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  • ecommerce - use server side code for hidden values in an html form

    - by bsarmi
    I'm trying to learn how to implement a donation form on a website using virtual merchant. The html code from their developer manual goes like this: <form action="https://www.myvirtualmerchant.com/VirtualMerchant/process.do" method="POST"> Your Total: $5.00 <br/> <input type="hidden" name="ssl_amount" value="5.00"> <br/> <input type="hidden" name="ssl_merchant_id" value="my_virtualmerchant_ID"> <input type="hidden" name="ssl_pin" value="my_PIN"> <input type="hidden" name="ssl_transaction_type" value="ccsale"> <input type="hidden" name="ssl_show_form" value="false"> Credit Card Number: <input type="text" name="ssl_card_number"> <br/> Expiration Date (MMYY): <input type="text" name="ssl_exp_date" size="4"> <br/> <br/> <input type="submit" value="Continue"> </form> I have that in an html file and it works fine, but they suggest that the merchant data (the input type="hidden" values) should be in a Server Side Code. I was looking at cURL but it'a all very new to me and I spent a couple of hours trying to find some guide or some sample code on how to accomplish that. Any suggestions or help is greatly appreciated. Thanks!

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  • Send <p> tags and simple HTML formatting through a form via PHP.

    - by Jonathan
    Hi, so I need the user to write a review about an article or book and send it to a DB via PHP but with some basic HTML formatting.. I mean, I have a form , when the user writes the review, the data is sent but without any kind of formatting, If the user want to write in a new line, the text is sent like plain text, I need to get also those new line breaks and simple stuff. I know how to use PHP and DB connection, I just need to know how to get those new line breakes and stuff..

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  • $_POST Variable Detected in Chrome but not in Firefox

    - by user1707973
    I am using 2 images in a form to sort out query results from the database. The form is submitted using the POST method. When i click on the first image, the query results have to be sorted in ascending order, and when i click on the second, the results have to be sorted in the descending order. This is the code for the form: <form name="" action="" method="post"> <input type="hidden" name="typep" value="price" /> <input type="image" name="sort" value="asc" src="images/asc-ar.png" /> <input type="image" name="sort" value="desc" src="images/dsc-ar.png" /> </form> Now this is the code for checking if the $_REQUEST['sort'] variable is set and therefore whether sorting is required or not. if ($_REQUEST['sort'] != "") { $sort = $_REQUEST['sort']; $typep = $_REQUEST['typep']; //query to be executed depending on values of $sort and $typep } Firefox does detect the $_REQUEST['typep'] variable but not the $_REQUEST['sort'] one. This works perfectly in Chrome though. When i test the site in Firefox, it doesn't detect the $_REQUEST['sort'] variable and therefore the if condition evaluates to false and the search results don't get sorted.

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  • Object synchronization with GUI Controls in C#

    - by Heka
    Hi, Every time when I change some values in form controls, I need to set a property of an object or vice versa. Instead of writing some methods for each control, I want a general solution for GUI elements. I do not use WPF but only C# 3.0. Any suggestions? Thanks.

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  • Rails - Update a single attribute : link with custom action or form with hidden fields?

    - by MrRuru
    Let's say I have a User model, with a facebook_uid field corresponding to the user's facebook id. I want to allow the user to unlink his facebook account. Do do so, I need to set this attribute to nil. I currently see 2 ways of doing this First way : create a custom action and link to it # app/controllers/users_controller.rb def unlink_facebook_account @user = User.find params[:id] # Authorization checks go here @user.facebook_uid = nil @user.save # Redirection go here end # config/routes.rb ressources :users do get 'unlink_fb', :on => :member, :as => unlink_fb end # in a view = link_to "Unlink your facebook account", unlink_fb_path(@user) Second way : create a form to the existing update action # app/views/user/_unlink_fb_form.html.haml = form_for @user, :method => "post" do |f| = f.hidden_field :facebook_uid, :value => nil = f.submit "Unlink Facebook account" I'm not a big fan of either way. In the first one, I have to add a new action for something that the update controller already can do. In the second one, I cannot set the facebook_uid to nil without customizing the update action, and I cannot have a link instead of a button without adding some javascript. Still, what would you recommend as the best and most elegant solution for this context? Did I miss a third alternative?

