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• How Do I Fix a mysql "system error: 111" in a hosting service?

  - by Ygam

  Got this error Lost connection to MySQL server at 'reading initial communication packet', system error: 111 I am currently hosting a site under a subdomain here is a page accessing the database : http://payment.ygamtester.co.cc/search/index.html I have seen a lot of posts about this all pointing to one solution use ssh to alter a file in the mysql server obviously you can't do that with a remotely hosted site under a hosting company

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• Using proxy server to redirect MySQL traffic to multiple servers using standard port?

  - by FrenchFry

  Is it possible to redirect MySQL (tcp) traffic to multiple servers based on domain name alone? Our DNS is setup to point several sub-domain aliases to one proxy machine. (running haproxy and iptables). We would like to redirect all database traffic through this proxy server and route it to the appropriate db server, WITHOUT deviating from the standard MySQL port. dev.domain1.com:3306 -- dbDevServer.domain1.com:3306 test.domain1.com:3306 -- dbTestServer.domain1.com:3306 prod.domain1.com:3306 -- dbProdServer.domain1.com:3306 Thanks!

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• mysql 5.0.23 vs 5.5 performance benefits and upgrade issues?

  - by WarDoGG

  I have been told that mysql 5.5 has a significant performance boost compared to 5.0 Our server handles a lot of data (around 30 million records processed per 5-10 seconds) and requires every drop of performance boost we can give. Will it be beneficial if we upgrade from 5.0.23 to mysql 5.5? Also, we have lots of database indexes setup on the tables and I've been told that sometimes the indexes become corrupt after a version upgrade and they have to be rebuilt. Is this true?

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• Is it possible to use Excel's OLAP features with MySQL?

  - by sblom

  I want to create an OLAP database for use with Excel, and most of the data is already stored in a MySQL database. Is it possible to create an OLAP schema on a MySQL database, probably on the same server, that Excel can use for ad hoc OLAP interaction?

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• What are these files ,can I delete them manually?

  - by apache

  [root@jiaoyou mysql]# pwd /var/lib/mysql [root@jiaoyou mysql]# ls -ls 338256 -rw-rw---- 1 mysql mysql 346030080 2010-04-22 08:08 ibdata1 626812 -rw-rw---- 1 mysql mysql 641222072 2010-01-26 07:17 mysql-bin.000008 316892 -rw-rw---- 1 mysql mysql 324173772 2010-03-25 12:51 mysql-bin.000009 These three files ibdata1,mysql-bin.000008 and mysql-bin.000009 are taking up too much of my space,will it be ok for me to delete some of them manually?

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• Recovered folders from Camera show as JPEG files and can can't be viewed.

  - by user642111

  I have recovered a CCTV camera hard disk after a crash and have managed to get most of the data using EasyRecovery Pro. The problem is now that all the data that I have recovered appear like File09.JPG with and image icon in windows XP, but the files can't be viewed in any JPEG viewer software. I suspect that the .JPG files are indeed folders, but I can't force windows XP the change the file type. Very Odd. Any help is appreciated. Thanks, Hoo

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• Can't upgrade MySQL Server on new Ubuntu 12.04 install

  - by user179627

  After freshly installing Ubuntu server 12.04, I did the usual apt-get update / apt-get upgrade, which failed for mysql-server-5.5: Setting up mysql-server-5.5 (5.5.31-0ubuntu0.12.04.2) ... start: Job failed to start invoke-rc.d: initscript mysql, action "start" failed. dpkg: error processing mysql-server-5.5 (--configure): subprocess installed post-installation script returned error exit status 1 dpkg: dependency problems prevent configuration of mysql-server: mysql-server depends on mysql-server-5.5; however: Package mysql-server-5.5 is not configured yet. dpkg: error processing mysql-server (--configure): dependency problems - leaving unconfigured I tried a wide variety a approaches suggested by googling, which involved various combinations of apt-get remove/purge/install -f/reinstall, etc., with no luck. I also tried downloading the package directly from launchpad.net and running dpkg -i on it (this had worked for a similar issue with a kernel upgrade), but to no avail. I'm not actually particularly interested in what's going on with mysql, per se (though I will need to figure it out at some time); at this point, my primary concern is that I am unable to apt-get install other packages! What to do?

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• Recover RAID 5 data after created new array instead of re-using

