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  • PHP radio button check if null

    - by Dallox
    So in class we get this school task where we need to check if one of the fields in unfilled and display an error. No we did this but for some strange reason it doesnt display a error when a radio button is unchecked. (textfield null check works fine) I've tried with a friend many possabilities but they all doesnt seem to work. We have been stuck at this task for 2 hours. Now we have tried making seperate if's but that doesnt seem to work too. These are the important parts: <p> <input type="hidden" name="taal" value="false"> Choose a language <input type="radio" name="taal" value="N"> Dutch <input type="radio" name="taal" value="E"> English <input type="radio" name="taal" value="S"> Spanish if (@$_POST['taal'] == null){ echo "No Language gotten"; return; }

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  • Make form redirect users after posting

    - by Liso22
    I need to change a form so that instead of reloading the page after submitting it, it redirects the user to another page, this is the form: <form class="questionform" name="questionform-0" id="questionform-0"> <textarea class="question-box" cols="12" rows="5" id="question-box-' . $questionformid . '" name="title" type="text" maxlength="200" size="28"></textarea> <input type="text" class="ubicacion" value="" name="question"> <input type="button" name="ask" value="Publicar" onclick="askquestion('questionform-0'); window.location.reload(true);"> I want to remove the window.location.reload and change it for a redirect that sends users to the page their comment will appear. Which is: www.chusmix.com/s?= (the content of the second field) The problem is that the content of the second field is part of the url I want to redirect, it's not simply always the same URL. So I have no idea how to do it. How do I do it? Anyway thanks for any info or whatever that points me on the right direction. Thanks

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  • Set hidden form field values with JavaScript but request still empty

    - by tigerstyle
    HI volks, I try to set some hidden form field values with an onclick event. Ok, after I did something like this: document.getElementById('hidden_field').value = 123; I can output the value with the firebug console by entering this: alert(document.getElementById('hidden_field').value); So the values are definitely set. But now when I submit the form, the hidden field values are still empty. Do you have any idea whats going wrong? Thx for your answers.

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  • Instantiate a form, then find it later, without showing it initially

    - by awilson53
    I am having a problem that is strange to me but hopefully is not so strange to someone else. : ) Some background: I am working on a simple IM client that allows the user to broadcast messages to multiple recipients. The goal is to create a chat form for each of the recipients containing the text of the broadcast message, then show that form only if the recipient responds to the broadcast-er. However, when the application receives a response then attempts to locate the form for that particular chat session (using Application.OpenForms) it cannot find it UNLESS I .Show at the time it is created. I would like to avoid having to show this form when it is created because this means that the user will see a flash on the screen. The form doesn't seem to really be created until I show it, but it would seem there has to be a way to do this without showing first. Can anyone assist? I can provide code snippets if needed, I didn't in this post because this feels more like a conceptual misunderstanding on my part than a bug in the code. Thanks in advance!

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  • Does Spring MVC form submit data bind children objects automagically?

    - by predhme
    I have a data model that is something like this: public class Report { // report owner private User user; ... typical getter setter ... } public class User { ... omitted for clarity } What happens is when a report is created, the current user is set to the report user object. When the report is edited, the spring controller handling the POST request is receiving a report where the user object is null. Here is what my controller looks like: @Controller @RequestMapping("/report") public class ReportController { @RequestMapping(value = "/edit/{id}", method = RequestMethod.GET) public String editReport(@PathVariable Long id, Model model) { Report r = backend.getReport(id); // fully loads object model.addAttribute("report", report); return "report/edit"; } @RequestMapping(value = "/edit/{id}", method = RequestMethod.POST) public String process(@ModelAttribute("report") Report r) { backend.save(r); return "redirect:/report/show" + r.getId(); } } I ran things throw the debugger and it looks like in the editReport method the model object is storing the fully loaded report object (I can see the user inside the report). On the form jsp I can do the following: ${report.user.username} and the correct result is rendered. However, when I look at the debugger in the process method, the passed in Report r has a null user. I don't need to do any special data binding to ensure that information is retained do I?

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  • Send <p> tags and simple HTML formatting through a form via PHP.

