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  • iPhone: Grouping records in multiple UITableView views

    - by Nic Hubbard
    Let me first say, I know how to create sections and group records within a UITableView. What I am wanting to do is something similar to creating a photo album. So, I have all my data objects coming from core data, and, I want to be able to create a custom group, such as "My Trip to Mexico" and "First Birthday". Then, the user should be able to add objects/records into new sections/albums. So, basically the user is creating custom sections with their own custom names, and then choosing what records should go into that section/album. So, I am just wondering what is the best way to do this? I am thinking that I would just create some extra attributes for my core data model. Or, would I create a whole new "Album Section" object, and somehow use that? Point me in the right direction. :)

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  • Shell Script- each unique user

    - by Dinis Monteiro
    Hi guys I need "for each unique user, report which group they are a member of and when they last logged in" so i have: #!/bin/sh echo "Your initial login:" who | cut -d' ' -f1 | sort | uniq echo "Now is logged:" whoami echo "Group ID:" id -G $whoami case $1 in "-l") last -Fn 10 | tr -s " " ;; *) last -Fn 10 | tr -s " " | egrep -v '(^reboot)|(^$)|(^wtmp a)|(^ftp)' | cut -d" " -f1,5,7 | sort -uM | uniq -c esac My question is: how i can show the each unique user? the script above only show the more recent user logged in the system, but i need all unique users. anyone can help? thanks

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  • How should I join these 3 SQL queries in Oracle?

    - by Nazgulled
    I have these 3 queries: SELECT title, year, MovieGenres(m.mid) genres, MovieDirectors(m.mid) directors, MovieWriters(m.mid) writers, synopsis, poster_url FROM movies m WHERE m.mid = 1; SELECT AVG(rating) FROM movie_ratings WHERE mid = 1; SELECT COUNT(rating) FROM movie_ratings WHERE mid = 1; And I need to join them into a single query. I was able to do it like this: SELECT title, year, MovieGenres(m.mid) genres, MovieDirectors(m.mid) directors, MovieWriters(m.mid) writers, synopsis, poster_url, AVG(rating) average, COUNT(rating) count FROM movies m INNER JOIN movie_ratings mr ON m.mid = mr.mid WHERE m.mid = 1 GROUP BY title, year, MovieGenres(m.mid), MovieDirectors(m.mid), MovieWriters(m.mid), synopsis, poster_url; But I don't really like that "huge" GROUP BY, is there a simpler way to do it?

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  • How to apply styles to the whole silverlight pplication?

    - by Subhen
    Hi I have created two different grid background and radio button style in my App.xaml. User can select any style to change the look of the page i.e: Changing the background and style of the radiobutton. Now When I click on the raduio button the application navigates to another page and the style disappears. Is there a way to Set the style in application level or I need to store the styleVar as Global Var and check on the second page load and then apply the styles as per the styleVar.

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  • Any way to optimize this MySQL query?

    - by manyxcxi
    My table looks like this: `MyDB`.`Details` ( `id` bigint(20) NOT NULL, `run_id` int(11) NOT NULL, `element_name` varchar(255) NOT NULL, `value` text, `line_order` int(11) default NULL, `column_order` int(11) default NULL ); I have the following SELECT statement in a stored procedure SELECT RULE ,TITLE ,SUM(IF(t.PASSED='Y',1,0)) AS PASS ,SUM(IF(t.PASSED='N',1,0)) AS FAIL FROM ( SELECT a.line_order ,MAX(CASE WHEN a.element_name = 'PASSED' THEN a.`value` END) AS PASSED ,MAX(CASE WHEN a.element_name = 'RULE' THEN a.`value` END) AS RULE ,MAX(CASE WHEN a.element_name = 'TITLE' THEN a.`value` END) AS TITLE FROM Details a WHERE run_id = runId GROUP BY line_order ) t GROUP BY RULE, TITLE; *runId is an input parameter to the stored procedure. This query takes about 14 seconds to run. The table has 214856 rows, and the particular run_id I am filtering on has 162204 records. It's not on a super high power machine, but I feel like I could be doing this more efficiently. My main goal is to summarize by Rule and Title and show Pass and Fail count columns.