  - by Brigadieren

  Folks please help - I am a newb with a major headache at hand (perfect storm situation). I have a 3 1tb hdd on my ubuntu 11.04 configured as software raid 5. The data had been copied weekly onto another separate off the computer hard drive until that completely failed and was thrown away. A few days back we had a power outage and after rebooting my box wouldn't mount the raid. In my infinite wisdom I entered mdadm --create -f... command instead of mdadm --assemble and didn't notice the travesty that I had done until after. It started the array degraded and proceeded with building and syncing it which took ~10 hours. After I was back I saw that that the array is successfully up and running but the raid is not I mean the individual drives are partitioned (partition type f8 ) but the md0 device is not. Realizing in horror what I have done I am trying to find some solutions. I just pray that --create didn't overwrite entire content of the hard driver. Could someone PLEASE help me out with this - the data that's on the drive is very important and unique ~10 years of photos, docs, etc. Is it possible that by specifying the participating hard drives in wrong order can make mdadm overwrite them? when I do mdadm --examine --scan I get something like ARRAY /dev/md/0 metadata=1.2 UUID=f1b4084a:720b5712:6d03b9e9:43afe51b name=<hostname>:0 Interestingly enough name used to be 'raid' and not the host hame with :0 appended. Here is the 'sanitized' config entries: DEVICE /dev/sdf1 /dev/sde1 /dev/sdd1 CREATE owner=root group=disk mode=0660 auto=yes HOMEHOST <system> MAILADDR root ARRAY /dev/md0 metadata=1.2 name=tanserv:0 UUID=f1b4084a:720b5712:6d03b9e9:43afe51b Here is the output from mdstat cat /proc/mdstat Personalities : [linear] [multipath] [raid0] [raid1] [raid6] [raid5] [raid4] [raid10] md0 : active raid5 sdd1[0] sdf1[3] sde1[1] 1953517568 blocks super 1.2 level 5, 512k chunk, algorithm 2 [3/3] [UUU] unused devices: <none> fdisk shows the following: fdisk -l Disk /dev/sda: 80.0 GB, 80026361856 bytes 255 heads, 63 sectors/track, 9729 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000bf62e Device Boot Start End Blocks Id System /dev/sda1 * 1 9443 75846656 83 Linux /dev/sda2 9443 9730 2301953 5 Extended /dev/sda5 9443 9730 2301952 82 Linux swap / Solaris Disk /dev/sdb: 750.2 GB, 750156374016 bytes 255 heads, 63 sectors/track, 91201 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000de8dd Device Boot Start End Blocks Id System /dev/sdb1 1 91201 732572001 8e Linux LVM Disk /dev/sdc: 500.1 GB, 500107862016 bytes 255 heads, 63 sectors/track, 60801 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00056a17 Device Boot Start End Blocks Id System /dev/sdc1 1 60801 488384001 8e Linux LVM Disk /dev/sdd: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000ca948 Device Boot Start End Blocks Id System /dev/sdd1 1 121601 976760001 fd Linux raid autodetect Disk /dev/dm-0: 1250.3 GB, 1250254913536 bytes 255 heads, 63 sectors/track, 152001 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00000000 Disk /dev/dm-0 doesn't contain a valid partition table Disk /dev/sde: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x93a66687 Device Boot Start End Blocks Id System /dev/sde1 1 121601 976760001 fd Linux raid autodetect Disk /dev/sdf: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0xe6edc059 Device Boot Start End Blocks Id System /dev/sdf1 1 121601 976760001 fd Linux raid autodetect Disk /dev/md0: 2000.4 GB, 2000401989632 bytes 2 heads, 4 sectors/track, 488379392 cylinders Units = cylinders of 8 * 512 = 4096 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 524288 bytes / 1048576 bytes Disk identifier: 0x00000000 Disk /dev/md0 doesn't contain a valid partition table Per suggestions I did clean up the superblocks and re-created the array with --assume-clean option but with no luck at all. Is there any tool that will help me to revive at least some of the data? Can someone tell me what and how the mdadm --create does when syncs to destroy the data so I can write a tool to un-do whatever was done? After the re-creating of the raid I run fsck.ext4 /dev/md0 and here is the output root@tanserv:/etc/mdadm# fsck.ext4 /dev/md0 e2fsck 1.41.14 (22-Dec-2010) fsck.ext4: Superblock invalid, trying backup blocks... fsck.ext4: Bad magic number in super-block while trying to open /dev/md0 The superblock could not be read or does not describe a correct ext2 filesystem. If the device is valid and it really contains an ext2 filesystem (and not swap or ufs or something else), then the superblock is corrupt, and you might try running e2fsck with an alternate superblock: e2fsck -b 8193 Per Shanes' suggestion I tried root@tanserv:/home/mushegh# mkfs.ext4 -n /dev/md0 mke2fs 1.41.14 (22-Dec-2010) Filesystem label= OS type: Linux Block size=4096 (log=2) Fragment size=4096 (log=2) Stride=128 blocks, Stripe width=256 blocks 122101760 inodes, 488379392 blocks 24418969 blocks (5.00%) reserved for the super user First data block=0 Maximum filesystem blocks=0 14905 block groups 32768 blocks per group, 32768 fragments per group 8192 inodes per group Superblock backups stored on blocks: 32768, 98304, 163840, 229376, 294912, 819200, 884736, 1605632, 2654208, 4096000, 7962624, 11239424, 20480000, 23887872, 71663616, 78675968, 102400000, 214990848 and run fsck.ext4 with every backup block but all returned the following: root@tanserv:/home/mushegh# fsck.ext4 -b 214990848 /dev/md0 e2fsck 1.41.14 (22-Dec-2010) fsck.ext4: Invalid argument while trying to open /dev/md0 The superblock could not be read or does not describe a correct ext2 filesystem. If the device is valid and it really contains an ext2 filesystem (and not swap or ufs or something else), then the superblock is corrupt, and you might try running e2fsck with an alternate superblock: e2fsck -b 8193 <device> Any suggestions? Regards!