    - by Jonathan
    Hi, so I need the user to write a review about an article or book and send it to a DB via PHP but with some basic HTML formatting.. I mean, I have a form , when the user writes the review, the data is sent but without any kind of formatting, If the user want to write in a new line, the text is sent like plain text, I need to get also those new line breaks and simple stuff. I know how to use PHP and DB connection, I just need to know how to get those new line breakes and stuff..

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  • Persisting object changes from child form to parent form based on button press.

    - by Shyran
    I have created a form that is used for both adding and editing a custom object. Which mode the form takes is provided by an enum value passed from the calling code. I also pass in an object of the custom type. All of my controls at data bound to the specific properties of the custom object. When the form is in Add mode, this works great as when the controls are updated with data, the underlying object is as well. However, in Edit mode, I keep two variables of the custom object supplied by the calling code, the original, and a temporary one made through deep copying. The controls are then bound to the temporary copy, this makes it easy to discard the changes if the user clicks the Cancel button. What I want to know is how to persist those changes back to the original object if the user clicks the OK button, since there is now a disconnect because of the deep copying. I am trying to avoid implementing a internal property on the Add/Edit form if I can. Below is an example of my code: public AddEditCustomerDialog(Customer customer, DialogMode mode) { InitializeComponent(); InitializeCustomer(customer, mode); } private void InitializeCustomer(Customer customer, DialogMode mode) { this.customer = customer; if (mode == DialogMode.Edit) { this.Text = "Edit Customer"; this.tempCustomer = ObjectCopyHelper.DeepCopy(this.customer); this.customerListBindingSource.DataSource = this.tempCustomer; this.phoneListBindingSource.DataSource = this.tempCustomer.PhoneList; } else { this.customerListBindingSource.DataSource = this.customer; this.phoneListBindingSource.DataSource = this.customer.PhoneList; } }

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  • Pass PHP variables without being seen when working with a database generated list

    - by Wilcoholic
    Looking for any help regarding the problem. Here's the deal: I have a database that has a teams table and it contains team_id. On one of my pages, I generate a list of links that contain the team_id of the creator in their get URL. I need the team_id on the next page but can't figure out how to pass it through any other way. Using a form and POST isn't an option because this method would only pass through the last links data on the list. Storing in a session isn't an option either because there is no way to discretely pass the the variables I need to a function to set the session variables. I have tried and it can pretty easily be viewed from viewing the source code. So here's some sample code to see exactly what I'm dealing with. <? if(mysql_num_rows($result2)>0){ ?> <a class="fltrt btn btn-danger btn-small" onclick="test()" href="acceptmatch-exec.php?match_id=<?php echo $match_id; ?>&team_id=<?php echo $team_id;?>&action=cancel">Cancel Match</a> <?}else{?> <a class="fltrt btn btn-success btn-small" href="acceptmatch-exec.php?match_id=<?php echo $match_id; ?>&team_id=<?php echo $team_id;?>&action=accept">Accept Match</a> <?} ?> The code above is generated multiple times on a page via a while loop that was excluded. I want to pass the match_id and team_id variables without being seen anywhere. If I made this a form, it wouldn't pass the correct variables unless there is only one result at the time (not likely). I'm sure there has to be an easy method that is eluding me, so please share thoughts on how to solve this. I feel as though I am not explaining it well enough, but it's not really easy to explain. I basically want something that works like GET but acts like POST and can be hidden from people viewing source code or link locations. Thanks

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  • Javascript - Text Input Attributes

    - by bobrusha
    I need to create a form element <input disabled type="text" value="smth" /> which is disabled by default. It enables when onmouseover occures. onmouseover="this.disabled=false;" And is disabled by onmouseout onmouseout="this.disabled=true;" What I need is to check the following. If the <input> is focused then it shouldn't be disabled. And if the form element loses focus it disables. Please help me to complete the events. <input disabled type="text" value="smth" onmouseover="this.disabled=false;" onfocus="???" onblur="???" onmouseout="if(???){this.disabled=true;}" />

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  • how to don't store a repeated field of a Symfony form?

    - by user454760
    Hello everybody, I am working with Symfony 1.4 and Doctrine. I have a model A with a email field. The form of A, display an input in which the user should insert the email correctly. But as everybody know sometiemes they don't do it. To fix this i have insert an extra field in the model (and in the form), called *repeat_email* to prevent the misspellings. Then, in the validation process, after validates all the fields, i use a global validator to compare the data of the two fields. This works, but i don't want to have the email stored two times in the database (i don't want the *repeat_email*). Is there any mechanism to use it in the validation process, but not to store it in the database? Thanks,

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  • Visual Basic: Newbie questions.