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  • Get the count of A -> B and B->A without duplicates

    - by TomGasson
    I have a table like so: index|from | to ------------------ 1 | ABC | DEF 2 | ABC | GHI 3 | ABC | GHI 4 | ABC | JKL 5 | ABC | JKL 6 | ABC | JKL 7 | DEF | ABC 8 | DEF | GHI 9 | DEF | JKL 10 | GHI | ABC 11 | GHI | ABC 12 | GHI | ABC 13 | JKL | DEF And I need to count how the total times between the points (regardless of direction) to get the result: A | B | count ----------------- ABC | DEF | 2 ABC | GHI | 5 ABC | JKL | 3 DEF | GHI | 1 DEF | JKL | 2 So far I can get: SELECT `a`.`from` as `A`, `a`.`to` as `B`, (`a`.`count` + `b`.`count`) as `count` FROM (SELECT `from`, `to`, count(*) as `count` FROM `table` GROUP BY 1,2) `a` LEFT OUTER JOIN (SELECT `from`,`to`, count(*) as `count` FROM `table` GROUP BY 1,2) `b` ON `a`.`from` = `b`.`to` AND `a`.`to` = `b`.`from` But I'm unsure how to remove the A/B swapped duplicates.

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  • Union All Won't work in stored procedure

    - by MyHeadHurts
    ALTER PROCEDURE [dbo].[MyStoredProcedure1] @YearToGet int AS Select Division, SDESCR, DYYYY, Sum(APRICE) ASofSales, Sum(PARTY) AS ASofPAX, Sum(NetAmount) ASofNetSales, Sum(InsAmount) ASofInsSales, Sum(CancelRevenue) ASofCXSales, Sum(OtherAmount) ASofOtherSales, Sum(CXVALUE) ASofCXValue From dbo.B101BookingsDetails Where Booked <= CONVERT(int,DateAdd(year, @YearToGet - Year(getdate()), DateAdd(day, DateDiff(day, 1, getdate()), 0) ) ) and (DYYYY = @YearToGet) Group By SDESCR, DYYYY, Division Having (DYYYY = @YearToGet) Order By Division, SDESCR, DYYYY union all SELECT DIVISION, SDESCR, DYYYY, SUM(APRICE) AS YESales, SUM(PARTY) AS YEPAX, SUM(NetAmount) AS YENetSales, SUM(InsAmount) AS YEInsSales, SUM(CancelRevenue) AS YECXSales, SUM(OtherAmount) AS YEOtherSales, SUM(CXVALUE) AS YECXValue FROM dbo.B101BookingsDetails Where (DYYYY=@YearToGet) GROUP BY SDESCR, DYYYY, DIVISION ORDER BY DIVISION, SDESCR, DYYYY The error I am getting is Msg 156, Level 15, State 1, Procedure MyStoredProcedure1, Line 36 Incorrect syntax near the keyword 'union'. But my goal here is the user inputs a year for example 2009, my first query will get all the sales made in 2009 to the same date it is was yesterday 12/23/2009, while the second query is getting 2009 totals up to dec 31 2009. I want the columns to be side by side not in one column

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  • label text limit

    - by ven in Iphone world
    i am having label and text on to it is loaded by dynamically is connecting to radio and displays name of song ,i am getting problem with song name is crosses my play button present on my player ...so i want to limit while display...

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  • Output something other than True or False