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• mysql query to dynamically convert row data to columns

  - by Anirudh Goel

  I am working on a pivot table query. The schema is as follows Sno, Name, District The same name may appear in many districts eg take the sample data for example 1 Mike CA 2 Mike CA 3 Proctor JB 4 Luke MN 5 Luke MN 6 Mike CA 7 Mike LP 8 Proctor MN 9 Proctor JB 10 Proctor MN 11 Luke MN As you see i have a set of 4 distinct districts (CA, JB, MN, LP). Now i wanted to get the pivot table generated for it by mapping the name against districts Name CA JB MN LP Mike 3 0 0 1 Proctor 0 2 2 0 Luke 0 0 3 0 i wrote the following query for this select name,sum(if(District="CA",1,0)) as "CA",sum(if(District="JB",1,0)) as "JB",sum(if(District="MN",1,0)) as "MN",sum(if(District="LP",1,0)) as "LP" from district_details group by name However there is a possibility that the districts may increase, in that case i will have to manually edit the query again and add the new district to it. I want to know if there is a query which can dynamically take the names of distinct districts and run the above query. I know i can do it with a procedure and generating the script on the fly, is there any other method too? I ask so because the output of the query "select distinct(districts) from district_details" will return me a single column having district name on each row, which i will like to be transposed to the column.

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• Trouble pre-populating drop down and textarea from MySQL Database

  - by Tony

  I am able to successfully pre-populate my questions using the following code: First Name: <input type="text" name="first_name" size="30" maxlength="20" value="' . $row[2] . '" /><br /> However, when I try to do the same for a drop down box and a textarea box, nothing is pre-populated from the database, even though there is actual content in the database. This is the code I'm using for the drop down and textarea, respectively: <?php echo ' <form action ="edit_contact.php" method="post"> <div class="contactfirstcolumn"> Prefix: <select name = "prefix" value="' . $row[0] . '" /> <option value="blank">--</option> <option value="Dr">Dr.</option> <option value="Mr">Mr.</option> <option value="Mrs">Mrs.</option> <option value="Ms">Ms.</option> </select><br />'; ?> AND Contact Description:<textarea id = "contactdesc" name="contactdesc" rows="3" cols="50" value="' . $row[20] . '" /></textarea><br /><br /> It's important to note that I am not receiving any errors. The form loads fine, however without the data for the drop down and textarea fields. Thanks! Tony

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• how to write this typical mysql query( ho to use subquery column into main query)

  - by I Like PHP

  I HAVE TWO TABLES shown below table_joining id join_id(PK) transfer_id(FK) unit_id transfer_date joining_date 1 j_1 t_1 u_1 2010-06-05 2010-03-05 2 j_2 t_2 u_3 2010-05-10 2010-03-10 3 j_3 t_3 u_6 2010-04-10 2010-01-01 4 j_5 NULL u_3 NULL 2010-06-05 5 j_6 NULL u_4 NULL 2010-05-05 table_transfer id transfer_id(PK) pastUnitId futureUnitId effective_transfer_date 1 t_1 u_3 u_1 2010-06-05 2 t_2 u_6 u_1 2010-05-10 3 t_3 u_5 u_3 2010-04-10 now i want to know total employee detalis( using join_id) which are currently working on unit u_3 . means i want only join_id j_1 (has transfered but effective_transfer_date is future date, right now in u_3) j_2 ( tansfered and right now in `u_3` bcoz effective_transfer_date has been passed) j_6 ( right now in `u_3` and never transfered) what i need to take care of below steps( as far as i know ) <1> first need to check from table_joining whether transfer_id is NULL or not <2> if transfer_id= is NULL then see unit_id=u_3 where joining_date <=CURDATE() ( means that person already joined u_3) <3> if transfer_id is NOT NULL then go to table_transfer using transfer_id (foreign key reference) <4> now see the effective_transfer_date regrading that transfer_id whether effective_transfer_date<=CURDATE() <5> if transfer date has been passed(means transfer has been done) then return futureUnitID otherwise return pastUnitID i used two separate query but don't know how to join those query?? for step <1 ans <2 SELECT unit_id FROM table_joining WHERE joining_date<=CURDATE() AND transfer_id IS NULL AND unit_id='u_3' for step<5 SELECT IF(effective_transfer_date <= CURDATE(),futureUnitId,pastUnitId) AS currentUnitID FROM table_transfer // here how do we select only those rows which have currentUnitID='u_3' ?? please guide me the process?? i m just confused with JOINS. i think using LEFT JOIN can return the data i need, but i m not getting how to implement ...please help me. Thanks for helping me alwayz

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• mysql database normalization question