    - by Omega
    Hello there. I am starting to learn visual basic. So far, it is quite simple and easy to use. I am liking it! Anyway, I want to make applications a little bit more complex. So far I have done very silly things. I would appreciate if you could help me with these: How do I open a new window (form)? Maybe I click a button on my main form and another form pops up. How do I "deactivate" the main form while the new form is running? (if I try to click the main form, an error sound plays) So my second form has a text field and a "OK" button. If I click it, the second form closes activating the main form again. I want to "pass" the text in the text field from the second form to the first one. How do I do that? Thank you, I am enjoying this new programming environment (didn't use Visual Studio much before)

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  • how to avoid storing several times a repeated field of a Symfony form?

    - by user454760
    Hello everybody, I am working with Symfony 1.4 and Doctrine. I have a model A with an email field. The form of A displays an input in which the user should insert the email correctly. But as everybody knows, sometimes they don't do it. To fix this I have inserted an extra field in the model (and in the form), called *repeat_email* to prevent the misspellings. Then, in the validation process, after validating all the fields, i use a global validator to compare the data of the two fields. This works, but I don't want to have the email stored two times in the database (I don't want the *repeat_email*). Is there any mechanism to use it in the validation process, but not to store it in the database? Thanks,

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  • How to nest a form in an ASP.NET page (which has a form wrapped around it)

    - by Josh
    I am writing HTML to an ASP.NET page (from a web service response), and the HTML has tags. Unfortunately, because the ASP.NET page already has a wrapped around it, a lot of the buttons on the page break. Does anyone know how I can nest the form inside the ASP.NET page without breaking the top-level form? Note: the HTML I am bringing in is a form with a bunch of hidden fields inside of it, and it has to be placed within the ASP.NET page, and thus nested in the top-level form. Thanks

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  • create php form, show message depending user choice

    - by user1056615
    I want to create a php form with checkbox, like this: < form method="post> <input type="checkbox" name="formpractise[]" value="A" /> <br/> <br/> <input type="checkbox" name="formpractise[]" value="B" /> <br/> <br/> <input type="checkbox" name="formpractise[]" value="C" /> <br/> <br/> <input type="checkbox" name="formpractise[]" value="D" /> <br/> <br/> <input type="checkbox" name="formpractise[]" value="E" /> <br/> <br/> <input type="checkbox" name="formpractise[]" value="F" /> <br/> <br/> <input type="submit" name="formsubmit" value="Submit" /> </form> When the user select checkbox I want to print a message according user choice. Not the choice he made, a message depending his choice.

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  • How do I submit a form from another page?

    - by Tommy
    I have a two page site. Each page contains a header with "tabs" at the top, to navigate between page 1 and 2. When a tab is selected, I need the selected page to re-POST to the server, to quickly refresh before it is displayed. I have a form on each page that allows a manual refresh from that page but need to submit that form from the other page. For example, page 2 is displayed. The tab for page 1 is selected (which is on page 2) It should then submit the refresh form on page 1. Any help is appreciated. (Using jQuery, js, html and CSS)

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  • ecommerce - use server side code for hidden values in an html form

    - by bsarmi
    I'm trying to learn how to implement a donation form on a website using virtual merchant. The html code from their developer manual goes like this: <form action="https://www.myvirtualmerchant.com/VirtualMerchant/process.do" method="POST"> Your Total: $5.00 <br/> <input type="hidden" name="ssl_amount" value="5.00"> <br/> <input type="hidden" name="ssl_merchant_id" value="my_virtualmerchant_ID"> <input type="hidden" name="ssl_pin" value="my_PIN"> <input type="hidden" name="ssl_transaction_type" value="ccsale"> <input type="hidden" name="ssl_show_form" value="false"> Credit Card Number: <input type="text" name="ssl_card_number"> <br/> Expiration Date (MMYY): <input type="text" name="ssl_exp_date" size="4"> <br/> <br/> <input type="submit" value="Continue"> </form> I have that in an html file and it works fine, but they suggest that the merchant data (the input type="hidden" values) should be in a Server Side Code. I was looking at cURL but it'a all very new to me and I spent a couple of hours trying to find some guide or some sample code on how to accomplish that. Any suggestions or help is greatly appreciated. Thanks!

