprequest and ajaxobject both but doesnt work. It doesnt even give a responseText when I give it as an alert Ill post both the code snippets here. url = http://mydomain.com:port/a/b/c AJAX : var ajaxRequest = new ajaxObject(URL); ajaxRequest.callback = function (responseText,responseStatus) { alert(responseStatus); JSONData = responseText.parseJSON(); processData(JSONData); } USING xmlhttprequest: var client = new XMLHttpRequest(); client.open('GET',URL,true ); data = JSON.parse(client.responseText); alert(data.links.length); can someone please help me out with this. I understand cross scripting may be an issue, but how to come over it? and shouldn't then too it should give the alerts as zero or null

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  • Not able to get data from Json completely

    - by Abhinav Raja
    i am getting JSON data from http://abinet.org/?json=1 and displaying the titles in a ListView. the code is working fine but the problem is, it is skipping few titles in my ListView and one title is being repeated. You can see the json data from url given above by copy paste it in JSON editor online http://www.jsoneditoronline.org/ i want titles in the "posts" array to be displayed in ListView, however it is being displayed like this: if you see the JSON data from the link above, its missing like 3 titles (they should come between the first and second title) and 5th title is being repeated. Dont know why this is happening. What minor adjustments i need to do? Please help me. this is my code : public class MainActivity extends Activity { // URL to get contacts JSON private static String url = "http://abinet.org/?json=1"; // JSON Node names private static final String TAG_POSTS = "posts"; static final String TAG_TITLE = "title"; private ProgressDialog pDialog; JSONArray contacts = null; TextView img_url; ArrayList<HashMap<String, Object>> contactList; ListView lv; LazyAdapter adapter; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); lv = (ListView) findViewById(R.id.newslist); contactList = new ArrayList<HashMap<String, Object>>(); new GetContacts().execute(); } private class GetContacts extends AsyncTask<Void, Void, Void> { protected void onPreExecute() { super.onPreExecute(); // Showing progress dialog pDialog = new ProgressDialog(MainActivity.this); pDialog.setMessage("Please wait..."); pDialog.setCancelable(false); pDialog.show(); } protected Void doInBackground(Void... arg0) { // Making a request to url and getting response JSONParser jParser = new JSONParser(); // Getting JSON from URL JSONObject jsonObj = jParser.getJSONFromUrl(url); // if (jsonStr != null) { try { // Getting JSON Array node contacts = jsonObj.getJSONArray(TAG_POSTS); // looping through All Contacts for (int i = 0; i < contacts.length(); i++) { // JSONObject c = contacts.getJSONObject(i); JSONObject posts = contacts.getJSONObject(i); String title = posts.getString(TAG_TITLE).replace("&#8217;", "'"); JSONArray attachment = posts.getJSONArray("attachments"); for (int j = 0; j< attachment.length(); j++){ JSONObject obj = attachment.getJSONObject(j); JSONObject image = obj.getJSONObject("images"); JSONObject image_small = image.getJSONObject("thumbnail"); String imgurl = image_small.getString("url"); HashMap<String, Object> contact = new HashMap<String, Object>(); contact.put("image_url", imgurl); contact.put(TAG_TITLE, title); contactList.add(contact); } } } catch (JSONException e) { e.printStackTrace(); } return null; } @Override protected void onPostExecute(Void result) { super.onPostExecute(result); // Dismiss the progress dialog if (pDialog.isShowing()) pDialog.dismiss(); adapter=new LazyAdapter(MainActivity.this, contactList); lv.setAdapter(adapter); } } } this is my JsonParser class (although its not required): public JSONParser() { } public JSONObject getJSONFromUrl(String url) { // Making HTTP request try { // defaultHttpClient DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); is = httpEntity.getContent(); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } try { BufferedReader reader = new BufferedReader(new InputStreamReader( is, "iso-8859-1"), 8); StringBuilder sb = new StringBuilder(); String line = null; while ((line = reader.readLine()) != null) { sb.append(line + "n"); } is.close(); json = sb.toString(); } catch (Exception e) { Log.e("Buffer Error", "Error converting result " + e.toString()); } // try parse the string to a JSON object try { jObj = new JSONObject(json); } catch (JSONException e) { Log.e("JSON Parser", "Error parsing data " + e.toString()); } // return JSON String return jObj; } } and this is adapter class: public class LazyAdapter extends BaseAdapter { private Activity activity; private ArrayList<HashMap<String, Object>> data; private static LayoutInflater inflater=null; public LazyAdapter(Activity a,ArrayList<HashMap<String, Object>> d) { activity = a; data=d; inflater = (LayoutInflater)activity.getSystemService(Context.LAYOUT_INFLATER_SERVICE); } public int getCount() { return data.size(); } public Object getItem(int position) { return position; } public long getItemId(int position) { return position; } public View getView(int position, View convertView, ViewGroup parent) { View vi=convertView; if(convertView==null) vi = inflater.inflate(R.layout.third_row, null); TextView title = (TextView)vi.findViewById(R.id.headline3); // title SmartImageView iv = (SmartImageView) vi.findViewById(R.id.imageicon); HashMap<String, Object> song = new HashMap<String, Object>(); song = data.get(position); // Setting all values in listview title.setText((CharSequence) song.get(MainActivity.TAG_TITLE)); iv.setImageUrl((String) song.get("image_url")); thumb_image); return vi; } } Please help me. I am stuck at this for more than a week now. I think there is just something to be changed in my MainActivity class.