  - by Chocho

  here is my 3 tables: table 1 -- stores user information and it has unique data table 2 -- stores place category such as, toronto, ny, london, etc hence this is is also unique table 3 -- has duplicate information. it stores all the places a user have been. the 3 tables are linked or joined by these ids: table 1 has an "table1_id" table 2 has an "table2_id" and "place_name" table 3 has an "table3_id", "table1_id", "place_name" i have an interface where an admin sees all users. beside a user is "edit" button. clicking on that edit button allows you to edit a specific user in a form fields which has a multiple drop down box for "places". if an admin edits a user and add 1 "places" for the user, i insert that information using php. if the admin decides to deselect that 1 "places" do i delete it or mark it as on and off? how about if the admin decides to select 2 "places" for the user; change the first "places" and add an additional "places". will my table just keep growing and will i have just redundant information? thanks.

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• complex MySQL Order by not working

  - by Les Reynolds

  Here is the select statement I'm using. The problem happens with the sorting. When it is like below, it only sorts by t2.userdb_user_first_name, doesn't matter if I put that first or second. When I remove that, it sorts just fine by the displayorder field value pair. So I know that part is working, but somehow the combination of the two causes the first_name to override it. What I want is for the records to be sorted by displayorder first, and then first_name within that. SELECT t1.userdb_id FROM default_en_userdbelements as t1 INNER JOIN default_en_userdb AS t2 ON t1.userdb_id = t2.userdb_id WHERE t1.userdbelements_field_name = 'newproject' AND t1.userdbelements_field_value = 'no' AND t2.userdb_user_first_name!='Default' ORDER BY (t1.userdbelements_field_name = 'displayorder' AND t1.userdbelements_field_value), t2.userdb_user_first_name; Edit: here is what I want to accomplish. I want to list the users (that are not new projects) from the userdb table, along with the details about the users that is stored in userdbelements. And I want that to be sorted first by userdbelements.displayorder, then by userdb.first_name. I hope that makes sense? Thanks for the really quick help! Edit: Sorry for disappearing, here is some sample data userdbelements userdbelements_id userdbelements_field_name userdbelements_field_value userdb_id 647 heat 1 648 displayorder 1 - Sponsored 1 645 condofees 1 userdb userdb_id userdb_user_name userdb_emailaddress userdb_user_first_name userdb_user_last_name 10 harbourlights [email protected] Harbourlights 1237 Northshore Blvd, Burlington 11 harbourview [email protected] Harbourview 415 Locust Street, Burlington 12 thebalmoral [email protected] The Balmoral 2075 & 2085 Amherst Heights Drive, Burlington

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• Exporting to CSV from MySQL via PHP in FireFox

  - by typoknig

  Hi all, I am pulling some info from a database with the following code: <input type="button" value="Export to Excel" onClick="window.navigate('breakfast_service.php?action=export')"> Here is the code for that action. <?php if ($_GET['action'] == 'export') { // Get the registration data $user = 'root'; $pass = 'billiards'; $server = 'localhost'; $link = mysql_connect($server, $user, $pass); if (!$link) { die('Could not connect to database!' . mysql_error()); } mysql_select_db('breakfast', $link); $query = "SELECT * FROM registration"; $result = mysql_query($query); mysql_close($link); // format into CSV $contents = "id, school_id, first_name, last_name, email, attending, created_on\n"; $num = mysql_num_rows($result); for ($i = 0; $i < $num; $i++) { $row = mysql_fetch_array($result); $id = $row['id']; $school_id = $row['school_id']; $fname = $row['first_name']; $lname = $row['last_name']; $email = $row['email']; $attending = ($row['attending'] == 0) ? 'No' : 'Yes'; $date = $row['created_on']; $contents = $contents . "$id, $school_id, $fname, $lname, $email, $attending, $date\n"; } // return as excel file $filename = "export.csv"; header('Content-type: application/ms-excel'); header('Content-Disposition: attachment; filename='.$filename); echo $contents; } ?> This combination of code works excellent in IE, but fails to do create/download a file in Firefox or Chrome. Why?

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• Optimizing MySql query to avoid using "Using filesort"

  - by usef_ksa

  I need your help to optimize the query to avoid using "Using filesort".The job of the query is to select all the articles that belongs to specific tag. The query is: "select title from tag,article where tag='Riyad' AND tag.article_id=article.id order by tag.article_id". the tables structure are the following: Tag table CREATE TABLE `tag` ( `tag` VARCHAR( 30 ) NOT NULL , `article_id` INT NOT NULL , INDEX ( `tag` ) ) ENGINE = MYISAM ; Article table CREATE TABLE `article` ( `id` INT NOT NULL AUTO_INCREMENT PRIMARY KEY , `title` VARCHAR( 60 ) NOT NULL ) ENGINE = MYISAM Sample data INSERT INTO `article` VALUES (1, 'About Riyad'); INSERT INTO `article` VALUES (2, 'About Newyork'); INSERT INTO `article` VALUES (3, 'About Paris'); INSERT INTO `article` VALUES (4, 'About London'); INSERT INTO `tag` VALUES ('Riyad', 1); INSERT INTO `tag` VALUES ('Saudia', 1); INSERT INTO `tag` VALUES ('Newyork', 2); INSERT INTO `tag` VALUES ('USA', 2); INSERT INTO `tag` VALUES ('Paris', 3); INSERT INTO `tag` VALUES ('France', 3);