    - by David
    Newb to JS. Trying to determain how to to output something other than Question 1 is True and False. If I understand this correctly, the output is the expression of the flag True or False. Trying to change to say Correct and Incorrect. Also trying to express a percentage of correct instead of the for example: Your total score is 10/100 $(function(){ var jQuiz = { answers: { q1: 'd', q2: 'd', }, questionLenght: 2, checkAnswers: function() { var arr = this.answers; var ans = this.userAnswers; var resultArr = [] for (var p in ans) { var x = parseInt(p) + 1; var key = 'q' + x; var flag = false; if (ans[p] == 'q' + x + '-' + arr[key]) { flag = true; g } else { flag = false; } resultArr.push(flag); } return resultArr; }, init: function(){ $("[class=btnNext]").click(function(){ if ($('input[type=radio]:checked:visible').length == 0) { return incorrect ; } $(this).parents('.questionContainer').fadeOut(500, function(){ $(this).next().fadeIn(500); }); var el = $('#progress'); el.width(el.width() + 11 + 'px'); }); $('.btnPrev').click(function(){ $(this).parents('.questionContainer').fadeOut(500, function(){ $(this).prev().fadeIn(500) }); var el = $('#progress'); el.width(el.width() - 11 + 'px'); }) $("[class=btnShowResult]").click(function(){ var arr = $('input[type=radio]:checked'); var ans = jQuiz.userAnswers = []; for (var i = 0, ii = arr.length; i < ii; i++) { ans.push(arr[i].getAttribute('id')) } }) $('.btnShowResult').click(function(){ $('#progress').width(260); $('#progressKeeper').hide(); var results = jQuiz.checkAnswers(); var resultSet = ''; var trueCount = 0; for (var i = 0, ii = results.length; i < ii; i++){ if (results[i] == true) trueCount++; resultSet += '<div> Question ' + (i + 1) + ' is ' + results[i] + '</div>' } resultSet += '<div class="totalScore">Your total score is ' + trueCount * 4 + ' / 100</div>' $('#resultKeeper').html(resultSet).show(); }) } }; jQuiz.init(); })

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  • Unknown Column?

    - by Kenny
    ok im trying to get mutual friends between these Two users, user1 and user92 This is the sql that is successful in displaying them SELECT IF(user_a = 1 OR user_a = 92, user_b, user_a) friend FROM friendship WHERE (user_a = 1 OR user_a = 92) OR (user_b = 1 OR user_b = 92) GROUP BY 1 HAVING COUNT(*) > 1 THis is how it looks friend 61 72 73 74 75 76 77 78 79 80 81 So now i want to select all users after the number 72, and i try to do it with this sql but its not working? It gives me the error, "unknown coulum name friend in where clause" SELECT IF(user_a = 1 OR user_a = 92, user_b, user_a) friend FROM friendship WHERE friend > 72 and (user_a = 1 OR user_a = 92) OR (user_b = 1 OR user_b = 92) GROUP BY 1 HAVING COUNT(*) > 1 what am i doing wrong? or what is the correct way?? thx

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  • what is a fast way to output h5py dataset to text?

    - by user362761
    I am using the h5py python package to read files in HDF5 format. (e.g. somefile.h5) I would like to write the contents of a dataset to a text file. For example, I would like to create a text file with the following contents: 1,20,31,75,142,324,78,12,3,90,8,21,1 I am able to access the dataset in python using this code: import h5py f = h5py.File('/Users/Me/Desktop/thefile.h5', 'r') group = f['/level1/level2/level3'] dset = group['dsetname'] My naive approach is too slow, because my dataset has over 20000 entries: # write all values to file for index in range(len(dset)): # do not add comma after last value if index == len(dset)-1: txtfile.write(repr(dset[index])) else: txtfile.write(repr(dset[index])+',') txtfile.close() return None Is there a faster way to write this to a file? Perhaps I could convert the dataset into a NumPy array or even a Python list, and then use some file-writing tool? (I could experiment with concatenating the values into a larger string before writing to file, but I'm hoping there's something entirely more elegant)

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  • getting userbase vote average and individual user's vote in the same query?

    - by Andrew Heath
    Here goes: T1 [id] [desc] 1 lovely 2 ugly 3 slender T2 [id] [userid] [vote] 1 1 3 1 2 5 1 3 2 2 1 1 2 2 4 2 3 4 In one query (if possible) I'd like to return: T1.id, T1.desc, AVG(T2.vote), T2.vote (for user viewing the page) I can get the first 3 items with: SELECT T1.id, T1.desc, AVG(T2.vote) FROM T1 LEFT JOIN T2 ON T1.id=T2.id GROUP BY T1.id and I can get the first, second, and fourth items with: SELECT T1.id, T1.desc, T2.vote FROM T1 LEFT JOIN T2 ON T1.id=T2.id WHERE T2.userid='1' GROUP BY T1.id but I'm at a loss as to how to get all four items in one query. I tried inserting a select as the fourth term: SELECT T1.id, T1.desc, AVG(T2.vote), (SELECT T2.vote FROM T2 WHERE T2.userid='1') AS userVote etc etc but I get an error that the select returns more than one row... Help? My reason for wanting to do this in one query instead of two is that I want to be able to sort the data within MySQL rather than one it's been split into a number of arrays.