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  • How to take value from radio selection and pass that value into a hidden inputs value attribute?

    - by Matthew
    Hello guys, I need to know if this can be done and if so can someone push me in the right direction. Okay I have a series of radio buttons: <input type="radio" name="level_id" id="radio1" value="XXXX" class="radio1" /> <label for="radio1">choice 1</label> <input type="radio" name="level_id" id="radio2" value="XXXX" class="radio2" /> <label for="radio2">choice 2</label> <input type="radio" name="level_id" id="radio3" value="XXXX" class="radio3" /> <label for="radio3">choice 3</label> <label for="radio4">second choice1</label> <input type="radio" name="level_id" id="radio4" value="1" class="radio4" /> <label for="radio5">second choice2</label> <input type="radio" name="level_id" id="radio5" value="2" class="radio5" /> <label for="radio6">second choice3</label> <input type="radio" name="level_id" id="radio6" value="3" class="radio6" /> Now what I am looking to do is if someone selects CHOICE 1 and then selects SECOND CHOICE1 I would like to pass the value of SECOND CHOICE1 into the value of a hidden input. <input type="hidden" name="sub_source" id="sub_source" value="" /> So that when the form is ready to submit the value that gets passed would be: <input type="hidden" name="sub_source" id="sub_source" value="1" />

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  • Object synchronization with GUI Controls in C#

    - by Heka
    Hi, Every time when I change some values in form controls, I need to set a property of an object or vice versa. Instead of writing some methods for each control, I want a general solution for GUI elements. I do not use WPF but only C# 3.0. Any suggestions? Thanks.

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  • Form wont stay on top. How do I keep my excel form from hiding behind other windows after I browse

    - by ScottK
    I have a vb.net program that opens up an excel workbook and runs a macro ("Report") in that workbook when a button is clicked. //Workbook with macro and form xlWorkbook = xlApp.Workbooks.Open("W:Data\Excel Program.xls") //Macro: xlApp.Run("Report") //Macro opens form from workbook. I browse for my two .csv files //and then click a button to run code that creates my reports. //form closes, show the excel report after its created xlApp.Visible = True After I browse my first file and select it so that its location is displayed in my text box, the excel form then hides behind any open windows. I want this form to stay on top. It is after this code executes that the form will hide behind all other open windows: Private Sub btnBrowseFile1_Click() Dim fileName1 As String fileName1 = Application.GetOpenFilename("CSV file (*.csv), *.csv") If fileName1 <> "False" Then Me.txtFileName1.text = fileName1 End If End Sub EDIT: I still have no luck with this problem. When the excel macro is opened from a vb program I have this hiding issue...but only after browsing for a file. Why does the focus leave the form and go to Windows after browsing a file? Any one have any suggestions?

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  • Possible to use Javascript to access the client side's network(knowingly)

    - by Earlz
    I recently found an exploit in my router to basically give me root access. The catch? There is a nonce hidden form value that is randomly generated and must be sent in for it to work that makes it difficult to do "easily" So basically I'm wanting to do something like this in javascript: get http://192.168.1.254/blah use a regex or similar to extract the nonce value put the nonce value into a hidden field in the current page submit the form by POST to http://192.168.1.254/blah complete with the nonce value and other form values I want to send in. Is this at all possible using only HTML and Javascript? I'm open to things like "must save HTML file locally and then open", which I'm thinking is one way around the cross domain policy. But anyway, is this at all possible? I'm hoping for this to be able to run from at least Firefox and Chrome. The audience for this is those with some technical know how.

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  • submit button on html to output result on same page

    - by amateur
    Hi, Although this seems like something very basic, but no matter what I tried I couldn't get my head around it. Basically I want a html form where a user types in their ID number in an input text box and when they hit the submit button it displays their email address which is their company ID number @ company.com, such as below <form action=""> ID Number: <input type="text" name="idnumber" /><br/> <input type="submit" value="Whats my email address" /> </form> <p>Your email address is 'idnumber'@email.com</p> Can this even be done using html or would I need to use Javascript or PHP for it? Thanks

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