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• Generating MySQL UPDATE statements containing BLOB image data

  - by Bob

  I'm trying to write an SQL statement that will generate an SQL script that will update a BLOB field with an IMAGE being selected from the database. This is what I have: select concat( 'UPDATE `IMAGE` SET THUMBNAIL = ', QUOTE( THUMBNAIL ), ' WHERE ID = ', ID, ';' ) as UPDATE_STATEMENT from IMAGE; In the above, THUMBNAIL is a BLOB field containing raw image data. When I run the resulting script I get the following error: ERROR at line 2: Unknown command '\\'. I first tried this without the QUOTE() function, like so: select concat( 'UPDATE `IMAGE` SET THUMBNAIL = \'', THUMBNAIL, '\' WHERE ID = ', ID, ';' ) as UPDATE_STATEMENT from IMAGE; Running the resulting script produces this error: ERROR at line 2: Unknown command '\0'. What is the proper function to apply to this BLOB field in the select, so the UPDATE statements will work? If context is required, I'm looking to migrate thumbnails generated on one server to another server for certain image IDs only. I would use mysqldump, but I don't want to clobber the entire table. Any help is greatly appreciated!

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• Help with MySQL Query using CASE statement

  - by hairdresser-101

  I am trying to group a number of customers together based on their "Head Office" or "Parent" location. THis works ok except for a flaw which I didn't forsee when I was developing my system... For customers that did not have a "Parent" (standalone business) I defaulted the parent_id to 0. Therefore, my data would look like this: id parent_id customer 1 0 CustName#1 2 4 CustName#2 - Melbourne 3 4 CustName#2 - Sydney 4 0 CustName#2 (Head Office) What I want to do is Group my results together so that I have one row for CustName#1 and one row for CustName#2 BUT my problem is that there is no parent record for parent_id=0 and these rows are being excluded when using an inner join. I've tried using a case statement but that is not working either (parents are still being ignored) Any help would be greatly appreciated. Here is my query (My CASE is basically trying to get the business_name from the customer table based on the parent_id EXCEPT when the parent_id = 0, THEN just use the customer_name that is listed in the job_summary table): SELECT js.month_of_year, (CASE js.parent_id WHEN 0 THEN js.customer_name ELSE c.business_name END) as customer, SUM(js.jobs), SUM(js.total_cost), sum(js.total_sell) FROM JOB_SUMMARY js INNER JOIN customer c on js.parent_id=c.id group by js.month_of_year, (CASE c.parent_id WHEN 0 THEN js.customer_name ELSE c.business_name END) ORDER BY `customer` ASC

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• Problem with WHERE columnName = Data in MySQL query in C#

  - by Ryan Sullivan

  I have a C# webservice on a Windows Server that I am interfacing with on a linux server with PHP. The PHP grabs information from the database and then the page offers a "more information" button which then calls the webservice and passes in the name field of the record as a parameter. So i am using a WHERE statement in my query so I only pull the extra fields for that record. I am getting the error: System.Data.SqlClient.SqlException:Invalid column name '42' Where 42 is the value from the name field from the database. my query is string selectStr = "SELECT name, castNotes, triviaNotes FROM tableName WHERE name =\"" + show + "\""; I do not know if it is a problem with my query or something is wrong with the database, but here is the rest of my code for reference. NOTE: this all works perfectly when I grab all of the records, but I only want to grab the record that I ask my webservice for. public class ktvService : System.Web.Services.WebService { [WebMethod] public string moreInfo(string show) { string connectionStr = "MyConnectionString"; string selectStr = "SELECT name, castNotes, triviaNotes FROM tableName WHERE name =\"" + show + "\""; SqlConnection conn = new SqlConnection(connectionStr); SqlDataAdapter da = new SqlDataAdapter(selectStr, conn); DataSet ds = new DataSet(); da.Fill(ds, "tableName"); DataTable dt = ds.Tables["tableName"]; DataRow theShow = dt.Rows[0]; string response = "Name: " + theShow["name"].ToString() + "Cast: " + theShow["castNotes"].ToString() + " Trivia: " + theShow["triviaNotes"].ToString(); return response; } }

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• Mysql select - improve performance