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  • Cocos2d-iPhone: CCSprite positions differ between Retina & non-Retina Screens

    - by bobwaycott
    I have a fairly simple app built using cocos2d-iphone, but a strange positioning problem that I've been unable to resolve. The app uses sprite sheets, and there is a Retina and non-Retina sprite sheet within the app that use the exact same artwork (except for resolution, of course). There are other artwork within the app used for CCSprites that are both standard and -hd suffixed. Within the app, a group of sprites are created when the app starts. These initially created CCSprites always position identically (and correctly) on Retina & non-Retina screens. // In method called to setup sprites when app launches // Cache & setup app sprites [[CCSpriteFrameCache sharedSpriteFrameCache] addSpriteFramesWithFile: @"sprites.plist"]; sprites = [CCSpriteBatchNode batchNodeWithFile: @"sprites.png"]; hill = [CCSprite spriteWithSpriteFrameName: @"hill.png"]; hill.position = ccp( 160, 75 ); [sprites addChild: hill z: 1]; // ... [create more sprites in same fashion] // NOTE: All sprites created here have correct positioning on Retina & non-Retina screens When a user taps the screen a certain way, a method is called that creates another group of CCSprites (on- and off-screen), animating them all in. One of these sprites, hand, is always positioned identically (and correctly) on Retina & non-Retina screens. The others (a group of clouds) successfully create & animate, but their positions are correct only on Retina displays. On a non-Retina display, each cloud has incorrect starting positions (incorrect for x, y, or sometimes both), and their ending positions after animation are also wrong. I've included the responsible code below from the on-touch method that creates the new sprites and animates them in. Again, it works as expected on a Retina display, but incorrectly on non-Retina screens. The CCSprites used are created in the same way at app-start to setup all the initial sprites in the app, which always have correct positions. // Elsewhere, in a method called on touch // Create clouds cloud1 = [CCSprite spriteWithSpriteFrameName: @"cloud_1.png"]; cloud1.position = ccp(-150, 320); cloud1.scale = 1.2f; cloud2 = [CCSprite spriteWithSpriteFrameName: @"cloud_2.png"]; cloud2.position = ccp(-150, 335); cloud2.scale = 1.3f; cloud3 = [CCSprite spriteWithSpriteFrameName: @"cloud_4.png"]; cloud3.position = ccp(-150, 400); cloud4 = [CCSprite spriteWithSpriteFrameName: @"cloud_5.png"]; cloud4.position = ccp(-150, 420); cloud5 = [CCSprite spriteWithSpriteFrameName: @"cloud_3.png"]; cloud5.position = ccp(400, 350); cloud6 = [CCSprite spriteWithSpriteFrameName: @"cloud_1.png"]; cloud6.position = ccp(400, 335); cloud6.scale = 1.1f; cloud7 = [CCSprite spriteWithSpriteFrameName: @"cloud_2.png"]; cloud7.flipY = YES; cloud7.flipX = YES; cloud7.position = ccp(400, 380); // Create hand hand = [CCSprite spriteWithSpriteFrameName:@"hand.png"]; hand.position = ccp(160, 650); [sprites addChild: cloud1 z: 10]; [sprites addChild: cloud2 z: 9]; [sprites addChild: cloud3 z: 8]; [sprites addChild: cloud4 z: 7]; [sprites addChild: cloud5 z: 6]; [sprites addChild: cloud6 z: 10]; [sprites addChild: cloud7 z: 8]; [sprites addChild: hand z: 10]; // ACTION!! [cloud1 runAction:[CCMoveTo actionWithDuration: 1.0f position: ccp(70, 320)]]; [cloud2 runAction:[CCMoveTo actionWithDuration: 1.0f position: ccp(60, 335)]]; [cloud3 runAction:[CCMoveTo actionWithDuration: 1.0f position: ccp(100, 400)]]; [cloud4 runAction:[CCMoveTo actionWithDuration: 1.0f position: ccp(80, 420)]]; [cloud5 runAction:[CCMoveTo actionWithDuration: 1.0f position: ccp(250, 350)]]; [cloud6 runAction:[CCMoveTo actionWithDuration: 1.0f position: ccp(250, 335)]]; [cloud7 runAction:[CCMoveTo actionWithDuration: 1.0f position: ccp(270, 380)]]; [hand runAction: handIn]; It may be worth mentioning that I see this incorrect positioning behavior in the iOS Simulator when running the app and switching between the standard iPhone and iPhone (Retina) hardware options. I have not been able to verify this occurs or does not occur on an actual non-Retina iPhone because I do not have one. However, this is the only time I see this odd positioning behavior occur (the incorrect results obtained after user touch), and since I'm creating all sprites in exactly the same way (i.e., [CCSprite spriteWithSpriteFrameName:] and then setting position with cpp()), I would be especially grateful for any help in tracking down why this single group of sprites are always incorrect on non-Retina screens. Thank you.