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  • Javascript form validation only works in firefox

    - by Logic Artist
    Hello, I am relatively new to Javascript so I'm hoping this is a simple mistake. I building a generic form validation function that is called on the form's onSubmit. The function loops through all the form's child elements, looks for certain classes, and analyzes the contents of the appropriate fields. If it finds something missing or erroneous, it displays the appropriate error message div and returns false, thus preventing the form from being submitted to the php page. It works well in firefox 3.6.3, but in every other browser I've tested (Safari 4.0.4, Chrome 4.1, IE8) it seems to ignore the onSubmit and jump straight to the php processing page. HTML CODE: <form name='myForm' id='myForm' action='process_form.php' method='post' onSubmit="return validateRequired('myForm')"> <fieldset class="required radioset"> <label for='selection1'> <input type='radio' name='selection' id='selection1' value='1'/> Option 1 </label> <label for='selection2'> <input type='radio' name='selection' id='selection2' value='2'/> Option 2 </label> <label for='selection3'> <input type='radio' name='selection' id='selection3' value='3'/> Option 3 </label> <label for='selection4'> <input type='radio' name='selection' id='selection4' value='4'/> Option 4 </label> <div class='errorBox' style='visibility:hidden'> Please make a selection </div> </fieldset> <fieldset class="required checkset"> <label> Choice 1 <input type='checkbox' name='choices' id='choice1' value='1'/> </label> <label> Choice 2 <input type='checkbox' name='choices' id='choice2' value='2'/> </label> <label> Choice 3 <input type='checkbox' name='choices' id='choice3' value='3'/> </label> <label> Choice 4 <input type='checkbox' name='choices' id='choice4' value='4'/> </label> <div class='errorBox' style='visibility:hidden'> Please choose at least one </div> </fieldset> <fieldset class="required textfield" > <label for='textinput1'> Required Text: <input type='text' name='textinput1' id='textinput1' size='40'/> </label> <div class='errorBox' style='visibility:hidden'> Please enter some text </div> </fieldset> <fieldset class="required email textfield"> <label for='email'> Required Email: <input type='text' name='email' id='email' size='40'/> </label> <div class='errorBox' style='visibility:hidden'> The email address you have entered is invalid </div> </fieldset> <div> <input type='submit' value='submit'> <input type='reset' value='reset'> </div> </form> JAVASCRIPT CODE: function validateRequired(id){ var form = document.getElementById(id); var errors = 0; var returnVal = true; for(i = 0; i < form.elements.length; i++){ var elem = form.elements[i]; if(hasClass(elem,"required")){ /*RADIO BUTTON or CHECK BOX SET*/ if(hasClass(elem,"radioset") || hasClass(elem,"checkset")){ var inputs = elem.getElementsByTagName("input"); var check = false; for(j = 0; j < inputs.length; j++){ if(inputs[j].checked){ check = true; } } if(check == false){ errors += 1; showError(elem); } else { hideError(elem); } } /*TEXT FIELD*/ else if(hasClass(elem,"textfield")){ var input = elem.getElementsByTagName("input"); if(input[0].value == ""){ errors += 1; showError(elem); } else { hideError(elem); /*EMAIL ADDRESS*/ if(hasClass(elem,"email")){ if(isValidEmail(input[0].value) == false){ errors += 1; showError(elem); } else { hideError(elem); } } } } } } if(errors > 0){ returnVal = false; } else { returnVal = true; } return returnVal;} I know this is a lot of code to look at, but any help would be appreciated. Since it works fine in one browser, Im not sure how to start debugging. Thanks Andrew

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  • How to set up default value in symfony2 select box with data from database

    - by user172409255
    I have this code ->add('user', 'entity', array( 'class' => 'Acme\Entity\User', 'query_builder' => function(EntityRepository $er) use ($options) { return $er->createQueryBuilder('u') ->orderBy('u.name', 'ASC'); }, 'data' => $option['id'] )) Its not working public function buildForm(FormBuilderInterface $builder, array $options) { $builder ->add('description') ->add('user', 'entity', array( 'class' => 'Acme\Entity\User', 'query_builder' => function(EntityRepository $er) use ($options) { return $er->createQueryBuilder('u'); }, 'preferred_choices' => array('2') )) ; }

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  • Select multiple submit issue - POST is empty if not selected

    - by Dasun
    I have a multiple select as below. It allows me to select options as below. Assume that 3 sports are selected. When the items are select as shown above form submit is successful. But unfortunately if the sports are not selected like below when the form is submitted post is empty. Select box <select style="width: 100px; height: 80px;" class="input" id="selected_sport_list" name="selected_sport_list[]" multiple=""> <option value="2">sport 2</option> <option value="3">sport 3</option> <option value="5">sport test x</option></select> How can I make sure that when the form is submitted particular items are selected? Is it possible to use jquery to fix this ? or how? Thanks

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  • How to get the right row in a sorted DataView?