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  • Requirements for connecting to Oracle with JDBC?

    - by Lord Torgamus
    I'm a newbie to Java-related web development, and I can't seem to get a simple program with JDBC working. I'm using off-the-shelf Oracle 10g XE and the Eclipse EE IDE. From the books and web pages I've checked so far, I've narrowed the problem down to either an incorrectly written database URL or a missing JAR file. I'm getting the following error: java.sql.SQLException: No suitable driver found for jdbc:oracle://127.0.0.1:8080 with the following code: import java.sql.*; public class DatabaseTestOne { public static void main(String[] args) { String url = "jdbc:oracle://127.0.0.1:8080"; String username = "HR"; String password = "samplepass"; String sql = "SELECT EMPLOYEE_ID FROM EMPLOYEES WHERE LAST_NAME='King'"; Connection connection; try { connection = DriverManager.getConnection(url, username, password); Statement statement = connection.createStatement(); System.out.println(statement.execute(sql)); connection.close(); } catch (SQLException e) { System.err.println(e); } } } What is the proper format for a database URL, anyways? They're mentioned a lot but I haven't been able to find a description. Thanks! EDIT (the answer): Based on duffymo's answer, I got ojdbc14.jar from http://www.oracle.com/technology/software/tech/java/sqlj_jdbc/htdocs/jdbc_10201.html and dropped it in the Eclipse project's Referenced Libraries. Then I changed the start of the code to ... try { Class.forName("oracle.jdbc.driver.OracleDriver"); } catch (ClassNotFoundException e) { System.err.println(e); } // jdbc:oracle:thin:@<hostname>:<port>:<sid> String url = "jdbc:oracle:thin:@GalacticAC:1521:xe"; ... and it worked.

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  • Using URI-fragments in Ruby on rails routing

    - by Alexei
    RoR application can generate URL such as /post/10. But now I want to create a site, which works with URI-fragments like gmail. For example gmail uses the following URLs https://mail.google.com/mail/?shva=1#sent https://mail.google.com/mail/?shva=1#label/books I need to generate URL such as /#/post/10, where controller = "post", action = "show", id = "10". Of course it will be good to use standard url-helpers.

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  • how to manage the use of both $_SERVER['PHP_SELF'] in action of form and htaccess for urlrewriting t

    - by OM The Eternity
    how to manage the use of both $_SERVER['PHP_SELF'] in action of form and htaccess for url-rewriting? If I submit a form and in the action attribute of it i pass "$_SERVER['PHP_SELF']" and at the same time i am using url rewriting for the same page.. then these two things will contradict each other resulting in the display of action value of form in address bar.. so how can i manage this to get the url rewrited form of $_SERVER['PHP_SELF']? here the rewrite rule is to change the name of url file likewise as if form is submitted to any file say direction.php then rewrite will change it to something 30/redirect.html

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  • Flash file playing FLV and relative paths

    - by MartinHN
    Hi Say you have a SWF file with an FLV player that you want to embed on any site. A scenario could look like this: Url of the page embedding the SWF: www.example.com Url to the SWF: www.swf-domain.com/player.swf Url to the FLV: www.swf-domain.com/movie.flv Is there any possible way, that you can refer to the FLV from within the SWF using a relative path?