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  • How do I create a point system in a Rails app that assigns points to users and non-authenticated-use

    - by codyvbrown
    I'm building a question and answer application on top of twitter and I'm hitting some snags because I'm inevitably dealing with two classes of users: authenticated and non-authenticated. The site enable users to give points to other users, who may or may not be authenticated, and I want to create a site-wide point system where the application stores and displays this information on their profile. I want to save this point data to the user because that would be faster and more efficient but non-authenticated users aren't in our system, we only have the twitter handle. So instead we display the points in our system like this: @points = point.all( :select => "tag, count(*) AS count", # Return tag and count :group => 'tag', # Group by the tag :order => "2 desc", :conditions => {:twitter_handle => params[:username]}) Is there a better way to do this? Is there a better way to associate data with non-authenticated users?

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  • making a combined sum of two columns

    - by bsandrabr
    I have a table (apples) containing: cid date_am date_pm ---------------------- 1 1 1 2 2 1 3 1 3 1 1 2 I asked a question earlier (badly) about how I would rank the customers in order of the number of ones(1) they had. The solution was (based on one column): SELECT cid, sum( date_pm ) AS No_of_ones FROM apples WHERE date_am =1 GROUP BY cid ORDER BY no_of_ones DESC This works great for one column but how would I do the same for the sum of the two columns. ie. SELECT cid, sum( date_pm ) AS No_of_ones FROM apples WHERE date_am =1 add to SELECT cid, sum( date_am ) AS No_of_ones FROM apples WHERE date_pm =1 GROUP by cid ORDER by no_of_ones(added) hope I've managed to make that clear enough for you to help -thanks

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  • COUNT issue across multiple tables

    - by Kim
    I am trying to count across 2 tables and I dont see whats wrong with my query yet I get a wrong result. User 2 does not exist in table_two, so the zero is correct. SELECT t1.creator_user_id, COUNT(t1.creator_user_id), COUNT(t2.user_id) FROM table_one AS t1 LEFT JOIN table_two AS t2 ON t2.user_id = t1.creator_user_id GROUP BY t1.creator_user_id, t2.user_id Actual result 1 192 192 2 9 0 Expected result 1 16 12 2 9 0 The result indicate a missing group by condition, but I already got both fields used. Where am I wrong ? Also, can I sum up all users that doesnt exist in table_two for t1 ? Like user 3 exists 21 times in t1, then the results would be: 1 16 12 (users with > 0 in t2 will need their own row) 2 30 0 (user 2=9 + user 3=21 => 30) Its okay for the user Id to be wrong for sum of t1 for all users with 0 in t2. If not possible, then I'll just do two queries.

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  • How do I indicate that a class doesn't support certain operators?

    - by romeovs
    I'm writing a class that represents an ordinal scale, but has no logical zero-point (eg time). This scale should permit addition and substraction (operator+, operator+=, ...) but not multiplication. Yet, I always felt it to be a good practice that when one overloads one operator of a certain group (in this case the math operators), one should also overload all the others that belong to that group. In this case that would mean I should need to overload the multiplication and division operators also, because if a user can use A+B he would probable expect to be able the other operators. Is there a method that I can use to throw an error for this at compiler time? The easiest method would be just no to overload the operators operator*, ... yet it would seem appropriate to add a bit more explaination than operator* is not know for class "time". Or is this something that I really should not care about (RTFM user)?

