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  • convert the key in MIME encoded form in python

    - by jaysh
    this is the code : f = urllib.urlopen('http://pool.sks-keyservers.net:11371/pks/lookup?op=get&search= 0x58e9390daf8c5bf3') #Retrieve the public key from PKS data = f.read() decoded_bytes = base64.b64decode(data) print decoded_bytes i need to convert the key in MIME encoded form which is presently comes in (ascii armored) radix 64 format.for that i have to get this radix64 format in its binary form and also need to remove its header and checksum than coversion in MIME format but i didnt find any method which can do this conversion. i used the base64.b64decode method and its give me error: Traceback (most recent call last): File "RetEnc.py", line 12, in ? decoded_bytes = base64.b64decode(data) File "/usr/lib/python2.4/base64.py", line 76, in b64decode raise TypeError(msg) TypeError: Incorrect padding what to do i'didnt getting .can anybody suggest me something related to this...... thanks!!!!

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  • Python script to delete old SVN files lacks permission

    - by Rosarch
    I'm trying to delete old SVN files from directory tree. shutil.rmtree and os.unlink raise WindowsErrors, because the script doesn't have permissions to delete them. How can I get around that? Here is the script: # Delete all files of a certain type from a direcotry import os import shutil dir = "c:\\" verbosity = 0; def printCleanMsg(dir_path): if verbosity: print "Cleaning %s\n" % dir_path def cleandir(dir_path): printCleanMsg(dir_path) toDelete = [] dirwalk = os.walk(dir_path) for root, dirs, files in dirwalk: printCleanMsg(root) toDelete.extend([root + os.sep + dir for dir in dirs if '.svn' == dir]) toDelete.extend([root + os.sep + file for file in files if 'svn' in file]) print "Items to be deleted:" for candidate in toDelete: print candidate print "Delete all %d items? [y|n]" % len(toDelete) choice = raw_input() if choice == 'y': deleted = 0 for filedir in toDelete: if os.path.exists(filedir): # could have been deleted already by rmtree try: if os.path.isdir(filedir): shutil.rmtree(filedir) else: os.unlink(filedir) deleted += 1 except WindowsError: print "WindowsError: Couldn't delete '%s'" % filedir print "\nDeleted %d/%d files." % (deleted, len(toDelete)) exit() if __name__ == "__main__": cleandir(dir) Not a single file is able to be deleted. What am I doing wrong?

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  • [Python] Tips for making a fraction calculator code more optimized (faster and using less memory)

    - by Logic Named Joe
    Hello Everyone, Basicly, what I need for the program to do is to act a as simple fraction calculator (for addition, subtraction, multiplication and division) for the a single line of input, for example: -input: 1/7 + 3/5 -output: 26/35 My initial code: import sys def euclid(numA, numB): while numB != 0: numRem = numA % numB numA = numB numB = numRem return numA for wejscie in sys.stdin: wyjscie = wejscie.split(' ') a, b = [int(x) for x in wyjscie[0].split("/")] c, d = [int(x) for x in wyjscie[2].split("/")] if wyjscie[1] == '+': licz = a * d + b * c mian= b * d nwd = euclid(licz, mian) konA = licz/nwd konB = mian/nwd wynik = str(konA) + '/' + str(konB) print(wynik) elif wyjscie[1] == '-': licz= a * d - b * c mian= b * d nwd = euclid(licz, mian) konA = licz/nwd konB = mian/nwd wynik = str(konA) + '/' + str(konB) print(wynik) elif wyjscie[1] == '*': licz= a * c mian= b * d nwd = euclid(licz, mian) konA = licz/nwd konB = mian/nwd wynik = str(konA) + '/' + str(konB) print(wynik) else: licz= a * d mian= b * c nwd = euclid(licz, mian) konA = licz/nwd konB = mian/nwd wynik = str(konA) + '/' + str(konB) print(wynik) Which I reduced to: import sys def euclid(numA, numB): while numB != 0: numRem = numA % numB numA = numB numB = numRem return numA for wejscie in sys.stdin: wyjscie = wejscie.split(' ') a, b = [int(x) for x in wyjscie[0].split("/")] c, d = [int(x) for x in wyjscie[2].split("/")] if wyjscie[1] == '+': print("/".join([str((a * d + b * c)/euclid(a * d + b * c, b * d)),str((b * d)/euclid(a * d + b * c, b * d))])) elif wyjscie[1] == '-': print("/".join([str((a * d - b * c)/euclid(a * d - b * c, b * d)),str((b * d)/euclid(a * d - b * c, b * d))])) elif wyjscie[1] == '*': print("/".join([str((a * c)/euclid(a * c, b * d)),str((b * d)/euclid(a * c, b * d))])) else: print("/".join([str((a * d)/euclid(a * d, b * c)),str((b * c)/euclid(a * d, b * c))])) Any advice on how to improve this futher is welcome. Edit: one more thing that I forgot to mention - the code can not make use of any libraries apart from sys.