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  • Applescript, how to get network address of a file

    - by CRP
    We are a network of Mac computers. I would like to send email addresses to colleagues with links to files on network locations. I made the following applescript: tell application "Finder" set uuu to URL of the first item of (get the selection) set the clipboard to uuu end tell which puts the URL of the currently selected file into the clipboard, which can then be pasted into the message (using the Add Link menu item), providing, for example: file://localhost/Volumes/Commerciale/Clienti/ unfortunately these links do not work. If I select Go To Folder from the menu item, I can get to the folder using an afp:// type url. Is there any way to get this via applescript like I do with url above? Thanks

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  • how to display a image in java application

    - by Nubkadiya
    i want to display a image in my java application. i found a code to download the image from the webserver. what that code do is it takes the image and show it in the jframe. i want to use a label to show the image or soemthing else. so i can put it in my java application. can someone help me. it shouldnt be JFrame please help me here is my code Image image = null; try { URL url = new URL("http://www.personal.psu.edu/acr117/blogs/audrey/images/image-2.jpg"); image = ImageIO.read(url); } catch (IOException e) { } // Use a label to display the image JFrame frame = new JFrame(); JLabel lblimage = new JLabel(new ImageIcon(image)); frame.getContentPane().add(lblimage, BorderLayout.CENTER); frame.setSize(300, 400); frame.setVisible(true); } can someone help me

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  • Counting HTML images with Python

    - by user2537246
    I need some feedback on how to count HTML images with Python 3.01 after extracting them, maybe my regular expression are used properly. Here is my code: import re, os import urllib.request def get_image(url): url = 'http://www.google.com' total = 0 try: f = urllib.request.urlopen(url) for line in f.readline(): line = re.compile('<img.*?src="(.*?)">') if total > 0: x = line.count(total) total += x print('Images total:', total) except: pass

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  • VB.NET 2.0 - StackOverflowException when using Thread Safe calls to Windows Forms Controls

    - by LamdaComplex
    I have a Windows Forms app that, unfortunately, must make calls to controls from a second thread. I've been using the thread-safe pattern described on the http://msdn.microsoft.com/en-us/library/ms171728.aspx. Which has worked great in the past. The specific problem I am having now: I have a WebBrowser control and I'm attempting to invoke the WebBrowser.Navigate() method using this Thread-Safe pattern and as a result I am getting StackOverflow exceptions. Here is the Thread-Safe Navigate method I've written. Private Delegate Sub NavigateControlCallback(ByRef wb As WebBrowser, ByVal url As String) Private Sub AsyncNavigate(ByRef wb As WebBrowser, ByVal URL As String) Try If wb.InvokeRequired Then Dim callback As New NavigateControlCallback(AddressOf AsyncNavigate) callback(wb, url) Else wb.Navigate(url) End If Catch ex As Exception End Try End Sub Is there a Thread-Safe way to interact with WinForms components without the side effect of these StackOverflowExceptions?

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  • PHP RegExpr error Unkown modifier '('

    - by Anonymous
    I have this regular expression: ([http://some.url.com/index.php?showtopic=\"]*)([0-9]+(?:\.[0-9]*)?) its for extracting links to topics from forum Now when i use it in my script $url = "([http://some.url.com/index.php?showtopic=\"]*)([0-9]+(?:\.[0-9]*)?)"; preg_match_all spits: "Unknown modifier '('" Can anyone help me with this obviously stupid problem

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  • PHP + CURL How to get file name