    - by ZeissS
    Hi, I have a DataGrid containing a small table. Until now, I had a double click handler on this grid which iterated over all rows to find the selected one: DataTable table = (DataTable)this.dataGrid.DataSource; int selectedRow = -1; for (int i=0; i<table.Rows.Count; i++) if (this.dataGrid.IsSelected(i)) selectedRow = i; break; } if ( selectedRow != -1 ) { DataRow row = table.Rows[selectedRow]; // More code ... } Problem: When the user clicks on a column header and sort the table, table.Rows does not return the right rows. It still contains the unsorted rows. How can I get the right column?

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  • Javascript - Text Input Attributes

    - by bobrusha
    I need to create a form element <input disabled type="text" value="smth" /> which is disabled by default. It enables when onmouseover occures. onmouseover="this.disabled=false;" And is disabled by onmouseout onmouseout="this.disabled=true;" What I need is to check the following. If the <input> is focused then it shouldn't be disabled. And if the form element loses focus it disables. Please help me to complete the events. <input disabled type="text" value="smth" onmouseover="this.disabled=false;" onfocus="???" onblur="???" onmouseout="if(???){this.disabled=true;}" />

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  • form validation with jquery and livevalidation

    - by ImpY
    I'm trying to do some form validation with livevaldation & jquery. I've a formular with an input field like that: <div id="prenameDiv" class="control-group"> `<input id="prename" name="prename" class="input-large" placeholder="Max" >` </div> So if there's an error on validation 'livevalidaton' adds the class 'LV_invalid_field' to the input - it looks like that: <div id="prenameDiv" class="control-group"> <input id="prename" name="prename" class="input-large LV_invalid_field" placeholder="Max" > </div> That's ok, but now I'll add another class 'error' to the div 'prenameDiv' when the DOM changes that it looks like that: <div id="prenameDiv" class="control-group error"> `<input id="prename" name="prename" class="input-large LV_invalid_field" placeholder="Max" ` </div> I tried it that way: if ($("#prenameDiv").bind("DOMSubtreeModified")){ `if ($("#prename").hasClass("LV_invalid_field")) {` $("#prenameDiv").addClass("error"); } } But nothing changes? Do you have some ideas?

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  • encode data in get request

    - by user902395
    <!DOCTYPE html> <html> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> <body onload="searchForPrograms.submit();"> <form id="searchForPrograms" name="searchForPrograms" enctype="application/x-www-form-urlencoded" method="get" action="searchingEngine.php"> <input type="text" id="query" name="query" value="MyProgram" /><br> <input type="submit" value="Search" /> </form> </body> The get request should have the form like "searchingEngine.php?query=%22MyProgram%22". How can I encode the value of the query input correctly?

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  • set an input value from jquery function

    - by user1499220
    I'm simply trying to set a value for an input but it doesn't work. Here is my jquery function : function display_form() { try { $('#start_date').val('2012/08/21'); }catch (e){ alert('error'); } window.alert( $('[name=start_date]').val() ); } This shows "undefined". Here is my form : <input id="start_date" name="start_date" type="text" size="6" /> Should I put somewhere the id of the form that I want to use? I just followed what is said in the documentation of jquery but it doesn't seem to work. Could anyone help me ?

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  • Setting variable to value of form [drupal 6]

    - by N Schleder
    I have this form $form['title'] = array( '#type' => 'textfield', '#title' => t('Title of Notice'), '#description' => t('Use_underscores_as_spaces'), '#size' => 30, // '#required' => TRUE ); and I want whatever the user types in to be the value of $test I've tried $test = $form['title']; which gives me $test = array also I've tried $test = current($form['title']); which gives me $test = textfield $form['values']['title'] doesn't work dont know what else to try

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  • create php form, show message depending user choice

    - by user1056615
    I want to create a php form with checkbox, like this: < form method="post> <input type="checkbox" name="formpractise[]" value="A" /> <br/> <br/> <input type="checkbox" name="formpractise[]" value="B" /> <br/> <br/> <input type="checkbox" name="formpractise[]" value="C" /> <br/> <br/> <input type="checkbox" name="formpractise[]" value="D" /> <br/> <br/> <input type="checkbox" name="formpractise[]" value="E" /> <br/> <br/> <input type="checkbox" name="formpractise[]" value="F" /> <br/> <br/> <input type="submit" name="formsubmit" value="Submit" /> </form> When the user select checkbox I want to print a message according user choice. Not the choice he made, a message depending his choice.