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  • Python - open text file, but specify name when executing command

    - by Dunnolol
    I have a directory of text files that all end in the extension .txt My goal is to print the contents of the text file. I wish to be able use the wildcard *.txt to be able to specific the text file name I wish to open (I'm thinking along the lines of something like "F:\text*.txt" ?), split the lines of the text file, then print the output. Here is an example of what I want to do, but I want to be able to change "somefile" when executing my command. f = open('F:\text\somefile.txt', 'r') for line in f: print line,

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  • Catch clearly defined exception from sub.submodule in python

    - by mynthon
    I have 3 files. xxx which imports xxx2 and xxx2 imports xxx3 which one raises OppsError exception. xxx3.py: class OppsError(Exception):pass def go(): raise OppsError() xxx2.py: import xxx3 xxx3.go() xxx.py: try: import xxx2 except xxx3.OppsError: print 'ops' When i run xxx.py i get error NameError: name 'xxx3' is not defined. Is importing xxx3 inside xxx only way to catch OppsError?

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  • Python List length as a string

    - by mvid
    Is there a preferred (not ugly) way of outputting a list length as a string? Currently I am nesting function calls like so: print "Length: %s" % str(len(self.listOfThings)) This seems like a hack solution, is there a more graceful way of achieving the same result?

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  • Text to a PNG on App Engine (Python)

    - by Bemmu
    Note: I am cross-posting this from App Engine group because I got no answers there. As part of my site about Japan, I have a feature where the user can get a large PNG for use as desktop background that shows the user's name in Japanese. After switching my site hosting entirely to App Engine, I removed this particular feature because I could not find any way to render text to a PNG using the image API. In other words, how would you go about outputting an unicode string on top of an image of known dimensions (1024x768 for example), so that the text will be as large as possible horizontally, and centered vertically? Is there a way to do this is App Engine, or is there some external service besides App Engine that could make this easier for me, that you could recommend (besides running ImageMagick on your own server)?

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  • Efficient way to build a MySQL update query in Python

    - by ensnare
    I have a class variable called attributes which lists the instance variables I want to update in a database: attributes = ['id', 'first_name', 'last_name', 'name', 'name_url', 'email', 'password', 'password_salt', 'picture_id'] Each of the class attributes are updated upon instantiation. I would like to loop through each of the attributes and build a MySQL update query in the form of: UPDATE members SET id = self._id, first_name = self._first name ... Thanks.

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  • python regular expressions, how to extract longest of overlapping groups

    - by xulochavez
    Hi How can I extract the longest of groups which start the same way For example, from a given string, I want to extract the longest match to either CS or CSI. I tried this "(CS|CSI).*" and it it will return CS rather than CSI even if CSI is available. If I do "(CSI|CS).*" then I do get CSI if it's a match, so I gues the solution is to always place the shorter of the overlaping groups after the longer one. Is there a clearer way to express this with re's? somehow it feels confusing that the result depends on the order you link the groups.