  - by realshadow

  Hey, I am working on an e-shop which sells products only via loans. I display 10 products per page in any category, each product has 3 different price tags - 3 different loan types. Everything went pretty well during testing time, query execution time was perfect, but today when transfered the changes to the production server, the site "collapsed" in about 2 minutes. The query that is used to select loan types sometimes hangs for ~10 seconds and it happens frequently and thus it cant keep up and its hella slow. The table that is used to store the data has approximately 2 milion records and each select looks like this: SELECT * FROM products_loans WHERE KOD IN("X17/Q30-10", "X17/12", "X17/5-24") AND 369.27 BETWEEN CENA_OD AND CENA_DO; 3 loan types and the price that needs to be in range between CENA_OD and CENA_DO, thus 3 rows are returned. But since I need to display 10 products per page, I need to run it trough a modified select using OR, since I didnt find any other solution to this. I have asked about it here, but got no answer. As mentioned in the referencing post, this has to be done separately since there is no column that could be used in a join (except of course price and code, but that ended very, very badly). Here is the show create table, kod and CENA_OD/CENA_DO very indexed via INDEX. CREATE TABLE `products_loans` ( `KOEF_ID` bigint(20) NOT NULL, `KOD` varchar(30) NOT NULL, `AKONTACIA` int(11) NOT NULL, `POCET_SPLATOK` int(11) NOT NULL, `koeficient` decimal(10,2) NOT NULL default '0.00', `CENA_OD` decimal(10,2) default NULL, `CENA_DO` decimal(10,2) default NULL, `PREDAJNA_CENA` decimal(10,2) default NULL, `AKONTACIA_SUMA` decimal(10,2) default NULL, `TYP_VYHODY` varchar(4) default NULL, `stage` smallint(6) NOT NULL default '1', PRIMARY KEY (`KOEF_ID`), KEY `CENA_OD` (`CENA_OD`), KEY `CENA_DO` (`CENA_DO`), KEY `KOD` (`KOD`), KEY `stage` (`stage`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 And also selecting all loan types and later filtering them trough php doesnt work good, since each type has over 50k records and the select takes too much time as well... Any ides about improving the speed are appreciated.

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• Improve speed of a JOIN in MySQL

  - by ran2

  Dear all, I know there a similar threads around, but this is really the first time I realize that query speed might affect me - so it´s not that easy for me to really make the transfer from other folks problems. That being said I have using the following query successfully with smaller data, but if I use it on what are mildly large tables (about 120,000 records). I am waiting for hours. INSERT INTO anothertable (id,someint1,someint1,somevarchar1,somevarchar1) SELECT DISTINCT md.id,md.someint1,md.someint1,md.somevarchar1,pd.somevarchar1 from table1 AS md JOIN table2 AS pd ON (md.id = pd.id); Tables 1 and 2 contain about 120,000 records. The query has been running for almost 2 hours right now. Is this normal? Do I just have to wait. I really have no idea, but I am pretty sure that one could do it better since it´s my very first try. I read about indexing, but dont know yet what to index in my case? Thanks for any suggestions - feel free to point my to the very beginners guides ! best matt

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• Modify MySQL INSERT statement to omit the insertion of certain rows

  - by dave

  I'm trying to expand a little on a statement that I received help with last week. As you can see, I'm setting up a temporary table and inserting rows of student data from a recently administered test for a few dozen schools. When the rows are inserted, they are sorted by the score (totpct_stu, high to low) and the row_number is added, with 1 representing the highest score, etc. I've learned that there were some problems at school #9999 in SMITH's class (every student made a perfect score and they were the only students in the district to do so). So, I do not want to import SMITH's class. As you can see, I DELETED SMITH's class, but this messed up the row numbering for the remainder of student at the school (e.g., high score row_number is now 20, not 1). How can I modify the INSERT statement so as to not insert this class? Thanks! DROP TEMPORARY TABLE IF EXISTS avgpct ; CREATE TEMPORARY TABLE avgpct_1 ( sch_code VARCHAR(3), schabbrev VARCHAR(75), teachername VARCHAR(75), totpct_stu DECIMAL(5,1), row_number SMALLINT, dummy VARCHAR(75) ); -- ---------------------------------------- INSERT INTO avgpct SELECT sch_code , schabbrev , teachername , totpct_stu , @num := IF( @GROUP = schabbrev, @num + 1, 1 ) AS row_number , @GROUP := schabbrev AS dummy FROM sci_rpt WHERE grade = '05' AND totpct_stu >= 1 -- has a valid score ORDER BY sch_code, totpct_stu DESC ; -- --------------------------------------- -- select * from avgpct ; -- --------------------------------------- DELETE FROM avgpct_1 WHERE sch_code = '9999' AND teachername = 'SMITH' ;

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• Javascript to PHP, mysql uploading, one button pressing solution