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  • bulk update/delete entities of different kind in db.run_in_transaction

    - by Ray Yun
    Here goes pseudo code of bulk update/delete entities of different kind in single transaction. Note that Album and Song entities have AlbumGroup as root entity. class AlbumGroup: pass class Album: group = db.ReferenceProperty(reference_class=AlbumGroup,collection_name="albums") class Song: album = db.ReferenceProperty(reference_class=Album,collection_name="songs") def bulk_update_album_group(album_group): updated = [album_group] deleted = [] for album in album_group.albums: updated.append(album) for song in album.songs: if song.is_updated: updated.append(song) if song.is_deleted: deleted.append(song) db.put(updated) db.delete(deleted) a = AlbumGroup.all().filter("...").get() # bulk update/delete album group. for simplicity, album cannot be deleted. db.run_in_transaction(bulk_update_album_group,a) But I met a famous "Only Ancestor Queries in Transactions" error at the iterating reference properties like album.songs or album_group.albums. I guess ancestor() filter does not help because those entities are modified in memory. Should I not to iterate reference property in transaction function and always provide them as function parameters like def bulk_update_album_group(updated,deleted): ??? Is there any good coding pattern for this situation?

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  • MySQL count problem

    - by Skuja
    I have 3 tables users(id,name),groups(id,name) and users_groups(user_id,group_id). users and groups have many to many relationship, so the third one is for storing users and groups relations. I would like to select all the data from groups with user count in each group. So far I came up with this: SELECT groups.*, COUNT(users_groups.user_id) AS user_count FROM groups LEFT JOIN users_groups ON users_groups.group_id = groups.id The problem is that query result is not returning any of groups which has no users (users_groups doesnt have any records with group_id of those groups). How should I create my query to select all the groups and they user count, or user count as 0 if there are no users for that group?

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  • Many-to-many relationship on same table with association object

    - by Nicholas Knight
    Related (for the no-association-object use case): http://stackoverflow.com/questions/1889251/sqlalchemy-many-to-many-relationship-on-a-single-table Building a many-to-many relationship is easy. Building a many-to-many relationship on the same table is almost as easy, as documented in the above question. Building a many-to-many relationship with an association object is also easy. What I can't seem to find is the right way to combine association objects and many-to-many relationships with the left and right sides being the same table. So, starting from the simple, naïve, and clearly wrong version that I've spent forever trying to massage into the right version: t_groups = Table('groups', metadata, Column('id', Integer, primary_key=True), ) t_group_groups = Table('group_groups', metadata, Column('parent_group_id', Integer, ForeignKey('groups.id'), primary_key=True, nullable=False), Column('child_group_id', Integer, ForeignKey('groups.id'), primary_key=True, nullable=False), Column('expires', DateTime), ) mapper(Group_To_Group, t_group_groups, properties={ 'parent_group':relationship(Group), 'child_group':relationship(Group), }) What's the right way to map this relationship?

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  • Rails 3 render :partials

    - by user297221
    Hi guys. I am migrating my 1.8.7 rails app to rails 3. But I have a problem with a partial: I have the following partial: in my cms controller : @clients = Client.all group = render_to_string :layout = 'layouts/window', :partial = 'clients/index' in my "clients/index" partial: <%= render :partial = 'clients/item', :collection = @clients % This worked great with rails 1.7.8 but with rails 3 only the partial in the index get's rendered!. So, to clarify this, the group variable in the controller doesn't get the html from the layout. Also the weird thing is that the window layout is _window.erb (if I do window.html.erb or just window.erb rails can't find it which is strange). Does anybody know if this behavior is normal for rails 3? thanxs!

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  • Drupal 6 CCK - Having a textbox appear when 'Other' is selected

    - by espais
    I have a special content-type that I have created, and one of the fields is a radio button list. The last element is named 'Other' and I would like to have a textbox appear and allow the user to enter in a non-defined value. Is this sort of capability provided by any sort of module, or is this something that needs to be coded by hand? (If so, would you mind pointing me in the correct direction?)

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