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  • is there a better way of replacing duplicates in a list (python)

    - by myeu2
    Given a list: l1: ['a', 'b', 'c', 'a', 'a', 'b'] output: ['a', 'b', 'c', 'a'_1, 'a'_2, 'b'_1 ] I created the following code to get the output. Its messyyy.. for index in range(len(l1)): counter = 1 list_of_duplicates_for_item = [dup_index for dup_index, item in enumerate(l1) if item == l1[index] and l1.count(l1[index]) > 1] for dup_index in list_of_duplicates_for_item[1:]: l1[dup_index] = l1[dup_index] + '_' + str(counter) counter = counter + 1 Is there a more pythonic way of doing this? I couldnt find anything on the web.

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  • Checking if a string's characters are ascending alphabetically and its ascent is evenly spaced python

    - by FRU5TR8EDD
    So need to check if a string's characters are ascending alphabetically and if that ascent is evenly spaced. a = "abc" b = "ceg" So a is alphabetically ascending and it's spacing is 1 (if you convert to the ordinal values they are 97,98,99). And b is also alphabetically ascending and it's spacing is 2 (99,101,103). And I am sticking with the following code: a = 'jubjub' words1 = [] ords = [ord(letter) for letter in a] diff = ords[1] - ords[0] for ord_val in range(1, len(ords)-1): if diff > 0: if ords[ord_val + 1] - ords[ord_val] == diff: if a not in words1: words1.append((a, diff)) print words1 How come 'jubjub' works, 'ace' works, but 'catcat' doesn't?

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  • Simple python mvc framework

    - by Overdose
    Is there any lightweight mvc webframework which is not necessary to install to the server? I need something simple, that i could just copy to the shared hosting. And it must handle urls other that localhost/test.py, something like this localhost/Blog/test

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  • Python. Strange class attributes behavior

    - by Eugene
    >>> class Abcd: ... a = '' ... menu = ['a', 'b', 'c'] ... >>> a = Abcd() >>> b = Abcd() >>> a.a = 'a' >>> b.a = 'b' >>> a.a 'a' >>> b.a 'b' It's all correct and each object has own 'a', but... >>> a.menu.pop() 'c' >>> a.menu ['a', 'b'] >>> b.menu ['a', 'b'] How could this happen? And how to use list as class attribute?

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  • escaping query string with special characters with python

    - by that_guy
    I got some pretty messy urls that i got via scraping here, problem is that they contain spaces or other special characters in the path and query string, here is some example http://www.example.com/some path/to the/file.html http://www.example.com/some path/?file=path to/file name.png&name=name.me so, is there an easy and robust way to escape the urls so that i can pass them to urlopen? i tried urlib.quote, but it seems to escape the '?', '&', and '=' in the query string as well, and it seems to escape the protocol as well, currently, what i am trying to do is use regex to separate the protocol, path name, and query string and escape them separately, but there are cases where they arent separated properly any advice is appreciated

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  • python send/receive hex data via TCP socket

    - by Mike
    I have a ethenet access control device that is said to be able to communicate via TCP. How can i send a pachet by entering the HEX data, since this is what i have from their manual (a standard format for the communication packets sent and received after each command)

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  • Network Communication program in python

    - by lamnep
    Hi all, Basically what I'm trying to achieve is a program which allow users to connect to a each other over a network in, essentially, a chat room. What I'm currently struggling with is writing the code so that the users can connect to each other without knowing the IP-address of the computer that the other users are using or knowing the IP-address of a server. Does anyone know of a way in which I could simply have all of the users scan the IP range of my network in order to find any active 'room' and then give the user a chance to connect to it? Also, the hope is that there will be no need for a central server to run this from, rather every user will simply be connected to all other user, essentially being the server and client at the same time.