    - by Gunjan
    I'm trying to download users profile picture from facebook in PHP using this function public static function downloadFile($url, $options = array()) { if (!is_array($options)) $options = array(); $options = array_merge(array( 'connectionTimeout' => 5, // seconds 'timeout' => 10, // seconds 'sslVerifyPeer' => false, 'followLocation' => true, // if true, limit recursive redirection by 'maxRedirs' => 2, // setting value for "maxRedirs" ), $options); // create a temporary file (we are assuming that we can write to the system's temporary directory) $tempFileName = tempnam(sys_get_temp_dir(), ''); $fh = fopen($tempFileName, 'w'); $curl = curl_init($url); curl_setopt($curl, CURLOPT_FILE, $fh); curl_setopt($curl, CURLOPT_CONNECTTIMEOUT, $options['connectionTimeout']); curl_setopt($curl, CURLOPT_TIMEOUT, $options['timeout']); curl_setopt($curl, CURLOPT_HEADER, false); curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, $options['sslVerifyPeer']); curl_setopt($curl, CURLOPT_FOLLOWLOCATION, $options['followLocation']); curl_setopt($curl, CURLOPT_MAXREDIRS, $options['maxRedirs']); curl_exec($curl); curl_close($curl); fclose($fh); return $tempFileName; } The problem is it saves the file in the /tmp directory with a random name and without the extension. How can I get the original name of the file (I'm more interested in the original extension) The important things here are: The url actually redirects to image so i cant get it from original url the final url does not have the file name in headers

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  • twitter basic authorisation not working?

    - by Bunny Rabbit
    URL url = new URL("http://twitter.com/statuses/update.xml"); HttpURLConnection conn = (HttpURLConnection) url.openConnection(); conn.setDoOutput(true); String cridentials = new sun.misc.BASE64Encoder().encode((username + ":" + password).getBytes()); conn.setRequestProperty ("Authorization", "Basic " + cridentials); OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream()); wr.write(status); wr.flush(); wr.close(); why the above code for updating twitter status is not working ? i am running it on google app engine.

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  • about friendfeed search parameter.

    - by user285020
    has anyone find out why FriendFeed advanced search result url doesn't have not search field parameter? some example: contains the words field, when you inputs a text "ok" and push search, then response url is http://friendfeed.com/search?q=ok if you also inputs a text into words in the title field, like texts "I'm", response url is http://friendfeed.com/search?q=ok+intitle%3Ai%27m well, pretty beautiful. not like other site response all field even you don't push a text into. anyone know how to make this effect?

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  • jQuery Dialog form serialize reposting incorrect data on subsequent uses

    - by Ben Dauphinee
    I'm working with forms inside jQuery Dialog, and am having some issues with the data it's posting. First load and save works fine, posts the correct data. Until I refresh the page though, every subsequent load seems to work, as in the correct data is in the form, however, when saved, the data from the first load is what is posted every time. function formdialog(url, tack, divid, scriptload){ $.getJSON(url+tack+"/form", function(data){ var formwin = '<div><form id="formdialog">'+data['form']+'</form></div>'; var dialog = $(formwin).dialog({ title: data['title'], autoOpen: false, modal: true, buttons: { "Save": function(){ $.post(url+tack+"/process", $("#formdialog").serialize(), function(data){ alert($("#formdialog").serialize()); $(this).dialog('close'); $(this).remove(); } ); }, "Cancel": function(){$(this).dialog('close'); $(this).remove();} } }); dialog.dialog("open"); }); } $(function(){ $("a.edlnk").click(function(){ var url = $(this).attr("href"); formdialog(CONFIG_HREF_SITE+"ajax/"+appControl, "/"+url, divid); return false; }); });

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  • .htaccess, two consecutive rewrites?

    - by Matthew Haworth
    I need to take a url, "/ServiceSearch/r.php?n=blahblah", and have it go to "/search/blahblah/" so that it appears in the browser as "/search/blahblah", but I actually want it to REALLY be going to "r.php?n=ServiceSearch&n=blahblah".. So I was thinking I'll need to rewrite the first URL to "/ServiceSearch/r.php?n=blahblah" and then the second url, "/search/blahblah/", to the third, "r.php?n=ServiceSearch&n=blahblah". Well, I know this is wrong, but it's my best guess. I'm really struggling with it.