  - by user2897858

  my program is generating buttons from a mysql database.When one of the button is pressed, it would uplod the current time and the gps coordinate. Sadly, it only works if the same button is pressed twice, but its not an option, because the button has to dissappear. I would like to have some help in coding how to make that possible the user only need to press the button once for the correct upload.Thanks in advance Here is the full code of my my file: <?php session_start(); ?> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>title</title> </head> <?php $maidatum=date("Ymj"); echo "<script>getLocation();</script>"; //Az adatbázishoz való csatlakozás $conn = mysql_connect("localhost","root","asd"); if(!($conn))die("Nincs conn a kiszolgálóval!".mysql_error()); $adatbazisneve="schtrans"; mysql_select_db($adatbazisneve,$conn); mysql_query("set names 'utf8'"); mysql_query("set character set 'utf8'"); //Combobox $sql = "SELECT Jaratszam,Vezeto FROM user"; $rs = mysql_query($sql) or die(mysql_error()); echo "<form action=\"\" method=\"post\">"; echo<<<nev <select name='Lista'> nev; while($row = mysql_fetch_array($rs)){ echo "<option value='".$row["Jaratszam"]."'>".$row["Vezeto"]."</option>"; }mysql_free_result($rs); echo "</select>"; ///Combox vége echo<<<lekerd <form action="" method="post"> <input type="submit" name="bekuldes" value="Lekérdez" /> </form> </form> lekerd; echo<<<gps <form action="" method="post"> <input type="hidden" name= "longitude" id="longitude"> <input type= "hidden" name ="latitude" id="latitude"> </form> gps; if(isset($_POST["bekuldes"])) { $jaratszam = $_POST['Lista']; $_SESSION['jaratsz']=$jaratszam; $lekerdez_parancs="SELECT * FROM cim_$maidatum WHERE jarat=$jaratszam;"; $lekerdez=mysql_query($lekerdez_parancs, $conn); echo "<table border=\"1\">"; echo "<td>Utánvétel</td> <td>Megrendelés összege</td> <td>ISZ</td> <td>Város</td> <td>Utca</td> <td>Megjegyzés</td> <td>Csomagok</td> <td>Raklaphely</td> <td>Súly</td><td>Térfogat</td><td>Latitude</td><td>Longitude</td><td>Ido</td>"; $g=1; //cimszámláló while ($adatok=mysql_fetch_array($lekerdez)) { echo "<tr>"; $_SESSION['adatok0'][$g]=$adatok[0]; echo "<td>$adatok[2]</td> <td>$adatok[3]</td> <td>$adatok[4]</td> <td>$adatok[5]</td> <td>$adatok[6]</td> <td>$adatok[7]</td> <td>$adatok[8]</td> <td>$adatok[9]</td> <td>$adatok[10]</td><td>$adatok[11]</td><td>$adatok[13]</td><td>$adatok[14]</td>"; if ($adatok[12]==null) { echo<<<gomb <form action="" method="post"> <td> <input type="hidden" name= "longitude" id="longitude$g"> <input type= "hidden" name ="latitude" id="latitude$g"> <input type="submit" name="ido" value="$g" /></td> </form> gomb; } else {echo "<td>$adatok[12]</td>";} $g++; } echo "</table>"; } if(isset($_POST["ido"])) { $hanyadik=$_POST["ido"]; $longitudee="longitude$hanyadik"; $latitudee="latitude$hanyadik"; ?> <script> var x=document.getElementById("log"); function getLocation() { if (navigator.geolocation) { navigator.geolocation.getCurrentPosition(showPosition); } else{x.innerHTML="GPS szolgáltatás nem müködik ezen a böngészon, kérlek értesítsd a rendszergazdát!";} } function showPosition(position) { var latitude = position.coords.latitude; var longitude = position.coords.longitude; document.getElementById("<?php echo $longitudee;?>").value = longitude; document.getElementById("<?php echo $latitudee;?>").value = latitude; } </script> <?php echo "<script>getLocation();</script>"; $latitude=$_POST["latitude"]; $longitude=$_POST["longitude"]; print_r($_POST); $currentime=date("H:i:s"); $acim=$_SESSION['adatok0'][$hanyadik]; $idofeltolt_parancs="UPDATE cim_$maidatum SET ido='$currentime',lat='$latitude',longi='$longitude' WHERE cimid='$acim';"; $feltoltes=mysql_query($idofeltolt_parancs, $conn) or die(mysql_error()); //tryy $jaratszam=$_SESSION['jaratsz']; $lekerdez_parancs="SELECT * FROM cim_$maidatum WHERE jarat=$jaratszam;"; $lekerdez=mysql_query($lekerdez_parancs, $conn); mysql_query("set names 'utf8'"); mysql_query("set character set 'utf8'"); echo "<table border=\"1\">"; echo "<td>Utánvétel</td> <td>Megrendelés összege</td> <td>ISZ</td> <td>Város</td> <td>Utca</td> <td>Megjegyzés</td> <td>Csomagok</td> <td>Raklaphely</td> <td>Súly</td><td>Térfogat</td><td>Latitude</td><td>Longitude</td><td>Ido</td>"; $g=1; //cimszámláló while ($adatok=mysql_fetch_array($lekerdez)) { echo "<tr>"; $_SESSION['adatok0'][$g]=$adatok[0]; echo "<td>$adatok[2]</td> <td>$adatok[3]</td> <td>$adatok[4]</td> <td>$adatok[5]</td> <td>$adatok[6]</td> <td>$adatok[7]</td> <td>$adatok[8]</td> <td>$adatok[9]</td> <td>$adatok[10]</td><td>$adatok[11]</td><td>$adatok[13]</td><td>$adatok[14]</td>"; if ($adatok[12]==null) { echo<<<gomb <form action="" method="post"> <td> <input type="hidden" name= "longitude" id="longitude$g"> <input type= "hidden" name ="latitude" id="latitude$g"> <input type="submit" name="ido" value="$g" /></td> </form> gomb; } else {echo "<td>$adatok[12]</td>";} $g++; } echo "</table>"; } mysql_close($conn); ?> </html>