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  • PHP radio button check if null

    - by Dallox
    So in class we get this school task where we need to check if one of the fields in unfilled and display an error. No we did this but for some strange reason it doesnt display a error when a radio button is unchecked. (textfield null check works fine) I've tried with a friend many possabilities but they all doesnt seem to work. We have been stuck at this task for 2 hours. Now we have tried making seperate if's but that doesnt seem to work too. These are the important parts: <p> <input type="hidden" name="taal" value="false"> Choose a language <input type="radio" name="taal" value="N"> Dutch <input type="radio" name="taal" value="E"> English <input type="radio" name="taal" value="S"> Spanish if (@$_POST['taal'] == null){ echo "No Language gotten"; return; }

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  • how to don't store a repeated field of a Symfony form?

    - by user454760
    Hello everybody, I am working with Symfony 1.4 and Doctrine. I have a model A with a email field. The form of A, display an input in which the user should insert the email correctly. But as everybody know sometiemes they don't do it. To fix this i have insert an extra field in the model (and in the form), called *repeat_email* to prevent the misspellings. Then, in the validation process, after validates all the fields, i use a global validator to compare the data of the two fields. This works, but i don't want to have the email stored two times in the database (i don't want the *repeat_email*). Is there any mechanism to use it in the validation process, but not to store it in the database? Thanks,

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  • How to take value from radio selection and pass that value into a hidden inputs value attribute?

    - by Matthew
    Hello guys, I need to know if this can be done and if so can someone push me in the right direction. Okay I have a series of radio buttons: <input type="radio" name="level_id" id="radio1" value="XXXX" class="radio1" /> <label for="radio1">choice 1</label> <input type="radio" name="level_id" id="radio2" value="XXXX" class="radio2" /> <label for="radio2">choice 2</label> <input type="radio" name="level_id" id="radio3" value="XXXX" class="radio3" /> <label for="radio3">choice 3</label> <label for="radio4">second choice1</label> <input type="radio" name="level_id" id="radio4" value="1" class="radio4" /> <label for="radio5">second choice2</label> <input type="radio" name="level_id" id="radio5" value="2" class="radio5" /> <label for="radio6">second choice3</label> <input type="radio" name="level_id" id="radio6" value="3" class="radio6" /> Now what I am looking to do is if someone selects CHOICE 1 and then selects SECOND CHOICE1 I would like to pass the value of SECOND CHOICE1 into the value of a hidden input. <input type="hidden" name="sub_source" id="sub_source" value="" /> So that when the form is ready to submit the value that gets passed would be: <input type="hidden" name="sub_source" id="sub_source" value="1" />

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  • Change Image in Resources at Runtime

    - by zaidwaqi
    Hi, My understanding of Resources is that I can combine resources i.e. images and my program into single executable. Let's say I have image pic1.png and I put it into Resource of my project, and is accessible with Properties.Resource.pic1. For example, PictureBox pb = new PictureBox(); pb.Image = Properties.Resource.pic1; What I want to do is for that my program will be able to replace this image at runtime. For example, my program runs, and locate newPicture.png, and use this new image to replace pic1.png that was originally used. Maybe my question is better reworded as "Can I include new image into Resources at runtime?" Please help. Thanks.

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  • Send form with jQuery using keypress()

    - by kexxcream
    What I have so far: I have a form in PHP that contain the following: <input type="submit" id="0" name="0" value="This button"> <input type="submit" id="1" name="1" value="This button"> <input type="hidden" id="response" name="response" value="150"> The problem: I would like to send the response value together with either name=1 or name=0, depending on which button the user submit. However, this should be done using the keyboard letters A and S. If a user press the letter A then the value 0 should be submitted, and if S is pressed then the value 1 should be sent. The jQuery code: $(document).ready(function() { // listens for any navigation keypress activity $(document).keypress(function(e) { switch(e.which) { // user presses the "a" case 97: submitViaKeypress("0"); break; // user presses the "s" key case 115: submitViaKeypress("1"); break; } }); }); // shows a given element and hides all others function submitViaKeypress(element_id) { var response = $('#response').attr('value'); $.ajax({ type: "POST", url: "initiate.php", data: "response=" + response + "&" + element_id + "=" + element_id }); } Goal: That "initiate.php receive two POST variables (response and either 0 or 1).

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