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  • Plone, behaviour of URLs

    - by jpet
    The situation is the following: I created a site with Plone, developed, used, but behind a test URL. Now it has to be published, but the test URL is not appropriate and I don't want to move the site. I think, if I use a redirect, it won't be appear in the URL-bar, only in the case of site start page. Am I wrong? (The test URL should not be used, because it will be a "semi-official" site.) What do you suggest to do? As far as I can see Plone uses absolute URLs everywhere. I can add relative URLs, but if I create a new page, a new event, etc., then they have absolute URLs on other automatically generated inner pages. Is there any way to convert these URLs to relative paths? Is there any setting possibilty where only a checkbox changes this default setting?

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  • Ie7 float problems and hiperlinks not clickable

    - by Uffo
    Markup <ul class="navigation clearfix"> <li class="navigation-top"></li> <div class="first-holder" style="height:153px;"> <dl class="hold-items clearfix"> <dd class="clearfix with"><a href="http://site.com" title="Protokoll">Protokoll</a></dd> <dd class="with-hover"><a href="http://site.com" title="Mein/e Unternehmen">Mein/e Unternehmen</a></dd> <dd class="with"><a class="face-me" href="http://site.com" title="Erweiterte Suche">Erweiterte Suche</a></dd> <dd class="with"><a href="http://site.com" title="Abmelden">Abmelden</a></dd> </dl> </div><!--[end] /.first-holder--> <li class="navigation-bottom"></li> </ul><!--[end] /.navigation--> Css: .first-holder{height:304px;position:relative;width:178px;overflow:hidden;margin-bottom:0px;padding-bottom: 0px;} .hold-items{top:0px;position:absolute;} .navigation dd.with{line-height:38px;background:url('/images/sprite.png') no-repeat -334px -46px;width:162px;height:38px;padding-bottom:0px;overflow: hidden;} .navigation dd.with a{position:relative;outline:0;display:block;font-weight:bold;color:#3f78c0;padding-left:10px;line-height:38px;} .with-hover{background:url('/images/sprite.png') no-repeat -505px -47px;width:178px;height:38px;line-height:38px;overflow:none;} .with-hover a{position:relative;display:block;font-weight:bold;color:#fff;padding-left:10px} .navigation-top{background:url('/images/sprite.png') no-repeat -694px -46px;width:160px;height:36px;} .navigation-top a{display:block;outline:0;height:20px;padding-top:18px;padding-left:138px;} .navigation-top a span{display:block;background:url('/images/sprite.png') no-repeat -212px -65px;width:8px;height:6px;} .navigation-bottom{background:url('/images/sprite.png') no-repeat -784px -402px;width:160px;height:37px;} .navigation-bottom a{display:block;outline:0;height:20px;padding-top:18px;padding-left:138px;} .navigation-bottom a span{display:block;background:url('/images/sprite.png') no-repeat -212px -74px;width:8px;height:6px;} Also the links, are not clickable, if I click on a link in IE7 it doesn't do the action..it doesn't redirect me to the location. This is how it looks in IE7: http://screencast.com/t/MGY4NjljZjc This is how it look in IE8,Firefox,Chrome and so on http://screencast.com/t/MzhhMDQ1M What I'm doing wrong PS: .navigation-top a span and .navigation-bottom a span I'm using some where else, but that it's ok it works fine.

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  • a + sing in email address

    - by d.andreykiv
    Hi. I need to submit an email address with a "+" sign and validate in on server. But server receives email like "[email protected]" as "aaa [email protected]". I send all data as POST request with following code NSURL* url = [NSURL URLWithString:[NSString stringWithFormat:@"%@%@", url, @"/signUp"]]; NSString *post = [NSString stringWithFormat:@"&email=%@&userName=%@&password=%@", user.email, user.userName, user.password]; NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:NO]; NSData* data = [self sendRequest:url postData:postData]; post variable before encoding has value &[email protected]&userName=Asdfasdfadsfadsf&password=sdfasdf after encoding it is same &[email protected]&userName=Asdfasdfadsfadsf&password=sdfasdf Method I use to send request looks like following code: -(id) sendRequest:(NSURL*) url postData:(NSData*)postData { // Create request NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init]; NSString *postLength = [NSString stringWithFormat:@"%d",[postData length]]; [request setURL:url]; [request setHTTPMethod:@"POST"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Current-Type"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setHTTPBody:postData]; NSURLResponse *urlResponse; NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&urlResponse error:nil]; [request release]; return data; }