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• PHP returns invalid MySQL resource

  - by DeadMG

  $LDATE = '#' . $_REQUEST['LDateDay'] . '/' . $_REQUEST['LDateMonth'] . '/' . $_REQUEST['LDateYear'] . '#'; $RDATE = '#' . $_REQUEST['RDateDay'] . '/' . $_REQUEST['RDateMonth'] . '/' . $_REQUEST['RDateYear'] . '#'; include("../../sql.php"); $myconn2 = mysql_connect(/*removed*/, $username, $password); mysql_select_db(/*removed*/, $myconn2); $LSQLRequest = "SELECT * FROM flight WHERE DepartureDate = ".$LDATE; $LFlights = mysql_query($LSQLRequest, $myconn2); $RSQLRequest = "SELECT * FROM flight WHERE DepartureDate = ".$RDATE; $RFlights = mysql_query($RSQLRequest, $myconn2); Assuming that all the $_REQUESTs are valid numerical values for their appropriate fields in the day/month/year field, how can LFlights and RFlights be invalid? When I polled the whole database I got hundreds of results so I know that the database and connection data is fine, and the field DepartureDate exists too.

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• MySQL Need some help with a query

  - by Jules

  I'm trying to fix some data by adding a new field. I have a backup from a few months ago and I have restored this database to my server. I'm looking at table called pads, its primary key is PadID and the field of importance is called RemoveMeDate. In my restored (older) database there is less records with an actual date set in RemoveMeDate. My control date is 2001-01-01 00:00:00 meaning that the record is not hidden aka visible. What I need to do is select all the records from the older database / table with the control date and join with those from the newer db /table where the control date is not set. I hope I've explained that correctly. I'll try again, with numbers. I have 80,000 visible records in the older table (with control date set) and 30,000 in the newer db/table. I need to select the 50,000 from the old database, to perform an update query. Heres my query, which I'd can't get to work as I'd like. jules-fix-reasons is the old database, jules is the newer one. select p.padid from `jules-fix-reasons`.`pads` p JOIN `jules`.`pads` ON p.padid = `jules`.`pads`.`PadID` where p.RemoveMeDate <> '2001-01-01 00:00:00' AND `jules`.`pads`.RemoveMeDate = '2001-01-01 00:00:00'

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• A typical mysql query( how to use subquery column into main query)

  - by I Like PHP

  I HAVE TWO TABLES shown below table_joining id join_id(PK) transfer_id(FK) unit_id transfer_date joining_date 1 j_1 t_1 u_1 2010-06-05 2010-03-05 2 j_2 t_2 u_3 2010-05-10 2010-03-10 3 j_3 t_3 u_6 2010-04-10 2010-01-01 4 j_5 NULL u_3 NULL 2010-06-05 5 j_6 NULL u_4 NULL 2010-05-05 table_transfer id transfer_id(PK) pastUnitId futureUnitId effective_transfer_date 1 t_1 u_3 u_1 2010-06-05 2 t_2 u_6 u_1 2010-05-10 3 t_3 u_5 u_3 2010-04-10 now i want to know total employee detalis( using join_id) which are currently working on unit u_3 . means i want only join_id j_1 (has transfered but effective_transfer_date is future date, right now in u_3) j_2 ( tansfered and right now in `u_3` bcoz effective_transfer_date has been passed) j_6 ( right now in `u_3` and never transfered) what i need to take care of below steps( as far as i know ) <1> first need to check from table_joining whether transfer_id is NULL or not <2> if transfer_id= is NULL then see unit_id=u_3 where joining_date <=CURDATE() ( means that person already joined u_3) <3> if transfer_id is NOT NULL then go to table_transfer using transfer_id (foreign key reference) <4> now see the effective_transfer_date regrading that transfer_id whether effective_transfer_date<=CURDATE() <5> if transfer date has been passed(means transfer has been done) then return futureUnitID otherwise return pastUnitID i used two separate query but don't know how to join those query?? for step <1 ans <2 SELECT unit_id FROM table_joining WHERE joining_date<=CURDATE() AND transfer_id IS NULL AND unit_id='u_3' for step<5 SELECT IF(effective_transfer_date <= CURDATE(),futureUnitId,pastUnitId) AS currentUnitID FROM table_transfer // here how do we select only those rows which have currentUnitID='u_3' ?? please guide me the process?? i m just confused with JOINS. i think using LEFT JOIN can return the data i need, or if we use subquery value to main query? but i m not getting how to implement ...please help me. Thanks for helping me alwayz

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