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  • Python regular expression

    - by user3692739
    I have this HTTP Request and I want to display only the Authorization section (base64 Value) : any help ? This Request is stored on a variable called hreq I have tried this : reg = re.search(r"Authorization:\sBasic\s(.*)\r", hreq) print reg.group() but doesn't work Here is the request : HTTP Request: Path: /dynaform/custom.js Http-Version: HTTP/1.1 Host: 192.168.1.254 Accept-Language: en-US,en;q=0.5 Accept-Encoding: gzip, deflate Referer: http://domain.com/userRpm/StatusRpm.htm Authorization: Basic YWhtEWa6MDfGcmVlc3R6bGH I want to display the value YWhtEWa6MDfGcmVlc3R6bGH Please I need your help thanks in advance experts

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  • Adding items to dictionary if condition is true, else dont - python

    - by CodeTalk
    I'm trying to take an existing process: if self.path_object is not None: dictpath = {} for path in self.path_object: self.params = path.pathval.split("?")[0] self.params = path.pathval.split("&", 2) if path.pathval.contains(self.params): out = list(map(lambda v: v.split("=")[0] +"=" + str(self.fuzz_vectors), self.params)) else: pass dictpath[path] = out print dictpath I added the sub-if/else block in, but it is failing, stating: AttributeError: 'unicode' object has no attribute 'contains' on the if block . How can I fix it? I'm simply trying to do: if the path.pathval has either ? or & in it: add to dictionary else: pass #forget about it. Thanks!

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  • Python Threading, loading one thread after another

    - by Michael
    Hi, I'm working on a media player and am able to load in a single .wav and play it. As seen in the code below. foo = wx.FileDialog(self, message="Open a .wav file...", defaultDir=os.getcwd(), defaultFile="", style=wx.FD_MULTIPLE) foo.ShowModal() queue = foo.GetPaths() self.playing_thread = threading.Thread(target=self.playFile, args=(queue[0], 'msg')) self.playing_thread.start() But the problem is, when I try to make the above code into a loop for multiple .wav files. Such that while playing_thread.isActive == True, create and .start() the thread. Then if .isActive == False, pop queue[0] and load the next .wav file. Problem is, my UI will lock up and I'll have to terminate the program. Any ideas would be appreciated.

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  • Normalising book titles - Python

    - by RadiantHex
    Hi folks, I have a list of books titles: "The Hobbit: 70th Anniversary Edition" "The Hobbit" "The Hobbit (Illustrated/Collector Edition)[There and Back Again]" "The Hobbit: or, There and Back Again" "The Hobbit: Gift Pack" and so on... I thought that if I normalised the titles somehow, it would be easier to implement an automated way to know what book each edition is referring to. normalised = ''.join([char for char in title if char in (string.ascii_letters + string.digits)]) or normalised = '' for char in title: if char in ':/()|': break normalised += char return normalised But obviously they are not working as intended, as titles can contain special characters and editions can basically have very different title layouts. Help would be very much appreciated! Thanks :)

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  • Assistance with regular expressions in Python

    - by da5id
    I am still learning REGEX, and I've run into an issue ... I am trying to separate a string that is composed of a mixture of letters and numbers that are in decimal format: AB0.500CD1.05EF2.29 Into something like this: list1 = AB,CD,EF list2 = 0.500,1.05,2.29 A complication to all this is that I also have strings that look like this: AB1CD2EF3 Which I'd also like to separate into this: list1 = AB,CD,EF list2 = 1,2,3 A previous inquiry yielded the following snippet, import re pattern = re.compile(r'([a-zA-Z]+)([0-9]+)') for (letters, numbers) in re.findall(pattern,cmpnd): print numbers print letters This example works fine for strings of the 2nd kind, but only "finds" the leading digit in the numbers that contain decimal places in the strings of the first kind. I've attempted an approach using the following line: pattern = re.compile(r'([a-zA-Z]+)([0-9]+(\.[0-9]))') But this results in an error: "ValueError: too many values to unpack" Thanks for any and all assistance!

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