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  • Using java class HttpsURLConnection

    - by KB22
    Hi all, I have a small piece of code which basically impements a HTTP-Client, i.e. it POSTS request and works with re RESPONSE. As long as HTTP is concenerned everthing work well. For some reason I now have to support HTTPS too. So here is briefly what I do in order to get a connection opened: URL url = new URL(serverAddress); HttpsURLConnection httpsConn = (HttpsURLConnection) url.openConnection(); This fails, stating: sun.net.www.protocol.https.HttpsURLConnectionImpl cannot be cast to com.sun.net.ssl.HttpsURLConnection I guess this is kinda trivial, but I just don't get what I'm doing wrong in this one... Googled it, and the code just looks right - not? any ideas are appreciated! thanks, K

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  • will_paginate and facebook/facebooker

    - by fenec
    I'm using will_paginate in a facebook application and when i click on the next button or a page number i get the url below. This is fine if everyone was using safari, but it breaks on ie and ff. That and people can't copy and paste the url to others. Anyone have any ideas how to fix this. http://apps.facebook.com/application/users/4785/votes.fbml?_method=GE... URL TOO BIG

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  • Why is parsing a jSON response to a jQUERY ajax request not working

    - by Ankur
    I know there are several similar questions on SO, I have used some of them to get this far. I am trying to list a set of urls that match my input values. I have a servlet which takes some input e.g. "aus" in the example below and returns some output using out.print() e.g. the two urls I have shown below. EXAMPLE Input: "aus" Output: [{"url":"http://dbpedia.org/resource/Stifel_Nicolaus"},{"url":"http://sempedia.org/ontology/object/Australia"}] Which is exactly what I want. I have seen that firebug doesn't seem to have anything in the response section despite having called out.print(jsonString); and it seems that out.print(jsonString); is working as expected which suggests that the variable 'jsonString' contains the expected values. However I am not exactly sure what is wrong. -------- The jQuery --------- $(document).ready(function() { $("#input").keyup(function() { var input = $("#input").val(); //$("#output").html(input); ajaxCall(input); }); }); function ajaxCall(input) { // alert(input); $.ajax({ url: "InstantSearchServlet", data: "property="+input, beforeSend: function(x) { if(x && x.overrideMimeType) { x.overrideMimeType("application/j-son;charset=UTF-8"); } }, dataType: "json", success: function(data) { for (var i = 0, len = datalength; i < len; ++i) { var urlData = data[i]; $("#output").html(urlData.url); } } }); } ------ The Servlet that calls the DAO class - and returns the results ------- public class InstantSearchServlet extends HttpServlet{ private static final long serialVersionUID = 1L; public void doGet(HttpServletRequest request, HttpServletResponse response) throws IOException, ServletException { System.out.println("You called?"); response.setContentType("application/json"); PrintWriter out = response.getWriter(); InstantSearch is = new InstantSearch(); String input = (String)request.getParameter("property"); System.out.println(input); try { ArrayList<String> urllist; urllist = is.getUrls(input); String jsonString = convertToJSON(urllist); out.print(jsonString); System.out.println(jsonString); } catch (SQLException e) { // TODO Auto-generated catch block e.printStackTrace(); } } private String convertToJSON(ArrayList<String> urllist) { Iterator<String> itr = urllist.iterator(); JSONArray jArray = new JSONArray(); int i = 0; while (itr.hasNext()) { i++; JSONObject json = new JSONObject(); String url = itr.next(); try { json.put("url",url); } catch (JSONException e) { // TODO Auto-generated catch block e.printStackTrace(); } jArray.put(json); } String results = jArray.toString(); return results; } }

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